what is the answer to −4.2+3.3=
Answers
answer: -0.9
correct me if I'm wrong
Related Questions
Sobre una embarcación de 160 kg que está en reposo con su proa apuntando a la orilla, comienza a caminar una persona de 70 kg desde la proa hacia la popa, a 0.80 m/s respecto a la embarcación. ¿Cuáles son las velocidades de la embarcación y de la persona respecto a la orilla? Desprecia la resistencia del agua al movimiento.
Answers
The velocities of the boat and the person relative to the shore are 1.337 m/s and 2.896 m/s, respectively.
How to calculate the velocityWe can use the conservation of momentum equation:
(mboat + mperson) * vboat = mperson * vperson
(160 kg + 70 kg) * vboat = 70 kg * (0.80 m/s + vperson)
230 kg * vboat = 56 kg * (0.80 m/s + vperson)
vboat = (56/230) * (0.80 m/s + vperson)
vperson = 0.80 m/s + vboat
vperson = 0.80 m/s + (56/230) * (0.80 m/s + vperson)
(174/115) * vperson = (504/115) * m/s
Dividing both sides by (174/115), we get:
vperson = 2.896 m/s
vboat = (56/230) * (0.80 m/s + vperson)
Substituting the value of vperson, we get:
vboat = 1.337 m/s
Learn more about velocity on
https://brainly.com/question/25749514
#SPJ1
On a 160-kg boat that is at rest with its bow pointed to the shore, a 70-kg person begins to walk from the bow to the stern at 0.80 m/s relative to the boat. What are the velocities of the boat and the person relative to the shore? Neglect the resistance of water to motion.
Find the value of x
8,
9,
7,
10
Answers
The value of x in this problem, considering the intersecting chords, is given as follows:
x = 10.
How to obtain the value of x?A chord of a circle is a straight line segment that connects two points on the circle, that is, it is a line segment whose endpoints are on the circumference of a circle.
When two chords intersect each other, then the products of the measures of the segments of the chords are equal.
Hence the value of x is obtained as follows:
12x = 15 x 8
12x = 120
x = 10.
More can be learned about the chords of a circle at brainly.com/question/16636441
#SPJ1
Complete the proof. Given LM¯¯¯¯¯¯¯¯¯≅JK¯¯¯¯¯¯¯¯, MJ¯¯¯¯¯¯¯¯≅KL¯¯¯¯¯¯¯¯ Prove △LMJ≅△JKL
Answers
Here is the proof :-
LM=JKMJ=KLSo
Adjacent angle is also equal
<LMJ=<JKLHence
∆LMJ=∆JKL(SAS)
g The pH measurements of water specimens from various locations along a given river basin are Normally distributed, with mean 8 and standard deviation 0.3. You take water specimens from four randomly selected locations on this river basin. What is the probability that the mean pH measurement of these four specimens is greater than 8.2
Answers
Answer:
0.0918 = 9.18% probability that the mean pH measurement of these four specimens is greater than 8.2
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean \(\mu\) and standard deviation \(\sigma\), the z-score of a measure X is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \(\mu\) and standard deviation \(\sigma\), the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \(\mu\) and standard deviation \(s = \frac{\sigma}{\sqrt{n}}\).
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean 8 and standard deviation 0.3.
This means that \(\mu = 8, \sigma = 0.3\)
Sample of 4:
This means that \(n = 4, s = \frac{0.3}{\sqrt{4}} = 0.15\)
What is the probability that the mean pH measurement of these four specimens is greater than 8.2?
This is 1 subtracted by the pvalue of Z when X = 8.2. So
\(Z = \frac{X - \mu}{\sigma}\)
By the Central Limit Theorem
\(Z = \frac{X - \mu}{s}\)
\(Z = \frac{8.2 - 8}{0.15}\)
\(Z = 1.33\)
\(Z = 1.33\) has a pvalue of 0.9082
1 - 0.9082 = 0.0918
0.0918 = 9.18% probability that the mean pH measurement of these four specimens is greater than 8.2
Check all of the ordered pairs that satisfy the equation below.
A.
(21, )
B.
(7, 14)
C.
(21, 14)
D.
(42, 28)
E.
(14, 21)
F.
(28, 42)
Answers
Answer:
what is the y-coordinate for A?
Step-by-step explanation:
4.586 to the nearest cm
Answers
Answer:
See below.
Step-by-step explanation:
We are asked to round 4.586 cm to the nearest cm.
What is Rounding?
Rounding is a simple method used to change a number, and all of the numbers behind it to 0. Rounding is similar to an approximation, in order to show you how I should give you an example.
Example:
Round 459 to the hundreds place.
The hundreds place is where the 4 is. We should look at the 5.
Requirements necessary are that 5 needs to be greater than \(4.\bar{9}.\)
Because 5 is greater, we can round up to 500.
Rounding is an approximation because it's close to the actual number, in other words, inexact.
Let's use the example as a guide for our problem now.
4.586 to the nearest cm (ones place)
The ones place is the 4. We should look at the 5.
5 is greater than \(4.\bar{9}.\)
Because 5 is greater, we can round up to 5.000 cm.
Our final answer is 5.000 cm.
Will mark brainiest for CORRECT answer!
Answers
ANSWER: y = (1/2)x - 1.
To find the equation of the tangent line to the curve y = √(x - 3) at the point (4, 1), we need to determine the slope of the tangent line and its y-intercept.
First, let's find the derivative of the function y = √(x - 3) using the power rule:
dy/dx = 1/(2√(x - 3))
Now, we can substitute x = 4 into the derivative to find the slope of the tangent line at that point:
m = dy/dx = 1/(2√(4 - 3)) = 1/2
So, the slope of the tangent line is 1/2.
Next, we can use the point-slope form of a line to find the equation of the tangent line. Given the point (4, 1) and the slope m = 1/2, the equation becomes:
y - y1 = m(x - x1)
Substituting the values (x1, y1) = (4, 1):
y - 1 = (1/2)(x - 4)
Simplifying the equation:
y - 1 = (1/2)x - 2
y = (1/2)x - 1
Therefore, the equation of the tangent line to the curve y = √(x - 3) at the point (4, 1) is y = (1/2)x - 1.
Answer:
y = (1/2)x - 1/2
Step-by-step explanation:
Step 1: Find the derivative of the function
The derivative of a function gives the slope of the tangent line to the curve at any point. To find the derivative of the given function y = sqrt(x - 3), we can use the power rule of differentiation which states that:
d/dx (x^n) = nx^(n-1)
Applying this rule to our function, we get:
dy/dx = d/dx sqrt(x - 3)
To differentiate the square root function, we can use the chain rule of differentiation which states that:
d/dx f(g(x)) = f'(g(x)) * g'(x)
Applying this rule to our function, we have:
g(x) = x - 3
f(g) = sqrt(g)
So,
dy/dx = d/dx sqrt(x - 3) = f'(g(x)) * g'(x) = 1/(2*sqrt(g(x))) * 1
Substituting g(x) = x - 3, we get:
dy/dx = 1/(2*sqrt(x - 3))
So, the derivative of y with respect to x is 1/(2*sqrt(x - 3)).
Step 2: Evaluate the derivative at the given point
To find the slope of the tangent line at the point (4, 1), we need to substitute x = 4 into the derivative expression:
dy/dx = 1/(2*sqrt(4 - 3)) = 1/2
So, the slope of the tangent line at the point (4, 1) is 1/2.
Step 3: Use point-slope form to write the equation of the tangent line
Now that we know the slope of the tangent line at the point (4, 1), we can use point-slope form to write the equation of the tangent line. The point-slope form of a line is given by:
y - y1 = m(x - x1)
where (x1, y1) is the point on the line and m is the slope of the line.
Substituting the values x1 = 4, y1 = 1, and m = 1/2, we get:
y - 1 = (1/2)*(x - 4)
Simplifying this equation, we get:
y = (1/2)x - 1/2
So, the equation of the tangent line to the curve y = sqrt(x - 3) at the point (4, 1) is y = (1/2)x - 1/2.
Hope this helps!
Mrs. Rokava bought 2 quintals of apples in Jumla for Rs 17.000. She paid Rs 15 per kg for the transportation from Jumla to Nepalgunj. 10 kg of apples were damage and she sold the remaining quantity at Rs 120 per kg Calculate her profit or loss percent in the total transaction
Answers
Answer:
Step-by-step explanation:
2 quintals = 200 kg Rs 17.000
transport 200(15) Rs 3.000 +
Total investment Rs 20.000
sales (200 - 10)(120) Rs 22.800
profit 22.800 - 20.000 Rs 2.800
Use the Binomial Theorem to expand (c – 11)4. Question 4 options:c4 – 44c3 + 726c2 – 5324c + 1464111c4 + 44c3 + 726c2 + 5324c + 14641cc4 + 44c3 + 726c2 + 5324c + 14641c4 – 44c3 + 726c2 – 5324c + 14641
Answers
Answer:
\(c^4-44c^3+726c^2-5324c+14641\)Explanation:
The Binomial theorem is given by the formula;
\((x+y)^n=_{}\sum ^n_{k\mathop=0}nC_kx^{n-k}y^k\)Given the below;
\((c-11)^4\)We'll go ahead and use the Binomial theorem formula above to expand where;
\(\begin{gathered} x=c \\ y=-11 \\ n=4 \end{gathered}\)So we'll have;
\(\begin{gathered} (c-11)^4=_4C_0c^{4-0}(-11)^0+_4C_1c^{4-1}(-11)^1+_4C_2c^{4-2}(-11)^2+_4C_3c^{4-3}(-11)^3+_4C_4c^{4-4}(-11)^4 \\ =c^4-44c^3+726c^2-5324c+14641 \end{gathered}\)11. Jim travelled at a speed of 18km/h for 2 hours. What was the distance covered?
Answers
Answer:
d = 36 km
Step-by-step explanation:
Speed of Jim, v = 18 km/h
Time, t = 2 hours
We need to find the distance covered. We know that the speed of an object is equal to the distance covered by it divided by total time taken.
\(v=\dfrac{d}{t}\\\\d=v\times t\\\\d=18\ km/h\times 2\ h\\\\=36\ km\)
So, he will cover 36 km.
Find the side length, b.
Round to the nearest tenth.
C
a
BL
b
A
C
b = [?]
B = 90°
a = 6
C=7
![Find the side length, b.Round to the nearest tenth.CaBLbACb = [?]B = 90a = 6C=7](https://i5t5.c14.e2-1.dev/h-images-qa/contents/attachments/aNYVDg7ey4EH5J1dBnGf9645QlVlYe91.png)
Answers
Answer:
b = 9.2 (Rounded to the nearest tenth)
Step-by-step explanation:
ABC is a right-angled triangle at B.
Then ,according to the Pythagorean theorem:
\(b = \sqrt{a^2 + c^2}\)
\(= \sqrt{6^2 + 7^2}\)
\(= \sqrt{36 + 49}\)
\(= \sqrt{85}\)
\(=9.219544457293\)
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
for such more question on journal entries
https://brainly.com/question/28390337
#SPJ8
this question is for the southern hemisphere. for each direction (n, s, e, or w), pick the drawing that best describes how the stars appear to move above that point on the horizon.
Answers
The drawings that best describe the way the stars appear to move in the Southern Hemisphere on the horizon is:
North - DSouth - A East - E West - F What direction do the stars appear to move ?When in the Southern Hemisphere, the drawings would appear to move upwards when moving North. The stars would also appear to move down when moving to the South as shown in A.
The East would show drawings moving towards the right as shown in E and the West would show stars appearing to move to the left which is shown with Drawing F.
Find out more on stars at https://brainly.com/question/14666763
#SPJ1
please help asap correct answer will be brainlist
Answers
Answer:
x = 3 and y = - 1
Step-by-step explanation:
1a. 2x + y = 5 Solve for y in the first equation.
y = -2x + 5
1b. 2(-2x + 5) = 2x - 8
-4x + 10 = 2x - 8
-6x + 10 = -8
-6x = -18
1c. x = 3
2y = 2x - 8
2y = 2(3) - 8
2y = 6 - 8
2y = -2
y = -1
Check Use x = 3; y = -1
1d. 2x + y = 5 2y = 2x - 8
2(3) - 1 = 5 2(-1) = 2(3) - 8
6 - 1 = 5 -2 = 6 - 8
5 = 5 -2 = -2 Checked
Which equation represents a line that passes through (5, 1) and has a slope of StartFraction one-half EndFraction?
y – 5 = y minus 5 equals StartFraction one-half EndFraction left-parenthesis x minus 1 right-parenthesis.(x –1)
y – y minus StartFraction one-half EndFraction equals 5 left-parenthesis x minus 1 right-parenthesis. = 5(x –1)
y – 1 = y minus 1 equals StartFraction one-half EndFraction left-parenthesis x minus 5 right-parenthesis.(x –5)
y – 1 = 5y minus 1 equals 5 left-parenthesis x minus StartFraction one-half EndFraction right-parenthesis.
Answers
Step-by-step explanation:
Slope 1/2 point 5,1
in point slope form would be
(y-1) = 1/2 (x-5)
Graph makes no sense to me
Answers
Answer:
(a) 0
(b) 0
(c) 1
The function is not continous at x = 9
Step-by-step explanation:
To the left and right of the point x = 9, the graph would seem to continue at f(x) = 0, however on the exact point x = 9 there is a hole in the graph allowing it to be equal to 1. Due to the hole in the graph, it is not continuous
Apologies if this is wrong its been a bit since I did calculus
Question 4Mple Choice Worth 2 points)
Ares of Polygons and Composite Figures MC)
A composte figure is shown
024413
028.445²
1.15 in
Which of the following represents the total area of the figure?
010 663 ²
034.335 ²
4.6 in.
3h 563
P
Answers
The total area of the composite figure which has triangle and rectangle is 24.41 square inches
The given composite figure has two triangles and one rectangle
Area of rectangle =length × width
=4.6×3.15
=14.49 square inches
Area of left side triangle, it has base of 3.3 in and height 3.15 inches
Area of triangle = 1/2×3.3×3.15
=5.1975 square inches
Area of triangle on right side
Base = 3 in
Height = 6.3-3.15=3.15 in
Area of triangle = 1/2×3×3.15
=4.725 square inches
Total area = 14.49 + 5.1975 + 4.725
=24.41 square inches
To learn more on Areas click:
https://brainly.com/question/20693059
#SPJ1
The amount of vitamin C found in one cup of six
varieties of orange juice is shown below. What is the
median amount of vitamin C in the different varieties?
104 mg, 85 mg, 83 mg, 100 mg, 89 mg
Answers
Answer:
Question:The amount of vitamin C found in one cup of six varieties of orange juice is shown below. What is the median amount of vitamin C in the different varieties?104 mg, 85 mg, 83 mg, 100 mg, 89 mgSolution:First thing first, we've to arrange the data in an ascending order=> 83mg ,85mg ,89mg ,100 mg ,104 mg
Now ,Since the no. of observation is odd(here,5), we'd apply this formula\( = > (\frac{n + 1}{2})\)
Where ,n= No. of observations, Hence, the median of the above data\( = > ( \frac{5 + 1}{2}) \\ = > \frac{6}{2} \\ = > 3\)
is the third observation ↦89mg\( \\ \\ \)
Hope it helps
-------☆ﾟ.･｡ﾟᵴɒƙυᴚᴀ_ƨȶäᴎ❀
The median amount of vitamin C in the different varieties is 89mg.
what is median?The median is the value that's exactly in the middle of a dataset when it is ordered.
Given:
104, 85, 83, 100, 89
On arranging the given data:
83, 85, 89, 100, 104
as, the data is in odd number.
So,
median = (n+1)/2
=(5+1)/2
=3
The third element is 89.
Hence, the median amount of vitamin C in the different varieties is 89mg.
Learn more about median here:
https://brainly.com/question/28060453
#SPJ1
The account balance on April 1st is $50.51. On April 15th a payment of $15.00 is made. On April 25th a purchase of $19.27 is made. The annual rate is 18%. What is the unpaid balance? What is the finance charge using the unpaid balance method? What is the new balance? Unpaid balance = $ Finance charge = $ New balance = $
describe me in 3 words ;-;
Answers
The new balance is the sum of the unpaid balance, the finance charge, and any new purchases or fees:
New balance = Unpaid balance + Finance charge + Purchase
= $35.51 + $0.84 + $19.27
= $55.62.
We must first identify the balance remaining after the payment and purchase in order to calculate the outstanding balance:
Balance after payment = $50.51 - $15.00 = $35.51
Amount remaining after payment: $35.51 + $19.27 = $54.78
The balance remaining after the payment is made, which comes to $35.51, is the unpaid balance.
We must first determine the average daily balance before we can calculate the finance charge using the unpaid balance technique. Finding the daily balance and dividing the total by the number of days in the billing cycle will allow us to achieve this:
$50.51 times 14 days in April equals $707.
14 April 15–24: $35.51 multiplied by 10 days equals $355.
10 April 25–30: $54.78 multiplied by six days is $328.68
Balance total: $707.14 plus $355.10 plus $328.68 ($1,390.92)
Average daily balance: $1,390.92 divided by 30 equals $46.36.
Hence, the finance charge can be determined as follows:
Finance fee equals $46.36 * (0.18 / 365) * 30 = $0.84. Finance charge formula: Average daily balance * Daily periodic rate * Number of days in billing cycle
The total of the unpaid debt, the finance charge, and any additional purchases or fees is the new balance:
Purchase + Finance fee + New balance = $35.51 + $0.84 + $19.27 = $55.62.
To Know more about Unpaid Balance visit:
https://brainly.com/question/3238364
#SPJ1
Answer:
The account balance on April 1st is $50.51. On April 15th a payment of $15.00 is made. On April 25th a purchase of $19.27 is made. The annual rate is 18%. What is the unpaid balance? What is the finance charge using the unpaid balance method? What is the new balance? Unpaid balance = $ Finance charge = $ New balance = $
Step-by-step explanation:
To calculate the unpaid balance, we first need to calculate the balance after the payment and the balance after the purchase:
Balance after payment on April 15th: $50.51 - $15.00 = $35.51
Balance after purchase on April 25th: $35.51 + $19.27 = $54.78
Next, we need to calculate the average daily balance for the billing period. The billing period runs from April 1st to April 30th, which is 30 days. We can split this into two parts:
April 1st to April 15th (15 days)
April 16th to April 30th (15 days)
For the first part of the billing period, the balance is $50.51 for 15 days. For the second part of the billing period, the balance is $54.78 for 15 days. The average daily balance is therefore:
($50.51 x 15 + $54.78 x 15) / 30 = $52.64
The unpaid balance is the average daily balance minus the payment, so:
$52.64 - $15.00 = $37.64
The finance charge using the unpaid balance method is the unpaid balance multiplied by the daily periodic rate and the number of days in the billing cycle. The daily periodic rate is the annual rate divided by 365 days, so:
Daily periodic rate = 0.18 / 365 = 0.000493
Finance charge = $37.64 x 0.000493 x 30 = $0.56
The new balance is the previous balance (after the purchase) plus the finance charge, so:
New balance = $54.78 + $0.56 = $55.34
Therefore, the unpaid balance is $37.64, the finance charge is $0.56, and the new balance is $55.34.
The number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9 is what
. The probability that both the first digit in the last digit of the three digit number are even numbers is what
Answers
The requried, probability that both the first digit in the last digit of the three-digit number is even numbers is 20%.
To count the number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9, we can use the permutation formula:
P(n, r) = n! / (n-r)!
In this case, we have n = 6 (since we have 6 digits to choose from) and r = 3 (since we want to form three-digit numbers). Using the formula, we get:
P(6, 3) = 120
We can choose the first digit in two ways (2 or 8), and we can choose the last digit in three ways (2, 8, or 6). For the middle digit, we have four digits left to choose from (1, 3, 5, or 9), since we cannot repeat digits. Therefore, the number of three-digit numbers with distinct digits that have an even first and last digit is:
2 x 4 x 3 = 24
The total number of three-digit numbers with distinct digits is 120, so the probability that a randomly chosen three-digit number with distinct digits has an even first and last digit is:
24/120 = 0.2 or 20%
Learn more about probability here:
brainly.com/question/14290572
#SPJ1
Find the 66th
term in the following
arithmetic sequence
-92, -85, -78, -71, ...
Answers
Answer:
The \(66\)th term is \(363\).
Step-by-step explanation:
To find the \(n\)th term, the formula is \(7n - 99\). Since we want to find the \(66\)th term, we can plug \(n\) for \(66\). So our expression is now \(7 \cdot 66 - 99 =\) \(66\)th term. Solving this we have
\(462 - 99 = 66\text{th term}\\363 = 66\text{th term}\\\). Therefore, the \(66\)th term is \(\boxed{363}\).
Answer:
a₆₆ = 363
Step-by-step explanation:
the nth term of an arithmetic sequence is
\(a_{n}\) = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = - 92 and d = a₂ - a₁ = - 85 - (- 92) = - 85 + 92 = 7 , then
a₆₆ = - 92 + (65 × 7)
= - 92 + 455
= 363
Suppose weights of the checked baggage of airline passengers follow a nearly normal distribution with mean 46 pounds and standard deviation 3.7 pounds. Most airlines charge a fee for baggage that weigh in excess of 50 pounds. Determine what percent of airline passengers incur this fee. (Round your answer to two decimal places.)
Answers
Answer:
85.99% of airline passengers incur this fee.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean \(\mu\) and standard deviation \(\sigma\), the zscore of a measure X is given by:
\(Z = \frac{X - \mu}{\sigma}\)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Mean 46 pounds and standard deviation 3.7 pounds.
This means that \(\mu = 46, \sigma = 3.7\)
Most airlines charge a fee for baggage that weigh in excess of 50 pounds. Determine what percent of airline passengers incur this fee.
As a proportion, this is 1 subtracted by the pvalue of Z when X = 50. So
\(Z = \frac{X - \mu}{\sigma}\)
\(Z = \frac{50 - 46}{3.7}\)
\(Z = 1.08\)
\(Z = 1.08\) has a pvalue of 0.8599
0.8599*100% = 85.99%
85.99% of airline passengers incur this fee.
what steps are needed to find the equation of a line given the graph?
Answers
The equation of the line is y = x.
To find the equation of a line given its graph, you need to follow the steps below.
Step 1: Determine the slope of the line.The slope of the line can be determined using the formula: slope = rise/run or m = Δy/Δx. Rise is the change in the y-coordinates and run is the change in the x-coordinates.
Step 2: Determine the y-intercept of the line.The y-intercept is the point where the line intersects the y-axis. You can determine the y-intercept by looking at the point where the line crosses the y-axis on the graph. The y-intercept is denoted by the letter b.
Step 3: Write the equation of the lineThe equation of the line can be written in slope-intercept form, which is y = mx + b. The slope (m) and y-intercept (b) that were determined in steps 1 and 2 are used to substitute into this equation. Thus, the equation of the line becomes y = slope(x) + y-intercept.
Example:Let's say you are given the graph of a line below: .
Step 1: Determine the slope of the line.To determine the slope of the line, you need to choose two points on the line and calculate the rise and run. Let's choose the points (2, 1) and (4, 3). The rise is 2 (3 - 1) and the run is 2 (4 - 2). Therefore, the slope of the line is: m = 2/2 = 1.
Step 2: Determine the y-intercept of the lineThe line crosses the y-axis at the point (0, 0). Therefore, the y-intercept of the line is b = 0.
Step 3: Write the equation of the line.The equation of the line in slope-intercept form is y = mx + b. Substituting the slope and y-intercept into this equation gives: y = 1x + 0 or y = x.
for such more question on line
https://brainly.com/question/24644930
#SPJ8
If M is the set of all square numbers less than 80 and N is the set of all non-negative even numbers that are under 30, Write the lists of all elements of M and N.
Answers
Answer:
The set M of all square numbers less than 80 is:
M = {0, 1, 4, 9, 16, 25, 36, 49, 64}
The set N of all non-negative even numbers that are under 30 is:
N = {0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28}
Answer:
All elements of the set M in ascending order are:
1, 4, 9, 16, 25, 36, 49, 64All elements of the set N in ascending order are:
0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28Step-by-step explanation:
A square number, also known as a perfect square, is a non-negative integer that is obtained by multiplying an integer by itself. In other words, it is the result of squaring an integer.
The square numbers less than 80 are:
1, 4, 9, 16, 25, 36, 49, and 64.An even number is an integer that is divisible by 2 without leaving a remainder.
The non-negative even numbers that are under 30 are:
0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, and 28.Therefore:
All elements of the set M in ascending order are:
1, 4, 9, 16, 25, 36, 49, 64All elements of the set N in ascending order are:
0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28QUESTION 43 A teacher has her students to sing about birds, to draw pictures of birds, to take a nature walk to observe and count birds. This method of teaching all subject areas around one central theme is referred to as (two words).
Answers
The method of teaching all subject areas around one central theme is referred to as "Integrated Curriculum."
We have,
The method of teaching all subject areas around one central theme is referred to as "Integrated Curriculum."
It is an approach to teaching and learning that combines different subjects and topics into a single, cohesive plan of study.
The goal is to help students see the connections between different subjects and apply their knowledge in practical ways.
By integrating subjects, teachers can create a more engaging and meaningful learning experience for their students.
For example, a unit on birds can integrate science, math, language arts, social studies, and art. Students can learn about the anatomy and habitats of birds in science, count and classify birds in math, read and write about birds in language arts, study the migration patterns of birds in social studies, and draw pictures of birds in art.
Thus,
The method of teaching all subject areas around one central theme is referred to as "Integrated Curriculum."
Learn more about Integrated Curriculum here:
https://brainly.com/question/31394722
#SPJ1
URGENT!!
Write an equation of the line in point-slope form that has a slope of 2 and passes through the point (-8,1).
Answers
Answer:
y = 2x + 17
Step-by-step explanation:
given m = 2, y = 1, x = -8
y = mx + b
1 = 2(-8) + b
1 = -16 + b
b = 17
y = 2x + 17
Find the value of x in this equation
Answers
Answer: x = 8
Step-by-step explanation:
57 = 8x-7 because they are vertical angles
Bring 7 to the other side: 57+7 = 8x
57 + 7 = 64
8x = 64
64/8 = x
x = 8
3/1/2+1/5/6÷1/3/5
hello good afternoon can u please solve this question
Answers
Answer:
1/2
Step-by-step explanation:
See the steps below:)
find the value of x for which
З(2^x-3) = 384
Answers
Answer:
x=log2(131)
Step-by-step explanation:
3(2^x-3)=384
x=7.03342
i don't know this question but i have made it by photomath app.
you can get it from playstore
A researcher conducts a survey of 230 wives and 230 husbands and the counts of spouses who had affairs within
certain numbers of years of marriage were reported. Is there enough evidence at alpha = 0.05 to conclude that the count of husbands who
have had affairs differ significantly from the count of wives who have had affairs in each category of years of marriage? The count of wives
who had affairs is used as comparison (expected) for the husbands.
Categories Husbands affairs Wives affairs
Before 2 yrs 99 108
Between 2-10 yrs 50 44
After 10 yrs 12 18
No Affair 60 60
Step 1. Indicate the correct formulation of the hypotheses.
Option A:
H0: The proportion of husbands who have had affairs does not differ from the proportion of wives who have had affairs.
Ha: The proportion of husbands who have had affairs differs from the proportion of wives who have had affairs.
Option B:
H0: The proportion of husbands who have had affairs differs from the proportion of wives who have had affairs.
Ha: The proportion of husbands who have had affairs does not differ from the proportion of wives who have had affairs.
Answer:
Step 2. What is the number of husbands expected to have affairs between 2 and 10 years of marriage? Round to two decimals if required.
Answer:
Step 3. Find the value of the test statistic. (Round your answer to 3 decimals.)
Answer:
Step 4. Find the degrees of freedom associated with the test statistic for this problem.
Answer:
Step 5. Find the critical value of the test statistic from the table for p < 0.05. (Round your answer to 3 decimals.
Table: Critical Values of the X2 Distribution
https://bsuonline.blackboard.com/bbcswebdav/pid-17666795-dt-content-rid-860559_1/xid-860559_1
Answer:
Step 6. At the 0.05 level of significance, determine whether to fail to reject or reject the null hypothesis.
A) Reject Null Hypothesis
B) Fail to Reject Null Hypothesis
Answer:
Step 7. Choose the correct conclusion at the 0.05 level of significance.
A) There is enough evidence to conclude that the proportions of husbands who have had affairs differ significantly from the proportions of wives who have had
affairs.
B) There is not enough evidence to conclude that the proportions of husbands who have had affairs differ significantly from the proportions of wives who have had
affairs.
Answer:
Answers
The answers are given below:
Option AExpected value is 44The test statistic is 2.068df= 3Critical value= 7.815Fail to reject the null hypothesisOption BWhat is the Null Hypothesis?
The null hypothesis is the assertion that there is no association between the two sets of data or variables being investigated in a scientific study.
The term "null" refers to the idea that any experimentally detected difference is purely accidental and that no underlying causal relationship exists.
Read more about null hypothesis here:
https://brainly.com/question/25263462
#SPJ1
