Answer:
It is the ratio of the density of a substance to the density of a given reference material.
Explanation:
Specific gravity is also known as relative density.
To find the relative density of substance, you:
Divide the density of substance measuredAnd divide that by the density of the referenceCalculate the molar heat capacity at pressure and volume constant ( ) when knowing = = 1.4 and the gas density: 0 = 1.3 /3 .
(a) The molar heat capacity at pressure is 29.1 J/K.mol.
(b) The molar heat capacity at volume is 20.785 J/K.mol.
Molar heat capacity of gas at volumeMolar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its volume is constant.
Cv = R/(γ - 1)
where;
R is universal gas constant = 8.314 J/K.mol.γ is heat ratio = 1.4Cv = (8.314) / (1.4 - 1)
Cv = 20.785 J/K.mol
Molar heat capacity of gas at pressureMolar heat capacity of a gas at constant volume is defined as the quantity of heat required to raise the temperature of one mole of the gas by 1 degree Kelvin when its pressure is constant.
γ = Cp/Cv
Cp = γCv
Cp = 1.4 x 20.785
Cp = 29.1 J/K.mol
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Image shows question, please help
Jonathan needs to maintain a separation of 0.543 mm between the plates to get the desired charge, and a dielectric constant of 92.6 to achieve a separation of 5 mm with a dielectric.
(a) Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can solve for the capacitance: C = Q/V =\((8.15 x 10^-9 C) / (50 V) = 1.63 x 10^-10 F.\)
Then, using the formula for capacitance of parallel plate capacitors: C = ε0A/d, where ε0 is the permittivity of free space, A is the area of the plates, and d is the separation distance, we can solve for the separation distance: d =\(_{3}OA/C = (8.85 x 10^-12 F/m) x (0.01 m^2) / (1.63 x 10^-10 F) = 0.543 mm.\)
(b) To find the dielectric constant, we can use the formula for capacitance of a parallel plate capacitor with a dielectric: C = εrε0A/d, where εr is the relative permittivity or dielectric constant of the material. Solving for εr, we get: εr = Cd / ε0A = \((1.63 x 10^-10 F)\) x (0.005 m) / \((8.85 x 10^-12 F/m)\) x \((0.01 m^2)\) = 92.6.
Therefore, Jonathan should use a dielectric with a relative permittivity of 92.6 to achieve a separation of 5 mm.
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A sample of vegetable oil with density 913 kg/m3 is found to have a mass of 0.0365 kg. Find the volume of this sample
The volume of the vegetable oil is 0.00003998 m³.
The density of vegetable oil,
ρ = 913 kg/m³
The mass of vegetable oil,
m = 0.0365 kg
To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.
The formula for density is:
ρ = m/V
where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:
V = m/ρSubstituting the given values of mass and density in the above formula,
We get:
V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)
Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.
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You position two plane mirriors at right angles to each other a light ray strikes one mirrior at an angle of 60 to the normal and reflects towards the second mirrior what is the angle of reflection off the second mirrior
Answer:
30 degrees
Explanation:
Reflects off of mirror 1 at 60 degrees....this makes it incident to second mirror at 30 degrees ....then angle of reflection equals this angle of incidence = 30 degrees
See atached diagram
To reduce auto emissions in the United States, modifications to automobile engines have been required since the 1960s.
a) true
b) false
Answer:
True
Explanation:
10- A block attached to a spring oscillates in simple harmonic motion along the x axis. The
limits of its motion are x = 10cm and x = 50 cm and it goes from one of these extremes to
the other in 0.25 s. Its amplitude and frequency are:
A 40 cm. 2Hz
B. 20 cm, 4Hz
C. 40cm, 2Hz
D. 25 cm, 4Hz
E. 20 cm, 2Hz
Answer:
Choice E.
Amplitude: \(20\; {\rm cm}\).
Frequency: \(2\; {\rm Hz}\).
Explanation:
The amplitude of a simple harmonic motion (SHM) is the maximum displacement from equilibrium.
In this question, the equilibrium is in the center of the two extremes. With one extreme at \(x = 10\; {\rm cm}\) and the other at \(x = 50\; {\rm cm}\), the center will be at \((1/2)\, (10 + 50)\; {\rm cm} = 30\; {\rm cm}\).
The maximum displacement will be \((50\; {\rm cm} - 30\; {\rm cm}) = 20\; {\rm cm}\) (or equivalently, \((30\; {\rm cm} - 10\; {\rm cm}) = 20\; {\rm cm}\).
Frequency measures the number of cycles completed in unit time (e.g., one second.) In one full cycle of an SHM, the oscillator will travel from one extreme to another and then back to the original extreme. In this question:
Travel from one extreme to the other: \(0.25\; {\rm s}\).Travel from the other extreme back to the original one: \(0.25\; {\rm s}\).In other words, one full cycle of this SHM will take \(0.25\; {\rm s} + 0.25\; {\rm s} = 0.50\; {\rm s}\). The period of this SHM will be \(0.50\; {\rm s}\). Hence, the frequency of this SHM will be:
\(\begin{aligned} (\text{frequency}) &= \frac{1}{(\text{period})} \\ &= \frac{1}{0.50\; {\rm s}} \\ &= 2\; {\rm Hz}\end{aligned}\).
At time t = 0 s, a puck is sliding on a horizontal table with a velocity 3.60 m/s, 35.0° above the +x axis. As the puck slides, a constant acceleration acts on it that has the following components: a = - 2 0.360 m/s and da, = -0.980 m/s. What is the velocity of the puck at time t = 1.50 s? 2 0
The velocity of the punk at time t = 1.5 s is equal to 2.47 m/s.
What are the components of velocity?The object will have two velocities during the projectile motion, one is horizontal velocity and the other is vertical velocity. The horizontal velocity of the object is constant throughout the projectile motion but the vertical velocity is changed in the projectile motion.
Given that the velocity vector is making an angle θ with a horizontal table, θ = 35°
The vertical component of the velocity of the puck can be determined as:\(u_x = u Sin 35^o = 3.60 \times 0.573 =2.06 m/s\)
The horizontal component of the velocity of the puck can be determined as:
\(u_y = u cos 35^o = 3.60 \times 0.82=2.95 m/s\)
Given the acceleration aₓ = -0.360 m/s² and a y = -0.980 m/s²
The final vertical components of the velocity of the punk are:
\(v_x = u_x + a_xt\)
\(v_x = 2.95 - (0.360) (1.5)\\v_x = 2.41 m/s\)
and, the horizontal velocity of the punk is:
\(v_y = u_y +a_yt\\v_y = 2.06 - (0.980) (1.5)\\v_y = 0.59 m/s\)
The velocity of the punk can be determined as:
\(v = \sqrt{v_x^2 + v_y ^2}\\ v =\sqrt{(5.80)^2 + (0.35)^2}\\ v = 2.47 m/s\)
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how much time is required for a bicycle to travel a distance of 100 m at an avreage speed
A bicycle traveling at an average speed of 2 mi./s will be take time 0.031 seconds to travel a distance of 100 m.
The average speed of 2 mi./s cannot be used to calculate the time required to travel a distance of 100 m because the units are not consistent.
To solve this problem, we need to convert the speed from miles per second to meters per second, as follows:
1 mile = 1609.34 meters
1 second = 1 second
Therefore, 2 mi./s can be converted to meters per second as:
2 mi./s * 1609.34 m/mi = 3218.68 m/s
Now we can use the formula
distance = speed × time
to find the time required to travel 100 m at this speed:
time = distance / speed
time = 100 m / 3218.68 m/s
time=0.031 s
Therefore, a bicycle traveling at an average speed of 2 mi./s would take approximately 0.031 seconds to travel a distance of 100 m.
The complete questions is,
How much time is required for a bicycle to travel a distance of 100 m at an average speed of 2 mi./s?
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PLEASE HELP!!!!
An object is launched horizontally from a cliff. The cliff is 80 m high and the object has an initial launch velocity of 50 m/s.
What is the initial horizontal velocity?
What is the initial vertical velocity?
What is the final horizontal velocity?
How much time did it take for the object to hit the ground?
What is the final vertical velocity?
What is the final resultant speed?
How far from the base of the cliff will the projectile land?
Answer:
a. 50 m/s b. 0 m/s c. 50 m/s d. 4.04 s e. -39.6 m/s f. 63.78 m/s g. 202 m
Explanation:
a. What is the initial horizontal velocity?
Since the object is launched horizontally, it initial horizontal velocity is 50 m/s
b. What is the initial vertical velocity?
Since the object is launched horizontally, it has no initial vertical component. So, its initial vertical velocity is 0 m/s
c. What is the final horizontal velocity?
Its final horizontal velocity is 50 m/s since no force acts on it in the horizontal direction to change its value.
d. How much time did it take for the object to hit the ground?
We use the equation s = ut - 1/gt² since the object is falling under gravity where u = initial vertical velocity = 0 m/s, s = height of cliff = 80 m, g = acceleration due to gravity = -9.8 m/s² and t = time it takes the object to hit the ground.
s = ut - 1/2gt²
80 m = 0 × t - 1/2 × -9.8 m/s² × t²
80 m = 4.9 m/s² × t²
t² = 80 m ÷ 4.9 m/s²
t² = 16.33 s²
t = √(16.33 s²)
t = 4.04 s
e. What is the final vertical velocity?
Using v = u + at where u = initial vertical velocity = 0 m/s, v = final vertical velocity, a = acceleration = -g = -9.8 m/s²and t = time it takes object to reach the ground = 4.04 s.
Substituting these values into the equation, we have
v = u + at
v = 0 m/s + (-9.8 m/s²) × 4.04 s
v = -39.6 m/s
f. What is the final resultant speed?
The final resultant speed v' is the resultant of the final horizontal velocity and the final vertical velocity. Let u' = final vertical velocity = 50 m/s.
v' = √(u'² + v²)
v' = √((50 m/s)² + (-39.6 m/s)²)
v' = √(2500 m²/s² + 1568.16 m²/s²)
v' = √(4068.16 m²/s²)
v' = 63.78 m/s
g. How far from the base of the cliff will the projectile land?
The distance from the base of the cliff, d where the projectile lands is
d = u't where u' = horizontal velocity = 50 m/s and t = time it takes object to land = 4.04 s
d = 50 m/s × 4.04 s
d = 202 m
Describe 3 Levers of Power and how they work.
DESCRIBE
WILL GIVE BRAINLIEST!!!!
How many revolutions around the Sun does Uranus complete by the time Jupiter finishes its orbit?
Answer:
0
Explanation:
it takes 84 years for Uranus to orbit the Sun. It only takes 12 years for Jupiter to orbit the Sun. So technically by the time that Jupiter finishes it's one, Uranus will not be able to even finish half of its orbit.
From fastest to slowest, which of the following lists describes the speed at which sound tends to travel in different materials?
A. Gases, solids, liquids
B. Gases, liquids, solids
C. Solids, liquids, gases
D. Solids, gases, liquids
Answer:
C. Solids,Liquids, Gases
what is the pressure of a tank of uniform cross sectional area 4.0m2 when the tank is filled with water a depth of 6m when given that 1 atm=1.013 x 10^5pa density of water=1000kgm-3 g=9.8m/s2
The pressure of the tank, when filled with water at a depth of 6 m, is approximately 580.124 atmospheres (atm). To calculate the pressure of the tank, one can use the equation: Pressure (P) = Density (ρ) × g × Depth (h)
Pressure (P) = Density (ρ) × g × Depth (h)
Given: Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Depth (h) = 6 m
Using the given values, one can calculate the pressure:
Pressure = 1000 kg/m³ × 9.8 m/s² × 6 m Pressure
= 58800 kg·m⁻¹·s⁻²
Now, let's convert the units to pascals (Pa) using the conversion 1 atm = 1.013 x \(10^5\) Pa:
Pressure = 58800 kg·m⁻¹·s⁻² × (1 atm / 1.013 x\(10^5\) Pa)
Pressure = 580.124 atm
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what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm
Answer:
75 cm/second.
Explanation:
Formula:
Walking speed = stride length / time per step
Walking speed = 90cm/time per step
= 90cm/1.2 seconds (a common estimate time per step)
= 75cm/second.
What is scintillator
Answer:
Scintillators are materials that are able to convert high energy radiation such as X or gamma-rays to a near visible or visible light. They are widely used as detectors in medical diagnostics, high energy physics and geophysical exploration (ref. Knoll).
https://web.stanford.edu › scintillators
What are scintillator materials? - Stanford: Advanced Optical Ceramics Laboratory
Push: Explain Newton's Third Law
Explain how a rocket taking off can be an example of Newton's Third Law of Motion.
Every action have equal and opposite reaction. for example when we fire bullet from a gun, the gun will recoil back and bullet moves forward. In case of rocket, rocket is fired, thrust is reaction of force applied by the gas on the floor.
A push or a pull that an object experiences as a result of interacting with another item is known as a force. Interactions result in forces! As was covered in Lesson 2, certain forces are the result of contact interactions (reaction, frictional, tensional, and applied forces are examples of contact forces), whilst other forces (gravitational, electrical, and magnetic forces) are the consequence of action-at-a-distance interactions. Newton postulated that whenever objects A and B interact, they exert forces on one another. You put a downward force on the chair when you sit on it, and the chair responds by exerting an upward force on your body. This contact creates two forces: one force on the chair and one force on your body.
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A Boeing 787 is initially moving down the runway at 6.0 m/s preparing for takeoff. The pilot pulls on the throttle so that the engines give the plane a constant acceleration of 1.9 m/s2. The plane then travels a distance of 1700 m down the runway before lifting off. How long does it take from the application of the acceleration until the plane lifts off, becoming airborne
Answer:
39.26 s
Explanation:
From the question given above, the following data were obtainedb
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Distance travelled (s) = 1700 m
Time (t) =?
Next, we shall determine the final velocity of the plane. This can be obtained as follow:
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Distance travelled (s) = 1700 m
Final velocity (v) =?
v² = u² + 2as
v² = 6² + (2 × 1.9 × 1700)
v² = 36 + 6460
v² = 6496
Take the square root of both side
v = √6496
v = 80.6 m/s
Finally, we shall determine the time taken before the plane lifts off. This can be obtained as follow:
Initial velocity (u) = 6 m/s
Acceleration (a) = 1.9 m/s²
Final velocity (v) = 80.6 m/s
Time (t) =?
v = u + at
80.6 = 6 + 1.9t
Collect like terms
80.6 – 6 = 1.9t
74.6 = 1.9t
Divide both side by 1.9
t = 74.6 / 1.9
t = 39.26 s
This, it will take 39.26 s before the plane lifts off.
It takes the Earth 24 hours to make a complete rotation around its axis. 33% Part (a) What is the period of rotation of the Earth in seconds? Grade Summary Deductions0 Potential 100 sin cotan) coso asin) atano acotan) sinh0 tan) acoso Attempts remaining per antemp4) detailed vie cosh0 tanhO cotanhO ODegrees O Radians Hint I give up Hints:-% deduction per hint. Hints remaining:- Feedback: dohction per fcedback ▲ 33% Part (b) What is the angular velocity of the Earth in rad/s? 33% Part (c) Given that Earth has a radius of 6.4 x 106 m at its equator, what is the linear velocity at Earth's surface?
Answer:
Explanation:
a )
one rotation per 24 hours
Time period of rotation of the earth T = time / no of rotation
T = 24 x 60 x 60 s / 1
= 86400 s .
b )
angular velocity = angle of rotation in radian / time
in one rotation , angle made at the centre = 2π radian
= 2 x 3.14 radian
angular velocity ω = 2π / T
= 2 x 3.14 / 86400 radian / s
= 72.68 x 10⁻⁶ radian / s
c )
Relation between linear and angular velocity is as follows
v = ω x R where R is radius of the earth and v is linear velocity .
linear velocity = 72.68 x 10⁻⁶ x 6.4 x 10⁶ m /s
= 465.152 m /s
=
Can u show me were these go on the picture:
Inner core
Crust/lithosphere
Lower mantle
Outer core
Upper mantle
Crust
Asthenosphere
Answer:
Here u go
Explanation:
HELP ASAP!!!!!!
If a car goes along a straight road heading east and speeds up from 45 ft/s to 60 ft/s in 5 s, calculate the acceleration.
fus 2
a=
Note: If the speed were given in miles per hour, and the time were given in minutes, you could change the minutes to a
fraction of an hour and do the problem. The answer would be in miles/h².
Answer:
3ft/s²
Explanation:
\(a = \frac{60 - 45}{5} = 3ft \div {s}^{2} \)
Spontaneous process of drying of leaves
The spontaneous drying of leaves occurs due to the loss of moisture through evaporation, primarily facilitated by transpiration and environmental factors such as temperature, humidity, and airflow. Aging and senescence also contribute to the process.
The spontaneous process of drying leaves, also known as desiccation, is a natural occurrence that takes place as a result of various factors. Primarily, it involves the loss of moisture from the leaf tissues through evaporation. Leaves have specialized structures called stomata, small openings on their surfaces, which facilitate the exchange of gases, including water vapor.
When environmental conditions such as high temperature, low humidity, and increased airflow prevail, water molecules escape through the stomata into the surrounding air. This process, called transpiration, plays a significant role in leaf drying. Additionally, sunlight accelerates the rate of evaporation by providing energy to convert water into vapor.
As moisture content decreases, the cell walls of the leaf tissues contract, causing the leaf to become dehydrated and eventually dry. The process is also influenced by the plant's natural aging and senescence, where the leaf undergoes programmed cell death.
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A force F with arrow applied to an object of mass m1 produces an acceleration of 3.10 m/s2. The same force applied to a second object of mass m2 produces an acceleration of 1.80 m/s2.(a) What is the value of the ratio m1/m2?(b) If m1 and m2 are combined into one object, find its acceleration under the action of the force F with arrow.
Answer:
(a) The value of the ratio m₁/m₂ is 0.581
(b) the acceleration of the combined masses is 1.139 m/s²
Explanation:
Given;
The acceleration of force applied to M₁, a₁ = 3.10 m/s²
The same force applied to M₂ has acceleration, a₂ = 1.80 m/s²
Let this force = F
According Newton's second law of motion;
F = ma
(a) the value of the ratio m₁/m₂
since the applied force is same in both cases, M₁a₁ = M₂a₂
\(\frac{m_1}{m_2} = \frac{a_2}{a_1} \\\\\frac{m_1}{m_2} = \frac{1.8}{3.1} \\\\\frac{m_1}{m_2} = 0.581\)
(b) the acceleration of m₁ and m₂ combined as one object under the action force F
F = ma
\(a = \frac{F}{M} \\\\a = \frac{F}{m_1 + m_2} \\\\a = \frac{F}{0.581m_2 + m_2}\\\\a = \frac{F}{1.581m_2}\)
\(But, m_2 = \frac{F}{a_2} \\\\a = \frac{F}{1.581m_2} = \frac{F*a_2}{1.581F} \\\\a = \frac{a_2}{1.581} \\\\a = \frac{1.8}{1.581} = 1.139 \ m/s^2\)
Therefore, the acceleration of the combined masses is 1.139 m/s²
a. The value of the ratio is 0.581.
b. The acceleration should be \(1.139 m/s^2\)
Newton's second law of motion:Since
The acceleration of force applied to \(M_1,a_1 = 3.10 m/s^2\)
The same force applied to\(M_2\) has acceleration, \(a_2 = 1.80 m/s^2\)
Here we assume force be F
Now we know that
F = ma
a. The ratio should be
\(m_1\div m_2 = a_2\div a_1\\\\m_1\div m_2 = 1.8\div 3.1\)
= 0.581
b. The acceleration should be
f = ma
a = F/m
\(a = f/m_1+m_2\\\\= F/0.581 + m_2\\\\=F/1.581m_2\)
However \(m_2 = F/a_2\)
So,
\(a = F\div 1.581m_2\\\\= f\times a_2/1.581F\\\\= a_2/1.581\\\\= 1.8/1.581\\\\= 1.139 m/s^2\)
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A safety plug is designed to melt when the pressure inside a metal tank becomes too high. A gas
at 51.0 atm and a temperature of 23.0°C is contained in the tank, but the plug melts when the
pressure reaches 75.0 atm. What temperature did the gas reach?
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion:
s = 4/t^2, where t is measured in seconds.
Required:
Find the velocity of the particle at times t = a, t = 1, t = 2, and t = 3.
Answer:
At \(t = 1\; \rm s\), the particle should have a velocity of \(-8\; \rm m \cdot s^{-1}\).At \(t = 2\; \rm s\), the particle should have a velocity of \(-1\; \rm m \cdot s^{-1}\).At \(t = 3\; \rm s\), the particle should have a velocity of \(\displaystyle -\frac{8}{27}\; \rm m \cdot s^{-1}\).For \(a > 0\), at \(t = a \; \text{second}\), the particle should have a velocity of \(\displaystyle -\frac{8}{a^3}\; \rm m \cdot s^{-1}\).
Explanation:
Differentiate the displacement of an object (with respect to time) to find the object's velocity.
Note that the in this question, the expression for displacement is undefined (and not differentiable) when \(t\) is equal to zero. For \(t > 0\):
\(\begin{aligned}v &= \frac{\rm d}{{\rm d}t}\, [s] = \frac{\rm d}{{\rm d}t}\, \left[\frac{4}{t^2}\right] \\ &= \frac{\rm d}{{\rm d}t}\, \left[4\, t^{-2}\right] = 4\, \left((-2)\, t^{-3}\right) = -8\, t^{-3} =-\frac{8}{t^3}\end{aligned}\).
This expression can then be evaluated at \(t = 1\), \(t = 2\), and \(t = 3\) to obtain the required results.
A slanted surface used to raise an object is a(n)
Answer:
Inclined Plane
Explanation:
You are holding a finishing sander with your right hand. THe sander has a flywheel which spins counterclockwise as seen from behind the handle. You are sanding a wall in front of you. as you turn the sander towards the right, you feel a tendency in the sander to...
a. pull away from you
b. turn towards the left
c. turn downward
d. turn upward
e. push toward you
Answer:
c. turn downward
Explanation:
From the information given:
To find the tendency of the sander;
We need to apply the right-hand rule torque; whereby we consider the direction of the flywheel, the direction at which the torque is acting, and the movement of the sander toward the right.
Since the flywheel of the sander is in counterclockwise movement, hence the torque direction will be outward placing on the wall. However, provided that the movement of the sander is toward the right, then there exists an opposite force that turns downward which showcases the tendency in the sander is downward.
A compact car can climb a hill in 10 s. The top of the hill is 30 m higher than the
bottom, and the car's mass is 1,000 kg What is the power output of the car?
Answer:
29.4 kW
Explanation:
time t = 10 s, height h = 30 m, mass m = 1,000 kg
power output = work done/time
work done = increase in potential energy = mgh = 1,000 * 9.8 * 30 = 294,000 J = 294 kJ
power output = 294/10 = 29.4 kW
A He-Ne laser produces 633 nm light.
When it passes through a diffraction
grating with d = 5.55 x 10^-6 m, what is
the angle of its third order (m = 3)
maximum?
Answer:
20.0086
Explanation:sin^-1(3×633×10^-9)÷5.55×10^-6Answer:
20.0086
Explanation:
Acellus
an airplane travels down a Runway at 1500 m in 17s what is the average speed
Answer:
88.23 m/s
Explanation: The equation for speed is s=d/t so in other words, speed equals distance over time so the distance is 1500 and the time is 17 seconds so you just devide 1500 by 17 and you get the speed. Remember to include your unit m/s after your answer
A 3.5 kilogram cannon is loaded with a 0.52-kilogram ball. The cannon and ball are initially rolling forward with a speed of 1.27 m/s. The cannon is fired and launches the ball forward with a total speed of 75 m/s. Determine the post-explosion velocity of the cannon.
The cannon's forward post-explosion velocity is 6.18 m/s.
What are the fundamentals of momentum?Momentum is the force necessary to bring an item to a complete halt in a unit of time and is determined by multiplying an object's mass by its velocity. The overall momentum is equal to the sum of the individual momenta for any array of multiple objects.
Total momentum before = Total momentum after
(3.5 kg + 0.52 kg) × 1.27 m/s = 3.5 kg × v_cannon + 0.52 kg × 75 m/s
where v_cannon is the velocity of the cannon after the explosion.
Simplifying and solving for v_cannon, we get:
v_cannon = (0.52 kg × 75 m/s - (3.5 kg + 0.52 kg) × 1.27 m/s) / 3.5 kg
v_cannon = 6.18 m/s.
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