What is the equation of a line with a slope of -2 that passes through the point(6,8)

Answer:

60% of 500 is 300 and 40% of 500 is 200. 300-200=100

Step-by-step explanation:

Answer:

100 more students

Step-by-step explanation:

500*0.4 = 200

500*0.6 = 300

300-200 = 100

Answer:

t = 6.8 years

Step-by-step explanation:

The formula for compound interest is

\(A(t)=P(1+r/n)^n^t\), where P is the principal/amount invested, r is the interest rate, n is the number of compound periods per year (4 for quarterly), and t in the time in years.

We know that A = $5900, P = $4000, and r = 0.0575 (we must convert the percentage to a decimal).  We must solve for t and round to the nearest tenth:

\(5900=4000(1+0.0575/4)^(^4^t^)\\\\59/40=(1623/1600)^4^t\\\\log(59/40)=log(1623/1600^4^t)\\\\log(59/40)=4t*log(1623/1600)\\\\log(59/40)/log(1623/1600)=4t\\\\1/4(log(59/40)/log(1623/1600))=t\\\\6.80773607=t\\\\6.8=t\)

The number N whose forty percent is 240 is 600, or we say that 40% of 600 is 240

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is

\(\dfrac{a}{100} \times b\)

For this case, we are specified that:

40% of N = 240

Since 40% of N is \(\dfrac{N}{100} \times 40\), thus, we get

\(\dfrac{N}{100} \times 40 = 240\) (as they both are same quantity, ie. 40% of N)

Now, solving it further to get value of N:

\(\dfrac{N}{100} \times 40 = 240\\\\\text{Multiplying 100 on both the sides}\\\\N \times 40 = 24000\\\\\text{Dividing both the sides by 40}\\\\N = 24000/40 = 600\)

Thus,  40% of 600 is 240 or we say that the number N whose forty percent is 240 is 600

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Answer:

It's B

Step-by-step explanation:

The original equation is y - (y intercept)= slope(x-(x intercept))

Answer:from top to bottom it’s

-4,-x^2,x^2,4

Step-by-step explanation:

Hope this helps :)

Answer:

1 is correct answer or not please reply me

In summary, days of the month can be considered as an example of categorical data, specifically ordinal data, since they have a natural ordering but the differences between categories are not necessarily equal.

Categorical data is a type of data that represents characteristics or qualities of a group of individuals or objects. It is a type of data that is divided into categories or groups based on specific characteristics or attributes. Categorical data is sometimes also referred to as qualitative data. Categorical data can be further divided into two subtypes: nominal and ordinal data. Nominal data is characterized by categories that have no natural order or ranking, such as colors, names, or categories of a variable. For example, the color of a car (red, blue, green) is nominal data. Ordinal data, on the other hand, is characterized by categories that have a natural order or ranking, such as rankings, levels, or scores. For example, a student's grade level (freshman, sophomore, junior, senior) is ordinal data.

Here,

In the case of days of the month, each day can be classified into a specific category or group, which is the corresponding day number. For example, we can classify January 1st, 2023 as day 1, January 2nd, 2023 as day 2, and so on.

Categorical data is typically divided into two types: nominal and ordinal. Nominal data is characterized by categories that have no natural order or ranking, while ordinal data is characterized by categories that have a natural order or ranking.

Days of the month can be considered as ordinal data since they have a natural ordering from 1 to 31 (or 28/29/30 in the case of February). However, it is important to note that the difference between the days is not necessarily equal, meaning that the distance between, for example, day 1 and day 2 is not the same as the distance between day 15 and day 16.

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The function that correctly defines S(x) is S(x) = 5x - 2(20 - x) + 20

We have the following definitions in the question

If the total questions is 20, then

Incorrect answers = 20 - x

So, the points gained/lost are

Gained = 5 * x = 5x

Lost = -2 * (20 - x) = -2(20 - x)

Bonus = 20

Add the above points to get the function S(x)

S(x) = 5x - 2(20 - x) + 20

Hence, the definition is S(x) = 5x - 2(20 - x) + 20

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The following form has two parallel sides, and, in accordance with the provided assertion, its area is 21 cm².

Area is the entire amount of space occupied by a flattened (2-D) surface or form of an item. The area of a planar figure is the space that its perimeter encloses. The quantity of unit rectangles that completely encircle a closed figure's surface is its area. Square units such as cm² and m² are used to measure area.

The ratio will also be 1/2 * (bases 1 + base 2) * length since it is a trapezium.

So, 1/2 * ( 9+5) * 3

   = 1/2 * 14 * 3

   =  1/2 * 42

   =  21 cm²

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The minutes it would take to empty the tank is 8 minutes.

The first step is to determine the volume of the oil tank. A cylinder is a three-dimensional object. It is a prism with a circular base.

Volume of a cylinder = πr²h

Where:

Volume of a cylinder = 3.14 x 0.9² x 4.5 = 11.45 ft³

Now, to determine the time it would take to empty the tank, divide the volume of the oil tank by the rate at which the tank is being drained.

Minutes it would take to drain the tank = volume of the oil tank / rate at which the tank is drained

Minutes it would take to drain the tank = 11.45 ft³ / 1.5 = 8 minutes

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Answer:

3 batches of meatloaf requires 6 pounds of beef

and 3 cups of bread crumbs.

Step-by-step explanation:

For pounds of beef

1 batch meatloaf = 2 pounds of beef

3 batches of meatloaf = x

Cross Multiply

x = 3 x 2 pounds of beef

x = 6 pounds of beef

3 batches of meatloaf requires 6 pounds of beef

For bread crumbs

1 batch meatloaf = 1 cup of bread crumbs

3 batches of meatloaf = x

Cross Multiply

x = 3 × 1 cup of bread crumbs

x = 3 cups of bread crumbs

3 batches of meatloaf requires 3 cups of bread crumbs.

Therefore, 3 batches of meatloaf requires 6 pounds of beef and 3 cups of bread crumbs.

Answer: The answer is D

Step-by-step explanation:

I took the quiz

Answer: 6 x 3.14 = 18.84

Step-by-step explanation:

To find the circumference of a circle, you multiply the diameter by pi.

Answer:

  18.84 units

Step-by-step explanation:

You want to know the circumference of a circle with a diameter of 6 units.

The circumference C of a circle with diameter d is given by the formula ...

  C = πd

Using the given values of π and d, this becomes ...

  C = 3.14 × (6 units)

  C = 18.84 units

The circumference of the circle is 18.84 units.

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The value of p when q is 2 is 1

Inverse variation is the relationships between variables that are represented in the form of y = k/x, where x and y are two variables and k is the constant value.

This means that has x increases y will decrease and vice versa.

If p is inversely proportional to q , then p = kq

when p = 2, q = 4

2 = k4

k = 2/4

k = 1/2

When q = 2

p = 1/2 × 2

p = 1

Therefore the value of p is 1

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Answer:

the awnser is 28

Step-by-step explanation:

the little 2 mean you times the 3 by it so it's 1+6. which is 7 and 18+2 is 20 and 20+7 is 28

Based on the limited information provided, it is not possible to definitively determine the type of economy in Country A. More specific details and factors would be necessary to make a conclusive determination.

Using the scale factor the actual length is A. 67.5 feet

Scale factor is a number which we use to enlarge or reduce the dimensions of an object.

Since the scale of a model train is 1 inch to 13.5 feet. One of the cars of the model train is 5 inches long. To find the length, in feet, of the actual train car, we use scale factor

Scale factor = dimension on scale/actual dimension

Since scale factor is 1 inch to 13.5 feet, we have that

1inch/13.5 feet = dimension on scale/actual dimension

Let actual dimension = x.

Since dimension on scale = 5 inches,

Substituting these into the equation, we have that

1 inch/13.5 feet = 5 inches/x

Cross-multiplying, we have that

1 inch × x = 5 inches × 13.5 feet

x = 5 inches × 13.5 feet/1 inch

= 67.5 feet

So, the actual length is A. 67.5 feet

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The amount cheaper is the car washes Malcolm orders than the car washes Martha's order is $13.

The correct answer choice is option B.

Malcolm's gift card = $50.

Cost Malcolm's car wash per visit = $7

Martha's gift card = $180

Cost Martha's car wash per visit = Difference between gift card balance of first and second visit

= $180 - $160

= $20

How cheap is the car washes Malcolm orders than the car washes Martha's order = $20 - $7

= $13

Therefore, Malcolm's car wash is cheaper than Martha's car wash by $13

The complete question is attached in the diagram.

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Answer:

j = 139.99 + 139.99 * 0.08625

Answer:

Step-by-step explanation:

Answer:

\(\frac{p^2-25}{p^2-10p+25}\)

We can factorise the numerator with the difference of squares formula:\(x^2-y^2=(x+y)(x-y)\)

-----------------------------

\(\frac{p^2-5^2}{p^2-10p+25} =\frac{(p+5)(p-5)}{p^2-10p+25}\)

Now we can factorise the denominator:

\(\frac{(p+5)(p-5)}{p^2-10p+25} =\frac{(p+5)(p-5)}{(p-5)^2}\)

\(\frac{(p+5)(p-5)}{(p-5)^2} =\frac{(p+5)(p-5)}{(p-5)(p-5)}\)

Cancel out the common factor of (p-5):

\(\frac{(p+5)(p-5)}{(p-5)(p-5)} =\frac{(p+5)}{(p-5)}\)

The value of the equation that defines the function is f(x) = 3(5/3)ˣ

From the question, we have the following parameters that can be used in our computation:

(0, 3) and (1, 5)

An exponential function is represented s

y = abˣ

Where,

a = y when x = 0

So, we have

y = 3bˣ

Using the other point, we have

3b = 5

This gives

b = 5/3

So, we have

f(x) = 3(5/3)ˣ

Hence, the equation defining f is f(x) = 3(5/3)ˣ

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Answer:

y=6 , x=8

Step-by-step explanation:

3y - 2 = 4y - 8 (opposite sides of a parallelogram are equal)

-2 + 8=4y - 3y

6=y

2x -4 =x +4 (opposite sides of a parallelogram are equal)

2x -x=4+4

x=8

The simplified form of the expression is \(-32\).

To simplify the expression, we can perform the calculations written below step by step:

\(\(\frac{{-2(4+6)+(-2)6}}{{-2(4-1)}}\)\)

We follow the order of operations (PEMDAS/BODMAS):

Step 1: Simplify within parentheses:

\(\(4+6 = 10\)\).

Step 2: Perform multiplications and divisions from left to right:

\(\(-2(10) = -20\) and \(-2(4-1) = -2(3) = -6\)\).

Step 3: Evaluate the remaining additions and subtractions:

\(\(-20 + (-2) \cdot 6 = -20 - 12 = -32\)\).

Therefore, the simplified form of the expression \(\(\frac{{-2(4+6)+(-2)6}}{{-2(4-1)}}\) is \(-32\).\)

When simplifying an expression, several factors need consideration. First, apply the order of operations correctly, respecting parentheses and exponents. Next, combine like terms by adding or subtracting them. Distribute and simplify within parentheses or brackets as needed. Pay attention to negative signs and ensure their proper placement.

Finally, review the simplified expression to ensure accuracy and validity within the given context.

Note: The complete question is:

\(\(\frac{{-2(4+6)+(-2)6}}{{-2(4-1)}}\)\), calculate the simplified form of this expression.

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Step-by-step explanation:

\((2x - 6) \frac{3}{2} = 21 - 4x \\ \\ lcm = 2 \\ 2\times (2x - 6) \frac{3}{2} = (21 \times 2) -( 4x \times 2) \\ \\ 3(2x - 6) = 42 - 8x \\ 6x - 18 = 42 - 8x \\ 6x + 8x = 42 + 18 \\ 14x = 60 \\ x = \frac{30}{7} = 4.286(2.d.p)\)

The value of ∂x/∂s is  4s^2 * t^6.

To find ∂x/∂s, we need to differentiate x with respect to s while treating t as a constant. Let's begin by substituting the given expressions for x, y, and z into the function f(x, y, z):

f(x, y, z) = (x^2)(y^3) + z^3

Substituting x, y, and z:

f(s, t) = ((s^2)(t^3))^2 * (s*t)^3 + ((s^2)*t)^3

Expanding the expression:

f(s, t) = (s^4 * t^6) * (s^3 * t^3) + (s^6 * t^3)

Now, let's differentiate x with respect to s:

∂x/∂s = ∂/∂s [(s^2)(t^3)]^2

Using the chain rule, we can differentiate each term separately:

∂x/∂s = 2 * (s^2 * t^3)^1 * ∂/∂s [(s^2)(t^3)]

Differentiating (s^2)(t^3) with respect to s:

∂/∂s [(s^2)(t^3)] = 2s * t^3

Substituting back into the expression for ∂x/∂s:

∂x/∂s = 2 * (s^2 * t^3)^1 * 2s * t^3

Simplifying:

∂x/∂s = 4s^2 * t^6

Therefore, ∂x/∂s = 4s^2 * t^6.

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Answer: Option(C) is correct option

Explanation:

Margin of error is the factor that occurs in survey for determining random sampling error. It indicates about confidence interval (CI) through describing difference occurring in poll result and actual population value.If there is high margin of error, then confidence is low because poll result will not reflect the actual population result collected through survey.

According to the question, researcher would try to get small margin of error so that lower confidence interval can be acceptable because large confidence interval(CI) will indicate more margin of error.

Other options are incorrect because small margin of error cannot produce increment in confidence or usage of large confidence.Large confidence interval will result in large margin of error. Thus, the correct option is option(c).

The two angles that satisfy this equation are 60 degrees and 300 degrees

Trigonometry are expressed as a function of sine, cosine and tangent.

Given the trigonometry expression below;

8secx - 3tan^2(x) =7

Since tan^2x= sec^2x - 1

Substitute

8secx - 3(sec^2x-1) =7

Expand

8secx - 3sec^2x + 3 = 7

3sec^2x - 8secx +4 = 0

Let P = secx such that;

3P^2 - 8P - 4 = 0

Factorize

3P^2 - 6P -2 P + 4 = 0
3P(P - 2) - 2(P - 2) = 0

P - 2 = 0

P = 2

since secx = P, hence;

secx = 2
1/cosx = 2

cosx = 1/2

x = 60 degrees

Since cosine is positive in the fourth quadrant, hence;

x2 = 360 - 60

x2 = 300degrees

Hence the two angles that satisfy this equation are 60 degrees and 300 degrees

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Recall that

tan(x) = sin(x)/cos(x)

and

sin(x) = x - x ³/6 + x ⁵/120 - x ⁷/5040 + …

cos(x) = 1 - x ²/2 + x ⁴/24 - x ⁶/720 + …

Truncate the series to three terms. Then

\(\displaystyle \lim_{x\to0}\frac{\tan(x)-x}{x^3} = \lim_{x\to0}\frac{\frac{x-x^3/6+x^5/120}{1-x^2/2+x^4/24}-x}{x^3} \\\\ = \lim_{x\to0}\left(\frac{x-x^3/6+x^5/120}{x^3-x^5/2+x^7/24}-\frac1{x^2}\right) \\\\ = \lim_{x\to0}\left(\frac{1-x^2/6+x^4/120}{x^2-x^4/2+x^6/24}-\frac1{x^2}\right) \\\\ = \lim_{x\to0}\left(\frac{1-x^2/6+x^4/120}{x^2\left(1-x^2/2+x^4/24\right)}-\frac1{x^2}\right) \\\\ = \lim_{x\to0}\left(\frac{1-x^2/6+x^4/120}{x^2\left(1-x^2/2+x^4/24\right)}-\frac{1-x^2/2+x^4/24}{x^2\left(1-x^2/2+x^4/24\right)}\right) \\\\ = \lim_{x\to0}\frac{x^2/3-x^4/30}{x^2\left(1-x^2/2+x^4/24\right)} \\\\ = \lim_{x\to0}\frac{1/3-x^2/30}{1-x^2/2+x^4/24} = \boxed{\frac13}\)