what is the post processing for selective laser sintering (sls)?

Answer:

busway

Explanation:

Answer:

A cost is something you have to give up or sacrifice and a benefit is something that is gained or is helpful.

Explanation:

In a cost-benefit analysis of a system, an engineer is to simply look at the requirements for the system and determine the costs to build the system, both in financial value and energy value.  Additionally, the engineer needs to determine the benefits that would come from choosing a particular path of cost.  If the benefits outweigh the cost for the project, then the solution is accepted.  Else, the cost outweighs the benefit and the solution is rejected.

No, G1 cannot move C onto the table at the same time G2 moves A onto B according to the ASP formalization. This is because in the ASP formalization, there is a rule that states that only one gripper can move an object at a time. Therefore, it is not possible for G1 and G2 to move objects simultaneously.

This rule ensures that the system is deterministic and predictable, meaning that all of the objects in the system will always be in a known state. This is important for ensuring the safety of the system and its objects, as well as for ensuring efficiency and accuracy in its operations. Additionally, it prevents conflicts from occurring, as two objects cannot occupy the same space at the same time. This rule is also important for ensuring that the system is able to achieve its objectives in the most efficient and accurate way possible.

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Using α = 0.4, the forecasted sales for 2011, 2012, and 2013 would all be $48,000, which is the same as the actual sales in 2009.

Using α = 0.8, the forecasted sales for 2011, 2012, and 2013 would also be $48,000.

In both cases, the forecasts for 2011, 2012, and 2013 remain the same as the actual sales in 2009 due to the zero difference between the actual and forecasted sales values.

To forecast sales for 2011, 2012, and 2013 using exponential smoothing, we need to apply the formula:

Forecast for the next period = Previous period's forecast + α * (Actual value - Previous period's forecast)

Given that the actual 2009 sales are $48,000 and are considered the forecast for 2010, we can calculate the forecasts for subsequent years using different values of α.

(a) For α = 0.4:

- Forecast for 2011 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000

- Forecast for 2012 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000

- Forecast for 2013 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000

Using α = 0.4, the forecasted sales for 2011, 2012, and 2013 would all be $48,000, which is the same as the actual sales in 2009.

(b) For α = 0.8:

- Forecast for 2011 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000

- Forecast for 2012 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000

- Forecast for 2013 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000

Using α = 0.8, the forecasted sales for 2011, 2012, and 2013 would also be $48,000.

In both cases, the forecasts for 2011, 2012, and 2013 remain the same as the actual sales in 2009 due to the zero difference between the actual and forecasted sales values.

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Answer:

P1+1/2pv2/1+pgh1=P2+1/2pv2/2+pgh2

During gait the body of a living organism is gaining speed: a. during terminal stance.

Physical fitness can be defined as a measure of both the physical and mental soundness (wellness) or ability of an individual to engage in physical exercises, sports, work and other day-to-day activities.

For instance, one of the ways in which an individual can model good physical fitness to other individuals in their neighborhood is by:

Gait can be defined as the way and manner in which an animal or individual walks or runs, thereby affecting and altering the shape of the body.

In this context, we can infer and logically deduce that during gait the body of a living organism is gaining speed, especially during terminal stance.

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Answer:

with turbo or nos

Explanation:

Answer: The process of data analysis uses analytical and logical reasoning to gain information from the data. The main purpose of data analysis is to find meaning in data so that the derived knowledge can be used to make informed decisions.

To modify the given HTML file to look like the web page, add the following CSS rules to the embedded stylesheet:

1. Add an ID selector for the ID game-table and use the border property to add a 2px solid border using the color from the CSS variable --table-color. Also, center all text using the text-align property and set a height of 200px and width of 400px.

2. Use a descendant selector that targets the inside the  and use the text-transform property to make the caption UPPERCASE. Set the background color using the CSS variable --table-color, font color to white and add 10px padding.

3. Use a pseudo-class selector :nth-child(even) for  and set the background color using the CSS variable --row-bg-color.

Step by step explanation:

1. Add the following CSS rules for the ID selector #game-table:
#game-table {
 border: 2px solid var(--table-color);
 text-align: center;
 height: 200px;
 width: 400px;
}

2. Use a descendant selector to target the inside the and add the following CSS rules:
#game-table caption {
 text-transform: uppercase;
 background-color: var(--table-color);
 color: white;
 padding: 10px;
}

3. Use a pseudo-class selector :nth-child(even) to target the even rows of the table and add the following CSS rule:
#game-table tbody tr:nth-child(even) {
 background-color: var(--row-bg-color);
}

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Answer:

Is there supposed to be a picture...try asking question again

TACACS+: A TCP-based access control protocol that enables a device to send a user's username and password to an authentication server in order to assess whether access is permitted.

If set up in this way, TACACS+ itself can function as an authentication server. Additionally, TACACS+ can offer services for accounting and authorization. The TACACS+ daemon is normally operating on a UNIX or Windows workstation, and TACACS+ services are kept up to date in a database on a server.

It offers distinct and modular facilities for authentication, authorization, and accounting. The TACACS+ daemon, a single access control server, enables autonomous provision of each service for authentication, authorization, and accounting. To benefit from various services offered on that server or on the Internet, each service can be connected to its own database.

Depending on the daemon's capabilities, a network. With the help of a single administration service, TACACS+ aims to offer a solution for managing numerous network access points.

1. Its architecture is client-server-based.

2. The Authentication Service (AS) and the Ticket Granting Service are implemented by the Kerberos server, also known as KDC (Key Distribution Cater) (TGS).

3. When a client communicates with an application server utilizing Kerberos tickets for authentication, the phrase "application server" normally refers to a Ferberized program. An example of an application server is the Kerberos telnet daemon (telnets).

4. Passwords are not transmitted over the network, in contrast to other authentication protocols (FTP, PAP, etc.) that do so.

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To compute the average flow time after each job is completed, we can use the following steps:1. Calculate the completion time for each job by summing up the processing times of all previously completed jobs.

2. Compute the average flow time by dividing the total completion time by the number of completed jobs.

Here are the calculations:

Job    | Processing Time | Completion Time | Average Flow Time

--------------------------------------------------------------

 1              80                 80                  80/1 = 80

 2             140               220                 220/2 = 110

 3             230               450                 450/3 = 150

 4             100               550                 550/4 = 137.5

 5             120               670                 670/5 = 134

 6             110               780                 780/6 = 130

The average flow time after each job is completed is as follows:

Job 1: Average flow time = 80 minutes

Job 2: Average flow time = 110 minutes

Job 3: Average flow time = 150 minutes

Job 4: Average flow time = 137.5 minutes

Job 5: Average flow time = 134 minutes

Job 6: Average flow time = 130 minutes

Using the SPT (Shortest Processing Time) rule, the jobs would be processed in the following order:

Job 1 -> Job 4 -> Job 6 -> Job 5 -> Job 2 -> Job 3

After each job is completed, the average flow time is recalculated as shown above.

Comparing the average flow times calculated using the original numerical order and the SPT rule, we can see that the SPT rule minimizes the average flow time and gets the most work done in the least amount of time.

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AASHTO assumes a deceleration value in calculating stopping sight distance (SSD) of B. 11.2 ft/s^2. This doesn't take any road defects into account.

To plot the bending stress profile, create a simple graph with y as the horizontal axis and sigma as the vertical axis. The values at A, B, C, and D can be indicated on the graph.

To compute the bending stress profile, we need to determine the maximum moment of inertia and the distance of the extreme fibers from the neutral axis.

Assuming that the cross-section is symmetric and uniform, we can determine the moment of inertia as follows:

I = 2[(1/2)(1)^3(0.125) + (1/2)(1)^3(0.125)] + (1)(1)(0.5)^3

I = 0.21875 in^4

The distance from the neutral axis to the extreme fibers is half of the height of the cross-section, which is 0.5 inches.

Using the bending stress formula:

sigma = M*y/I

where M is the applied moment, y is the distance from the neutral axis, and I is the moment of inertia.

Computing the bending stress at each point of interest:

At point A (y = 0.5 inches), sigma = (-50 kip-in)(0.5 in)/(0.21875 in^4) = -228.57 psi

At point B (y = 0.25 inches), sigma = (-50 kip-in)(0.25 in)/(0.21875 in^4) = -457.14 psi

At point C (y = 0 inches), sigma = (-50 kip-in)(0 in)/(0.21875 in^4) = 0 psi

At point D (y = -0.25 inches), sigma = (-50 kip-in)(-0.25 in)/(0.21875 in^4) = 457.14 psi

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Answer:

the SI base unit of electrical current.

Answer:

An ampere is the SI base unit of electrical current

Answer:

Explanation:

A torch with an additional bulb. ...

Wheel chair convertible to crutches. ...

Pen to check concentration. ...

Bulb/CFL remover/connector. ...

Multicolor headphone wires. ...

Adjustable electricity extension board. ...

Automatic blade swinging ceiling fan for easy cleaning

Answer:

static electricity

Explanation:

depending on what grade u are on

the reason why is because of that answer is because it sticks to your hair and u can zap people a little a least it feels like a pinch

Answer:

a. 115

b. 135

c. 220

d. 185

Explanation:

Spheriodite is microscopic constituents in some steels which is composed of spherically shaped cementide particle. It is most ductile and softest type of steel. Pearlite is two phased lamellar compose of alternating layer of ferrite and cementite. It is hard and strong but not tough. It is applied on cutting tools like chopper, blades and knives.

Answer:

peak-hour volume = 1890 veh/h

Explanation:

Determine the peak-hour Volume

Applying the equation below

Vp =  v / ( PHF * N * Fg * Fdp )  -------------- ( 1 )

where :

Vp = 1250

v ( peak - hour volume ) =  ?

PHF ( peak hour factor ) = 0.84

N  = 2 lanes per direction

Fg ( grade adjustment for rolling terrain ) = 0.99 ≈ 1

Fdp = 0.90

Back to equation 1

v = Vp (  PHF * N * Fg * Fdp )  

  = 1250 ( 0.84 * 2 * 1 * 0.90 )

  = 1890 veh/h

Answer:

10 ohms Ω

Explanation:

V = IR

120 = I(12)

120/12 = 10Ω

Answer:

The appropriate answer is "0.0043".

Explanation:

The given values is:

Error probability,

p = 0.01

Received digits,

n = 10

and,

\(x\sim Binomial\)

As we know,

⇒  \(P(x)=\binom{n}{x}p^xq^{n-x}\)

Now,

⇒  \(P(x >1) =1- \left \{ P(x=0)+P(x=1) \right \}\)

⇒                 \(=1-\left \{\binom{10}{0}(0.01)^0(0.99)^{10-0}+\binom{10}{0}(0.01)^1(0.99)^{10-1} \right \}\)

⇒                 \(=1-0.9957\)

⇒                 \(=0.0043\)

The expected value of the difference between the strength of a cable and the weight of a light fixture cannot be determined without specific information about their probability distributions.

The expected value is a measure of central tendency that represents the average value we would expect to obtain from a random variable. To calculate the expected value of the difference between the strength of a cable and the weight of a light fixture, we would need to consider the probability distribution associated with each variable.

If we have the probability distributions for the strength of the cable and the weight of the light fixture, we can calculate the expected value by taking the difference between the two variables and multiplying it by the corresponding probabilities. We would sum up these products for all possible values of the variables.

However, without specific information about the probability distributions or any assumptions made, we cannot calculate the expected value. The expected value would vary depending on factors such as the variability and correlation between the strength of the cable and the weight of the light fixture.

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1) the sketch of thetypical GSM TDMA frame is attached accordingly.

2) a) Tail bits -  Provide synchronization and signal recovery in frame transmission.

b) Stealing bits -  Control purposes   by taking bits from payload data.

c) Training sequence -  Predefined patterns for channel estimation and synchronization.

d) Guard bits -  Reduce interference and fading effects in communication channels.

e) Data bits scenarios -  Transmit user data, control info, error correction codes, etc.

a) Tail bits -  Tail bits are used indigital communications to ensure proper synchronization and signal recovery by providing a known pattern at the end of a frame.

b) Stealing bits -  Stealing   bits are used in certain encoding schemes to steal bits from the payload for control purposes, such as error detection or channel coding.

c) Training sequence -  Training sequences are predefined patterns inserted in a data frame tofacilitate channel estimation, equalization, or synchronization in communication systems.

d) Guard bits -  Guard   bits, also known as guard intervals, are inserted between symbols or frames to mitigate the effects of inter-symbol interference or multipath fading in communication channels.

e) Possible scenarios for   data bits usage -  Data bits in a frame can be used for various purposes, including transmitting user data, control information, error correction codes,synchronization markers, addressing, or any other relevant information needed for the specific communication protocol or application.

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Answer:

False

Explanation:

As seen in the diagram, electrons are rotating around the nucleus and are, therefore, not part of the nucleus.

The precursor to modern operating systems that allowed programs to be processed without human interaction is B) batch processor.

A batch processor is a system that processes a collection of jobs or programs in a sequential manner, without requiring constant human intervention. It allows multiple programs or jobs to be submitted for execution as a batch, and the system automatically executes them one after another without the need for manual intervention between jobs.

In a batch processing environment, programs are typically stored on punched cards, magnetic tapes, or other storage media. The batch processor reads the programs and data from the storage media, executes the programs, and produces the desired output. This process continues until all the jobs in the batch have been processed.

Batch processing was a significant advancement in the early days of computing when computers were primarily used for scientific and business applications. It allowed programs to be executed without the need for constant human attention, thereby improving efficiency and productivity.

Resident monitor (A) refers to a portion of the operating system that remains in memory at all times and provides basic system services. Middleware (C) refers to software that acts as an intermediary between different applications or systems, facilitating communication and data exchange. Spooling (D) stands for "Simultaneous Peripheral Operation On-Line" and refers to a technique used to improve input/output performance by storing data in a buffer before it is processed.

Among the given options, batch processor (B) is the best choice as the precursor to modern operating systems that enabled automated, non-interactive processing of programs.

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Technician B says that a weak pump could be the cause. Tech a technician is correct.

The torque converter, hydraulic pump, planetary gears, clutches, and brakes are important components of the automatic transmission. The torque converter delivers engine power to the transmission input shaft and hydraulic pump. The planetary gears are arranged in a series, one after the other.

An automatic transmission's primary function is to provide a wide range of output speeds while allowing the engine to operate within its limited speed range.

Question incomplete:

Two technicians are discussing what could be wrong with a hydraulically controlled automatic transmission/transaxle that does not shift out of first gear regardless of vehicle speed. Technician A says that a defective governor could be the cause. Technician B says that a weak pump could be the cause. Which technician is correct?

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Answer:

The above three conditions are commonly referred to as the equations of equilibrium for planar structures. ∑ Fx and ∑ Fy are the summation of the x and y components of all the forces acting on the structure, and ∑ Mz is the summation of the couple moments and the moments of all the forces about an axis z, perpendicular to the plane xy of the action of the forces.

Explanation:

The reinforcement must be stored in such a manner as to prevent: deterioration and corrosion.

Concrete reinforcement is accomplished by inserting deformed steel bars or welded wire fabric inside newly cast concrete. The goal of reinforcing is to give strength to concrete where it is required.

All exposed reinforcing surfaces should be carefully cleaned of loose mortar, corrosion, and other pollutants. To prevent overbuilding and limit bond development loss at rebar deformations, the high-performance protective coating should be placed at a thickness of 305 microns.

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Full Question:

What are the words that complete the sentence below:

The reinforcement must be stored in such a manner as to prevent: