What is the name of this compound?
S₂F10

Answers

Answer 1

Answer:

Disulfur decafluoride

Explanation:

Answer 2

Disulfur decafluoride is the correct answer.

What Is The Name Of This Compound?SF10

Related Questions

PLEASE HELP ASAP!

5 + 6 HNO3 -> H2504 + 6 NO2 + 2H20
In the above equation how many moles of water can be made when 112.6 grams of HNO3 are consumed?

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:


Hydrogen 1
Nitrogen 14
Sulfur 32
Oxygen 16

Answers

0.595 moles of water can be made at 112.6 grams of \(HNO_{3}\) are consumed

To determine the number of moles of water produced when 112.6 grams of \(HNO_{3}\) are consumed, we use the equation's stoichiometry and molar masses.

To determine the number of moles of water produced when 112.6 grams of \(HNO_{3}\) are consumed, we need to use the molar mass of \(HNO_{3}\) and the stoichiometric coefficients of the balanced chemical equation.

The molar mass of \(HNO_{3}\) is calculated as follows:

1 mole of hydrogen (H) = 1 g/mol

1 mole of nitrogen (N) = 14 g/mol

3 moles of oxygen (O) = 3 × 16 g/mol = 48 g/mol

Adding these together, the molar mass of \(HNO_{3}\) is 1 + 14 + 48 = 63 g/mol.

Now, we can set up a conversion factor using the stoichiometry of the balanced equation:

From the equation: 5 + 6 \(HNO_{3}\) -> \(H_{2}SO_{4}\) + 6 \(NO_{2}\) + 2 \(H_{2}O\)

From the coefficients: 6 moles of \(HNO_{3}\) produce 2 moles of \(H_{2}O\)

To find the moles of water produced, we use the following calculation:

112.6 g \(HNO_{3}\) × (1 mol \(H_{2}O\) / 63 g \(HNO_{3}\)) × (2 mol \(H_{2}O\) / 6 mol \(HNO_{3}\)) = 0.595 mol \(H_{2}O\)

Therefore, when 112.6 grams of \(HNO_{3}\) are consumed, approximately 0.595 moles of water can be produced according to the given balanced equation and molar masses.

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How many kilocalories of heat are needed to raise the temperature of 500 grams of
water from 10.0°C to 30.0°C?
A.
10.0 kcal
B. 25.0 kcal
C.
50.0 kcal
D. 40.0 kcal

Answers

Option D.40.0 kcal of heat is needed to raise the temperature of 500 grams of water from 10.0°C to 30.0°C.

Temperature is the degree of the average kinetic energy of the debris in an item. while the temperature will increase, the movement of this debris additionally will increase. Temperature is measured with a thermometer or a calorimeter.

heat = msΔt

       = 500 ×  4.186 × 20

      = 41860 Joule = 40.0 kcal

Temperature is just a dimension that indicates the common kinetic energy of 1 atom or molecule. as a result, when we are saying something is warm or bloodless, we're generally using any other reference point to define the hotness and coldness of a frame.

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Fet2 and Fe3 are
valences
isotopes
ions
Molecules

Answers

Answer:

Ions.

Explanation:

Hello!

In this case, since iron is a metal which has lots of uses in the design of metallic alloys and materials, when it is at its ground state we say it is just Fe; however, since it is a metal, it is very likely to lose electrons and therefore getting positively charged as +2 or +3, say:

\(Fe^{2+}\\\\Fe^{3+}\)

Thus, since they are positively charged, they are classified as cations, which are ions.

Best regards!

How many hydrogen atoms are present in 3.42 kg of C3H7NH2(l)?

Answers

Answer:

Explanation:

From the given information:

mass = 3.42 kg = 3420 g

molar mass of \(C_3H_7NH_2\) = 59 g

Number of moles of  \(C_3H_7NH_2 = \dfrac{mass (in gram) }{molar mass}\)

Number of moles of \(C_3H_7NH_2 = \dfrac{3420 \ g }{59 \ g}\)

= 57.966

number of hydrogen atoms present = \(n \times N_A\)

where;

\(N_A = avogadro's \ constant = 6.022 \times 10^{23}\)

number of hydrogen atoms present \(=9 \times 57.966 \imes 6.022 \times 10^{23}\)

\(\mathbf{= 3.14 \times 10^{26}}\)

Identify and describe the three ways that mutations affect organisms?

Answers

Answer:

The ways that mutation can affect an organism include:

Changing the physical characteristics of the organism.

It can impact the way that the DNA is able to code the genetic information.

Also, mutation can lead to the death of an organism.

What is mutation?

Mutation simply means a change in the DNA sequence of an organism. It can result from DNA copying mistakes that were made during the cell division.

Mutation can affect an organism as it changes the phenotype of the organism. It can also impact the way that the DNA is able to code the genetic information and lead to the death of an organism.

changing its physical characteristics (or phenotype) or it can impact the way DNA codes the genetic information (genotype). When mutations occur they can cause termination (death) of an organism or they can be partially lethal.

what is the mass of a product if the reactants masses are 11.26g hydrogen and 88.26g oxygen?

Answers

The mass of the product (water) if the reactants masses are 11.26g hydrogen and 88.26g oxygen is 99.37g

From the question,

We are to determine the mass of the product formed from reacting 11.26g hydrogen and 88.26g oxygen.

The product of the reaction is water.

First, we will write a balanced chemical equation for the reaction,

The balanced chemical equation for the reaction between hydrogen and oxygen is

2H₂ + O₂ → 2H₂O

This means,

2 moles of Hydrogen reacts with 1 mole of Oxygen to produce 2 moles of water

Now, we will determine the number of moles of each reactant present

For Hydrogen

Mass of hydrogen present = 11.26g

Molar mass of hydrogen = 2.016 g/mol

Using the formula

\(Number\ of\ moles = \frac{Mass}{Molar\ mass}\)

∴ Number of moles of hydrogen present = \(\frac{11.26}{2.016}\)

Number of moles of hydrogen present = 5.5853 moles

For Oxygen

Mass of oxygen present = 88.26g

Molar mass of oxygen = 32 g/mol

∴ Number of moles of oxygen present = \(\frac{88.26}{32}\)

∴ Number of moles of oxygen present = 2.7581 moles

Now,

Since

2 moles of Hydrogen reacts with 1 mole of Oxygen to produce 2 moles of water

Then,

5.5162 moles of Hydrogen will react with 2.7581 moles of Oxygen to produce 5.5162 moles of water

∴  Number of moles of the product (water) produced = 5.5162 moles

Now, for the mass of product

Using the formula

Mass =  Number of moles × Molar mass

Molar mass of water = 18.015 g/mol

∴ Mass of water produced =  5.5162 × 18.015

Mass of water produced = 99.374343g

Mass of water produced ≅ 99.37g

Hence, the mass of the product (water) if the reactants masses are 11.26g hydrogen and 88.26g oxygen is 99.37g

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2. For the following reaction, what volume of 1.8M Na2CO3 is needed to react with 10.0L of 0.30M of
AICI3

Answers

Answer:

Molarity = 3.33 L

Explanation:

The balanced chemical equation for the reaction is:

Na2CO3 + 2AlCl3 → 2NaCl + Al2(CO3)3

To determine the volume of 1.8 M Na2CO3 needed, we need to use the stoichiometry of the reaction and the formula:

Molarity (M) = moles of solute / liters of solution

First, let's find the moles of AlCl3 in 10.0 L of 0.30 M solution:

moles AlCl3 = Molarity x Volume = 0.30 mol/L x 10.0 L = 3.0 mol

From the balanced equation, we can see that 1 mole of Na2CO3 reacts with 2 moles of AlCl3. Therefore, we need:

moles Na2CO3 = (2/1) x moles AlCl3 = 2 x 3.0 mol = 6.0 mol

Now we can use the formula for molarity to find the volume of 1.8 M Na2CO3 needed:

Molarity = moles of solute / liters of solution

1.8 mol/L = 6.0 mol / liters of Na2CO3

Solving for liters of Na2CO3:

liters of Na2CO3 = moles of solute / Molarity = 6.0 mol / 1.8 mol/L = 3.33 L

Therefore, we need 3.33 L of 1.8 M Na2CO3 to react with 10.0 L of 0.30 M AlCl3.

Solve the following problem with the correct number of significant figures: 4.192 + 913.30 + 4.71. Show your work in detail.

Answers

Answer:

922.202

Explanation:

4.192+ 913.30+ 4.71 complying with sig figs would be solved like this:

004.192+ 913.300+ 004.710= 922.202

Which phrases apply to metamorphic rock formation? Check all that apply.

form from existing rocks
form without melting
appear foliated or non-foliated
form from liquid rock
form from deposition
require heat and pressure to form

Answers

Final answer:

Metamorphic rock formation involves the transformation of existing rocks under heat and pressure. They form without melting and can appear foliated or non-foliated.

Explanation:

Metamorphic rocks are formed from the transformation of existing rock types in a process called metamorphism, which means 'change in form'. The appropriate phrases that describe metamorphic rock formation are: 'form from existing rocks', 'form without melting', 'appear foliated or non-foliated', and 'require heat and pressure to form'. These rocks are subject to conditions of heat and pressure that cause them to change physically and/or chemically, resulting in a new type of rock. They can either be foliated (layered) or non-foliated. Importantly, metamorphic rock formation does not include a liquid state, meaning they do not 'form from liquid rock' or 'form from deposition'.

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Calculate the theoretical pH at equivalence for this titration. Show all your work. 10.00mL of methanoic acid initial volumemethanoic acid – HCOOH, Ka = 1.8 x 10-4

Calculate the theoretical pH at equivalence for this titration. Show all your work. 10.00mL of methanoic

Answers

The titration between the weak acid (HCOOH) and the strong base (KOH) can be represented like:

HCOOH (aq) + KOH (aq) <----> HCOOK (aq) + H₂O (l)

In the equivalence point we have the same number of moles of acid and base.

The number of moles of Acid that we initially have is:

number of moles of HCOOH = 10.00 mL * 0.1 mmol/mL

number of moles of HCOOH = 1.00 mmol

In the equivalence point we will have the same number of moles of the strong base:

number of moles of KOH = 1.00 mmol

The volume of KOH that we add in the equivalence point is:

volume of KOH = number of moles/molar concentration

volume of KOH = 1.00 mmol / 0.1 mmol/mL

volume of KOH = 10.00 mL

So we reach the equivalence point when 10.00 mL of KOH are added. Unfortunately in the chart that we are given, we are not given the pH when 10.00 mL of KOH are added, so we will have to calculate it.

We have to set up the ICE table.

HCOOH (aq) + OH- (aq) ----> HCOO- (aq) + H₂O (l)

I: 1.00 mmol 1.00 mmol 0 0

C: -1.00 mmol -1.00 mmol +1.00 mmol

E: 1 - 1 = 0 1-1 = 0 1.00 mmol

We reach the equivalence point when we have the same number of moles of the acid and base. That's why the initial amount of them is the same. In the equilbrium the base and the acid will be converted into the conjugate base of the weak acid (HCOO-). So the equilibrium number of moles of HCOOH and KOH are zero, and we produced 1.00 mmol of HCOO--

HCOO- is the conjugate base of the weak acid HCOOH. Since it is the only compound present in the equilibrium, we have to calculate the pH of that weak base.

HCOO- (aq) + H₂O (l) <----> HCOOH + OH-

The Kb of the conjugate base of our weak acid can be calculated using this expression:

Ka * Kb = Kw

Kb = Kw/Ka

We are given the Ka and the Kw is a constant (Kw = 1.0 *10^-14)

Kb =(1.0 * 10^-14)/ 1.8 * 10^-4

Kb = 5.56 *10^-11

Now we have to find the concentration of ion HCOO- in the equivalence point. We know that at the equilibrium we have 1.00 mmol of it. But, we had 10.00 mL of the HCOOH solution and we added 10.00 mL of the KOH solution. So now, the total volume that we have in the erlenmeyer is 20.00 mL. So the concentration of HCOO- is:

Volume of HCOOH = 10.00 mL

Volume of KOH = 10.00 mL

Total volume = 20.00 mL

Concentration at equilibrium of HCOO- = 1.00 mmol/20.00 mL

Concentration at equilibrium of HCOO- = 0.05 M

Finally we have to find the pH of the conjugate base (HCOO-) that is the only compound present at the equivalence point.

HCOO- (aq) + H₂O (l) <----> HCOOH + OH-

I 0.05 M 0 0

C -X +X +X

E 0.05 M - X +X +X

Kb = [HCOOH] * [OH-]/[HCOO-]

Kb = X * X / (0.05 M - X)

Kb = X²/(0.05 M - X)

If we consider that x is too small, we can assume that 0.05 M - X = 0.05 M

Kb = X²/0.05 M

We found that the Kb = 5.56 *10^-11

X² = 5.56 *10^-11 * 0.05

X² = 2.78 *10^-12

X = √2.78 *10^-12

X= 1.67*10^-6 M = [OH-]

We found that the concentration of OH- at the equilibrium is 1.67*10^-6 M. With that value we can find the pOH and finally we can find the pH.

pOH = -log [OH-]

pOH = -log (1.67*10^-6 M)

pOH = 5.78

pH + pOH = 14

pH = 14 - pOH

pH = 14 - 5.78

pH = 8.22

Answer: The thoretical pH at the equivalence point is 8.22

A 1500 kg race car accelerates at a rate of about 9M /s2 as to how much force does the engine need to create for this to happen

Answers

Answer:

13500 N

Explanation:

According to newtons second law of motion

mass m =1500 Kg

a = 9m/s^2

Force F = mass m × acceleration a

F = 1500×9= 13500 N

“all elements are produced by all stars” why is this statement not completely true

Answers

It would be more accurate to say that all stars produce some elements, but not all elements are produced by all stars. While it is true that many elements are produced by stars through the process of nuclear fusion, not all elements are created by all stars.

For example, the heaviest elements such as gold and platinum are formed through a process called neutron capture, which occurs during supernova explosions or in the collision of neutron stars.

Additionally, some stars may not be massive enough or may not live long enough to produce certain elements. Therefore, it would be more accurate to say that all stars produce some elements, but not all elements are produced by all stars.

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6. Cross-cuts are best made with which of the following types of knife? A. Utility knife B. Scaler C. Paring knife D. Chef's knife

Answers

Answer:

A

Explanation:

Utility knife

Answer:

Utility knife

Explanation:

The cylinder shown contains 0.79 moles of nitrogen, 0.19 moles of oxygen and 0.02 moles carbon dioxide, a total of 1.00 mole of molecules in the approximate proportion in which they are present in air. Of the three gases, only carbon dioxide is appreciably soluble in the water in the well at the bottom. Assume an equilibrium between dissolved and undissolved carbon dioxide at the beginning and sufficient time lapse to reestablish that equilibrium after the change described. If 0.02 mole of carbon dioxide is forced into the cylinder, the solubility of carbon dioxide ... a) increases by a factor of about 50. b) increases by a factor of about 2. c) increases by 2%. d) remains unchanged. e) decreases.

Answers

Answer:

b) increases by a factor of about 2.

Explanation:

Ignore the nitrogen and oxygen. Each gas acts independently of the others.

You have 0.02 mol of CO₂ gas at some pressure in equilibrium with the CO₂ in solution.

According to Graham's Law,

S  = kp

That is, the solubility of a gas in a liquid is directly proportional to its partial pressure above the liquid.

If you add another 0.02 mol of CO₂, you have doubled the number of moles.

According to Avogadro's Law, doubling the number of moles doubles the pressure.

According to Graham's Law, doubling the pressure doubles the solubility.

The solubility of CO₂ increases by a factor of two.

 

Cathodic protection of iron involves using another more reactive metal as a sacrificial anode. Classify each of the following metals by whether they would or would not act as a sacrificial anode to iron under standard conditions.

a. Ag
b. Mg
c. Cu
d. Pb
e. Sn
f. Zn
g. Au

Answers

Answer:

a. Ag ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

b. Mg ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

c. Cu ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

d. Pb ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

e. Sn ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

f. Zn ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

g. Au ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

Explanation:

Cathodic protection of iron involves using another more reactive metal as a sacrificial anode. The reactivity series of metals arranges metals based on decreasing order of reactivity. The more reactive metals are found higher up in the series while the least reactive metals are found at the lower ends of the series. Thus, metals above iron in the reactivity series can serve as sacrificial anodes by protecting against corrosion, while those lower than iron cannot.

Based on the reactivity series, the following metals can be classified as either a sacrificial anode for iron or not:

a. Ag ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

b. Mg ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

c. Cu ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

d. Pb ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

e. Sn ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

f. Zn ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

g. Au ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

a competition between a given substance and its dissolved species is ?

Answers

Answer:

Explanation:

It is odd to describe the presence of a given substance and its dissolved species as a competition but the state is called an equilibrium in solubility.

Answer:

Solubility

Explanation:

Mark that

The amount of given substance and dissolved species is constant at equilibrium .

As per le ch atler's principle

If you change the concentration it would affect the Equilibrium n

an iron ( Fe ) bar that loses 2.42 kJ when its temperature decreases from 252 ∘C to 79 ∘C

Answers

The calculated mass is 35.6.

The movement of minuscule atoms, molecules, or ions in solids, liquids, and gases produces heat energy. From one thing to another, heat energy can be exchanged. Heat is the flow or transfer that occurs as a result of the temperature differential between two objects.

Q = m*c*ΔT,

ΔT = Initial T - Final T

For iron, the specific heat capacity is 0.450 J/(g°C) and ΔT Q is the heat energy in calories (2.92 KJ = 2920 Joules).

The mass of water is m.

The values 2920 J= m* 0.450 J/g°C * are entered (254 °C-72 °C)

The solution is mass=2920 J/ 0.450*180°C

mass = 35.6.

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A 14 year old girl is small in stature and appears younger than her age. She has not started menstruating, and her parents are concerned that she is not growing taller nor entering puberty. She has frequent headaches, and is having difficulty seeing the board at school, even though she sits near the front of the room. She feels cold, even when the room is warm, and she is often constipated. Her parents are concerned. She is in the 30th percentile for height and weight, significantly below her peers.

Required:
What hormones are of LEAST concern in this person?

a. insulin
b. GH
c. GnRH
d. TSH

Answers

Answer:

A.

B.

Explanation:

Describe the porosity and permeability of Antarctic soil.

Answer within 5 minutes or you wont get a thanks, 5 stars, or brainliest

I will give brainliest, 5 stars, and a thank you

Answers

Antarctic soils exist, in general, they comprise a surface pavement (i.e., a layer of gravel, stones or boulders formed largely by weathering and the removal of fine materials mainly by wind action) and a seasonally thawed active layer over permafrost.

Electrons are found inside the nucleus, True or False?

Answers

Answer:

False their found outside of nucleus

Explanation:

Mn(OH)3 what is it called

Answers

Answer:

Lets start by looking at the elements We had Mn= manganese OH= Hydroxide We have a subscript of 3 Hence Manganese III Hydroxide

In H₂SO4 the oxidation number of H is [I], that of S is and that of O is​

Answers

In H₂SO₄, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2.

The charge an atom would have if the compound were made up of ions is known as its oxidation number. 1. In a neutral substance with atoms of only one element, the oxidation number of an atom is zero.

The oxidation state, often known as the oxidation number, in chemistry is the hypothetical charge that an atom would have if all of its links with other atoms were entirely ionic.

In sulfuric acid, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2.

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Using the following portion of the activity series for oxidation half-reactions, determine which combination of reactants will result in a reaction. Li(s) Al3 (aq) eCr(s) Al3 (aq) 3e75) A) Li(s) with Al(s) B) Li(s) with Al3 (aq) C) Li (aq) with Al(s) D) Li (aq) with Al3 (aq)

Answers

The question is incomplete, the complete question is:

Using the following portion of the activity series for oxidation half-reactions, determine which combination of reactants will result in a reaction.

\(Li(s)\rightarrow Li^+(aq)+e^-\)

\(Al(s)\rightarrow Al^{3+}(aq)+3e^-\)

A) Li(s) with Al(s)

B) Li(s) with \(Al^{3+}\) (aq)

C) \(Li^+\) (aq) with Al(s)

D) \(Li^+\) (aq) with \(Al^{3+}\) (aq)

Answer: The correct option is B): Li(s) with \(Al^{3+}\) (aq)

Explanation:

The oxidation reaction is defined as the reaction in which a chemical species loses electrons in a chemical reaction.

A reduction reaction is defined as the reaction in which a chemical species gains electrons in a chemical reaction.  

The chemical species will undergo a reduction reaction if the value of standard reduction potential is more positive or less negative.

For the given half-reactions:

\(Li(s)\rightarrow Li^+(aq)+e^-;E^o_{Li^+/Li}=-3.04V\)

\(Al(s)\rightarrow Al^{3+}(aq)+3e^-;E^o_{Al^{3+}/Al}=-1.662V\)

As the value of standard reduction potential of aluminium is less negative. Thus, it undergoes reduction reaction and lithium will undergo oxidation reaction.

The half-reaction follows:

Oxidation half-reaction:  \(Li(s)\rightarrow Li^+(aq)+e^-\)            ( × 3)

Reduction half-reaction:  \(Al^{3+}(aq)+3e^-\rightarrow Al(s)\)

Overall cell-reaction:  \(3Li(s)+Al^{3+}(aq)\rightarrow 3Li^+(aq)+Al(s)\)

Hence, the correct option is B): Li(s) with \(Al^{3+}\) (aq)

What is the pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C? A) 4.48 x 10¹¹ atm B) 2.24 x 10⁰ atm C) 1.12 x 10³ atm D) 2.24 x 10³ atm​

Answers

The pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C is 2.24 × 10⁰ atm.

How to calculate pressure?

The pressure of a substance can be calculated using the following formula;

PV = nRT

P = pressureV = volumen = no of molesR = gas law constantT = temperature

According to this question, the pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C can be calculated as follows:

P × 2 = 0.1 × 0.0821 × 546

2P = 4.48266

P = 2.24 × 10⁰ atm

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2. lithium hydroxide Formula: ______________________ (hint: Li+1 and OH-1)
Molar mass: Li = x _____ (subscript) =

O = x _____ (subscript) =

H = x _____ (subscript) =

Formula mass = Add Li + O + H =

Answers

The formula of lithium hydroxide is LiOH.

The molar mass of LiOH = 24 g/mol

What is the molar mass of a compound?

The mass of 1 mole of a chemical is indicated by its molar mass.

It provides you with the amount of grams per mole of a substance, to put it another way. Hence, grams/mole are the units for molar mass.

The mass of a specific chemical element or chemical compound (g) divided by the amount of substance is known as the molar mass (mol). By multiplying the standard atomic masses (in g/mol) of the constituent atoms, one can determine the molar mass of a compound.

The molar mass of lithium hydroxide, LiOH is derived as folows:

Molar mass = 7 + 16 + 1

Molar mass of LiOH = 24 g/mol

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A syringe filled with gas holds a volume of 35mL The pressure of the gas in the syringe is
105kPa and it is being held at a temperature of 22°C

If the syringe were warmed to 45°C but the volume were not changed what would be the new
pressure of the gas in the syringe?

if, instead the syringe were warmed to 45°C but the volume was allowed to increase while the
pressure remained constant predict the new volume of the syringe.

Answers

The new pressure of the gas in the syringe is 113 kPa

The new volume of the syringe will also increase if the syringe were warmed to 45°C and the pressure remains constant.

When we have a relation between the volume of a gas, the pressure, and the temperature participating together we can use the Combined Gas Law to solve the new pressure or volume.

What is Combined Gas Law?

The combined gas law shows the relation between Boyle's Law, Charles Law, and Gay-Lussac's Law and can be expressed by using the formula:

\(\mathbf{\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}}\)

From the parameters given:

Initial volume = 35 mLInitial Pressure = 105 kPaInitial Temperature = 22°C = (273 + 22) K = 295 K

Final  temperature = 45 °C = 318 KFinal volume =  35 mLFinal Pressure = unknown??

\(\mathbf{\dfrac{105 \times 35 }{295 }= \dfrac{P_2 \times 35}{318}}\)

\(\mathbf{P_2= \dfrac{12.458 \times 318}{35}}\)

\(\mathbf{P_2= 113 \ kPa}\)

However, if the initial volume is increased let say to 50 mL and pressure is constant:

\(\mathbf{\dfrac{V_1}{T_1}= \dfrac{V_2}{T_2}}\)

\(\mathbf{\dfrac{ 50 }{295 }= \dfrac{ x}{318}}\)

\(\mathbf{x = \dfrac{ 318 \times 50 }{295 }}\)

x = 54 mL

Therefore, the new volume of the syringe will also increase if the syringe were warmed to 45°C and the pressure remains constant.

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What is an example of a gas in motion and a fluid in motion?

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Answer:

Gas in motion : Vaporization

Examples of fluid flow :

A river flowing down a mountainAir passing over a bird's wingBlood moving through a circulatory systemFuel moving through an engine.

Explanation:

a. Identify the structures shown in the diagram. b. Identify the information that is contained within these structures. c. Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person. d. Explain why the structures are in pairs.

Answers

The answer responses to  the structures shown in the diagram are:

A. chromosomes

C. They would be the same.

B. They are in pairs because each one comes from a different parent.

What is the structure about?

The chromosomes are in pairs because humans have a diploid number of chromosomes, meaning they have two sets of chromosomes, one inherited from each parent.

The nucleus is important in eukaryotic cells and has many important parts that help the cell work properly. There are some parts inside cells called the nuclear membrane, nucleoplasm, nucleolus, and chromatin. Chromatin is made up of DNA and other proteins.

Every part of a person's body has the same genes, but the way they are organized can be different in different types of cells. The chromosomes in our skin cells might not be the same as the chromosomes in our muscle cells, even if they come from the same person.

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Identify the structures shown.

A. chromosomes

B. mitochondria

C. nuclei

D. vacuoles

C

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Explain why the structures are in pairs.

A. They aren't in pairs.

B. They are in pairs because each one comes from a different parent.

C. This cell is making a copy of itself.

D. The cell always has 2 copies in case 1 is damaged.

Chemical reactions in words

1) Na + FeBr3 = NaBr + Fe
2) PBr3 = P4 + Br2
3) Zn + O2 = ZnO
4) NH3 = N2 + H2
5) Cu + O2 = CuO

Answers

Sry I'm a minor and do not have the amount of brain cells to compute this equation. :')

hi how do i do this question? thanks in advance!

hi how do i do this question? thanks in advance!

Answers

The pH of the solution made by dissolving 135 g of sulphuryl chloride in water to make 1 dm^3 of solution will be acidic.

To calculate the pH of the solution made by dissolving 135 g of sulphuryl chloride (SOCl2) in water to make 1 dm^3 of solution, we need to consider the hydrolysis reaction of sulphuryl chloride with water:

SOCl2 + 2H2O → H2SO4 + 2HCl

In this reaction, sulphuryl chloride reacts with water to form sulphuric acid (H2SO4) and hydrochloric acid (HCl).

First, we need to determine the number of moles of sulphuryl chloride in the solution. To do this, we divide the given mass of sulphuryl chloride by its molar mass:

Molar mass of SOCl2 = 32.5 g/mol + 2 × 35.5 g/mol = 118.5 g/mol

Number of moles of SOCl2 = Mass / Molar mass = 135 g / 118.5 g/mol = 1.14 mol

Since we are dissolving 1.14 mol of sulphuryl chloride in 1 dm^3 of solution, the concentration of sulphuryl chloride is 1.14 M.

Now, we can consider the hydrolysis reaction. The hydrolysis of sulphuryl chloride produces hydrochloric acid, which is a strong acid. When a strong acid is completely dissociated in water, it results in a solution with a low pH. Therefore, the pH of the solution will be acidic.

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