what is 4/5s divided by 2/3s .

Therefore, the correct answer is (b) H(0) and H(a), where H(0) represents the null hypothesis and H(a) represents the alternative hypothesis.

Based on the given information, D represents the null hypothesis (H₀) and E represents the alternative hypothesis (Hₐ).

The null hypothesis (H₀) is a statement that there is no significant difference between the observed data and the expected results. In this case, the null hypothesis is that the population mean (μ) is greater than or equal to 1000.

The alternative hypothesis (Hₐ) is a statement that there is a significant difference between the observed data and the expected results. In this case, the alternative hypothesis is that the population mean (μ) is less than 1000.

Correct answer is (b) H(0) and H(a), where H(0) represents the null hypothesis and H(a) represents the alternative hypothesis.

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Answer:

hmmmm give me a minute..

Step-by-step explanation:

Answer:

First, find the value of x:

\(h(5-x)=h(9)\\5-x=9\\-x=9-5\\-x=4\\x=-4\)

Substitute the x-value in to the function \(x^{2}+x+1\) and solve:

\((-4)^{2}+(-4)+1=16-4+1=12+1=13\)

Therefore, the value of h(9) = 13.

Hope this is correct O-o

Answer:

A

Step-by-step explanation:

Since we need to find the value of h(9), we can substitute the (5-x) part from the original equation with 9 to get the value of x, which is 5-x = 9, x = -4. With that, we can go ahead and plug the x into the right side of the equation to get (-4)^2 + (-4) + 1, which equals 16 - 4 + 1, which equals 13.

I hope this helped! Please do let me know if you have further questions :D

<3

if you don't understand please ask in the comment section

The probability that a student scores between 450 and 600 on the SAT math section is approximately 0.4147 or 41.47%.

To find the probability that a student scores between 450 and 600 on the SAT math section, we need to use the properties of the normal distribution. We know that the mean is 511 and the standard deviation is 110.

First, we need to standardize the values of 450 and 600 using the formula:

z = (x - μ) / σ

where x is the value we want to standardize, μ is the mean, and σ is the standard deviation.

For 450:

z = (450 - 511) / 110 = -0.55

For 600:

z = (600 - 511) / 110 = 0.81

Next, we need to find the area under the normal curve between these two standardized values. We can use a table or a calculator to find that the area between z = -0.55 and z = 0.81 is approximately 0.4147.

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The horizontal asymptote of the rational expression as given in the task content is; Choice B; y = 15/20.

It follows from the task content that the horizontal asymptote of the given expression is to be determined.

It is important to remember that;

If a rational polynomial has N as the degree of the numerator and D is the degree of the denominator, and…

N < D, then the horizontal asymptote is said to be y = 0.

N = D, then the horizontal asymptote is y = ratio of leading coefficients.

N > D, then there is no horizontal asymptote.

Hence, since the degree of numerator and denominator are same for the given rational expression.

Therefore, the horizontal asymptote is the ratio of the leading coefficient in the numerator to that in the denominator.

Horizontal asymptote is therefore;

y = 15/20.

Ultimately, the required horizontal asymptote is; Choice B; y = 15/20.

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The equation of the curve is y = x² - 4x + 3

Since we are given the slope of the curve at each point, we can use integration to find the equation of the curve. Let's denote the equation of the curve as y = f(x).

The slope of the curve is given by dy/dx = 2x - 4. We can integrate this expression with respect to x to obtain an expression for f(x):

∫dy = ∫(2x - 4)dx

y = x² - 4x + C

where C is the constant of integration.

To determine the value of C, we use the fact that the curve passes through the point (4,7):

7 = 4² - 4(4) + C

C = 7 + 4(4) - 16 = 3

Thus, the equation of the curve is y = x²- 4x + 3.

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Answer:

56 cm^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh where b is the base and h is the height

A = 1/2 (14) (8)

A = 56 cm^2

The secant of the angle in this problem is given as follows:

sec(θ) = 2.4625.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

Considering the terminal side at (4,9), the hypotenuse is given as follows:

h² = 4² + 9²

h = sqrt(97)

h = 9.85.

Then the cosine of the angle is given as follows:

cos(θ) = 4/9.85

The secant of the angle is the inverse of the cosine, hence it is given as follows:

sec(θ) = 9.85/4

sec(θ) = 2.4625.

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Answer:

9 1/3

Step-by-step explanation:

Pls, choose me as brainliest!

The probability of selecting a pen from the first box is 1/8 (since there is only 1 pen out of 8 items in the box). The probability of selecting a crayon from the second box is 3/6 (since there are 3 crayons out of 6 items in the box).

To find the probability of both events happening together, we multiply the probabilities:

P(pen and crayon) = P(pen) x P(crayon)

P(pen and crayon) = (1/8) x (3/6)

Simplifying the fraction 3/6 to 1/2:

P(pen and crayon) = (1/8) x (1/2)

Multiplying the numerators and denominators:

P(pen and crayon) = 1/16

Therefore, the probability of selecting a pen from the first box and a crayon from the second box is 1/16.

Answer:

\(\frac{1}{9}\)

Step-by-step explanation:

The quantities must be in the same measure

3 feet = 3 × 12 = 36 inches ( 1 foot = 12 inches )

Then

fraction = \(\frac{4}{36}\) = \(\frac{1}{9}\)

The inner product interval of  f1(x) = eˣ and f2(x) = sin(x) is not equal to zero. So the given functions are not orthogonal on the indicated interval [T/4, 5T/4].

The functions f1(x) = eˣ and f2(x) = sin(x) are orthogonal to the interval [T/4, 5T/4],

For this, their inner product over that interval is equal to zero.

The inner product of two functions f(x) and g(x) over an interval [a,b] is defined as:

⟨f,g⟩ = ∫[a,b] f(x)g(x) dx

⟨f1,f2⟩ = \(\int\limits^{T/4}_{ 5T/4}\) eˣsin(x) dx

Using integration by parts with u = eˣ and dv/dx = sin(x), we get:

⟨f1,f2⟩ = eˣ(-cos(x)\()^{T/4}_{5T/4}\) - \(\int\limits^{T/4}_{ 5T/4}\)eˣcos(x) dx

Evaluating the first term using the limits of integration, we get:

\(e^{5T/4}\)(-cos(5T/4)) - \(e^{T/4}\)(-cos(T/4))

Since cos(5π/4) = cos(π/4) = -√(2)/2, this simplifies to:

-\(e^{5T/4}\)(√(2)/2) + \(e^{T/4}\)(√(2)/2)

To evaluate the second integral, we use integration by parts again with u = eˣ and DV/dx = cos(x), giving:

⟨f1,f2⟩ = eˣ(-cos(x)\()^{T/4}_{5T/4}\) + eˣsin(x\()^{T/4}_{5T/4}\)  - \(\int\limits^{T/4}_{ 5T/4}\) eˣsin(x) dx

Substituting the limits of integration and simplifying, we get:

⟨f1,f2⟩ = -\(e^{5T/4}\)(√(2)/2) + \(e^{T/4}\)(√(2)/2) + (\(e^{5T/4}\) - \(e^{T/4}\))

Now, we can see that the first two terms cancel out, leaving only:

⟨f1,f2⟩ = \(e^{5T/4}\) - \(e^{T/4}\)

Since this is not equal to zero, we can conclude that f1(x) = eˣ and f2(x) = sin(x) are not orthogonal over the interval [T/4, 5T/4].

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Answer: 3.375oz

Explanation

Given

• Reduce his daily soda intake by ​25%.

• Currently, he drinks 4.5oz. cans of soda per day.

• Ounces of soda can the patient drink if he reduces his intake by 25​%?

We have to build a relation, where 4.5 is our 100% and x is 75% (100 - 25 = 75%):

Solving for x:

Answer:

Yes. good job :)

keep up the good work 0u0

Step-by-step explanation:

The net annual percentage growth rate of the city population is 0.4%

To calculate the net annual percentage growth rate of a population, we can use the following formula:

Net Annual Percentage Growth Rate = ((Births + Immigrants) - (Deaths + Emigrants)) / Initial Population x 100%

Plugging in the given values, we get:

Net Annual Percentage Growth Rate =\(((100 + 10) - (40 + 30)) / 10,000 x 100%\)

Net Annual Percentage Growth Rate = \((40 / 10,000) x 100%\)

Net Annual Percentage Growth Rate =\(0.4%\)

The net annual percentage growth rate of the city population is 0.4%

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Answer:

I think it’s 7,920 feet

Step-by-step explanation:

I did 1.5 miles times the amount of feet ( 5,280 )

And got 7,920

There are 720 different ways can a race with 6 runners be completed.

What is a combination?

The process of combining or the condition of combining. a combination of things; an amalgamation of concepts. a grouping of notes: A chord is a grouping of notes. a grouping of people or entities acting together to impede commerce.

Here, we have

The winner can be chosen from all 6 runners, the second person can be chosen from 5 people, the third - from 4, and so on.

So the total number of possible results can be calculated as:

n = 6×5×4×3×2×1= 6!

= 720

Hence, there are 720 different ways can a race with 6 runners be completed.

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The range would be needed to label the subjects correctly is 000-210.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

Given that a researcher is comparing the effectiveness of three devices.

There are 210 people who snore participating in the experiment

The researcher will randomly place the participants into three equally sized treatment groups suitable for comparison.

We need to find the range which would be needed to label the subjects correctly.

210 people are participating in experiment

We need to label subjects from 001 to 210

Since there is no value in using 000 to indicate someone.

Hence, 000–210 is the range would be needed to label the subjects correctly.

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Answer:

10.3 is the width

Step-by-step explanation:

set up an equation

42w=432

divided both sides by 42

W=10.2857142857

to rounded it to nearest tenth it will be 10.3

to check your answer multiply 10.3 by 42 it will be 432

check check

Answer:

18 ≤ w ≤ 24

Step-by-step explanation:

A = l * w

A ≥ 432 sq ft.

l = 42 - w

432 ≤ (42 - w) (w)

432 ≤ -w² + 42w

w² - 42w ≥ 432

Substitute values for w

w = 18

w = 24

The statement "with respect to the 3-sigma rule used in reliability analysis, studies have shown that even experts tend to under-predict the range in parameter values (max-min). however, this is conservative because it leads to a smaller estimate of reliability" is true because studies have shown that experts tend to under-predict the range in parameter values when using the 3-sigma rule, leading to a conservative estimate of reliability.

The 3-sigma rule is a widely used method in reliability analysis that assumes the range of parameter values is within three standard deviations of the mean value. However, studies have shown that experts tend to under-predict the range of parameter values.

This under-prediction can result in a conservative estimate of reliability because it leads to a smaller range of possible outcomes. In other words, the estimated reliability is likely to be lower than the actual reliability. Therefore, it is important to take into account the potential for under-prediction when using the 3-sigma rule and to use other methods to estimate reliability as well.

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there are approximately 34 boys in the introductory geology course.

To determine the number of boys in the introductory geology course, we need to calculate the ratio of boys to girls and use the total number of students enrolled.

The given ratio states that there are six boys for every five girls. This can be expressed as 6 boys : 5 girls.

Let's assume the number of boys in the course is represented by B and the number of girls is represented by G.

According to the given information, we can set up the following equation:

6 boys / 5 girls = B / G.

Since the total number of students enrolled in the course is 374, we can write another equation:

B + G = 374.

To solve these equations simultaneously, we can use the concept of proportion.

From the first equation, we can rewrite it as:

6G = 5B.

Now we can substitute this expression into the second equation:

B + G = 374

5B + 6B = 374

11B = 374

B = 374 / 11

B ≈ 34.

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Answer:

last one

Step-by-step explanation:

The square root of 75 is 5√3, which can also be written as 5√-1+4

The given expression [-20 - (-4)] is equivalent to (-20 + 4).

A linear expression is an expression in which the highest power of the variable is always 1. If there is no variable, we can assume the power of the variable as 0.

Therefore, the variable x⁰ = 1.

Given linear expression:

-20 - (- 4)

= (-20 + 4)

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The following differential equations with a solution
y" + y = 0 corresponds to solution A: y = cos(2)

y" + y' + 28y = 0 corresponds to solution B: y = e^(-4x)

y" + 11y' + 28y = 0 corresponds to solution C: y = e^(7x)

2x^2y" + 3xy' = y corresponds to solution D: y = x^(1/2)

1. y" + y = 0:

This is a second-order homogeneous differential equation with constant coefficients. The characteristic equation is r^2 + 1 = 0, which has complex roots r = ±i. The general solution is therefore a linear combination of sine and cosine functions:

y = c1 cos(x) + c2 sin(x)

Using the initial condition y(0) = 1, we can solve for the constants to get:

y = cos(x)

2. y" + y' + 28y = 0:

This is a second-order homogeneous differential equation with constant coefficients. The characteristic equation is r^2 + r + 28 = 0, which has complex roots given by the quadratic formula:

r = (-1 ± sqrt(1 - 4*28)) / 2 = (-1 ± 7i) / 2

The general solution is therefore a linear combination of exponential and sine/cosine functions:

y = e^(-x/2) (c1 cos(7x/2) + c2 sin(7x/2))

Using the initial condition y(0) = 1, we can solve for the constants to get:

y = e^(-4x)

3. y" + 11y' + 28y = 0:

The characteristic equation is r^2 + 11r + 28 = 0, which can be factored as (r + 4)(r + 7) = 0. The roots are r = -4 and r = -7. Therefore, the general solution is a linear combination of exponential functions:

y = c1 e^(-4x) + c2 e^(-7x)

Using the initial condition y(0) = 1, we can solve for the constants to get:

y = e^(7x)

4. 2x^2y" + 3xy' = y:

Dividing both sides by x^2 and letting z = y/x^(1/2). Then, we get:

z' + (1/4x)z = 0

This is a first-order homogeneous differential equation with an integrating factor of e^(1/4 ln x) = x^(1/4). Multiplying both sides by the integrating factor, we get:

x^(1/4) z' + (1/4)x^(-3/4)z = 0

The left-hand side is the derivative of (x^(1/4) z), so we can integrate both sides to get:

x^(1/4) z = c1

Solving for z, we get:

z =c1/x^(1/4)

Substituting back for y, we get:

y = x^(1/2) z = c1 x^(1/4)

Using the initial condition y(1) = 1, we can solve for the constant to get:

y = x^(1/2)

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The cost of one ounce of cereal is $0.23

Given:

Amount of cereals a box contain = 24 ounces

Cost of one box = $5.52

Cost of cereal per ounce = Cost of cereal / Amount of cereals in  a box

Cost of cereal per ounce =  $5.52 / 24

Cost of cereal per ounce =  $0.23

An ounce is any of various units of mass, weight or volume derived almost invariably from the ancient Roman unit of measure, the ounce. an avoirdupois ounce is 1⁄16 avoirdupois pound; it is the US and British imperial ounce. 1 ounce is equal to 437.5 grains or 28.349 grams, A US customary fluid ounce is 1⁄16 of a US liquid pint and 1⁄128 of a US liquid gallon or exactly 29.5735295625 mL.

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       For C1(Q) = 3 - 2Q.

        For C2(Q) =  4.

     2. The AVC function

           For C1(Q) = 5/Q + 3 + 20/Q - Q.

           For C2(Q) = 3/Q + 4 + 2/Q.

     3. The AFC function

              For C1(Q)= 5/Q - 20/(5 + 3Q + 20/Q - Q)

              For C2(Q) = 0.

     4.  To find the AC function

        For C1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

         For C2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

    5.To find the ATC function

    For C1(Q)= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²)

     For C2(Q)= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

1. To find the MC function, we take the derivative of the cost functions with respect to Q.

For C1(Q) = 5 + 3Q + 202 - Q^2, MC1(Q) = 3 - 2Q.

For C2(Q) = 3 + 4Q + 2, MC2(Q) = 4.

2. To find the AVC function, we divide the cost functions by Q.

For C1(Q), AVC1(Q) = (5 + 3Q + 202 - Q^2)/Q = 5/Q + 3 + 20/Q - Q.

For C2(Q), AVC2(Q) = (3 + 4Q + 2)/Q = 3/Q + 4 + 2/Q.

3. To find the AFC function, we subtract the AVC function from the ATC function.

For C1(Q), AFC1(Q) = (5 + 3Q + 202 - Q^2)/Q - (5 + 3Q + 202 - Q^2)/(5 + 3Q + 20/Q - Q)

= 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AFC2(Q) = (3 + 4Q + 2)/Q - (3 + 4Q + 2)/(3/Q + 4 + 2/Q) = 0.

4. To find the AC function, we add the AVC function to the AFC function.

For

C1(Q), AC1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AC2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

5. To find the ATC function, we divide the AC function by Q.

For

C1(Q), ATC1(Q) = [(5 + 3Q + 202 - Q²)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q)]/Q

= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²).

For

C2(Q), ATC2(Q) = [(3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q]/Q

= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

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Answer:

perpendicular  

Step-by-step explanation:

First we need to dtemine the slopes of the line

For line 1

L1: (-4, 6) (-3,-1)

m1 = y2-y1/x2-x1

m1= -1-6/-3+4

m1 = -7/1

m1 = -7

For line 2:

L2: (8,9) (15, 10)

m2  = 10-9/15-8

m2 = 1/8

Take their product

m1 * m2 = -7 * 1/7

m1m2 = -1

Since the product of their slopes is -1, hence they are perpendicular  

Answer:

(-6, -29)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Systems

-5x + y = 1

9x - 2y = 4

Step 2: Rewrite Systems

-5x + y = 1

Step 3: Redefine Systems

y = 5x + 1

9x - 2y = 4

Step 4: Solve for x

Substitution

Step 5: Solve for y