Answer:
The difference of two squares is a method of factorising used when an algebraic expression includes two squared terms, one subtracted from the other: a 2 – b 2 When we are subtracting a squared term from another squared term we can use the difference of two squares method. Square numbers are sometimes called perfect squares.
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Step-by-step explanation:
Jimmy rolls a number cube multiple times and records the data in the table above. At the end of the experiment, he counts that he has rolled 185 fours. Find the experimental probability of not rolling a four, based on Jimmy’s experiment. Round the answer to the nearest thousandth.
In this case, the experimental probability is D. 0.860
Why is this so?First, note that Experimental probability, also known as Empirical probability, is founded on real experiments and adequate documentation of events.
In the table we can see that he rolled the cube 1000 times, and he recorded that 140 of those times he rolled a 5.
Then, the probability of rolling a 5 will be equal to:
P1 = 140/1000 = 0.14
Now, the probabilty of NOT rolling a 5, is equal to the rest of the probabilities, this is:
P2 = 1 - 0.14 = 0.86
then the correct option is D
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Jimmy rolls a number cube multiple times and records the data in the table above. At the end of the experiment, he counts that he had rolled 140 fives. Find the experimental probability of not rolling a five, based in Jimmy’s experiment. Round the answer to the nearest thousandth.
A. 0.140
B. 0.167
C. 0.667
D. 0.860
Rewrite, using the distributive
property.
16b-8b = ([?]-8)b = [?]b
Answer:
8b
Step-by-step explanation:
You can factor the b-term out since b-term exists for all terms in the expression. By factoring out, you are basically dividing the factored term off and put it outside of the bracket, thus:
\(\displaystyle{16b-8b=\left(16-8\right)b}\)
Then evaluate and simplify:
\(\displaystyle{\left(16-8\right)b=8\cdot b}\\\\\displaystyle{=8b}\)
Arrange the equations in increasing order of the value of their solutions.
1/4x + 5/2x - 2 = 4 - 1/4x
7.9x + x + 4 = 1.1x - 16
3.2x + 5.7 = -2.5x
10.1x - 1.6x + 44 = -7
Answer:
The answer is below
Step-by-step explanation:
a)
1/4x + 5/2x - 2 = 4 - 1/4x
collecting like terms:
(1/4)x + (5/2)x + (1/4)x = 4 + 2
3x = 6
x = 6/3
x = 2
b)
7.9x + x + 4 = -1.1x - 16
collecting like terms:
7.9x + x + 1.1x = - 16 - 4
10x = -20
x = -2
c)
3.2x + 5.7 = -2.5x
collecting like terms:
3.2x + 2.5x = 5.7
5.7x = 5.7
x = 1
d)
10.1x - 1.6x + 44 = -7
collecting like terms:
10.1x - 1.6x = -7 - 44
8.5x = -51
x = -6
Hence the equations in increasing order of the value of their solutions is:
10.1x - 1.6x + 44 = -7
7.9x + x + 4 = -1.1x - 16
3.2x + 5.7 = -2.5x
1/4x + 5/2x - 2 = 4 - 1/4x
The average salary in this city is $46,800. Is the average less for single people? 46 randomly selected single people who were surveyed had an average salary of $43,254 and a standard deviation of $13,020. What can be concluded at the α = 0.05 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: H 0 : ? Select an answer H 1 : ? Select an answer The test statistic ? = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? α Based on this, we should Select an answer the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean is not significantly less than 46,800 at α = 0.05, so there is statistically insignificant evidence to conclude that the population mean salary for singles is less than 46,800. The data suggest that the populaton mean is significantly less than 46,800 at α = 0.05, so there is statistically
significant evidence to conclude that the population mean salary for singles is less than 46,800. The data suggest that the sample mean is not significantly less than 46,800 at α = 0.05, so there is statistically insignificant evidence to conclude that the sample mean salary for singles is less than 43,254. Interpret the p-value in the context of the study There is a 3.56556842% chance of a Type I error. There is a 3.56556842% chance that the population mean salary for singles is less than $46,800. If the population mean salary for singles is $46,800 and if another 46 singles are surveyed then there would be a 3.56556842% chance that the sample mean for these 46 singles surveyed would be less than $43,254. If the population mean salary for singles is $46,800 and if another 46 singles are surveyed then there would be a 3.56556842% chance that the population mean salary for singles would be less than $46,800. Interpret the level of significance in the context of the study. There is a 5% chance that the population mean salary for singles is less than $46,800. There is a 5% chance that you won the lottery, so you may not have to even have to worry about passing this class. If the population population mean salary for singles is less than $46,800 and if another 46 singles are surveyed then there would be a 5% chance that we would end up falsely concluding that the population mean salary for singles is equal to $46,800. If the population mean salary for singles is $46,800 and if another 46 singles are surveyed then there would be a 5% chance that we would end up falsely concluding that the population mean salary for singles is less than $46,800.
The null and alternative hypotheses for this study are:
H0: The population mean salary for singles is equal to or greater than $46,800.
H1: The population mean salary for singles is less than $46,800.
The test statistic, t, can be calculated using the formula:
\(t = (sample mean - hypothesized mean) / (sample standard deviation / \sqrt{(sample size)} )\)
In this case, the sample mean is $43,254, the hypothesized mean is $46,800, the sample standard deviation is $13,020, and the sample size is 46. Plugging in these values, we can calculate the test statistic.
The p-value can be determined by comparing the test statistic to the critical value from the t-distribution table. At α = 0.05 level of significance, the critical value corresponds to a 95% confidence level. If the p-value is less than 0.05, we reject the null hypothesis.
Interpreting the p-value in the context of the study, a p-value of 0.0357 indicates that there is a 3.57% chance of obtaining a sample mean as extreme as $43,254, assuming that the population mean salary for singles is $46,800.
Based on the α = 0.05 level of significance, the p-value is less than 0.05. Therefore, we reject the null hypothesis. The data suggest that the population mean salary for singles is significantly less than $46,800.
In hypothesis testing, the null hypothesis represents the status quo or the belief that there is no significant difference or effect. The alternative hypothesis, on the other hand, proposes a specific difference or effect. In this study, the null hypothesis states that the population mean salary for singles is equal to or greater than $46,800, while the alternative hypothesis suggests that it is less than $46,800.
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When multiplying or dividing integers, if the signs are the same, you keep the sign for the answer
False
True
Answer:
False
Step-by-step explanation:
If you were to divide a negative number by a negative number, or multiply a negative number by a negative number, you would change the sign to positive as two negatives make a positive.
Answer:
False
Step-by-step explanation:
if you multiply two negative integers, you will get a positive result
For example
(-1) x (-2) = 2 (the sign of the answer is different from the sign of the two negative integers that we multiplied)
A sequence is defined by the explicit formula an=3n+4. Which recursive formula represents the same sequence of numbers?
The recursive formula that represents the same sequence of numbers as the explicit formula an = 3n + 4 is an = an-1 + 3, with the initial term a1 = 7.
A recursive formula defines a sequence by expressing each term in terms of previous terms. In this case, the explicit formula an = 3n + 4 gives us a direct expression for each term in the sequence.
To find the corresponding recursive formula, we need to express each term in terms of the previous term(s). In this sequence, each term is obtained by adding 3 to the previous term. Therefore, the recursive formula is an = an-1 + 3.
To complete the recursive formula, we also need to specify the initial term, a1. We can find the value of a1 by substituting n = 1 into the explicit formula:
a1 = 3(1) + 4 = 7
Hence, the complete recursive formula for the sequence is an = an-1 + 3, with the initial term a1 = 7. This recursive formula will generate the same sequence of numbers as the given explicit formula.
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Please help with 9-12
Answer:
9. Cylinder
10. 14 in
11. 20π in³
12. circle, ellipse, rectangle, truncated ellipse
Step-by-step explanation:
You want the solid obtained by revolving a rectangle around one edge, the perimeter of the rectangle, the volume of the solid, and the names of at least 2 cross sections of the solid.
9. Solid of revolutionEvery point on the outside edge of the solid will be 2 inches from the center axis. That is, the cross section perpendicular to the axis of revolution will be a circle. The solid is a cylinder.
10. PerimeterThe perimeter of a rectangle is given by the formula ...
P = 2(L +W)
P = 2(2 in + 5 in) = 2(7 in) = 14 in
The perimeter is 14 inches.
11. VolumeThe radius of the cylinder is 2 inches, and its height is 5 inches. The volume is given by ...
V = πr²h
V = π(2 in)²(5 in) = 20π in³
The volume is 20π cubic inches, about 62.8 cubic inches.
12. Cross sectionsThe four attachments show possible cross sections of the cylinder. They include a circle, ellipse, rectangle, and truncated ellipse. The truncated ellipse may be cut off on one or both ends.
Find the moment of inertia about the x-axis of a thin plate with density bounded by the circle . then use your result to find =5
The lamina's moment of inertia about the origin is given by, \(I_0=640 \pi\).
What is a moment of inertia?The tendency of a body to withstand an object's angular acceleration is known as its moment of inertia. Inertia can be calculated by multiplying the mass by the orthogonal distance.Given:
Density - \(\delta=d(x, y)=5\)Circle - \(x^2+y^2=16\)Find the moment of inertia \(I_y\) and \(I_0\).
The lamina's moment of inertia about the x-axis is:
\(I_x=\iint_D y^2 d(x, y) d A\)In the above equation, substitute the given value:
\(I_x=\iint_D 5 y^2 d A\)Make use of polar coordinates:
\(\begin{aligned}x &=r \cos \theta \\y &=r \sin \theta \\d A &=d x d y=r d r d \theta \\D &=\{(r, \theta) \mid 0 \leq r \leq 4,0 \leq \theta \leq 2 \pi\}\end{aligned}\)
As we all know, the general equation of a circle is:
\(x^2+y^2=r^2\)The given circle equation is:
\(x^2+y^2=4^2\)As a result, r ranges from 0 to 4.
And ranges from 0 to 2\(\pi\).
As a result, the integral is shown below; simply enter all of the values and then integrate.
\(\begin{aligned}&I_x=\iint_D 5 y^2 d A \\&I_x=\int_0^{2 \pi} \int_0^4 5(r \sin \theta)^2 r d r d \theta \\&I_x=\int_0^{2 \pi} \int_0^4 5 r^3 \sin ^2 \theta d r d \theta \\&I_x=5 \int_0^{2 \pi}\left(\frac{r^4}{4}\right)_0^4 \sin ^2 \theta d \theta \\&I_x=320 \int_0^{2 \pi} \sin ^2 \theta d \theta \\&I_x=320 \int_0^{2 \pi}\left(\frac{1-\cos 2 \theta}{2}\right) d \theta \\&I_x=320\left(\theta-\frac{\sin 2 \theta}{2}\right)_0^{2 \pi} \\&I_x=320\left(\frac{2 \pi}{2}\right) \\&I_x=320 \pi\end{aligned}\)
Now, calculate \(I_y\) and \(I_0\).
Make use of polar coordinates.
\(\begin{aligned}&x=r \cos \theta \\&y=r \sin \theta \\&d A=d x d y=r d r d \theta \\&D=\{(r, \theta) \mid 0 \leq r \leq 4,0 \leq \theta \leq 2 \pi\}\end{aligned}\)
As we all know, the general equation of a circle is:
\(x^2+y^2=r^2\)The given circle equation is:
\(x^2+y^2=4^2\)As a result, r ranges from 0 to 4.
And ranges from 0 to 2\(\pi\).
As a result, the integral is shown below; simply enter all of the values and then integrate.
\(\begin{aligned}&I_y=\iint_D 5 x^2 d A \\&I_y=\int_0^{2 \pi} \int_0^4 5(r \cos \theta)^2 r d r d \theta \\&I_y=\int_0^{2 \pi} \int_0^4 5 r^3 \cos ^2 \theta d r d \theta \\&I_y=5 \int_0^{2 \pi}\left(\frac{r^4}{4}\right)_0^4 \cos ^2 \theta d \theta \\&I_y=320 \int_0^{2 \pi} \cos ^2 \theta d \theta \\&I_y=320 \int_0^{2 \pi}\left(\frac{1-\cos 2 \theta}{2}\right) d \theta \\&I_y=320\left(\theta-\frac{\sin 2 \theta}{2}\right)_0^{2 \pi} \\&I_y=320\left(\frac{2 \pi}{2}\right) \\&I_y=320 \pi\end{aligned}\)
The lamina's moment of inertia about the origin is given by:
\(\begin{aligned}&I_0=\iint_D\left(x^2+y^2\right) d(x, y) d A \\&I_0=\iint_D 5 r^2 r d r d \theta \\&I_0=5 \int_0^{2 \pi} \int_0^4\left(\frac{r^4}{4}\right)_0^4 d \theta \\&I_0=320 \int_0^{2 \pi} d \theta \\&I_0=320(\theta)_0^{2 \pi} \\&I_0=640 \pi\end{aligned}\)
So, the moment of inertia is \(I_x=320 \pi\).
The worth of, \(I_y=320 \pi\).
Therefore, the lamina's moment of inertia about the origin is given by, \(I_0=640 \pi\).
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The correct question is given below:
Find the moment of inertia about the x-axis of a thin plate with density δ=5 bounded by the circle x2+y2=16. Then use your result to find Iy and Io.
All items are being sold at a 35% discount. If the original price of the item is x dollars, which TWO of the following expressions can be used to determine the sale price?
0. 35x
0. 35x
0. 65x
0. 65x
x + 0. 35x
x + 0. 35x
x - 0. 35x
x - 0. 35x
x - 0. 65x
x - 0. 65x
The two expressions used to determine the sale price of the product is 0.35x and x - 0.35x.
Explain the term discounted price?Discount pricing describes a number of business practices where the cost of a good or service is reduced to attract customers, get rid of extra stock, or increase sales. Discount pricing works best when customers feel like they're "getting a good deal" on the product.If the original price of the product is x dollars.
Discount = 35%.
Discount = 35/100 x = 0.35x.
Then,
Sales price = original price - discount
Sales price = x - 0.35x.
Thus, the two expressions used to determine the sale price of the product is 0.35x and x - 0.35x.
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convert 9/5 into a mixed number
Answer:
9/5 = 1(4/5)
Step-by-step explanation:
In the figure below, side AC of ABC lies on line l.
A. 25
B. 30
C. 22
D. 24
what are the greatest numbers : 4, -8, 4, 8, 7, -3, -9, 2, 6, 1, -5, 5, -2, 0.
Answer:
Step-by-step explanation:
I would say 8 is the greatest number
the order from least to greatest
-9,-8,-5,-3,-2,0,1,2,4,4,5,6,7,8
4.* 4. Students were asked how many hours a weeknight they spend on homework and exercise. The dot plots display the results. Which statement is not supported? Homework Exercise LG 2 3 4 5 Number of Hours 1 2 3 4 5 Number of Hours A. More time is spent on homework than exercise. B. The mode activity times are equal. C. The median exercise time is not equal to the median homework time. D. The range of homework hours is greater for homework than for exercise ОА
Analyze each statement to see if it is supported by the dot plots or not.
A) More time is spent on homework than exercise.
Find the total time spent on each activity to compare
Which statements are true about squares? Select all that apply.
Answer: B, C, D
Step-by-step explanation:
Are correct:
B) Diagonals are perpendicular
C) Consecutive Angles are Supplementary
D) Diagonals bisect angles
Not correct:
A) Diagnols are congruent to sides is not correct the because diagonals of a square are congruent to each other, not to the sides
what is the answer to this?!
2/3x−1/5x=x−1
Answer: x = 15/8
Explanation: I used a calculator on a website.
Answer:
15/8
Step-by-step explanation:
Hope this helps: )
the coordinates of three points in the plane are given below. What is the point of the line through B and C?
A. y = -x + 2
B. y = -2x + 1
C. y = x + 2
D. y = x + 2
Step-by-step explanation:
y= x +2
.is the equation of line pass through B, C
The histogram shows the time it takes a class of 22 third-graders to finish their multiplication drills. Time to Complete Drills Number of Students 2 10 5 Time, minutes
Micah's boxplot is incorrect because the statistical summary given by his boxplot is inaccurate.
The boxplot is a better at analysing the data as it gives more statistical output of the data than the histogram.
We need to write out the number of times taken by each student,
From the histogram; the data values are :
1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 5, 5, 7, 7, 8, 8, 9, 9, 10, 10, 10
Using a boxplot maker or excel, we could create a boxplot of the data and compare with that given in the question.
5 number summary of Micah's boxplot :
Minimum = 1 (position of lower whisker)
Maximum = 9 (Position of upper whisker)
Lower quartile = 3(starting point of box)
Upper quartile = 8 (endpoint of box)
Median = 5 (vertical line in between box)
Outlier = 10
5 number summary of correct or accurate boxplot :
Minimum = 1 (position of lower whisker)
Maximum = 10 (Position of upper whisker)
Lower quartile = 2 (starting point of box)
Upper quartile = 8.2 (endpoint of box)
Median = 4.5 (vertical line in between box)
Outlier = None
Comparing the box plots, it can be concluded that Micah did not create the boxplot correctly.
Charge Q
1. =6.0nC is at (0.30 m,0), charge Q
2 =−1.0nC is at (0,0.10 m), and charge Q
3 =5.0nC is at (0,0). What is the magnitude of the net electrostatic force on the 5.0−nC charge due to the other charges? (k=8.99×10^9 N⋅m^2C ^2 )
The magnitude of the net electrostatic force on the 5.0−nC charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0), charge Q2 = −1.0 nC is at (0, 0.10 m), and charge Q3 = 5.0 nC is at (0, 0) is 6.21 N.
The value of the net electrostatic force on the 5.0-nC
charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0),
charge Q2 = −1.0 nC is at (0, 0.10 m), and
charge Q3 = 5.0 nC is at (0, 0) can be calculated as follows:
Given data,Charge Q1 = 6.0 nC is at (0.30 m, 0),
Charge Q2 = -1.0 nC is at (0, 0.10 m),
Charge Q3 = 5.0 nC is at (0, 0)
The formula to find out the force on the third charge Q3 is:
F = k * |Q1 * Q3| / r1^2 + k * |Q2 * Q3| / r2^2
Here, k = 8.99 × 10^9 N·m^2/C^2, Q1 = 6.0 nC, Q2 = -1.0 nC, Q3 = 5.0 nC
For the third charge Q3, the distance from Q1 is:
r1 = √(0.3^2 + 0^2) = 0.3 m
And the distance from Q2 is: r2 = √(0^2 + 0.1^2) = 0.1 m
Substituting all the given values in the formula:
F = 8.99 × 10^9 * [ (6.0 × 10^-9 * 5.0 × 10^-9) / 0.3^2 ] + 8.99 × 10^9 * [ (-1.0 × 10^-9 * 5.0 × 10^-9) / 0.1^2 ]F = 6.21 N
Therefore, the magnitude of the net electrostatic force on the 5.0−nC charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0), charge Q2 = −1.0 nC is at (0, 0.10 m), and charge Q3 = 5.0 nC is at (0, 0) is 6.21 N.
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_____ Is a function that calls itself. Each time it calls itself, a separate copy is created that has its own values for its parameters and variables. Base cases stop infinite recursion.
Recursion is a function that calls itself and creates separate copies with their own parameters and variables. Base cases are essential to prevent infinite recursion.
The term you are referring to is "recursion". Recursion is a powerful programming technique that involves a function calling itself in order to solve a problem. Each time the function is called, a new copy of the function is created, with its own set of parameters and variables. Recursion can be used to solve a wide range of problems, from simple mathematical calculations to complex algorithms.
One important aspect of recursion is the need for base cases. These are the conditions that stop the recursion from continuing indefinitely.
Without base cases, the function would continue to call itself forever, resulting in an infinite loop. Base cases are usually simple conditions that can be easily checked, such as the value of a variable reaching a certain threshold.
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how much work was done to move the car from 0.3 m to
0.7 m?
Use the power property to rewrite log3x9. 3 log subscript 9 baseline x 9 log subscript 3 baseline x 3 log x 2 + log subscript 3 baseline x.
By using the power property, the resultant answer when we rewrite log3x9 is (B) 9log3x.
What is power property?Multiply the exponents to determine the power of the power.
This is a development of the powers property.
Consider raising a number to a power and repeatedly multiplying the entire phrase by itself.
According to the power of a powerful formula, you can multiply two exponents together if one is increased to a power.
How many times to multiply two numbers together is indicated by an exponent.
For instance, 42 instructs you to multiply by 4 and 4. Alternatively, multiply four by two.
So, we have: log3x9
We have the following for logarithm properties:
loga (x ^ b) = b * loga (x)
As a result of this property, in this instance, we have:
log3 (x ^ 9) = 9log3 (x)
Therefore, by using the power property, the resultant answer when we rewrite log3x9 is (B) 9log3x.
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Correct question:
Use the power property to rewrite log3x9.
A) 3log9x
B) 9log3x
C) 3logx
D) 2 + log3x
How could you estimate the quotient 162 / 19
Answer:
To estimate the quotient, you can use compatible numbers like 160 and 20.
Step-by-step explanation:
Answer:
You could estimate the quotient by rounding 162 to the nearest multiple of 10, which is 160, and 19 to the nearest multiple of 10, which is 20. Then you can calculate the quotient of 160 / 20, which is 8.
eric is studying people's typing habits. he surveyed 515 people and asked whether they leave one space or two spaces after a period when typing. of those surveyed, 429 responded that they leave one space. create a 90% confidence interval for the proportion of people who leave one space after a period. use a ti-83, ti-83 plus, or ti-84 calculator, rounding your answers to three decimal places.
We can say with 90% confidence that the proportion of people who leave one space after a period when typing is between 0.800 and 0.866.
To create a confidence interval for the proportion of people who leave one space after a period, we can use the following formula:
\(CI = \hat{p} \pm z*\sqrt{( \hat{p}(1- \hat{p})/n) }\)
where:
\(\hat{p}\) is the sample proportion (i.e., the proportion of people in the sample who leave one space after a period)
n is the sample size (i.e., the number of people surveyed)
z is the z-score corresponding to the desired confidence level (i.e., 90% confidence level)
First, we need to calculate \(\hat{p}\) :
\(\hat{p}\) = 429/515
\(\hat{p}\) = 0.833
Next, we need to calculate the z-score corresponding to the 90% confidence level. We can use a table or a calculator to find this value.
For a 90% confidence level, the z-score is approximately 1.645.
Now, we can plug in the values we have into the formula and solve for the confidence interval:
CI = 0.833 ± 1.645*√(0.833(1-0.833)/515)
CI = 0.833 ± 0.033
CI = (0.800, 0.866),
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What is the solution of this equation?
-1y = -4
Answer:
y = 4
Step-by-step explanation:
-1y = -4
Divide both sides by -1 to get y by itself.
-1/-1 = -4/-1
y = 4
It's positive because there are two negatives, which mean they cancel out.
If students get their assignments done on time there is an 80% chance of earning a good grade in the class. If the assignments are finished during class or late then there is only a 30% chance of earning a good grade in the class. If the assignments are not done at all then there is only a 5% chance of earning a good grade in the class. In a certain class, 50% of the students have the assignments completed on time, 40% finish during class, and 10% do not do their assignments. If a student from this class is selected at random, what is the probability that student has a good grade?
Answer:
Probability that student has a good grade = 0.525
Step-by-step explanation:
Given
Chances of earning a good grade when assignments are done on time = 0.80
Chances of earning a good grade when assignments are finished during class or late = 0.30
Chances of earning a good grade when assignments are not done at all = 0.05
% of students who completed assignment on time = 0.50
% of students who completed assignment during class = 0.40
% of students who did not completed assignment at all = 0.10
Probability that student has a good grade
= (0.80 *0.50) + (0.30*0.40) + (0.05*0.10)
= 0.525
Please help if you would like to have brianleist! (No links please!) Thank you! :)
11. Which solution for the value of x in the figure below is incorrect? Explain a. 3X -44=x-24 2x - 44 = -24 2x = 20 (3x-440) b. 3x - 44 + x - 24 = 180 4x - 68 = 180 4x = 248 X = 10 (x-249) x = 62
Answer:
Theradius is 16 + 9 = 5. The equation of thecircle is2 2( x− 4) + ( y− 3) = 25. 53.54.x2 + y2 – 4 x ...
A linear model for the situation below passes through the origin. A manufacturer can produce 4,200 gears in 8 hours. How many gears can be made in 1 hour? values of the following algebraic expressions : L 3c2; 72/3; 5a&; ... 2x^-x^-3x-^ by 2 x'^ - 3 x~^ - x-^ ; a" - 1 + ft- " by a^ + ft~i ...
Step-by-step explanation:
A less character after a greater in10 = X. creases its value, as XI X+I, ... the root of each and set one above the other; as, % is the square root of 3X.180 / 90 / 15 lm | 12 VDC | 3 W module | 16 Wh battery | white | ... 48 VDC | PV 23,6 kW | 4 x VE SmartSolar MPPT 25 / 100-TR | 3x VE .
What is an example of slope-intercept form?.
Answer:
y = 3x + 1
Step-by-step explanation:
The equation for slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
What is the values of the 7s in 7,276 .
Answer: the first 7 is in the thousands place the second seven is in the tens place.
Step-by-step explanation:
pls answer this question brainliest will be given
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