Answers
The number of C atoms in 0.247 mol of C is 1.48 X 10²³ .
The number of C atoms in 1 mol of C is 6.02 X 10²³, which is also called Avogadro’s number .
so, The number of C atoms in 0.247 mol of C is _
0.247x6.02x10²³= 1.48 X 10²³.
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Related Questions
Match the solution with the correct concentration.
Answers
Answer:
1. is Molar (with capital M)
2. is molal (m)
Explanation:
By definition, 1 Molar solutions have 1 mol of solute in 1 L of solution and 1 molal solutions have 1 mol of solute in 1 Kg of solvent
If 32.73g of FePO4 react with excess Na2SO4 how many grams of Fe2 (SO4)3 can be made?
Answers
First, we must write our reaction and balance it:
2 FePO4 + 3 Na2SO4 => Fe2(SO4)3 +2 Na3PO4 (balanced)
We have 32.73 g FePO4 that reacts, and we want to get the amount of Fe2(SO4)3 produced.
The excess here is Na2SO4
We also need the molar masses for FePO4 (150.8 g/mol) and for Fe2(SO4)3 (399.8 g/mol)
Procedure:
2 x 150.8 g FePO4 ------------------- 399.8 g Fe2(SO4)3
32.73 g FePO4 ------------------- X
X = 32.73 g x 399.8 g/ 2 x 150.8 g = 43.39 g
Answer: 43.39 g of Fe2(SO4)3
Reflect on the learning activities titled “Hypothesis”, “Variables and Hypothesis” and “Constructing a Hypothesis”. Describe some similarities and differences between a question that comes in response to an observation, and a scientific research question? Cite quotes from the readings to support your answer. Where do variables fit into this thinking? In other words, if you imagine a number line with observation questions at one end and scientific research questions at the other, what role do variables play anywhere along this continuum?
Answers
The learning activities titled "Hypothesis," "Variables and Hypothesis," and "Constructing a Hypothesis" all share certain similarities and differences. A question that arises in response to an observation is similar to a scientific research question in that both require some level of investigation to achieve an answer. However, scientific research questions are typically more specific and refined, with a defined methodology for obtaining data and verifying results.
The following quotes from the readings illustrate this distinction:"A scientific question is one that can be answered by using scientific investigation. In contrast, an observation question is one that comes in response to observing or experiencing something in the natural world" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."An important feature of a scientific question is that it should be answerable within a reasonable amount of time and with the resources available" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Research questions can be narrow or broad, depending on the scope of the research" (Constructing a Hypothesis).The concept of variables is crucial to both observation and scientific research questions, but they play different roles depending on where they fall on the continuum. Observation questions are usually less precise and may not require much consideration of variables. On the other hand, scientific research questions are likely to include a rigorous examination of variables and their potential effects."Variables are an essential part of a scientific experiment. They are the things that change in an experiment" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Variables are important because they can affect the outcome of the research" (Constructing a Hypothesis).In summary, observation questions and scientific research questions share some similarities, but the latter is more specific, has a defined methodology, and may require more consideration of variables.For such more question on Hypothesis
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What is the mass of oxygen, in grams, required to completely react a 24 gram sample of methane gas?
Answers
Answer: 96 g O2
Explanation:
this is combustion
CH4 + 2 O2 --> CO2 + 2 H2O
24 g CH4 X 1 mole Ch4 / 16.043 g CH4) X ( 2 moles O2 / 1 moles CH4) X
( 31.999 G O2 / 1 mole O2 ) = 95.74 g O2 = 96 g O2 in correct sig figs
Solve whoever gets it right first gets brainlest!
Answers
i’m not sure tho don’t mark me as that
I think the answer is b i might be slow but I think it’s b
Explanation:
Which of the following is an incorrect representation for a neutral atom?
36Li
613C
3063Cu
1530P
Answers
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li
To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.
Let's analyze the given representations:
36Li:
This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.
613C:
This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.
3063Cu:
This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.
1530P:
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.
Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.
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Acetone is a common solvent that has a density of 0.7899 g/mL. What volume of acetone, in milliliters, has a mass of 32.3 g ?
Answers
Answer:
40.9 mL
Explanation:
The volume of acetone can be found by dividing mass by density. Density can be defined as the amount of substance (mass) per unit volume.
Volume of acetone
= 32.3 ÷0.7899
= 40.9 mL (3 s.f.)
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When temperature increases, the random movement of molecules increases which subsequently increases diffusion rate. If you have the same concentration of each of the following substances and they all have the same molecular weight, predict which substance will have the greatest diffusion rate?
a. substance #3 in aliquid at 64' F
b. substance 14 in a gas at 32 F
c. substance #2 in aliquid at a 32°F
d. substance #5 in a gas at 78' F
e. substance in a semisolid at 78' F
Answers
Answer:
d. substance #5 in a gas at 78' F
Explanation:
Diffusion in substances simply has to do with the movement of the particles of a substance from one point to another.
The rate of diffusion varies in gases, liquids and solids. Gas molecules are usually more energetic than molecules of solids and liquids. Gases and are also in constant random motion at high velocities.
Therefore, substance #5 in a gas at 78' F will have the greatest diffusion rate.
A sample of oxygen gas initially at 323 K was heated to 377 K. If the volume of the oxygen gas sample at 377 K is 753.8 mL,
what was its volume at 323 K?
Answers
ANSWER : 643.1 mL
STEPS:
V1/T1 = V2/T2
Volume of oxygen gas.
A sample of oxygen gas was initially at a temperature of 323 K.
The sample was heated to a new temperature of 377 K.
The volume of the sample at the new temperature of 377 K is 753.8 mL.
We want to find the volume of the sample at the initial temperature of 323 K.
To solve for the initial volume, we can use the combined gas law:
(V1/T1) = (V2/T2), where:
V1 is the initial volume of the gas
T1 is the initial temperature of the gas
V2 is the final volume of the gas
T2 is the final temperature of the gas
Rearranging the equation to solve for V1, we get: V1 = (V2/T2) x T1
Plugging in the values we know, we get:
V1 = (753.8 mL / 377 K) x 323 K
Solving for V1, we get:
V1 = 643.1 mL
Therefore, the volume of the oxygen gas sample at 323 K is approximately 643.1 mL.
ChatGPT
A bear has just had a sandwich that contained the equivalent of 2.70 mol of glucose ΔHo 2810 kJ mol 1 The standard molar entropy ΔSo of reaction is 182 J K 1 mol 1 How much energy in kJ is available for sustaining the bear's muscular and nervous activity assuming a body temperature of 36.1oC Make sure that your answer has the correct number of significant figures
Answers
Answer:
no
Explanation:
Determine the number of grams 0.25 moles of KCI
Answers
Answer:
0.25 moles of KCI is equal to 18.638 grams.
Explanation:
The molar mass of a substance is the mass of one mole of that substance. The molar mass of KCI is 74.55 g/mol.
To find the number of grams in 0.25 moles of KCI, we can use the formula:
mass = moles x molar mass
mass = 0.25 moles x 74.55 g/mol
mass = 18.638 g
So, 0.25 moles of KCI is equal to 18.638 grams.
(Please give brainlist)
How many moles of Ag can be obtained from 2.77 moles Cu using the following
balanced reaction?
2AgNO3
+ Cu
Cu(NO3)2
+ 2Ag
Answers
Answer:
2.77×2= 5.4 mol Ag can be obtained
Electrons further from the nucleus are partially shielded from the pull of the nucleus.
True
False
Answers
Hope this helps
how would you confirm the presence of lead in an ore?
Answers
There are numerous ways to determine whether lead is present in an ore. Atomic absorption spectroscopy is a popular approach. With this method, an ore sample is dissolved in acid and then atomized in a flame or plasma.
The sample's atoms will absorb light at particular wavelengths that are peculiar to the element under investigation. The amount of light absorbed can be used to calculate how much lead is present in the sample. Inductively coupled plasma mass spectrometry and X-ray fluorescence spectroscopy are further techniques. It is crucial to remember that these procedures call for specialized tools and training, thus they ought to only be carried out in a lab by qualified experts.
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what is the original pressure of a 750 ml sample of He at 0 degrees Celsius if it exerts 2 atm at 25 degrees Celsius and 500 ml
Answers
To determine the original pressure of a 750 ml sample of helium (He) at 0 degrees Celsius, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The combined gas law equation is:
(P1 × V1) / (T1) = (P2 × V2) / (T2)
Where:
P1 and P2 are the initial and final pressures, respectively.
V1 and V2 are the initial and final volumes, respectively.
T1 and T2 are the initial and final temperatures, respectively.
Let's assign the given values:
P1 = unknown (original pressure)
V1 = 750 ml (initial volume)
T1 = 0 degrees Celsius (initial temperature)
P2 = 2 atm (final pressure)
V2 = 500 ml (final volume)
T2 = 25 degrees Celsius (final temperature)
Before using the combined gas law equation, we need to convert the temperatures to Kelvin scale by adding 273.15 to both T1 and T2:
T1 = 0 + 273.15 = 273.15 K
T2 = 25 + 273.15 = 298.15 K
Now we can plug in the values into the combined gas law equation:
(P1 × 750 ml) / (273.15 K) = (2 atm × 500 ml) / (298.15 K)
To solve for P1, we can cross multiply and rearrange the equation:
P1 = (2 atm × 500 ml × 273.15 K) / (750 ml × 298.15 K)
P1 = 0.924 atm
Therefore, the original pressure of the 750 ml sample of helium at 0 degrees Celsius is approximately 0.924 atm.
What is the concentration of chloride ions when 2.5 g FeCl is dissolved in 150 mL water?
Answers
The concentration of chloride ions when 2.5 g of FeCl is dissolved in 150 mL of water is approximately 0.54 M.
To determine the concentration of chloride ions when 2.5 g of FeCl is dissolved in 150 mL of water, we need to consider the molar mass of FeCl and perform some calculations.
The molar mass of FeCl is 55.85 g/mol (for iron) + 35.45 g/mol (for chlorine), which gives a total molar mass of 91.3 g/mol for FeCl.
First, we need to calculate the number of moles of FeCl present in 2.5 g of the compound. This can be done using the formula:
moles = mass / molar mass
moles of FeCl = 2.5 g / 91.3 g/mol = 0.027 moles
Next, we convert the volume of water from milliliters (mL) to liters (L):
volume of water = 150 mL = 150/1000 L = 0.15 L
Now, we can calculate the concentration of chloride ions (Cl-) using the formula:
concentration (Cl-) = moles of Cl- / volume of water
Since FeCl dissociates into one Fe3+ ion and three Cl- ions, the number of moles of Cl- is three times the moles of FeCl:
moles of Cl- = 3 * moles of FeCl = 3 * 0.027 moles = 0.081 moles
concentration (Cl-) = 0.081 moles / 0.15 L = 0.54 M.
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Liquid octane (CH3(CH2)6CH3) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO2) and gaseous water (H2O). Suppose 17. g of octane is mixed with 112. g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to significant digits.
Answers
The maximum mass of water that could be produced by the chemical reaction is 162 g.
The given chemical equation is: 2 C8H18(l) + 25 O2(g) → 16 CO2(g) + 18 H2O(l)In the chemical reaction of liquid octane with gaseous oxygen, the products are gaseous carbon dioxide and gaseous water.According to the balanced chemical equation, 2 moles of C8H18 react with 25 moles of O2 to form 18 moles of H2O.So, 1 mole of C8H18 react with 25/2 = 12.5 moles of O2 to form 9 moles of H2O.The molar mass of C8H18 is 114 g/mol. So, the number of moles in 17 g of C8H18 is:17 g / 114 g/mol = 0.149 molThe molar mass of O2 is 32 g/mol. So, the number of moles in 112 g of O2 is:112 g / 32 g/mol = 3.5 molFrom the balanced chemical equation, 1 mole of C8H18 react with 12.5 moles of O2 to form 9 moles of H2O.So, the number of moles of O2 required to react with 0.149 mol of C8H18 to form H2O is:(12.5 mol / 1 mol) × (0.149 mol / 2 mol) = 0.935 molThe maximum number of moles of H2O that can be produced from 0.149 mol of C8H18 and 0.935 mol of O2 is 9 mol.So, the mass of water produced from 17 g of C8H18 and 112 g of O2 is:9 mol × 18 g/mol = 162 g
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In the reaction represented by the equation COCl2+2NaI>2NaCl+CO+I2 how many milliliters of a .5500 M solution of NaI are needed to produce 34.81mg of I2?
Answers
472.7ml of a .5500 M solution of NaI are needed to produce 34.81mg of I\(_2\) in the reaction COCl\(_2\)+2NaI → 2NaCl+CO+I\(_2\).
What is volume?A measurement of three-dimensional space is volume. Several imperial or US customary units, as well as SI-derived units (such the cubic meter and liter), are frequently used to quantify it quantitatively. Volume and length (cubed) have a symbiotic relationship.
COCl\(_2\)+2NaI → 2NaCl+CO+I\(_2\)
number of moles of I\(_2\) =34.81/254=0.13moles
2 moles of NaI gives 1 moles of I\(_2\)
0.13moles are obtained by 2×0.13=0.26moles of NaI
0.550moles of I\(_2\) is present in 1000ml
0.26moles of I\(_2\) is present in (1000/0.55)×0.26=472.7ml
Therefore, 472.7ml of a .5500 M solution of NaI are needed to produce 34.81mg of I\(_2\).
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1) 1.644 kg
Express your answer using three significant figures.
2) 74.2587 L
Express your answer using three significant figures.
3) 0.00268756 cm
Express your answer using three significant figures.
4) 8907 m
Express your answer using three significant figures.
Answers
Answer:
\(1) \: 1.644 kg = 1.64kg \: in \: three \: significant \: figures. \\ 2) \: 74.2587 L =74.3L \: in \: three \: significant figures. \\
3) 0.00268756 cm \: = 0.00269cm \: in \: three \: significant \: figures. \\ 4) 8907 m = 8910m \: in \: three \: significant \: figures.\)
What else should the second group of researchers measure to test the hypothesis
Answers
Answer:
Testing of thesis testing is used to determine the plausibility of a thesis.
The test assess the plausibility of the thesis of a sample data.
It occurs through different way, the first step is used to test the state the two suppositions.
In the coming step evaluation of data, third step include carry out plan and dissect the data.
The final step is to dissect the results of the data, it can moreover accept the thesis and reject the null thesis.
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Predict the product formed when calcium, Ca, combines with arsenic, As? (Please explain why) a. Ca3As2 b. Ca2As3 c. CaAs d. Ca2As2 e. Ca3As3
Answers
The chemical element calcium has the atomic number 20 and the letter Ca as its symbol. Calcium is an alkaline earth metal that reacts with air to create a black oxide-nitride coating.
What happens when calcium reacts with?With the chemical symbol Ca and atomic number 20, calcium is a member of the calcium family. Calcium is a reactive metal and an alkaline earth metal that, when exposed to air, develops a shady oxide-nitride layer.
In this article, the arsenic acid formula—also known as orthoarsenic acid formula or as arsoric acid formula—is explored. Three hydroxyl and one oxo group make up this arsenic oxoacid.
Arsenopyrite is the mineral with the greatest prevalence of arsenic. Realgar, orpiment, and enargite are some more minerals. Most arsenic is created as a byproduct of the copper and lead refining process.
Metal calcium and water interaction - Less vehemence is produced when calcium metal combines with water.
Therefore, the correct answer is option e) Ca3As2.
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How many liters of a 0.26 M solution of Na₂MnO4 would contain 0.38 mole of Na₂MnO4?
Answers
The molarity of the solution (0.26 M). The result is 1.46 L, which is the volume of the solution that would contain 0.38 mole of Na₂MnO4.
What is molarity?Molarity is a unit of measure used to indicate the concentration of a solute in a solution. It is expressed in moles of solute per liter of solution (mol/L). This measure is useful for describing the amount of a particular chemical species present in a solution, as well as for determining the amount of a reactant or product that is produced in a chemical reaction. Molarity is also used to calculate the amount of a substance that must be added to a solution to achieve a desired concentration.
The number of liters of a 0.26 M solution of Na₂MnO4 that would contain 0.38 mole of Na₂MnO4 can be calculated using the following equation:
Volume (L) = moles (mol) / Molarity (M)
Therefore, the volume of a 0.26 M solution of Na₂MnO4 that would contain 0.38 mole of Na₂MnO4 is:
Volume (L) = 0.38 mol / 0.26 M
Volume (L) = 1.46 L
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52
p3
N?
Br1
CaBr2
Cas
Ca3P2
Cal2
Ca3N2
Cat2
K1
Mg2
Zn2
Fe3
Answers
Two asteroids are 75,000 m apart one has a mass of 8 x 10^7 N what is the mass of the other asteroid
Answers
The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg
To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:
F = (G * m1 * m2) / \(r^{2}\)
where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.
Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):
1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)
Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.
The question was incomplete. find the full content below:
Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid
A. 3.4 x \(10^{11}\) kg
B. 8.3 x \(10^{12}\) kg
C. 1.2 x \(10^{12}\) kg
D. 1.2 x \(10^{10}\) kg
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A scientist plans to find out the cause of decrease in bird population in a location. He interviews 50 people who work in the local oil mine and 45 of them believe that the mine does not affect the birds. The scientist concludes that 90 percent of people in the location believe that the local oil mine does not cause decrease in bird population. Why is the scientist's conclusion most likely unreliable? (2 points)
Group of answer choices
a. the results of the investigation cannot be repeated
b. the source of information could be biased
c. bird population cannot be measured accurately
d. the investigation is done by only one person
Answers
Answer:
Explanation:
what properties of a natural resource make it useful for humans as a materials or energy source?
Answers
The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.
What are natural resources?The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.
Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.
Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.
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How many electrons will an Oxygen (O) atom gain or lose in forming an ion?
Answers
Answer:
two electrons.... oxygen needs two electrons to attain stability
A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, at what temperature will this same xenon gas sample have a volume of 2.64 L?
Answers
Answer:
204.8 K
Explanation:
(P1 * V1)/T1 = (P2 * V2)/T2
"If the pressure remains constant" means
you can cancel the pressure part of the equation
T2 = (V2 * T1)/(V1)
T2 = (2.64 L * 453 K)/(5.82 L)
T2 = 204.8 K
chatgpt
A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, the temperature that will make this same xenon gas sample have a volume of 2.64 L is 220K.
What is combined gas law?The combined gas law is the law of of gaseous state which is made by combination of Boyle's law, Charle's law, Avogadro's law and Gay Lussac's law.
It is a mathematical expression that relates Pressure, Volume and Temperature.
(P1 × V1)÷T1 = (P2 × V2)÷T2
We can also use the following relation-
PV = nRT
At constant pressure,
V1÷T1 = V2÷T2
This is Charles's law.
V1 = 5.82L
T1 = 453K
V2 = 2.64L
T2 = ?
T2 = 220K
Therefore, A sample of xenon gas occupies a volume of 5.82 L at 453 K. If the pressure remains constant, the temperature that will make this same xenon gas sample have a volume of 2.64 L is 220K.
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The following are the conjugate bases of some strong and weak acids. Which of these would you expect to act as a base if placed in aqueous solution? (1) HCOO (ii) HCO3 (iii) HSO4 (iv) H2PO4 (v) Br" (vi) F a.(i),(ii),(iv), and (vi) onlyb. (i),(ii),(iii),(iv), and (vi) onlyc. (iii) onlyd. (i),(ii),(iii),(iv) onlye. all of them
Answers
Due to the strength of their conjugate acids, I would anticipate that I (ii), (iv), and (vi) would behave as bases if put in an aqueous solution. As both alternatives (a) and (d) contain the conjugate bases of weak acids, they are both accurate.
Strong acids' conjugate bases, such as (v) Br- and (vi) F-, cannot take any more protons since they are already fully deprotonated and cannot function as bases in aqueous solutions. Strong acids have conjugate bases that may receive protons and function as bases in aqueous solutions. These bases include I HCOO-, (ii) HCO3-, (iii) HSO4-, and (iv) H2PO4-. As both alternatives (a) and (d) contain the conjugate bases of weak acids, they are both accurate. Because (v) and (vi), which are conjugate bases of strong acids and cannot function as bases, are included in Option (b), it is wrong. Option (c) is untrue because it only accounts for the conjugate bases of strong acids and ignores those of weak acids.
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What is the Ka for an acid HA, if the equilibrium concentrations are [HA]=0.822 M, [H3O+]=1.15×10−4 M, and [A−]=1.15×10−4 M?
Report your answer in scientific notation.
Your answer should have three significant figures.