what is the lighting load on a 120v circuit for six 100w incandescent lights and four fluorescent fixtures with a ballast rating of 1.5a, all operating continuously for 8 hours per day?

Answer:

In my opinion, Energy, Time, Money and Development

Answer:

Pollution, time, money, and energy.

Explanation:

Loose Coupling. Loose coupling is a method of connecting system or network components so that they depend on one another as little as possible. These components are also known as elements.

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The area of the gutter is therefore equal to the area of the rectangle plus the area of the triangles.

A = rectangle + 2 * triangle

= 10h + 2 * (1/2 hw)

Using trig work out h and w.

h = 10 sin ?

w = 10 cos ?

A = 10h + hw

= 100sin? + 100sin?cos?

Differentiate the expression (either use the product rule for sin? cos?, or write 100sin?cos? as 50sin2? using the double angle formula)

A = 100sin? + 50sin2?

dA/dt = 100cos? + 100cos2?

For A to be a max or min the derivative must equal zero

100cos? + 100cos2? = 0

cos? + cos2? = 0

Use the double angle formula to write cos2? as 2cos^2 ? - 1

cos? + 2cos^2 ? - 1 = 0

2cos^2 ? + cos? - 1 = 0

This quadratic factorizes:

(2cos? - 1)(cos? + 1) = 0

This means that

cos ? = 1/2 or cos ? = 1

giving:

? = pi/3 or ? = pi

Which means that to achieve the maximum area ? should be pi/3 = 60 degrees

You can check that this is the max by substituting in these values of theta and the two end points (theta = 0, theta = pi), and seeing that pi/3 gives the maximum.

The maximum area is therefore

A = 100sin? + 100sin?cos?

= 100sin(pi/3) + 100sin(pi/3)cos(pi/3)

= 100 sqrt(3) / 2 + 100 sqrt(3)/2 * 1/2

= 100 * 3/2 * sqrt(3) / 2

= 3 * 25 * sqrt(3)

= 75 sqrt(3)

= 129.9...

= 130 cm^3

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Of the three types of hazard controls – engineering, administrative, and personal protective equipment (PPE) – PPE is the last line of defense: True.

OSHA is simply an abbreviation for occupational safety and health administration that was created under the Occupational Safety and Health Act, so as to develop work-safety standards for workers and providing precautionary measures against all workplace hazards.

Generally, there are three types of hazard controls and these include the following:

PPE is an acronym for personal protective equipment and it can be defined as a terminology that is used to denote any piece of equipment which offer protection to different parts of the body while working in a potentially hazardous environment.

Also, some examples of personal protective equipment (PPE) used to protect the different parts of the body are:

According to occupational safety and health administration (OSHA), the use of a faulty personal protective equipment (PPE) should be the last line of defense.

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Complete Question:

Of the three types of hazard controls – engineering, administrative, and personal protective equipment (PPE) – PPE is the last line of defense. True or False?

Answer:

98 x 100=9,00

Explanation:

The phase angle is 180°.

A resistor, inductor, and capacitor are connected in series to an AC source.

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Answer:

1/8 is the maximum length for opening any on the surface of 2 gtam guided bend test specimen

Asbestos may cause cancer by inhalation. Moreover, asbestos is also known to cause different respiratory diseases (especially asbestosis) by affecting the mucosa of the bronchi.

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Answer:

False

Explanation:

To complete the assignment, modularize your code using functions and classes. Utilize exception handling and implement two classes: "Store" with a constructor, setter method, and display method. Test your program thoroughly to avoid crashes and deductions in points.

To complete this assignment, you will need to use functions and classes to modularize your work. Additionally, you should utilize exception handling where necessary to ensure that your program does not crash on expected input. Failure to do so will result in a deduction of 50 points.

The main goal of this assignment is to create an application where the user can input the name and location of a store and then start their grocery shopping by adding items to a cart. To accomplish this, you will need to implement two classes with methods and attributes.

The first class you will need to implement is the "Store" class. This class should have a constructor that initializes two instance attributes: "name" and "location". Additionally, you should include a setter method that allows you to set the name and location of the store.

Lastly, you will need to implement a "display" method in the Store class. This method should output all the information from the Store class, including the name and location of the store.

Here is a step-by-step breakdown of what you need to do:

1. Define the Store class with the following attributes:
  - name
  - location

2. Implement a constructor in the Store class that takes the name and location as parameters and assigns them to the corresponding attributes.

3. Implement a setter method in the Store class that allows you to set the name and location of the store.

4. Implement a display method in the Store class that outputs all the information from the Store class, including the name and location of the store.

Remember, you have the flexibility to add extra methods or attributes as needed to complete the program successfully. Make sure to test your program thoroughly to ensure it functions as expected and does not crash on expected input.

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In the given question, Moist unit weight = 115lbs/ft³, Dry unit weight = 103.6 lbs/ft³, Void ratio = 0.626,  Porosity = 0.385 and Degree of saturation =  47.4%

Porosity, also known as void fraction, is a measure of the void (i.e., "empty") spaces in a material. It ranges from 0 to 1, or as a percentage, between 0% and 100%, and represents the volume of voids over the total volume. Some tests, strictly speaking, measure the "accessible void," or the total volume of void space that is reachable from the surface (cf. closed-cell foam).

Porosity in a substance or part can be tested in a variety of ways, including through industrial CT scanning. The word "porosity" is used in a variety of disciplines, including pharmaceutics, ceramics, metallurgy, materials, manufacturing, petrophysics, hydrology, earth sciences, soil mechanics, and engineering.

a. Moist unit weight

W/V = 23/0.2 = 115lbs/ft³.

b.  Dry unit weight

89℅ of 115 = 103.6 lbs/ft³

c. Void ratio = volume of void/ volume of total sample

                     = (2.7 × 62.4)/103.6

                     = 0.626

d. Porosity = 0.626/1+0.626

                  = 0.385

e. Degree of saturation =  47.4%

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Each step should be explained by assuming that n is odd, that is, it is not even. The conclusion is refuted. After that, for some integer k, n = 2k + 1.

It is easy to understand how to make a contrapositive statement once one is familiar with the inverse statement. To get the inverse of the conditional statement, take the negation of the hypothesis and the conclusion. To generate the contrapositive of the conditional statement, first make the inverted statement, then switch the hypothesis and conclusion. 3.5n + 3 = 5(2k + 1) + 3 = 10k + 8 = 2(5k + 4). What is an even number? 1. Suppose that n is odd, that is, it is not even. The conclusion is refuted. 2. n is defined as an odd number when it equals 2k + 1 for some integer k. The definition of an even number in mathematics is 3.5n + 3 = 5(2k + 1) + + 3 = 10k + + 8 = 2(5k + 4) 5. As a result, 5n + 3 is even.

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Answer:

Explanation:

The most common HFC used in air conditioners is R-410A. This refrigerant is better than R-22 in terms of “Ozone Depletion” potential and energy efficiency, but it still causes global warming. A few more HFCs that are commonly used are: R-32 in Air Conditioners and R-134A in refrigerators.

Answer:

The most common refrigerants used for air conditioning over the years include

Explanation:

The most common refrigerants used for air conditioning over the years include.

Answer:

The greatest mass, that the weight C can have such that block A does not move is approximately 23.259 kg

Explanation:

The given parameters are;

The mass of the block A= 58 kg

The coefficient of static friction between the block and the surface, \(\mu _s\) = 0.300

The coefficient of static friction between the rope and the fixed peg, B \(\mu _B\) = 0.310

Let T represent the tension in the rope

Therefore, when the rope is static, T = The normal reaction at the peg, B, \(N_B\)

The angle of inclination of the rope holding the block A = arctan(3/4) ≈ 36.87°

The length of the rope = √(0.4² + 0.3²) = 0.5

∴ sin(θ) = 3/5 = 0.6

cos(θ) = 4/5 = 0.8

The vertical component of the tension in the rope = T × sin(θ) = 0.6·T

The horizontal component of the tension in the rope = T × cos(θ) = 0.8·T

The friction force = μ×(W - 0.6·T) = 0.300×(58×9.8 - 0.6·T) = 170.52 - 0.18·T

The block will start to move when we have;

The horizontal component of the tension in the rope = The friction force

∴ 0.8·T = 170.52 - 0.18·T

0.8·T + 0.18·T = 170.52

0.98·T = 170.52

T = 170.52/0.98 = 174

Therefore, the tension in the rope = T = 174 N = The normal reaction at the peg, B \(N_B\)

The frictional force at the peg, \(F_B\) = \(\mu _B\) × \(N_B\) = 0.310 × 174 N = 53.94 N

The weight of the mass, \(m_c\), \(W_c\) = The frictional force at the peg, \(F_B\)  + The tension in the rope

∴ The weight of the mass, \(m_c\), \(W_c\) = 53.94 N + 174 N = 227.94 N

Weight, W = Mass, m × The acceleration due to gravity, g, from which we have;

m = W/g

Where;

g = 9.8 m/s²

∴ \(m_c\) = \(W_c\)/g = 227.94 N/(9.8 m/s²) ≈ 23.259 kg.

The greatest mass, that the weight C can have such that block A does not move = \(m_c\) ≈ 23.259 kg.

Trim moldings, including baseboard, casing, chair rail, and crown molding, are typically removed during the demolition or renovation phase of a project.

Trim moldings, which consist of baseboard, casing, chair rail, and crown molding, serve both decorative and functional purposes in a home or building. They help protect walls, cover gaps, and enhance the overall appearance of a space. When a renovation or demolition project takes place, these moldings need to be removed in order to make any necessary structural changes or updates to the interior space.

The removal process involves carefully prying the moldings from the walls using tools such as pry bars or crowbars, taking care not to damage the surrounding surfaces. Once removed, they can either be discarded, reused, or replaced with new moldings, depending on the project's requirements and the condition of the existing moldings.

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Answer:

  0.42 kg

Explanation:

Heat is proportional to mass by way of the conversion factor that is the inverse of the specific heat.

  \(\dfrac{63000\text{ J}}{\dfrac{3000\text{ J}}{\text{kg$\cdot$K}}\cdot(65-15)\text{ K}}=0.42\text{ kg}\)

The mass of the liquid is about 0.42 kg.

If I had to guess, I'd say the answer is

Drier conditions will likely result in more wildfires

Studies show that warmer and drier areas will double in wildfires by 2050.

Answer:

Explanation:

how

Answer: a thicker line

Explanation:

Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

Here are the appropriate flowchart symbols for each of the statements:

I. Accept Variable num: Parallelogram with "Input/Output" written inside

II. Is num > 0 ?: Diamond with "Yes" and "No" written on either side

III. Display num: Parallelogram with "Input/Output" written inside

IV. Num = num + 1: Rectangle with "Process" written inside

V. Stop: Oval with "Terminator" or "End" written inside

Putting all these symbols together, the flowchart would look like this:

     +--------------+

     |              |

+---->+ Input/Output |

|     |              |

|     +------+-------+

|            |

|            v

|      +-----+-----+

|      |           |

|      |   Diamond |

|      |           |

|      +-+-----+---+

|        | Yes |

|        v     v

|      +-------+---+

|      |           |

|      | Input/Output |

|      |           |

|      +-------+---+

|              |

|              v

|      +-------+-+

|      |         |

|      |  Process |

|      |         |

|      +---------+

|              |

|              v

|      +-------+-+

|      |         |

|      |  End    |

|      |         |

|      +---------+

|              

+--------------+

Answer: Si (Yes)

Explanation:

Answer:

Protozoario o protozoo es un organismo unicelular y eucariota (con núcleo celular definido) perteneciente al Reino protista. Los protozoarios se encuentran junto con los protófitos o algas simples, generalmente acuáticas, dentro del Reino protista o también denominado Reino protoctista.

Explanation:

Answer:

The main reason for bridges collapses is: earthquakes (natural disasters) and construction incidents. Whenever a natural disaster occur, it makes the bridge collapse. An example is hurricanes. Hurricanes come with a great wind and that might lead to the bridge collapsing. Construction incidents means the bridge falls during construction. Those who are employed in health, safety and environmental management need to make sure that during the construction, they have examined the material and made sure it is strong. Working with economists, they should seek better understanding of the methods for minimizing the costs during the life of the bridge. In case for natural disasters, like flooding, they should make the bridge in a lever where the water won't reach the bridge. And they should have a limit for weight in the bridges because that is another reason it collapses, because the bridge does not support extra weight.

Explanation:

hope this helps

Answer:

90 degrees

Explanation:

In the case when the sheer stress acts in the one plane of an element so it should be equal and opposite also the shear stress acted on a plan i.e. 90 degrees from the plane

Therefore as per the given situation it should be 90 degrees from the plane

hence, the same is to be considered and relevant too

Field relative density (Dr) can be calculated using the relationship between field moist unit weight (γfm) and maximum and minimum dry unit weight (γdmax and γdmin) as follows:$$Dr = \frac{\gamma_{fm} - \gamma_{dmin}}{\gamma_{dmax} - \gamma_{dmin}}$$Given: Field moist unit weight (γfm) = 18.08 kN/m³,

Maximum dry unit weight (γdmax) = 16.93 kN/m³, Minimum dry unit weight (γdmin) = 14.46 kN/m³The field relative density (Dr) can be calculated as follows:$$Dr = \frac{\gamma_{fm} - \gamma_{dmin}}{\gamma_{dmax} - \gamma_{dmin}}=\frac{18.08 - 14.46}{16.93 - 14.46}=0.3939$$Therefore, the field relative density of the construction project is 0.3939 or approximately 39.39% which is less than 50%.Hence, the construction project is in a loose state or in the compaction stage.

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It appears that the country has a problem with infrastructure and public facilities maintenance.

The updating of water and sewer systems, road and bridge closures, and public parks full of litter and decaying facilities suggest that there is a lack of attention to and investment in the maintenance and improvement of these critical elements of the country's infrastructure.

This can lead to a number of problems, including health and safety risks, environmental degradation, and reduced quality of life for citizens. In addition, outdated and decaying infrastructure can also have a negative impact on the economy, as it may limit the ability of businesses and individuals to transport goods and travel effectively. To address these issues, the country may need to allocate more resources to infrastructure and public facility maintenance and improvement.

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Answer: Technician A is wrong , Technician B is correct.

Explanation:

The Air fuel ratio is used in the combustion process of engines whether internal or external, and defined as the mass  ratio of air to  fuel present in a combustion process.  When the ratio of the mass of air and fuel is right, combustion is said to be efficient and balanced and this is refereed to as stoichiometrc mixture which is a standard that all engines are required to target.

when the air fuel Ratios is  lower than the target stoichiometric, it is considered as a Rich mixture  while higher ratios  than stoichiometric are considered Lean mixtures. Lean mixtures are more efficient than rich mixtures although the main aim is to be at the stoichiometic mixture point.

Air fuel equivalence ratio, lambda and the amount of oxygen in an exhaust are two indicators for lean or rich mixtures in an air fuel ratio for combustion in engines

Now, Air–fuel equivalence ratio, λ (lambda), is defined as the  ratio of actual AFR to stoichiometry for a particular mixture,

when Lambda λ = 1.0 , the mixture is at stoichiometry,

when  λ < 1.0, the mixtrure is rich.

when  λ > 1.0, the mixture is  lean

 Therefore Technician A is wrong

Also The amount of oxygen present in the exhaust determines if the air-fuel mixture supplied to the combustion chambers is at the target or best ratio. Too much oxygen indicates that the mixture is lean and too little  indicates the mixture is rich. Therefore Technician B is right.

Answer:

the answer I know is A. different substances. hope this helps :).

Explanation:

just always study hard and God bless.