What is the decay rate of americium in Gs-1?
Answers
The decay rate of americium in Gs-1 represents the rate at which the isotope undergoes radioactive decay.
The decay rate of americium in Gs-1 refers to the number of radioactive decays that occur per second. Americium-241, the most common isotope of americium, undergoes alpha decay with a half-life of 432 years. During alpha decay, the nucleus emits an alpha particle consisting of two protons and two neutrons. This process leads to the formation of a daughter nucleus, in this case, neptunium-237. The decay rate of americium in Gs-1 can be calculated using the equation λ = ln2/t1/2, where λ is the decay constant, ln is the natural logarithm, and t1/2 is the half-life of the isotope. Thus, for americium-241, the decay rate in Gs-1 is approximately 0.016 disintegrations per second.
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The estimated rate of decay for Americium-241 is about 5.5 × 10²¹ Bq/Gs
What is the decay rate?The extent to which Americium-241 (Am-241) decays can be quantified in becquerels (Bq), a unit that tells the frequency of radioactive disintegrations per second. A gigasecond, denoted as Gs, is equivalent to 1 billion seconds or 10 to the power of 9 seconds.
The radioactive decay of Americium-241 occurs at a rate of around 5. 5 × 10¹² becquerels per gram (Bq/g). If the reference is made to the decay rate of Americium-241 in grams, then the decay rate would be as such.
Multiplying
5. 5 × 10¹² x 10⁹ g = 5.5 × 10²¹ Bq/Gs
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Related Questions
rosbel or Janette lol baakkaaa
Answers
Answer:
t5g5gtttttttttttttttttttttttttttttttttttttttttttt
Explanation:gt555555555555555555555555555555555555555555555555
Answer:
dawbkjbjwwjhjfbfjewfaekfhawkjndwkja
Explanation: dum*as*
A germanium diode carries a current of 1 mA at room temperature when a forward bias of 0.15v is applied. Estimate the reverse saturation current at room temperature.
Answers
I = I0 * (exp(qV/kT) - 1)
where I is the current through the diode, q is the charge of an electron, V is the voltage across the diode, k is Boltzmann's constant, and T is the temperature in Kelvin.
At room temperature, T = 298 K. We are given that the diode carries a current of 1 mA when a forward bias of 0.15 V is applied. Let's assume that the diode is ideal, meaning that it has no series resistance, so the voltage across the diode equals the forward bias voltage.
Plugging in these values, we get:
1E-3 A = I0 * (exp((1.602E-19 C)(0.15 V) / (1.381E-23 J/K)(298 K)) - 1)
Simplifying, we get:
1E-3 A = I0 * (exp(0.01275) - 1)
1E-3 A / (exp(0.01275) - 1) = I0
I0 = 2.34E-12 A, or approximately 0.23 nA. Therefore, the estimated reverse saturation current at room temperature is 0.23 nA.
Determine the slopes and deflections at points B and C for the beam shown below by the moment-area method. E=constant=70Gpa I=500 (10^6)mm^4
Answers
Answer:
hello your question is incomplete attached below is the complete question
answer :
Slopes : B = 180 mm , C = 373 mm
Deflection: B = 0.0514 rad , C = 0.077 rad
Explanation:
Given data :
I = 500(10^6) mm^4
E = 70 GPa
The M / EI diagram is attached below
Deflection angle at B
∅B = ∅BA = [ 150 (6) + 1/2 (300)*6 ] / EI
= 1800 / ( 500 * 70 ) = 0.0514 rad
slope at B
ΔB = ΔBA = [ 150(6)*3 + 1/2 (300)*6*4 ] / EI
= 6300 / ( 500 * 70 ) = 0.18 m = 180 mm
Deflection angle at C
∅C = ∅CA = [ 1800 + 300*3 ] / EI
= 2700 / ( 500 * 70 )
= 2700 / 35000 = 0.077 rad
Slope at C
ΔC = [ 150 * 6 * 6 + 1/2 (800)*6*7 + 300(3) *1.5 ]
= 13050 / 35000 = 373 mm
a c-section specimen is designed to tolerate a stress-concentration factor for 1.75. calculate the allowable normal strength in the c-section if the material used to make the section has a yield strength of 84 kpsi.
Answers
The allowable normal strength in the c-section is 48000 pounds per square inch.
The allowable stress depends on both the factor of safety imposed on the object and the yield strength or stress at which an object will be permanently damaged. To calculate the allowable normal strength we can divide the yield strength by the factor of safety.
To determine the allowable normal strength output we can use this equation below:
The allowable normal strength = The number yield strength : A stress-concentration factor
The number yield strength is 84 kpsi.
Then convert kpsi to psi : 84 kpsi = 84000 psi
A stress-concentration factor is 1.75
The formula to find allowable normal strength output is:
84000 psi : 1.75 = 48000
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Calculate the ID, VG, VS, VD, VGS, VDS values mathematically.
Answers
Answer:
S
Explanation:
Horizontal shear forces and, consequently, horizontal shear stresses are caused in a flexural member at those locations where the internal bending moment is changing along the beam span. The imbalance in the bending stress resultant forces acting on a portion of the cross-section demands an internal horizontal shear force for equilibrium.
a. True
b. False
Answers
Answer:
False
Explanation:
When the horizontal shear forces act on the surface there is transverse shear stress at a particular point which is equal in magnitude. Pure bending is less common than a non uniform bending because the beam is not in equilibrium.
Which of the following statements are true? (Select all that apply.)
When the temperature change during a process is large and the specific heats vary nonlinearly with temperature, the constant-specific-heat assumption is preferred. -Errors introduced by the constant-specific-heat assumption are minimized when the specific heat values are evaluated at room temperature. -When the specific heats are independent of temperature, the constant-specific-heat assumption produces exact answers. -For monatomic ideal gases, the constant specific-heat assumption introduces no error. -The accuracy of using the constant-specific-heat assumption is usually sufficient if the temperature range is not greater than a few hundred degrees.
Answers
The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C)
What is specific heat capacity?The amount of heat needed to raise a substance's temperature by one degree Celsius per gram. In general, specific heat is expressed in calories or joules per gram per degree Celsius. For instance, the specific heat of water is 1 calorie (4.186 joules) per gram per degree Celsius. The notion of specific heat was developed in the 18th century by the Scottish scientist Joseph Black, who noted that equivalent masses of various substances required varying quantities of heat to raise them across the same temperature range.Early in the nineteenth century, Pierre-Louis Dulong and Alexis-Thérèse Petit of France made the case that calculating a substance's atomic weight is possible by measuring its specific heat. likewise see heat capacity.To learn more about specific heat capacity refer to
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Many architects are innovators. Select the examples of innovation presented in this chapter.
A. Arches
B. Flying buttresses
C. Horizontal ribbon windows
D. Flat pack modules
E. Solar panels with DC microgrids
F. A, B, and C only
G. A, B, and D only
Answers
The options A, B, and C are the correct examples of innovation presented in the chapter by architects.
how we know that?
A, B, and C only are the examples of innovation presented in the chapter that are the innovation presented by architects
.What is innovation? Innovation is the process of creating something new or improved, or introducing something new to the market or society.
To produce a new or improved version of something, one must have the desire and resources to do so.
Many architects are innovators, and this chapter provides examples of their innovation.
The following examples of innovation are presented in this chapter :Arches Flying buttresses Horizontal ribbon windows Innovators and architects are usually the ones who are concerned with designing, developing, and enhancing our built environment.
Architects are responsible for designing and planning a wide range of structures and spaces that meet the demands of clients while adhering to rigorous industry and ethical standards.
It is said that architects have a hand in everything from the types of materials and building techniques used in construction to how people interact with the building they design.
Flat pack modules and solar panels with DC microgrids are innovative solutions in today's world, making it more efficient, sustainable, and cost-effective.
These new, cutting-edge solutions are ideal for the modern age, where the need for eco-friendly construction and sustainable living is becoming increasingly important.
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A cylindrical vessel is pressurized to 1.7 MPa. The structure on which the vessel rests becomes damaged, resulting in uneven support that causes a twisting moment T0 of 8 106 N-m on the vessel. The vessel has an outer diameter of 2.5 m and a wall thickness of 50 mm. The steel wall has a uniaxial yield strength of 600 MPa. Determine the factor of safety with respect to yielding (a) assuming a maximum shear stress yield criterion and (b) assuming a von Mises yield criterion.
Answers
Answer:
a) 15.075 , b ) 12.9
Explanation:
pressure on cylindrical vessel = 1.7 MPa
Twisting moment due to pressure = To of 8( 10^6 ) N-m
outer diameter of vessel = 2.5 m
wall thickness of vessel = 50 mm
Steel wall uniaxial yield strength = 600 MPa
Calculate the factor of safety
a) assuming a max shear stress yield criterion
safety factor = 15.075
b) assuming a von Mises yield criterion
safety factor = 12.9
attached below is the detailed solution of the problem
6.
A mobile welding machine of mass 80 kg was rolling freely on a horizontal surface
at speed of 5 m/s when locks to its castor wheels are applied, causing all four wheels
to stop rotating. The machine skidded a distance s-4 m before coming to rest.
Determine
the magnitude of normal reaction of each wheel
(b) the coefficient of kinetic friction between the wheels and the ground.
Answers
The magnitude of reaction for the wheel is 250 N. The coefficient of kinetic energy between the wheel and ground is 0.32.
What is friction?
The friction is given as the stop force acted by the surface to the moving object.
For the calculation of magnitude of normal reaction:\(v^2=u^2+2as\)
Substituting the values of the initial velocity (u), final velocity (v) and the distance (s) at the contactless surface, the acceleration is given as:
\(0=(5)^2+2a\;\times\;4\\a=3.125\;\rm m/s^2\)
The force can be given as:
\(F=ma\\F=80\;\text{kg}\;\times\;3.125\; \rm {m/s^2}\\\textit F=250\;N\)
The magnitude of reaction for the wheel is 250 N.
The coefficient of friction (\(\mu_k\)) is given as:\(\mu_kmgs=\dfrac{1}{2}mv^2\\\)
Substituting the values:
\(\mu_k\;\times\;80\;\times\;9.8\;\times\;4=\dfrac{1}{2}\;\times\;80\;\times\;5^2\\\mu_k=\dfrac{5^2}{2\;\times\;9.8\;\times\;4}\\\mu_k=0.32\)
The coefficient of kinetic energy between the wheel and ground is 0.32.
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he is going ___ in the hot air ballon
Answers
no artical shoul be used here
Identify the prefixes used in the International System of
Units (SI)
Meaning
Prefix
Meaning
Prefix
1/1,000,000
1,000,000
1/1,000
1,000
1/100
100
1/10
10
nce
Answers
Answer:
i need points 425677
Explanation:
yurrrrrr awnser C
6. What is the resistance of a curling iron that draws 12 A of current on a 120 V circuit?
Answers
Answer:
10 ohms Ω
Explanation:
V = IR
120 = I(12)
120/12 = 10Ω
According to the EWR specifications, ___ is responsible for picking up and disposing of debris or rubbish from
equipment installed by the electrical contractor on the project.
Select one:
a. The general contractor
b. Contracted laborers
c. The electrical contractor
d. none of these
Answers
Answer:
The correct answer is C) Electrical Contractor
Explanation:
EWR refers to Electrical Work Request.
According to the EWR Specifications, the Contractor is responsible for picking up and disposing of debris or rubbish from equipment installed by the electrical contractor on the project.
The EWR specification state that:
For the disposal of building waste materials, and garbage, the contractor shall have on-site enclosed dumpsters or bins and shall regularly eliminate the items referred to above from the site.
Cheers
0-0 what is Boyle’s Law
Answers
Hope it helps
Who is responsible for shielding a welding arc to protect
the eyes and skin of all persons in the working area?
Answers
Answer:
manager and supervisor
Explanation:
Which of these is known as the greatest danger associated with excavations?
Select the best option.
Asphyxiation
Cave-ins
Fire
Underground utility lines
Answers
Answer:
Cave-ins
Explanation:
The term excavation means any form of cuts, depression or trench by removing the surface of the earth. This process is intended primarily for the purpose of construction and maintenance or exploration. In this process there are many hurdles that pose danger to both human life and earth. The excavation workers face the great threat because of cave-ins. The collapsing of the earth's surface and random accidents prove to be very dangerous for the workers.
a series could be an arithmetic progression or geometric progression or fibonacci series.you will be provided with N numbers. you task is to identify which series it is, and find the next number in that series.
Answers
Answer:
import java.util.*;
class fibonacci
{
public static void main(String args[])
{
Scanner scanner = new Scanner(System.in);
int n1=0,n2=1,n3,i,count;
count = scanner.nextInt();
System.out.print(n1+" "+n2);//printing 0 and 1
for(i=2;i<count;++i)
{
n3=n1+n2;
System.out.print(" "+n3);
n1=n2;
n2=n3;
}
}
}
Explanation:
Resistors are used to reduce current flow, adjust signal levels to divide voltages, bias active elements and terminate transmission line.true or false
Answers
Answer:
True
Explanation:
Those are the exact uses of a resistor
the shear strength of each of ten test spot welds is determined, yielding the following data (psi): 392 376 401 367 389 362 409 415 358 375 a. assuming that shear strength is normally distributed, estimate the true average shear strength and standard deviation of shear strength using the method of maximum likelihood. b. again assuming a normal distribution, estimate the strength value below which 95% of all welds will have their strengths. [hint: what is the 95th percentile in terms of m and s? now use the invariance principle.] c. suppose we decide to examine another test spot weld. let x 5 shear strength of the weld. use the given data to obtain the mle of p(x
Answers
(a) The sample mean is calculated as 382.3 psi and sample standard deviation is calculated as 19.76 psi.
(b) The 95th percentile is calculated as 414.80 psi that is below 414.80 psi, the 95% of all the welds have their strengths.
(c) There are 81.5% chances that the shear strength of the welds is less than or equal to 400 psi.
What is standard deviation?A statistic known as the standard deviation, which is calculated as the square root of variance, gauges a dataset's dispersion from its mean. By figuring out how far off from the mean each data point is, the standard deviation can be calculated as the square root of variance.
A higher deviation exists within a data set if the data points are further from the mean; consequently, the higher the standard deviation, the more dispersed the data.
By comparing the annual rate of return of an investment to the standard deviation, a statistical measurement used in finance, one can learn more about the historical volatility of that investment.
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In this figure, assume there is no slip on any of surfaces and the slab is slowly moving down. A- Direction of friction force on the slab (from the rollers) is down
B-velocity of the center of the rollers is the same as that of the slab
C - direction of friction force on the slab (from the rollers) is up
D-velocity of the center of the rollers is half of that of the slab
Answers
The slab experiences downward-directed friction force from the rollers.
What forces you to stop when you slide on a slick floor and finally slow down?The force that prevents motion between two surfaces that are touching one another is known as friction. Without friction, you wouldn't be able to walk since your feet would just slide across the floor. Friction is an essential component of daily living.
What kind of friction prevents slipping or sliding* by slowing down or stopping motion?A surface cannot be moved by an item due to static friction. The force that prevents a book from slipping off a desk even when the desk is slightly inclined and that enables you to pick up an object without the need for a hand grip item that eludes your grasp.
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Find the perpendicular distance from the point P(9,11,−8) ft to a plane defined by three points A(1,9,−4) ft, B(−4,−8,6) ft, and C(−1,−2,2) ft
Distance = ______ ft
Answers
Answer:
0 ft
Explanation:
The equation of the plane can be found from the cross product AC×BC. That vector is ...
N = (2, 11, -6) × (-3, -6, 4) = (8, 10, 21)
Then the equation of the plane is ...
8x +10y +21z = 14 . . . . . 14 = N·A
Point P satisfies this equation, so is on the plane. The distance is 0 feet.
8(9) +10(11) -8(21) = 72 +110 -168 = 14
when will a station send a reassociation request frame?
Answers
A station will send a reassociation request frame when it wants to move to a different access point within the same wireless network.
When a station roams from one location to another while maintaining the same wireless network connection, it may need to switch to a different access point that provides a stronger signal or better quality of service. To do this, the station will send a reassociation request frame to the new access point, which includes information about the station's identity and capabilities. The new access point will then respond with a reassociation response frame, indicating whether the station is authorized to join the network and providing the necessary configuration information for the station to connect to the new access point.
Reassociation request frames are part of the IEEE 802.11 standard for wireless local area networks (WLANs) and are used to facilitate seamless roaming between access points. They are sent by the station using the media access control (MAC) layer of the protocol and include a timestamp and other parameters that allow the new access point to synchronize with the station's current connection. The reassociation process helps to ensure that wireless clients can maintain a stable network connection while moving around within a WLAN, without having to disconnect and re-establish the connection each time they move to a new access point.
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For the following production environments, indicate whether the preferred production system is more likely to be a job shop (process layout), production line (product layout), batch process (group technology layout), or hybrid. Provide support for your answer.
a. Manufacturer of Clothes: makes many styles (shirts, pants, coats, rain jackets, etc.) and sells to small specialty stores.
b. Manufacturer of Gaskets: makes styles for 4-5 engine blocks: sells to GM and Ford (i.e., high volume).
c. Independent Automobile Service Shop: body work, general service, engine repair, serving many makes of automobiles.
d. Producer of Pharmaceutical Drugs: make approximately 50-75 drugs in tablet form: sell to pharmacies nationwide.
Answers
Answer:
A) Batch shop production
B) Batch shop production
C) Job shop production
D) production line
Explanation:
A)The preferred production system here will be Batch shop production because the manufacturer produces different styles of clothing and sells to small specialty stores hence producing in Batches can help meet up the needs
B) The preferred production system here will be Batch shop production because the manufacturer produces Gaskets and they are of different styles hence he needs to produce them in batches
C) Job shop production
D) production here is streamlined to a particular ( tablet form ) hence the production system here would be a Production line system of production
Assume this attempted implementation of a lock: void init(lock_t∗mutex) \{ mutex-> flag=0; // 0 -> lock is available, 1 -> held \} void lock(lock_t∗mutex) \{ while (mutex->flag==1) mutex-> flag = 1 \} void unlock(lock_t *mutex) \{ mutex->flag=0\} Assume 5 threads are competing for this lock. How many threads can possibly acquire the lock? Note: More than one answer. a.1 b.2 c.3 d.4 e.5 Given the following command:prog1 < file1.txt ∣ prog 2 prog3 > file3.txt Please describe the FDs (file descriptors) for each of the programs.
Answers
In the case of the student question provided, we are asked to assume an attempted implementation of a lock and determine how many threads can possibly acquire the lock.
The implementation includes three functions: init(), lock(), and unlock(). The init() function initializes the lock to be available with a flag value of 0. The lock() function waits while the flag value is 1, indicating that the lock is currently held by another thread. The unlock() function sets the flag value back to 0, indicating that the lock is available againGiven that 5 threads are competing for the lock, it is possible for up to 4 threads to acquire the lock. The reason for this is that one thread can initialize the lock to be available (flag = 0), and then up to three additional threads can acquire the lock before the flag is set back to 0 by the first thread to release the lock.In the second part of the question, we are given a command (prog1 < file1.txt | prog2 prog3 > file3.txt) and asked to describe the file descriptors (FDs) for each of the programs. File descriptors are used by Unix-like operating systems to represent file-like objects such as input/output files, pipes, sockets, and devices.In this command, prog1 is being run with input from file1.txt and its output is being piped to prog2. The file descriptor for file1.txt is 0 (standard input), and the file descriptor for the pipe is 1 (standard output). The output of prog2 is being piped to prog3, with the file descriptor for the input pipe being 0 and the file descriptor for the output pipe being 1. Finally, the output of prog3 is being redirected to file3.txt, with the file descriptor for the output file being 1. In summary, when answering questions on Brainly, it is important to be accurate, professional, and concise in your answers. This includes using the correct terminology and concepts related to the topic at hand, and avoiding irrelevant information or typos.
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3. PMMA and polycarbonate polymers are known to plastically deform following the Sternstein and Ongchin's hydrostatic-stress-dependent yield criterion. Given the following (proportional) loading modes, please discuss the polymer yielding mechanisms: (a). hydrostatic compression (b). pure shear
Answers
PMMA and polycarbonate polymers are known to plastically deform following the Sternstein and Ongchin's hydrostatic-stress-dependent yield criterion. The yielding mechanisms for the given (proportional) loading modes are discussed below:a) Hydrostatic compression mechanism:This loading mechanism applies equal force from all directions of the object.
Hydrostatic compression causes deformation in the material when the forces applied from all directions are equal or when the ratio of the stresses are identical. Here, the polymers will deform plastically following the Sternstein and Ongchin's hydrostatic-stress-dependent yield criterion.b) Pure shear mechanism:
Pure shear is a type of deformation in which the body experiences forces parallel to its surface but in opposing directions. When this is done, the object undergoes deformation that results in the shape of the object changing, while the volume remains constant. In this case, the mechanism of yielding for the polymer would be related to the deformation and the applied force, which causes the molecular orientation of the polymer to be distorted and induces shearing of the material.The mechanisms of yielding for PMMA and polycarbonate polymers under hydrostatic compression and pure shear loading modes are discussed above in long answer format.
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what is the division of demand
Answers
When thrust faults occur, the region undergoing stress is subject to: Group of answer choices compression tension shearing No answer text provided.
Answers
When thrust faults occur, the region undergoing stress is subject to compression stress.
What is compression stress?Compressive stress is a force that causes a substance to deform in order to take up less space.
When thrust faults occur, the region undergoing stress is subject to compression stress. A substance is said to be under compression when it is subjected to compressive stress.
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A rigid tank contains air at a pressure of 90 psia and a temperature of 60 °F. By how much will the pressure increase as the temperature is increased to 110°F?
Answers
Answer:
165 psi
Explanation:
First, you can find the ratio between 90:60 equal to 3:2. With this information, you can figure out what number to multiply the ratio by to achieve 110 degrees by doing 110/2. After multiplying both sides by 55, You will get 165:110.
165 psia will the pressure increase as the temperature is increased to 110°F.
What is meant by air tank?An example of an air tank is a diving cylinder that scuba divers use to store air and other breathing gases under high pressure. Paintball guns, brake systems, and other equipment are powered by compressed air stored in pneumatic pressure vessels.
An air tank is the component of an air suspension system that stores and keeps the compressed air used to raise your car. The air compressor or air compressors pump air into the air tank, where it is stored until you inflate.
An example of a pressure vessel is an air receiver tank, which receives air from the air compressor and stores it under pressure for later use. It is also referred to as an air compressor tank or a compressed air storage tank.
Thus, it is 165 psia.
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A safe breaker is attempting to crack a safe with a 7 combination code. So far they have worked out that
the first digit is double the third
the code is a palindrome
the fourth number is seven
the third number is one less than the sixth number
the second number is three less than the fourth number
what is the safe combination?
Answers
Answer:
6 4 3 7 3 4 6
Explanation:
Let us denote the digits of the code using letters.For a 7-digit code this would be a b c d e f gHowever we are given that the code is a palindrome. So the last 3 digits must be the same as the first 3 digits reversed giving the code as:a b c d c b aWe are given that the 4th number (d) is 7. So this give the combination as
a b c 7 c b a
The second number(b) is three less than the fourth number
So b = 7 - 3 = 4. b is also the same s the sixth number so we get
a 4 c 7 c 4 a
The third number (c) is 1 less than the sixth number
c = 4 - 1 = 3
c is also the 5th number
So..
a 4 3 7 3 4 a
The first digit(a) is twice the third digit.. First digit same as last
6 4 3 7 3 4 6