What is observation of demonstrating the force of attraction and repulsion between two current parallel carrying conductor

The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.

Answer:

Explanation:

if he is moving at a constant velocity, the work changes the potential energy

W = PE = mgh = 80(9.8)(5) = 3,920 J

Power is the rate of doing work

P = W/t = 3920/10 = 392 W(atts)

Answer:

Chaos.

Explanation:

Given that the time taken to reach the ground is t = 6 s

The final velocity is v = 0m/s

We have to find the height of the monument, h.

The initial velocity can be calculated by the formula

Here, g is the acceleration is due to gravity whose value is 9.81 m/s^2

Substituting the values, the initial velocity will be

The formula to find height is

Substituting the values, the height will be

Thus, the correct option is 177 m.

Answer:

Below

Explanation:

In a mass-spring system that is oscillating horizontally, the energy changes between potential energy and kinetic energy. When the mass is at its maximum displacement from the equilibrium position, it has maximum potential energy and zero kinetic energy. As the mass starts to move towards the equilibrium position, its potential energy decreases while its kinetic energy increases. At the equilibrium position, the mass has zero potential energy and maximum kinetic energy. As the mass moves away from the equilibrium position, its kinetic energy decreases while its potential energy increases. This cycle repeats as long as the system is oscillating.

Now, if the support of the system is vibrating vertically, the energy changes that occur during horizontal oscillations cause the mass to move vertically as well. As the mass moves to its maximum displacement from the equilibrium position horizontally, it also moves upwards, gaining potential energy due to its increased height from the ground. As the mass moves towards the equilibrium position horizontally, it also moves downwards, losing potential energy and gaining kinetic energy due to its increased speed towards the ground. At the equilibrium position, the mass has zero potential energy but maximum kinetic energy, which is all in the vertical direction. As the mass moves away from the equilibrium position horizontally, it also moves upwards, gaining potential energy again. The cycle repeats, causing the mass to oscillate vertically as well.

Therefore, the energy changes that occur during horizontal oscillations in a mass-spring system can cause the system to vibrate vertically if the support is vibrating vertically.

Answer:

D

Explanation:

the other students are making fun of her most likely because they are jealous that she is successing in school. hope this helps :)

Answer:

D

Explanation:

Answer:

the value of t = 0.49 seconds shows that its upward journey

and

at t = 5.43 seconds shows in downward journey

Explanation:

Given:

initial speed, u = 29 m/s

acceleration due to gravity, g = - 9.8 m/s^2

h = 13 m

Let it is moving with velocity v at a height of 13 m.

Use third equation of motion

v² = u² + 2gh

By substituting the values

v² = 29² - (2 * 9.8 * 13)

v = sqrt 585.94

v  = 24.2 m/s

Let it takes time t to reach at height 13 m

Use second equation of motion

s = u * t + 1/2 * g * t²

13 = 29t - 4.9t²

4.9t² - 29t + 13 = 0

using quadratic equation to solve time

     29 ± \(\sqrt{29^2 - 4 * 4.9 * 13}\\\)

t = ------------------------------------

                     2 * 4.9

t = 5.43 second or t = 0.49 second

Therefore...

the value of t = 0.49 seconds shows that its upward journey

and

at t = 5.43 seconds shows in downward journey

The net torque acting on the board due to the four forces is 36.1 N·CM in the clockwise direction.

To calculate the torques acting on the board, we need to first determine the forces acting on the board due to the two weights.

Let's start by calculating the force due to the 366 G weight hanging from the 70 CM point:

Force1 = (366 G) x (9.81 m/s^2) = 3.59 N

The force due to the 183 G weight hanging from the 10 CM point is:

Force2 = (183 G) x (9.81 m/s^2) = 1.79 N

Now we can calculate the torques due to these forces. The torque due to a force is equal to the force multiplied by the distance between the force and the pivot point.

For the 366 G weight at 70 CM:

Torque1 = Force1 x (100 CM - 70 CM) = 3.59 N x 30 CM = 107.7 N·CM

For the 183 G weight at 10 CM:

Torque2 = Force2 x (10 CM - 50 CM) = 1.79 N x (-40 CM) = -71.6 N·CM

To calculate the net torque acting on the board, we need to add the clockwise and counterclockwise torques:

Net torque = Torque1 + Torque2

= 107.7 N·CM + (-71.6 N·CM)

= 36.1 N·CM

Therefore, the net torque acting on the board due to the four forces would be 36.1 N·CM in the clockwise direction.

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Answer:

1.08 ×10^9 N attraction

Explanation:

By employing Columbs law of force between charge .the force is defined as;

F = KQ1Q2/ r2

= 9×10^9 ×80×40×(6×10^-6) / 0.4 ^2

= 1.08 ×10^9 N

K = 9×10^9 N m2/C2

Answer:

A. True, I think

Explanation:

Two factors that determine the amount of electricity that can be generated by an individual hydroelectric power plants - It depends on the vertical distance through which the water falls and the flow rate, or amount of water that flows past a certain point per unit time, The greater the distance that the water falls, the more potential energy it had and the more electricity is generated the more kinetic energy it has and the more .

Impoundment, diversion, and pumped storage facilities are the three different types of hydroelectric facilities. Hydropower plants vary in their utilisation of dams. Despite the fact that not all dams were constructed for hydropower, they have been successful in supplying vast amounts of renewable energy to the grid. As of 2020, fewer than 2,300 of the more than 90,000 dams in the United States were producing electricity. The other dams are utilised for water supply, irrigation, flood control, stock/farm ponds, and recreation. Hydropower facilities come in a variety of sizes, from modest initiatives providing electricity for a single house or community to massive undertakings. 

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Answer:

the data change decreased and then increased. this went on repeatly but the decrease became less as the increase became more.

Answer:

2.8 would be the correct answer as 1 rounds down

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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The speed of the ball at launch is 23m/s.

After 0.5 seconds, the ball initially passed the pole.

Then it will again reach the top of the pole after 4.1 seconds.

Consequently, the ball's travel time above the pole is

Δt  = 4.1 - 0.5 = 3.6sec

Now the time it will take to reach the highest point from the top of the pole is given as t = Δt/2 = 1.8sec.

Now the total time to reach the top from the bottom is given as 2.3sec.

After 0.5 seconds, the ball initially passed the pole.

Consequently, the ball's travel time above the pole is

\(v_{f} - v_{i} = at\)

\(v_{i}=22.54m/s\)

also the speed after 0.5 s is

\(v_{f} = 17.64m/s\)

So, the speed of the ball at launch is 23m/s.

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The rocket movement due to the direction between a and b, and turning on the engine, movement is described by E image

Is continuously increasing, the force is constant and the acceleration too, which means that the speed continues increasing

Answer:

A

I say this because exponential growth takes place when a population per Capita growth stays the same

The Kinetic energy possessed by the cycle with a mass of 100 kg and velocity 40 m/s is 80 kJ.

Kinetic energy is the energy of an object when the object is in motion. It is obtained by the product of the mass of the object and the velocity of the object. The unit of kinetic energy is the joule (J).

From the given,

mass of the motorcycle (m) = 100 kg

velocity (v) = 40 m/s

K.E =?

K.E = (mv²) / 2

     = (100×40×40) / 2

    = 160,000 / 2

   = 80,000 J

Thus, the kinetic energy of the motorcycle is 80kJ.

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Interpolation refers to determining a value within an established dataset. In the context of the spring stretch experiment, the value 'Force = 4.4 N, stretch = 7.9 cm' is considered an interpolated value as it falls within the used force range (0N to 5N). The other values are either used in the experiment or extrapolations.

In this context, interpolation refers to the process of determining a value within an existing data set or between two known values. In your given data for the spring stretch experiment, the force values used in the experiment range from 0N to 5N. As such, an interpolated value would need to fall within this range.

Given that, the value Force = 4.4 N, stretch = 7.9 cm would be considered an interpolation because it falls within the known values used in the experiment. The rest of the options are either values used in the experiment (0 N, 3 N) or extrapolation (5.2 N) as they are outside of the range of force investigated.

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Considering the values from the experiment, the interpolated value between the known points on the graph is 'Force = 4.4 N, stretch = 7.9 cm', since it falls within the range of given values.

In the context of this laboratory experiment, interpolation refers to predicting a value within a range of known values. From the given points plotted on the graph, the values of force range from 0 N to 5 N, and the corresponding stretch ranges from 0 cm to 9.1 cm. Looking at the listed options, the value Force = 4.4 N, stretch = 7.9 cm falls within these known ranges of both force and stretch, thereby qualifying as an interpolation.

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The relationship between the speed, wavelength and frequency of light is:

where c is the speed of light

λ is the wavelength

and f is the frequency

From the question:

Therefore, the wavelength of the photon of light is

Answer:

\(3.34 * 10^{-2}\)

Explanation:

Scientific notation is writing a number between 1 and 10, and multiplying the number by a power of 10.

Our number is 0.0334

Let's move the decimal point of the number to make it so that the number is at least 1 and less than 10.

We get: 3.34

We moved the decimal point 2 places to the right, so the power of 10 would be -2

Putting what we got together, the scientific notation for the number is:

\(3.34 * 10^{-2}\)

Answer: See the diagram,from the vevtor addition we can say,net force acting on the apple is =

√

2.25

2

+

1.05

2

+

2

⋅

2.25

⋅

1.05

cos

90

=

2.48

N

And,this resultant force makes an angle of

tan

−

1

(

1.05

2.25

)

or,

25

degrees w.r.t vertical

Answer:

Yes, the object will turn.

Explanation:

The object will turn because there is an net clockwise moment of 5 Nm and an anti-clockwise moment of 10 Nm, resulting in a net clockwise moment of 5 Nm. According to the laws of physics, an object will rotate in the direction of the net torque acting upon it. In this case, the net torque is acting in a clockwise direction, causing the object to rotate in that direction.

The focal length of the concave mirror is approximately option B. 8.20 cm,

To solve this problem, we can use the mirror equation, which relates the object distance (d_o), image distance (d_i), and the focal length (f) of a concave mirror. The equation is:

1/f = 1/d_o + 1/d_i

Given the object distance (d_o) is 12.2 cm and the image distance (d_i) is 25.0 cm, we can plug in these values to find the focal length (f):

1/f = 1/12.2 + 1/25.0

To solve for f, first find the common denominator and combine the fractions:

1/f = (25 + 12.2) / (12.2 * 25) = 37.2 / 305

Now, take the reciprocal of both sides to isolate f:

f = 305 / 37.2

After calculating, we get:

f ≈ 8.20 cm

Thus, the focal length of the concave mirror is approximately 8.20 cm, Therefore the correct option to option b.

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a) Minimum speed required for the riders so that they stay pinned against the inside of the drum is 18m/s.

b) Angular velocity of the drum at this speed having diameter of the drum is 10 m is 3.6 rad/s

Friction is a resistance to motion of the object. for example, when a body slides on horizontal surface in positive x direction, it has friction in negative x direction and that measure of friction is a frictional force.

frictional force is directly proportional to the Normal(N).

i.e. \(F_{fri}\) ∝ N

\(F_{fri}\) = μN

where μ is called as coefficient of the friction. It is a dimensionless quantity.

When a body is kept on horizontal surface, its normal will be straight upward which is reaction of mg. i.e. N=mg.

Given,

Diameter of the drum D = 10m , Radius r = 5m

Coefficient of static friction = 0.15

a) To stay everyone pinned against the wall of drum. Frictional Force must be equal to weight mg which are opposite to each other.

μN = mg ........1)

Centrifugal acceleration = Normal

mv²÷r = N

With this equation 1 becomes

μ\(\frac{mv^{2} }{r}\) = mg

v² = rg÷μ

v² = 5m*9.8m/s ÷ 0.15

v² = 326.6

v= \(\sqrt{326.6}\) = 18.07 ~ 18 m/s

Hence minimum speed required for the riders is 18m/s.

b) for angular velocity of the drum, V=rω

ω = v÷r

ω = 18m/s ÷ 5m

ω = 3.6 rad/s

hence angular velocity of the drum at 18m/s speed is 3.6 rad/s

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