what is the current in the 15-w resistor when e = 9.0 v?

Answer: 0.28 A

Explanation:

Answer:

Explanation:

use gauthmat is helpful

To find the electric field between the two points, we can use the formula. So, the electric field between the two points is approximately 10.57 V/m.

Electric field = Potential difference / Distance between the points
Plugging in the given values, we get:
Electric field = 44.4 V / 4.2 m
Electric field = 10.57 V/m
Therefore, the electric field between the two points is 10.57 V/m.

To find the electric field between two points with a potential difference, you can use the formula:
Electric Field (E) = Potential Difference (V) / Distance (d)
In this case, the two points are 4.2 meters apart and the potential difference between them is 44.4 V. Plugging these values into the formula, we get:
E = 44.4 V / 4.2 m
E ≈ 10.57 V/m
So, the electric field between the two points is approximately 10.57 V/m.

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\(\text{Given that,}\\\\\text{Force, F = 20 N.} ~ \\\\ \text{Area , A = 2 m}^2 . \\\\ \text{Pressure, P =? }\\\\P = \dfrac FA = \dfrac{20}2 = 10~~ \text{Nm}^{-2}\)

Hooke's Law gives the relationship between applied forces m·g, 2·m·g and extensions of an elastic material x, 2·x based on its elasticity.

Reason:

Given parameter;

Spring constant = 30 N/m

Value of the extension, x = 0.5 m

Extension of the spring by mass, m = x

Extension of the spring by mass, 2·m = 2·x

Required:

To find the value of mass m.

Solution:

The measures of weight and extension from the diagram are;

\(\begin{array}{|l|cl|}\mathbf{Extension}&&\mathbf{Weight \ (Force), \, F}\\0&&0\\x&&m \cdot g\\2 \cdot x&&2 \cdot m \cdot g\end{array}\right]\)

The rate of change of the extension with the applied force are;

\(Between \ second \ and \ frirst\ row, \ \dfrac{\Delta F}{\Delta x} =\dfrac{m \cdot g}{x}\)

\(Between \ third \ row \ and \ second \ row, \ \dfrac{\Delta F}{\Delta x} = \dfrac{2 \cdot m \cdot g - m \cdot g}{2 \cdot x - x} = \dfrac{m \cdot g}{x}\)

Therefore;

The rate of change of the extension with the applied force, \(\dfrac{\Delta F}{\Delta x}\), is a

constant equal to m·g, and the spring obeys Hooke's law.

Where;

F = The spring force

Therefore;

∴ m·g = -(-k·x) = 30 N/m × 0.5 m

Where;

g = Acceleration due to gravity = 9.81 m/s²

The mass, m ≈ 1.53 kg

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A  radioactive tracer atom with carrier molecules attached to them. They are used in alternate medicine known as radioactive medicine therapy.

Using radioactive tracers (also known as radiopharmaceuticals) to diagnose and treat disease, nuclear medicine is a branch of medicine. Doctors are able to follow the passage of these radioactive tracers thanks to specially created cameras. Carrier molecules that are firmly bound to a radioactive atom make up radioactive tracers. Depending on the goal of the scan, these carrier molecules can have many different forms. Some tracers use chemicals that interact with certain body proteins or sugars, and some even use the patient's own cells. A patient receives an intravenous injection of the radioactive tracer for the majority of nuclear medicine diagnostic procedures.

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Answer:

C. precipitation

Explanation:

if clouds store too much water from evaporation, it will rain which is precipitation

Answer:

because nono gravity

Explanation:

no gravity

Answer:

La tensión es 85.3 N.

Explanation:

Cuando el objeto gira en dirección horizontal, la sumatoria de fuerzas se puede calcular usando la segunda ley de Newton:  

\( \Sigma F_{x} =ma_{c} \)

\( T = ma_{c} \)  

Dado que el movimiento es horizontal, el peso (que está en el eje y) no contribuye en la sumatoria de fuerzas en el eje x. Por lo que la única fuerza actuando sobre el objeto en la dirección del movimiento es la tensión.  

En donde:                                          

m: es la masa del objeto = 200 g = 0.200 kg

\(a_{c}\): es la aceleración centrípeta

La aceleración centrípeta viene dada por:  

\(a_{c} = \omega^{2} r\)

En donde:    

ω: es la velocidad angular del objeto = 3 rev/s

r: es el radio = 1.20 m

Entonces, la tensión es:

\(T = m\omega^{2} r = 0.200 kg(3\frac{rev}{s}*\frac{2\pi rad}{1 rev})^{2}*1.20 m = 85.3 N\)

Por lo tanto, la tensión es 85.3 N.  

Espero que te sea de utilidad!                                                                          

Answer:

12.3°C should be the correct answer

Answer:

12.3

Explanation:

Answer:

See the answer below

Explanation:

According to Amonton's law, the pressure of a gas is directly proportional to the temperature of its molecules given that the volume remains constant.

Hence, if the temperature of a tyre increases, heat is transferred to the air molecules within the tyre leading to an increase in the air temperature. The air thus exerts more pressure on the tyre in agreement with Amonton's law.

Explanation:

-body temp: when cold, erector muscle contract, hair raise, vasoconstriction occurs, sweat production reduces, muscle shiver to enhance metabolism, and thyroid gland secret more thyroxine to enhance metabolism

-water potential balance: when we are thirsty, pituitary gland secret more ADH, kidney tubules become more permeable to water, so more water re-absorbed, less urine produced, retaining more water.

Answer:

The power of the car, the gear ratio, weight of the car, aerodynamics of the car, grip of the tires on the road, calorific value of the fuel used, and friction would affect the speed of the car.

Answer: D

Explanation: a p e x :)

Answer:

B. The magnetic field pushes negative charges and positive charges in opposite directions.

The formula for the magnetic flux is given by:φ = B x Awhere,φ = magnetic flux (weber or tesla meter²).B = magnetic flux density (tesla).A = area of the loop (meter²).

According to the problem, the magnetic flux density increases at the rate of 10 in the z direction, this means that the magnetic field is increasing towards the upper side of the loop and decreasing towards the lower side. Let's consider a clockwise loop with sides of length 'a'.The rate of change of magnetic flux is given by:dφ/dt = B(dA/dt)where,dφ/dt = -B(a²) (as the area of the loop does not change)dA/dt = -a² (as the area of the loop does not change)Therefore,dφ/dt = 10(a²)Now, the electromotive force is given by:e = -dφ/dt = -10(a²)The direction of the induced current in the loop is given by Lenz's law, which states that the direction of the induced current will be such that it opposes the change that produced it. In this case, the induced current will flow in the clockwise direction.The magnitude of the induced current is given by:I = e/Rwhere,R = resistance of the loop.The resistance of the loop is given as distributed resistance, which means the resistance varies throughout the loop. Therefore, we need more information to calculate the resistance of the loop and hence the magnitude of the induced current.

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Several radio telescopes are combined into an interferometer in order to 2) observe astronomical objects during daylight hours when the sky is otherwise too bright.

Radio astronomers may combine the signals from several antennas and even telescopes using interferometry. They are able to produce images that are more brighter and more precise than what is feasible with only one antenna dish.

To investigate objects in space, astronomers utilize a variety of telescopes sensitive to various regions of the electromagnetic spectrum. Despite the fact that all light is fundamentally the same, astronomers view light differently depending on the part of the spectrum they are interested in.

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5,28 ft is the distance from the base of the cliff to the point on the ground.

This question is incomplete, it should be:

Height of the cliff = 462 ft

Angle of depression = 5°

Determine the angle of the base first,

Use the hypotenuse side:

90° - 5° = 85°

Hence, the angle of depression form the top of the cliff = 5°

So, the distance from the base of the cliff to the point on the ground:

tan α = opposite / adjacent

tan 85° = h/462

h = 462 × tan 85°

= 462 x 11.43

h ≈  5,28 ft

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B: q magnet or a magnetic field

(a) The number of Calories required to power the heart for one day is 258 Cal.

(b) The mass of metabolized fat that would power the heart for one day is 0.0287 kg.

The number of Joules of energy required to power the heart for one day is calculated as follows;

Power = 12.5 J / s

Energy = power x time

time = 1 day = 86400 seconds

Energy pumped by heart in one day = 12.5 J/s  x 86400 s = 1,080,000 J

The number of calories contained in 1,080,000 J of chemical energy is calculated as;

1 Calorie = 4186 J

= 1,080,000 J / 4186 J

= 258 Cal

The mass of metabolized fat that would power the heart for one day is calculated as;

9000 Cal = 1 kg

258 Cal = ?

= 258 / 9000

= 0.0287 kg

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Value analysis is a method used to evaluate the worth and effectiveness of an organization or project.

In the case of DEWA (Dubai Electricity & Water Authority), conducting a value analysis can provide insights into the overall value created by the organization. Here are some key points to consider in a value analysis of DEWA:

1. Service Quality: Evaluate the quality and reliability of the electricity and water services provided by DEWA. Assess factors such as uptime, response time, customer satisfaction, and the overall impact on the daily lives of residents and businesses in Dubai.

2. Cost Efficiency: Analyze the cost-effectiveness of DEWA's operations, including the generation, transmission, and distribution of electricity, as well as water production and distribution. Assess the efficiency of resource utilization, cost management practices, and the impact on consumer tariffs.

3. Sustainability: Evaluate DEWA's commitment to sustainable practices, such as renewable energy integration, water conservation efforts, and environmental stewardship. Assess the organization's contributions to reducing carbon emissions and promoting a greener future.

4. Innovation and Technology: Assess DEWA's adoption of innovative technologies, such as smart grids, advanced metering systems, and digital solutions. Evaluate the impact of these technologies on service delivery, efficiency, and customer experience.

5. Stakeholder Engagement: Analyze DEWA's relationships with stakeholders, including customers, suppliers, government entities, and the community. Assess the effectiveness of communication, collaboration, and the organization's contribution to social and economic development in Dubai.

By conducting a comprehensive value analysis of DEWA, stakeholders can gain a holistic understanding of the organization's performance, impact, and value proposition. This analysis can guide decision-making, identify areas for improvement, and support DEWA's ongoing efforts to provide reliable, sustainable, and affordable electricity and water services to the residents and businesses of Dubai.

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Answer:

Explanation:

What is the value of a in the function's equation?

A. -2

B. -3

C. 3

D. 2

ANSWER: c.

Answer:

38.31867 grams

Explanation:

(a) The average pressure exerted by the person is 40,000 N/m².

(b) The average pressure exerted by the elephant is  295,000 N/m².

The average pressure exerted by the elephant is about 7 times greater than the average pressure exerted by the person.

The average pressure exerted by each is defined as the force per unit area.

Mathematically, the formula for average pressure is given as;

P = F/A

where;

P = W / A

where;

The average pressure exerted by the person is calculated as follows;

P = (640 N) / (0.016)

P = 40,000 N/m²

The average pressure exerted by the elephant is calculated as follows;

P = (4.13 x 10⁴ N) / (0.14)

P = 295,000 N/m²

Thus, the average pressure exerted by the elephant and the person depends on their weight and area of their shoes.

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Answer:

For example, if the body rotates around a circle of radius r at 360o, then the angular displacement is found by the distance traveled around the circumference. This is found by 2πr, divided by radius θ = 2πr/r. In simplistic terms, it can be denoted as θ=2π, where 1 revolution is 2π radians.

Explanation:

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To calculate the book value at year 3 (BV3), we need to determine the accumulated depreciation at year 3. The depreciation is calculated by subtracting the salvage value from the initial cost and dividing it by the number of years.

Initial cost: $20,000

Salvage value: $5,000

Number of years: 5

Depreciation per year = (Initial cost - Salvage value) / Number of years

Depreciation per year = ($20,000 - $5,000) / 5 = $3,000

Accumulated depreciation at year 3 = Depreciation per year * Number of years

Accumulated depreciation at year 3 = $3,000 * 3 = $9,000

Book value at year 3 = Initial cost - Accumulated depreciation at year 3

Book value at year 3 = $20,000 - $9,000 = $11,000

Therefore, the Book Value at year 3 (BV3) is $11,000 (option d).

To calculate the depreciation at year 3 (D3), we can simply use the depreciation per year, which is $3,000. Therefore, the Depreciation at year 3 (D3) is $3,000 (option b).

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Gamma-ray bursts are intense flashes of high-energy radiation that come from various sources in the universe. These bursts are short-lived, lasting only a few seconds to a few minutes, and emit more energy in that brief time than our sun will in its entire lifetime.

The majority of gamma-ray bursts come from the distant reaches of space, beyond our own Milky Way galaxy. Scientists believe that most of these bursts are caused by the collapse of massive stars, which create black holes or neutron stars. These events, known as supernovas, release huge amounts of energy in the form of gamma rays.
However, there are also other types of gamma-ray bursts that come from different sources, such as merging neutron stars or even collisions between galaxies. Some gamma-ray bursts have also been detected coming from our own Milky Way, likely caused by the explosive deaths of massive stars.

In summary, gamma-ray bursts come from a variety of sources in the universe, but the majority are caused by the collapse of massive stars into black holes or neutron stars.
Gamma-ray bursts (GRBs) tend to come from two primary sources in the universe. They are extremely energetic and short-lived bursts of gamma-ray light, the most energetic form of electromagnetic radiation.

1. Long-duration GRBs: These bursts typically last from a few seconds to several minutes and are believed to originate from the collapse of massive stars. When a massive star reaches the end of its life, its core collapses into a black hole or a neutron star. This process, known as a core-collapse supernova, releases a tremendous amount of energy in the form of gamma rays. The resulting jet of energy is called a long-duration gamma-ray burst.

2. Short-duration GRBs: These bursts usually last less than two seconds and are thought to result from the merger of two compact objects, such as neutron stars or a neutron star and a black hole. When these objects collide, they release a vast amount of energy in the form of gamma rays, producing a short-duration gamma-ray burst.

Both types of gamma-ray bursts are observed at vast distances across the universe, indicating that they come from diverse cosmic environments. These powerful events serve as important probes of the early universe and can provide valuable information about star formation, cosmic evolution, and the nature of matter under extreme conditions.

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Moving at the same velocity to the East which means that they are both on the same planet in space.

Relative to the center of the Earth, a person on the North Pole is moving at the same velocity to the East because both are present on the same planet in space.

The whole planet of earth spins in the same direction as well as with the same velocity so we can conclude that option A is the correct statement about direction and velocity of the earth.

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It is a linear expansion, when a rod undergoes a change in temperature and there is a change in its length.

The length that a rod changes to as a result of a temperature change relies on the rod's initial length, the rate of temperature change, and the material's coefficient of linear expansion. The formula for linear expansion is:

ΔL = αL₀ΔT

Where ΔL is the change in length of the object, is the coefficient for linear expansion of the material in question, and L₀ is the initial length of the object.

Volumetric expansion refers to change in one dimension (volume), whereas linear expansion refers to change in one dimension (length) (volumetric expansion). The area thermal expansion coefficient connects a material's area changes to temperature changes.

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Complete question is:

A rod undergoes a change in temperature. the change in length is:

A. linear expansion

B. volumetric expansion