What is the pH of a 0.300 M NH₃ solution that has Kb = 1.8 × 10⁻⁵ ? The equation for the dissociation of NH₃ is: NH₃ (aq) + H₂O (l) ⇄ NH₄⁺ (aq) + OH⁻ (aq)

We can see here that the catalytic cycle for the hydrogenation of alkenes using Wilkinson's catalyst involves several steps.

Here's an overview of the catalytic cycle, including the necessary details:

i. Chemical structure of the catalyst:

Wilkinson's catalyst, also known as chloridotris(triphenylphosphine)rhodium(I), has the following chemical structure: [RhCl(PPh3)3]

ii. Molecular geometry of the catalyst:

The Wilkinson's catalyst has a trigonal bipyramidal geometry around the rhodium center. The three triphenylphosphine (PPh3) ligands occupy equatorial positions, while the chloride (Cl) ligand occupies an axial position.

iii. Type of reactions involved:

The catalytic cycle involves several reactions, including:

iv. Starting material, reagent, and solvent:

The starting material is an alkene, and the reagent is Wilkinson's catalyst ([RhCl(PPh3)3]). The reaction is typically carried out in a suitable solvent, such as dichloromethane (CH2Cl2) or tetrahydrofuran (THF).

v. Major and minor end-products:

The major end-product of the hydrogenation reaction is the fully saturated alkane, resulting from the addition of hydrogen across the double bond. The minor end-product may include cis- or trans-configured alkanes if the original alkene substrate possesses geometric isomers.

vi. Intermediates:

The intermediates in the catalytic cycle include:

These intermediates play a crucial role in facilitating the hydrogenation reaction and enabling the catalytic cycle to proceed.

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The rock sample on the left is basalt, a type of igneous rock. Heat and intense pressure changed the basalt into blueschist, a type of metamorphic rock glaucophane schist

Blueschist facies is determined by the particular temprature and pressure condition required to metamorphose basalt to form blueschist and felsic rock and pelitic sediment which are subjected to blueschist facies condition will form different mineral assemblages then metamorphosed and blueschist facies rock are generally formed in subduction zones where oceanic crust is being stuffed into a trench that will become true blueschist once they were pressure cooked and also called glaucophane schist and is a metavolcanic rock that with similar composition at high pressure and low temprature

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The concentration of H₂SO₃ solution is equal to 0.123 M.

A neutralization reaction is described as a reaction in which an acid and base react to form salt and water. When a strong acid will react with a base then the salt which is formed can be neither acidic nor basic.

When H₂SO₃ (a strong acid) reacts with KOH, the resulting salt is K₂SO₃  and water.

H₂SO₃  +  2KOH   →   K₂SO₃  +   2H₂O

Given, the concentration of KOH = 0.235 M

The volume of the KOH = 65.25 ml = 0.06525 L

The number of moles of KOH, n = M × V = 0.235 × 0.06525 = 0.0153 M

The volume of the  H₂SO₃ = 62.4 ml = 0.0624 L

The number of moles of  H₂SO₃, n = 0.0153/2 = 0.00767 mol

The concentration of H₂SO₃ =0.00767/0.0624 = 0.123 M

Therefore, the molarity of  H₂SO₃ is 0.123 M.

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Answer:

Mass percent: 53.23%

Explanation:

Balancing the reaction in acidic medium:

Fe2+ → Fe3+ + 1e-

Cr₂O₇²⁻  → 2Cr³⁺

Cr₂O₇²⁻ → 2Cr³⁺ + 7H₂O  (Balancing oxygen)

Cr₂O₇²⁻  + 14H⁺ → 2Cr³⁺ + 7H₂O (Balancing protons)

Cr₂O₇²⁻  + 14H⁺ + 6e-→ 2Cr³⁺ + 7H₂O (Balancing charges)

To cancel the 6e-:

6 Fe2+ → 6 Fe3+ + 6e-

The balanced redox equation in acidic medium is:

6Fe²⁺ + Cr₂O₇²⁻ + 14H⁺ → 6Fe³⁺ + 2Cr³⁺ + 7H₂O

We need to find moles of potassium dichromate used to reach the final point in the titration. Then, using the chemical equation, we can find moles of Fe²⁺. With its molar mass (Molar mass Fe: 55.85g/mol)b we can find mass of Fe²⁺ in the iton ore and its mass percent:

Moles potassium dichromate:

28.72mL = 0.02872L * (0.05051mol / L) = 1.4506x10⁻³ moles K₂Cr₂O₇

Moles Fe²⁺:

As 6 moles of Fe²⁺ reacted per mole of K₂Cr₂O₇:

1.4506x10⁻³ moles K₂Cr₂O₇ * (6 moles Fe²⁺ / 1 mole K₂Cr₂O₇) = 8.7039x10⁻³ moles Fe²⁺

Mass Fe²⁺:

8.7039x10⁻³ moles Fe²⁺ * (55.845g / mol) = 0.4861g of Fe²⁺

Mass percent:

As the sample of iron ore weighs 0.9132g. Mass percent is:

0.4861g of Fe²⁺ / 0.9132g * 100

The mass percentage of the iron in the sample is 53.7%.

The balanced redox reaction equation is;

6Fe2+(aq) + Cr2O7^2-(aq) + 14H^+(aq)→ 6Fe3+(aq) + 2Cr3+(aq) + 7H2O(l)

The number of moles of dicromate ion is; 28.72/1000 L × 0.05051M

= 0.00145 moles

Now;

6 moles of Fe2+ reacts with 1 mole of dichromate ion

x moles of  Fe2+ reacts with 0.00145 moles of dichromate ion

x = 6 moles × 0.00145 moles/1 mole

x = 0.0087 moles

Mass of iron = 0.0087 moles × 56 = 0.49 g

Mass percent of iron = 0.49 g/0.9132 g × 100/1

= 53.7%

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

I guess option \(b) \:CCl_4\)  is the correct choice.

Explanation:

Carbon tetrachloride \((CCl_4)\) is a non-polar solvent. Therefore, the non-polar substance will be most soluble in \(CCl_4\).

Best Regards!

The percentage left is 57%.

We know that a fraction is a part of a whole. Let us in this case take the whole as one and then the fraction that we remove out of it is 3/7. We now have to find the percentage that remains.

Thus'

Fraction that remains = 1 - 3/7 = 4/7

Hence;

Percentage that is left = 4/7 * 100

= 57%

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Answer:

i think the answer is... A

Answer:

The conservation of momentum states that, within some problem domain, the amount of momentum remains constant; momentum is neither created nor destroyed, but only changed through the action of forces as described by Newton's laws of motion. ... Momentum is conserved in all three physical directions at the same time.

The temperature of the water in the teapot increases by 10 degrees Celsius when 5000 calories of heat are added to it.

To calculate the increase in temperature of the water, we need to use the specific heat capacity of water, which is approximately 1 calorie/(gram * degree Celsius). We also need to know the mass of the water in grams since the calorie unit is based on grams.

The volume of water in the teapot is given as 500 milliliters. We can convert this to grams using the density of water, which is 1 gram/mL. Therefore, the mass of water in the teapot is:

500 mL * 1 g/mL = 500 grams

The amount of heat added to the water is 5000 calories. We can use the equation:

Q = m * c * ΔT

where Q is the amount of heat, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

Rearranging this equation to solve for ΔT, we get:

ΔT = Q / (m * c)

Substituting the given values, we get:

ΔT = 5000 calories / (500 grams * 1 calorie/(gram * degree Celsius)) = 10 degrees Celsius

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From the equation of the reaction; for every 1 mole of copper, the reaction uses 2 moles of silver nitrate.

A chemical reaction involves the transformation of one chemical specie into another. The reaction is not shown here hence the question is incomplete.

However, the reaction should be of the sort; Cu + 2AgNO3 ---> Cu(NO3)2 + Cu. Thus, for every 1 mole of copper, the reaction uses 2 moles of silver nitrate.

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Answer:

Al = 13.4%  Cr = 38.8%  O = 47.7

Aluminium Chromium Oxygen

Explanation:

im so sorry if i am wrong

Answer:

Animals benefit from photosynthesis, because they consume the plants and therefore the sugars stored in the plants from the process of photosynthesis for energy

Explanation:

The heating curve of water is the temperature of a given volume of water changes as heat is added at a consistent pace, as shown by the water heating curve. The temperature of the water does not vary throughout a phase shift, creating a plateau on the graph.

A meniscus is a curvature that appears on the surface of a molecular substance (water, of course) when it comes into contact with another material. You may imagine that happening with water when it adheres to the interior of a glass.

Hence, The relationship between the supply temperature of the heating system and the outside air temperature is known as the heating curve. The CH boiler's ability to heat water to a specific temperature at a specific outside temperature is determined by the heating curve.

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Regardless of size, shape, or substance of construction, heavy objects sink while light objects float. A floating object must be entirely above the liquid's surface to qualify as such.

According to its size, something's density tells us how heavy it is. When placed in water, a dense object will float if it is less dense than the water, and vice versa if it is more dense.

To be more precise, when submerged in water, a weighted object sinks until it moves the same volume of water as it does. Objects drop farther the more mass they possess. Until it moves 1 g of water, a 1 g object will bob up and down. Until 2 g of water are moved, a 2 g object will float.

Regardless of their size, form, or type of construction material, heavy items sink and light objects float. An item must be entirely above the liquid's surface in order to be considered to be floating. There must be some trapped air in every thing that floats; this is the only explanation.

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Answer:

Most especially, solutions lose color when;

\({}\)

Answer:

10.5%

Explanation:

The equation used to calculate mass percent by volume is:

                                        Mass Solute (g)
Mass/Volume %  =  -----------------------------------  x  100%
                                   Volume Solution (mL)

In this case, the solute is the glucose. You can plug the given values into the equation and solve.

                                      34.1 g C₆H₁₂O₆
Mass/Volume %  =  -------------------------------  x  100%
                                        325 mL soln

Mass/Volume %   =  0.105 x 100%

Mass/Volume %  =  10.5%

Answer:

The maximum number of valence electrons is 8

Explanation:

element 3 has 3 valence electrons. 7 has 5, and 10 has 8, as we increased the number of electrons in element 11, the number of valence electrons became 3, and the pattern went on, it cannot exceed 8.

The electron configuration of an atom depicts the arrangement of electrons scattered throughout the orbital shells and subshells.

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Option C) New atoms are created when a new substance is formed is not true about the Law of Conservation of Mass.

The Law of Conservation of Mass states that "Mass can neither be created nor be destroyed". This means that the mass of an object will remain the same, regardless of the changes that occur to its form or composition. The law is a fundamental principle of physics and chemistry and is used to calculate the amount of matter that is present in a given sample.

The same number of atoms are in both the products and reactants as the mass of the reaction is conserved.

Since the same number of atoms are present in both reactants and products, then no new atoms or compounds are created in the process.

Hence, the correct option is C).

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Avogadro's numbers are used to convert the moles, atoms, and molecules. There are 51.17 × 10²¹ molecules in 8.5 x 10⁻² moles of HF.

Avogadro's number converts the moles into molecules with the help of the value of the Avogadro's number as 6.02 x 10²³.

We know that 1 mole of HF has 6.02 x 10²³ molecules

Then, 8.5 x 10⁻² moles of HF will have:

(8.5 x 10⁻²) × 6.02 x 10²³ = 51.17 × 10²¹ molecules.

Therefore, 51.17 × 10²¹ molecules are present in 8.5 x 10⁻² moles of HF.

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The heat released by each molecule, in joules, when ethanol undergoes complete  combustion is 2.28 × \(10^-18\) J.

The number of moles in 1.00 g  of ethanol is obtained from;

Mass of ethanol/molar mass of ethanol

Molar mass of ethanol = 46.07 g/mol

Number of moles =  1.00 g/46.07 g/mol = 0.022 moles of ethanol

1 mole of ethanol contains 6.022 × \(10^23\) molecules

0.022 moles of ethanol contains  0.022 moles ×  6.022 × \(10^23\) molecules/1 mole

=  1.32 × \(10^22\) molecules of ethanol

If 1.32 × \(10^22\) molecules of ethanol release  29.8 × \(10^3\) J of heat

1 molecule of ethanol will release 1 molecule × 29.8 × 10^3 J / 1.32 × \(10^22\)

=  2.28 × \(10^-18\) J

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Answer:

a) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶

b) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶

c) 1s²

d) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

e) 1s² 2s² 2p⁶

f) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰

g) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰

h) 1s² 2s² 2p⁶

j) 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 4d¹⁰

k) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁶

l) 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰

Answer:

A

Explanation:

because on the first alphabet they've been specific of the weather partaking in the area

Answer:

A. True

B. True

2. It losses energy as heat.

Explanation:

Internal energy is the sum of the potential and kinetic energy of all the particles in the system that form the system.

2. Atoms in a chemical system consist of nucleus which are positively charge and the electrons surrond it which are negatively charged. The protons are positively charged and the neutrons are neutral and this require energy to move, a change in the internal energy convert it to work.

Statement that there is equality between internal energy ( E ) of a chemical system as well as sum of the kinetic and potential energies is True.

Statement that the summation of all the energies in the system is regarded as Thermal energy as a result of motion is True.

The statement that energy in a chemical system is formed due to arrangement of the nuclei and electrons within an atom is True.

When a gas is produced from chemical reaction , the newly produced gas will create a space for itself by pushing atmosphere a way and energy will be lose as Heat.

It can be concluded that the energy in chemical system can be occur as a result of arrangement of the nuclei and electrons within an atom

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We must take into consideration the balance of atoms and charges in order to balance the half-reaction for the conversion of S2O3 2- to S4O6 2- in acidic solution.

Write the imbalanced half-reaction as the first step.

S2O3 S4O6 2- (aq)

Step 2: Align the atoms, with the exception of hydrogen and oxygen.

2S4O6 2-(aq) = S2O3 2-(aq)

Step 3: Add water (H2O) to balance the oxygen atoms.

2S4O6 2- (aq) + H2O = S2O3 2- (aq)

Step 4: Add hydrogen ions (H+) to balance the hydrogen atoms.

2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq)

Step 5: Add more electrons (e-) to balance the charge.

2S4O6 2- (aq) + H2O = S2O3 2- (aq) + 4H+ (aq) + 2e-

The balanced half-reaction in acidic solution is:

S2O3 2- (aq) + 4H+ (aq) + 2e- → 2S4O6 2- (aq) + H2O

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Answer:

Its C

Explanation:

The mass of 0.550 mol of methanol, CH3OH, is 17.6 g

To find the mass of 0.550 mol of methanol, CH3OH, we need to use the molar mass of CH3OH. The molar mass is the sum of the atomic masses of each element in the molecule, which can be found on the periodic table.
For CH3OH, we have:

- Carbon (C): 12.01 g/mol
- Hydrogen (H): 1.01 g/mol (there are 4 hydrogen atoms in CH3OH)
- Oxygen (O): 16.00 g/mol

So the molar mass of CH3OH is:

12.01 g/mol + (1.01 g/mol x 4) + 16.00 g/mol = 32.04 g/mol

This means that one mole of CH3OH weighs 32.04 grams.

To find the mass of 0.550 mol of CH3OH, we can use the following formula:

mass = number of moles x molar mass

So the mass of 0.550 mol of CH3OH is:

0.550 mol x 32.04 g/mol = 17.62 g

Rounding this to three significant figures gives us:
17.6 g

Therefore, the mass of 0.550 mol of methanol, CH3OH, is 17.6 g (rounded to three significant figures).

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation: