What is the formula for lead(ii) phosphate?

Oxidation State

In chemistry, when naming ionic compounds there will sometimes be a roman numeral after the first element. This number represents the oxidation state of the element. An oxidation state is defined as the hypothetical charge of an atom, assuming that all of its bonds are fully ionic. In other words, the oxidation state shows how many electrons an atom gives or receives after ionization.

In ionic compounds, there will only ever be a roman numeral after the first element. This element will always be the cation (positively charged ion). So, the roman numeral will show how many electrons each cation gave.

When Roman Numerals are Necessary

This is necessary when you deal with transition metals or any other element that has multiple oxidation states. For example, iron can give 2 or 3 electrons. So, when naming a compound with iron you need to use a (II) or (III) to show how many electrons each iron atom gave.

When Roman Numerals are Unnecessary

On the other hand, roman numerals are unnecessary when using an element that only has one possible oxidation state. For example, Na can only give 1 electron ever, so it does not need a roman numeral. Additionally, elements in the second group like Mg can only ever give 2 electrons, so they also don't need a roman numeral to follow their name.

Answer:

definition of atom

Atoms are the basic units of matter and the defining structure of elements

Definition of compound

A compound is a material formed by chemically bonding two or more chemical elements.

Definition of Molecule

a group of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

Definition of mixture

a substance made by mixing other substances together.

Explanation:

examples of elements : carbon, oxygen, hydrogen, gold, silver and iron.

examples of compounds:  table salt or sodium chloride, a sample of copper, and water

examples of molecules: water, nitrogen, ozone, calcium oxide, glucose, and table salt.

examples of mixtures: sand and water, salt and water, sugar and salt, ethanol in water, air, salt and pepper,  Solutions, colloids, and, suspensions.

(I'm sorry I don't know what I need to do for the diagrams but I did everything else and it took me like 15 mins to do so I hope it helps)

Answer:

pp

pp

pp

cp Sana po makatulong ☺️

Answer:

Explanation:

basically pp has volume of pp because pp pp pp pp pp

The following units indicate these quantities:

1.  mL- Volume

2. cm^2- Area

3. mm^3- volume

4. mg/L- Concentration

5. ps- Time

6. nm- Length

7. K- Temprature

- mL: This unit indicates volume, specifically the volume of liquid or fluid in milliliters.

- cm^2: This unit indicates area, specifically the area of a two-dimensional object in square centimeters.

- mm^3: This unit indicates volume, specifically the volume of a three-dimensional object in cubic millimeters.

- mg/L: This unit indicates concentration, specifically the concentration of a substance in milligrams per liter of solution.

- ps: This unit indicates time, specifically time measured in picoseconds (one trillionth of a second).

- nm: This unit indicates length, specifically the length of an object in nanometers (one billionth of a meter).

- K: This unit indicates temperature, specifically temperature measured in kelvins, which is a unit of temperature that starts at absolute zero (the coldest possible temperature).

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Initially, retrosynthesis The target molecule is the ultimate outcome of this process, and the intermediates and raw materials utilised to create the product are determined by a stepwise breakdown.

The chemical route can also be established using a retrosynthetic investigation.

Second step: retrosynthesis of CH3,CH2;CH2;CHO

To create a pathway where starts off as a two-carbon compound.

Step 3: CH3,CH2,CH2;CHO synthesis

The entire synthetic pathway of manufacturing depends on the retrosynthetic analysis.

Hydrocarbons with the carbonyl substituents are known as aldehydes. A hydrogen atom is also present in the material to which the quintuple oxygen is bonded. Aldehydes' carbonyl atoms are thus present at the hydrocarbon's terminal elements.

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                                     "Complete question"

Deeply Devise a synthesis of CH3CH2CH2CHO from two-carbon starting materials. Be sure to answer all parts of the question Step 1: Intermediate 1?

Answer:

the answer is unsteady

Answer:

luminous flame appears unsteady

Answer:

The energy transferred is known as kinetic energy, and it depends on the mass and speed achieved.

This equation reveals that the kinetic energy of an object is directly proportional to the square of its speed.

KE = 0.5 • m • v2

where m = mass of object

v = speed of object

That means that for a twofold increase in speed, the kinetic energy will increase by a factor of four. For a threefold increase in speed, the kinetic energy will increase by a factor of nine.

2.20 g (to 3 sig. figs.) the maximum mass of water that could be produced by the chemical reaction. round your answer to significant digits.

hexane is C6H14 or put another way, as in the question CH3(CH2)4CH3. Actually, it is incorrect as depicted in the question.Nonetheless..

2C6H14 + 19O2 ===> 12CO2 + 14H2O ... balanced equation

moled hexane present = 2.6 g x 1 mole/130 g = 0.02 moles

moles O2 present = 5.29 g x 1 mole/32 g = 0.165 moles

Which reactant is limiting? Hexane = 0.02/2 = 0.01; O2 = 0.165/19 = 0.0087

Thus O2 is limiting...

moles of H2O that can be produced =0.165 moles O2 x 14 H2O/19 CO2 = 0.122 moles H2O

Mass of water( H2O) = 0.122 moles x 18 gm/mole = 2.20 g (to 3 sig. figs.)

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(i) The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1.\)

(ii) The half-life period of the reaction is 1386 seconds.

(iii) The time taken to complete 75% of the reaction is approximately 2772 seconds.

We can use the first-order rate equation:

Rate = k[N2O5]

Where:

Rate is the reaction rate,

k is the rate constant,

[N2O5] is the concentration of N2O5.

Given:

Rate constant (k) = \(5*10^{-4} sec^{-1}\)

Initial concentration of N2O5 =\(0.4 mol litre^{-1}\)

(i) To find the initial reaction rate:

Substitute the given values into the rate equation:

Rate = k[N2O5]

Rate = \((5*10^{-4} sec^{-1})(0.4 mol litre^{-1})\)

Rate = \(2*10^{-4} mol litre^{-1} sec^{-1}\)

The initial reaction rate is \(2*10^{-4} mol litre^{-1} sec^{-1}\).

(ii) To find the half-life period:

The half-life of a first-order reaction is given by the equation:

t(1/2) = (0.693 / k)

Substitute the given value of k into the equation:

t(1/2) = \((0.693 / 5*10^{-4} sec^{-1})\)

t(1/2) = 1386 sec

The half-life period of this reaction is 1386 seconds.

(iii) To find the time taken to complete 75% of the reaction:

The time required to complete a certain percentage of a reaction can be found using the equation:

t = (ln(1 / (1 - x)) / k)

Where x is the fraction of the reaction completed (in this case, 75%).

Substitute the given values into the equation:

t =\((ln(1 / (1 - 0.75)) / 5*10^{-4} sec^{-1})\)

t = 2772 sec

The time taken to complete 75% of the reaction is approximately 2772 seconds.

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As the molar mass calculated is 24.90 g/mol, hence the gas is most likely to be NO.

The ratio between mass and the amount of substance of any sample is called molar mass.

To determine whether the gas is NO, NO2, or N2O5, we need to calculate the molar mass of the gas and compare it to the molar masses of these three possible gases.

n = PV/RT

Given, P = 760.0 mmHg, V = 250.0 mL = 0.2500 L, T = 17.00°C + 273.15 = 290.15 K, and R = 0.08206 L atm/mol K.

So, n = (760.0 mmHg)(0.2500 L)/(0.08206 L atm/mol K)(290.15 K) = 0.01003 mol

M = m/n

Given m = 0.2500 g.

M = 0.2500 g/0.01003 mol = 24.90 g/mol

Comparing this molar mass to the molar masses of NO (30.01 g/mol), NO2 (46.01 g/mol), and N2O5 (108.01 g/mol), we see that the gas is most likely NO.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: A 250.0-mL flask contains 0.2500 g of a volatile oxide of nitrogen. The pressure in the flask is 760.0 mmHg at 17.00°C. Is the gas NO, NO2, or N2O5?

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles KMnO4, or 158.033949 grams.

Explanation:

I belive that is correct,hope it helps:)

The missing part of the equation is found to be 4/2He. Option A

The term nuclear equations have to do with the type of equation in which one type of nucleus is transformed into another sometimes by the bombardment or loss of a particle.

Now the full equation ought to be written as 7/3Li + 1/1H -----> 4/2He + 4/2He. This is because the total mass on the left is 8 and the total charge on the left is 4.

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Answer:

sorry i never learned this

Explanation:

Answer:

A and D

Explanation:

It might seem like B and D but I took the test and it's A and D.

The statistic that provides a better indication of the overall location (centre) of the distribution of CO2 emissions in 2020 is the total CO2 emissions by country.

To determine the overall location or center of the distribution of CO2 emissions, it is crucial to consider the total CO2 emissions by country rather than just the number of countries or their consumption of fossil fuels. The main reason for this is that most of the world's CO2 emissions come from a relatively small number of countries that have high levels of industrial activity and large populations.

When we examine the total CO2 emissions by country, we can identify the countries that contribute the most to global emissions. These countries typically have extensive industrial sectors, rely heavily on fossil fuels for energy production, and have large populations. By focusing on the total emissions, we can gain a more accurate understanding of the distribution of CO2 emissions worldwide.

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1) Among 0.10M hydrochloric acid or 0.10M acetic acid, the more acidic one is 0.10M hydrochloric acid;

2) For for 0.0010M hydrochloric acid or 0.010M acetic acid, the more acidic one is 0.010M acetic acid;

3) For 0.00010M hydrochloric acid or 0.0010M acetic acid,  it is 0.0010M acetic acid;

4) The percent ionization of  a) 0.10m hydrochloric acid is 100% b) 0.10m acetic acid is 1.8% c) 0.10m hydrochloric acid  is 100% d) 0.10m acetic acid  is 1.3% e)  0.10m hydrochloric acid  is 100% f) 0.10m acetic acid

is 1.3%.

As per the question, which is more acidic, 0.10M hydrochloric acid or 0.10M acetic acid, the answer is 0.10M hydrochloric acid. The higher the concentration of hydrogen ions (H+), the stronger the acid is. Hydrochloric acid ionizes completely in water and provides more H+ ions than acetic acid. However, acetic acid is a weak acid, and it only partially dissociates in water. Hence the concentration of H+ ions in acetic acid is less than the concentration of H+ ions in hydrochloric acid.

Similarly, for 0.0010M hydrochloric acid or 0.010M acetic acid, the answer is 0.010M acetic acid. Since this concentration is greater than 0.0010M hydrochloric acid, the concentration of H+ ions is more in acetic acid. Hence it is more acidic than hydrochloric acid.

For 0.00010M hydrochloric acid or 0.0010M acetic acid, the answer is 0.0010M acetic acid. For this, we again consider the concentration of H+ ions. The concentration of H+ ions in acetic acid is more than that in hydrochloric acid. Hence it is more acidic than hydrochloric acid.

Now let's calculate the percent ionization for each of the above solutions.

a) 0.10M hydrochloric acid:

Hydrochloric acid ionizes completely in water. Hence, the percent ionization is 100%.

b) 0.10M acetic acid:

The ionization constant for acetic acid \(CH_{3}COOH\)  is Ka = 1.8 × \(10^{-5}\)

\(CH_{3}COOH\) ⇌ \(CH_{3}COO^{-}\) + \(H^{+}\)

0.10                                        0.10-x                                      x

Initial concentration of \(CH_{3}COOH\) is 0.10M and the equilibrium concentration would be 0.10 - x and x for  \(CH_{3}COO^{-}\) and \(H^{+}\) respectively. Since the concentration of x is less than 5% of the initial concentration of acetic acid, we can assume that it is negligible. Hence, the percent ionization is (x/0.10) × 100% = 1.8%.

c) 0.0010M hydrochloric acid:

Hydrochloric acid ionizes completely in water. Hence, the percent ionization is 100%.

d) 0.010M acetic acid:

The ionization constant for acetic acid \(CH_{3}COOH\) is Ka = 1.8 × \(10^{-5}\)

\(CH_{3}COOH\) ⇌ \(CH_{3}COO^{-}\) + \(H^{+}\)

0.010                                        0.010-x                                      x

Initial concentration of \(CH_{3}COOH\) is 0.010 and the equilibrium concentration is 0.010 - x and x for \(CH_{3}COO^{-}\) and \(H^{+}\) respectively. Since the concentration of x is less than 5% of the initial concentration of acetic acid, we can assume that it is negligible. Hence, the percent ionization is (x/0.010) × 100% = 1.3%.

e) 0.00010M hydrochloric acid:

Hydrochloric acid ionizes completely in water. Hence, the percent ionization is 100%.

f) 0.0010M acetic acid:

The ionization constant for acetic acid\(CH_{3}COOH\) is Ka = 1.8 × \(10^{-5}\)

\(CH_{3}COOH\) ⇌ \(CH_{3}COO^{-}\) + \(H^{+}\)

0.0010                                        0.0010-x                                      x

Initial concentration of \(CH_{3}COOH\) is 0.0010 and the equilibrium concentration 0.0010 - x and x for \(CH_{3}COO^{-}\) and \(H^{+}\) respectively. Since the concentration of x is less than 5% of the initial concentration of acetic acid, we can assume that it is negligible. Hence, the percent ionization is (x/0.0010) × 100% = 1.3%.

Hence, the percent ionization of each solution is:a) 100%b) 1.8%c) 100%d) 1.3%e) 100%f) 1.3%.

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Answer:

The empirical formula is Ag2O.

The empirical formula is Ag2O.Explanation:

The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.

The empirical formula is Ag2O.Explanation:The empirical formula is the simplest whole-number ratio of atoms in a compound.The ratio of atoms is the same as the ratio of moles. So our job is to calculate the molar ratio of Ag to 2O.

do the steps ...

To get this into an integer ratio, we divide both numbers by the smaller value.

From this point on, I like to summarize the calculations in a table.

ElementAgMass/gXMolesXllRatiomllIntegers

—————————————————−———mAgXXXm7.96Xm0.07377Xll2.00mmm2

mlOXXXXl0.59mm0.0369Xml1mmmml1

There are 2 mol of Ag for 1 mol of O.

Answer:

Hello There!!

Explanation:

The answer is↬The empirical formula is Ag2O. It is the simplest whole-number ratio of atoms in a compound.

hope this helps,have a great day!!

~Pinky~

Answer:

B = A/DH – C

Explanation:

From the question given above, we obtained:

A = D • H(B + C)

Thus, we can obtain B in terms of D, H, A and C by doing the following:

A = D • H(B + C)

A = DH(B + C)

Divide both side by DH

A/DH = B + C

Subtract C from both side

A/DH – C = B + C – C

A/DH – C = B

B = A/DH – C

1) The reaction is exothermic and heat is a product

2) The color would turn to pink.

Let us recall that an endothermic reaction is one in which the increase in the temperature of the system would drive the forward reaction. This implies that the equilibrium would shift to the right when the set up is heated. Since the color of the solution changes to blue when heated hence the reaction is exothermic.

If you removed heat by placing the solution in the ice bath, we can see that we have removed the heat thus we expect that the reverse reaction would take place and the color would change to pink.

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Answer:

6.14x10^24

Explanation:

convert the given 47.0g to mols then to molecules.

\(\frac{47.0g}{} x\frac{1mol}{46.07g}x\frac{6.022x10^{23} }{1 mol}\)

46.07 is the molar mass of ethanol

6.022x10^23 is avogadros number

Answer:

If a liquid is heated the particles are given more energy and move faster and faster expanding the liquid.

The distance between the particles increases tremendously the attraction doesn't change.

Whilst water is boiled, the heat energy is transferred to the molecules of water, which begin to pass extra quickly. ultimately, the molecules have an excessive amount of power to stay connected as a liquid. while this takes place, they shape gaseous molecules of water vapor, which go with the flow to the floor as bubbles and tour into the air.

On heating, their kinetic electricity pushes neighboring atoms or molecules other than each different. This pushing of atoms or molecules outcomes in a slightly accelerated distance among molecules and the volume of stable additionally increases.

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In semiconductors, Boron acts as a donor, i.e. electrons are introduced into the conduction band when added as impurities to silicon. Option C is the correct answer.

When boron impurities are added to silicon, it acts as a donor, which means that it introduces electrons into the conduction band of silicon. This results in an excess of electrons, which increases the conductivity of the material.

This process is called doping and is used in the semiconductor industry to create p-type semiconductors. The addition of boron impurities creates a p-type semiconductor because the extra electrons in the conduction band create "holes" in the valence band. These holes behave like positive charges and are free to move throughout the material.

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Answer:

b. 6.02 x 1023 molecules

Explanation:

The formula mass of ammonia is 14 + 1 × 3 = 17.

The number of moles in 27.6g ammonia is 27.6 ÷ 17 = 1.62 mol.

A mole is 6.02 × 10²³, so the number of hydrogen atoms in a 1.62 moles of ammonia is 1.62 × 6.02 × 10²³ × 3 = 2.93 × 10² atoms.

Answer:

Answer is flagella

Explanation:

I hope it's helpful!

The mass percent composition of nitrogen in acetaminophen is 9.26 %.

The mass percent composition of an element is the percentage of the ratio of the molar mass of that element to the molar mass of the entire compound. Acetaminophen represented as C8H9NO2 is a drug that is used as a pain reliever.

First, we will calculate the molar mass of this compound. For this, we should know the mass of each element present in the compound.

mass of C = 12, mass of H = 1, mas of N = 14, mass of  O = 16.

Now, we will calculate the molar mass of acetaminophen

= 12*8+ 1*9+14*1+16*2

=  151 g

Now, we have to calculate the mass percent composition of Nitrogen.

The molar mass of nitrogen = 14g

The molar mass of the entire compound =  151 grams.

Mass percent composition of N =  (mm of N ÷ mm of C8H9NO2) ×100

=  (14/151) × 100 =  0.0926 × 100

= 9.26 %

Therefore, the mass percent composition of nitrogen in acetaminophen (C8H9N02) is 9.26%.

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Answer: CH4

Explanation: Methane