What is the best next step in the constructed of a line that passes through point C and is parallel to AB? (Assume that the arc drawn with the compass placed at point A was the result of the last step performed.)

Step-by-step explanation:

1) 3 – 36i = 9a + 4bi

3 = 9a => a = 3/9 = ⅓

-36 = 4b => b = -36/4 = -9

2) a – 15i = -7 – (2b-3)i

a = -7

-15 = -(2b-3)

2b-3 = 15

2b = 18

b = 18/2= 9

The solutions to the system of equations are x=5, z=1,y=-3

What is system of equations?

Given equations:

x+y+z=3

3x+(y/3)-2z=12

-5x-6y+3z=-4

Solving by using the substitution method:

\(\begin{bmatrix}x+y+z=3\\ 3x+\left(\frac{y}{3}\right)-2z=12\\ -5x-6y+3z=-4\end{bmatrix}\)

Substitute x=3-y-z

\(\begin{bmatrix}3\left(3-y-z\right)+\frac{y}{3}-2z=12\\ -5\left(3-y-z\right)-6y+3z=-4\end{bmatrix}\)

Substitute z={8y+9}/{15}

\(\begin{bmatrix}-y+8\left(-\frac{8y+9}{15}\right)-15=-4\end{bmatrix}\)

simplify

\(\begin{bmatrix}\frac{-79y-72}{15}-15=-4\end{bmatrix}\)

Substitute y=-3

\(z=-\frac{8\left(-3\right)+9}{15}\)

z=1

For x=3-y-z

Substitute z=1,y=-3

x=3-(-3)-1

x=5

The solutions to the system of equations are:

x=5, z=1,y=-3

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The marginal frequencies of chocolate and strawberry are 0.75 and 0.25 and chocolate is greater by 0.5

Marginal frequency is the ratio between either a column total or a row total and the total sample size.

For example, in a table of students classified by sex and area of study, the number of female students, regardless of area of study, would be one marginal frequency.

The marginal frequency of chocolate is calculated as;

The total frequency of chocolate = 30+45 = 75

The grand frequency = 75+25 = 100

marginal frequency of chocolate = 75/100

= 0.75

The marginal frequency of strawberry = 25/100

= 0.25

The difference in the marginal frequencies of chocolate and strawberry = 0.75 - 0.25 = 0.50

Therefore the marginal frequency of chocolate is greater than strawberry by 0.5

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A triangle is a shape used to represent the components of total health. True

Answer:

Yes, changing from 3 states to 6 states changes the median because:

- The median of the first 3 states is simply the middle-placed state of the 3 states.

- The median of 6 states is the average of the 2 middle states.

Step-by-step explanation:

Suppose the first 3 states in order are:

A, B, C.

The median of these states is simply the middle state, B.

Adding 3 new states to have:

A, B, C, D, E, F.

The median is not explicit. It is the average of the two middle states, C and D.

Average of C and D is half of the sum of C and D.

That is (C + D)/2.

Which is different from B.

Answer:B.Sample space

Step-by-step explanation:

Answer:

(-2,-14), (0, -8), (2, -2), (4, 4)

Step-by-step explanation:

Plug the x-value into the equation to get the corresponding y-value.

Example: Want the y-value for -2?

y = 3(-2) - 8

y = -6 - 8

y = -14

y-value for 2?

y = 3(2) - 8

y = 6 - 8

y = -2

Repeat that for all values.

Hope this helped!

A tree of n vertices has (n-1) edges.

In a tree, each vertex is connected to exactly one other vertex through an edge, except for the root of the tree which has no incoming edges. Since there are n vertices in the tree, there will be (n-1) edges connecting them.

The reason behind this is that a tree is defined as a connected acyclic graph. In order for a graph to be connected, each vertex must be reachable from every other vertex through a path. However, in order for the graph to be acyclic, it should not contain any cycles or loops. If we assume that there are n vertices in the tree, the maximum number of edges that can be present without creating a cycle is (n-1).

Therefore, a tree of n vertices will have (n-1) edges. This property holds true for all trees, regardless of their specific structure or arrangement of vertices.

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the size of the union of the three sets is: |A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |A ∩ C| - |B ∩ C| + |A ∩ B ∩ C| = 3  × 24 million - 3 × 1.4 million + 1.2 million ≈ 69 million

A combination is a way of selecting a subset of objects from a larger set without regard to their order. The formula for the number of combinations of n objects taken r at a time is:
C(n, r) = n! / (r! ×  (n - r)!)
where n! means the factorial of n, which is the product of all positive integers up to n. For example, 5! = 5 ×  4 ×  3 ×  2 ×  1 = 120.
To apply this formula to our problem, we first need to count the total number of coins in the pile. Since there are at least 16 of each type, the minimum total is:
16 + 16 + 16 + 16 = 64
But there could be more coins of each type, so the total could be larger than 64. However, we don't need to know the exact number, only that it is large enough to allow us to choose 16 coins from it.
Using the formula for combinations, we can calculate the number of different collections of 16 coins that can be chosen from the pile:
C(64, 16) = 64! / (16! × (64 - 16)!) ≈ 1.1 billion
That's a very large number! It means there are over a billion ways to choose 16 coins from a pile that contains at least 16 of each type.
To answer the second part of the question, we need to count the number of collections that contain at least 3 coins of each type. One way to do this is to use the inclusion-exclusion principle, which says that the number of elements in the union of two or more sets is equal to the sum of their individual sizes minus the sizes of their intersections, plus the sizes of the intersections of all possible pairs, minus the size of the intersection of all three sets, and so on.
In this case, we can consider three sets:
- A: collections with at least 3 pennies
- B: collections with at least 3 nickels
- C: collections with at least 3 dimes
- D: collections with at least 3 quarters
The size of each set can be calculated using combinations:
|A| = C(48, 13) ≈ 24 million
|B| = C(48, 13) ≈ 24 million
|C| = C(48, 13) ≈ 24 million
|D| = C(48, 13) ≈ 24 million
Note that we have to choose 3 coins of each type first, leaving 4 coins to be chosen from the remaining 48 coins.
The size of the intersection of any two sets can be calculated similarly:
|A ∩ B| = C(43, 10) ≈ 1.4 million
|A ∩ C| = C(43, 10) ≈ 1.4 million
|A ∩ D| = C(43, 10) ≈ 1.4 million
|B ∩ C| = C(43, 10) ≈ 1.4 million
|B ∩ D| = C(43, 10) ≈ 1.4 million
|C ∩ D| = C(43, 10) ≈ 1.4 million
Note that we have to choose 3 coins of each type first, leaving 1 coin to be chosen from the remaining 43 coins.
The size of the intersection of all three sets can also be calculated:
|A ∩ B ∩ C| = C(38, 7) ≈ 1.2 million
Note that we have to choose 3 coins of each type first, leaving 1 coin to be chosen from the remaining 38 coins.

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Answer:

solutions for these simultaneous equations are x = 6 and y = x = 6, or x = 1 and y = x = 1

Step-by-step explanation:

To solve these simultaneous equations, we need to find the values of x and y that satisfy both equations.

Given:

y = x

y = x² - 6

We can substitute the first equation into the second:

x = x² - 6

we can subtract x from both sides to get:

0 = x² - 7x + 6

Then we can factor it:

(x-6)(x-1) = 0

Therefore x = 6 or x = 1

So the solutions for these simultaneous equations are x = 6 and y = x = 6, or x = 1 and y = x = 1

There are two solutions, (6,6) and (1,1)

Answer:

-6

Step-by-step explanation:

-2(-12 - u )

u = -15

-2 ( -12 - (-15))

remove parenthesis.

-2 ( -12 + 15 )

add -12 and 15

-2 ( 3 )

multiply -2 and 3

= -6

Step-by-step explanation:

-2(-12 - u) = -2(-12 + 15) = -2(3) = -6

The value of x is 8.

A linear equation system is a collection of two or more linear equations involving the same set of variables. The goal of solving a linear equation system is to find a set of values for the variables that satisfy all of the equations simultaneously. In general, a linear equation can be written as:

a₁x₁ + a₂x₂ + ... + aₙxₙ = b

Given linear system:

2x - y + 5z = 16 ...(1)

y + 2z = 2 ...(2)

z = 2 ...(3)

From equation (3), we get z = 2. Substituting this value of z in equation (2), we get y + 4 = 2, which gives us y = -2.

Substituting the values of y and z in equation (1), we get:

2x - (-2) + 5(2) = 16

2x + 12 = 16

2x = 4

x = 2

Therefore, the value of x is 2.

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Answer:

B. 2x²

Step-by-step explanation:

What is the greatest common factor of 14x² and 38x³ ?

GCF of 14 & 38 is 2

GCF of x² & x³ is x²

So, the answer is B. 2x²

Answer:

8 ounces

Step-by-step explanation:

Answer:

By forming regression equation

y=a+bx

a=0

b=3/4

y=3/4x

for 1 guest 3/4 ounces

Answer:

I think it's the second one

Step-by-step explanation:

Answer:

I'm thinking the answer is the second one. –a ≤ –12 or a > –5

Step-by-step explanation:

Well for –a ≤ –12, the symbol means less than or equal to so that is why -12 has a dot on it. For a > –5, it makes sense because -5 does not have a dot which means it is greater than 5 but not equal to 5.

Answer:

  4200π ft² ≈ 13195 ft²

Step-by-step explanation:

You want the surface area of a cylinder 30 feet in radius and 40 feet high.

The formula for the area of a cylinder adds the area of the two circular bases to the lateral area:

  A = 2πr² +2πrh = 2πr(r+h)

For the given dimensions, r=30, h=40, the area is ...

  A = 2π(30 ft)(30 ft +40 ft) = 4200π ft² ≈ 13195 ft²

total no of marbles = 10

no of marbles which are not white = 8

8/10 = 4/5

hope it helps...!!!

The approximate cost of producing the 41st food processor is $2,534.60 (rounded to two decimal places).

Given function is f(x) = 168x - 1222. To find the following

(A) The instantaneous velocity function v= f'(X)To find the instantaneous velocity, we need to differentiate the function w.r.t time.  f(x) = 168x - 1222. Differentiate w.r.t time => f'(x) = 168. This is the instantaneous velocity function. It means that the velocity of the moving object is constant and equals 168 feet/sec.

(B) The velocity when x = 0 and x=4 secrets use the derivative to find the velocity at these points. When x = 0, the velocity = f'(0) = 168When x = 4, the velocity = f'(4) = 168Therefore, the velocity is constant and equals 168 feet/sec for all values of x. (C) The time(s) when v=0 The instantaneous velocity is constant and equals 168 feet/sec. Therefore, it never equals zero. Hence there is no time when v=0.

Marginal cost function: C(x)= 180 +5.7x -0.02% C'(x) = to find the marginal cost, we need to differentiate the cost function w.r.t x.  C(x) = 1900 + 60x -0.3x²C'(x) = 60 - 0.6x. This is the marginal cost function.

To find the cost of producing the 41st food processor, we can substitute the value of x in the cost function. C(x) = 1900 + 60x -0.3x²C(41) = 1900 + 60(41) -0.3(41)²= $2,534.20. The exact cost of producing the 41st food processor is $2,534.20. (B) Use the marginal cost to approximate the cost of producing the 41st food processor use the marginal cost to approximate the cost of producing the 41st food processor, we can multiply the marginal cost with a small change in x. C'(x) = 60 - 0.6x. When x = 41, C'(41) = 60 - 0.6(41) = 36.40. This means that the cost increases by $36.40 when one more processor is produced. Hence, the approximate cost of producing the 41st food processor is: C(41) ≈ C(40) + C'(40)≈ $2,498.20 + $36.40≈ $2,534.60

Therefore, the approximate cost of producing the 41st food processor is $2,534.60 (rounded to two decimal places).

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The minimum value is 0.5 and the maximum value is 3.5.

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The amount of concrete required to make 80 pots is 0.24192 cubic meters after adding 5% of the required concrete.

Given that:External dimensions of the prism, a = 18 cmHeight of the prism, h = 16 cm Thickness of the walls, t = 3 cmNumber of pots, n = 80Wastage is 5% of the required concreteLet the side of the inner square be 'a1'. Then,a = a1 + 2t⇒ a1 = a - 2t = 18 - 2×3 = 12 cmVolume of the pot = volume of the outer prism - volume of the inner prismVolume of the outer prismVolume of the outer prism = a²hVolume of the outer prism = 18²×16 = 5184 cm³Volume of the inner prismVolume of the inner prism = a1²hVolume of the inner prism = 12²×16 = 2304 cm³Volume of the potVolume of the pot = 5184 - 2304 = 2880 cm³In m³, Volume of the pot = 2880/1000000 m³Volume of 80 such potsVolume of 80 pots = 80 × 2880/1000000 m³= 0.2304 m³Concrete required for the potsConcrete required = volume of 80 pots × (100 + 5)/100Concrete required = 0.2304 × 105/100 m³Concrete required = 0.24192 m³

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The solution to the inequality from the graph using online geogebra tool is point (3, 3)

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the inequality:

4x + 8y > 16

The solution to the inequality from the graph using online geogebra tool is point (3, 3)

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Answer:

4

Step-by-step explanation:

24 divided by 6 equals 4

Answer:

...

Step-by-step explanation:

Hello!

surface area

= 2(6*2) + 2(4*2) + 4*6

= 2*12 + 2*8 + 24

= 24 + 16 + 24

= 64 square inches

The solution of the system would be (3,6).

Lets solve the problem,

Other equation: y = 1/3x+5

Slope-Intercept Form: y = mx + b

Slope Formula:

y2-y1/x2-x1 = m

Have to find equation now:

m = (6 - 5)/(3 - 0)

m = 1/3

y = 1/3x + b

5 = 1/3(0) + b

b=5

y = 1/3x + 5

Lets put the substituition method here,

1/3x + 5 = -1/3x + 7

2/3x + 5 = 7

2/3x = 2

x = 3

y = 1/3(3) + 5

y = 1 + 5

y = 6

Therefore the coordinates are (3,6)

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Here's the solution,

The given triangle is an equilateral triangle, because it's all angles measure 60° each

now,

Area of an equilateral triangle :

=》

\( \dfrac{ \sqrt{3} }{4} {a}^{2} \)

where,

=》

\( \dfrac{ \sqrt{3} }{4} \times 8 \times 8\)

=》

\( \sqrt{3} \times 16\)

=》

\(16 \sqrt{3} \: \: \: cm {}^{2} \)

or

=》

\(27.71 \: \: cm {}^{2} \)

Answer:

answer is 12

12 because 5x12+5 = 65 and 180-115=65 meaning x=65

The completed table with regards to terms of an expression are presented as follows;

     Condition      \({}\)              (6·x + 3) + (5·x - 4)            (-4·y - 16) - 8·y + 10 + 2·y

         Exactly 3 terms          N/A     \({}\)                              N/A

         Exactly 5 terms          N/A         \({}\)                          N/A

Includes a zero pair             No \({}\)                                   No

Uses distributive property   No                                    No

Includes a negative factor   No                                    

Has no like terms                False                                False

Condition       \(8 - \dfrac{1}{2} \cdot \left(4 \cdot x - \dfrac{1}{2} + 12\cdot x -\dfrac{1}{4} \right)\)  0.25·(8·m - 12) - 0.5·(-4·m + 2)

Exactly 3 terms       No                         \({}\)                    No

Exactly 5 terms       Yes                          \({}\)   \({}\)              No

Includes a zero pair No    \({}\)                         \({}\)              Yes

Uses the distributive property Yes            \({}\)             Yes

Includes a negative factor      Yes           \({}\)                Yes

Has no like terms                    No          \({}\)                  No

A mathematical expression is a collection of variables and numbers along with mathematical operators which are all properly arranged.

The details of the conditions in the question are as follows;

Terms of an expression

A term is a subunit of an algebraic expression which are joined together by operators such as addition or subtraction

Zero pair

A zero pair are two numbers that when added together have a zero result

Distributive property

The distributive property of multiplication states that the multiplication of a number or variable by an addend is equivalent to the sum of the multiplication of the number or variable and each member of the addend

Negative factor

A negative factor is a factor that has a negative sign prefix

Like terms

Like terms are terms consisting of identical variables with the same  powers of the variable

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Mike and Jed stopped for lunch at 12:00 p.m. after skiing for 1 hour and 40 minutes.

To add time, we need to convert minutes to hours and minutes. There are 60 minutes in an hour, so we can divide the number of minutes by 60 to get the number of hours and the remaining minutes. In this case, 1 hour and 40 minutes is the same as

(1 hour + 40/60 hours) = 1.67 hours

So, to find out what time they stopped for lunch, we can add 1.67 hours to the starting time of 10:30 a.m. We can do this by converting 10:30 a.m. to 24-hour format, which is 10:30. We then add 1.67 hours to 10:30, which gives us a total of 12:00 p.m. (or noon).

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