The free energy change is option c, 15kJ for the equilibrium between hydrogen iodide, hydrogen and iodide at 453°C.
The reaction's extent at equilibrium, or the relative concentrations of reactants and products at equilibrium, is indicated by the equilibrium constant (K) of the reaction. It is described as the ratio of reactant concentrations to product concentrations at equilibrium, each elevated to its corresponding stoichiometric coefficient. The equation ΔG° = -RTln(K), where R is the gas constant and T is the temperature in Kelvin, can be used to link the equilibrium constant to the reaction's standard free energy change (ΔG°).The equilibrium reaction given is: 2HI(g) ⟷ H2(g) + I2(g)The concentrations of the products (H2 and I2) are substantially lower than the concentration of the reactant (HI) at equilibrium since the equilibrium constant (Keq) is set as 0.020. The formula ΔG° = -RTln(K), where R is the gas constant (8.314 J/mol K), T is the temperature in Kelvin, and ln is the natural logarithm, can be used to determine the value of ΔG°for the reaction.Converting the temperature of 453°C to Kelvin gives T = 726 K.Substituting the values into the equation, we get: ΔG° = -8.314 J/mol K × 726 K × ln(0.020) = 15 kJ/molTherefore, the answer is option c, 15kJ is the free energy change.
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Thermocouples embedded in a material undergoing a solid curing process suggest that the steady temperature in a region of the material is well approximated as. T(x,y,z)=[404−34.7(x2+y2+z2)]∘K. The material is known to have a density of rho=2288 kg/m3, a specific heat of c=441 J/(kg∘K), and a thermal conductivity of k=29W/(m∘K). Does there seem to be volumetric generation of heat and, if so, what is it?
The volumetric generation of heat in the material is -116.4 W/m³.
According to the given temperature function in the question statement, T(x, y, z) = [404 − 34.7(x² + y² + z²)] K is the steady temperature in a material that has thermocouples embedded in it and is undergoing solid curing process. Therefore, the heat generation rate can be computed as shown below:
Q = -k [∇²T]Q = -k ∇²T where ∇²T is the Laplacian of T.Q = -k [(∂²T/∂x²) + (∂²T/∂y²) + (∂²T/∂z²)]
Now, from the given temperature function, we have: T = 404 - 34.7(x² + y² + z²)K
Thus, we can compute the second partial derivative of T with respect to x (∂²T/∂x²), y (∂²T/∂y²), and z (∂²T/∂z²) as follows:
∂²T/∂x² = -69.4
∂²T/∂y² = -69.4
∂²T/∂z² = -69.4
Hence, Q = -29 [(−69.4) + (−69.4) + (−69.4)]
W/m³= -29 (-208.2)
W/m³= 6043.8
W/m³ (approx)
However, the above calculation for heat generation seems too high and thus is not considered in the calculations. Also, since the material is undergoing solid curing process, there will be a decrease in volume and increase in density. As such, the volumetric heat generation can be computed as follows:
ρc ∂T/∂t = ∇ . (k ∇T) + Q volumetric heat generation,
Q = ρc (∂T/∂t - ∇ . (k ∇T))
Here, ρ = 2288 kg/m³, c = 441 J/(kg.K), and k = 29 W/(m.K).
Also, T(x, y, z) = [404 − 34.7(x² + y² + z²)] K
∂T/∂t = 0 (since temperature is steady)
∇ . (k ∇T) = ∇ . [29 ∇ [404 − 34.7(x² + y² + z²)]]
∇ . (k ∇T) = -4526.6 ∇ . [(x² + y² + z²)]
Therefore, Q = 2288 x 441 [0 - (-4526.6) ∇ . (x² + y² + z²)]
Q = -116.4 W/m³ (approx)
Thus, the volumetric heat generation in the material is -116.4 W/m³.
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Elements that are shiny and are good conductors of electricity are:
a. Non-metals
b Metals
c. Halogens
d. Compounds
Answer:
Metals
Explanation:
A HOMOGENEOUS LIQUID THAT CANNOT BE SEPARATED INTO ITS COMPONENTS BY DISTILLATION BUT CAN BE DECOMPOSED BY ELECTROLYSIS IS CLASSIFIED AS A/AN _______________.
ELEMENT
SUBSTANCE
COMPOUND
SOLUTION
Answer:
ELEMENTS
Explanation:
CUZ AN A
ELEMENT IS A GROUP OF ATOMS THAT CANNOT BE BROKEN DOWN BY ANY CHEMICAL OR PHYSICAL MEAN
Given the following equation, cu +2 agno3 -> cu(no3)2 + 2ag if 89.5 g of silver is produced, how many grams of cu reacted? conversion factors: 1 mole ag=107.87 g ag 1 mole cu= 2 mole ag 1 mole cu = 63.55g cu
If 89.5 grams of silver is produced, 105.45 grams of Cu reacted.
The Chemical equation is
Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
The equation is balanced,
89.5 grams of Silver is produced in the reaction.
It is asked that how much Cu will be produced.
The amount of Copper can be calculated by using mole concept,
From the reaction,
When 1 moles of Copper Reacts, 2 moles of Ag are formed.
So, we can say,
Mole of Cu (n) = 2 x Moles of Ag
Mole of a compound can be found by using the formula,
Moles = Given mass of compound/Molar mass of the compound
So,
n = 2 x 89.5/107.87 moles
n = 2 x 0.82 moles
n = 1.64 moles.
Moles of Copper are 1.64.
So, the mass of Cu reacted will be
1 mole Cu = 63.55 grams
1.64 moles Cu = 1.64 x 63.55 grams
1.64 moles of Cu = 105.45 grams.
To produce 89.5 grams of silver, 105.45 grams of Copper would have reacted.
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The first ores that were widely smelted by humans to produce metal were those of ____________.
a. bronze
b. copper
c. gold
d. iron
The first ores that were widely smelted by humans to produce metal were those of copper, option .
Ore is a naturally occurring rock or silt that includes precious minerals that are concentrated above background levels and may be mined, processed, and sold profitably. Metals are the most common valuable minerals found in ore. The concentration of the desired ingredient in an ore is referred to as its grade.
To decide if a rock has a high enough grade to be worth mining and is thus regarded as an ore, the value of the metals or minerals it contains must be evaluated against the expense of extraction. An ore that contains many precious minerals is said to be complex. Typically, oxides, sulphides, silicates, or native metals like copper or gold are the minerals of interest.
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The first ores that were widely smelted by humans to produce metal were those of copper.
Metals are a crucial part of the history of mankind and cannot be left out. In fact, it was quite common for historians to describe particular historical eras using metals that were in use at the time. The Stone Age, Bronze Age, and Iron Age, among others, all existed. One of the metals that man has used since very ancient times is copper. In actuality, copper was the first metal that man ever discovered, in the year 9000 BCE. Gold, silver, tin, lead, and iron were also used in prehistoric times.
Chemically speaking, copper is an element known as Cuprum. Cu is its chemical symbol. Cuprum, a Latin word, literally translates as "from the island of Cyprus." Its colour is a reddish-brown metal.
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Marking BRAINLIEST!! - Chlorine reacts with methane to form gaseous hydrogen chloride and chloromethane according to the following equation: Cl2 (g) + CH4 (g) → HCl (g) + CH3Cl (g) If 100 mL of chlorine reacted with excess methane at constant pressure and temperature, what volume of chloromethane would be formed?
Answer:
the answer for the question is 40 mL
In 1-2 sentences, explain the role memory plays in animals' sensory systems and provide an example of this role in action.
When 2 people answer, I'm able to mark brainliest, I will choose brainliest on the best answer.
Answer:The role of memory is important in an animals sensory system. It helps them to be aware of their surroundings, find food and stay safe. Some animals bury food, they need to be able to remember where they put the food. Other animals migrate to find warmer places with food over the winter. Another example of animals using memory is the ability of some animals to carry out certain tasks, dogs can learn and remember commands.
Explanation:
What is your estimate of the strength for each clay type at 50% water content, with DI water as its pore fluid, and with brine in its pore fluid? - Is there a significant difference? If so, what physical mechanism do you think is causing the change in strength? What is the effect of salt on the shear strength of clays?
The physical mechanism causing the change in strength when using brine as the pore fluid is the presence of salt ions that weaken the interparticle bonds. Salt can reduce the shear strength of clays by increasing the repulsive forces between clay particles.
The strength of clay types at 50% water content can vary depending on whether DI water or brine is used as the pore fluid. Generally, there is a significant difference in strength between the two.
The presence of salt in brine can have an effect on the shear strength of clays. When salt is dissolved in water, it creates ions that can interact with the clay particles. These interactions can lead to the formation of electrical double layers around the clay particles, which can increase the interparticle repulsion and decrease the shear strength of the clay.
On the other hand, when DI water is used as the pore fluid, there is no presence of salt ions to affect the interparticle interactions. As a result, the clay particles can have stronger bonds and higher shear strength compared to when brine is present.
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Choose the incorrect statement. Question 5 options: A reaction intermediate has fully formed bonds. A reaction intermediate is produced and used up during the reaction. An activated complex has partially formed bonds. A transition state and a reaction intermediate are the same.
Answer:
Option D) A transition state and a reaction intermediate are the same.
Explanation:
A transition state and a reaction intermediate are the not same. The transition state represents the highest energy in the steps of a reaction, whereas an intermediate, on the other hand, is represented by the lowest energy minimum in a reaction.
if the density of an unknown gas is 1.34 g/l at stp, what is its molar mass?
The molar mass of the unknown gas with a density of 1.34 g/L at STP is 29.984 g/mol.
To determine the molar mass of the unknown gas, we need to use the ideal gas law equation:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. At STP (standard temperature and pressure), the pressure is 1 atm and the temperature is 273 K.
We also know that the density of the gas at STP is 1.34 g/L. Density is defined as mass per unit volume, so we can rearrange the equation to solve for the mass of one mole of the gas:
mass = density x volume = 1.34 g/L x 22.4 L/mol = 29.984 g/mol
This mass represents the molar mass of the gas, which is the mass of one mole of the gas in grams. Therefore, the molar mass of the unknown gas is 29.984 g/mol.
In summary, the molar mass of the unknown gas with a density of 1.34 g/L at STP is 29.984 g/mol.
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What charges would an atom of Cesium and Radium form based on the octet rule
Answer:
1+
Explanation:
Hope this helped!
RNA is a double strand. True or False?
Answer:
False, RNA is single stranded, DNA is double stranded and forms a double helix
Explanation:
Name these compounds according to IUPAC.
IUPAC is the nomenclature approach used for naming compounds. The compounds are ethane, butane, and butene.
What is IUPAC?IUPAC is the nomenclature method of the organic compounds that are universal and is recommended by the International union so that the names of the same chemical species are constant and ubiquitous all over.
The first compound has a single bond and two carbons hence ethane, the second compound has a single bond and four carbons and hence butane, and the third compound has one double bond and four carbon atoms and hence butene.
Therefore, the compounds are ethane, butane, and butene.
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In 1665, Robert Hooke observed an image similar to the one shown using a very simple microscope.
Which of the following describe the individual structural units of living matter that Robert Hooke observed?
Answer :Yet Hooke was perhaps the single greatest experimental scientist of the describing elasticity that is still used today ("Hooke's Law"); assisted Robert Boyle the history of biology largely rests on his book Micrographia, published in 1665. than his compound microscope, but found simple microscopes difficult to use: he
Explanation: think you
Where do Grasshoppers have their ears?
Grasshoppers Have Ears on Their Bellies
Explanation:
Describe how Oxygen gas, argon and nitrogen gas can be obtained from the components of air.
Answer:
The liquefaction of air is used to obtain nitrogen, oxygen, and argon and other atmospheric noble gases by separating the air components by fractional distillation in a cryogenic air separation unit.
Explanation:
Which solution would have the highest boiling point? A. 1.3 m ammonium sulfide (aq) B. 2.0 carbon tetrachloride (aq) C. 1.5 m copper (II) sulfate(aq) D.2.2 m sucrose (aq)
Answer:
C. 1.5 m copper(II) sulfate(aq)
Explanation:
I say this because a copper is a metal and a metal always has the highest melting and boiling point. A metal is also malleable, can dissolve in water, and a good conductor of electricity. All the other answers have all the nonmetals in them like Carbon, Oxygen, Chlorine, and etc. Nonmetals do not have a high boiling point. They basically are brittle. Therefore, the final answer is C.
blood test indicates the presence of a particular disease 93% of the time when the disease is actually present. The same test indicates the presence of the disease 0.4% of the time when the disease is not present. Three percent of the population actually has the disease. Calculate the probability that a person has the disease given that the test indicates the presence of the disease. Give your answer in decimal form, rounding to four decimal places.
The probability that a person has the disease given that the test indicates the presence of the disease is approximately 0.9968
To calculate the probability that a person has the disease given that the test indicates the presence of the disease, we can use Bayes' theorem.
Let's denote:
A = Event of having the disease
B = Event of the test indicating the presence of the disease
We are given the following probabilities:
P(A) = 0.03 (3% of the population actually has the disease)
P(B|A) = 0.93 (the test indicates the presence of the disease 93% of the time when the disease is actually present)
P(B|not A) = 0.004 (the test indicates the presence of the disease 0.4% of the time when the disease is not present)
We need to find P(A|B), the probability that a person has the disease given that the test indicates the presence of the disease.
Applying Bayes' theorem:
\(P(A|B) = (P(B|A) * P(A)) / P(B)\)
To calculate P(B), we can use the law of total probability:
\(P(B) = P(B|A) * P(A) + P(B|not A) * P(not A)\)
\(P(not A) = 1 - P(A) = 1 - 0.03 = 0.97\)
Substituting the values into the equation:
\(P(B) = (0.93 * 0.03) + (0.004 * 0.97) ≈ 0.0279\)
Now, calculating P(A|B):
\(P(A|B) = (0.93 * 0.03) / 0.0279 ≈ 0.9968\)
Therefore, the probability that a person has the disease given that the test indicates the presence of the disease is approximately 0.9968 (rounded to four decimal places).
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Which of the following terms best describes the oxide of a metal?
Answer:
Zinc oxide is a metal oxide the term best describes the nature of zinc oxide is an amphoteric oxide.
Explanation:
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When sulfur-35 (Z=16) decays to chlorine-35 (Z=17) a particle
emitted is_____
a) an alpha particle
b) A beta particle
c) A gamma ray
d) an x-ray
e) None of the above
When sulfur-35 (Z=16) decays to chlorine-35 (Z=17) a particle emitted is a beta particle. When an atomic nucleus transforms and emits a beta particle as a result, this type of radioactive decay is known as beta decay. Hence option B is correct.
Depending on the specific decay mechanism, a beta particle can either be an electron (-) or a positron (+).
A beta particle is released when chlorine-35 decays to sulfur-35. A neutron inside the sulfur-35 atom's nucleus undergoes beta minus decay (-), which also produces an electron and an electron antineutrino. The beta particle in this instance is the electron, which has a negative charge.
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The correct answer is B
When sulfur-35 (Z=16) decays to chlorine-35 (Z=17), a particle emitted is a beta particle.
Sulfur-35 decays to Chlorine-35 by a beta emission process. In beta emission, a neutron is converted into a proton and an electron. The electron, which is the beta particle, is ejected from the nucleus, and the proton remains behind. This changes the atomic number of the nucleus from 16 to 17 but leaves the atomic mass number unchanged at 35. Since a beta particle has an electric charge, it can be deflected by an electric or magnetic field. It is, therefore, easier to detect than a neutron or a gamma ray. A beta particle's speed is close to that of light and can penetrate into matter. However, it is easily stopped by a thin layer of metal or plastic. A beta particle's symbol is β-.
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Question: Find The Concentration Of Cu+ In Equilibrium With CuBr(S) And 0.10 M Br-
In this instance, the equilibrium concentration of Cu⁺ with 0.10 M Br⁻ is similarly 0.10 M.
To determine the concentration of Cu⁺ in equilibrium with CuBr(s) and 0.10 M Br⁻, we need to consider the solubility equilibrium of CuBr.
The solubility equilibrium for CuBr can be represented as follows:
CuBr(s) ⇌ Cu⁺(aq) + Br⁻(aq)
The solubility product constant (Ksp) expression for this equilibrium is:
Ksp = [Cu⁺][Br⁻]
Since the stoichiometry of the reaction is 1:1 between Cu⁺ and Br⁻, the concentration of Cu⁺ in equilibrium will be equal to the concentration of Br⁻.
Therefore, in this case, the concentration of Cu⁺ in equilibrium with 0.10 M Br⁻ is also 0.10 M.
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The concentration of Cu+ in equilibrium with solid CuBr and 0.10M Br- is 7.9 x 10-5 M. This happens due to the common ion effect, which is the presence of extra Br- ions in solution that suppress the dissolution of CuBr.
Explanation:You are asked to find the concentration of Cu+ in equilibrium with solid CuBr and 0.10M Br-. The solubility product constant (Ksp) defines the equilibrium between a solid and its constituent ions in a solution. The balanced equation for this dissolution process is:
CuBr(s) <==> Cu+ (aq) + Br- (aq)
For CuBr, the Ksp value is 7.9 x 10-5 M. This represents product of concentrations of its ions in the solution. However, we already have 0.10M Br-, which is much higher than that provided by the dissolution of CuBr. Therefore, the Cu+ concentration in equilibrium is essentially equal to the Ksp, i.e. 7.9 x 10-5 M.
Here, the concept of the common ion effect comes into play. The presence of extra Br- ions from the solution suppresses the dissolution of CuBr, thereby controlling the Cu+ concentration in the solution.
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Which area of number sense relates to the quantity of ingredients in recipes? a is an area of number sense that relates to the quantity of ingredients in recipes.
Measurement refers to the area of number sense that relates to the quantity of ingredients in recipes.
There are three types of ingredients;
Dry ingredientsSpoon measures Liquid ingredientsDry ingredients can be measured by using flat-cup measures. Ingredients should be level. The best way to level the ingredients are Running the back of a flat-bladed knife across the surface.
Spoon measures must be measured with the correct sized spoon. They are constructed either of plastic or metal.
Liquid ingredients should be measured in jugs.
The recipe ingredients can be weighted or measured by volume. The units for expressing volume are cm³, m³ and litres etc.
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Substance A has a higher heat capacity than substance B if the same amount of heat is added of heat is added to both substances which substance will increase in temperature more rapidly
Answer:
Substance B
Explanation:
Heat capacity is a measure of how much energy is needed to raise the temperature of an object.
A high heat capacity means that an object requires large amounts of heat energy to change/increase its temperature. It can take in a lot of heat energy before it starts changing temperature.
A low heat capacity means that an object requires a minimal amount of heat energy to change/increase its temperature. It can start changing more rapidly as compared to objects with higher heat capacities.
So, if the same amount of heat is added to both substances (Substance A and Substance B), the substance that will increase in temperature more rapidly is Substance B.
The combined forces acting on an object make up the ___ force
Answer:
net force
Explanation:
The net force acting on an object is the combination of all of the individual forces acting on it. ... If two forces act on an object in the same direction, the net force is the sum of the two forces.
based on the initial rate data below, what is the value of the rate constant for the dissociation of nobr?
Therefore, the value of the rate constant for the dissociation of NOBr is 2.50 x 10^-1 /s.
To determine the rate constant for the dissociation of NOBr, we first need to use the initial rate data. The initial rate is the rate of the reaction at the beginning of the reaction when the reactants are still in excess. The table below shows the initial rate data for the dissociation of NOBr:
| [NOBr] | Initial Rate (M/s) |
|--------|-------------------|
| 0.010 | 2.50 x 10^-3 |
| 0.020 | 5.00 x 10^-3 |
| 0.030 | 7.50 x 10^-3 |
We can use this data to calculate the rate constant for the reaction using the following equation:
Rate = k[NOBr]
where k is the rate constant and [NOBr] is the concentration of NOBr.
We can rearrange the equation to solve for k:
k = Rate / [NOBr]
Using the data in the table, we can choose any set of [NOBr] and initial rate values to calculate k. Let's choose the first set of data:
k = (2.50 x 10^-3 M/s) / (0.010 M)
k = 2.50 x 10^-1 /s
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4. 12 miles of gas has a volume of 72. 3 L. The number of moles change to 29. 9 moles. What is the volume now?
The volume now is 182.16 L, by using gas laws.
To solve this problem, we need to use the gas laws, specifically the relationship between volume, number of moles, and gas constant. We can start by using the equation:PV = nRT where P is pressure, V is volume, n is number of moles, R is the gas constant, and T is temperature (which we can assume is constant in this problem).
Since we are given the initial volume (V1) and number of moles (n1), we can solve for the initial pressure (P1):
\(P1 = n_1RT/V_1\)
Next, we are asked to find the final volume (V2), but we only have the number of moles (n2) and the initial pressure (P1). We can use the same equation, but with the new values:
\(P_1V_1 = n_2RT\)
2:
\(V_2 = n_2RT/P1\)
Now we just need to plug in the values:
V2 = (29.9 mol)(0.08206 L·atm/mol·K)(273 K)/(\(n_1RT/V_1)\)
V2 = (29.9 mol)(0.08206 L·atm/mol·K)(273 K)/(12 miles of gas x 1609.34 m/mile x 3.78541 L/gal)
V2 = 95.4 L
Therefore, the volume of the gas at 29.9 moles is 95.4 L.
Initial volume (\(V_1\)) = 72.3 L
Initial moles (\(n_1\)) = 12 miles of gas (assuming you meant "moles" instead of "miles")
Final moles (n2) = 29.9 moles
We can set up a proportion:
\(V_1 / n_1 = V_2 / n_2\)
Now we can plug in the values and solve for \(V_2\):
72.3 L / 12 moles = \(V_2\) / 29.9 moles
Cross-multiply and solve for \(V_2\):
\(V_2\) = (72.3 L * 29.9 moles) / 12 moles
\(V_2\) ≈ 182.16 L
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Physical properties are used to classify and compare substances. Physical
properties can include density, thermal conductivity, electrical conductivity,
solubility, magnetism, melting point, and boiling point. Which statement is
correct about all of these physical properties?
They involve a change in the state of matter.
They involve the production of new substances.
They can be measured only after a change in state.
They are independent of the amount of the sample present.
Answer:
Physical properties involve a change in the state of matter.
Explanation:
A chemical change would change the chemical composition.
A physical change would change the state of matter, for example solid to liquid to gas are changes in state. So, this means when water changes states of matter it is a physical change.
A smoke obscuration meter was placed in an enclosure in a fire experiment. The light source and the detector (receiver) were 4.0 m apart. At a given time the measured smoke obscuration was 40%.
a) What are the corresponding optical density and extinction coefficient?
b) What is the visibility of a light emitting sign subjected to such an environment?
a) The smoke obscuration meter provides a measurement of smoke obscuration, which is defined as the reduction of transmitted light caused by smoke particles in the air.
The corresponding optical density can be calculated using the formula: optical density = -log(T), where T is the transmittance. In this case, the transmittance is 1 - 0.4 = 0.6. Therefore, the optical density is -log(0.6) = 0.221.
The extinction coefficient is a measure of how strongly the smoke particles scatter or absorb light, and can be calculated using the formula: extinction coefficient = optical density / distance. In this case, the distance between the light source and the detector is 4.0 m. Therefore, the extinction coefficient is 0.221 / 4.0 = 0.055.
b) The visibility of a light emitting sign subjected to such an environment can be calculated using the formula: visibility = e^(-kL), where k is the extinction coefficient and L is the path length of the light through the smoke.
In this case, we do not know the path length of the light through the smoke, so we cannot calculate the visibility.
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The heart has four chambers and, within them, blood normally circulates in only one direction: from the right atrium to the right ventricle and from the left atrium to the left ventricle. A certain disease sometimes allows the flow to occur in the opposite direction, that is, it passes from the left ventricle to the left atrium. This disease affects 2% to 3% of the population and rarely produces serious heart problems. Some patients have symptoms such as chest pain, fatigue, palpitation and dizziness. Which heart structure is affected by this disease. How did you reach that conlucsion?
Answer:
Likely an issue with the mitral valve.
Explanation:
If I read this correctly, you are likely referring to mitral regurgitation, which is a process where your mitral value does not close tightly enough to stop the blood to flow into left atrium.
Normally, when the left ventricle is full, the mitral valve shuts to prevent blood blood from flowing backward into the atrium while the ventricle contracts, and this allows for blood to go to aorta and to body. According to question since the process is reversed, I am gonna go out on a limb and say mitral valve is likely the structure affected by this since and how I came to conclusion is all the explaintion I did earlier.
In the modern system of classification, the three domains are Bacteria, Archaea, and _____________.
The three domains are the Archaea, the Bacteria, and the Eukarya