A device that uses the pressure of fluid to move a piston that is connected to a rod is called a hydraulic cylinder. Hydraulic cylinders are commonly used in many applications where a large force is required to move heavy loads or perform work.
The hydraulic cylinder consists of a cylinder barrel, which contains a piston that is connected to a piston rod. The piston separates the cylinder into two chambers, one on each side. When pressurized fluid is supplied to one of the chambers, it forces the piston to move in the opposite direction, which in turn moves the piston rod.
The force that can be generated by a hydraulic cylinder depends on the size of the piston and the pressure of the fluid. By increasing the pressure of the fluid, a greater force can be exerted on the piston and piston rod, which allows for greater power and efficiency. Hydraulic cylinders are commonly used in heavy machinery, construction equipment, and industrial automation systems.
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Marcus is playing tug-of-war with his cat using a stuffed toy. At one instant during the game, Marcus pulls on the toy with a force of 22.0 N, the cat pulls in the opposite direction with a force of 19.5 N, and the toy experiences an acceleration of 6.25 m/s 2 . What is the mass of the toy?
Answer:
0.4Kg
Explanation:
Marcus pulled the toy with a force of 22.0N and the cat pulled it in the opposite direction with 19.5N
=> F1= 22N
F2= -19.5N
Therefore the net force on the toy= F1+F2
Fnet =22-19.5
Fnet =2.5N
Force= Mass* Acceleration
2.5= (Mass)*6.25
=> Mass=2.5/6.25
=0.4Kg
Therefore the mass of the toy is 0.4Kg
a dentist's mirror is placed 2.4 cm from a tooth. the enlarged image is located 6.5 cm behind the mirror. (a) what kind of mirror (plane, concave, or convex) is being used? (b) determine the focal length of the mirror. (c) what is the magnification? (d) how is the image oriented relative to the object?
a) The kind of mirror it is concave.
b) to find the focal length we use the formula,
V = uf/(u-f)
6.5 = -2.4f/(-2.4-f)
f = 3.8
c) magnification = v/u
=6.5/2.4
=2.7
d) image which is oriented to the object is virtual and erect
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A vehicle traveling 63 km/h [E] accelerates 1.0 m/s2 [E] for 9.0s. Determine the displacement of the vehicle during this 9.0 s it take to pass the car. Express your answer in the form a.b x 10c and input the digits a,b,and c with no commas or spaces.
The displacement of the vehicle during the 9.0 s it takes to pass the car is 198.0 m or 1.98 x 10² m as requested.
The displacement
We can use the kinematic equation for displacement with constant acceleration:
Δx = v_iΔt + 1/2aΔt^2
where Δx is the displacement, v_i is the initial velocity, a is the acceleration, and Δt is the time interval.
In this problem, v_i = 63 km/h = 17.5 m/s [E] (since the vehicle is traveling due east), a = 1.0 m/s^2 [E], and Δt = 9.0 s.
Plugging these values into the equation, we get:
Δx = (17.5 m/s) (9.0 s) + 1/2 (1.0 m/s^2) (9.0 s)^2
Δx = 157.5 m + 40.5 m
Δx = 198.0 m
Therefore, the displacement of the vehicle during the 9.0 s it takes to pass the car is 198.0 m.
Expressing this answer in the requested format (a.b x 10c), we have:
1.98 x 10² m
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A 15000 kg truck moving with a speed of 9 m/ sis about to collide with a stationary loaded truck with a total mass of 45000 kg as shown in the figure below.
After the collision, both of the trucks move together.
Calculate the kinetic energy of the combined trucks just after the collision (neglect friction).
Without accounting for friction, the combined trucks' kinetic energy immediately following the impact is 75937.5 J (joules).
How is the kinetic energy calculated after a collision?Common objects will have a lower final kinetic energy than they did at the beginning. The only method to boost kinetic energy is if the hit results in some sort of energy release.
Prior to the collision, the 15000 kg truck's momentum is:
p1 = m1v1 = (15000 kg)(9 m/s) = 135000 kg*m/s
The second truck's starting momentum is 0 because it is stationary:
p2 = m2*v2 = 0
Hence, the system's total momentum prior to the impact equals:
p_initial = p1 + p2 = 135000 kg*m/s
we can treat them as a single object with a combined mass of:
m_total = m1 + m2 = 15000 kg + 45000 kg = 60000 kg
Applying the idea of conservation of momentum, we may say:
p_initial = p_final
Since the two trucks move together with a common velocity, we have:
p_final = m_total*v_final
Equating p_initial and p_final, we get:
p_final = p_initial = 135000 kg*m/s
Substituting m_total and solving for v_final, we get:
v_final = p_final / m_total = 135000 kg*m/s / 60000 kg = 2.25 m/s
The kinetic energy of the combined trucks just after the collision is given by: KE = (1/2)m_totalv_final²
Substituting the values of m_total and v_final, we get:
KE = (1/2)(60000 kg)(2.25 m/s)² = 75937.5 J
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30 points plz help ill do anything... literally anything.
A car moving at 10 m/s slows to a stop.
It moves 25 meters forward while braking.
1. How much time does it take to slow to a stop? Explain how you found your answer.
2. What is its braking acceleration? Explain how you found your answer.
Answer:
1. 2.5s
Explanation:
1. For time, divide Distance / speed
25m / 10
=2.5s
1. Write two important precautions that you took during the connected in parallel?
Answer:
1)The connection should be tight.
2)The wire should be connected at the terminals not in between.
3)clean the ends of the wire by sandpaper.
4)Take the voltmeter and ammeter in proper range.
5)The rheostat should be used of low resistant(about 100).
At an amusement park, you and a friend sit on a large rotating disk. You sit at the edge and have a rotational speed of 10 RPM and a linear speed is 12 m/s. Your friend does halfway to the center What is her rotational speed and linear speed
GUYS PLEASE HELPPPP
Q. A body is thrown at an angle of 30 degree with velocity of 30m/s downward, if the height of the tower is 15m find:
1) the time when body reaches the ground
2) displacement vector
3) angle when body hits the ground
4) max height?
1. To find the time when the body reaches the ground, we can use the vertical motion equation:
h = v₀y * t + (1/2) * g * t²
where:
h = height of the tower = 15m
v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)
g = acceleration due to gravity = 9.8m/s²
t = time
Plugging in the values:
15 = (30 * sin(30°) * t) + (0.5 * 9.8 * t²)
Simplifying the equation:
15 = 15t * 0.5t² + 4.9t²
Combining like terms:
15 = 7.5t² + 4.9t²
Simplifying further:
15 = 12.4t²
Dividing both sides by 12.4:
t² = 15 / 12.4
Taking the square root of both sides:
t = √(15 / 12.4)
Calculating the value:
t ≈ 1.01 seconds
Therefore, the time it takes for the body to reach the ground is approximately 1.01 seconds.
2. To find the displacement vector, we need to calculate the horizontal and vertical components separately.
Horizontal component:
The horizontal displacement can be calculated using the formula:
x = v₀x * t
where:
v₀x = initial horizontal velocity = v₀ * cos(θ) = 30m/s * cos(30°)
t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)
Plugging in the values:
v₀x = 30m/s * cos(30°)
t = 1.01 seconds
Calculating the value:
v₀x ≈ 26.02 m/s
Vertical component:
The vertical displacement can be calculated using the formula:
y = v₀y * t + (1/2) * g * t²
where:
v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)
g = acceleration due to gravity = 9.8m/s²
t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)
Plugging in the values:
v₀y = 30m/s * sin(30°)
t = 1.01 seconds
Calculating the value:
v₀y ≈ 15 m/s
Now we have the horizontal and vertical components of the displacement vector:
Horizontal component: x ≈ 26.02 m/s
Vertical component: y ≈ 15 m/s
Therefore, the displacement vector of the body is approximately (26.02 m/s, 15 m/s).
3. To find the angle when the body hits the ground, we can use the vertical and horizontal components of the velocity.
The horizontal component of the velocity, v₀x, can be calculated using the formula:
v₀x = v₀ * cos(θ)
where:
v₀ = initial velocity = 30m/s
θ = angle of projection = 30 degrees
Plugging in the values:
v₀x = 30m/s * cos(30°)
Calculating the value:
v₀x ≈ 26.02 m/s
The vertical component of the velocity, v₀y, can be calculated using the formula:
v₀y = v₀ * sin(θ)
where:
v₀ = initial velocity = 30m/s
θ = angle of projection = 30 degrees
Plugging in the values:
v₀y = 30m/s * sin(30°)
Calculating the value:
v₀y ≈ 15 m/s
Now, to find the angle when the body hits the ground, we can use the inverse tangent function:
θ = arctan(v₀y / v₀x)
Plugging in the values:
θ = arctan(15 m/s / 26.02 m/s)
Calculating the value:
θ ≈ 30.96 degrees
Therefore, the angle when the body hits the ground is approximately 30.96 degrees.
4. To find the maximum height, we can use the vertical motion equation:
h = v₀y² / (2 * g)
where:
h = maximum height
v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)
g = acceleration due to gravity = 9.8m/s²
Plugging in the values:
h = (30 * sin(30°))² / (2 * 9.8)
Calculating the value:
h ≈ 27.55 meters
Therefore, the maximum height reached by the body is approximately 27.55 meters.
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Please help!!
A shopping bag can provide a force of 65 N before breaking. A shopper puts 5 kg of groceries in the bag. If the shopper tries to lift the bag with an upward acceleration of 2 m/s/s, will the bag break?
Answer:
the bag DOES NOT BREAK, F = 59 N
Explanation:
For this exercise, let's use Newton's second law, let's set a reference frame with the positive direction up
F -W = m a
the mass of the groceries is m = 5 kg, the weight is
W = m g
indicate the acceleration a = 2 m / s², let's find the force
F = mg + ma
F = m (g + a)
let's calculate
F = 5 (9.8 + 2)
F = 59 N
F <65 N
as the force with which it pulls the bag less than the breaking force the bag DOES NOT BREAK
True or false? A well-oiled machine has no friction. Explain your answer.
Answer:
False
Explanation:
A well-oiled machine has oil because there is friction. The oil lessens the friction and also allows the machine to operate and function without wear parts heating up. Oil is a cooling lubricant that decreases friction but does not eliminate it.
You throw a dodge ball with a mass of 2.1 kg. The ball leaves your hand with a speed of 25 m/s. Identify the energy (PE or KE) and calculate it.
Given,
The mass of the object, m=2.1 kg
The speed of the object, v=25 m/s
Kinetic energy is the energy that an object possesses due to its motion. And potential energy is the energy that an object possesses due to its position.
The gravitational potential energy depends on the height of the object. As the change in the height of the object is not mentioned in the question, let us assume that there is no change in the potential energy.
The velocity of the object, however, changes. Thus the energy possessed by the object is the kinetic energy.
And the kinetic is given by
\(E_K=\frac{1}{2}mv^2\)On substituting the known values,
\(\begin{gathered} E_K=\frac{1}{2}\times2.1\times25^2 \\ =656.25\text{ J} \end{gathered}\)Thus the kinetic energy of the ball is 656.25 J
The kinetic energy of a golf ball is measured to be 140.5 J. If the golf ball has a mass of about 40g, what is its speed
Answer:
V= in square root 2KE/M=2(143.3J)/0.047kg=6097.8723 in square root around 78.1 approxmete
Explanation:
train starting from a railway station and moving with a uniform accleration attains a speed of 90km/hr in 10s .Find the accleration
Options
90m/s2
1m/s2
10m/s2
0.1m/s2
Answer:
a= 2.5m/s²
Explanation:
U=0
V=90km/hr
T= 10s
Convert 90km/hr to m/s
1km= 1000m
1hr= 3600s
(60×60)
therefore, 90km/hr = 90000/3600
90km/hr= 25m/s
From Newton First Equation,
V=U + AT
25=0+ A(10)
25= 10A
25/10 =10A/10
A= 2.5m/s²
Which type of box will best protect a fragile object by minimizing the force on the object
You are walking toward the back of a train that is moving forward with a constant velocity. The train's velocity relative to the ground is 30 m/s forward. Your velocity relative to the train is 1.5 m/s backward. How fast are you moving relative to the ground?
Answer:
28.5 m/s
Explanation:
There are 2 different velocities: the train velocity and yours velocity. They're in opposite directions, so one is positive and other is negative. Take the forward direction as the positive:
V = +30 -1.5
V = 28.5 m/s
28.5 m/s forward
Consider the train as a “positive movement” and you as a “negative movement” combine those and take the larger direction
A soccer ball is moving with a momentum of 5 kg m/s when a soccer player
kicks the ball back in the opposite direction. After the kick, the soccer ball
is moving with a momentum of 7 kg m/s. What is the impulse the soccer
player applied to the soccer ball?
The impulse applied to the soccer ball by the soccer player is the combined force and time of the kick applied to the ball.
What do you mean by Impulse?
Impulse is an instantaneous force applied to an object, resulting in a change in the object's momentum. It is a vector quantity, which means that it has both magnitude and direction. Impulse is the product of a force applied to an object for a certain period of time. It is calculated as the product of the average force applied multiplied by the time period over which the force is applied. For example, when a ball is hit with a bat, the force of the bat is applied to the ball for a certain amount of time, resulting in an impulse which causes the ball to move.
1. Calculate the change in momentum of the soccer ball:
Change in momentum = Final Momentum - Initial Momentum
= 7 kg m/s - 5 kg m/s
= 2 kg m/s
2. Calculate the impulse:
Impulse = Change in Momentum
= 2 kg m/s
Therefore, the impulse applied by the soccer player to the soccer ball is 2 kg m/s.
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A ray of light is incident on a square slab of transparent
plastic in air. It strikes the centre of one side at an angle of
61
Find the minimum refractive index of the plastic if the light is
to be to
To achieve total internal reflection, the minimum refractive index of the plastic must be at least 0.869 when a ray of light is incident at an angle of 61 degrees on the center of one side of the plastic slab in air.
The minimum refractive index of the plastic can be found , we need to consider the conditions for total internal reflection.
Total internal reflection occurs when the angle of incidence is greater than the critical angle, which is the angle at which the refracted ray is at a 90-degree angle to the normal.
In this scenario, the ray of light is incident on the plastic at an angle of 61 degrees. We can use Snell's law to relate the angle of incidence to the angle of refraction:
n1 * sin(angle of incidence) = n2 * sin(angle of refraction)
Here, n1 is the refractive index of air (approximately 1), and n2 is the refractive index of the plastic.
Since we want the light to be totally internally reflected, the angle of refraction will be 90 degrees. Thus, we have:
1 * sin(61 degrees) = n2 * sin(90 degrees)
Rearranging the equation, we get:
n2 = sin(61 degrees) / sin(90 degrees)
Calculating this expression, we find that n2 is approximately 0.869.
Therefore, the minimum refractive index of the plastic should be at least 0.869 to ensure total internal reflection in this scenario.
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Complete question:
A ray of light is incident on a square slab of transparent plastic in air. It strikes the center of one side at an angle of 61 degrees. Find the minimum refractive index of the plastic if the light is to be totally internally reflected.
an astronaut has a momentum of 280 kg and travels 10 m/s. what is the mass of the astronaut?
Answer:
The answer is
28 kgExplanation:
The mass of an object given it's momentum and velocity / speed can be found by using the formula
\(m = \frac{p}{v} \\ \)
where
m is the mass
p is the momentum
v is the speed or velocity
From the question
p = 280 kg/ms
v = 10 m/s
The mass of the object is
\(m = \frac{280}{10} = 28 \\ \)
We have the final answer as
28 kgHope this helps you
With an average mass of only 30.0 gthe mouse lemur of Madagascar the smallest primate on Earth. Suppose this lemur swings on a light vine with a length of 2.4 m, so that the tension in the vine at the bot- tom point of the swing is 0.393 N. What is the lemur's tangential speed at that point?
Suppose that Reid weighs 72 kg. 2. The mouse macaque of India is the shortest primate on Earth, with an average weight of just 30.0 g. Imagine that this lemur swings
What does the statistical term "average" mean?
Average. In everyday speech, a average is a specific number chosen to represent a collection of figures. In various settings, various average ideas are utilized. The word "average" frequently refers to the mathematical mean, which is the total of the values divided by the number of numbers being averaged. Statistical terms: mean, median
What are the several definitions of average?
In various settings, various average ideas are utilized. The word "average" frequently refers to the mathematical mean, which is the total of the integers divided by the amount of numbers being averaged. Mean, average, and mode all are considered measures of normal distribution in statistics, and in common parlance, any of these could be referred to as an average figure.
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. A car starts to move from rest has an acceleration of 3m/s².what will be the velocity and distance travelled by the car after 50sec.
Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :
Step 1: Calculate the velocity using the equation:
\(v = u + at\)
where:
- \(v\) is the final velocity
- \(u\) is the initial velocity (0 m/s, as the car starts from rest)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)
Step 2: Calculate the distance traveled using the equation:
\(s = ut + \frac{1}{2}at^2\)
where:
- \(s\) is the distance traveled
- \(u\) is the initial velocity (0 m/s)
- \(a\) is the acceleration (3 m/s²)
- \(t\) is the time (50 seconds)
Substituting the values into the equation:
\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)
Now, let's simplify these equations:
\(v = 3 \times 50\)
\(s = \frac{1}{2} \times 3 \times 50^2\)
Calculating the results:
\(v = 150\) m/s
\(s = 3750\) meters
Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.
Block A is set on a rough horizontal table and is connected to a horizontal spring that is fixed to a wall, as shown.
Block A is then also connected to hanging block B by a lightweight string that passes over an ideal pulley, as
shown. The friction force exerted on block A by the table is not negligible. The blocks are initially held at rest so
that the spring is not stretched. When the blocks are released, hanging block B moves downward and block A on
the table moves to the right until the system comes again to rest. Let E1 be the mechanical energy of the blocks-
spring system, and let E2 be the mechanical energy of the blocks-spring-Earth system. How do these two energies
change from when the blocks are held at rest to when the blocks come to rest again?
The mechanical energy of the system is sum of the potential and kinetic
energy of the system.
Response:
E1 increases, E2 decreasesMethods by which the the above response is obtainedMechanical energy, M.E. in the block and spring system can be presented as follows;
M.E. = Energy in the spring + Kinetic energy of the blocks + Energy done on friction
Mechanical energy of the block-spring system, E1When the blocks are held at rest;
The mechanical energy in the block-spring system when the blocks are held at rest can be found as follows;
Energy in the spring = 0
Kinetic energy of the blocks = 0
Friction energy = 0
Therefore;
E1 for the block at rest = 0
E1 when the blocks come to rest again
Energy in the spring = \(\mathbf{\frac{1}{2} \cdot k \cdot x^2}\) > 0
Kinetic energy = 0
Energy of friction = 0
Therefore;
The mechanical energy of the block-spring system, E1, increases
The mechanical energy of the block-spring-Earth system, E2When the blocks are held
Energy in the spring = 0
Energy done due to friction = 0
Potential energy of Block B = m·g·h
Kinetic energy of the blocks = 0
When the blocks come to rest again, we have;
Energy in the spring = \(\frac{1}{2} \cdot k \cdot x^2\)
Energy received due to friction = 0
Potential energy of Block B = m·g·(h - y)
Where;
\(m \cdot g \cdot h = \mathbf{m \cdot g \cdot (h - y) + \frac{1}{2} \cdot k \cdot x^2 + Energy \ loss \ due \ to \ friction}\)
Which gives;
\(m\cdot g \cdot h > m \cdot g \cdot (h - y) + \frac{1}{2} \cdot k \cdot x^2\)
The energy in the spring-block-Earth system, E2, when initially held is more than the the energy when the blocks com to rest again.
Therefore, E2 decreases
The correct option is therefore;
E1 increases, E2 decreasesThe possible question options obtained from a similar question posted online are;
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Five 6 ohm resistors are connected in parallel. Which of the following is their effective resistance?
A. 6 ohm
B. 1.2 ohm
C. 30 ohm
D. 5/6 ohm
1/Rt = 1/R1 + 1/R2 + 1/R3+ 1/R4+ 1/R5
1/Rt = 1/6+ 1/6+1/6+1/6+1/6
1/Rt = 5/6
Rt = 6/5
Rt = 1.2 ohm
so B is the answer
Calculating the Magnitude of the Resultant Vector
R
13 m
5m
What is the magnitude of the resultant vector? Round
your answer to the nearest tenth.
m
The magnitude of the resultant vector is 13.9m.
The size of the resulting vector can be determined using the Pythagorean theorem. As you can see from these two examples, the result of adding three or more rectangular vectors is easy to determine using the Pythagorean theorem. The vectors should be added in a different order. Equation 2 Subtracts the vectors in opposite directions from each other to get the resulting vector.
Where vector B is in the opposite direction to vector A and R is the resulting vector. The resulting vector is defined as a single vector that produces the same effect as many vectors produced together. The size of a vector is the length of the vector. The absolute value of vector a is represented by |a|. For more information on vector sizes, see Vectors overview. The formulas for the sizes of 2D and 3D vectors in terms of coordinates are derived on this page.
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Which statement describes what most likely occurs when a compass is placed next to a simple circuit made from a battery, a light bulb, and a wire?
A. A magnetic field created by the compass increases the current in the electrical circuit.
B. A magnetic field created by the compass causes the light bulb to stop working.
C. A magnetic field created by the electric current places negative charges on the compass.
D. A magnetic field created by the electric current causes the compass needle to move.
A magnetic field created by the electric current causes the compass needle to move. Option D is the correct answer.
When an electric current flows through a wire, it creates a magnetic field around the wire. The direction of the magnetic field is determined by the direction of the current. When a compass is placed next to the wire, the magnetic field created by the current causes the compass needle to move.
In a simple circuit made from a battery, a light bulb, and a wire, the electric current flows from the battery, through the wire, and through the light bulb, and then back to the battery. This creates a magnetic field around the wire, which can cause the compass needle to move when it is placed next to the wire. Hence, option D is correct choice.
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Odysseus has returned from his epic voyage across the seas and gets off his boat at the end of a 50 meter pier. His beloved Penelope is waiting at the far side of the pier, at the origin. At the same time they see each other and race towards each other, meeting in a fierce embrace. Odysseus, exhausted from his journey, is able to run at 4 m/s, while Penelope can run at 6 m/s. Write an equation of motion for Odysseus.
Answer:
We know that:
Distance between Odysseus and Penelope = 50m
Speed of Odysseus = So = 4m/s
Speed of Penelope = Sp = 6m/s.
Now we want to find the equation of motion for Odysseus.
First, let's find the amount of time that he is moving, we know that when he meets with Penelope, he will stop moving.
Now they weel meet each other when the total distance traveled by both of them is equal to 50m.
Then, recalling that:
Distance = Time*speed.
50m = 4m/s*t + 6m/s*t = 10m/s*t
t = 50m/10m/s = 5s
They will move for 5 seconds.
Now we can write the movement equation for Odysseus as:
p(t) = 4m/s*t + p0 for (0s ≤ t ≤ 5s)
Where p0 is the initial position of Odysseus, and because we can put our coordinate axis where we want, we can define p0 = 0m.
Then the position of Odysseus is:
P(t) = 4m/s*t if 0s ≤ t ≤ 5s
P(t) = 4m/s*5s = 20m if t > 5s.
The second piece says that for t larger than 5 seconds, he will not move (at least for a given amount of time)
I need helpppp :((((((
Answer: c. The electric force increases
Explanation:
If the distance between two charged particles decreases, the electric force between them increases.
According to Coulomb's Law, the electric force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the equation can be represented as:
F = k * (q1 * q2) / r^2
Where:
F represents the electric force between the particles.
k is the electrostatic constant.
q1 and q2 are the charges of the particles.
r is the distance between the particles.
As the distance (r) between the particles decreases, the denominator of the equation (r^2) becomes smaller, causing the overall electric force (F) to increase. Conversely, if the distance between the charged particles increases, the electric force between them decreases. This inverse relationship between the distance and electric force is a fundamental characteristic of the electrostatic interaction between charged objects.
if a spring is released x meters from equilibrium, at what distance from equilibrium will it have acceleration equal to half its maximum acceleration?
When the stretch distances are at half of their maximum displacement, the acceleration will be half of its maximum value by Hooke's Law.
F= -kx
In accordance with Hooke's law, a principle of elasticity, for relatively minor deformations of an object, the displacement or size of the deformation is directly proportional to the deforming force or load The elasticity of an object is likewise governed by Hooke's law; for example, a metal spring can only be stretched so far before being broken by too much effort. A mass that we already have is then expanded out by x. Displacement and acceleration are inversely related. When the stretch distances are at half of their maximum displacement, the acceleration will be half of its maximum value.
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Explain why a smart meter monitors the amount of electrical energy being used as well as the time at which it is being used.
Answer:
Smart Meters measure both the amount of electrical energy used and the time at which it is being used because they are used to monitor the energy consumption at real time, such that the time of use of energy can be monitored, thereby enabling several utility functions for load sharing and maintenance, including;
i) Time of use tariffs, where energy is billed based on peak and off peak periods, which increases profits to the producer, reduces cost for some consumers, encourages more even hourly and daily usage of electricity, lower maintenance cost, lower capital expenditure for peak stations, and reduces carbon emission
ii) Guarantees more accurate energy consumption measurement and billing
iii) Accurate crew dispatch to fault locations
iv) Prevent fraud due to tampering with meter
v) Increase customer confidence in billing
Explanation:
Describe the laws of liquid pressure and Explain the term fluid. (Please give the correct answer, it's really urgent)
Answer:
The laws of liquid pressure are
(i) Pressure inside the liquid increases with the depth from the free surface of the liquid.
(ii) Pressure is same at all points on a horizontal plane, in case of stationary liquid.
(iii) Pressure is same in all directions about a point inside the liquid.
(iv) Pressure at same depth is different in different liquids. It increases with the increase in the density of the liquid.
(v) A liquid will always seek its own level.
A Fluid is any liquid or gas or generally any material that cannot sustain a tangential, or shearing, force when at rest.
Explanation:
Suppose a particle moves along a straight line with velocity meters per second after seconds.
Many meters will a particle have traveled after t seconds if it is moving in a straight line at a velocity of v(t)=t2e2t meters per second?
What are velocity and speed?In contrast to velocity, which describes the speed and direction of such an object's movement, speed is the rate of movement along a path. Alternatively, velocities is a vector while speed is just a scalar quantity.
Why is there a velocity formula?Velocity (v), which can be expressed by the expression v = s/t, is still a tensor quantity that determines dislocation (or the shift in position, s), over change in time (t).
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