what is nuclear emission?
Answers
Related Questions
What is acceleration?
A.speed
B.distance over time
C.speed with direction
D.a change in motion over time
Answers
Answer:
c
Explanation:
Identify which portions of the electromagnetic spectrum are used in each of the devices listed. a. a microwave oven b. a television set c. a single-lens reflex camera
Answers
The portions of the electromagnetic spectrum are used in the television set. It is used in the picture tube in the old television set.
What is the electromagnetic spectrum ?The electromagnetic radiation distribution in accordance with the frequency or wavelength is known as the electromagnetic spectrum.
The portions of the electromagnetic spectrum are used in the television set. It is used in the picture tube in the old television set.
Hence, option b is correct.
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The focal length of a converging lens is 10 cm. What is the angular magnification of this lens if the image is viewed by a relaxed eye with a near point of 25 cm?.
Answers
The angular magnification of this lens if the image is viewed by a relaxed eye with a near point of 25 cm is 0.056.
The given values are: The focal length of a converging lens is 10 cm and the near point of the relaxed eye is 25 cm. To determine the angular magnification of this lens if the image is viewed by a relaxed eye with a near point of 25 cm, we need to use the formula given below:Angular magnification, m = (-) v / uwhere v = the distance of the image from the eyeand u = the distance of the object from the eye
The near point of the relaxed eye is 25 cm, so the distance of the object from the eye, u = 25 cm.Using the formula of the lens equation, we can find the value of v:1/f = 1/v - 1/u1/10 = 1/v - 1/25v = 1/10 + 1/25v = (5 + 2) / 50v = 7/50 cmNow we can substitute the values of u and v to calculate the angular magnification:m = (-) v / um = (-) (7/50) / 25m = (-) 7 / 125m = -0.056 or 0.056 (taking magnitudes)
Therefore, the angular magnification of this lens if the image is viewed by a relaxed eye with a near point of 25 cm is 0.056.
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Answer the question?
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A cylindrical rod with one end in a steam chamber and the other end is in ice. It is found that 1 gm of ice melts per second. If the rod is replaced by another one of the same material but of double length and double area of cross section, the mass of ice that melts per second is :
Answers
The mass of ice that melts per second in the second case will be 2 gm.
The rate of heat transfer through a cylindrical rod is directly proportional to the area of the cross-section and inversely proportional to the length of the rod. Therefore, if the length and area of the cross-section are both doubled, the rate of heat transfer will remain the same. However, since the area of the cross-section is doubled, the mass of ice that melts per second will also be doubled.
The equation for the rate of heat transfer through a cylindrical rod is Q/t = kA(T1 - T2)/L, where Q/t is the rate of heat transfer, k is the thermal conductivity of the material, A is the area of cross-section, T1 and T2 are the temperatures at the two ends of the rod, and L is the length of the rod.
In the first case, Q/t = kA(T1 - T2)/L
In the second case, Q/t = k(2A)(T1 - T2)/(2L) = kA(T1 - T2)/L
Therefore, the rate of heat transfer is the same in both cases. However, since the area of the cross-section is doubled in the second case, the mass of ice that melts per second will also be doubled. So, the mass of ice that melts per second in the second case is 2 gm.
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If the current through a 500 W heater is 4.00 A, what is the potential difference
across the ends of the heating element? *
O 2x10^3 V
8x10^-3 V
25 V
125 V
Answers
Answer:
125 V
Explanation:
Given,
Power ( P ) = 500 W
Current ( I ) = 4 A
To fine : -
Potential difference ( V ) = ?
Formula : -
P = V I
V = P / I
= 500 / 4
V = 125 V
Therefore,
the potential difference across the ends of the heating element is 125 V.
4. To get to the sandwich shop, you left home and drove 6 miles south and then 10 miles west.
If a bird flew from your house to the sandwich shop in a straight line, how far do you think the
bird would fly? Use the simulation to check your reasoning.
. What direction should it fly from your house to get to the shop?
. Explain how you could use the simulation to answer these questions.
• Explain how you could use geometry equations to answer these questions.
Answers
If a bird flew from my house to the sandwich shop in a straight line, it would travel a distance of 10.44 miles.
The direction that it should fly from my house to get to the shop is at an angle 73.30°.
Pythagorean theorem-
The position vector are
OA = -6j AB = -10iBC=3j
where
O is the position of the house
C is the position of the shop.
Now drawing a perpendicular from C to OA at P we have,
Thus we have,
PC = 10i
PA = 3j
Thus,
OP = OA - PA = -6j + 3j = -3j
OC is the resultant of CP and OP
a) Thus the magnitude of OC
| OC | = √CP^2 + OP^2
= √ (10^2 +3^2) =10.44
b) The angle made by OC with OP
tan θ = OP/CP = 10/3
θ = 73.30°
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Determine the orbits period of the moon when the distance between the earth and the moon is 3.82 x 10 to the power of 8
Answers
Answer:
3820000000
Explanation:
Use the motion map to answer the question, describe the position and velocity of the object based moo the motion map?
Answers
answer:
20 points y'all it's urgent
As a light’s intensity decreases...
a. its amplitude increases
b. its amplitude decreases
c. its wavelength decreases
d. its wave speed decreases
Answers
Answer:
There is an inverse relationship between distance and light intensity - as the distance increases, light intensity decreases. This is because as the distance away from a light source increases,..
Explanation:
The light intensity decreases as magnification increases. There is a fixed amount of light per area, and when you increase the magnification of an area, you look at a smaller area. So you see less light, and the image appears dimmer. Image brightness is inversely proportional to the magnification squared.
what did edison mean with the claim that there is no similar institution in existence?
Answers
Edison means with the claim that "there is no similar institution in existence" was that he had created the first ever laboratory dedicated to research and invention.
After the successful installation of his first power plants in the starting of 1880s, Edison lived up to his reputation as the "Inventor of the Age." For many years Edison had no single, central laboratory. He researched at his electrical manufacturing shops in Harrison, New Jersey and New York.
When his wife Mary died in 1884 he withdrew somewhat from electric light work. In 1887 he had decided to build a new facility near his house in West Orange, New Jersey, several times bigger than the Menlo Park laboratory had been. The new laboratory equipped with everything Edison had learned about the process of invention.
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1. american ski jumper lee ben fardest's (a mass of approximately 58.5 kg) begins from rest at position a as he begins his descent down the slope to the big jump ramp. consider the friction between the skies and snow to be negligible. how much energy does fardest have at position a?
Answers
Lee Ben Fardest has 34,174.7 Joules of energy at position A.
Since Lee Ben Fardest begins from rest, his initial kinetic energy is zero. Therefore, his total energy at position A is equal to his potential energy.
The potential energy of an object is given by the formula:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference level.
In this case, we need to determine the height of Lee Ben Fardest above some reference level. Let's assume that the reference level is the height of the takeoff ramp. Then, we can use the following diagram to determine the height of position A above the takeoff ramp:
. A
/|
/ |
/ |
ramp / | h
--------
From the diagram, we see that the height h is equal to the length of the ramp, which we'll assume is 60 meters.
Now we can calculate the potential energy of Lee Ben Fardest at position A:
PE = mgh = (58.5 kg)(9.81 m/s^2)(60 m) = 34,174.7 J
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12.5.65 Question Help Given two lines in space, either they are parallel, they intersect, or they are skew (lie in parallel planes). Determine whether the lines below, taken two at a time, are parallel, intersect, or are skew. If they intersect, find the point of intersection. Otherwise, find the distance between the two lines. L1: L2: L3: x= 1-t, y=2-2t, z=2-t, -00
Answers
Lines L1, L2, and L3 are skew (they do not intersect and do not lie in parallel planes). The distance between L1 and L2 is 3 units.
Given lines in space L1, L2, and L3 such thatL1: x= 1-t, y=2-2t, z=2-t,L2: x= -1+3t, y=-1-t, z=3+5tL3: x= 2+s, y= 1+2s, z= -2-3s. Determine whether the lines below, taken two at a time, are parallel, intersect, or are skew (lie in parallel planes) If they intersect, find the point of intersection. Otherwise, find the distance between the two lines.The general equation of a line is given by L1: r = a + λ b Here, (x, y, z) are the coordinates of any point on the line. `a` is the position vector of a known point on the line, `λ` is a scalar parameter, and `b` is the direction vector of the line.L1 : x = 1 - t, y = 2 - 2t, z = 2 - t => r = i + 2j + 2k + (-i - 2j - k)λ = i + 2j + k + t(-i - 2j - k)L2: x = -1 + 3t, y = -1 - t, z = 3 + 5t => r = -i - j + 3k + (3i - j + 5k)λ = 2i - j + 8k + t(3i - j + 5k)L3: x = 2 + s, y = 1 + 2s, z = -2 - 3s => r = 2i + j - 2k + si + 2sj - 3sk = (2 + i) + (1 + 2s)j + (-2 - 3s)k Since the direction vectors of L1 and L2 are not equal and neither are their direction vectors proportional to each other, L1 and L2 are skew lines. Likewise, the direction vector of L3 is not proportional to the direction vector of either L1 or L2 and hence L3 is also skew to the other two lines.The distance between skew lines is the shortest distance between them. It is perpendicular to both the lines. Therefore, we need to find the normal to the plane containing L1 and L2. The normal to the plane containing L1 and L2 is given by the cross-product of their direction vectors. n = b1 × b2 = (-1-2) i + (-2-(-1)) j + (1-4) k = -3i - j - 3k Now, to find the shortest distance, we can take any point on L1 and find its perpendicular distance from L2. For example, we can take the point (1, 2, 2) on L1. The distance is |(r2 - r1).n/|n|| where r1 = i + 2j + 2k is a point on L1 and r2 is the position vector of a point on L2. r2 = -i - j + 3k + 3λi - λj + 5λk. r2 - r1 = -2i - 3j + k + 3λi - λj + 5λkTherefore, the shortest distance between L1 and L2 is |(-2i - 3j + k + 3λi - λj + 5λk).(-3i - j - 3k)/√(9 + 1 + 9) = 3√11/√11 = 3. Therefore, the lines are skew and the distance between L1 and L2 is 3.For more questions on parallel planes
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What is the direction of the force on a positive charge when passing through a magnetic field as indicated in this diagram? Explain how you got
your answer.
Answers
Answer:
The direction of the magnetic force on a moving charge is perpendicular to the plane formed by v and B and follows right hand rule–1 (RHR-1)
Explanation:
hope this helps
Answer:
The direction is into the page. Your thumb is along the velocity vector and your fingers travel along the magnetic-field vector to leave your palm moving into the page
Explanation:
Plato
How does the observed pitch of the buzzer change as it moves
observer?
pitch of the buzzer increased (higher tone) as it moves towards the observer
The pitch of the buzzer decreased (lower tone) as it moves towards the observer
The pitch of the buzzer stayed the same no matter where it was in relationship
to the observer
Answers
The answer is
Pitch of the buzzer increased (higher tone) as it moves towards the observer
The correct option that explains the change in the observed pitch of the buzzer as it moves towards the observer is;
A; pitch of the buzzer increased (higher tone) as it moves towards the observer
This is based on the concept of doppler effect which is defined as the change in frequency/pitch of a sound that is heard by an observer due to the fact that the sound source and the observer have different velocities with respect to the medium through the sound travels.Now, according to doppler effect, when the source of the sound moves towards the observer, the frequency will increase due to the fact that the time between successive sound waves is shortened. Thus, this means that the pitch will be higher. However, when the sound source moves away from the observer, the frequency would decrease due to the fact that the time between successive sound waves or the crest is now longer. Thus, the pitch will decrease.In conclusion, the pitch of the buzzer will increase as it moves towards the observer.
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Question: In an average year, the Creek drainage basin (150 mi^2) receives 550 mm of precipitation. Has an average stream discharge of 1.8 m^3s^-1. (1 mile = 1.609 km).
Please develop the water budget equation for this problem.
Answers
The water budget equation for the Creek drainage basin is: Precipitation = Stream discharge + Evapotranspiration ± Change in storage.
To develop the water budget equation for this problem, we need to account for the inputs and outputs of water in the Creek drainage basin. The water budget equation can be expressed as,
P = Q + ET ± ΔS
P = Precipitation input (mm)
Q = Stream discharge (m³/s)
ET = Evapotranspiration (mm)
ΔS = Change in storage (mm)
First, let's convert the units of the given values,
Precipitation input (P) = 550 mm
Stream discharge (Q) = 1.8 m³/s
Now, let's determine the evapotranspiration (ET) and change in storage (ΔS) terms. However, the problem doesn't provide information about ET, so we cannot calculate it accurately. The problem doesn't provide information about ΔS, so we cannot calculate it accurately.
Given these limitations, we can write the simplified water budget equation for this problem,
550 mm = 1.8 m³/s + ET ± ΔS
Please note that without information about evapotranspiration and changes in storage, we cannot fully determine the water budget for the Creek drainage basin.
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The energy an object has by virtue of its position is kinetic energy.
True
False
Answers
Answer:
false
Explanation:
the energy an object has by virtue of its position is gravitational energy.
the energy which an object possess due to its motion is kinetic energy.
hope it helps !
Maya uses a tuning fork of frequency 250 Hz to produce transverese waves on a stretched string. Her friend justin measure the distance between the.two consecutive crest on the string as 5 cm. What was the velocity of the wave?
Answers
Answer:
The velocity of the wave is 12.5 m/s
Explanation:
The given parameters are;
he frequency of the tuning fork, f = 250 Hz
The distance between successive crests of the wave formed, λ = 5 cm = 0.05 m
The velocity of a wave, v = f × λ
Where;
f = The frequency of the wave
λ = The wavelength of the wave - The distance between crests =
Substituting the known values gives;
v = 250 Hz × 0.05 m = 12.5 m/s
The velocity of the wave, v = 12.5 m/s.
What does weight require?
Responses
gravity and volume
gravity and volume
only mass
only mass
mass and gravity
mass and gravity
mass and volume
Answers
Answer:
Mass and gravity
Explanation:
\({ \rm{weight = mass \times gravity}}\)
Weight is the force exerted on an object due to gravity. The correct answer is mass and gravity. The correct option is an option (3).
Weight requires both mass and gravity.
The formula for calculating weight is given by:
Weight = mass × gravitational acceleration
W = m × g
The gravitational acceleration is known by the strength of the gravitational field, which is typically constant at any given point.
The mass of an object and the strength of its gravitational field is its weight. It is the gravitational force that pulls an object toward the center of the Earth.
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Therefore, The correct option is (3).
The complete question is:
What does weight require?
1) gravity and volume
2) only mass
3) mass and gravity
4) mass and volume
Elvira throws a meatball at the wall. When the meatball hits the wall, it makes a sound. The kinetic energy of the meatball is transferred into the surroundings through what? (Hint: your answer should be a type of wave. )
Answers
Answer:
sound waves
Explanation:
The kinetic energy of the meatball is transferred into the surroundings through sound waves.
When the meatball hits the wall, the kinetic energy of the meatball causes vibrations in the wall and the surrounding air. These vibrations create sound waves which transfers the kinetic energy to sound energy until it runs out of energy.
When an object / medium vibrates, the particle of the object / medium starts to move. This movement of particles is called as sound waves. It is a type of mechanical wave.
Therefore, the kinetic energy of the meatball is transferred into the surroundings through sound waves.
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Calculate the focal length of a lens needed by a woman whose near point is 50cm from her eyes, assuming the least distance of distinct vision for a normal eye is 25cm.
Answers
The focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.
To find the answer, we have to know about the focal length of correcting lens.
How to find the focal length of correcting lens?If x is the distance of nearest point of the defective eye and D is the least distance of distinct vision, then, the expression for focal length of the correcting lens will be,\(f=\frac{XD}{X-D}\)
It is given that, the woman whose near point is 50cm from her eyes, assuming the least distance of distinct vision for a normal eye is 25cm. Thus, the focal length will be,\(f=\frac{50*25}{50-25} =50cm.\)
Thus, we can conclude that, the focal length of a lens needed by a woman whose near point is 50cm from her eyes is 50cm.
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Work is required to lift a barbell. How many times more work is required to lift the barbell 2 times as high
Answers
Answer:
2 time
Explanation:
when distance double the work double
A large boulder has been perched on the side of a mountain for many years. What change would cause it to suddenly roll down the mountain?
Answers
Answer:
he weight vector approaches the point within the mass, the equilibrium becomes unstable
any change in the conditions of the environment can cause the rock to slide
Explanation:
In general, a rock in a mountain is in stable equilibrium with the help of the force of gravity that causes its weight to be within the center of mass, that is, the weight vector is first and then it is electing the center of mass.
When for some reason the weight vector approaches the point within the mass, the equilibrium becomes unstable, and any change in the conditions of the environment can cause the rock to slide, for example a rain that reduces the friction force.
It may happen that the weight vector is after the center of the hubs, in this case there is an unstable balance and the stone is held in place by the force of friction with the environment that surrounds it, if this friction decreases the rock will slide .
Below are a pair of wires holding a hanging light that weighs 50N. Is the tension in each of the wires less than 50N, 50N, or more than 50N?
Answers
Answer:
Less than 50N
Explanation:
Given that a pair of wires holding a hanging light that weighs 50N.
Since the hanging weight is equal to 50 N, the sum of the tension in the wires will also experience the same magnitude of force acting on the weight.
Considering each of the wire, the tension on each of the wire will surely be less than 50N
Therefore, the tension in each wire is less than 50N
Can you please answer my question correctly ASAP
Answers
Answer:
1) C, 2) C, 3) B, 4) D, 5) A/B, 6) D, 7) D, 8) A, 9) B, 10) A
Explanation:
1) Seconds, minutes and days are time units. (Correct answer: C)
2) The displacement is shortest distance between the point of origin and the point of destination. (Correct answer: C)
3) The velocity is the rate of change of position in time. (Correct answer: B)
4) Graphs are a very useful ressource to infer characteristics inherent to a studied physical variable. (Correct answer: D)
5) There are two possible answers, since both milimeters and meters are units for distance. (Correct answers: A/B)
6) The distance is the arc length of the entire path that object travelled. (Answer: D)
7) Traditionally, in a position vs. time graph we plot time in the x-axis. (Answer: D)
8) In this case, we use a distance-time graph, where travelled distance is the dependent variable and time is the independent variable. (Answer: A)
9) The point of origin is the initial position of the object. (Answer: B)
10) The point of destination is the final position of the object. (Answer: A)
a 959 kg car starts from rest on a horizontal roadway and accelerates eastward for 5.00 s when it reaches a speed of 20.0 m/s what is the average force exerted on the car during this time
Answers
The average force exerted on the car of mass 959 kg during eastward acceleration for 5 seconds is 3836 N
v = u + at
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time
v = 20 m / s
u = 0
t = 5 s
20 = 0 + ( 5 a )
a = 20 / 5
a = 4 m / s²
F = m a
F = Force
m = Mass
m = 959 kg
F = 959 * 4
F = 3836 N
Therefore, the average force exerted on the car is 3836 N
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Changes in the Moon’s position as it revolves around the Earth results in more or less of the sunlight __________from the Moon being visible when observing the Moon from the Earth. This causes the Moon to appear to change shape from Earth. *
Answers
Answer:
reflection of the moon, or just reflection
Explanation:
when the sunlight hits the moon, it refects back to earth making the moon appear to glow
Answer:
reflecting
Explanation:
the sun's light reflects off the moon, making the moon visible
PLEASE HELP!!! I have an electromagnet. If I detach the two wires from the battery and reattach them to the opposite terminals, how would that change the current and magnetic field?
Answers
Explanation:
hope it helps thanks
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The gravitational force beyween two objects is 2000 N. The mass of the objects is reduced to one-third of its original mass
Answers
Which is consistent with the laws of physics governing energy?
Answers
The explanation provided is consistent with the laws of physics governing energy.
Kinetic energy, potential energy, and total energy are fundamental principles in classical mechanics, derived from well-established laws like Newton's laws of motion and the law of universal gravitation.
The conservation of energy, stating that energy cannot be created or destroyed but only converted between forms, is considered.
By analyzing changes in kinetic and potential energy, we can determine the energy required to move the satellite to a higher orbit while maintaining consistency with the laws of physics.
This approach ensures a thorough understanding aligned with the fundamental principles of energy conservation.
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