What is the change in potential energy of a 2.00 nC test charge, Uelectric, b - Uelectric, a, as it is moved from point a at x

Answers

Answer 1

The question is incomplete. Here is the complete question.

A uniform electric field of 2kN/C points in the +x-direction.

(a) What is the change in potential energy of a +2.00nC test charge, \(U_{electric,b} - U_{electric,a}\) as it is moved from point a at x = -30.0 cm to point b at x = +50.0 cm?

(b) The same test charge is released from rest at point a. What is the kinetic energy when it passes through point b?

(c) If a negative charge instead of a positive charge were used in this problem, qualitatively, how would your answers change?

Answer: (a) ΔU = 3.2×\(10^{-6}\) J

(b) KE = 2×\(10^{-6}\) J

Explanation: Potential Energy (U) is the amount of work done due to its position or condition and its unit is Joule (J). Kinetic Energy (KE) is the ability to do work by virtue of velocity and the unit is also (J). Mechanical Energy is the sum of Potential and Kinetic Energies of a system.

(a) Related to electricity, Potential Energy can be calculated as:

ΔU = Eqd

where E is the electric field (in N/C);

q is the charge (in C);

d is the distance between plaques (in m);

For a at x = - 30cm and b at x = 50 cm:

E = 2×\(10^{3}\) N/C

q = 2×\(10^{-9}\) C

d = 50 - (-30) = 80×\(10^{-2}\) = 8×\(10^{-1}\)m

ΔU = \(U_{electric,b} - U_{electric,a}\) = Eqd

\(U_{electric,b} - U_{electric,a}\) = 2×\(10^{3}\) .  2×\(10^{-9}\) . 8×\(10^{-1}\)

ΔU = 3.2×\(10^{-6}\) J

(b) Mechanical Energy is constant, so:

\(KE_{i} + U_{i} = KE_{f} + U_{f}\)

Since the initial position is zero and there is no initial kinetic energy:

\(KE_{f} = - U{f}\)

\(KE_{f} =\) - (2×\(10^{3}\). 2×\(10^{-9}\) . 5×\(10^{-1}\))

\(KE_{f} = - 2.10^{-6}\) J

(c) If the charge is negative, electric field does positive work, which diminishes the potential energy. The charge flows from the negative side towards the positive side and stays, not doing anything.


Related Questions

A wire 48 m long carries a current of 18 A from west to east. If a magnetic field of 8.3 x 10-4 T directed toward the
south is acting on the wire, find the direction and magnitude of the magnetic force. (Remember F = BIL)
0.72 N left
-0.72 N left
0.72 N downward
-0.72 N downward

Answers

Using the right-hand rule, we can determine that the magnetic force will be directed upward, perpendicular to both the direction of current and the direction of the magnetic field.

The magnitude of the magnetic force can be calculated using the formula F = BIL, where B is the magnetic field strength, I is the current, and L is the length of the wire. Substituting the given values, we get:

F = (8.3 x 10^-4 T) x (18 A) x (48 m) = 0.72 N

Therefore, the direction and magnitude of the magnetic force is 0.72 N upward. However, the question asks for the direction of the magnetic force, which is to the left (in the westward direction) according to the right-hand rule. Therefore, the answer is -0.72 N left.

PLS THIS IS DUE IN 2 MINUTES
Which has more momentum, a 0.5kg toy car moving a 5 m/s or a 1000kg real car that is
parked?

Answers

Answer:

The toy car. An object that isn't moving has no momentum

Explanation:

Shopper leaves home and drives to a store located 7km away in direction 30° north of east.Leaving the store,the shopper drives 5km in a direction 50° west of north to a restaurant.Find the distance and direction from shopper's home to the restaurant?​

Answers

As a result, from the homes of the shoppers to the restaurant, the distance is 12 km, and the direction is 80° north.

What is distance and direction?

As the name implies, questions based on direction and/or distance are also known as Direction and Distance questions. Candidates must calculate the distance traveled between the starting location and the final / end point based on the provided starting point and direction. The position of one point and person with regard to another point and person and the distance among them must be determined for the Direction & Distance reasoning part.

How do you teach directions?

Declare the terms "right" and "left." Ask the kids to tell you what these terms imply or mean when they are translated, then write their answers on the board with arrows pointing in the appropriate directions. Show the class how to pronounce the words once their meanings are obvious. Relative terminology, such as up, down, in, out, left, right, forward, backward, or sideways, can be used to define direction. You can also depict direction using the four cardinal directions: north, south, east, & west.

7km = 30 Degree of NE

5km = 50 degree of N

Therefore distance = 7km+5km

=12km

thus, direction = 50+30

=80° N

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why is the unit of power called derived unit​

Answers

Answer:The ampere is unique in that it uses the base unit of time (t) in its definition (second). All other electrical and magnetic units (such as voltage, power, and magnetic flux) use various combinations of base units in their definitions and are called derived units.

Explanation:

A 0.360-m-long metal bar is pulled to the left by an applied force F. The bar rides on parallel metal rails connected through a 45.0 ohm resistor, as shown in the diagram, so the apparatus makes a complete circuit. The circuit is in a uniform 0.650-T magnetic field that is directed out of the plane of the figure. At the instant when the bar is moving to the left at 5.90 m s, (a) is the induced current in the circuit clockwise or counterclockwise and (b) what is the rate at which the applied force is doing work on the bar? ​

Answers

(a) The induced current in the circuit is clockwise.

b. To find the power (P) using P = Fd/t or P = Fv (since d/t = v). Here, F = ILB (from the Lorentz force), so P = (ILB)v.

How to solve

(a) The induced current in the circuit is clockwise.

This can be determined using the right-hand rule.

As the metal bar moves to the left through the magnetic field directed out of the plane, the generated force on the electrons (Lorentz force) will push them toward the top rail, creating a clockwise current.

(b) To find the rate at which the applied force is doing work on the bar, first calculate the induced EMF (ε) using Faraday's law:

induced EMF (ε) using Faraday's law:

ε = BLv

= (0.65 T) * (0.36 m) * (5.9 m/s)

= 1.389 Tm²/s

= 1.389 V (since 1 Tm²/s = 1 V)

induced current (I) using Ohm's law:

I = ε/R

= 1.389 V / 45 Ω

= 0.03086 A

force (F) from the Lorentz force law, where F = ILB:

F = ILB

= (0.03086 A) * (0.36 m) * (0.65 T)

= 0.00723 N

Finally, we find the power (P) using P = Fv:

P = Fv

= (0.00723 N) * (5.9 m/s)

= 0.04266 W

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A 0.360-m-long metal bar is pulled to the left by an applied force F. The bar rides on parallel metal

What must be true in order for magnetism to induce an electric current in a wire?

What must be true in order for magnetism to induce an electric current in a wire?

Answers

Answer:

The wire must be part of a closed circuit.

Explanation:

A closed circuit in electric is what we called a wire that has a complete electrical connection in which electricity flows, where electric current flow from one end to another, in order for magnetism to induce an electric current the circuit has to be closed, or no current will flow.

Is solar power and solar energy the same thing ?

Answers

Answer:

yes I think

Explanation:

Solar energy systems refer to any technology that converts the sun's energy into another form of energy, such as heat or electricity. ... Solar power is a a subset of solar energy, a more narrow term that typically refers to the conversion of the sun's rays to electricity.

Which statement best describes work in the scientific sense?
O A. Work is the sum of the distances an object moves due to the
forces applied to it.
O B. Work is the number of tasks done in the amount of time needed to
complete them.
O C. Work is the ratio of the force acting on an object and the distance
the object travels.
O D. Work is the product of a force and the distance an object moves
because of the force.

Answers

Answer:

the answer is D I tought

Suppose a mad scientist went back in time to the beginning of the solar system and caused the newly formed Mars and Venus to switch places. So now there is a Venus-sized planet where Mars was (let's call it Venus 2), and a Mars-sized planet where Venus was (let's call it Mars 2). How would these hypothetical new planets, Mars 2 and Venus 2, turn out in this alternate time line

Answers

Answer:

Mars2   illuminated side of the planet is very  heat, dark side very cool

Venus 2 a warm planet with a constant temperature across the entire surface

Explanation:

For this hypothetical case, when changing the planets they are changed with their current characteristics.

Case of Mars2

In this case, there is a planet with a very thin atmosphere, so the solar radiation reaches the ground without damping it, causing a lot of noise, so the illuminated side of the planet is very heat and when the dark side turns due to the little atmosphere it loses everything the heat for which it is very cold.

This thermal stress between the two sides of the planet continues constantly creating possible fruit trees in its rocky systems.

Case of Venus 2

The planet has a high atmospheric density, but it is very far from the sun, so the amount of radiation that arrives slightly warms the planet, but due to the thin atmosphere the losses for the dark period are very small, so the entire planet it is heated until it reaches an almost uniform temperature over its entire surface.

In this case we have a warm planet with a constant temperature across the entire surface, regardless of which side is lit.

Part A
When you sneeze, the air in your lungs accelerates from rest to 125 km/h in approximately 0.30 s. What is the acceleration of the air in m/s²?
Express your answer to two significant figures and include the appropriate units.
Value
Submit
Request Answer
m/s²
?

Answers

The value of acceleration is 3 m/s2.

What is Acceleration?

Our body makes every effort to open up our airways. When sneezing, the diaphragm, abdomen, vocal cord, and chest muscles all work together. As a result, the air leaving our lungs accelerates rapidly.

Change in velocity, Δv

Change in time, Δt

Note that

1 km = 1000 m

1 h = 3600 s

Therefore

Δv = (125,000 m/h)*(1/3600 h/s) = 3 m/s2.

Therefore, The value of acceleration is 3 m/s2.

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Which of the following words means resources that are drawn from nature and used with few modifications. a. natural resource b. renewable c. competition d. non-renewable

Answers

correct option in a. natural resources

Resources that are drawn from Nature and used without much modification are called natural resources. The air we breathe, the water in our rivers and lakes, the soils, and minerals are all natural resources.

Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93

Particles q +8.0 C, q2 +3.5 C, and93-2.5 C are in a line. Particles q and q2 areseparated by 0.10 m and

Answers

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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HELP PLEASE DUE IN 3 MINUTES

HELP PLEASE DUE IN 3 MINUTES

Answers

Answer:

africa

Explanation:

África África ooo

The answer is Pangaea

4- What force must be applied to a surface area of 0.0025m , to create a pressure ol
200.000Pa?​

Answers

Force = area * pressure
F = 0.0025 m * 200000 pa
F = 500 N

Any forensic scientist is equipped to study an explosion crime site.

Answers

Answer:

false

Explanation:

I had the same answer for this question on my schoolwork

:) HOPE THIS HELPS

Answer:

It is false

Explanation:

I just took the test, sorry for no other explanation. Have a fabulous day!

What is the minimum amount ( in kg) of liquid water at 26 degrees that would be required to completely melt 41 grams of ice? The specific heat capacity of liquid water is 4180 J/kg/°C and the specific heat of fusion of ice is 3.33×105 J/kg.

Answers

Approximately 0.123 kg of liquid water at 26 degrees Celsius would be needed to melt 41 grams of ice.


To calculate the minimum amount of liquid water required to melt 41 grams of ice at 0°C, we need to consider the energy required for the phase change from solid to liquid, which is known as the specific heat of fusion of ice.

The energy required to melt 1 kg of ice is 3.33×105 J/kg.

Therefore, the energy required to melt 41 grams of ice is (3.33×105 J/kg) × (41/1000) kg = 13653 J.

To calculate the amount of liquid water required, we use the specific heat capacity of water, which is 4180 J/kg/°C.

Assuming the initial temperature of water is 26°C, the amount of water needed can be calculated as (13653 J) ÷ (4180 J/kg/°C) ÷ (26°C) = 0.123 kg or approximately 123 ml of water.

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Calculate the magnetic field at point P in the image below.

Calculate the magnetic field at point P in the image below.

Answers

Answer:

B. 10.08

C.2448

Explanation:

Terminal velocity. A rider on a bike with the combined mass of 100kg attains a terminal speed of 15m/s on a 12% slope. Assuming that the only forces affecting the speed are the weight and the drag, calculate the drag coefficient. The frontal area is 0.9m2 .

Answers

Answer:

0.9378

Explanation:

Weight (W) of the rider = 100 kg;

since 1 kg = 9.8067 N

100 kg will be = 980.67 N

W = 980.67 N

At the slope of 12%, the angle θ is calculated as:

\(tan \ \theta = \dfrac{12}{100} \\ \\ tan \ \theta = 0.12 \\ \\ \theta = tan^{-1}(0.12) \\\\ \theta = 6.84^0\)

The drag force D = Wsinθ

\(\dfrac{1}{2}C_v \rho AV^2 = W sin \theta\)

where;

\(\rho = 1.23 \ kg/m^3\)

A = 0.9 m²

V = 15 m/s

Drag coefficient \(C_D = \dfrac{2 *W*sin \theta}{\rho *A *V^2}\)

\(C_D =\dfrac{2 *980.67*sin 6.84}{1.23 *0.9 *15^2}\)

\(C_D =0.9378\)


A jet needs to reach a "lift-off' speed of 120 m/s before it can leave the ground. How quickly must
the jet accelerate if the run way has a length of 322 m?

Answers

The jet must accelerate in 5.37 s if it must reach the lift-off speed

From the question given above, the following data were:

Initial velocity (u) = 0 m/s

Final velocity (v) = 120 m/s

Distance (s) = 322 m

Time (t) =?

The time needed for the jet to accerate can be obtained as follow:

\(s = \frac{(v + u)t}{2} \\ \\ 322 = \frac{(120 + 0)t}{2} \\ \\ 322 = \frac{120t}{2} \\ \\ cross \: multiply \\ \\ 120t = 322 \times 2 \\ \\ 120t = 644 \\ \\ divide \: both \: side \: by \: 120 \\ \\ t = \frac{644}{120} \\ \\ \)

t = 5.37

Thus, the jet must accelerate in 5.37 s in order to reach the lift-off speed

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As the jet leaves the ground, it accelerates at a rate of 22.4 ms-2.

We have the following information from the question;

Final velocity = 120 m/s

Initial velocity = 0 m/s

Distance covered = 322 m

Acceleration = ?

Using the equation;

v^2 = u^2 + 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance

(120)^2 = 0^2 + (2 × a × 322)

14400 = 644a

a = 14400/644

a = 22.4 ms-2

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A 1.2-kg mass is projected from ground level with a velocity of 31.3 m/s at some unknown angle above the horizontal. A short time after being projected, the mass barely clears a 16-m tall fence. Disregard air resistance and assume the ground is level. What is the kinetic energy of the mass as it clears the fence

Answers

Answer:

The kinetic energy will be "399.65 J".

Explanation:

Given:

Mass,

m = 1.2 kg

Velocity,

v = 31.3 m/s

The total energy of mass will be:

⇒ \(E=K+U\)

or,

⇒ \(E=.5mv^2+mgh\)

By putting the values, we get

        \(=.5(1.2)(31.3)^2+0\)

        \(=0.6\times 979.69+0\)

        \(=587.81 \ J\)

Since,

The system's total energy is unchanged, then

⇒ \(E=K+U\)

or,

⇒ \(E=K+mgh\)

   \(587.81=K+1.2(9.8)(16)\)

   \(587.81=K+188.16\)

          \(K=587.81-188.16\)                

               \(=399.65 \ J\)

.An airplane accelerates down a runway at
3.20 m/s2 for 32.8 s until is finally lifts off the
ground. Determine the distance traveled before
takeoff.

Answers

Starting from rest, the plane travels a distance

x = 1/2 at²

with acceleration a after time t. In this instance, it travels

x = 1/2 (3.20 m/s²) (32.8 s)²

x ≈ 1720 m

which two technologies use lenses

Answers

well the two technologies that i can think of are microscopes and telescopes since they can see things up closer.

what do all elements have in common?
A.they cannot lose or gain electrons
B. They are made of a single type of atom.
C.they have the same number of protons
D.they have the same number of neutrons

Answers

B…. … …..,…… …., ,,,,,,

Answer:

B) All elements are made of a single type of atom.

Explanation:

Elements are made up of a single type of atom and are bound together chemically. Elements cannot be broken down further by chemical or physical means.

Hope this helps.

Please mark me as brainliest.

How do you calculate the maximum angle at which an object will not slip on an incline? I know that it's arctan(μ) but why? Where does that come from? Thank you in advance!

Answers

The maximum angle at which an object will not slip on an incline can be calculated using the coefficient of friction (μ).

Balance of forces on an incline

When an object is on an inclined plane, there are two main forces acting on it: the gravitational force pulling it downward (mg) and the normal force (N) exerted by the inclined plane perpendicular to its surface. Additionally, there is a frictional force (F) acting parallel to the surface of the incline.

To prevent slipping, the frictional force must be equal to or greater than the force component pulling the object down the incline. This force component is given by the equation F = mg sin(θ), where θ is the angle of inclination.

The maximum frictional force that can be exerted between two surfaces is given by the equation F = μN, where μ is the coefficient of friction.

For an object not to slip, the maximum frictional force (F) must be equal to or greater than the force component pulling the object down the incline (mg sin(θ)). Therefore, we have:

F ≥ mg sin(θ)

Substituting F = μN, we get:

μN ≥ mg sin(θ)

Since N = mg cos(θ) (the normal force is equal to the component of the gravitational force perpendicular to the incline):

μmg cos(θ) ≥ mg sin(θ)

μ cos(θ) ≥ sin(θ)

Now, divide both sides of the equation by cos(θ):

μ ≥ tan(θ)

Taking the inverse tangent (arctan) of both sides, we get:

θ ≤ arctan(μ)

Therefore, the maximum angle at which an object will not slip on an incline is given by θ = arctan(μ).

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PLEASE HELP SOON! For the circuit below , the battery has 4.2V calculate power giving and power receiving

PLEASE HELP SOON! For the circuit below , the battery has 4.2V calculate power giving and power receiving

Answers

For this circuit, the voltage is 4.2 V. then power given is 0.9 W and receiving across 55Ω resistance is 0.07 W and that of 30Ω resistance is 0.14 W. Resistor are connected in parallel, its equvalent resistance is R₁R₂/R₁+R₂.

Both resistor are connected in parallel hence their equivalent resistance in parallel combination is given as,

R = 55*30/(55+30)

R = 19.4 Ω

Power given to the circuit is,

P = V²/R = 4.2/19.4 = 0.9 W

Receiving power taken from 55Ω resistor

P = V²/R = 4.2/55 = 0.07 W

Receiving power taken from 30Ω resistor

P = V²/R = 4.2/30 = 0.14 W

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what is a water resavore.......................................

Answers

Answer: A Water resavoir is a place where they hold water until needed. Like let's say there was a drought in Arizona, the state would rely on the resavoir's until the drought is gone. I hope I explained it well.

A soccer player kicks a soccer ball (m = 0.42 kg) accelerating from rest to 32.5m/s in 0.21s. Determine the force that sends soccer ball towards the goal.
Plis I need Help:(

Answers

Answer:

F=65 N

Explanation:

Uniform Acceleration

When an object changes its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

\(v_f=v_o+a.t\)

Solving for a:

\(\displaystyle a=\frac{v_f-v_o}{t}\)

Where:

vf  = Final speed

vo = Initial speed

a   = Constant acceleration

t   = Elapsed time

The ball is kicked from rest vo=0 to vf=32.5 m/s in t=0.21 s. Computing the acceleration:

\(\displaystyle a=\frac{32.5-0}{0.21}\)

\(a=154.8\ m/s^2\)

Note: We have shown this result rounded to the nearest tenth, but we kept all the decimals in a scientific calculator for further calculations.

The force needed to accelerate the soccer ball is calculated by:

F = ma

The ball has a mass of m=0.42 kg, thus:

F=0.42*154.8

F=65 N

As mentioned, this result can only be obtained by keeping full precision in the above calculations.

An object traveling at 1.5 rad
accelerates at 0.75d for 12
S
seconds. What is the object's final
velocity?

Answers

The object's final velocity, given the data is 10.5 rad/s

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

How to determine the final velocity

The following data were obtained from the question

Initial velocity (u) = 1.5 rad/sAcceleration (a) = 0.75 rad/s²Time (t) = 12 sFinal velocity (v) = ?

The final velocity can be obtained as follow:

a = (v – u) / t

0.75 = (v – 1.5) / 12

Cross multiply

v – 1.5 = 0.75 × 12

v – 1.5 = 9

Collect like terms

v = 9 + 1.5

v = 10.5 rad/s

Thus, the final velocity of the object is 10.5 rad/s

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A 500 g object is dropped from a height of 2 meters. What is its kinetic energy just before it hits the ground?

Answers

Answer: 9.8 J

Explanation:

Since the gravitational potential energy of the object is mgh or mass*acceleration due to gravity*initial height, its \(U_{g}\) is 9.8 J. Due to the Law of Conservation of Energy, its kinetic energy will also be 9.8 J. This can be seen in the equation \(KE_{i}+ PE_{i}= KE_{f} + PE_{f}\). Since there is no initial kinetic energy and no final potential energy, its initial potential energy is equal to its final kinetic energy.

Answer:

9.81 joules.

Step by step solved:

The kinetic energy (KE) of an object is given by the formula:

KE = 1/2 * m * v^2

where m is the mass of the object and v is its velocity.

When an object is dropped from rest, it gains speed as it falls due to the force of gravity. The velocity of a falling object can be calculated using the formula:

v = √(2gh)

where g is the acceleration due to gravity (9.81 m/s^2) and h is the height from which the object is dropped.

In this problem, the mass of the object is 500 g or 0.5 kg, and the height from which it is dropped is 2 meters. Using the formula for velocity, we get:

v = √(2gh) = √(2 x 9.81 m/s^2 x 2 m) = √(39.24) = 6.27 m/s

Now that we know the velocity of the object just before it hits the ground, we can calculate its kinetic energy using the formula:

KE = 1/2 * m * v^2 = 1/2 * 0.5 kg * (6.27 m/s)^2 = 9.81 J

Therefore, the kinetic energy of the 500 g object just before it hits the ground is 9.81 joules.

A beam of light is incident on a flat piece of polystyrene at an angle of 21.98o relative to a surface normal. What angle does the refracted ray make with the plane of the surface ?

Answers

Given:

The angle of incidence is

\(\angle i\text{ = 21.98}^{\circ}\)

The light travels from the air to polystyrene.

The refractive index of air is n1 = 1

The refractive index of polystyrene is n2 = 1.6

Required: Angle of refracted ray.

Explanation:

According to Snell's law,

\(\begin{gathered} n1sin\text{ i =n2sin r} \\ sin\text{ r=}\frac{n1sin\text{ i}}{n2} \end{gathered}\)

On substituting the values, the angle of refraction will be

\(\begin{gathered} sin\text{ r =}\frac{1\times sin\text{ 21.98}^{\circ}}{1.6} \\ r=sin^{-1}(\frac{1s\imaginaryI n(\text{21.98})^{\operatorname{\circ}}}{1.6}) \\ =13.53^{\circ} \end{gathered}\)

The angle of refraction is 13.53 degrees.

Final Answer: The angle of refraction is 13.53 degrees.

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