what is the effect of divorce on females?​

Answer:

Explanation:

vo= 0

a=5.5m/s^2

v= 28 m/s

t=?

v=vo+at

at=v-vo

t=(v-vo)/a

t=28/5.5

t=5.09 seconds

The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.

The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.

Calculation:-

A. angular velocity ω = v/r

                                     = 30 /8

                                      = 3.75 m/s

B. Centripetal force = mv²/r

                             = 2×30²/8

                              = 225 N

There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.

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Answer: A flower pot falling

Explanation:

The car on the curve (its direction is changing) and the falling flower pot (its speed is changing) are both undergoing acceleration.

On one cookie containing 50 calories, you could potentially go approximately 298 meters

Given that one food calorie is equivalent to 4184 joules, we can calculate the total energy in joules contained in the 50 calorie cookie:

50 food calories * 4184 J/calorie = 209,200 joules

Assuming an average efficiency of around 25% (meaning 25% of the energy is effectively used for movement), and a body weight of 70 kilograms, we can use a rough estimation that it takes about 1 joule of energy to move 0.4 meters (based on the energy cost of walking).

Distance = (Energy obtained from the cookie * Efficiency) / (Energy cost per meter * Body weight)

Distance = (209,200 J * 0.25) / (1 J/m * 0.4 m/kg * 70 kg)

Distance ≈ 298 meters

Therefore, on one cookie containing 50 calories, you could potentially go approximately 298 meters

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Answer:

Explanation:

The needle is showing north south direction . when current starts flowing in the wire which is held vertical to the ground , it deflects towards east .

a )

Therefore a magnetic field towards east has been created . It is possible only if current flows towards the surface in the vertical wire .

b )

magnetic field created at the magnetic needle B = 10⁻⁷ x  2I / d where I is current and d is distance .

B = 10⁻⁷ x  2 x 26.3  / .27

= 194.81 x 10⁻⁷ T

angle of deflection of solenoid = 22.9°

Tan 22.9 = B /H

.422 = 194.81 x 10⁻⁷ / H

H = 461.63 x 10⁻⁷ T

= .46 x 10⁻⁴ T .

A) The current in the wire flows towards the Earth's surface

B) The magnitude of the horizontal component of the Earth's magnetic field is :   0.46 x 10⁻⁴ T

A) The compass needle held horizontally points in a North-south direction of the earth and also deflects eastwards when current is allowed to flow through it. The deflection of the needle indicates the presence/generation of a magnetic field on the earth surface. which is facilitated by the flow of the current in the wire towards the Earth's surface

B) Determine The magnitude of the horizontal component of the Earth's magnetic field

B ( magnetic field ) = 10⁻⁷ * 2I / d ---- ( 1 )

where : l = 26.3 A,   d = 0.27 m

Back to equation ( 1 )

B = 10⁻⁷ * 2 * 26.3 / 0.27

  = 194.81 * 10⁻⁷ T

Final step : Calculate the magnitude of horizontal component  ( H )

Tan ∅ = B / H ---- ( 2 )

where : ∅ ( angle of deflection ) = 22.9°

∴ H = B / Tan ( 22.9° )

      = (  194.81 * 10⁻⁷ ) / 0.422

      = 0.46 x 10⁻⁴ T

Hence we can conclude that The current in the wire flows towards the Earth's surface and  The magnitude of the horizontal component of the Earth's magnetic field is :   0.46 x 10⁻⁴ T

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Answer:

Am doing well am fine thank you

The magnitude of the net force causing the block’s acceleration is 8N.

We know that,

                         \(F_{x} = mg* cos\alpha\) (force along x - axis) and

                         \(F_{y} = mg* sin\alpha\) (force along y - axis)

The magnitude of net force is given by :

                         \(F_{net} = \sqrt{F_{x} ^{2} + F_{y} ^{2} }\)

                         \(F_{net} = \sqrt{(mg*cos\alpha )^{2} + (mg*sin\alpha )^{2} } \\F_{net} = \sqrt{(mg)^{2}[ (cos\alpha) ^{2}+(sin\alpha) ^{2} ] } \\F_{net} = mg\)

Given, weight = 8N and angle \(\alpha =\) 15°

We know that F (force) = ma = mg = weight

Putting these values in above equation we get ,

                          \(F_{net} = 8N\)

So the magnitude of the net force causing the block’s acceleration is 8N.  

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Answer:

The energy of the system and total momentum are both conserved in an elastic head-on collision. The atomic nucleus receives 1.87 percent of the neutron's kinetic energy and final kinetic energy is 12.3×10-13J.

Explanation:

In elastic head-on collision, the energy of the system and total momentum is conserved.

For the neutron,

m - mass, - initial velocity,  - final velocity

For the atom,

M- mass , - initial velocity, - final velocity

Conserved momentum on the head-on collision

mv_i=mv_f+MV_f

v_i-v_f=MmV_f

v_i-v_f=14.9V_f.........(I)

The kinetic energy

v_i^2-v_f^2=14.9V_f^2............(II)

From equation (I) and (II)

(v_i-v_f)/(v_i^2-v_f^2 )=(12v_f^2)/(12v_f^2 )

v_i+v_f=V_f.........(III)

Solve equation (I) and (III) for  

v_i=7.9v_f

Now, the fraction of the neutron's kinetic energy transferred to the atomic nucleus,

(1/2 MV_f^2)/(1/2 mv_i^2 )=14.9/7.95=1.87

K2=1.87×6.58×10-13J=12.3×10-13J

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L1/k1A + L2/k2A is the total thermal resistance between the surfaces at temperatures T0 and TL.

A measurement of the temperature differential at which a material or item resists the transfer of heat is known as thermal resistance. Thermal resistance is the inverse of thermal conductivity. Since the bulk of electrical components generate heat and need cooling, thermal resistance of materials is of special interest to electronic engineers. Electronic components might malfunction or fail due to overheating, hence special care must regularly be taken while designing those components.

Engineering regularly uses another important concept. Since there is a resemblance between the dispersion of heat and electrical charge, engineers typically use the thermal resistance (i.e., thermal resistance vs heat conduction) to compute heat transport through materials. Thermal resistance is the reverse of thermal conductivity.

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The complete question is,

A composite wall is shown with surface temperatures T0 and TL. Layer L1 has conductivity K1, thickness L1 and layer 2 has conductivity k2, thickness L2. The cross-sectional area of both layers is A. The total thermal resistance between the surfaces at temperatures T0 and TL is.

Answer:524 Hz

Explanation:

Approximate frequency, heard in other car, when two car approaches each other, before they cross each other is 524 Hz.

Frequency of wave is the number of waves, which is passed thorough a particular point at a unit time.

For the two cars approaching each other the Doppler formula to find the frequency of second car is given as,

\(f_2=\dfrac{V_s+V_2}{V_s-V_1}f_1\)

Here, \(V_s\) is the speed of the sound.

Two cars approach each other from opposite directions.The velocity of car one is 54 km/h and the velocity of the car two is also 54 km/h.

Convert the unit of velocity of the car as,

\(\rm 54km/s=54\times\dfrac{5}{18}m/s\\\rm 54km/s=15m/s\)

As we know that the speed of the sound is 340 m/s and one of the cars emits a note of frequency 480 Hz.

Thus, putting the values in the above formula to find out the frequency heard in the other car before they cross each other as,

\(f_2=\dfrac{340+15}{340-15}480\\f_2=524.3\rm Hz\)

The approximate frequency heard in the other car before they cross each other is 524 Hz.

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Answer:

8m/s²

Explanation:

a = change in v/t

a = (65-25)/5

a = 8

Answer:

To find the work done, we need to calculate the force applied to the block and the distance it moves.

The force applied to the block can be resolved into two components: one parallel to the floor and one perpendicular to the floor. The parallel component of the force is responsible for pushing the block forward, while the perpendicular component does not contribute to the work done.

The parallel component of the force is:

F_parallel = F * cos(30°) = F * √3/2

where F is the magnitude of the force applied.

The force of friction opposing the motion is:

F_friction = μ * F_norm

where μ is the coefficient of friction and F_norm is the normal force acting on the block, which is equal to the weight of the block since it is on a level floor:

F_norm = m * g = 25 kg * 9.81 m/s^2 = 245.25 N

where g is the acceleration due to gravity.

So the force of friction is:

F_friction = 0.4 * 245.25 N = 98.1 N

Since the block is moving at constant speed, the force applied must be equal and opposite to the force of friction:

F_parallel = F_friction

F * √3/2 = 98.1 N

F = 56.6 N

The work done by the force applied is:

W = F_parallel * d = 56.6 N * 5 m = 283 J

Therefore, the work done by the force applied is 283 J

Given data:

* The acceleration of gravity on other planet is,

where g' is the acceleration of gravity of the other planet , and g is the acceleration due to gravity of Earth,

* The weight of the gold medal on the other planet is,

Solution:

The weight of the gold medal on the other planet in terms of its mass is,

As the mass of gold medal remain unchanged,

Thus, the weight of the gold medal on Earth is,

Thus,

Substituting the known values,

Thus, the weight of the gold medal on the Earth is 0.5 N.

Answer: They are only taken when a player from the other team does something wrong. And they are only worth 1 point

Explanation:

Answer: You don't jump on your free throws, since they are not a jumpshot or layup and since u were fouled, they're only worth 1pt each.

Explanation:

Answer:

The four primary types of encoding are visual, acoustic, elaborative, and semantic. Encoding of memories in the brain can be optimized in a variety of ways, including mnemonics, chunking, and state-dependent learning.

Explanation:

Answer:

604m

Explanation:

30 * 20=600

600 + 4 = 604m

(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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Answer:

the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

Explanation:

The change in the momentum of a body, if the mass of the body is constant, is given by the following formula:

\(\Delta p=\Delta (mv)\\\\\Delta p=m\Delta v\)

p: momentum

m: mass

\(\Delta v\):  change in the velocity

The sign of the change in the velocity determines the direction of rate of change. Then you have:

\(\Delta v=v_2-v_1\)

v2: final velocity = 35m/s

v1: initial velocity = 40m/s

\(\Delta v =35m/s-40m/s=-5m/s\)

Hence, the direction of rate of change of the momentum is against the motion of the body, that is, downward.

The applied force is also against the direction of motion of the body, downward.

As the tension in the rope is constant therefore the boat engine will also be pushing the boat with the same force as that of the drag force that is given to be 450 Newton.

Drag force is similar to friction force but is experienced by a moving body in a fluid. Direction of drag force is a positive to the direction of motion.

Centripetal force is not a new force in nature but a manifestation of some force that causes rotation of a body.

Given:

Mass of the boat = 531 kg

Tension in the cable = 12900 Newton

Drag force experienced by the boat = 450 N

The boat along with the man is rotating using a cable which experiences a constant tension of 12900 Newton.

The boat's engine should also be generating a force perpendicular to the circular path travelled by the boat.

Now the tension in the string is constant this implies that all the force that the both engine is generating is being used in balancing the drag force exerted by water on the boat.

Therefore, the force produced by the engine will be equal to 450 Newton which will be used to balance the drag force.

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Answer:

If a zero is found between important digits, it is important. Zeros are also used as (not salient) holders to the left of digits if the number is in fact a decimal. Example from www.rpi.edu: , a mass of 42 g has two significant digits. Expressed in kilograms, the mass of 0.042kg should still have two significant digits.

Explanation:

Zeros are also used as (not salient) holders to the left of digits if the number is in fact a decimal. Example from www.rpi.edu: "A mass of 42 g has two significant digits. Expressed in kilograms, the mass of 0.042kg should still have two significant digits."

Hope this comes in handy, have a great day!

The aim of this study is to develop a Sun-Earth-Moon model that will serve to describe "the real and apparent movements of the Sun-Earth-Moon system and the results of these movements".

A fundamental topic in astronomy, that is difficult To properly understand the why requires three-dimensional thinking and imagination. In this context;

• Students have difficulty understanding basic concepts of astronomy; H.

such as creating seasons, phases of the moon, lunar and solar eclipses that require three-dimensional thinking must be properly understood. So to teach difficult abstract concepts,

• To solve the problem of the lack of materials and tools related to matter.

• To enhance learning retention by engaging students' multiple senses,

• Capturing concepts visually and verbally increases skills. Remember the image of this concept when you meet its verbal equivalent, or reversed. Therefore, to help students remember what they are learning,

• Have students see tools, objects, and events that they cannot see perceive with their five senses,

• Show students tools, objects, and events that they cannot reach

or bring to class,

• Attract attention and arouse interest in a topic, needed a model to grow.

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Answer:

b

Explanation:

the answer is b because if you do the math it equals to b

Answer:

Let's start by calculating how much of a head start Car A has in distance before Car B starts.

In 3 minutes, Car A will have travelled:

d = r * t = (60 km/h) * (3/60) h = 3 km

So when Car B starts, Car A is 3 km ahead.

Now let's consider the time it takes for both cars to meet. Let's call the time it takes for both cars to meet t.

During that time, Car A will travel at a speed of 60 km/h, and Car B will travel at a speed of 70 km/h.

The distance that Car A will travel during that time is:

dA = 60 km/h * t

The distance that Car B will travel during that time is:

dB = 70 km/h * t

The total distance between the two cars when they meet is:

d = dA + dB

We want to find the value of t that makes dA + dB = 3 km (the distance that Car A is ahead of Car B when Car B starts).

Substituting the expressions for dA and dB, we get:

60 km/h * t + 70 km/h * t = 3 km

Simplifying, we get:

130 km/h * t = 3 km

t = 3 km / 130 km/h

t = 0.0231 h

Now we can calculate the distance that both cars will have travelled when they meet:

dA = 60 km/h * 0.0231 h = 1.38 km

dB = 70 km/h * 0.0231 h = 1.61 km

d = dA + dB = 1.38 km + 1.61 km = 2.99 km

Therefore, the two cars will draw level after travelling approximately 2.99 km from the starting point.

The constant acceleration of the train is 50/9 m/s².

The two balls will collide at a height of approximately 10.204 meters above the ground.

Using the kinematic equations of motion, we have:

distance = initial velocity * time + 1/2 * acceleration * time^2

For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:

d1 = 0 + 1/2 * a * (300)^2

For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:

d2 = v * 300

For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:

d3 = v * 300 + 1/2 * (-a) * (300)^2

The total distance traveled is the sum of these three distances:

distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600

Since the total distance traveled is given as 10 km = 10000 m, we have:

v * 600 = 10000

Solving for v, we get:

v = 10000/600 = 50/3 m/s

Now we can use the second equation above to find a:

d2 = v * 300 = (50/3) * 300 = 5000 m

Therefore, the constant acceleration of the train is:

a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2

The constant acceleration of the train is 50/9 m/s^2.

Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.

Using the kinematic equation for free fall, we have:

h = 10 + 1/2 * g * t^2

where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.

The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.

Using the kinematic equation for motion with constant acceleration, we have:

0 = 10 + (-g) * t

Solving for t, we get:

t = 10/g = 10/9.81 seconds

Substituting this value of t into the first equation, we get:

h = 10 + 1/2 * 9.81 * (10/9.81)^2

Simplifying, we get:

h = 10.204 m

The two balls will collide at a height of approximately 10.204 meters above the ground.

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Answer:

Solids have a definite shape and volume. Liquids have a definite volume.Gases have no definite volume.

The rise in temperature of the body as determined from the specific heat capacity, mass, and heat change of the body is 12.24 °C.

The rise in temperature of the body is determined from the specific heat capacity, mass, and heat change of the body.

The formula relating the temperature rise of the body, the specific heat capacity, mass, and heat change of the body is given below:

Heat change = mass * specific heat capacity * temperature rise

Temperature rise = Heat change / mass * specific heat capacity

Temperature rise = 3.6 * 10⁶ J / 84 kg * 3,500 J/kg/°C

Temepartaure rise = 12.24 °C

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The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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The quarterback is getting hit with a force of 100 Newtons.

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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Answer:

Image result for total velocity definition

The average speed of an object is defined as the distance traveled divided by the time elapsed.

Explanation: