What is the image of (- 4, 3) after a dilation by a scale factor of 2 centered at the origin?

Answer:

Jennifer - 1st

Susan - 2nd

Emily - 3rd

Janice - 4th

Maria - 5th

Step-by-step explanation:

Susan is 2nd.

Places 1, 3, 4, and 5 are left.

Janice and Jennifer both start with J. None of the other swimmers start with the same first letter. One is 1st and one is 4th.

Since Maria finished immediately after Janice, and Janice must be 1st or 4th, Janice can't be first since 2nd place is already taken. This means that Janice is 4th and Maria is 5th.

Places 1 and 3 are left.

We know Jennifer is 1st or 4th and since 4th is taken, Jennifer is first.

Place 3 is left.

Emily must be 3rd since that is the only spot left.

The true statement is, Parameter values can be used within the method code block. (option e).

In computer programming, methods are used to group a set of instructions together that can be executed repeatedly. Parameters are used to pass values to a method so that the method can perform specific actions based on the values passed. Let's discuss the given statements one by one to determine which ones are true.

Parameter values can be used within the method code block.

This statement is true. Parameter values can be used within the method code block to perform specific actions. The parameter values can be manipulated or combined with other values to produce the desired result.

In summary, methods can be written with any number of parameters, and parameter values can be used within the method code block to perform specific actions. The number of parameters needed will depend on the specific task the method is designed to perform.

Hence the option (e) is correct.

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Answer:

The 3 option

Step-by-step explanation:

Answer:c

Step-by-step explanation:

Sub

Answer:

x = 18.4

Step-by-step explanation:

x - 3.5 = 14.9

Add 3.5 to both sides.

x = 14.9 + 3.5

x = 18.4

Answer:

x = 18.4

Step-by-step explanation:

x - 3.5 = 14.9

   + 3.5    +3.5

---------------------

x = 18.4

The equation 6(x + 5) = 6x + 5 has NS (No Solution) and the equation -4x = 7x - 33 has IM (Infinite Many solutions).

Let us take the given equation

6(x + 5) = 6x + 5

⇒ 6x + 30 = 6x + 5

⇒ 6x - 6x = 5 - 30

⇒ 0 = -25

Hence, the given equation has No Solution (NS)

Let us take the given equation

-4x = 7x - 33

-4x - 7x = -33

-11x = -33

x = 3

Hence, the given equations has Infinite Many solutions (IM)

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To match the equations in Column I with the correct first step for solving them in Column II, we need to identify the appropriate algebraic manipulation for each equation.

Equation (a) is 2x + 3 = 5. The correct first step for solving this equation is to subtract 3 from both sides to isolate the term with x, resulting in 2x = 2.

Equation (b) is √(x + 5) = 9. The correct first step for solving this equation is to square both sides of the equation, eliminating the square root, resulting in x + 5 = 81.

Equation (c) is (x + 5)^(5/2) = 32^(2/3). The correct first step for solving this equation is to raise both sides of the equation to the power 2/3, resulting in (x + 5)^(5/2)^(2/3) = 32.

Equation (d) is (x + 5)^(-6) = 0. The correct first step for solving this equation is to take the reciprocal of both sides, resulting in 1/(x + 5)^6 = 0.

Equation (e) is √(x(x + 5)) = -6. The correct first step for solving this equation is to square both sides of the equation, eliminating the square root, resulting in x(x + 5) = 36.

Matching the equations with their correct first steps:

(a) - Subtract 3 from both sides

(b) - Square both sides

(c) - Raise both sides to the power 2/3

(d) - Take the reciprocal of both sides

(e) - Square both sides

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The area bounded by the two functions f(x) = −x2 4x 2 and g(x) = −2x is =64 unit

To find the area bounded by the two functions f(x) = −x2 + 4x + 2 and g(x) = −2x + 10, we must first determine where the two functions intersect.

To do this, we set the two functions equal to each other and solve for x:

−x2 + 4x + 2 = −2x + 10
−x2 − 2x + 8 = 0
(x − 4)(x − 2) = 0
x = 4, x = 2

Now, we can calculate the area of the bounded region between f(x) and g(x):

Area = ∫24(g(x) − f(x)) dx

Area = ∫24(−2x + 10 − (−x2 + 4x + 2)) dx

Area = ∫24(x2 − 2x + 8) dx

Area = [x3/3 − x2/2 + 8x]24

Area = (64/3) − (32/2) + (64) = 64

Therefore, the area bounded by the two functions is 64.

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Answer:

x=-5-4=0

Step-by-step explanation:

Answer:

USE A CALCULATOR DUH

Step-by-step explanation:

simple push 0.8 divided by 0.6 on the calculator, boom, out comes the answer. then just round it to the nearest hundredth. simple as that

hope that helps! :)

The expression 0.8÷0.6 to the nearest hundredth is 1.33

Given the following expression: 0.8÷0.6

Convert each of the terms to fraction:

0.8 = 8/10

0.6 = 6/10

Substitute into the expression

0.8÷0.6

= 8/10 ÷ 6/10

= 8/10 * 10/6

= 8/6

= 1.3333

Hence the expression 0.8÷0.6 to the nearest hundredth is 1.33

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Answer:

The equation a parallel line will be:

\(y=\frac{4}{3}x-9\)

Hence, option B is correct.

Step-by-step explanation:

Given the equation

\(8x-6y=7\)

Writing the line into the slope-intercept form

\(y = mx+b\)

where m is the slope and b is the y-intercept

so

\(8x-6y=7\)

\(6y\:=\:8x-7\)

Dividing both sides by 6

\(y=\frac{4}{3}x-\frac{7}{6}\)

comparing with the slope-intercept form

Thus, the slope of the line = m = 4/3

We know that the parallel lines have the same slope.

Thus, the slope of the parallel line is also 4/3

Using the point-slope form of the line equation

\(y-y_1=m\left(x-x_1\right)\)

where m is the slope of the line and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (6, -1)

\(y-y_1=m\left(x-x_1\right)\)

\(y-\left(-1\right)=\frac{4}{3}\left(x-6\right)\)

\(y+1=\frac{4}{3}\left(x-6\right)\)

Subtract  1 from both sides

\(y+1-1=\frac{4}{3}\left(x-6\right)-1\)

\(y=\frac{4}{3}x-9\)

Thus, the equation a parallel line will be:

\(y=\frac{4}{3}x-9\)

Hence, option B is correct.

Londell needs to deliver newspapers for 24 weeks to have enough money to buy the bicycle.

Londell currently has $40 saved, and he needs a total of $400 to buy the bicycle. Each week, he earns $15 delivering newspapers.

To calculate the number of weeks Londell needs to work, we can set up an equation:

$40 (current savings) + $15 (weekly earnings) × (number of weeks) = $400 (total cost of the bicycle)

Simplifying the equation:

$40 + $15 = $400

Subtracting $40 from both sides of the equation:

$15 = $400 - $40

$15 = $360

Dividing both sides of the equation by $15:

= $360 / $15

≈ 24

Therefore, Londell will have to deliver newspapers for approximately 24 weeks to have enough money to buy the bicycle.

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Yes, they're equal.

det(A + AB) = det(AI + AB) = det(A (I + B)) = det(A) det(I + B)

and

det(A + BA) = det(IA + BA) = det((I + B) A) = det(I + B) det(A)

which are the same.

Therefore, the number of ways a student can work 7 out of 10 questions on the exam is 120, which corresponds to option (D).

The number of ways a student can work 7 out of 10 questions on an exam can be calculated using the concept of combinations.

The formula for combinations is given by:

C(n, k) = n! / (k!(n - k)!)

Where n is the total number of items and k is the number of items chosen.

In this case, the student is choosing 7 questions out of a total of 10, so we have:

C(10, 7) = 10! / (7!(10 - 7)!) = 10! / (7!3!)

Simplifying:

10! = 10 * 9 * 8 * 7!

3! = 3 * 2 * 1

C(10, 7) = (10 * 9 * 8 * 7!) / (7! * 3 * 2 * 1)

The 7! terms cancel out:

C(10, 7) = (10 * 9 * 8) / (3 * 2 * 1)

C(10, 7) = 120

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The price per T-shirt should be at least $15 to achieve a profit of $250.

To calculate the price per T-shirt that will yield a profit of at least $250, we need to consider the cost of production, the desired profit, and the number of shirts to be sold.

Given that the cost to make each T-shirt is $10, and we want to sell 50 shirts, the total cost of production would be 10 * 50 = $500.

Now, let's calculate the minimum revenue needed to achieve a profit of $250. We add the desired profit to the total cost of production: $500 + $250 = $750.

Finally, to determine the price per T-shirt, we divide the total revenue by the number of shirts: $750 ÷ 50 = $15.

Therefore, to make a profit of at least $250, the price per T-shirt should be set at $15.

By selling each T-shirt for $15, the total revenue would be $15 * 50 = $750. From this revenue, we subtract the total production cost of $500 to calculate the profit, which amounts to $750 - $500 = $250. Thus, by charging $15 per T-shirt, the desired profit of $250 is achieved.

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Answer: the third one

Step-by-step explanation:

The best estimate of the average change in mood rating linked with an additional hour spent playing sports is 1.5 points, according to the presented linear function.

A linear function is modeled by:

\(y = mx + c\)

In which:

m is the slope, which is the rate of change of y when x changes by 1.

c is the y-intercept, which is the value of y when x = 0.

x is the number of hours they spent playing sports.

y be their mood rating.

Therefore, the equation will be:

\(y=1.5x+5\)

The best estimate of the average change in mood rating linked with a 1 hour increase in hours spent doing sports is 1.5 points because the slope is m= 1.5.

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Answer:

the answer  is 8

Step-by-step explanation:

yes Ezra can plant 8 sunflowers

hope this helpsss :)

Answer:

Step-by-step explanation:

Answer:

Find the retail sale price of each item below. Round to two decimal places when necessary. Original price : $325.50; Markdown: 15%.

Answer:

center = \((-4,8)\)

Radius = 7 units

Step-by-step explanation:

Given: Equation of circle is \(x^2+y^2+8x-16y+31=0\)

To find: Radius and center of the circle

Solution:

Equation of circle is \((x-a)^2+(y-b)^2=r^2\)

Here, \((a,b)\) is the center and r is the radius.

\(x^2+y^2+8x-16y+31=0\\\left [ x^2+2(4)x+4^2 \right ]+\left [ y^2-2(8)y+8^2 \right ]+31=4^2+8^2\)

Use formula \((u+v)^2=u^2+v^2+2uv\)

\((x+4)^2+(y-8)^2=16+64-31\\(x+4)^2+(y-8)^2=49=7^2\)

On comparing this equation with equation of circle,

center = \((-4,8)\)

Radius = 7 units

Answer:

center: (4,-4)

Radius: 9

Step-by-step explanation:

KHAN ACADEMY

Answer:

13. \(12.88m\)

14. \(10ft\)

Step-by-step explanation:

To calculate the circumference, use the following formula, where \(d\) is the diameter:

\(C = \pi d\\C = 3.14159 * 4.1 = 12.88m\)

To find the arc length, use the following formula, where \(r\) is radius and \(\theta\) is the angle in radians:

\(s = r\theta\)

Before you plug in any values, convert the angle from degrees to radians using the following formula, where x is the angle in degrees:

\(\theta = \frac{x}{180}\pi\\\theta = \frac{144}{180}\pi\\\theta \approx 2.5\)

Now plug in your values:

\(s = 4 \cdot 2.5\\s = 10ft\)

The Linnaean class system provides a framework for understanding the diversity of life on Earth by grouping similar organisms together based on shared characteristics.

By comparing and contrasting the definitions of each class, we can see how different groups of animals are related to each other and how they differ in terms of their biological traits.

The Linnaean class system is a way of organizing living things based on shared characteristics. Let's compare and contrast the definitions of the Linnaean classes using a Venn diagram.

First, we have the class Mammalia, which includes all animals that have hair or fur, produce milk to feed their young, and have specialized teeth. This class overlaps with the class Aves, which includes all birds, because some birds have specialized beaks and feathers that are similar to mammalian hair and teeth. However, birds do not produce milk.

Next, we have the class Reptilia, which includes animals that are cold-blooded, lay eggs, and have scales or plates on their skin. This class overlaps with both Mammalia and Aves in terms of species that lay eggs, such as monotremes (platypus and echidnas) and some birds (ostriches and emus). However, reptiles lack specialized teeth and do not produce milk.

Finally, we have the class Amphibia, which includes animals that are cold-blooded, breathe through their skin, and undergo metamorphosis from a water-dwelling larval stage to a land-dwelling adult stage. This class overlaps with Reptilia in terms of some shared characteristics, but Amphibia also lacks specialized teeth and does not lay eggs with hard shells like reptiles.

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Answer:

2+2+28+28=60 is the answer of the perimeter

Step-by-step explanation:

Inequalities help us to compare two unequal expressions. The length of the rectangle can be 19 cm, while its width will be 17 cm.

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

Let the length of the rectangle be represented by x centimeters. Given the width of a rectangle is 2 cm less than the length. Therefore, the width of the rectangle is (x-2) centimeters.

Since the perimeter of the rectangle should be greater than 28 inches, therefore,

Perimeter of the rectangle > 28 inches × 2.54 = 71.12 centimeters

Now, given the perimeter is greater than 28 inches. Therefore,

2[x+(x-2)] > 71.12

x + (x-2) > 35.56

x + x - 2 > 35.56

2x - 2 > 35.56

2x > 37.56

x > 18.78

x = 19

Thus, the length of the rectangle can be 19 cm, while its width will be 17 cms.

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ANSWER

Let the inequality for the prices of the items in the store be y

The solution set for y is {...................,$-3 ,$-2 ,$-1 ,$0 ,$1}

The inequality is y < $1

Answer:

8p=c

Step-by-step explanation:

The number of pounds Lamar buys multiplied by the cost of a pound which is 8 equals c. 8p=c

Answer:

x=0, -5/3

Step-by-step explanation:

If A is an invertible matrix, then ATA is also invertible. This is because the determinant of ATA is the product of the determinants of AT and A, and since A is invertible, its determinant is not equal to zero. Therefore, the determinant of ATA is also not equal to zero, which means that ATA is invertible.

1. If A is invertible, then det(A) ≠ 0.
2. The determinant of ATA is equal to the product of the determinants of AT and A, i.e. det(ATA) = det(AT) * det(A).
3. Since A is invertible, det(A) ≠ 0, and det(AT) = det(A), we have det(ATA) = det(A) * det(A) ≠ 0.
4. Therefore, ATA is also invertible.

In conclusion, if A is an invertible matrix, then ATA is also invertible.

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