Answer:2 seconds
Explanation:
Una prenda de 320gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene 40 cm y gira con una frecuencia de 4 hz halla el periodo la velocidad angular la fuerza con la que gira la prenda y la velocidad lineal de la lavadora
Answer:
Período del tambor: \(T = 0.25\,s\), fuerza sobre la prenda: \(F \approx 80.852\,N\), velocidad lineal del tambor: \(v \approx 10.053\,\frac{m}{s}\), velocidad angular del tambor: \(\omega \approx 25.133\,\frac{rad}{s}\).
Explanation:
La expresión tiene un error por omisión, su forma correcta queda descrita a continuación:
"Una prenda de 320 gramos de ropa gira en el interior de una lavadora si dicha lavadora tiene un radio de 40 centímetros y gira con una frecuencia de 4 hertz. Halle a) el período, b) la velocidad angular, c) la fuerza con la que gira la prenda y d) la velocidad lineal de la lavadora."
El tambor gira a velocidad angular constante (\(\omega\)), en radianes por segundo, lo cual significa que la prenda experimenta una aceleración centrífuga (\(a\)), en metros por segundo al cuadrado. En primer lugar, calculamos el período de rotación del tambor (\(T\)), en segundos:
\(T = \frac{1}{f}\) (1)
Donde \(f\) es la frecuencia, en hertz.
(\(f = 4\,hz\))
\(T = \frac{1}{4\,hz}\)
\(T = 0.25\,s\)
Ahora determinamos la fuerza aplicada sobre la prenda (\(F\)), en newtons:
\(F = m\cdot a\) (2)
\(F = \frac{4\pi^{2}\cdot m \cdot r}{T^{2}}\) (2b)
Donde:
\(m\) - Masa de la prenda, en kilogramos.
\(r\) - Radio interior del tambor, en metros.
(\(m = 0.32\,kg\), \(r = 0.4\,m\), \(T = 0.25\,s\))
\(F = \frac{4\pi^{2}\cdot (0.32\,kg)\cdot (0.4\,m)}{(0.25\,s)^{2}}\)
\(F \approx 80.852\,N\)
La velocidad lineal de la lavadora es:
\(v = \frac{2\pi\cdot r}{T}\) (3)
(\(r = 0.4\,m\), \(T = 0.25\,s\))
\(v = \frac{2\pi\cdot (0.4\,m)}{0.25\,s}\)
\(v \approx 10.053\,\frac{m}{s}\)
Y la velocidad angular del tambor de la lavadora:
\(\omega = \frac{2\pi}{T}\)
(\(T = 0.25\,s\))
\(\omega = \frac{2\pi}{0.25\,s}\)
\(\omega \approx 25.133\,\frac{rad}{s}\)
You have viewed multiple unknown astronomical objects in this lab activity. In all tests, what was your test variable (independent variable)?
The amount of an element in each object
The type of elements in each spectrum
The astronomical object viewed by the spectrometer
Answer:
Could you give information about the lab
Explanation:
Answer:
The spectrum of each astronomical object
Explanation:
I took the test and got it right
a disc starts from rest with an angular acceleration completes 10 revolutions in 2 seconds. the time taken by it to complete 10 more revolution from that instant is
Starting from rest, the disc completes \(\theta\) revolutions after \(t\) seconds according to
\(\theta=\dfrac\alpha2t^2\)
with angular acceleration \(\alpha\). It completes 10 rev in 2 s, which means
\(10\,\mathrm{rev}=\dfrac\alpha2(2\,\mathrm s)^2\implies\alpha=5\dfrac{\rm rev}{\mathrm s^2}\)
Find the time it takes to complete 20 rev with this acceleration:
\(20\,\mathrm{rev}=\dfrac12\left(5\dfrac{\rm rev}{\mathrm s^2}\right)t^2\implies t=\sqrt8\,\mathrm s\approx2.83\,\mathrm s\)
so it takes approximately 0.83 s to complete 10 more rev.
Jamie lifts weight in the Olympics with power output of P
The efficiency of the lifting process is: η = U/W = mgh/Pt
In this case, the useful work output is the gravitational potential energy gained by the weight, which is given by:
U = mgh
The total work input is the power output multiplied by the time taken, which is given by:
W = Pt
where P is the power output and t is the time taken.
Therefore, the efficiency of the lifting process is:
η = U/W = mgh/Pt
Assuming no frictional losses, all the power output by Jamie goes into lifting the weight, so the efficiency is solely dependent on the work done and the power output.
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--The complete Question is, If Jamie lifts a weight of mass m a distance of h in time t with a power output of P, what is the efficiency of the lifting process? (Assuming no frictional losses) --
A 4.04 kg block slides down a smooth, frictionless plane having an inclination of 30◦. The acceleration of gravity is 9.8 m/s^2. The acceleration of the plane is 4.9
What is the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline?
Answer in units of N.
Answer:
Explanation:
What a lot of words to solve such a simple problem! The perpendicular force is the one that is pushing straight down on the plane. There is no side to side movement here or friction acting on this dimension at all. Perpendicular force is the same as the weight of the block. That's it! Perpendicular force is also normal force which is the same thing as weight:
w = mg so
w = (4.04)(9.8) and
w = 4.0 × 10¹ N
The magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N
The given parameter are:
mass M = 4.04 kg
Angle of inclination = 30 degree
Acceleration due to gravity = 9.8 m/s^s
To calculate the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the plane, The force will be the weight of the block which is equal to the normal reaction.
Normal N = mgcosФ
N = 4.04 x 9.8 x cos30
N = 34.28 Newtons
At all point in the plane, the magnitude of the perpendicular force that the block exerts on the surface of the plane will be the same.
Therefore, the magnitude of the perpendicular force that the block exerts on the surface of the plane at a distance of 2.37 m down the incline plane is 34.3N
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now add a fourth charged particle, particle 3, with positive charge q3 , fixed in the yz-plane at (0,d2,d2) . what is the net force f⃗ on particle 0 due solely to this charge? express your answer (a vector) using k , q0 , q3 , d2 , i^ , j^ , and k^ . include only the force caused by particle 3. view available hint(s)
The net force is F = k × q0 × q3 / 2×\(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^k)N
How to find the net force?
Coulomb's law states that the electrostatic force of attraction between two charges separated by a distance r, q 1 and q 2, is given by:
F = k (q1q2/r2)
Coulomb's constant k = 9×\(10^{9}\) Nm2/Kg2
Location of charge q3: P (0,d2,d2)
By Coulomb's law, the force on charge q0 due to q3 is:
F = k × q0 × q3 / \(d_{2} ^{2}\) × \(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^ k)
F = k × q0 × q3 / 2×\(d_{2} ^{2}\) × (1√2 ^j + 1√2 ^k)N
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Formation of a precipitate in a chemical reaction is considered a??
Answer: chemical change
Explanation: your answer for ck-12
The formation of a precipitate in a chemical reaction is considered a chemical change.
What is a Chemical reaction?A chemical reaction may be defined as a type of reaction that significantly involves a process that demonstrates the rearrangement of the molecular or ionic appearance of a substance, as distinct from an alteration in physical form or a nuclear reaction.
The formation of an insoluble compound will sometimes appear during a chemical reaction when a solution consisting of a particular cation is significantly mixed with another solution that consists of a specific anion.
This insoluble compound is known as a precipitate and will always form during a chemical reaction. The formation of this insoluble compound illustrates an example of chemical change.
Therefore, the formation of a precipitate in a chemical reaction is considered a chemical change.
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She specifically mentioned the sun's place on the HR diagram. Use your understanding of stellar evolution from class to elaborate further on what would likely have happened if the sun was brighter or dimmer than it is. What else would also change if the sun's brightness changed? What implications would those changes have for the planets in our solar system? Life on Earth?
Changes in the sun's brightness would have a major impact on the habitability of Earth and the other planets in the solar system.
In the HR diagram, the position of the sun determines its luminosity, surface temperature, and evolutionary stage. Changes in any of these parameters would have serious implications for life on earth, the other planets in our solar system, and the sun itself. If the sun were brighter or dimmer, the entire HR diagram would shift, and the sun would occupy a different location.
Brighter Sun:
If the sun were brighter, it would emit more energy and be positioned to the left of its current position on the HR diagram. This increase in brightness would cause life on Earth to become more challenging. The surface temperature of Earth would increase, leading to melting ice caps and rising sea levels. If the brightness of the sun increased by 150%, the temperature on Earth would be too hot to support life.
Dimmer Sun:
If the sun were dimmer, it would be positioned to the right of its current position on the HR diagram. This would cause temperatures on Earth to fall, resulting in a global cooling period. This would lead to the expansion of ice caps and a decrease in sea levels. If the sun's brightness decreased by 150%, Earth's climate would become too cold to support life. Thus, the amount of energy the sun produces has significant implications for life on Earth and the other planets in the solar system.
The intensity of sunlight reaching the surface of the Earth and other planets would be affected if the sun's brightness changed. This would have an impact on the planet's temperature, atmospheric composition, and weather patterns. The sun's brightness is a critical factor in determining the habitability of a planet.
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How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium
The height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.
Pressure and temperature at equilibrium
The relationship between pressure and temperature can be used to determine the height risen by the water.
\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\)
where;
V₁ = ALV₂ = A(L - y)P₁ = PaP₂ = Pa + ρghT₁ = 20⁰C = 293 KT₂ = 10⁰ C = 283 k\(\frac{PaAL}{T_1} = \frac{(P_a + \rho gh)A(L-y)}{T_2} \\\\\frac{PaL}{T_1} = \frac{(P_a + \rho gh)(L-y)}{T_2} \\\\L-y = \frac{PaLT_2}{T_1(P_a + \rho gh)} \\\\y = L (1 - \frac{PaT_2}{T_1(P_a + \rho gh)})\\\\y = 4.2(1 - \frac{101325 \times 283}{293(101325\ +\ 1000 \times 9.8 \times 100)} )\\\\y = 3.8 \ m\)
Thus, the height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.
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A diving bell is a 4.2 m -tall cylinder closed at the upper end but open at the lower end. The temperature of the air in the bell is 20 °C. The bell is lowered into the ocean until its lower end is 100 m deep. The temperature at that depth is 10°C. How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium?
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Please help me I swear will mark you brainiest
Answer:
C
Explanation:
please mark as brainliest
why is saturn almost as large in radius as jupiter despite its smaller mass?
Answer:
Saturn is almost as big as Jupiter despite its smaller mass because Jupiter is a more dense gas giant than Saturn.
Explanation:
If the rate at which the oceanic ridge is spreading is 5 cm/yr. How much farther (in kilometers) will continents A and B be from each other in one million years? Hint: Speed = Time Dis tan ce , so Distance = Speed × Time. 1 km=1000 m,1 m=100 cm. Show your work. (2)
In one million years, continents A and B will be 50 kilometers farther apart.
The rate at which the oceanic ridge is spreading is given as 5 cm/yr. To find how much farther continents A and B will be from each other in one million years, we can use the formula Distance = Speed × Time.
First, let's convert the speed from cm/yr to km/yr. Since 1 km = 1000 m and 1 m = 100 cm, we divide the speed by 100,000 to convert cm/yr to km/yr. Therefore, the speed is 5 cm/yr ÷ 100,000 = 0.00005 km/yr.
Next, we multiply the speed by the time (1 million years) to find the distance. Distance = 0.00005 km/yr × 1,000,000 years = 50 km.
Therefore, in one million years, continents A and B will be 50 kilometers farther from each other.
To summarize:
- Convert cm/yr to km/yr by dividing by 100,000.
- Multiply the speed in km/yr by the time (1 million years) to find the distance.
- The continents will be 50 kilometers farther from each other.
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A speeding Thunderbird left skid marks on the road that were 76.7 m long when it came to a stop. If the acceleration of the car was -10 m/s2, how fast was the car initially going?
Answer: 39.2 m/s
Explanation:
You can use the kinematic equation:
\(v_f^2=v_i^2+2a*d\)
We know the final velocity because it says it came to a stop. So now all we gotta do is plug in.
\(0^2=v_i^2+2(-10)(76.7)\\v_i^2=1,534\\v_i=\sqrt{1534} \\=39.166 m/s\)
whats the process to getting the answer
The third charge is in equilibrium, 2a/3
What is electric field?An electric property associated with each point in space when charge is present in any form.
The magnitude and direction of the electric field are expressed by the value of E, called electric field strength or electric field intensity or simply the electric field.
According to the question,
force on it due to +4e= force due to +e
\(\frac{ k(4e)q}{x^{2} } = \frac{ k(e)q}{(a-x)^2}\)
4(a-x)² = x²
2(a-x)=x
2a-2x =x
x= \(\frac{2a}{3}\)
Therefore,
The position along the line XY is \(\frac{2a}{3}\)
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Can someone help me out??? I need this done ASAP TYSM!!
Answer:
Answer is D
Explanation:
By changing the direction of the current moving through the wire will change polarity of the magnet but it will not affect the strength of the magnet.
 you have a battery in a lightbulb what else must you have to complete the circuit to light the bulb. Why is this component necessary?
Answer:
Wire
Explanation:
To make a complete circuit, you need to connect the battery, the wire, and the bulb so that electricity will have a path to flow from the bottom of the battery, through the wire, into the little wire on the side of the bulb, up that wire, through the filament, down the other bulb wire to the bottom of the bulb base
The purpose of a cell phone cover is to protect your phone from impact forces. How does a cell phone case do this?
Answer:
the material of the phone case
The purpose of a cell phone cover is to protect your phone from impact forces. It is done by absorbing the impact of force by back cover.
What is Force ?
Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s².
The case is made in such a way that, if the cell phone is dropped, the cover will absorb the kinetic energy of the falling phone by the means of deforming without transferring the impact onto the phone.
Cell phone cover is made up of rubber which can restore the forces like a spring. when u apply force to the rubber it get displaced and applied force is stored in the rubber. when cell phone drops, rubber of the cover absorbs the energy of impact. it also provides shied protection to the phone.
Hence this is how cell phone case do this.
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the manufacturer of a 12 v car headlight specifies it will draw a current of 6 a. you would like to check this claim with an ammeter designed to measure currents up to 10 a and having a resistance of 0.1 ohms. a. which of the two circuits in the attached figure represents a circuit where the ammeter correctly measures the current in the headlight? b) How much current (in A) would flow in the ammeter forCircuit a? c) How much current (in A) flows through the ammeter for Circuitb?
a) Circuit b represents a circuit where the ammeter correctly measures the current in the headlight.
b) The current flowing in the ammeter for Circuit a would be 6.67 A.
c) The current flowing in the ammeter for Circuit b would be 6 A.
To ensure that the ammeter correctly measures the current in the headlight, it should be placed in series with the headlight, as shown in Circuit b.
To calculate the current flowing through the ammeter in Circuit a, we can use Ohm's Law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance. In this case, the voltage across the headlight and the ammeter is 12 V, and the resistance of the ammeter is 0.1 ohms. Therefore, the current flowing through the ammeter would be I = V/R = 12/1.8 = 6.67 A.
To calculate the current flowing through the ammeter in Circuit b, we can use the same formula. Since the ammeter and the headlight are in series, they have the same current flowing through them. Therefore, the current flowing through the ammeter would be 6 A, which is the same as the current specified by the manufacturer.
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If the current in each wire is the same, which wire produces the strongest magnetic field?
-a wire that is 1mm thick and not coiled
-a wire that is 2mm thick and not coiled
-a wire that is 1-mm thick and coiled******
-a wire that is 2-mm thick and coiled
Answer:
Im pretty sure its c
Explanation:
Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q. Reason: The relation will hold even when Q is a null vector.
Answer:
The assertion is true and reason is false.
Explanation:
Assertion: I P+ Q I = I P- QI, then P must be perpendicular to Q.
Reason : The relation will hold even when Q is a null vector.
Now
\(\left | P + Q \right |=\left | P - Q \right |\\\\P^2 + Q^2 + 2 P Q cos \theta =P^2 + Q^2 - 2 P Q cos \theta\\\\4 P Q cos \theta = 0 \\\\cos \theta = 0 \\\\\theta = 90 degree\)
So, P and Q are perpendicular to each other.
So, the assertion is true.
Reason is false.
Explain how the law of conservation of energy applied to the energy transformations that occur from the outlet charger to the ringing phone
Answer: ELECTRICAL ENERGY to CHEMICAL ENERGY to SOUND ENERGY.
Explanation:
There are laws governing the conservation of energy in physics. The first law of thermodynamics states that in a closed system, energy can neither be created nor destroyed during transformation. With this, the total energy of a given system always remains constant.
This first law of thermodynamics which arouse from special relativity, says that changes in the energy of systems will also coincide with changes in a measure of its energy content.
The ELECTRICAL energy from the outlet charger is transformed and stored as CHEMICAL energy in the battery of the phone. This in turn is converted to SOUND energy when the phone rings.
A 23.6 kg girl stands on horizontal surface _ HINT (a) What is the volume of the girl's body (in m if her average density is 983 kg/m ? (b) What average pressure (in Pa) from her weight exerted on the horizontal surface if her two feet have combined area of 1.40 * 10 -? m2?
To calculate the volume of the girl's body, we can use the formula V = m/ρ, where m is the mass of the girl and ρ is her average density. Plugging in the given values, we get V = 23.6 kg / 983 kg/m³ = 0.024 m³.
The pressure exerted by the girl's weight on the horizontal surface can be calculated using the formula P = F/A, where F is the force exerted by her weight and A is the area of her two feet. To find the force, we can use the formula F = mg, where m is the girl's mass and g is the acceleration due to gravity (9.81 m/s²). Plugging in the given values, we get F = 23.6 kg * 9.81 m/s² = 231.516 N.
To find the pressure, we can now plug in the values for F and A: P = 231.516 N / 1.40 × 10⁻³ m² = 165,369 Pa. Therefore, the average pressure exerted by the girl's weight on the horizontal surface is 165,369 Pa.
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A- The volume of the girl's body is V = 0.024 m³.
b-the average pressure exerted by her weight on the horizontal surface is P = 165,714.29 Pa.
(a) To find the volume of the girl's body, we can use the formula:
V = m / ρ,
where V is the volume, m is the mass, and ρ is the density. Plugging in the given values:
V = 23.6 kg / 983 kg/m³ = 0.024 m³.
(b) The average pressure exerted by the girl's weight on the horizontal surface can be calculated using the formula:
P = F / A,
where P is the pressure, F is the force (weight), and A is the area. The force is given by the weight of the girl, which is F = m * g, where g is the acceleration due to gravity (g = 9.8 m/s²). The area is given as A = 1.40 × 10⁻² m². Plugging in the values:
P = (23.6 kg * 9.8 m/s²) / (1.40 × 10⁻² m²) = 165,714.29 Pa.
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A new ride being built at an amusement park includes a vertical drop of 70.0 meters. Starting from rest, the ride vertically drops that distance before the track curves forward. The velocity at the bottom of the drop is 12.0 m/s and the mass of the cart and passengers is 3.5 x 104 kg.
a. Calculate the potential, kinetic and total energy at the top.
b. Calculate the potential, kinetic and total energy at the bottom.
c.Is the total energy at the top equal to the total energy at the bottom? Justify your observation.
The potential, kinetic and total energy at the top are 2.38 x 10⁷ Joule, 0 Joule, 23.8 x 10⁶ Joule respectively and the potential, kinetic and total energy at the bottom are 0 Joule, 2.448 x 10⁶ Joule, 2.448 x 10⁶ Joule respectively. moreover the total energies are not same as not all potential energy converting into Kinetic energy of vertically drop of ride as the ride moves straight afterwards so that also need some energy which is again coming from potential energy.
Energies at the top:-
Potential energy = mgh
Potential energy = 3.4 x 10⁴ × 10 × 70 Joule
Potential energy = 2.38 x 10⁷ Joule
Kinetic Energy = (1/2) mv²
Kinetic Energy = (1/2) × 3.4 x 10⁴ × 0²
Kinetic Energy = 0 Joule
Total Energy = Potential Energy + Kinetic Energy
Total Energy = ( 23.8 x 10⁶ Joule ) + ( 0 Joule )
Total Energy = 23.8 x 10⁶ Joule
Energies at the bottom:-
Potential energy = mgh
Potential energy = 3.4 x 10⁴ × 10 × 0 Joule
Potential energy = 0 Joule
Kinetic Energy = (1/2) mv²
Kinetic Energy = (1/2) × 3.4 x 10⁴ × 12²
Kinetic Energy = 2.448 x 10⁶ Joule
Total Energy = Potential Energy + Kinetic Energy
Total Energy = ( 0 Joule ) + ( 2.448 x 10⁶ Joule )
Total Energy = 2.448 x 10⁶ Joule
The total energies are not the same since not all potential energy is converted into Kinetic energy of the vertical drop of the ride as the ride travels straight thereafter thus that also requires some energy which is again derived from potential energy.
So we have calculated the potential, kinetic and total energy at top and bottom both, and also stated the reason of why total energy at the top is not equal to the total energy at the bottom.
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The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for: A) photon effect. B) atmospheric window effect. C) greenhouse effect.
The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for the greenhouse effect, which is a key contributor to global warming and climate change. The atmospheric window effect and photon effect are related phenomena but do not directly contribute to the greenhouse effect.
The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for the greenhouse effect. This effect occurs when gases such as carbon dioxide, water vapor, and methane trap heat from the sun in the Earth's atmosphere, preventing it from escaping into space. This trapped heat leads to an increase in the average temperature of the Earth's surface, causing global warming and climate change.
The atmospheric window effect, on the other hand, refers to the phenomenon where certain wavelengths of radiation are not absorbed by the Earth's atmosphere, allowing them to pass through and escape into space. This occurs in the region of the electromagnetic spectrum where the atmosphere is relatively transparent, such as in the visible and near-infrared portions.
The photon effect, on the other hand, refers to the behavior of photons, which are packets of energy that make up electromagnetic radiation. The absorption of radiation by gases in the atmosphere occurs through the interaction of photons with molecules in the air. When a photon is absorbed, its energy is transferred to the molecule, causing it to vibrate and rotate. This can lead to changes in the temperature and chemical composition of the atmosphere.
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A variable resistor has a voltage of 12.0 V placed across it. If the resistance is increased 20%, what happens to the current flowing through it
Answer:
Explanation:
Remark
The answer is in the formula
E = I * R
E = the voltageI = the CurrentR = the ResistanceSolution
Let the resistance = R
I = 12/R
If we increase the resistance by 20% then we get
R1 = R + (20/100) * R
R1 = R + 1/5 * R
R1 = 6 R/5
What happens to I when you do this
I = 12/(6/5 R) Effectively you need to treat 6/5 as a reciprocal
I = 12 * 5/6 * R
I = 10 / R
What does this tell you? Since the Resistance has a base value of R, when increased by 20%, the numerator of the fraction is reduced to 10 from 12. In other words the current is now smaller when R goes up.
Two light waves of the same frequency start out in phase (with amplitudes going up at the same moment), and they interfere having traveled different distances. What happens if the path difference in the two waves is 600 nm and the wavelength of the light is 400 nm (blue light)
The path difference is 600 nm and the wavelength of the light is 400 nm (blue light). Since the path difference (600 nm) is not a multiple of the wavelength (400 nm), the two waves will interfere destructively,
When two waves of the same frequency and amplitude interfere, the resulting wave is determined by the phase difference between them. If the two waves are in phase when they start, then they will continue to be in phase until they encounter a path difference. In this case, the path difference is 600 nm, which is 1.5 times the wavelength of the blue light (400 nm).
When the two waves interfere, they will produce a pattern of interference known as a diffraction pattern. In this case, the path difference is large enough that the two waves will interfere destructively, meaning that the amplitudes of the waves will cancel each other out at certain points along the diffraction pattern. The exact locations of these points depend on the angle of incidence, but in general, they will be spaced at regular intervals corresponding to the wavelength of the light.
Therefore, when two light waves of the same frequency start out in phase and interfere having traveled different distances, if the path difference in the two waves is 600 nm and the wavelength of the light is 400 nm (blue light), the interference will be destructive and result in a diffraction pattern with points of cancellation spaced at regular intervals corresponding to the wavelength of the light.
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What is the acceleration of a car with the mass of 1’980 kg if it experiences a net horizontal force of 1’000 N
Answer:
See below
Explanation:
For the, just remember the equation
F = m a
1000 N = 1980 kg * a
1000/1980 = a = .505 m/s^2
A wire of resistance 27 ohm is folded 3 times find its new resistance
Answer:
New resistance = 243 ohm
Explanation:
Given:
Current resistance = 27 ohm
Computation:
The wire is extended to three times its initial size, and its cross-section is therefore shortened to one-third of how it used to be. We found the current resistance to be 3x3= 9 times
So,
New resistance = 27 x 9
New resistance = 243 ohm
What does Quantum mean?
a 0.33[kg] pendulum bob is attached to a string that is 1.2[m] long. what is the change in potential energy of the system as the bob swings from point a to point b?
The change in potential energy of the system as the pendulum bob swings from point A to point B is given by ΔU = mgΔh, where m is the mass of the bob, g is the acceleration due to gravity, and Δh is the change in height between A and B.
The potential energy of a pendulum depends on its height above some reference point. In this case, we can assume that the reference point is at the lowest point of the pendulum's swing, which we'll call point C. As the bob swings from point A to point B, it rises to a height h above point C. The potential energy gained by the bob is equal to the work done on it by gravity, which is given by mgh, where m is the mass of the bob, g is the acceleration due to gravity, and h is the height above point C. To calculate the change in potential energy, we need to subtract the potential energy at point A from the potential energy at point B. At point A, the bob is at its lowest point, so its potential energy is zero. At point B, the height above point C is h = L - Lcos(θ), where L is the length of the pendulum and θ is the angle between the string and the vertical. Thus, the change in potential energy is ΔU = mg(L - Lcos(θ)), where g = 9.81 \(m/s^2\).
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