What is the graph of the inequality?
2. d<2 (1 point)
--4
+
-2
0
2
4
O
--4
-2
0
2
+
4.
++
4.
--4
-2
0
2
-4
-2
0
0
2
4

Answer:

Both

Step-by-step explanation:

You can find both from the given 85

Answer:

9 miles

Step-by-step explanation:

The answer is 9 miles because if you divide 0.6 mile by 4 minutes, you will have an answer of 9 miles an hour, as 0.6x15=9. In a full hour, Mike would walk 9 miles.

Answer:

I think this is right:

50:50

5/10

0.5

50%

Step-by-step explanation:

Answer:

90 Rotation: (-2,2) // (-2,10)

180 Rotation: (-2,-2) // (-10,-2)

270 Rotation: (2,-2) // (2,-10)

Part A: (x,y) --> (-y,x)

Part B: B^1(-4,1)  K^1(3,4)

Answer:

90 Rotation: (-2,2) // (-2,10)

180 Rotation: (-2,-2) // (-10,-2)

270 Rotation: (2,-2) // (2,-10)

Part A: (x,y) --> (-y,x)

Part B: B^1(-4,1)  K^1(3,4)

Step-by-step explanation:

I just did this and I got it right

hopes this helps you.

Answer:

10 chocolate cakes

Step-by-step explanation:

Your welcome!

Answer: So the division between two persons is 1/6 and 1/2.

Step by step: First Person = 1*4/24= 4/24 = 1/6 (0.16)

Second Person = 3*4/24 = 12/24= 1/2 (0.5)

Answer: the division between two persons is 1/6 & 1/2.

Step-by-step explanation:

Just divide

Answer:

700,000+ 8+20+ 40,000

Step-by-step explanation:

All you needed to do was line them up and find the missing value. Or add all of the given numbers and subract the answer. Quite simple actually

Answer:

700,000+40,000+ 20+8= 740,028

20 is the missing number

Answer:

5 faster than car 2

Step-by-step explanation:

find the slope abd divide

There are 5 erasers to accompany the 20 pencils based on the given ratio.

If the ratio of pencils to erasers is 4:1, and there are 20 pencils, we can determine the number of erasers by setting up a proportion.

The proportion can be written as:

pencils/erasers = 4/1

Given that there are 20 pencils, we can substitute this value into the proportion:

20/erasers = 4/1

To solve for erasers, we can cross-multiply:

\(20*1=4*erasers\)

\(20 = 4*eraser\)

Since there is only 1 unit assigned to erasers, we multiply the unit value (5) by the number of eraser units (1) to find the total number of erasers, which is 5.

Dividing both sides by 4:

20/4 = erasers

5 = erasers

Therefore, there are 5 erasers.

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Answer:

It will be A

Step-by-step explanation:

6453

- 135

--------

6318 dollars needed for Sarah's food.

Hope this helps!

The Solution.

The total number of people surveyed = 750.

The number of age group 41 - 50 that favored the Do-It-Yourself books = 69

The percentage of the people in age group 41 - 50, and favored the Do-It-Yourself books is calculated as below:

Hence, the correct answer is 9 percent.

The x-coordinate of the x-intercept of line k is -5/2.

Since this point lies on the x-axis, its y-coordinate is 0.

Given that the line has a y-intercept at the point (0, p), where p is a positive constant. This means that when x = 0, y = p.

As we know that the equation of the line can be written as y = mx + b, where m is the slope and b is the y-intercept.

Here, the slope is the negative of the fraction 2p/5, so the equation of line k is y = -2p/5 x + p.

Substitute y = 0 into the equation and solve for x:

0 = -2p/5 x + p

Subtract p from both sides and then multiply by 5/(-2p):

-2p/5 x = -p

x = (-p)(5/2p)

x = -5/2

Therefore, the x-coordinate of the x-intercept of line k is -5/2.

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The height of the building from which the angle of elevation is 32 degrees is 127.87m.

The angle of elevation is found to be 32 degrees and when moving 50 closer to the building, the angle of elevation is 53.

Let us say that the height of the building is X.

Now, let us say the distance between the building and the person is Y.

So, we write,

tan(32°) = X/Y

Also, tan(53°) = X/(Y-50)

0.62 = X/Y and 1.32 = X/(Y-50)

0.62Y = 1.32Y - 66

66 = 0.32Y

Y = 206.25 m

Now, we know, X = 206.25m x 0.62

X = 127.87m

So, the height of the building is 127.87m.

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Solving problems involving normal proportions requires careful attention to detail, as well as a good understanding of statistical concepts such as standardization and probability.

When solving a problem where you want to find normal proportions, you can follow the following steps:

Define the problem: Clearly define the problem you are trying to solve, including any relevant details such as the population, sample size, and the variable of interest.

Check assumptions: Check if the conditions for using normal distributions are met. The data should be continuous, the sample size should be large enough, and the distribution should be approximately normal.

Calculate the sample mean and standard deviation: If you are working with a sample, calculate the sample mean and standard deviation.

Standardize the data: Convert the data into standard normal distribution, by subtracting the mean from each observation and dividing by the standard deviation.

Determine the probability: Once the data has been standardized, you can use a standard normal distribution table or a calculator to determine the probability of the variable falling within a certain range or above/below a certain value.

Interpret the results: After determining the probability, interpret the results in the context of the problem. For example, you might conclude that there is a 95% chance that a randomly selected observation falls within a certain range, or that the variable of interest is higher than a certain value in 5% of cases.

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The volume of the sphere is 2308.4 mm³

From the question, we are to determine the volume of the sphere

The volume of a sphere is given by the formula

\(V=\frac{4}{3}\pi r^{3}\)

Where V is the volume

and r is the radius

From the given information,

Diameter, d, of the sphere = 16.4 mm

r = 16.4/2

r = 8.2 mm

∴ \(V=\frac{4}{3}\times 3.14 \times 8.2^{3}\)

V = 2308.394

V ≅ 2308.4 mm³

Hence, the volume of the sphere is 2308.4 mm³

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Answer:

The order of rotational symmetry is 4.

(a) The inverse z-transform of X(2) is r[n] = 8δ[n-2] + 3δ[n-2].

(b) The inverse z-transform of X(2) is r[n] = 7δ[n-2] + 3δ[n-2] + 2δ[n-2].

(c) The inverse z-transform of X(2) is r[n] = 22(-0.75)^n + 0.125(-2)^n.

(a) The inverse z-transform of X(2) is obtained by replacing z with the unit delay operator δ[n-2], which represents a shift of the signal by 2 units to the right. Since X(2) has two terms, we multiply each term by the corresponding δ[n-2] to obtain the inverse z-transform r[n] = 8δ[n-2] + 3δ[n-2].

(b) Similar to (a), we replace z with δ[n-2] and multiply each term in X(2) by the corresponding δ[n-2]. This yields the inverse z-transform r[n] = 7δ[n-2] + 3δ[n-2] + 2δ[n-2].

(c) For X(2), we have a geometric series with a common ratio of -0.75 or -2, depending on the absolute value of the term. By applying the inverse z-transform, we obtain r[n] = 22(-0.75)^n + 0.125(-2)^n.

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The returns when 30 tickets were sold would be $ 70 .

To calculate the total earnings from 30 sold tickets using the formula a ( n ) = 3 n - 20 , we must input n as 30 and assess the outcome .

Therefore, the returns raised when there were 30 tickets sold would be :
= 3 n - 20

= 3 ( 30 ) - 20

= 3 x 30 - 20

= 90 - 20

= 90 - 20

= $ 70

Therefore, with 30 tickets sold, the amount of money raised is $70.

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Question is:

How much was raised when 30 tickets were sold?

The true statement about the sampling distribution is "the sampling distribution of a statistic is a distribution that we should approximate in exercise by taking many small samples."

The sampling distribution is the theoretical distribution of a statistic (including the imply, median, or variance) based totally on all viable samples of a given size that could be taken from a population. it is a beneficial idea in statistics as it allows us to make inferences approximately the populace based on records gathered from a pattern.

In practice, we can not examine the whole sampling distribution, as it's far based totally on all viable samples, which isn't always feasible to gain. but, we will approximate the sampling distribution by taking many small samples from the population and calculating the applicable statistic for every sample.

Because the variety of samples increases, the distribution of these data will converge to the sampling distribution, allowing us to make more accurate inferences approximately the population.

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If we assume that 1 Student can have atmost 1 award , then the possible selections for the 4 awards is  657720 .

The total number of students at Gatech is = 30 ;

The 4 awards that are being distributed to students are : Chemistry, English, Math and Physics ;

all the awards are different , and 4 students needed to be chosen out of 30 for 4 awards ; and

every student can have atmost only 1 award

So , the number of ways is = ³⁰P₄ (because order is important) = 657720 ;

Therefore , the possible selection for 4 awards is 657720 .

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The given question is incomplete , the complete question is

At Gatech there are 30 students and 4 awards in Chemistry, English, Math and Physics. Assume that a student can have at most one award.

How many possible selections for the 4 awards ?  

The Wronskian determinant W(f, g) at t = e² is:

W(f, g) = 2e^(3e²) - e^(e² + 4)

To compute the Wronskian determinant W(f, g) of the functions f(t) = e^t and g(t) = t^2 at the point t = e², we need to evaluate the determinant of the matrix:

W(f, g) = | f(t) g(t) |

| f'(t) g'(t) |

Let's calculate the Wronskian determinant at t = e²:

f(t) = e^t

g(t) = t^2

Taking the derivatives:

f'(t) = e^t

g'(t) = 2t

Now, substitute t = e² into the functions and their derivatives:

f(e²) = e^(e²)

g(e²) = (e²)^2 = e^4

f'(e²) = e^(e²)

g'(e²) = 2e²

Constructing the matrix and evaluating the determinant:

W(f, g) = | e^(e²) e^4 |

| e^(e²) 2e² |

Taking the determinant:

W(f, g) = (e^(e²) * 2e²) - (e^4 * e^(e²))

= 2e^(3e²) - e^(e² + 4)

Therefore, the Wronskian determinant W(f, g) at t = e² is:

W(f, g) = 2e^(3e²) - e^(e² + 4)

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Answer:

p = 3

Step-by-step explanation:

Given

4(2 + px) = 12x

If the coefficient of the x- term is the same on both sides of the equation, it will have no solution.

Distributing gives

8 + 4px = 12x ( equate the coefficients of the x- term )

4p = 12 ( divide both sides by 4 )

p = 3

The value of p when the equation has no solution will be 3. Then the correct option is B.

A relationship between two or more parameters that, when shown on a graph, produces a linear model. The degree of the variable will be one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The linear equation is given below.

4(2 + px) = 12x

8 + 4px = 12x

If the coefficient of the x-term is the same on both sides of the equation, it will have no solution.

4p = 12

p = 3

The value of p when the equation has no solution will be 3. Then the correct option is B.

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Answer:

y = 2x - 6

Step-by-step explanation:

     Equation of the line:

            \(\sf \boxed{ y = mx +b}\)

      Here m is the slope and b is the y-intercept.

Step 1:  Find the slope

       (3 , 0) ⇒ x₁ = 3  & y₁ = 0

       (4 , 2) ⇒ x₂ = 4  &  y₂ = 2

      \(\sf \boxed{Slope=\dfrac{y_2-y_1}{x_2-x_1}}\)

                \(\sf = \dfrac{2 -0}{4-3}\\\\= \dfrac{2}{1}\\\\=2\)

Step2: Now, substitute the value of 'm' in the equation.

    y = 2x + b

Step3: In the above equation plug in any point. Here, (3 ,0) is chosed.

      0 = 2*3 + b

      0 = 6 + b

      -6 = b

Step4: Equation of the line:

Step-by-step explanation:

what do u think ?

not always true so the answer is false

Using the pumping lemma, it can be proven that the language L = {ωωRβ∣ω, β ∈ {0,1}+} is not regular. By selecting a string that violates the pumping condition, it is shown that the language cannot be generated by a regular grammar or finite automaton.

To use the pumping lemma to prove that the language L = {ωωRβ∣ω, β ∈ {0,1}+} is not regular, we assume that L is regular and proceed with the following steps:

Let p be the pumping length of L (as guaranteed by the pumping lemma).

Choose a string s = 0p10p, which is in L and has a length greater than or equal to p.

According to the pumping lemma, s can be divided into three parts: s = xyz, where |xy| ≤ p, |y| > 0, and for any non-negative integer n, xyⁿz must also be in L.

Consider pumping y, i.e., repeating y zero or more times. Pumping y should affect the number of 0s and 1s in the string.

If we pump y, the resulting string will have more or fewer 0s and 1s, which means it will no longer be of the form ωωRβ, violating the language L's definition.

Hence, the assumption that L is regular leads to a contradiction, indicating that L is not regular.

Therefore, we can conclude that the language L = {ωωRβ∣ω, β ∈ {0,1}+} is not regular based on the pumping lemma.

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Complete Question

using pumping lemma to prove that languge is not regularL

3 ={ωωRβ∣ω,β∈{0,1}+}

Answer:

The longest side of the ΔQRS is Side RS.

Step-by-step explanation:

Given:  m∠R=65°, m∠S=35° we don't know what m∠Q is in ΔQRS.

To find m∠Q , we first need to know that all triangles have a sum of 180°. Since we are already given two angle measurements ( m∠R and  m∠S) we can add them both measurements up which gives us 100°. Then we subtract 100 from the triangle sum which is 180° (180°-100°) and we are left with 80°. Which mean that m∠Q got to be 80°.

Now we know the all the angles measurements we can immediately find out which side is the longest. To find the longest side its always lie opposite the largest angle which in this m∠Q (80°). Which mean that side RS is the longest side in the triangle.

A conclusion which can be inferred about an individual score that corresponds to a z-value of 1.0 is that: c.) it is likely to come from the healthy distribution.

A z-value is also referred to as a z-score or standard score and it can be defined as a measure of the distance between a raw score and the mean, when standard deviation units are used.

In Statistics, z-values can either be positive or negative and it can be calculated by using this formula:

\(Z=\frac{x\;-\;u}{\delta}\)

Where:

Since the individual score that corresponds to a z-value of 1.0, we can reasonably infer and logically conclude that an individual score is likely to come from the healthy distribution.

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Complete Question:

Scores of healthy adults on a neurological test form a normal distribution with mean = 100 and SD = 15. What conclusion can be inferred about an individual score that corresponds to a z value of 1.0?

a.) it falls in the general region of the population

distribution

b.) it falls in the common region of the distribution

c.) it is likely to come from the healthy distribution

d.) it is unlikely to come from the healthy distribution