what is the correlation between the number of different codons of an amino acid and the frequency of the amino acid in proteins for this bacteria?

Answer:

See Explanation

Explanation:

It is a common observation that a strip of aluminium metal in aqueous copper(II)Sulfate does not show any visible reaction. Aluminium is normally expected to displace copper in solution since it is higher than copper in the electrochemical series.

The reason for this is that aluminium forms an oxide film around its surface which prevents reaction with aqueous copper(II)Sulfate. This oxides film protects the aluminium surface such that it is now unable to react with the aqueous copper(II)Sulfate

Answer:

2

Explanation:

2

The correct chemical formula for barium nitride is: b. Ba3N2

The chemical formula for barium nitride can be determined by balancing the charges of the ions involved. Barium ions carry a 2+ charge, while nitrogen ions carry a 3- charge.

To balance the charges, we need two barium ions (2 × 2+ = 4+) for every three nitrogen ions (3 × 3- = 9-). The positive and negative charges must cancel each other out in the compound.

Therefore, the correct chemical formula for barium nitride is: b. Ba3N2

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The IR spectrum of Acetylferrocene will differ from that of Ferrocene because of the carbonyl stretching and bending modes that appear in the Acetylferrocene.

The IR spectrum of Acetylferrocene will differ from that of Ferrocene due to the carbonyl stretching and bending modes that appear in the Acetylferrocene.

Ferrocene and Acetylferrocene have similar IR spectra since they both have the Fe-Cp stretching and bending modes. The acetyl group of Acetylferrocene is reflected by an intense band in the 1700-1750 cm-1 range, which is due to carbonyl stretching.

                                     In Acetylferrocene, the IR spectra are dominated by the presence of the acetyl group's vibration, resulting in a change in the frequency of stretching vibration from 200 to 220 cm−1. Another change in the IR spectra of Acetylferrocene is the presence of two bands due to C-O stretching at 1230-1260 cm-1 in addition to the appearance of a strong band due to C-H bending vibrations in the 1410-1450 cm-1 region.

                           Ferrocene does not have a carbonyl group, which is why it will not display the carbonyl stretching and bending vibrations in the IR spectra. This is the most significant difference between the two IR spectra. So, we can conclude that the IR spectrum of Acetylferrocene will differ from that of Ferrocene due to the presence of the carbonyl group.

Therefore,  The IR spectrum of Acetylferrocene will differ from that of Ferrocene because of the carbonyl stretching and bending modes that appear in the Acetylferrocene.

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Answer:

A)

Explanation:

Increasing of oxidation number shows that the process is oxidation(or losing of electrons).

-1 to +2, oxidation number is increased. This is an oxidation process.

-  

a) We have a Fe ion with a positive charge +2, therefore we will also have a Fe ion with a +3 charge.

The charge difference is +1, this means that the Fe3+ ion gained an electron, therefore 1 must be put in front.

b) Now, in the second reaction we have 4 oxygens in the reactants and one in the products, so we put the coefficient 4 in front of H2O and thus we will have 4 oxygens in the products.

Now it would be necessary to balance the hydrogens, we have 8 hydrogens in the products and 1 in the reactants, so we put the coefficient of 8 in front of the hydrogen

Now the Mn, there is an atom of Mn in the reactants, the coefficient 1 is placed in front of the Mn+2.

So far the balanced reaction will go like this:

We need to balance the electrons. For that, we see what is the oxidation state of Mn in the molecule MnO4-. Oxygen has an oxidation state of -2.:

The oxidation state in the MnO4 molecule is +7, therefore it must gain 5 electrons to be left with a +2 charge.

And so we have the balanced equation.

Answer:0.67

Explanation:

Answer:

The event placed in order is;

b, a, c, d

Explanation:

1) b) The marble is placed on a wooden sled

Before the marble is lifted up the ramp, it is placed on a wooden sled that allows the pulley system which can be attached to the wooden sled to lift it up the ramp

2) a) The marble is moved up the ramp using the pulley system

The attached pulley system is then used to move the marble up the ramp

3) c) Iron wedges are used to break the massive marble

The massive marble is broken into pieces that can be worked upon by each mason

4) d) Masons begin carving the marble

The masons (more than one mason) begin carving the pieces of marbles into shape

There are 0,419 moles of glucose in a sample that weights 75.5g.

To calculate the amount in moles of glucose in 75.5g, we first need the molar mass of this compound. To calculate that I'll be using the following atomic mass values:

C: 12

H: 1

O: 16

To calculate the molar mass, we multiply the number of atoms by the respective atomic mass:

(6 * 12) + (12 * 1) + (6 * 16) = 180 g/mol

Since the molar mass is 180 g/mol, we know that each mol has 180 g of glucose:

1 mol glucose ---------- 180g glucose

x --------------------------- 75.5g glucose

Solving for x, we have x = 0.419 moles of glucose

Answer:

the tempeture increases

Explanation:

Zn(s) + CuSO4(aq) � ZnSO4(aq) + Cu(s) An important aspect of these experiments is that they are exothermic.

Answer:

the Coriolis effect

Explanation:

the Coriolis effect is a pattern of deflection responsible for this pattern of movement. since the earth rotates on it's axis, circulating air is deflected.

Answer: The Coriolis effect (make the other guy brainlyest he said it first)

Explanation:

Answer:

To avoid spattering

Explanation:

If we are heating a hydrate to drive off the water of crystallization, we must initially heat the hydrate gently, at a lower temperature and then more strongly only after most of the water has been driven off in order to to prevent spattering.

Since we obtain the amount of water by the mass difference, Spattering  decreases the mass of water obtained and ultimately results in a lower percent of water being calculated for the hydrate.

Answer:

a. 0.0413 moles Zn

b. 0.0500 moles HCl

c. HCl is the limiting reactant

d. 0.0250 moles H₂

e. V = 0.56L

Explanation:

The reaction of Zn(s) with HCl is:

Zn(s) + 2HCl (aq) → ZnCl₂ (aq) + H₂(g)

Where 1 mole of Zn reacts with 2 moles of HCl.

a) To convert mass in grams to moles of a substance you need to use molar mass (Molar mass Zn: 65.38g/mol), thus:

2.70g Zn × (1mol / 65.38g) = 0.0413moles of Zn

b. Now, when you have a solution in molarity (Moles / L), you can know the moles of a volume of solution, thus:

Moles HCl:

50.0mL = 0.0500L × (1.00mol / L) = 0.0500 moles HCl

c. The limiting reactant is founded by using the chemical reaction as follows:

For a complete reaction of 0.0500 moles HCl you need:

0.0500 moles HCl × (1 mole Zn / 2 moles HCl) = 0.0250 moles Zn

As you have 0.0413 moles of Zn, and you need just 0.0250 moles for the complete reaction, Zn is the exces reactant and HCl is the limiting reactant

d.As HCl is limiting reactant and 2 moles of HCl react with 1 mole of H₂, moles of hydrogen formed are:

0.0500 moles HCl × (1 mole H₂ / 2 moles HCl) = 0.0250 moles H₂

e. Using PV = nRT, you can find volume of  gas, thus:

PV = nRT

V = nRT / P

Where P is pressure 1atm at STP, n are moles, R is gas consant 0.08206Latm/molK and T is absolute temperature 273.15K at STP.

V = 0.0250molesₓ0.082atmL/molKₓ273.15K / 1atm

V = 0.56L

Answer:

jayfeather friend me    ccccccc

Explanation:

is: cellular respiration creates an energy molecule when glucose is broken down.

Conservation of mass (mass is never lost or gained in chemical reactions), during chemical reaction no particles are created or destroyed, the atoms are simply rearranged from the reactants to the products.

Hello ☺️, given below will be the answers:-

• 1.1 Å = 1.1 x 10^-7 mm

• 5.38 Å = 5.38 × 10^-24 cm³

• 0.234 mg = 0.000234 kg

✍️ By Benjemin ☺️

In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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Answer:

6

Explanation:

2+2=6

Answer:

3.10 × 4.520 = 14.0

Explanation:

Sig Figs

3

Decimals

1

Scientific Notation

1.40 × 10'

When aqueous solutions of potassium acetate (KC2H3O2) and sodium sulfide (Na2S) are combined, a reaction will occur.

The reaction can be represented by the following chemical equation:2KC2H3O2(aq) + Na2S(aq) → 2NaC2H3O2(aq) + K2S(aq) In this reaction, the potassium acetate and sodium sulfide react to form sodium acetate (NaC2H3O2) and potassium sulfide (K2S) in aqueous solution. Therefore, a reaction does occur when aqueous solutions of potassium acetate and sodium sulfide are combined. Aqueous solutions of potassium acetate (CH3COOK) are formed when potassium acetate is dissolved in water. When potassium acetate dissolves in water, it dissociates into its constituent ions, potassium cations (K+) and acetate anions (CH3COO-). Potassium acetate solutions are often used in various applications such as a buffer solution in biochemistry experiments, as a deicer in winter road maintenance, and as a food additive in some processed foods.

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The compound that will readily react with the solution of bromine resulting from the mixture of hydrobromic acid and hydrogen peroxide is option (a) Cyclohexene.

A solution is a specific kind of homogenous mixture made up of two or more components that is used in chemistry. A solute is a substance that has been dissolved in a solvent, which is the other substance in the mixture.

Free bromine (Br2), a potent electrophilic and oxidizing agent, can be produced in situ by mixing hydrobromic acid (HBr) and hydrogen peroxide (H2O2). So, we must choose a substance that Br2 can easily react with in these circumstances.

Cyclohexene, one of the provided compounds, is an unsaturated double-bonded molecule that can go through electrophilic addition processes. With alkenes like cyclohexene, bromine easily engages in an electrophilic addition process to generate a dibromoalkane.

Hence, option (a) cyclohexene is the substance that will most rapidly react with the bromine solution produced by the mixture of hydrobromic acid and hydrogen peroxide.

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Answer:

3F2+P2_>2PF3now f is 6 on both sides and your p is also 2 on both sides

Answer

3.075 g Fe²⁺

Procedure

The formula of iron (II) sulfite is FeS, to get the grams of Fe²⁺ present, we need to determine the ratio of the elements that form the molecule.

Fe = 55.845 g/mol

S = 32.065 g/mol

FeS = 55.845 g/mol + 32.065 g/mol = 87.91 g/mol

Ratio Fe = 55.845/87.91= 0.6353

Ratio S= 32.065/89.91 = 0.3647

Grams of Fe²⁺ = 4.84 (0.6353) = 3.075 g Fe²⁺

Answer: 2.94x10^22 atoms of O2

Explanation:

To determine the number of atoms in a given volume of a gas, you need to know the molar volume of the gas and the number of moles of the gas present.

The molar volume of a gas at standard temperature and pressure (STP) is 24.45 L/mol. At STP, the pressure is 1 atm and the temperature is 0°C (273.15 K).

So, to find the number of moles of a gas present in a container, you can use the Ideal Gas Law: PV = nRT.

Where:

P = pressure (atm)

V = volume (L)

n = number of moles

R = ideal gas constant (0.0821 L·atm/mol·K)

T = temperature (K)

So we can rearrange the formula to find n = PV/RT

n = (2.44 atm * 2.54 L) / (0.0821 L·atm/mol·K * 275 K) = 0.049 moles

To find the number of atoms of O2, we just multiply the number of moles by Avogadro's number which is 6.022x10^23 atoms/mol.

So the number of atoms of O2 in 2.54 L at 2.44 atm and 275 K is:

6.022x10^23 atoms/mol * 0.049 moles = 2.94x10^22 atoms of O2

This is the number of atoms of O2 present in the container.

A Weak base (B) has a pKb value of 5.64. pH can be calculated as follows: pKb + pOH = 14pOH = 14 - pKbpOH = 14 - 5.64pOH = 8.36pH = 14 - 8.36pH = 5.64The [BH+] and [B] are equal at pH 5.64.

The species of B that predominates at pH 6.27 can be determined by comparing the pH and pKb values of B with the Henderson-Hasselbalch equation: pH = pKb + log([BH+]/[B])6.27 = 5.64 + log([BH+]/[B])[BH+]/[B] = 1.96 [BH+]:[B] = 1.96:1Since [BH+] > [B] at pH 6.27, the predominant species is BH+.

Similarly, we can determine the predominant species of B at pH 10.87:pH = pKb + log([BH+]/[B])10.87 = 5.64 + log([BH+]/[B])[BH+]/[B] = 333.52[BH+]:[B] = 333.52:1Since [BH+] >> [B] at pH 10.87, the predominant species is BH+.So, the answers are:[BH+]=[B] at pH 5.64. The predominant species at pH 6.27 is BH+. The predominant species at pH 10.87 is BH+.

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Answer:

he distance to a star can be found by comparing its luminosity to its apparent brightness.

Explanation: A star that is far away will be very dim compared to its luminosity. So it proves that  the ratio of its luminosity to apparent brightness will be greater than for a nearby star.

S denotes the ''number of shared electron pairs by an atom'', Hence, Silicon shares its 4 electrons with 4 Cl-atoms. Thus the Value of S is 4 in SiCl₄ .It is also known as covalency

The number of covalent bonds that a particular atom can make with other atoms in forming a molecule.

Covalent bond id formed by the sharing of electron between two atoms.

Hence, Silicon shares its 4 electrons with 4 Cl-atoms. Thus the Value of S is 4 in SiCl₄ . It is also known as covalency

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The curve represents saturation. Below the curve, the water is unsaturated. Above the curve, water is supersaturated. This means that more solute is present than the water can contain.

The line of the solubility curve indicates that the solution is saturated. A saturated solution is defined as a solution in which 100 g of solute is dissolved in 100 g of water. Simulations below this line indicate unsaturated solutions.

The difference between unsaturated and saturated solutes can be determined by adding very small amounts of solute to the solution. In unsaturated solutes, solutes will dissolve, and solutes in saturated solutes will not dissolve. In saturated solutes, crystals will form very quickly around the added solute.

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Le Chatelier's principle can be used to alter the chemical balance of the reaction N2 + 3H2  2NH3 + energy in the company's favour. This idea states that a shift in temperature, pressure, or concentration will upset an equilibrium in a system.

Ammonia production is an exothermic process. The reaction shifts backward when the temperature rises in order to cancel out the impact of the rise in temperature.

N2(g)+3H2(g)2NH3 Equilibrium constant, KC for the process at 500K is 0.061.(g). The study reveals that the reaction mixture's composition at a specific moment is 3.0 molL-1 N2, 2.0 mol.

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Answer:

I do believe the answer is false.

Hope This Helps!!

To purify a heat-sensitive liquid by distillation without overheating, the distillation process can be performed under reduced pressure, which reduces the boiling point of the liquid.

In this method, the distillation apparatus is operated at a pressure lower than atmospheric pressure, reducing the boiling point of the heat-sensitive liquid. This allows the liquid to be distilled at a lower temperature, reducing the risk of decomposition due to overheating.

The purified liquid can be collected in a cooled condenser, which further helps to prevent overheating and decomposition. This method of distillation under reduced pressure is a gentle and effective way to purify heat-sensitive liquids while minimizing the risk of thermal degradation.

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The experiments that can infer the strength of the intermolecular forces of the compound are melting point of substance, comparing the state of the matter at room temperature and by comparing the viscosity of each substance.

The intermolecular forces are dependent for the melting point of a substance. So, if the melting point of a substance is very high it means that the intermolecular forces between the particle of the matter is very high.

Similarly at the room temperature the state of substance define that at room temperature what is the state of the matter.

The viscosity of the substances also dependent on the intermolecular forces if the intermolecular forces between the layer of the substance is very high then it results in the increase in the viscosity of the substance.

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