What is the longest wavelength of electromagnetic radiation capable of ionizing this hydrogen atom in an excited state

Answer:

So... for the element of SODIUM, you already know that the atomic number tells you the number of electrons. That means there are 11 electrons in a sodium atom. Looking at the picture, you can see there are two electrons in shell one, eight in shell two, and only one in shell three.

Explanation:

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Answer:

so there would be 2 electrons because

Explanation:

sodium has 11 electrons but if you look at the shels it onl has one electron (from the image im looking at) and the other shell only have one so theres 2 electrons

The molarity of the solution is 0.168 mol/L. Moles is a unit of measurement used in chemistry to express the amount of a chemical substance.

To find the molarity of the solution, we need to use the formula:

Molarity = moles of solute / liters of solution

First, let's calculate the moles of KCl in the solution:

moles of KCl = mass of KCl / molar mass of KCl

mass of KCl = 50.0 g

molar mass of KCl = 74.5 g/mol

moles of KCl = 50.0 g / 74.5 g/mol = 0.6711 mol

Next, we can plug in the values into the formula for molarity:

Molarity = moles of solute / liters of solution

moles of solute = 0.6711 mol

liters of solution = 4.00 L

Molarity = 0.6711 mol / 4.00 L = 0.168 mol/L

Therefore, the molarity of the solution is 0.168 mol/L.

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Butyryl chloride reacts with Grignard reagent, methyl magnesium bromide, to form pentan-2-one. Pentan-2-one reacts with vinyl magnesium bromide to form the final product 3-methylhex-1-en-3-ol.

The following diagram illustrates how butyryl chloride becomes 3-methylhex-1-en-3-ol. conversion of 3-methylhex-1-en-3-ol from butyryl chloride. Tertiary alcohols are produced when carboxylic esters, R'CO2R, combine with two equivalents of an organolithium or Grignard reagent. Two identical alkyl groups are present in the tertiary alcohol (see R) A ketone intermediate is used to carry out the reaction, which is subsequently used to react with the second equivalent of the organometallic reagent. As we've just seen, the ketone undergoes further reactions to create a tertiary alcohol. This explains why, when reacting with esters, two equivalents of Grignard are required. a mechanism The Grignard performs an addition reaction on the ester in the first step, resulting in the formation of C-C and the breakdown of C-O (pi), giving us an intermediate with a negatively charged oxygen.

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Answer:

What is meant by activated complex?

The state of the particles that is in between the reactants and products is called the activated complex. An activated complex is an unstable arrangement of atoms that exists momentarily at the peak of the activation energy barrier.

source:Gogle

What to do is On Form N-445, Notification of Naturalization Oath Ceremony, complete the questionnaire.Visit USCIS before your naturalisation ceremony and report there.Your Legal Resident Card must be returned (Green Card).To become an American citizen, you must take a Oath of Allegiance.

In a Nutshell:Application for Naturalization Form N-400 takes between 8 and 12 months to complete.On the USCIS website, keep records of your naturalisation application, and remain in touch wit your immigration attorney if you need any guidance.

$1,170.You have three options for paying the fee: cashier's check, personal check, or money order.You can pay with a credit card while submitting paperwork at the a USCIS lockbox by utilising Form G-1450, Permission for Card Transactions.

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Answer:

chemical bonds

Explanation:

The atoms in chemical compounds are held together by attractive electrostatic interactions known as chemical bonds. Ionic compounds contain positively and negatively charged ions in a ratio that results in an overall charge of zero. The ions are held together in a regular spatial arrangement by electrostatic forces.

The frequency of the electromagnetic wave is 8.1 x 10 ¹⁸ Hz.

The speed of light in a vacuum is given as 3.00 x 10⁸ m/s. The speed of light is also related to the wavelength and frequency of the electromagnetic wave by the equation:

c = λν

where c is the speed of light, λ is the wavelength, and ν is the frequency.

Rearranging the equation to solve for frequency, we get:

ν = c/λ

Substituting the values given in the problem, we get:

ν = (3.00 x 10⁸ m/s) / (3.7 x 10⁻¹¹ m)

ν = 8.1 x 10 ¹⁸ Hz

Therefore, the frequency of the electromagnetic wave is 8.1 x 10 ¹⁸ Hz, and the correct answer is (A) 8.1 x 10 ¹⁸ Hz.

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Answer::

Explanation::

Mangrove trees' robust roots aid in stabilizing the soil and preventing soil erosion. This is especially crucial in swampy coastal locations, where the soil is frequently loose and prone to wind and wave erosion. Mangrove trees work to stabilize the coastline and stop land erosion by securing the soil in place.

Mangrove trees also aid in removing contaminants from the water, enhancing the quality of the water in coastal areas while serving as an essential home for a variety of wildlife species. Mangrove trees contribute significantly to environmental protection and are an essential component of coastal ecosystems.

Mangrove trees are crucial for environmental preservation because they hold the soil in place and stop erosion in marshy coastal areas. They also provide crucial habitats for numerous wildlife species, stabilize the coastline, and stop the land from being lost to erosion while enhancing water quality by filtering pollutants from the ocean.

Mangrove trees are an essential part of coastal ecosystems overall, and preserving them is essential for preserving a healthy and sustainable environment.

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the possible quantum numbers (ordered n, ℓ, mℓ ) are:Option B.5, 3, -3 and Option C. 4, 3, -2

The quantum numbers n, ℓ, mℓ represent respectively the principal quantum number, the orbital angular momentum quantum number and the magnetic quantum number.

These are the three most important quantum numbers. T

here is another quantum number called the spin quantum number, denoted by ms.

Let's see which of the given quantum number sets is possible.2, 1, 3 is not possible because for ℓ = 1, mℓ can only be -1, 0, or 1. 5, 3, -3 is possible.4, 3, -2 is possible. -4, 3, 1 is not possible.

For any value of ℓ, mℓ must be between -ℓ and +ℓ. e. 2, 1, -2 is not possible because for ℓ = 1, mℓ can only be -1, 0, or 1. f. 3, 2, 2 is not possible because for ℓ = 2, mℓ can only be -2, -1, 0, +1, or +2. g. 3, 3, 1 is not possible because for any value of ℓ, mℓ must be between -ℓ and +ℓ.

Therefore, the possible quantum numbers (ordered n, ℓ, mℓ ) are:5, 3, -34, 3, -2

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Answer:  **

H-N-H

   |

  H

Explanation:

Look at a periodic table to determine how many electrons you need to account for. Hydrogen (H) only has 1 electron, while Nitrogen (N) has 5. We have three Hydrogen atoms and one Nitrogen atom, so the total number of electrons will be 3 * 1 + 5 = 8 e-.

Now, place the center atom, which will be Nitrogen and place the three Hydrogens on three sides of it as above in the answer. You should use single bonds for this. Each single bond is a pair of electrons, so since we have three single bonds so far, we have accounted for 2 * 3 = 6 electrons. However, we need 2 more electrons for the total of 8. We put these electrons in as a lone pair above Nitrogen.

We check to see if everything follows the octet rule: Nitrogen has three single bonds, so that's 6 e-, as well as one lone pair, so that's another 2 e- for a total of 8 e-. Check. Now look at Hydrogen: H is the only element whose full orbital is 2 e-. Each H has a single bond with Nitrogen, so each does have 2 e-.

Thus, we know this is the correct diagram, and we are done.

Explanation:

A bond line structure of a compound has H N H in linear plane and a hydrogen is branching upward, and the compound is H N (H) H. The nitrogen has two dots at its bottom represents a lone pair of electrons. So ,the correct answer is option C.

The correct Lewis structure for ammonia (\(NH_3\)) is option C. It shows a bond line structure with three hydrogen atoms (H) bonded to a central nitrogen atom (N) in a linear plane.

One hydrogen atom branches upward from the plane. Additionally, the nitrogen atom in this structure has two dots at its bottom, indicating a lone pair of electrons. This arrangement follows the octet rule, as nitrogen has formed three covalent bonds with hydrogen, completing its valence shell. The lone pair on nitrogen gives ammonia its characteristic properties.

Thus, option C accurately represents the Lewis structure of ammonia, showing the bonding and lone pair arrangement of its atoms.

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All of the organelles are held in a special gel called cytoplasm.

A cell can be defined as the fundamental (basic) functional, structural and smallest unit of life, which is found within the body of an organism.

In Science, some examples of cell organelles that are found in the body of an organism include the following:

A cytoplasm can be defined as a gelatinous liquid (semifluid substance) that fills the inside of cells in the body of an organism. This ultimately implies that, cytoplasm is an cell organelle that holds every other cell organelles in a gelatinous liquid (semifluid substance).

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Answer: The half-life of the compound is 93 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

\(t=\frac{2.303}{k}\log\frac{a}{a-x}\)

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant =100

a - x = amount left after decay process = (100-36) = 64

a) for completion of 36 % of reaction

\(60=\frac{2.303}{k}\log\frac{100}{100-36}\)

\(k=\frac{2.303}{60}\log\frac{100}{64}\)

\(k=0.0074min^{-1}\)

b) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

\(t_{\frac{1}{2}}=\frac{0.693}{k}\)

\(t_{\frac{1}{2}}=\frac{0.693}{0.0074min^{-1}}=93min\)

The half-life of the compound is 93 minutes

Answer:

There are

Explanation:

There are 10 elements in CH3CH2COONa.

The electrons move from left to right through the circle labeled "M" to reach the cathode, where reduction takes place.

If oxidation occurs on the left side of the fuel cell and reduction occurs on the right side, the movement of electrons can be described as follows: Electrons move from left to right through the circle labeled "M."

In a fuel cell, the process of oxidation takes place at the anode (labeled A) where the fuel is oxidized, releasing electrons. These electrons then flow through the external electrical circuit, represented by the wire connecting objects A and B. The electrons reach the cathode (also labeled A) on the right side of the cell, where reduction occurs.The circle labeled "M" represents the membrane or electrolyte in the fuel cell. This membrane allows the transport of ions but blocks the movement of electrons. As a result, electrons cannot flow directly through the electrolyte but must travel through the external circuit.

This movement of electrons through the external circuit is what generates an electric current that can be used to power electrical devices or systems.

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Answer:

Explanation:

Here, we want to get the limiting reagent

The limiting reagent will be the reactant that produces less amount of the product

This is indicated by the number of moles of the product each of the reactant produce. The reactant that produces less product in terms of the number of moles is the limiting reactant.

The atomic mass of sulfur is 32 amu, while the molar mass of the oxygen molecule is 32 g/mol

To get the number of moles, we divide the mass by the molar mass/atomic mass

6.3g S translates to:

6.3/32 = 0.196875 mol

From the equation of reaction,

2 moles S gave 2 mol SO3

That means 0.196785 mol S will give 0.196785 mol SO3

Let us get for oxygen

10g of O2 will translate to:

10/32 = 0.3125 mol

From the equation of reaction:

3 mol O2 gave 2 mol SO3

0.3125 mol O2 will give: (0.3125*2)/3 = 0.2083 mol

As we can see, O2 gave the higher number of moles

This makes SO2 the limiting reactant

The process by which the molecules of the gas can be able to move is the process of diffusion.

We know that according to the Graham's law, the rate of the diffusion  of the gas is inversely proportional to the molar mass of the gas. When we open the bottles, the molecules of the perfume would begin to move.

As the bottle is opened, the molecules would escape from the bottle and then be able to travel through the room and get to where you are by the principle of diffusion.

Hence, the movement of the perfume is according to the Graham's law of diffusion in gases.

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The value of Kc for the given reaction is 0.0579 (rounded to four decimal places).

The formula for the equilibrium constant, Kc, of a reaction is given by the ratio of the product of the concentrations of the products raised to their respective stoichiometric coefficients to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

The stoichiometric coefficients are the coefficients in the balanced chemical equation.

To determine the value of Kc for the reaction given by the following chemical equation:N2(g) + 3 H2(g) ⇌ 2 NH3(g)

we first need to write the expression for Kc.

The expression for Kc is given by the following formula:Kc = [NH3]² / [N2][H2]³.

We are given the equilibrium concentrations as follows:[N2]eq = 2.66 M[H2]eq = 0.64 M[NH3]eq = 3.34 M

We can substitute these values into the expression for Kc and obtain the following:Kc = (3.34)² / (2.66)(0.64)³ = 0.0579 (rounded to four decimal places).

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Answer:

the answer is C ( i hope your teacher explains

Answer:

45 degrees at 29 so 105 is lower than 45 and 105 wants to be 32 so 45 can be higher. so then the water vapor will be 35 because 105 is too much of water gallon

Hi there!

\(\large\boxed{4.04g}\)

To solve, we can use dimensional analysis to convert from molecules to grams.

We must use Avogadro's number (6.02 × 10²³) in converting from molecules to moles.

After converting, multiply by the atomic mass, or grams per mole.

\(1.204 * 10^{24} moles *\frac{1 mol}{6.02*10^{23}moles}* \frac{2.02g}{1mol }= 4.04g\)

Answer:

increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object would make the oppositely charged objects attract each other more.

Answer:

in all green plants and most algae

Hope it helps you ... ...

Answer:

A. PbI2(s) ===> Pb2+(aq) + 2I-(aq)

B. Ksp = [Pb2+][I-]^2

C. 1.52 x 10^-3 M. It is equal to the moles/L of PbI2 that go into solution.

D. 2 x 1.52 x 10^-3 = 3.04 x 10^-3 M

E. Ksp = (1.52x10^-3)(2.31x10^-6) = 3.51 x 10^-9

Explanation:

In the given question, \(\rm PbI_2(s) \rightleftharpoons Pb^{2+}(aq) + 2I^-(aq)\) is the dissolution reaction of \(\rm PbI_2\) in water,   \(\rm Ksp = [Pb^{2+}][I^-]^2\) is expression for Ksp for \(\rm PbI_2\),  \(1.52\times 10^{-3 }\) mol/L is the concentration of \(\rm Pb^{2+ }\) in the equilibrium solution,  \(3.04\times 10^{-3}\) mol/L is the concentration of I- in the equilibrium solution and

\(1.40\times 10^{-8}\) is the solubility product of  \(\rm PbI_2\), respectively.

A reaction is a process that involves the transformation of one or more substances into one or more different substances.

1. The dissolution reaction of \(\rm PbI_2\) in water is:

\(\rm PbI_2(s) \rightleftharpoons Pb^{2+}(aq) + 2I^-(aq)\)

2. The expression for Ksp for \(\rm PbI_2\) is:

 \(\rm Ksp = [Pb^{2+}][I^-]^2\)

Where, \(\rm [Pb^{2+}]\) is the concentration of \(\rm Pb^{2+ }\) ions in solution and \(\rm [I^-]\) is the concentration of \(\rm I^-\) ions in solution.

3. The solubility of  \(\rm PbI_2\) is \(1.52\times 10^{-3 }\) mol/L. Since \(\rm PbI_2\) dissociates into one  \(\rm Pb^{2+ }\) ion and two \(\rm I^-\) ions, the concentration of  \(\rm Pb^{2+ }\) in solution is equal to the solubility of  \(\rm PbI_2\), which is \(1.52\times 10^{-3 }\) mol/L.

\(\rm [Pb^{2+}] = 1.52\times 10^{-3}\ mol/L\)

4. Since  \(\rm PbI_2\) dissociates into one \(\rm Pb^{2+ }\) ion and two  \(\rm I^-\) ions, the concentration of  \(\rm I^-\) ions in solution is twice the solubility of  \(\rm PbI_2\) .

\(\rm [I^-] = 2 \times 1.52\times 10^{-3 }\ mol/L\)

= \(3.04\times 10^{-3}\) mol/L

5. The solubility product of  \(\rm PbI_2\) can be calculated using the expression for Ksp and the concentrations of \(\rm Pb^{2+ }\) and  \(\rm I^-\) ions in solution.

\(\rm Ksp = [Pb^{2+}][I^-]^2\)

=  \(1.52\times 10^{-3 }\)  \(\times\) \(\rm (3.04\times 10^{-3} mol/L)^2\)

= \(1.40\times 10^{-8}\)

Therefore, the dissolution reaction of \(\rm PbI_2\) in water, expression for Ksp for \(\rm PbI_2\), the concentration of Pb2+ in the equilibrium solution, the concentration of I- in the equilibrium solution and solubility product of  \(\rm PbI_2\) is mentioned above.

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when a chemical change is complete the reactant before the chemical reaction and the product after the chemical reactant will weigh same.

According to the law of mass of conservation : the mass in the chemical reaction is neither be created nor be destroyed. This means the the total mass of the reactant before the chemical reaction and the mass of the product after the reaction is same. we can say that atoms in the reactant side is equal to the atoms in the product side.

Thus, when a chemical change is complete the reactant before the chemical reaction and the product after the chemical reactant will weigh same.

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Answer:

D. 13.44 dm³

Explanation:

Step 1: Write the balanced equation

CuO + H₂ ⇒ Cu + H₂O

Step 2: Calculate the mass corresponding to 47.7 g of CuO

The molar mass of CuO is 79.55 g/mol.

47.7 g × (1 mol/79.55 g) = 0.600 mol

Step 3: Calculate the moles of H₂ that react with 0.600 mol of CuO

The molar ratio of CuO to H₂ is 1:1. The moles of H₂ are 1/1 × 0.600 mol = 0.600 mol.

Step 4: Calculate the volume of 0.600 moles of H₂ at STP

1 mol of any gas at STP has a volume of 22.4 dm³.

0.600 mol × (22.4 dm³/1 mol) = 13.44 dm³

Answer

CO2 = 494 mmHg

H2 = 190 mmHg

HCl = 41.04 mmHg

HF = 21.28 mmHg

SO2 = 12.92

H2S = 0.76 mmHg

Explanation

Given:

Composition in mole percent of the gases are:

65% CO2, 25% H2, 5.4% HCl, 2.8% HF, 1.7 % SO2 and 0.1% H2S.

The total pressure of the volcanic gas = 760 mmHg

What to find:

The partial pressure of each of these gases.

Solution:

The partial pressure of each of the gases can be calculated using the % composition and the total pressure.

For 65% CO2

Its partial pressure = (65/100) x 760 mmHg = 494 mmHg

For 25% H2

Its partial pressure = (25/100) x 760 mmHg = 190 mmHg

For 5.4% HCl

Its partial pressure = (5.4/100) x 760 mmHg = 41.04 mmHg

For 2.8% HF2

Its partial pressure = (2.8/100) x 760 mmHg = 21.28 mmHg

For 1.7% SO2

Its partial pressure = (1.7/100) x 760 mmHg = 12.92 mmHg

For 0.1% H2S

Its partial pressure = (0.1/100) x 760 mmHg = 0.76 mmHg

Answer

A. More H⁺ and HCO₃⁻ would be produced.

Explanation

A solution of carbonic acid, H₂CO3(aq), at equilibrium is represented as shown below:

H₂CO₃(aq) ⇌ H⁺ (aq) + HCO₃⁻(aq)

The addition of more carbonic acid to the solution will shift the system to the right; that is, more H⁺ and HCO₃⁻ would be produced.

The amount of energy that is required to change 20.0 g of an unknown substance from -15.0 °C to 7.0 °C is q = +49.65 kJ.

Energy is the ability to do tasks. It can exist in various forms, including potential, kinetic, thermal, electrical, chemical, and nuclear.

At -15°c, it will be solid, to increase the amount of heat to raise

temp from -15°C to 40°C.

(20.0) (3.3J/g°c) x 15°C) = 330 J.

At -10°C, it is in which phase transformation takes place from sold to wound.

ΔHfue = 0.945 J/gx 20g = 18.93.

After that, it will be in want and it will be in liquid form 40°C.

To 7°C, then.

922 m Cgas 47

=(20g) (1455/g°c) (17)

493005.

Total Energy = q1 + ΔHfus  + q2

47 = 7.0°C - 10°C) = 14°C -

2 330J18.95 + 49300J

q = 49648.9 3. 9

q = +49.65 KJ

Therefore, the amount of energy is q = +49.65 KJ.

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