What is the mass in grams of 8 moles of Cu?

Answer:

Covalent Molecule

Explanation:

Answer:

0.15 M KCl

Explanation:

(Step 1)

Convert the original volume from mL to L. Calculate the moles of the original solution.

75.0 mL / 1,000 = 0.0750 L

Molarity = moles / volume (L)

0.200 M = moles / 0.0750 L

0.0150 = moles

(Step 2)

Convert the final volume from mL to L. Calculate the final molarity.

100. mL / 1,000 = 0.100 L

Molarity = moles / volume (L)

Molarity = 0.0150 moles / 0.100 L

Molarity = 0.15 M

The claim that cold water boils faster than hot water is not true. The reason why this misconception may have emerged is likely due to a misunderstanding or misinterpretation of certain observations. However, there is no scientific evidence supporting this claim.

One possible reason for this misconception is the notion that hot water takes longer to reach its boiling point because it starts at a higher temperature. When comparing hot and cold water in terms of reaching the boiling point from room temperature, the cold water may appear to boil faster.

However, this is simply because the hot water has already gained a head start in terms of temperature. In reality, once both liquids reach their respective boiling points, the hot water will boil first.

Scientifically, the boiling point of water is determined by its temperature and pressure. Under normal atmospheric conditions, the boiling point of water is 100 degrees Celsius (212 degrees Fahrenheit). Heating water raises its temperature, and once it reaches 100 degrees Celsius, it transitions into the gaseous state. The initial temperature of the water does not affect the boiling point itself.

In conclusion, the claim that cold water boils faster than hot water is a misconception. It likely arose from a misinterpretation of observations, and there is no scientific evidence to support this claim. The boiling point of water is solely determined by its temperature and pressure, regardless of whether the water is initially hot or cold.

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When two solutions are mixed, the concentration of the resulting solution will depend on the volumes and concentrations of the two original solutions.

The final concentration can be calculated using the following formula:

Cfinal = (C1V1 + C2V2) / (V1 + V2)

where C1 and C2 are the concentrations of the two solutions, V1 and V2 are their volumes, and Cfinal is the concentration of the final solution.

In this case, one solution has a concentration of 2.00 M, and the other has a concentration of 4.00 M. Let's assume that we have much more of the 4.00 M solution, and that we mix 100 mL of the 2.00 M solution with 400 mL of the 4.00 M solution. We can calculate the resulting concentration of the mixed solution as follows:

Cfinal = (2.00 M x 100 mL + 4.00 M x 400 mL) / (100 mL + 400 mL) = 3.20 M

Therefore, a possible concentration of the final solution is 3.20 M. The actual concentration of the mixed solution will depend on the volumes and concentrations of the original solutions used.

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Complete Question

You are given a solution containing a pair of enantiomers (A and B). Careful measurements show that the solution contains 98% A and 2% B. What is the enantiomeric excess?

Answer:

The value is  \(k  = 96 %\)

Explanation:

From the question we are told that

   The  percentage of  enantiomer A is  A =  98%

    The  percentage of  enantiomer B is  B =  2%

Generally the enantiomeric excess is mathematically represented as

      \(k  =  \frac{A -B}{A+B}  *  100\)

=>   \(k  =  \frac{98 -2}{98+2}  *  100\)

=>   \(k  = 96 %\)

Answer:

The answer is

Explanation:

Density = mass / volume

mass = density × volume

volume = 2cm³

density = 520g/cm³

mass = 2 × 520

= 1040g

Hope this helps you

Cicadas are known for their broadly spaced, pronounced eyes, and short antennae.

While annual cicadas are widespread, periodicals are only found in North America. In the middle and eastern parts of the country, there are mostly periodic broods, and in some places, there are multiple broods.

Adult cicadas are black in color with green or orange-brown markings, and they have wingspans of 1 to 2 inches. They have clear wings with orange veins and big, black or red eyes. Nymphs resemble their adult counterparts in appearance, although they lack wings and are not as vividly colored.

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Answer:

It released hydroxide ions (OH ¯).

Explanation:

A PH of 8.3 indicates that the solution has become a basic solution.

Now, for us to have a basic solution from the addition of an alka-seltzer to Koolaid, it means the Alka-seltzer released plenty of hydroxide ons (OH¯) to the solution.

Answer:

that they all dissolved went on watef

Answer:

hope this helpful for u

Explanation:

4°celsius

Yes, when an alkane reacts with a halogen, the reaction that occurs is a substitution reaction.

In this type of reaction, the halogen atom replaces a hydrogen atom in the alkane structure. The halogenated compound formed in this reaction is known as a halogenated hydrocarbon. This type of reaction is also known as halogenation.

The halogenation reaction can be carried out using a variety of methods, such as direct halogenation, radical halogenation, and electrophilic halogenation. The method used depends on the nature of the reactants and the desired product.

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The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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Answer:

Option C . CO2(g) + H2O(g)

Explanation:

When hydrocarbon undergoes combustion, carbon dioxide (CO2) and water (H2O) are produced.

C2H4(g) + O2(g) —› CO2(g) + H2O(g)

Thus, the product of the unbalanced combustion reaction is:

CO2(g) + H2O(g)

Thus, we can balance the equation as follow:

C2H4(g) + O2(g) —› CO2(g) + H2O(g)

There are 2 atoms of C on the left side and 1 atom on the right side. It can be balanced by putting 2 in front of CO2 as shown below:

C2H4(g) + O2(g) —› 2CO2(g) + H2O(g)

There are 4 atoms of H on the left side and 2 atoms on the right side. It can be balanced by putting 2 in front of H2O as shown below:

C2H4(g) + O2(g) —› 2CO2(g) + 2H2O(g)

There are a total of 6 atoms of O on the right side and 2 atom on the left side. It can be balanced by putting 3 in front of O2 as shown below:

C2H4(g) + 3O2(g) —› 2CO2(g) + 2H2O(g)

Thus, the equation is balanced.

Answer:

3 RbOH + H₃PO₄ → Rb₃PO₄ + 3 H₂O

Explanation:

Let's consider the double-replacement reaction between rubidium hydroxide and phosphoric acid to form rubidium phosphate and water. The cation rubidium replaces the cation hydrogen and the anion hydroxyl replaces the anion phosphate. The balanced chemical reaction is:

3 RbOH + H₃PO₄ → Rb₃PO₄ + 3 H₂O

Answer:

1-water 2-Sun 3-Gravity

The compound that is shown as X can be seen in the option labelled C

The process of esterification involves the condensation of an alcohol (or phenol) with an acid to produce an ester. To create the ester bond, the water molecule must be removed from the alcohol and acid (dehydration).

Usually, an acid catalyst is used to catalyze the reaction, which makes it easier to remove water and encourages the creation of the ester. The acid catalyst aids in protonating the acid's carbonyl oxygen, which increases its electrophilicity and makes it more vulnerable to alcohol's nucleophilic attack.

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Carbon contains four electrons in its outer shell

No, a 1.5 M solution cannot be made from a 0.98 M solution.

Explain molarity

Probably the most frequently used unit of measurement for solution concentration is molarity, abbreviated as (M). The ratio of the number of liters of solution to the number of moles of solvent is known as molarity.

Knowing the molarity (M) of the solution of a specific volume will allow you to calculate the number of moles (n) of a chemical dissolved in a solution (V). The quantity of solvent moles per kilogram is known as molality, which is a property of solutions. Since molality solely depends on the masses of the solute and solvent, which are unaffected by changes in temperature and pressure, it is a particularly advantageous way to estimate concentration.

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Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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Answer:

In an acid-base reaction, the base always receives the H+.

Explanation:

Answer:

It travel's about 4,000 km through the Earth in 13 minutes.

Answer:

4,000 km is the correct answer!!!

Answer:

Temperature, concentration, and a catalyst can all affect the rate of a chemical reaction.

Temperature: Increasing the temperature generally increases the rate of a reaction. This is because higher temperatures provide more kinetic energy to the reactant particles, causing them to move faster and collide more frequently. With increased collision frequency, the chances of successful collisions with sufficient energy to overcome the activation energy barrier and proceed with the reaction are also increased. As a result, the reaction rate typically increases with temperature.

Concentration: Increasing the concentration of reactants generally increases the rate of a reaction. When the concentration of reactant particles is higher, they become more crowded, increasing the likelihood of collisions between reactant particles. With more collisions occurring, there is a higher probability of successful collisions leading to a reaction. Therefore, higher reactant concentrations generally result in a higher reaction rate.

Catalyst: A catalyst is a substance that increases the rate of a reaction by providing an alternative reaction pathway with a lower activation energy. Catalysts themselves are not consumed during the reaction and do not undergo any permanent changes. They work by providing an alternative route that requires less energy for the reactants to reach the transition state. This lowers the activation energy barrier, making it easier for the reaction to occur. By providing an alternative pathway, catalysts increase the rate of reaction without being consumed in the process.

Regarding collision theory, the three key points required for a reaction to happen are:

Collision: Reactant particles must collide with each other for a reaction to occur. Collisions bring the reactant particles in close proximity, allowing them to interact and potentially form new chemical bonds.

Energy: Colliding particles must possess enough energy, equal to or greater than the activation energy, for the reaction to take place. Activation energy is the minimum energy required for the reactant particles to break existing bonds and initiate the formation of new bonds. Only collisions with sufficient energy can overcome the activation energy barrier and lead to a reaction.

Orientation: In addition to sufficient energy, the collision between reactant particles must occur with the correct orientation. This means that the particles must collide in a way that allows the necessary atoms or groups to come into contact and form new bonds. If the collision occurs with an incorrect orientation, the particles may simply bounce off each other without any reaction taking place.

In summary, according to collision theory, for a reaction to happen, reactant particles must collide with sufficient energy and the correct orientation. Temperature and concentration affect the rate of reaction by influencing collision frequency, while a catalyst provides an alternative reaction pathway with lower activation energy.

The number of electrons present in the p orbitals in the outermost electron shell of the halogen atoms depends on the element.

Halogens are a group of chemical elements consisting of fluorine, chlorine, bromine, iodine, and astatine. They are all highly reactive and are found in a variety of compounds. Halogens are used in a wide range of applications from household cleaning products to industrial processes.

The number of electrons present in the p orbitals in the outermost electron shell of the halogen atoms is

For Fluorine (F): 2 electrons in the 2p orbital

For Chlorine (Cl): 6 electrons in the 3p orbital

For Bromine (Br): 10 electrons in the 4p orbital

For Iodine (I): 14 electrons in the 5p orbital

For Astatine (At): 18 electrons in the 6p orbital

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Paramecia sweep food into mouthlike openings and a pine tree carriers out photosynthesis. These describe a way that an other-feeder gets food. The correct option is option B,D.

Filter feeders are a subclass of animals that eat by sifting food particles and suspended materials from water, often by running the water through a specially designed filtering apparatus. Baleen whales, clams, krill, sponges, various fish (including some sharks), and krill are just a few species that adopt this technique of eating. Paramecia sweep food into mouthlike openings and a pine tree carriers out photosynthesis. These describe a way that an other-feeder gets food.

Therefore, the correct option is option B,D.

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Answer:

its shorter than a regular one

Explanation:

the only reason is simply because it is shorter

Answer:

C in motion

Explanation:

trust