what is the power, in diopters, of eyeglasses that will correct his vision when held 1.50 cm from his eyes?

Answers

Answer 1

To calculate the power, in diopters, of eyeglasses that will correct vision when held 1.50 cm from the eyes, you need to know the individual's refractive error in diopters.

Refractive error refers to the degree of near sightedness (myopia), farsightedness (hyperopia), or astigmatism that an individual has. This value is typically measured by an optometrist or ophthalmologist using a phoropter.

Once the refractive error is known, the power of the corrective eyeglasses can be determined by dividing the refractive error by the distance (in meters) between the glasses and the eyes. In this case, since the glasses are held 1.50 cm from the eyes, the distance in meters would be 0.015 meters.

For example, if the individual has a refractive error of -2.00 diopters, the power of the corrective eyeglasses when held 1.50 cm from the eyes would be -2.00 / 0.015 = -133.33 diopters.

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Related Questions

The measured index of refraction of x-rays in rock salt is less than one. this is consistent with the theory of relativity because?

Answers

The measured index of refraction of x-rays in rock salt is less than one. this is consistent with the theory of relativity because Vp is phase velocity. Vp does not represent the particle velocity. The physical speed of the particle is represented by group velocity, Vg.

What is a refractive index?

The refractive index of an optical medium is a dimensionless number that indicates how well that medium bends light in optics. The refractive index controls how much light is refracted or twisted when it enters a substance.

Index of refraction, n = c/v

For X-rays, n is 1 → v > c (violates the theory of special relativity) However, this is ok because in this case, Vp is phase velocity. Vp does not represent the particle velocity. The physical speed of the particle is represented by group velocity, Vg.

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Calculate the momentum of a high-speed
"bullet train" with a mass of 9.2 X 108 kg
moving at a speed of 61 m/s.

Answers

The momentum of the bullet train is  60,609.6 kgm/s

What is momentum?

Momentum is define as  the quantity of motion that an object has.

Mathematically ,

The momentum of an object is equal to the mass of the object times the velocity of the object.

Momentum = Mass x Velocity

It is denoted by P

P = m x v

According to the question .

Mass of bullet train is 9.2 X 108 kg

Speed or velocity of bullet train is 61 m/s

P = 9.2 X 108 kg x 61 m/s

P = 60,609.6 kgm/s

So , the momentum of the bullet train is  60,609.6 kgm/s

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A transformer has 1,000 turns of wire in the primary coil and 50 turns in the secondary coil. If the input voltage is 2,400 V, what is the output voltage? - this is for my physical science class

Answers

the output voltage of the transformer that has 1,000 turns of wire in the primary coil and 50 turns in the secondary coil is 120 V

What is a transformer?

A transformer is an electrical device that transfer electric energy from one circuit to another.

To calculate the output voltage of the transformer, we use the formula below.

Formula:

V/V' = N/N'........... Equation 1

Where:

V = Primary/input VoltageV' = Secondary/output voltageN = Primary turnsN' = Secondary turns

Make V' the subject of the equation

V' = VN'/N........... Equation 2

From the question,

Given:

V = 2400 VN' = 50 turnsN = 1000 turns.

Substitute these values into equation 2

V' = (2400×50)/1000V' = 120 V

Hence, the output voltage of the transformer that has 1,000 turns of wire in the primary coil and 50 turns in the secondary coil is 120 V.

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a transverse traveling sinusoidal wave on a string has a frequency of 100 hz, a wavelength of 0.040 m and an amplitude of 2.0 mm. the maximum velocity of any point on the string is

Answers

The maximum velocity of any point on the string is approximately 1.2566 m/s.

We want to find the maximum velocity of any point on a string with a transverse traveling sinusoidal wave, given the frequency of 100 Hz, a wavelength of 0.040 m, and an amplitude of 2.0 mm.

Convert the amplitude from mm to m.
Amplitude = 2.0 mm = 0.002 m

Calculate the angular frequency (ω) using the given frequency (f).
ω = 2πf
ω = 2π(100 Hz)
ω = 200π rad/s

Use the formula for the maximum velocity (Vmax) of any point on the string in a sinusoidal wave:
Vmax = ω * amplitude

Plug in the values for ω and amplitude to find Vmax.
Vmax = (200π rad/s) * (0.002 m)
Vmax ≈ 1.2566 m/s

Therefore, any point on the string can move at a maximum velocity of about 1.2566 m/s.

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an ac sine wave with an rms value of 120vac is connected to a full-wave rectifier. what is the average dc voltage

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The average DC voltage would be approximately 0.9 times the RMS value of the original AC waveform, which is 108VDC.

A full-wave rectifier converts an AC waveform into a unidirectional waveform, typically using diodes. In the case of a full-wave rectifier, both the positive and negative half cycles of the AC waveform are rectified. This means that the negative half cycles are flipped to become positive.

When the AC sine wave with an RMS value of 120VAC is rectified, the resulting waveform consists of positive half cycles only. The peak voltage of this rectified waveform is equal to the RMS value of the original AC waveform, which is 120VAC.

The rectified waveform is then passed through a smoothing filter, usually a capacitor, to reduce the ripple. The capacitor charges up during the positive half cycle of the rectified waveform and discharges slowly during the gaps between the half cycles, providing a more constant output voltage.

The output voltage of the smoothing filter is approximately equal to 0.9 times the peak voltage of the rectified waveform. This is due to the voltage drop across the diodes and the charging and discharging behavior of the capacitor.

Therefore, in this scenario, the average DC voltage would be approximately 0.9 times the RMS value of the original AC waveform, which is 0.9 * 120VAC = 108VDC.

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Describe how your body uses chemical energy.

Answers

Explanation:

Your body uses chemical energy every day to perform daily tasks. Food contains calories and when you digest food, the energy is released. The molecules in food are broken down into smaller pieces. As the bonds between the atoms break or loosen, oxidation occurs.The chemical reaction involved in digestion supplies you with warmth, helps to maintain and repair your body and gives you the energy you need to move around.

Can electromagnetic waves travel in a vacuum?

Yes
Or
No

Answers

Answer:

Yes

Explanation:

Yes because Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

how do the placement of calcium, oxygen, and neon on the periodic table compare

Answers

Calcium, oxygen, and neon are elements that belong to different groups and periods on the periodic table. Their placements on the table can provide insights into their atomic structures, properties, and chemical behaviors.

Calcium (Ca) is located in Group 2 and Period 4 of the periodic table. As a member of Group 2, it is an alkaline earth metal. Alkaline earth metals are characterized by having two valence electrons and relatively high reactivity, although not as reactive as the alkali metals in Group 1. Calcium is known for its important role in biological processes, such as bone formation and muscle contraction. It exhibits metallic properties, is a good conductor of electricity, and readily forms ionic compounds.

Oxygen (O) is located in Group 16 and Period 2 of the periodic table. It is a nonmetal and is highly reactive due to its tendency to gain electrons and form negatively charged ions. Oxygen is an essential element for supporting life, and it is a key component of water and many organic compounds. It readily combines with other elements to form oxides, and its reactivity is a fundamental aspect of many chemical reactions. Oxygen also plays a vital role in respiration, both for organisms that use aerobic respiration and in the process of combustion.

Neon (Ne) is located in Group 18 and Period 2 of the periodic table. It is a noble gas, which means it has a full complement of valence electrons and is highly stable and unreactive. Noble gases are known for their low reactivity and low boiling points. Neon is widely used in neon signs due to its characteristic bright red-orange light emission when an electric current passes through it. Its stability and lack of reactivity make it an excellent choice for these applications.

In summary, the placement of calcium, oxygen, and neon on the periodic table highlights their distinct characteristics. Calcium is an alkaline earth metal, oxygen is a highly reactive nonmetal, and neon is an unreactive noble gas. Their positions in different groups and periods reflect variations in electron configurations, reactivity, and chemical properties, ultimately influencing their behavior and applications in various fields.

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interference with the normal pattern of the electrical current is also referred to as .:

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Interference with the normal pattern of the electrical current is also referred to as arrhythmia.

What is arrhythmia?

Arrhythmia refers to an irregular heartbeat, meaning the heart beats too quickly, too slowly, or in an irregular manner. The heart's electrical signals are responsible for its rhythm. Arrhythmias are often caused by underlying heart disease.

These diseases include congenital heart disease, high blood pressure, coronary artery disease, heart valve disorders, cardiomyopathy, and many more. Heart disease, alcoholism, hyperthyroidism, electrolyte imbalances, caffeine consumption, smoking, and drug use can all cause arrhythmias.

Treatment for arrhythmias can range from simple monitoring to medication to surgery or pacemaker implantation.

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imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? view available hint(s)for part a imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? 2 years it cannot be determined from the information given. 6 months 1 year

Answers

1year is the orbital period of this planet.

The orbital period  is the quantity of time a given astronomical object takes to complete one orbit around every other object. In astronomy, it generally applies to planets or asteroids orbiting the solar, moons orbiting planets, exoplanets orbiting different stars, or binary stars.

Kepler's third law - indicates the relationship among the length of an items orbit and the common distance that it's far from the issue it orbits. this could be used  for something clearly orbiting round another factor.

Entire revolution is known as the orbital duration. At 200 km that is approximately ninety minutes. The orbital duration will increase with altitude for two motives. First, as the altitude increases, Earth's gravity decreases, so the orbital speed had to stability it decreases.

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1. A 20 ohms resistor is connected in parallel with resistor " R " and the combination is then connected in series with 10 ohms resistor. Find the value of " R " if the equivalent total resistance between them is also equal to " R " ?

2.Two equal resistors R1 and R2 are connected in parallel. If the total voltage is equal to the total current, find R1 and R2 .

3. The resistance of a given electric device is 46 ohms at 25 0C. If the temperature coefficient of resistance of the material is 0.00454 at 20 0C determine the temperature of the device when its resistance is 92 ohms.

4. A electric motor operates 20 hours a day, 20 days a month, at an average output of 20 Hp. Calculate the cost of supplying this energy if the billing rate is constant at 1.5 cents per kwhr?

5.A coil of copper wire (  = 10.37 ) has a length of 600 feet. What is the length of an aluminum conductor (  = 17 ) if its cross-sectional area and resistance are the same ?

6.. Three resistors with values 1, 2 and 3 ohms respectively are connected in parallel. The combination is in series with 6 ohms resistor across a supply battery. The resistor that carries minimum current is

7. A electric motor operates 20 hours a day, 20 days a month, at an average output of 20 Hp. Calculate the cost of supplying this energy if the billing rate is constant at 1.5 cents per kw-hr.?

8.. A variable resistor R is connected in parallel with a 30 ohms resistor and the combination is connected in series with a 6 ohms across a 120 volts source. What are the values of R so that the power in it is equal to that of a 6 ohms resistor?

9. 8 ohms, 12 ohms and a variable resistor are connected in parallel. To what value in kilohm should resistor R be adjusted so that the power in 12 ohms resistor shall be 441 watts, if the total current is 20 amperes?

Answers

Explanation of electrical circuit and resistance-related questions.

Physics questions related to electrical circuits and resistors.

The given set of questions focuses on different aspects of electrical circuits and resistance.

These questions require applying principles and formulas related to resistors in parallel and series, temperature coefficient of resistance, power calculations, and variable resistors.

By solving these questions, one can deepen their understanding of electrical circuit concepts and practice the application of relevant formulas.

Answering these questions helps to reinforce knowledge of circuit analysis, resistance calculations, and power considerations, which are fundamental in the study of electrical engineering and physics.

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A total lunar eclipse is:

a. Visible only from the path of totality
b. Visible to all observers on the night time side of the earth
c. Visible only during a new moon
d. an opportunity to study the corona of the sun

Answers

Answer:

B) Visible to all observers on the night time side of the earth

Explanation:

I hope this helps.

As a city planner, you receive complaints from local residents about the safety of nearby roads and streets. One complaint concerns a stop sign at the corner of Pine Street and 1st Street. Residents complain that the speed limit in the area ( 8989 km/h) is too high to allow vehicles to stop in time. Under normal conditions this is not a problem, but when fog rolls in visibility can reduce to only 4747 meters. Because fog is a common occurrence in this region, you decide to investigate. The state highway department states that the effective coefficient of friction between a rolling wheel and asphalt ranges between 0. 5360. 536 and 0. 5990. 599 , whereas the effective coefficient of friction between a skidding (locked) wheel and asphalt ranges between 0. 3500. 350 and 0. 4800. 480. Vehicles of all types travel on the road, from small cars with a mass of 563563 kg to large trucks with a mass of 39513951 kg. Considering that some drivers will brake properly when slowing down and others will skid to stop, calculate the minimum and maximum braking distance needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection

Answers

The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:

- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m

- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m

To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.

The equation for the braking distance of a vehicle is given by:

d = (v^2) / (2 * μ * g)

where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.

Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.

For small cars with a mass of 563 kg:

- Minimum braking distance:

  v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s

  μ_min = 0.536

  d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m

  Maximum braking distance:

  μ_max = 0.599

  \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)

For large trucks with a mass of 3951395 kg:

- Minimum braking distance:

  v = 8989 km/h = 2496.944 m/s (same as for small cars)

  μ_min = 0.350

 \(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)

  Maximum braking distance:

  μ_max = 0.480

 \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)

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A fridge is kept at a constant temperature of 3°C. An object placed in the fridge cools from its initial temperature of 20°C down to 10°C in half an hour. Using Newton's Law of Cooling, find the mathematical model which would be solved to find y(t), the temperature of the object after t hours.

Answers

According to Newton's Law of Cooling, the mathematical model that can be solved to find y(t), the temperature of the object after t hours, is y(t) = 3 + 17e^(-kt), where k is a constant that can be determined using the given information.

Given that the fridge is kept at a constant temperature of 3°C and the object cools from 20°C to 10°C in half an hour, the mathematical model y(t) = a + (b - a)e^(-kt) can be used, where a represents the temperature of the fridge (3°C), b represents the initial temperature of the object (20°C), and k is a constant that needs to be determined.

Newton's Law of Cooling states that the rate of change of temperature of an object is directly proportional to the difference between the object's temperature and the ambient temperature. In this case, the ambient temperature is 3°C. Based on the given information, we can set up the following equation:

dy/dt = k(b - y)

Where dy/dt represents the rate of change of temperature, k is a constant, b is the initial temperature of the object (20°C), and y is the temperature of the object at time t.

Integrating the equation, we get:

∫(1/(b - y)) dy = ∫k dt

This results in:

-ln|b - y| = kt + C

Simplifying further, we have:

ln|b - y| = -kt + C

Exponentiating both sides, we obtain:

|b - y| = e^(-kt + C)

Since e^C is a positive constant, we can rewrite the equation as:

b - y = Ae^(-kt)

Where A is a positive constant.

To determine the constant k, we can use the fact that the object cools from 20°C to 10°C in half an hour. Plugging in the values for t = 0.5 and y = 10, we have:

20 - 10 = Ae^(-0.5k)

10 = Ae^(-0.5k)

Solving for A, we find:

A = 10e^(0.5k)

Substituting this value of A back into the equation, we get:

b - y = (10e^(0.5k))e^(-kt)

Simplifying further, we obtain:

y(t) = b - (b - a)e^(-kt)

Since a represents the temperature of the fridge (3°C) and b represents the initial temperature of the object (20°C), the final mathematical model to find y(t), the temperature of the object after t hours, is given by:

y(t) = 3 + (20 - 3)e^(-kt)

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Calculate the % crystallinity of branched polyethylene with a density of 0.925 g/cm3

Answers

To calculate the percent crystallinity of branched polyethylene, you need to know its density. However, the density alone is not sufficient to determine the crystallinity.

Crystallinity is usually determined using techniques such as X-ray diffraction or differential scanning calorimetry. These techniques analyze the polymer's structure and thermal behavior to determine the percentage of crystalline regions.

If you have additional information, such as the degree of branching or molecular weight, please provide it so that I can assist you further. Crystallinity is usually determined using techniques such as X-ray diffraction or differential scanning calorimetry (DSC).

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what is units for joules?

Answers

The work performed by a force of one newton acting through one meter is equivalent to one joule, a unit of work or energy in the International System of Units (SI). James Prescott Joule, an English physicist, inspired the name.

The fundamental SI unit of energy is called a joule, or J. One joule is equal to one kgm²/s², or the kinetic energy of a kilograms mass travelling at one meter per second. As an alternative, it is the amount of work that is performed on an object when a force of one newton operates over a distance of one meter in the direction of the object's motion (1 joule equals 1 newton meter or Nm). The system bears James Prescott Joule's name. Because it is a person's name, the symbol's first letter is capitalised (J instead of j). The term is, however, written in lowercase when it is written out.

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A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.

Answers

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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Can someone please answer this, ill give you brainliest Would be very appreciated.

Can someone please answer this, ill give you brainliest Would be very appreciated.

Answers

Answer:

See below ~

Explanation:

What is happening to each event as the climate changes? Temperatures are increasing, carbon dioxide levels are increasing, the pH of the ocean is decreasing, sea levels are increasing, and the amount of sea ice is decreasing.

Here are orders of answers from start

IncreasingIncreasingDecreasingincreasingdecreasing

The main reason behind these situations is global warming

The emmison of carbon dioxide has increased a lot which is getting harmful day by day

Consider an insulating sphere carrying uniformly distributed over the volume charge q. three gaussian surfaces are concentric with the sphere. surface

Answers

The scenario described involves an insulating sphere with a uniform volume charge distribution, carrying a charge q. The electric field passing through each of the three concentric Gaussian surfaces will be constant, and the net flux through each surface will also be the same.

There are three concentric Gaussian surfaces surrounding the sphere.

Gaussian surfaces are hypothetical surfaces used to analyze electric fields and charge distributions.

Considering the concentric Gaussian surfaces, the electric field due to a uniformly charged sphere is proportional to the charge enclosed by each Gaussian surface. In this case, since the charge distribution is uniform, the charge enclosed by each Gaussian surface will be proportional to the volume enclosed by that surface.

Since the sphere carries a uniformly distributed charge, the electric field at any point inside the sphere is zero. This means that the charge enclosed by each Gaussian surface will be the same, and hence, the electric field through each Gaussian surface will also be the same.

Therefore, the electric field passing through each of the concentric Gaussian surfaces will be constant, and the net flux through each surface will also be the same.

In summary, for the scenario described, the electric field passing through each of the three concentric Gaussian surfaces will be constant, and the net flux through each surface will also be the same.

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in order for the average velocity to be different from the avergae speed, what has to be true of the object's motion?

Answers

Answer:

ok

Explanation:

Acceleration is defined as the rate of change of velocity.

Acceleration = (Change in velocity) / time taken

Acceleration = (Final velocity - initial velocity) / time

As the object velocity changes by the same amount in each second, it means the acceleration is constant.

I forgot to post the pic
But please help
just need answers​

I forgot to post the picBut please helpjust need answers

Answers

Answer:

1.127,56,000m

2. 347,600,000

3. 384,000

4. 200000000

5.  16,000,000cm

6. 36,000,000cm

7. 125,000m long, 400m deep, 1,500m wide

8. 11.18km/sec

9. 5,400,000

10.  2g

11. 1,200 mg to 2700 mg

12.   158000 kg

13. 450000000 mg

14.    23,000g to 90,000g

15.   40,000 ML

16.  1,000 ML

17.  26,600 KL

18. 1,558,000 L

19. 60 ML

20. 0.947

A student who weighs 460 N is wearing a backpack that weighs 73 N. The student is standing still on level ground. Give your answers to the following questions in newtons. Remember, enter only the number; don't try to enter the units.(a) What is the magnitude of the net force on the student?(b) What is the magnitude of the contact force on the student by the backpack?(c) What is the magnitude of the contact force on the student by the ground?

Answers

For the student who weighs 460 N and weirs a backpack that weighs 73 N, we have:

a) The magnitude of the net force on the student is 533 N.

b) The magnitude of the contact force on the student by the backpack is 73 N.

c) The magnitude of the contact force on the student by the ground is 533 N.

a) The magnitude of the net force on the student is given by the sum of forces in the vertical direction:

\( \Sigma F_{net} = W_{s} + W_{b} \)

Where:

\( W_{s}\): is the weight of the student = 460 N        

\( W_{b}\): is the weight of the backpack = 73 N

Hence, the magnitude of the net force is:

\(\Sigma F_{net} = W_{s} + W_{b} = 460 N + 73 N = 533 N\)

   

b) The magnitude of the contact force on the student is equal to the normal force as follows:

\( F_{c} = N_{c} \)

Where:

\( N_{c} \): is the normal force on the student by the backpack

This normal force is opposite to the weight force:

\( F_{c} = N_{c} = -W_{b} = -73 N \)

Hence, the magnitude of the contact force on the student by the backpack is 73 N.

c) The magnitude of the contact force on the student by the ground is the normal force:

\( F_{n} = N_{g} \)

Where:

\(N_{g} \): is the normal force on the student by the ground  

The normal force on the student by the ground is the opposite to the net force of point A, so:

\( F_{n} = -F_{net} = -533 N \)        

Therefore, the magnitude of the contact force on the student by the ground is 533 N.  

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The volume occupied by a sample of gas is 480 mL when the pressure is 115 kPa.What pressure must be applied to the gas to make its volume become 650 mL? (P2= P1V1/V2)

Answers

Answer:

The answer is

84.9 kPa

Explanation:

Using Boyle's law to find the final pressure

That's

\(P_1V_1 = P_2V_2\)

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final pressure

\(P_2 = \frac{P_1V_1}{V_2} \)

From the question

P1 = 115 kPa

V1 = 480 mL

V2 = 650 ml

So we have

\(P_2 = \frac{115000 \times 480}{650} = \frac{55200000}{650} \\ = 84923.076923...\)

We have the final answer as

84.9 kPa

Hope this helps you

There is a 2kg ball resting on the roof of a house that is 8m high. What is the balls gravitational potential energy? GPE- mgh. G-9.8 m/s^2

Answers

Answer:

156.8 J

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 2 × 9.8 × 8 = 156.8

We have the final answer as

156.8 J

Hope this helps you

I need the answer to these quick

Answers

Answer:

where is the question ??/dude

Uhhhhhh we need the question lollllll

Why can we get the absolute ages of the surfaces of both Mercury and Mars by using the surface ages determined from the Moon

Answers

Answer: because when you take the rock(dwanye) and bring it to the lab you can studie it and see how old it is mabey u will se the rock(Dwayne Johnson)

Explanation:

To get the absolute age of the surfaces of both Mercury and Mars by using the age of the surface determined from the moon by the process of dating surfaces by looking at the relationships between them is called stratigraphy.

How the age of a planet's surface is determined?Determining how a planet's surface has evolved over time is a key issue in planetary research. This provides information on both the dynamics of planetary interiors (such as how frequently volcanoes erupt or earthquakes occur) and the external processes that have an impact on planets (for example, how likely it is that a giant asteroid might hit the Earth and change it radically.)The age of each component of a surface is the easiest method to explain how it has changed over time. For example, a map of the area could be created and color-coded, with each color denoting a certain age group. On Earth, we frequently have easy access to numerous other ancient surfaces that are buried beneath the surface. (Obviously, the deeper surface must be older if it has buried the lower surface.) For example, in the Grand Canyon, it is possible to immediately observe the many strata of rock that have been dug on the canyon walls.

To learn more about Planet's surface, refer to

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A 20.0 kg cannonball is fired from a 2.40 ´ 103kg. If the cannon recoils with a velocity of 3.5 m/s backwards, what is the velocity of the cannonball?

Answers

Answer:420ms^-1

Conserving linear momentum (mv)=(MV)

Anyone knows this please help me

Anyone knows this please help me

Answers

Answer:

True

Explanation:

this is a physics question please help

this is a physics question please help

Answers

Answer:

mass×Velocity

Explanation:

b/c when we want to get KE =one over two mass times velocity square

The freezing point of water is a (physical/chemical) property. The ability of oxygen to react with iron to cause rust is a (physical/chemical) property.

Answers

So the freezing point of water is physical and the ability of oxygen to react with iron to cause rust is chemical

The freezing Point of water is a physical property

The ability of oxygen to react with iron to cause rust is chemical property

Explanation:

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