What is the measure of arc ADC if the measure of arc BC is 52 degrees

The values of the given expression having exponent with negative fractional base i.e. \(-2^{(3/2)^2}\\\) is evaluated out to be 16/9.

First, we need to simplify the expression inside the parentheses using the rule that says "exponents with negative fractional base can be rewritten as a fraction with positive numerator."

\(-2^{(3/2)^2}\) = (-2)² × (2/3)²

Now, we can simplify the expression  further by solving the exponent of (-2)² and (2/3)²:

(-2)² × (2/3)² = 4 × 4/9 = 16/9

Therefore, the value of the given expression \(-2^{(3/2)^2}\\\)  is 16/9.

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The question is :

What is the value of the expression \(-2^{(3/2)^2}\) ?

The other endpoint of the line segment with the given endpoint and midpoint is (19, 15).

To find the other endpoint of the line segment, we can use the midpoint formula. The midpoint of a line segment is the average of the coordinates of the two endpoints. We can use this information to set up the following system of equations:

x_mid = (x₁ + x₂) / 2

y_mid = (y₁ + y₂) / 2

where (x_mid, y_mid) is the midpoint and (x₁, y₁) and (x₂, y₂) are the two endpoints.

Substituting the given values, we get:

6 = (-7 + x₂) / 2

7 = (-1 + y₂) / 2

Solve for x₂ and y₂.

12 = (-7 + x₂)

x₂ = 19

14 = (-1 + y₂)

y₂ = 15

Therefore, the other endpoint is (x₂, y₂) = (19, 15).

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Using Pythagorean Theorem, the length of the line segment from (-3, 10) to (4, -1) is 13 units.

Pythagorean theorem describes the relationship between the sides of a right triangle. It states that the square of the hypotenuse is equal to the sum of the squares of the two other side.

c² = a² + b²

Let a = vertical distance between the two points

b = horizontal distance between the two points

c = distance between the two points / length of line segment

Hence, c² = (|y₂ - y₁|)² + (|x₂ - x₁|)².

Substitute the values of x and y and solve for c.

c² = (|y₂ - y₁|)² + (|x₂ - x₁|)²

c² = (|-1 - 10|)² + (|4 - -3|)²

c² = (|-11|)² + (|7|)²

c² = 11² + 7²

c² = 121 + 49

c² = 170

c = 13.04

length of line segment ≅ 13 units

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Using the sine ratio, the length of the missing side is: 11.8.

The sine ratio is, sin ∅ = opposite/hypotenuse.

Given the following:

∅ = 24°

Opposite = x

Hypotenuse = 29

sin 24 = x/29

x = (sin 24)(29)

x = 11.8

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Answer:

=√100

= 10

=√49

= 7

=√144

= 12

=√9

=3

The minimum number amount of light energy that can exist in Hasbrouck 20 is zero due to the divisibility of light.

According to quantum theory, light is composed of particles called photons. Each photon carries a certain amount of energy, which is directly proportional to its frequency.

However, the size of the lecture hall being 9 m across does not impose any constraints on the minimum amount of light energy. In the quantum realm, light can be continuously divided, and there is no lower limit to the amount of light energy that can exist.

Therefore, the minimum amount of light energy in Hasbrouck 20 is considered to be zero.

This implies that arbitrarily small quantities of light can exist, and the division of light energy can continue indefinitely.

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Let X be the amount of money that you win, and you play the game by tossing a biased coin. In this case, the probability of getting heads is 0.9, and the probability of getting tails is 0.1.

Suppose you win 2 dollars when you get a head and 3 dollars when you get a tail.

Now, we can calculate the probability distribution of X as follows:

X                         P(X)               Money  Won

Head                     0.9                    $2Tail                       0.1                    $3

The above table shows the probability distribution of X, where P(X) is the probability of getting X amount of money. Therefore, this is the probability distribution of X:

X              P(X)                 Money  Won

Head        0.9                  $2Tail          0.1                  $3

Hence, we have completed the probability distribution of X.

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The power to which a number or expression is raised is called the exponent.

1. An exponent is a mathematical notation that represents the power to which a number or expression is raised. It is written as a superscript number or variable placed above and to the right of the base number or expression.

2. The base number or expression is the number or expression that is being multiplied repeatedly by itself, raised to the power of the exponent.

3. The exponent tells us how many times the base number or expression should be multiplied by itself. For example, in the expression \(2^3\), the base is 2 and the exponent is 3. This means that 2 should be multiplied by itself three times: 2 * 2 * 2 = 8.

4. The exponent can be a positive whole number, a negative number, zero, or a fraction. Each of these cases has different interpretations:

  - Positive exponent: Indicates repeated multiplication. For example, \(2^4\)means 2 multiplied by itself four times.

  - Negative exponent: Indicates the reciprocal of the base raised to the positive exponent. For example, \(2^{-3\) means 1 divided by \(2^3\).

  - Zero exponent: Always equals 1. For example, \(2^0\) = 1.

  - Fractional exponent: Represents a root. For example, \(4^{(1/2)\)represents the square root of 4.

5. Exponents follow certain mathematical properties, such as the product rule \((a^m * a^n = a^{(m+n)})\), the quotient rule \((a^m / a^n = a^{(m-n)})\), and the power rule \(((a^m)^n = a^{(m*n)})\).

Remember to use these rules and definitions to correctly interpret and evaluate expressions involving exponents.

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Examining the functions the end behavior is

The end behavior of function typically says the characteristics of the function at the ends

The given function when examined shows that:

m(x) = -8x +10. has a negative leading coefficient; hence

x ⇒ ∞ m(x) ⇒ -∞: as x tends to positive infinity the function tends to negative infinity

x ⇒ -∞ m(x) ⇒ ∞: as x tends to negative infinity the function tends to positive infinity

n(x) = 5x^2 - 9. has a positive leading coefficient; hence

x ⇒ ∞ n(x) ⇒ ∞: as x tends to positive infinity the function tends to positive infinity

x ⇒ -∞ m(x) ⇒ -∞: as x tends to negative infinity the function tends to negative infinity

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Answer:

yes, the following is a function

Subtraction property of equality

====================================================

Explanation:

Let's say we started with the equation a = b

Subtract c from both sides to get a-c = b-c

This is the subtraction property of equality

-----------------

Example:

x+5 = 12

x+5-5 = 12-5 ... using the subtraction property of equality

x+0 = 7

x = 7

------------------

For this current problem, we're subtracting 3 from both sides in the second step.

A very closely related property is the addition property of equality where we add the same thing to both sides.

Technically we could add -3 to both sides to get the same task done in the second step. But the subtraction property is more direct and straight-forward in my opinion.

Z and W are not independent, because  fZ(Z) × fW(W) is not equal to f(Z, W).

To obtain the joint pdf of Z and W, we need to transform the variables (X, Y) to (Z, W) using the following equations:

Z = sqrt(X^2 + Y^2)

W = arctan(Y/X)

The inverse transformation equations are:

X = Z×cos(W)

Y = Z×sin(W)

To compute the Jacobian transformation, we need the partial derivatives of X and Y with respect to Z and W:

dx/dZ = cos(W)

dx/dW = -Z×sin(W)

dy/dZ = sin(W)

dy/dW = Z×cos(W)

The Jacobian determinant is then:

|J| = dx/dZ × dy/dW - dy/dZ × dx/dW = Z

The joint pdf of Z and W can be obtained using the transformation formula:

f(Z, W) = f(X, Y) × |J| = (1/pi) × Z, for 0 ≤ Z ≤ 1 and -π/2 ≤ W ≤ π/2

To check if Z and W are independent, we need to compute their marginal pdfs:

fZ(Z) = ∫f(Z, W) dW = ∫(1/pi)×Z dW = Z/pi, for 0 ≤ Z ≤ 1

fW(W) = ∫f(Z, W) dZ = ∫(1/pi)Z dZ, from Zsin(W) ≤ X ≤ Z×cos(W) and Z ≥ 0

The integration limits for Z are determined by the circle equation X^2 + Y^2 ≤ 1, which can be expressed as Z ≤ 1.

fW(W) = (1/pi)×sin(W)×∫Z^2 dZ - (1/pi)×cos(W)×∫Z^2 dZ

fW(W) = (1/3)×sin(W) - (1/3)×cos(W) = (1/3)×sqrt(2)×sin(W - π/4)

The product of the marginal pdfs is:

fZ(Z)×fW(W) = (1/3)Zsqrt(2)×sin(W - π/4), for 0 ≤ Z ≤ 1 and -π/2 ≤ W ≤ π/2

This product is not equal to f(Z, W), which means that Z and W are not independent.

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The given question is incomplete, the complete question is:

The joint density of X and Y is f(x, y) = 1/pi, x^2 + y^2 less than or equal to 1 Obtain the joint pdf of Z = square root X^2 + Y^2 W = tan^-(Y/X) Are Z and W independent? Provide the proof.

The probability of 1 red is 0.79, which can also be expressed as 79/100.

To find the probability of drawing one red marble, we need to calculate the sum of the frequencies for the outcomes that involve at least one red marble.

From the given table:

- The outcome "Red, Red" occurred 19 times.

- The outcome "Red, Blue" occurred 32 times.

- The outcome "Blue, Red" occurred 28 times.

Adding up these frequencies, we get:

Frequency of at least one red marble = 19 + 32 + 28 = 79

The total number of experiments conducted is given as 100.

Therefore, the probability of drawing one red marble is:

P(1 red) = Frequency of at least one red marble / Total experiments

= 79 / 100

= 0.79

So, P(1 red) is 0.79, which can also be expressed as 79/100.

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The y - intercept indicates if hours spent on video games is zero, then the total hours spent on homework will be 23.

Given is the graph shows the relationship between hours spent on video games and hours spent on homework last week for students in Joyce's class.

The y - intercept indicates that if hours spent on video games is zero, then the total hours spent on homework will be 23.

Therefore, the y - intercept indicates if hours spent on video games is zero, then the total hours spent on homework will be 23.

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Answer:

5 ,a lot

Step-by-step explanation:

1683.5

To minimize the number of bulbs that burn out during operating hours, all bulbs are replaced at once. How often should the bulbs be replaced so that only 1% burn out between replacement periods?The given normal distribution has a mean of 1800 hours and a standard deviation of 50 hours. We need to find out how often the bulbs should be replaced so that only 1% of them burn out between replacement periods. The probability that a bulb will burn out during one replacement period can be given by the probability that a bulb will burn out in less than x hours, where x is the number of hours for which a bulb is used before it is replaced.P(burn out during one replacement period) = P(burn out in less than x hours)where x is the number of hours a bulb is used before it is replaced. Using the standard normal distribution table, we can determine the value of z such that P(Z < z) = 0.01, where Z is the standard normal random variable.If we use the normal distribution, the probability that a bulb will burn out in less than x hours is given by:P(burn out in less than x hours) = P(Z < (x - µ)/σ)where µ = 1800 and σ = 50Given P(burn out during one replacement period) = 0.01P(Z < (x - µ)/σ) = 0.01⇒ (x - µ)/σ = -2.33⇒ x - µ = -116.5⇒ x = µ - 116.5 = 1683.5Therefore, the bulbs should be replaced every 1683.5 hours so that only 1% of them burn out between replacement periods. The answer is 1683.5.

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Answer:

uh what is this address for or am i not supposed to be in this

Step-by-step explanation:

sorry if im getting in your buisness

Data distributions are essential to analytics because they provide a way to summarize and understand the behavior of data. To test whether data are normally distributed, analysts can use the Shapiro-Wilk test

By identifying the distribution of data, analysts can make informed decisions about modeling, hypothesis testing, and prediction. Distributions are commonly used in analysis to assess data quality, detect outliers, and select appropriate statistical methods.

To identify appropriate sample distributions, analysts can use visual inspection of histograms or density plots. To test whether sample data match the data generating process, analysts can use goodness-of-fit tests such as the chi-square test or the Kolmogorov-Smirnov test.

To test whether data are normally distributed, analysts can use the Shapiro-Wilk test, which tests the null hypothesis that the data come from a normal distribution. In R, the function shapiro.test() can be used to perform the test. Another common approach is to use visual inspection of a normal probability plot.

Overall, understanding and testing data distributions is essential for accurate and reliable analysis in business settings.

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The pail was pale because it was most likely made from a light-coloured material such as plastic or metal.

It is not clear why the pail was pale. The phrase "the pail was pale" does not make sense in the context of the properties of a pail. Pails are typically made of metal, plastic, or some other type of material and do not have a color or shade.

It is possible that you meant to ask a different question or that the phrase "the pail was pale" was intended as a joke or a play on words. Without more context, it is not possible to provide a meaningful answer.

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The area under the curve is \(\frac{6 \sqrt{3}}{5}\).

Consider the following parametric equations:\($$x=t^2-3 t \text { and } y=\sqrt{t} \text { and the } y \text {-axis. }$$\)

The objective is to find area enclosed by the curve using the formula.

The area under the curve is given by parametric equations x=f(t), y=g(t),  and is traversed once as t increases from α to β, then the formula for calculating the area under the curve:

\($$A=\int_\alpha^\beta g(t) f^{\prime}(t) d t$$\)

The curve has intersects with y-axis. so x=0

\($$\begin{aligned}t^2-3 t & =0 \\t(t-3) & =0 \\t & =0 \text { or } t=3\end{aligned}$$\)

Now we have to draw the graph,

Let f(t)=\(t^2-3 t, g(t)=\sqrt{t}$\)

Differentiate the curve f(t) with respect to t.

\(f^{\prime}(t)=2 t-3\)

Now, find the area under the curve use the above formula.

\(\begin{aligned}A & =\int_0^3(\sqrt{t})(2 t-3) d t \\& =\int_0^3(2 t \sqrt{t}-3 \sqrt{t}) d t \\& =\int_0^3\left(2 t^{\frac{3}{2}}-3 t^{\frac{1}{2}}\right) d t \\& =\left[2 \frac{t^{\frac{5}{2}}}{\frac{5}{2}}-3 \frac{t^{\frac{3}{2}}}{\frac{3}{2}}\right]_0^3 \\& \left.\left.=\left[\frac{4 t^{\frac{5}{2}}}{5}-2 t^{\frac{3}{2}}\right]_0^3\right]^{\frac{5}{2}}\right] \\\\\end{aligned}$$\)

\(& =\left[\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}\right]-\left[\frac{4(0)^{\frac{5}{2}}}{5}-2(0)^{\frac{3}{2}}\right]\)

\($\begin{aligned}& =\left[\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}\right]-\left[\frac{4(0)^{\frac{5}{2}}}{5}-2(0)^{\frac{3}{2}}\right] \\& =\frac{4(3)^{\frac{5}{2}}}{5}-2(3)^{\frac{3}{2}}-0 \\& =\frac{6 \sqrt{3}}{5}\end{aligned}\)

Therefore,  the area of the curve is \(\frac{6 \sqrt{3}}{5}\).

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Answer:

1

Step-by-step explanation:

m [slope] = ∆y/∆x = y₂-y₁/x₂-x₁

m [slope] = 9 - 6 / 4 - 1 = 3 / 3 = 1

The equation for this relationship is

y = x + 5

Answer:

n=-0.425

Step-by-step explanation:

subtract 16.2 from both sides. divide 8 from both sides

Answer:

N= -1.825

Step-by-step explanation:

First, we must isolate the variable. So we can write 8N+16.2=1.6. Let's subtract 16.2 from both sides of the equal sign. So now we have 8N=-14.6. Now we have to only get N, so we must divide every side by 8. We do this to cancel out the 8 multiplying the N. We get N= -1.825. This is your answer!

I hope this helped you solve this problem and help you solve future problems!

The tangent ratio is used to solve for a missing angle in a right triangle by dividing the length of the side opposite the angle by the length of the side adjacent to the angle.

Using the tangent ratio, we can find a missing angle in a right triangle by taking the inverse tangent (arctan) of the ratio. For example, if we know the length of the side opposite an angle and the length of the side adjacent to the angle, we can use the tangent ratio to find the value of the angle.

Using the cotangent ratio, we can also find a missing angle in a right triangle by taking the inverse cotangent (arccot) of the ratio. If we know the length of the side adjacent to an angle and the length of the side opposite the angle, we can use the cotangent ratio to find the value of the angle.

The main difference between using the tangent ratio and the cotangent ratio is the order of the sides in the ratio. The tangent ratio involves the opposite side divided by the adjacent side, while the cotangent ratio involves the adjacent side divided by the opposite side.

Both the tangent and cotangent ratios are useful tools for solving right triangles and finding missing angles. The choice between using one or the other depends on the given information and the specific problem at hand.

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The given two-way Frequency table, there are 33 left-handed students who are not in the music program.

The number of left-handed students who are not in the music program, we need to examine the data presented in the two-way frequency table.

From the table, we can see that the number of left-handed students in the music program is 15, and the total number of left-handed students is 48.

the number of left-handed students not in the music program, we subtract the number of left-handed students in the music program from the total number of left-handed students.

Number of left-handed students not in the music program = Total number of left-handed students - Number of left-handed students in the music program

Number of left-handed students not in the music program = 48 - 15

Calculating this, we find that the number of left-handed students not in the music program is 33.

Therefore, there are 33 left-handed students who are not in the music program, based on the data provided in the two-way frequency table.

In conclusion, based on the given two-way frequency table, there are 33 left-handed students who are not in the music program.

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To find the values of t that bound the middle 0.98 of the distribution for df = 22, we need to determine the two percentiles that correspond to the middle 0.98.

Using a t-table or statistical software, we can find the critical t-values associated with the degrees of freedom (df) and the desired confidence level. For df = 22 and a 90% confidence level, we find that the critical t-value is approximately 1.717.

To find the values that bound the middle 0.98 of the distribution, we subtract and add half of the remaining probability from the extreme values. Thus, the lower bound is -1.717 and the upper bound is 1.717.

For constructing a 90% confidence interval estimate for the mean using the given sample information, we need to consider the sample mean, sample standard deviation, sample size, and the t-value associated with the desired confidence level.

Without the given sample information, it is not possible to provide the specific confidence interval estimate. The interval estimate would typically be calculated as:

Confidence Interval = (sample mean) ± (t-value) * (standard deviation / sqrt(sample size))

However, with the sample information provided, we can't determine the specific values needed to calculate the confidence interval estimate.

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Answer:

15+24=39

42-39=3

she has 3 dollars left

Step-by-step explanation:

Here is the full question:

Triangle ABC is a right-triangle and sin(53o) = StartFraction 4 Over x EndFraction. Solve for x & round to the nearest whole number.

Triangle A B C is shown. Angle A C B is a right angle and angle B A C is 53 degrees. The length of B C is 4 centimeters, the length of A C is y, and the length of hypotenuse A B is x.

Which equation correctly use the value of x to represents the cosine of angle A?

cos(53o) = StartFraction 4 Over x EndFraction cos(53o) = StartFraction y Over 5 EndFraction cos(53o) = StartFraction x Over 4 EndFraction cos(53o) = StartFraction 5 Over y EndFraction

Answer:

cos(53°) = StartFraction y Over 5 EndFraction

Step-by-step explanation:

From the information above:

The sketch of the triangle is drawn and attached in the diagram below.

To find x using the sine rule,

We know that:

\(Sin \theta = \dfrac{opposite}{hypothenuse}\)

∴

\(Sin (53^0) = \dfrac{4}{x}\)

Making x the subject of the formula:

\(x = \dfrac{4}{Sin \ 53^0}\)

\(x = \dfrac{4}{0.7986}\)

\(x \simeq 5\)

Now, the equation that correctly uses the value of x can be determined by finding the cosine of ∠ A.

Recall that:

\(Cos \theta = \dfrac{adjacent}{hypothenuse}\)

\(Cos \ 53^0 = \dfrac{y}{x}\)

where; x = 5

\(Cos \ 53^0 = \dfrac{y}{5}\)

Thus, the equation that correctly uses the value of x to represent the cosine of angle A is:

cos(53°) = StartFraction y Over 5 EndFraction

Answer:

simple answer B

Step-by-step explanation: