Answer:
That expression is the same with
6 -2
This equals 4
Hope this helped!
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Satir Corp. reported the following information for 2013 and 2014.Salaries payable, December 31, 2013 $ 3,700Salaries payable, December 31, 2014 1,800Salaries expense--2014 57,000How much cash was paid for salaries during 2014?A. $55,100B. $55,200C. $57,000D. $58,900
Cash was paid for salaries during 2014 was $55,100. These are the formulas for calculating the cash salary received in 2014:
Salary paid in cash = Salary expense in 2014 - Reduction in salary payable
The difference between the balance due for salaries at the end of each year—that is, at December 31, 2013 and December 31, 2014—can be used to determine the decline in salaries payable:
Salaries payable at December 31, 2013, compared to salaries payable at December 31, 2014, are $3,700, $1,800, and $1,900, respectively.
The drop in the balance of salaries payable from 2013 to 2014 indicates that the business paid more compensation than it incurred for the year. As a result, the 2014 salary payments in cash are:
Cash paid for salaries equals salaries paid in 2014 less salaries payable, or $57,000 minus $1,900, or $55,100.
Hence, (A) $55,100 is the correct response.
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The point P(3,5) is rotated 180 degrees CW about the point A(3,2) and then rotated 90 degrees CCW about point B(1,1). What is the coordinate of P after the rotations?
To determine the coordinate of point P after the described rotations, let's go step by step.
First, the point P(3, 5) is rotated 180 degrees clockwise about the point A(3, 2). To perform this rotation, we need to find the vector between the center of rotation (A) and the point being rotated (P). We can then apply the rotation matrix to obtain the new position.
Let \(\vec{AP}\) be the vector from A to P. We can calculate it as follows:
\(\vec{AP} = \begin{bmatrix} 3 \\ 5 \end{bmatrix} - \begin{bmatrix} 3 \\ 2 \end{bmatrix} = \begin{bmatrix} 0 \\ 3 \end{bmatrix}\).
Now, we can apply the rotation matrix for a 180-degree clockwise rotation:
\(\begin{bmatrix} x' \\ y' \end{bmatrix} = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \\ \sin(\theta) & \cos(\theta) \end{bmatrix} \begin{bmatrix} x \\ y \end{bmatrix}\),
where \(\theta\) is the angle of rotation in radians. Since we want to rotate 180 degrees, we have \(\theta = \pi\).
Applying the rotation matrix, we get:
\(\begin{bmatrix} x' \\ y' \end{bmatrix} = \begin{bmatrix} \cos(\pi) & -\sin(\pi) \\ \sin(\pi) & \cos(\pi) \end{bmatrix} \begin{bmatrix} 0 \\ 3 \end{bmatrix} = \begin{bmatrix} -1 & 0 \\ 0 & -1 \end{bmatrix} \begin{bmatrix} 0 \\ 3 \end{bmatrix} = \begin{bmatrix} 0 \\ -3 \end{bmatrix}\).
The new position of P after the first rotation is P'(0, -3).
Next, we need to rotate P' (0, -3) 90 degrees counterclockwise about the point B(1, 1).
Again, we calculate the vector from B to P', denoted as \(\vec{BP'}\):
\(\vec{BP'} = \begin{bmatrix} 0 \\ -3 \end{bmatrix} - \begin{bmatrix} 1 \\ 1 \end{bmatrix} = \begin{bmatrix} -1 \\ -4 \end{bmatrix}\).
Using the rotation matrix, we rotate \(\vec{BP'}\) by 90 degrees counterclockwise:
\(\begin{bmatrix} x'' \\ y'' \end{bmatrix} = \begin{bmatrix} \cos(\theta) & -\sin(\theta) \\ \sin(\theta) & \cos(\theta) \end{bmatrix} \begin{bmatrix} x' \\ y' \end{bmatrix}\),
where \(\theta\) is the angle of rotation in radians. Since we want to rotate 90 degrees counterclockwise, we have \(\theta = \frac{\pi}{2}\).
Using the rotation matrix, we get:
\(\begin{bmatrix} x'' \\ y'' \end{bmatrix} = \begin{bmatrix} \cos \left(\frac{\pi}{2}\right) & -\sin\left(\frac{\pi}{2}\right) \\ \sin\left(\frac{\pi}{2}\right) & \cos\left(\frac{\pi}{2}\right) \end{bmatrix} \begin{bmatrix} -1 \\ -4 \end{bmatrix} = \begin{bmatrix} 0 & -1 \\ 1 & 0\end{bmatrix} \begin{bmatrix} -1 \\ -4 \end{bmatrix} = \begin{bmatrix} 4 \\ -1 \end{bmatrix}\).
The final position of P after both rotations is P''(4, -1).
Therefore, the coordinate of point P after the rotations is (4, -1).
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8. Mrs. Jackson, an English teacher, gives pop quizzes to her students every marking period. This is an example of: * 0/1 A. Variable interval schedule of reinforcement B. Variable ratio schedule of reinforcement C. Fixed ratio schedule of reinforcement D. Fixed interval schedule of reinforcement E. Interval ratio schedule of reinforcement
An English teacher, gives pop quizzes to her students every marking period. (D. Fixed interval schedule of reinforcement.)
The other options listed are not applicable in this scenario:
A. Variable interval schedule of reinforcement: This schedule involves providing reinforcement after varying time intervals. Mrs. Jackson's quizzes occur at fixed intervals, not varying intervals.
B. Variable ratio schedule of reinforcement: This schedule involves providing reinforcement after a varying number of responses. The pop quizzes are not contingent on the number of responses from the students.
C. Fixed ratio schedule of reinforcement: This schedule involves providing reinforcement after a fixed number of responses. The pop quizzes are not contingent on the number of responses from the students.
D. Fixed interval schedule of reinforcement :fixed interval schedule of reinforcement involves providing reinforcement at a fixed time interval. Mrs. Jackson gives the pop quizzes every marking period, which is a predetermined fixed interval of time. This schedule of reinforcement is characterized by a steady rate of response from the students, with an increase in responding closer to the time when the reinforcement is expected.
E. Interval ratio schedule of reinforcement: This is not a recognized schedule of reinforcement. The correct term would be fixed interval or variable interval schedule of reinforcement.
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5
A Petri dish is filled with 250 bacterial cultures. The number of bacteria in the dish triples
every hour.
Select the recursive and explicit formulas that model the scenario.
The recursive and the explicit formulas are f(n) = 3f(n - 1), where f(1) = 250 and f(n) = 250(3)ⁿ‐¹
Calculating the recursive and explicit formulas that model the scenario.From the question, we have the following parameters that can be used in our computation:
Initial = 250 bacterial cultures.Rate = triples every hour.This means that
Initial, a = 250 bacterial cultures.
Rate = 3
So, the recursive formulas is
f(n) = 3f(n - 1), where f(1) = 250
For the explicit formula, we have
f(n) = 250(3)ⁿ‐¹
Hence, the recursive and the explicit formulas are f(n) = 3f(n - 1), where f(1) = 250 and f(n) = 250(3)ⁿ‐¹
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Of the 24 guests invited to Hannah’s party, 12 are male and 15 have dark hair. If 7 of
the females have dark hair, what is the probability that the first guest to arrive will either
have dark hair or be a male?
Given that Hannah has invited 24 guests to her party, 12 of them are male and 15 have dark hair. Out of the 24 guests, the number of females will be:24 – 12 = 12 females
The number of females with dark hair will be:15 – 7 = 8 femalesLet the probability of the first guest to arrive having dark hair be P (D), and the probability of the first guest to arrive being male be P (M).To find the probability of the first guest to arrive having dark hair or being a male,
we can use the union formula:\(P (D∪M) = P (D) + P (M) – P (D∩M)\) To find the probability of the first guest to arrive having both dark hair and being male,
we use the multiplication rule:\(P (D∩M) = P (D) × P (M|D)\)
Probability of a female having dark hair = 8/12
Probability of a male = 12/24
Therefore,\(P (D) = (8/12) × (1) + (7/12) × (0) = 8/12P (M) = (12/24) × (1) + (12/24) × (0) = 12/24P (D∩M) = (8/12) × (12/23) ≈ 0.3478P (D∪M) = 8/12 + 12/24 – 0.3478 ≈ 0.8696\)
Thus, the probability that the first guest to arrive will either have dark hair or be a male is approximately 0.8696.
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x=\(\frac{1}{2+\sqrt{3} }\)
y=\(\frac{1}{2-\sqrt{3} }\)
x+y=
Answer:
4
Step-by-step explanation:
Simplify x and y by rationalising the denominator of both
To rationalise the denominator multiply the numerator/ denominator by the conjugate of the denominator.
The conjugate of 2 + \(\sqrt{3}\) is 2 - \(\sqrt{3}\)
The conjugate of 2 - \(\sqrt{3}\) is 2 + \(\sqrt{3}\)
x = \(\frac{1(2-\sqrt{3)} }{(2+\sqrt{3})(2-\sqrt{3}) }\) = \(\frac{2-\sqrt{3} }{4-3}\) = 2 - \(\sqrt{3}\)
y = \(\frac{1(2+\sqrt{3}) }{(2-\sqrt{3})(2+\sqrt{3}) }\) = \(\frac{2+\sqrt{3} }{4-3}\) = 2 + \(\sqrt{3}\)
Thus
x + y = 2 - \(\sqrt{3}\) + 2 + \(\sqrt{3}\) = 4
I really need help..im confused
In the expression 2 ^3, the 3 is known as the
Answer:
3 is known as the power of 2.
Answer:
The three is the exponent, it is also called power so 2 to the power of 3
Step-by-step explanation:
a sample obtained in such a way that every element in the population has an equal chance of being selected is called a/an _______ sample.
The correct term for a sample obtained in such a way that every element in the population has an equal chance of being selected is a "random sample."
In a random sample, each member of the population has an equal probability of being chosen, providing a representative subset of the population. This sampling method helps to reduce bias and ensures that the sample is more likely to accurately reflect the characteristics of the entire population.
Random sampling is a fundamental principle in statistics and research, allowing for generalizations and inferences to be made about the population based on the characteristics observed in the sample. It is widely used in various fields, such as social sciences, market research, and opinion polls, to draw meaningful conclusions about a larger population.
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I really need an answer for this FAST so if anybody can answer id really appreciate it :)
both Square and Rectangle
because all squares are rectangles, but not all rectangles are squares. Hope this helps. :)
In the year 2000, there were approximately 400 million telephones in use and it was projected that the amount of telephones would increase at a rate of 5% each year. Based on this model, how many telephones were in use in the year 2006?
In the year 2006, there were approximately 546.10 million telephones in use.
This is calculated by first finding the amount of increase each year, which is 5% of 400 million, or 20 million. Then, for each year from 2001 to 2006, we add the previous year's amount to the amount of increase to find the new amount. So:
- 2001: 400 million + 20 million = 420 million
- 2002: 420 million + 20 million = 440 million
- 2003: 440 million + 20 million = 460 million
- 2004: 460 million + 20 million = 480 million
- 2005: 480 million + 20 million = 500 million
- 2006: 500 million + 20 million = 520 million
Therefore, in the year 2006, there were approximately 546.10 million telephones in use.
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anybody got any limiteds if so which one you got
Answer:
what does that mean?
Step-by-step explanation:
Answer:
bru.h
Step-by-step explanation:
bobux hehehehhee
James thinks of two numbers. He says “The Highest Common Factor (HCF) of my two numbers is 3 The Lowest Common Multiple (LCM) of my two numbers is 45” Write down two numbers that James could be thinking of.
Answer:
9 , 15
Step-by-step explanation:
HCF = 3
LCM = 45
Product of two numbers = HCF * LCM
= 3*45
= 135
The two numbers are the factors of 135
9 * 15 = 135
9 = 3*3
15 = 3 * 5
HCF = 3
LCM = 3* 3 * 5 = 45
FILL IN THE BLANK. A 85 kg object is lifted 16 meters. How much work is done in lifting the object? _____ joules. Work is positive when the force acts in the direction of travel and negative when the force is opposite of the direction of travel.
The work done in lifting the 85 kg object for a height of 16 meters is 13,357.6 joules (J).
The work done in lifting the 85 kg object for a height of 16 meters is given by the formula:
Work = Force x Distance x cos(theta)
Here, the force applied is the weight of the object, which is given by:
Force = mass x gravity
where mass = 85 kg and gravity = 9.81 m/s^2 (acceleration due to gravity).
Therefore, Force = 85 kg x 9.81 m/s^2 = 834.85 N (Newtons).
The distance lifted is 16 meters.
The angle between the force and the direction of travel (vertical) is zero degrees, so cos(theta) = 1.
Substituting these values in the formula, we get:
Work = 834.85 N x 16 m x cos(0) = 13,357.6 joules
Therefore, the work done in lifting the 85 kg object for a height of 16 meters is 13,357.6 joules (J).
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The volume of a right circular cone is 300 cubic inches. What is the volume, in cubic inches, of
a right cylinder that has the same base and height as the cone?
Answer:
900 cubic inches.
Step-by-step explanation:
Given the following data
Volume of right circular cone = 300in³
We know that the volume of a right circular cone is given by the formula;
\( V = \frac{1}{3} \pi r^{2}h\)
Where;
V is the volume of right circular cone.r is the radius of the base of the right circular cone.h is the height of the right circular cone.The volume of a right circular cylinder is given by the formula;
\( V = \pi r^{2}h\)
Thus, multiplying the volume of the right circular cone by 3 would give us the volume of the right circular cylinder.
\( V = \frac{1}{3} \pi r^{2}h * 3\)
Substituting into the equation, we have;
V = 300 * 3
V = 900in³
Therefore, the volume of a right cylinder that has the same base and height as the cone is 900 cubic inches.
Shinji is considering two different layouts for a new garden. He needs to put a length of fence around whichever
layout he chooses.
The following diagram shows both layouts on a coordinate grid.
B
Coordinate values are in meters.
Which layout needs more fencing, and how much more?
Answer:
Layout A needs 4.8 m more fencing
Step-by-step explanation:
Khan academy answer
Describe the transformation that took place if f(x)=x? became f (x) = 0.2(x - 5)2 – 2
at what point does the curve have maximum curvature? y = 8ex
The curve y = 8e^x has maximum curvature at the point (0, 8).there is no point where the second derivative equals zero,
To determine the point of maximum curvature on the curve y = 8e^x, we need to find the second derivative of the function and identify the point where it equals zero. The second derivative represents the rate of change of the slope, or the curvature, of the curve.
First, we find the first derivative of y = 8e^x with respect to x:
dy/dx = 8e^x
Then, we differentiate again to find the second derivative:
d²y/dx² = d(8e^x)/dx = 8e^x
Setting the second derivative equal to zero:
8e^x = 0
Exponential functions, such as e^x, are never equal to zero for any value of x. Therefore, there is no point where the second derivative equals zero, indicating that the curve y = 8e^x does not have any inflection points or points of maximum curvature.
However, we can determine the point where the curvature is the greatest by considering the graph of y = 8e^x. Since the exponential function e^x is always positive, the curve y = 8e^x is always concave up. This means that the curvature is positive throughout the curve, but there is no specific point of maximum curvature.
In conclusion, the curve y = 8e^x does not have a point of maximum curvature but is always positively curved.
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Hi . i'm kinda stuck on this question .
Any help will be appreciated.
Please show workings ;
Solve the following expressions using laws of logarithm and using antilogarithm ;
1.\(\sqrt{69.5^2-30.5^2}\)
2. \(\frac{371.2^\frac{1}{3}\times 76500 }{1125 \times 0.012}\)
Answer:
62.4499840725.2396667Step-by-step explanation:
Refer to https://brainly.com/question/17913554 for the formulas and the method if not clear here1.................................................
√69.5^2 - 30.5^2 = √(69.5+30.5)((69.5- 30.5) =√100*39 =10√39 =antilog (log (10√39)) =antilog (1 + 1/2 log 39)= antilog (1 + 1/2*1.59106460703) =antilog (1.79553230351) =62.449982..................................................
371.2^(1/3)×76500/(1125×0.012) =371.2^(1/3)×76500/13.5 =371.2^(1/3) × 5666.66666667Solving the first part
antilog (log (371.2^(1/3))) = antilog (1/3 log(371.2)) =antilog (1/3*2.56960796755) =antilog (0.85653598918) = 7.186807Continuation
7.186807× 5666.66666667 = 40725.2396667Note. the numbers are not rounded
Hope it helps.
the number of cars produced when x x dollars is spent on labor and y y dollars is spent on capital invested by a manufacturer can be modeled by the equation 45 x 1 3 y 2 3
The formula in terms of x and y for dy/dx is y/ -2x
The value of dy/dx at the point (1,1) is -0.5
The question is incomplete, the full question is given below:
200 cars can produced when x dollars is spent on labor and y dollars is spent on capital. the equation that relates x and y is 45 x^1/3 y^2/3= 200
a. Find a formula in terms of x and y for dy/dx
b. Find the value of dy/dx at the point (1,1). Round your answer to 4 decimal places
Part a
A formula in terms of x and y for dy/dx
We differentiate equation that relates x and y with respect to x by implicit differentiation:
=d/dx(45 x^1/3 y^2/3) =d/dx( 200)
=> 45 *(1/3) x^-2/3 y^2/3 + 45 x^1/3 2/3 y^ -1/3 dy/dx=0
=> x^-2/3y^2/3+ 2 x^1/3 y^-1/3 dy/dx=0
=> y/x= -2dy/dx
=> log y = -2 log x +log c
=> y= x^ -2 +c
putting x=y=1
c=0
then y= 1/x^2
b) y/x= -2dy/dx
put x=y=1 we get
-1/2 = dy/dx
dy/dx =-0.5
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-4x – (-3 − 5x) = -3(2x − 8)
Answer:
x=3
Step-by-step explanation:
U 2 can help me by marking as brainliest.........
Answer:
x = 3
Step-by-step explanation:
-4x - (-3 - 5x) = -3(2x - 8)
=> -4x + 3 + 5x = -6x + 24
=> x + 3 = -6x + 24
=> x + 6x = 24 - 3
=> 7x = 21
=> x = 3
Mr. A sold his land to Mr.B at a profit of 10%. Mr.B. sold it to Mr.C at a gain of 5%. Mr.C.paid N1240 more for the house than Mr. A paid. What did Mr. A paid.
Answer:
Mr. A initially paid approximately N8000 for the land.
Step-by-step explanation:
Step 1: Let's assume Mr. A initially purchased the land for a certain amount, which we'll call "x" in currency units.
Step 2: Mr. A sold the land to Mr. B at a profit of 10%. This means Mr. A sold the land for 110% of the amount he paid (1 + 10/100 = 1.10). Therefore, Mr. A received 1.10x currency units from Mr. B.
Step 3: Mr. B sold the land to Mr. C at a gain of 5%. This means Mr. B sold the land for 105% of the amount he paid (1 + 5/100 = 1.05). Therefore, Mr. B received 1.05 * (1.10x) currency units from Mr. C.
Step 4: According to the given information, Mr. C paid N1240 more for the land than Mr. A paid. This means the difference between what Mr. C paid and what Mr. A paid is N1240. So we have the equation: 1.05 * (1.10x) - x = N1240
Step 5: Simplifying the equation: 1.155x - x = N1240
Step 6: Solving for x: 0.155x = N1240
x = N1240 / 0.155
x ≈ N8000
Therefore, in conclusion, Mr. A initially paid approximately N8000 for the land.
If there are 4 green apple and 3 red apples, what's the probability that a red apple is picked?
Answer: 3/7
Step-by-step explanation:
What is 713.49 written in standard form as powers
Answer:
one hundred seven thirteen and forty nine hundreds standard form
Step-by-step explanation:
Standard form is a way of writing down very large or very small numbers easily. 103 = 1000, so 4 × 103 = 4000 . So 4000 can be written as 4 × 10³ . This idea can be used to write even larger numbers down easily in standard form.
Mr. Estrada's car can travel no more than 510 miles on one full tank of gasoline. After filling up the tank with gasoline, he traveled 194 miles in the car. Write an inequality that represents the values of m, the number of miles Mr. Estrada can travel in the car with the remaining gasoline in the tank and solve.
please help me!! this is due very soon
Answer:
Step-by-step explanation:
The required inequality x + m ≤ 510, and the distance is 316 miles.
What is inequality?Inequity occurs when two phrases are joined by a sign such as "not equal to," "more than," or "less than." The inequality illustrates the larger than and less than the relationship between variables and numbers.
Given that Mr. Estrada's car can only drive 510 miles on a full tank of petrol. He drove the car 194 miles after filling up the tank with gasoline.
Let,
x miles = distance already traveled
m miles = distance miles can travel with remaining gas
510 = max. miles can travel on a full tank
As per the given question,
The inequality will be written as,
x + m ≤ 510
194 + m ≤ 510
m ≤ 510 - 194
Apply the subtraction operation, and we get
m ≤ 316
Therefore, the required inequality x + m ≤ 510, and the distance is 316 miles.
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original price $48.60 markup percent is 100% what is the mark up
Answer:
So the mark up= the profit divided by the cost so the revenue is 97.20 and the profit is 48.60.
The dean of Blotchville University boasts that the average class size there is 20. But the reality experienced by the majority of students there is quite different: they find themselves in huge courses, held in huge lecture halls, with hardly enough seats or Haribo gummi bears for everyone. The purpose of this problem is to shed light on the situation. For simplicity, suppose that every student at Blotchville University takes only one course per semester.
a) Suppose that there are 16 seminar courses, which have 10 students each, and 2 large lecture courses, which have 100 students each. Find the dean’s eye view average class size (the simple average of the class sizes) and the student’s eye view average class size (the average class size experienced by students, as it would be reflected by surveying students and asking them how big their classes are). Explain the discrepancy intuitively.
b) Give a short proof that for any set of class sizes (not just those given above), the dean’s eye view average class size will be strictly less than the student’s eye view average class size, unless all classes have exactly the same size.
a) Find the dean’s eye view average class size and the student’s eye view average class size:Given that there are 16 seminar courses, each having 10 students each.Number of students in seminar courses: 16 × 10 = 160There are 2 large lecture courses, each having 100 students each.
Number of students in large lecture courses: 2 × 100 = 200
Dean’s view average class size is the simple average of the class sizes:Let’s find the Dean’s view average class size. There are 18 courses in total.
This can be obtained by dividing the total number of students by the total number of classes.
Student’s view average class size = Total number of students/Total number of classes
= 360/18
= 20
Therefore, the dean’s eye view average class size is 46.67 (approximately) and the student’s eye view average class size is 20.
Now, we need to prove that D 2, then (k/(k + 1)) - (1/n) < 0.
Therefore, we have:
S - D< (c2 - c1)*[(k/(k + 1)) - (1/n)]< 0
Hence, S < D.Therefore, the dean’s eye view average class size will be strictly less than the student’s eye view average class size, unless all classes have exactly the same size.
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24% of what number is 16.08
Answer:
67
Step-by-step explanation:
Answer:
67
Step-by-step explanation:
16.08*100/24 is the formula
in a coin jar the ratio of dimes to pennies is 3 to 8 . the number of pennies is 32.
why can't the number of dimes be 10
Answer: 12 dimes is the correct answer. 10 dimes doesn’t fit the 3:8 ratio given for 32 pennies.
Step-by-step explanation: