Answer:
Find the value of x the value is x=4
3x4=12
12-5=7
Step-by-step explanation:
The solution of the equation is \(x=4\)
Linear equation :The given equation is,\(3x-5=7\)
To solve above equation, isolate variable x on one side and constant numbers on other side of equation.
\(3x-5=7\\\\3x=7+5\\\\3x=12\\\\x=12/3\\\\x=4\)
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A situation in which conclusions based upon aggregated crosstabulation are different fromunaggregated crosstabulation is known asa.wrong crosstabulationb.Simpson's rulec.Simpson's paradoxd.aggregated crosstabulationANS: C
A situation in which conclusions based upon aggregated crosstabulation are different from unaggregated crosstabulation is known as Simpson's paradox.
Simpson’s Paradox is an example of statistics that can be wrong. The paradox is defined as averages that can be silly and misleading. Sometimes they can be just plain baffling.
It is also called the Yule-Simpson effect which is an effect that occurs when the marginal association between two categorical variables is qualitatively different from the partial association between the same two variables after controlling for one or more other variables.
This result is often encountered in social science and medical science statistics and is particularly problematic when frequency data are unduly given causal interpretations.
It is a statistical phenomenon where an association between two variables in a population emerges or reverses when the population is divided into subpopulations.
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Help plssssss I will mark as brainlest if correct???
Answer:
4
Step-by-step explanation:
Subtract 108 from 124 and get 16 then count up how many tables he did in between 6 and 10 that would be 4 so, 16 divided by 4 is 4 :)
A lacrosse player throws a ball into the air from a height of 8 feet with an initial vertical
velocity of 32 feet per second. What is the maximum height of the ball? When will the ball hit the ground?
Answer:
256Step-by-step explanation:
Read the answer carefully and then you'll know hey i need to multiply 8 times 32.
And what do you get...... 256Modeling the situation with a quadratic equation, it is found that:
The maximum height of the ball is of 60.2 feet.The ball hits the ground after 3.39 seconds.Considering the gravity, the height of the ball, after t seconds, is given by the following quadratic equation.
\(h(t) = -4.9t^2 + v_0t + h_0\)
In which:
\(v_0\) is the initial velocity.\(h_0\) is the initial height.In this problem:
Height of 8 feet, thus \(h_0 = 8\).Initial velocity of 32 feet per second, \(v_0 = 32\)The equation is:
\(h(t) = -4.9t^2 + 32t + 8\)
Which is a quadratic equation with \(a = -4.9, b = 32, c = 8\).
The maximum height is the output of the vertex, which is:
\(h_{MAX} = -\frac{\Delta}{4a} = -\frac{b^2 - 4ac}{4a}\)
Then, with the coefficients of this question:
\(h_{MAX} = -\frac{32^2 - 4(-4.9)(8)}{4(-4.9)} = 60.2\)
The maximum height of the ball is of 60.2 feet.
It hits the ground at t for which \(h(t) = 0\), thus:
\(\Delta = b^2 - 4ac = 32^2 - 4(-4.9)(8) = 1180.8\)
\(t_{1} = \frac{-32 + \sqrt{1180.8}}{2(-4.9)} = -0.12\)
\(t_{2} = \frac{-32 - \sqrt{1180.8}}{2(-4.9)} = 3.39\)
We want the positive value, so:
The ball hits the ground after 3.39 seconds.
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the multiplication rule is used to calculate what type of probability?
The multiplication rule is used to calculate joint probability.
Joint probability is the probability of two events happening simultaneously. The multiplication rule states that the probability of two independent events happening together is equal to the product of their individual probabilities.
The formula can be expressed as: P(A and B) = P(A) x P(B). For example, if the probability of event A is 0.3 and the probability of event B is 0.4, then the joint probability of both events happening together is 0.3 x 0.4 = 0.12. The multiplication rule is only applicable for independent events, meaning that the occurrence of one event does not affect the probability of the other event.
When events are dependent, the calculation of joint probability is more complicated and may involve conditional probability.
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the mean of a normal probability distribution is 500 and the standard deviation is 10. about 95% of the observations lie between what two values? multiple choice 400 and 600 475 and 525
The correct answer is 475 and 525. To find the range of values that 95% of the observations lie between.
We can use the empirical rule, which states that for a normal distribution with mean μ and standard deviation σ, about 95% of the observations will fall within 2 standard deviations of the mean.
In this case, the mean is 500 and the standard deviation is 10. So, 2 standard deviations below the mean is 500 - 2(10) = 480, and 2 standard deviations above the mean is 500 + 2(10) = 520.
Therefore, about 95% of the observations lie between 480 and 520, or approximately between 475 and 525.
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The volume of a box is 0.001 cubic units. If the box is a cube, what is the length of one of its edges?
===============================================
Work Shown:
0.001 = 1/1000
Apply the cube root to both parts of 1/1000 to get
\(\sqrt[3]{1} = 1\\\\\sqrt[3]{1000} = 10\)
So this means that, \(\left(\frac{1}{10}\right)^3 = \frac{1}{10}*\frac{1}{10}*\frac{1}{10} = \frac{1}{1000} = 0.001\)
Having a side length of 1/10 = 0.1 unit leads to a volume of 0.001 cubic units.
-------------
A shortcut alternative is to use your calculator to get
\((0.001)^{1/3} = 0.1\)
The exponent of 1/3 is the same as a cube root.
let us suppose that sixteen adult polar bears are weighed in an attempt to estimate the average weight of all adult polar bears. the standard deviation of the population of weights is not known, so a t-interval will be reported. what will be the degrees of freedom for the t-procedure?
Answer:
your mom + your mom = big mama there you go your welcome
Step-by-step explanation:
your mom + your mom = big mama there you go your welcome
Please help!! I’m confused :(
I’ll give brainliest!
An axiom is a basic assumption about a mathematical situation. There are five axioms that form the basis for Euclidean geometry. List the five axioms.
The five axioms are:
Things which are equal to the same thing are also equal to one another.
If equals be added to equals, the wholes are equal.
If equals be subtracted from equals, the remainders are equal.
Things which coincide with one another are equal to one another.
The whole is greater than the part.
Answer:
AXIOMS AND POSTULATES OF EUCLID
Step-by-step explanation:
AXIOMS
Things which are equal to the same thing are also equal to one another.
If equals be added to equals, the wholes are equal.
If equals be subtracted from equals, the remainders are equal.
Things which coincide with one another are equal to one another.
The whole is greater than the part.
POSTULATES
To draw a straight line from any point to any point.
To produce a finite straight line continuously in a straight line.
To describe a circle with any center and distance.
That all right angles are equal to one another.
That if a straight line falling on two straight lines makes the interior angles on the same side less than two right angles, the straight lines, if produced indefinitely, will meet on that side on which the angles are less that two right angles.*
Solve the logarithmic equation. loga(x−2)−loga(x+9)=loga(x−3)−loga(x+4) Determine the equation to be solved after removing the logarithm. (Type an equation. Do not simplify.) What is the exact solution? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is (Simplify your answer. Type an exact answer. Use a comma to separate answers as needed.) B. There is no solution.
Solution set is {7, -6}
The given logarithmic equation is as follows:loga(x - 2) - loga(x + 9) = loga(x - 3) - loga(x + 4)To determine the equation to be solved after removing the logarithm, we need to apply the logarithmic identity:loga(b) - loga(c) = loga(b / c)Using this identity in the above equation, we get:loga[(x - 2) / (x + 9)] = loga[(x - 3) / (x + 4)]Now, we can equate the logarithmic expressions inside the function. Therefore,(x - 2) / (x + 9) = (x - 3) / (x + 4)Cross-multiplying the above equation, we get:(x - 2)(x + 4) = (x + 9)(x - 3)Simplifying the above equation, we get:x² - 5x - 42 = 0Factoring the above equation, we get:(x - 7)(x + 6) = 0Therefore, the solutions are x = 7 and x = -6. Hence, the solution set is {7, -6}.Thus, the correct choice is A. The solution set is {7, -6}.
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"Derive the demand function
Endowment (1,0)
U(x,y) = -e⁻ˣ — e⁻ʸ
To derive the demand function from the given utility function and endowment, we need to determine the optimal allocation of goods that maximizes utility. The utility function is U(x, y) = -e^(-x) - e^(-y), and the initial endowment is (1, 0).
To derive the demand function, we need to find the optimal allocation of goods x and y that maximizes the given utility function while satisfying the endowment constraint. We can start by setting up the consumer's problem as a utility maximization subject to the budget constraint. In this case, since there is no price information provided, we assume the goods are not priced and the consumer can freely allocate them.
The consumer's problem can be stated as follows:
Maximize U(x, y) = -e^(-x) - e^(-y) subject to x + y = 1.
To solve this problem, we can use the Lagrangian method. We construct the Lagrangian function L(x, y, λ) = -e^(-x) - e^(-y) + λ(1 - x - y), where λ is the Lagrange multiplier.
Taking partial derivatives of L with respect to x, y, and λ, and setting them equal to zero, we can find the values of x, y, and λ that satisfy the optimality conditions. Solving the equations, we find that x = 1/2, y = 1/2, and λ = 1. These values represent the optimal allocation of goods that maximizes utility given the endowment.
Therefore, the demand function derived from the utility function and endowment is x = 1/2 and y = 1/2. This indicates that the consumer will allocate half of the endowment to each good, resulting in an equal distribution.
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Takiya recorded the heights of two sets of plants, one set planted in the shade and one set planted in full sun. Her data are shown in the plots below.
A dot plot. A number line going from 1.5 to 4.5 in increments of 0.5 is labeled Heights of Shaded plants (inches). There are 0 dots above 1.5, 4 above 2, 3 above 2.5, 2 above 3, 0 above 3.5 and 4, and 1 above 4.5.
A dot plot. A number line going from 1.5 to 4.5 in increments of 0.5 is labeled Heights of Full Sun plants (inches). There are 0 dots above 1.5, 1 above 2, 0 above 2.5, 2 above 3, 0 above 3.5, 4 above 4, and 3 above 4.5.
Which best explains the variability of the sets?
Answer:
The shaded plants set has greater variability because more data is clustered around the median. "NC"The sets are equally variable because the ranges of the data sets are equal.The full sun plants set has greater variability because the IQR for full sun plants is greater. The full sun plants set has greater variability because the median for full sun plants is greater.
Step-by-step explanation:
The shaded plants can always get a greater variability because remember more data around the median. The sets would eventually equal the variable.
Sun plans can get greater variability because the median can always be used for sun plants and which is being called greater.
Using left-factoring and/or elimination of left-recursion give grammars equivalent to the below two grammars where the immediate problems preventing use of recursive-descent parsing have been removed. Capital letters denote variables and the set of terminals is {a,b,c,d}. (a) S + bccs | adaSa | adacSc | de (b) S + Scbc | Sbbc abs | dbSa E
The given grammars (a) and (b) have been modified by applying left-factoring and eliminating left recursion, resulting in equivalent grammars suitable for recursive-descent parsing.
To eliminate left recursion and left-factoring in the given grammars, let's start with grammar (a) and then move on to grammar (b).
(a) Grammar: S + bccs | adaSa | adacSc | de
Left-Factoring
To apply left-factoring, we identify common prefixes in the productions.
S → bccs | adaSa | adacSc | de
We can see that "ada" is a common prefix in the second and third productions. Let's factor it out
S → bccs | ada(Sa | cSc) | de
Elimination of Left Recursion
To eliminate left recursion, we'll rewrite the grammar using new non-terminals.
S → bccsT | adaUT | de
T → Sa | cScT
U → daUT | cScU | ε
The grammar is now free of left recursion and left-factoring.
Moving on to grammar (b)
(b) Grammar: S + Scbc | Sbbc abs | dbSa
Left-Factoring
S → Scbc | Sbbc abs | dbSa
We can see that "Sb" is a common prefix in the second and third productions. Let's factor it out:
S → Scbc | Sb(bc | bc abs) | dbSa
Elimination of Left Recursion
S → ScbcT | SbUT | dbSa
T → ε
U → cbcT | bcUT | bc absT
The resulting grammar is free of left recursion and left-factoring.
Now, you have equivalent grammars for (a) and (b) where the problems preventing the use of recursive-descent parsing have been removed.
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a sequence has an explicit rule f(n)=6 - n^2. find the first 3 terms.
help pretty pleaseeee
Answer:
5, 2, - 3
Step-by-step explanation:
To find the first 3 terms substitute n = 1, 2, 3 into the explicit rule, that is
f(1) = 6 - 1² = 6 - 1 = 5
f(2) = 6 - 2² = 6 - 4 = 2
f(3) = 6 - 3² = 6 - 9 = - 3
The first 3 terms are 5, 2, - 3
Each baby dinosaur made 151515 paintings and each adult dinosaur made 777 paintings. The entire herd made 208208208 paintings in total, and there were 333 times as many baby dinosaurs as adult dinosaurs.
How many baby dinosaurs and adult dinosaurs were there?
Using the expression, 15x + 7y = 208 there were x = 12 baby dinosaurs and y = 4 adult dinosaurs.
A finite combination of symbols that are well-formed in accordance with context-dependent principles is referred to as an expression or mathematical expression.
Each baby dinosaur made 15 paintings and every adult dinosaur made 7 paintings.
The total number of paintings the entire herd made is 208.
There were 3 times as many baby dinosaurs as adult dinosaurs.
Now, let x be the number of baby dinosaurs and y be the number of adult dinosaurs.
Then,
x = 3y
So,
The expression for the total number of paintings will be:
208 = 15x + 7y
208 = 15(3y) + 7y
208 = 45y + 7y
208 = 52y
y = 4
So,
x = 3y = 3(4) = 12
There were 12 baby dinosaurs and 4 adult dinosaurs.
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how many 5/8 foot peices of wood can you cut from a board that is 4 5/8 feet long
Answer:
7
Step-by-step explanation:
5/8 x 7= 4 3/8
That's the closest you are going to get without going over.
Heads up there could be more then one answer so look out for that :)
Answer:
(-2,0)
Step-by-step explanation:
(-2,0) falls on the line 3x-y=-6
Hope this helps!
need to be taught how to do this, thanks
Answer:
x = 36.27
Step-by-step explanation:
By using the steps to find sin θ backwards, we can find x, the hypotenuse.
sin θ = \(\frac{opposite}{hypotenuse}\) or side \(\frac{a}{c}\) (as seen in my example picture).
We already know the value for sin (α), which is 32° because its given. The opposite side (a) is 20 and the hypotenuse side (c) is x which are both also given.
So the equation now looks like:
sin 32° = \(\frac{20}{x}\)
Don't solve for the sin 32 yet! First, we have to isolate the variable.
To get rid of the x in the denominator you have to multiply both sides by x:
( sin 32 ) · x = ( \(\frac{20}{x}\) ) · x
( sin 32 ) x = 20
Then, you have to divide both sides by sin 32 to get x by itself:
(( sin 32 ) x ) ÷ ( sin 32 ) = 20 ÷ ( sin 32 )
x = 20 ÷ ( sin 32 )
Lastly, you have to use a calculator to find 20 ÷ ( sin 32 ), and it should give you 36.2695543766.
The question asks you to round to 2 decimal places so:
x = 36.27
some alkenes have geometric cis trans isomers because
Some alkenes have geometric cis-trans isomers because of the presence of a double bond between two carbon atoms. In a carbon-carbon double bond, the carbon atoms are connected to two different groups of atoms, which can be oriented differently in space. In the cis configuration, the two substituent groups on each carbon atom are on the same side of the double bond, while in the trans configuration, the two substituent groups on each carbon atom are on opposite sides of the double bond.
The cis-trans isomerism arises due to the restricted rotation around the carbon-carbon double bond. In the case of cis isomers, the substituent groups are too bulky to rotate around the double bond, and they remain on the same side of the double bond. In contrast, in the trans isomers, the substituent groups are oriented on opposite sides of the double bond, which allows them to rotate freely around the bond.
The presence of cis-trans isomers has important consequences for the physical and chemical properties of alkenes, including their reactivity, solubility, and melting points. The two isomers can have different properties and can exhibit different biological activities, making them important targets for drug design and synthesis.
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help!!!!!!!!!!!!!!!!!!!!!!!!!!! im a dummy
your scientific notation will be 2.505 x 10^4
1.2p - 2q for p = 3.5 and q = 1.2 = ??
Answer:
1.8
Step-by-step explanation:
1.2p - 2q
Let p = 3.5 and q = 1.2
1.2 ( 3.5) - 2(1.2)
Multiply
4.2 - 2.4
Subtract
1.8
For the following set of data, find the percentage of data within 2 population standard deviations of the mean, to the nearest percent
chart is in the photo
Percentage of data within 2 population standard deviations of the mean is 68%.
To calculate the percentage of data within two population standard deviations of the mean, we need to first find the mean and standard deviation of the data set.
The mean can be found by summing all the values and dividing by the total number of values:
Mean = (20*2 + 22*8 + 28*9 + 34*13 + 38*16 + 39*11 + 41*7 + 48*0)/(2+8+9+13+16+11+7) = 32.68
To calculate standard deviation, we need to calculate the variance first. Variance is the average of the squared differences from the mean.
Variance = [(20-32.68)^2*2 + (22-32.68)^2*8 + (28-32.68)^2*9 + (34-32.68)^2*13 + (38-32.68)^2*16 + (39-32.68)^2*11 + (41-32.68)^2*7]/(2+8+9+13+16+11+7-1) = 139.98
Standard Deviation = sqrt(139.98) = 11.83
Now we can calculate the range within two population standard deviations of the mean. Two population standard deviations of the mean can be found by multiplying the standard deviation by 2.
Range = 2*11.83 = 23.66
The minimum value within two population standard deviations of the mean can be found by subtracting the range from the mean and the maximum value can be found by adding the range to the mean:
Minimum Value = 32.68 - 23.66 = 9.02 Maximum Value = 32.68 + 23.66 = 56.34
Now we can count the number of data points within this range, which are 45 out of 66 data points. To find the percentage, we divide 45 by 66 and multiply by 100:
Percentage of data within 2 population standard deviations of the mean = (45/66)*100 = 68% (rounded to the nearest percent).
Therefore, approximately 68% of the data falls within two population standard deviations of the mean.
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A swim team member performs a dive from a 14-foot high springboard. Her path is represented by the equation LaTeX: h\left(t\right)=-0.875t^2+5.25t+14h ( t ) = − 0.875 t 2 + 5.25 t + 14, where t is time in seconds and h is the height above the surface of the water. She needs to finish her flip no later than 5 feet above the surface of the water in order to prepare for the splash. What time does this happen? Round to the nearest tenth of a second.
Answer:
7.4secs
Step-by-step explanation:
If the path of a swim team member is modeled by the equation
h(t) = -0.875t²+5.25t+14
where t is time in seconds and h is the height above the surface of the water
If she need to finish in no later than 5feet above the surface, the expression will become:
-0.875t²+5.25t+14≤5
-0.875t²+5.25t+14-5≤0
-0.875t²+5.25t+9≤0
Rewriting using fraction
-7/8t²+21/9t+9≤0
To get the time that this happens we will need to factorize the resulting expression above;
On factorising
Find the roots of the equation using the formulas
t = 3+3√105/7
t = 3+ 3(10.25)/7
t = 3 + (30.75)/7
t = 3 + 4.393
t = 7.393
t = 7.4secs
Hence this happens at t = 7.4secs
Answer:
The time when the swim team member is 5 feet above the water surface is 7.4 seconds.
Step-by-step explanation:
You want to know when a member of the swim team finished his jump no later than 5 feet above the surface of the water to prepare for the splash, that is, when t is 5 feet above the surface of the water. Substituting h(t) for this value 5 in the equation you obtain:
5= -0.875*t²+5.25*t+14
A quadratic equation has the general form:
a*x² + b*x +c= 0
where a, b and c are known values and a cannot be 0.
Taking the equation 5= -0.875*t²+5.25*t+14 to that form, you get:
-0.875*t²+5.25*t+14-5=0
-0.875*t²+5.25*t+9=0
The roots of a quadratic equation are the values of the unknown that satisfy the equation. And solving a quadratic equation is finding the roots of the equation. For this you use the formula:
\(\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}\)
In this case, solving the equation is calculating the values of t, that is, you find the time when the swim team member is 5 feet above the water surface.
Being a= -0.875, b=5.25 and c= 9, then
\(\frac{-5.25+-\sqrt{5.25^{2}-4*(-0.875)*9 } }{2*(-0.875)}\)
\(\frac{-5.25+-\sqrt{27.56+31.5 } }{-1.75}\)
\(\frac{-5.25+-\sqrt{59.06 } }{-1.75}\)
\(\frac{-5.25+-7.685}{-1.75}\)
Then:
\(t1=\frac{-5.25+7.685}{-1.75}\) and \(t2=\frac{-5.25-7.685}{-1.75}\)
Solving for t1:
\(t1=\frac{2.435}{-1.75}\)
t1= -1.39 ≅ -1.4
Solving for t2:
\(t2=\frac{-12.935}{-1.75}\)
t2= 7.39 ≅ 7.4
Since time cannot be negative, the time when the swim team member is 5 feet above the water surface is 7.4 seconds.
solve:
4 = k/7
a. 24
b.11
c. 32
d. 28
Answer:
D. 28
Step-by-step explanation:
\(4 = \frac{k}{7} \\\\28 = k\)
Answer:
D
Step-by-step explanation:
D because 28 divided by 4 is 7 which means k=28
ii. suppose the following system has a center as its critical point. what is the value of α? x1′ = αx1 2x2 x2′ = −3x1 2x2
The value of α for which the system has a center as its critical point is α = -3.
The given system of equations is:
x₁' = αx₁ + 2x₂
x₂' = -3x₁ + 2x₂
To find the critical points, we set the derivatives equal to zero:
αx₁ + 2x₂ = 0
-3x₁ + 2x₂ = 0
From the first equation, we can solve for x1 in terms of x₂:
x₁ = (-2x₂) / α
Substituting this expression into the second equation:
-3((-2x₂) / α) + 2x₂ = 0
(6x₂ / α) + 2x₂ = 0
Multiplying through by α:
6x₂ + 2αx₂ = 0
Factoring out x₂:
6 + 2α) x₂ = 0
For x₂ to be nonzero, the term (6 + 2α) must be zero:
6 + 2α = 0
Solving for α:
2α = -6
α = -3
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if something is $380, then the sellers mark up the price by 84%, what is the final sale price??
To prepare for his mountain biking trip, Rhyan bought four tire patches. Rhyan paid using a gift card that had $22.20 on it. After the sale, Rhyan’s gift card had $1.90 remaining. Which equations could you use to find the price of one tire patch? Select all that apply. 4x – 1.9 = 22.2 4x – 22.2 = 1.9 4x + 1.9 = 22.2 4x + 22.2 = –1.9 22.2 – 4x = 1.9
Answer:
your mom
1234567891011
find the value of sin30+tan^(2)60+sec^(2)45
Answer:
Step-by-step explanation:
sin 30+tan²(60)+sec²(45)
=1/2+ (√3)^2+(√2)²
=1/2+3+2
=5 1/2
=5.5
PLEASE HELP ME ASAP!!!
Answer:
tell me more explain how do you need help
Step-by-step explanation:
The owner of a store advertises on the television and in a newspaper. He has found that the number of units that he sells is approximated by N«, ») =-0.1x2 - 0.5y* + 3x + 4y + 400, where x (in thous
To maximize the number of units sold, the owner should spend $15,000 on television advertising (x) and $4,000 on newspaper advertising (y).
To find the values of x and y that maximize the number of units sold, we need to find the maximum value of the function N(x, y) = -0.1x² - 0.5y² + 3x + 4y + 400.
To determine the maximum, we can take partial derivatives of N(x, y) with respect to x and y, set them equal to zero, and solve the resulting equations.
First, let's calculate the partial derivatives:
∂N/∂x = -0.2x + 3
∂N/∂y = -y + 4
Setting these derivatives equal to zero, we have:
-0.2x + 3 = 0
-0.2x = -3
x = -3 / -0.2
x = 15
-y + 4 = 0
y = 4
Therefore, the critical point where both partial derivatives are zero is (x, y) = (15, 4).
To verify that this critical point is a maximum, we can calculate the second partial derivatives:
∂²N/∂x² = -0.2
∂²N/∂y² = -1
The second partial derivative test states that if the second derivative with respect to x (∂²N/∂x²) is negative and the second derivative with respect to y (∂²N/∂y²) is negative at the critical point, then it is a maximum.
In this case, ∂²N/∂x² = -0.2 < 0 and ∂²N/∂y² = -1 < 0, so the critical point (15, 4) is indeed a maximum.
Therefore, to maximize the number of units sold, the owner should spend $15,000 on television advertising (x) and $4,000 on newspaper advertising (y).
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A piece of wire 22m long is bent to form a rectangle of area 24m² find the length and breadth of the rectangle