What is the pressure, in mmHg, of a 4.00 g sample of O2 gas, which has a temperature of 37.0 °C, and a volume of 4400 mL?

Compared to 2,3,4-trifluoropentane, the nonane's carbon chains are longer.

A substance's molar mass is defined as its molecular weight in grams. By adding the molar masses of a substance's constituent atoms, we may get the substance's molar mass. Then, to convert between mass and the quantity of moles of the material, we may utilize the computed molar mass.

Adding the atomic masses of a particular substance results in the calculation of molar mass. Below each element's symbol on the periodic table is a designation of the mass of that specific element. The molar mass is obtained by averaging the atomic masses obtained from the periodic table.

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Because of their different longitude.

Answer:

landslide mudflows slump and creep

Explanation:

no explanation

Answer:

(a) Elements are combined in a specific ratio. 2 atoms of hydrogen and 1 atom of oxygen make water. (b) The properties of water are different from that of oxygen and hydrogen.

C₂H₄O₂ + NaHCO₃ —> NaC₂H₃O₂ + H₂O + CO₂ the amount of Carbon dioxide produced is 5.28 mg.

Water, CO₂ , and C₂H₃NaO₂ were produced when acetic acid and NaHCO₃ were combined. The chemistry is as follows: The reaction between vinegar and baking soda was endothermic.

Acetic acid:  2(12.01 g/mol) + 4(1.01 g/mol) + 2(16.00 g/mol)

                                              = 60.05 g/mol

NaHCO₃ 22.99 g/mol + 1.01 g/mol + 3(16.00 g/mol)

                                             = 84.01 g/mol

100 mg of Acetic acid is equal to 0.1 g, and 10 mg of NaHCO₃ is equal to 0.01 g.

Number of moles of Acetic acid = 0.1 g / 60.05 g/mol

                                             = 0.00167 mol

Number of moles of NaHCO₃  = 0.01 g / 84.01 g/mol

                                               = 0.00012 mol

Since NaHCO₃ has fewer moles, it is the limiting reactant.

Therefore, 0.00012 mol of NaHCO₃  will produce 0.00012 mol of CO₂

The mass of CO₂ produced can be calculated as follows:

Mass of CO₂ = Number of moles of CO₂  x Molar mass of CO₂

Mass of CO₂ = 0.00012 mol x 44.01 g/mol

                             = 0.00528 g or 5.28 mg

Therefore, the amount of CO₂ produced is 5.28 mg.

The theoretical yield of CO₂ is 0.00012 mol x 44.01 g/mol

                               = 0.00528 g or 5.28 mg.

This is equal to the actual yield of CO₂ produced.

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Answer:

see attachment

Explanation:

see attachment for your answer.

Hope this helps.

-Rishabh

strontium sulfate (s) + lithium iodide (aq)  →  strontium iodide (aq) and lithium sulfate (aq).

The reaction between strontium sulfate (SrSO4) and lithium iodide (LiI) can be represented by the following balanced chemical equation:

SrSO4 (s) + 2 LiI (aq) → SrI2 (aq) + Li2SO4 (aq)

In this reaction, strontium sulfate (SrSO4) in its solid state reacts with lithium iodide (LiI) in its aqueous state to produce strontium iodide (SrI2) and lithium sulfate (Li2SO4), both in their aqueous forms. The reaction can be understood by examining the ionic compounds involved. Strontium sulfate dissociates into strontium ions (Sr2+) and sulfate ions (SO4^2-), while lithium iodide dissociates into lithium ions (Li+) and iodide ions (I^-). The ions then rearrange to form the products, with strontium combining with iodide to form strontium iodide, and lithium combining with sulfate to form lithium sulfate. It's important to note that this reaction occurs in an aqueous solution, indicating that lithium iodide is dissolved in water. The solid strontium sulfate reacts with the aqueous lithium iodide to produce the aqueous products. This reaction demonstrates the chemical combination of the ions present in strontium sulfate and lithium iodide to form different ionic compounds.

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The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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The Ammonium Chloride solution at 0.25 M has a pH of 2.67.

As a result, the weak basic (Chlorine) in the solution is overpowered by the conjugate acid (Ammonium cation), making the solution mildly acidic. According to the equation pH =log[Hydrogen ion], an acidic solution has a pH lower than 7. Aqueous ammonium chloride solution has a pH that is less than 7.

Ammonium cation + Water ⇌ Nitrogen trihydride + Hydronium ion

Kb = [Nitrogen trihydride][Hydronium ion] / [Ammonium cation]

[Nitrogen trihydride] = [Hydronium ion] = x

[Ammonium cation] = 0.25 - x

Kb = [Nitrogen trihydride][Hydronium ion] / [Ammonium cation]

1.8 × 10–5 = x² / (0.25 - x)

1.8 × 10–5 = x² / 0.25

x² = 4.5 × 10–6

x = 2.12 × 10–3

pH = -log[Hydronium ion] = -log(2.12 × 10–3) = 2.67

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Keeping the car well tuned with regular servicing helps to reduce the emission of oxides of nitrogen gas to the atmosphere. Hence, option B is correct.

NOₓ is a representation of oxides of nitrogen gas. Nitrogen gas reacts with atmospheric oxygen produces NO, NO₂ etc. all are causing atmospheric  pollution and other serious issues such as acid rain, global warming, ozone layer depletion etc.

Thus, it is very important to reduce the emission of oxides of nitrogen. Vehicles and industries are the main sources of NOₓ emission. Evolving these gas directly to air caused serious consequences.

Keeping the vehicles maintained regularly with ensuring that no gas leakage or over expulsion is there. Hence, option C is helpful to reduce the emission of this gas.

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Answer:

e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature

Answer:

Sharing electrons forms a covalent bond between the atoms

Explanation:

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding.

Answer:Proton and neutron

Explanation:

the answer is that it is a

The concentration of the chloride ion. I got 0.9 M is  mathematically given as

[CL^-]=0.9mm

The reactants are listed on the left side of a chemical equation, while the products are listed on the right. Both sides of a balanced chemical equation have the same number of atoms of each element and the same overall charge.

Generally, the chemical equation for the question  is  mathematically given as

b) If the solution is \($\mathrm{Fe}_{3}(a \omega)$\)

\(\begin{aligned}\mathrm{FCl}_{3} & \rightarrow \mathrm{a}^{+3}+3 \mathrm{Cl}^{-} \\& 1 \mathrm{Fe}^{+3} \mathrm{~S} 3 \mathrm{al} \text { ions incota. } \\\Rightarrow\left[\mathrm{El}^{-}\right] &=\frac{3}{4} \mathrm{Cl}^{-}+4 \mathrm{Cl}^{-} \\therefore\left[\mathrm{Cl}^{-}\right] &=1.2 \mathrm{~mm} \times \frac{3}{4} \\&=0.9 \mathrm{~mm}\end{aligned}\)

In conclusion, the concentration of the chloride ion. I got 0.9 M is

[CL^-]=0.9mm

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Answer: the answer is c

Explanation:

I just did the test

Each graph below represents a different type of electromagnetic wave. Then graph C most likely illustrates radio waves.

The electromagnetic field's waves, which travel through space and convey electromagnetic radiant energy, are what make up electromagnetic radiation. It consists of X-rays, gamma rays, microwaves, infrared, light, and radio waves. These waves are all a component of the electromagnetic spectrum.

There are seven different kinds of them are X-rays, gamma rays, visible light, infrared light, radio waves, and microwaves. They may be compared to seven distinct types of light.

Lower frequency electromagnetic radiation than microwaves is referred to be a radio wave. Radio waves have wavelengths that range from tens of thousands of meters to 30 centimeters. These are equivalent to frequencies between 3 Hz and 1 GHz (109 Hz).

Thus, option C is correct.

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The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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A: begin to cool and daylight hours decrease.

Plants go through seasonal changes from summer to fall because of the changes in temperature and the length of daylight hours. As summer ends and fall begins, temperatures begin to cool down and the days become shorter. This change in temperature and daylight hours triggers physiological changes in plants, such as the slowing down of growth and the production of pigments like anthocyanins, which give leaves their characteristic red and orange colors in the fall. These changes allow the plant to prepare for the colder winter months and conserve energy for the upcoming spring growth season.

Answer:

a. begin to cool and daylight hours decrease

hope this helps ;)

The centripetal acceleration at the equator is around 3.39 cm/sec2 (I'm taking this estimate from the CRC) in 1995 when Cathy Marshall of Germany cycled 47.112 km 1.000 hours.

You can use the following equation to get centripetal acceleration: A C Equals V 2 R where r is the circle's radius and v is the velocity, which is expressed in meter per second (m/s). Centripetal acceleration is measured in meters per second squared, or m/s2 m/s2.

An=v2r=2r is used to calculate the acceleration. Equations for constant acceleration can be applied with the acceleration (assuming constant tangential velocity) to determine.

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Answer:

a) 101%

b)59.7%

Explanation:

The equation for the thermal decomposition of baking soda is shown;

2NaHCO3 → Na2CO3 + H2O + CO2

Number of moles of baking soda= mass/molar mass= 1.555g/84.007 g/mol = 0.0185 moles

From the reaction equation;

2 moles of baking soda yields 1 mole of sodium carbonate

0.0185 moles of baking soda will yield = 0.0185 moles ×1 /2 = 9.25 ×10^-3 moles of sodium carbonate.

Therefore, mass of sodium carbonate= 9.25 ×10^-3 moles × 106gmol-1= 0.9805 g of sodium carbonate. This is the theoretical yield of sodium carbonate.

%yield = actual yield/theoretical yield ×100

% yield = 0.991/0.9805 ×100

%yield = 101%

Since ;

2NaHCO3 → Na2CO3 + H2O + CO2

And H2O + CO2 ---> H2CO3

Hence I can write, 2NaHCO3 → Na2CO3 + H2CO3

Molar mass of H2CO3= 62.03 gmol-1

Molar mass of baking soda= 84 gmol-1

Therefore, mass of baking soda=

0.325/62.03 × 2 × 84 = 0.88 g of NaHCO3

% of NaHCO3= 0.88/1.473 × 100 = 59.7%

The decomposition reaction of baking soda is a reaction in which water and carbon dioxide ae given off as gaseous products.

Reasons:

Mass of baking soda = 1.555 g

Mass of Na₂CO₃ produced = 0.991 g

Required:

Calculation for the theoretical yield

Solution:

Theoretical yield (mass) of Na₂CO₃ produced is found as follows;

Molar mass of Na₂CO₃ = 105.9888 g/mol

Molar mass of NaHCO₃ = 84.007 g/mol

\(\displaystyle 1.555 \, g \, NaHCO_3 \times \frac{1 \, mol \, NaHCO_3}{84.007 \, g \, NaHCO_3} \times \frac{1 \, mol \, Na_2CO_3}{2 \, mol \, NaHCO_3} \times 105.9888 \ g \approx 0.9809 \, g \, Na_2CO_3\)

The theoretical yield of Na₂CO₃ ≈ 0.9809 grams.

The percentage yield is given as follows;

\(\displaystyle Percentage \ yield = \mathbf{\frac{Actual \, Yield}{Theorectical \, Yield} \times 100 \%}\)

The percentage yield of Na₂CO₃ is therefore;

\(\displaystyle Percentage \ yield \ of \ Na_2CO_3= \frac{0.991}{0.9809} \times 100 \% \approx \underline{ 101.02 \%}\)

(Some baking soda may remain if the reaction is not completed)

6. Mass of the unknown mixture of baking soda = 1473 g

Mass loss from the mixture = 0.325 g

Required:

The percentage of NaHCO₃ in the mixture.

Solution:

The chemical in the mass loss from heating the NaHCO₃ = H₂CO₃

Molar mass of H₂CO₃ = 62.03 g/mol

\(\displaystyle \mathrm{Number \ of \ moles \ of \ H_2CO_3 \ produced} = \frac{0.325 \, g}{62.03 \, g/mol} \approx 5.2394 \times 10^{-3} \ moles\)

The chemical reaction is presented as follows;

The number of moles of NaHCO₃ in the mixture is therefore;

Mass of NaHCO₃ in the mixture is therefore

\(\displaystyle Percentage \ of \ NaHCO_3 \ in \ the \ mixture \ = \mathbf{ \frac{Mass \ of \ NaHCO_3}{Mass \ of \ mixture} \times 100}\)

Which gives;

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Answer:

The reaction rate or rate of reaction is the speed at which a chemical reaction takes place. Reaction rate is defined as the speed at which reactants are converted into products. Reaction rates can vary dramatically.

Explanation:

PLS MAKE ME AS BRAINLIST

The serving of peanut butter contains 117kcal

1 gram of both carbohydrate and protein contains 4 (kcal)

1 gram of fat contains 9 (kcal)

But peanut butter contains 5g of fat. The kilocalories of fat present is;

1 g = 9 kcal

5g = F

F = 5×9

F = 45 kcal

The kilocalories of carbohydrates present is;

1g = 4kcal

12g = C

C= 12×4

C = 48kcal

The kilocalories of proteins present is;

1g = 4kcal

6 g = P

P = 4× 6

P = 24 kcal

Therefore, the total kilocalories of the peanut = 45 + 48 + 24 = 117kcal

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We can see here that the best fuel is the one that produces the most heat per unit mass. In this case, the fuel that produces the most heat per unit mass is methanol.

Fuel is a substance that is used to produce energy through combustion or other chemical reactions. It is commonly utilized to power various forms of transportation, generate heat or electricity, and operate machinery and appliances.

The results of the experiment are shown below:

Fuel            Mass (g)      Heat produced (J)       Heat per gram (J/g)

Methanol 1.0                          350                   350

Ethanol         1.0                          250                   250

Propane         1.0                          200                   200

Butane         1.0                          150                            150

Pentane         1.0                          100                            100

It is important to note that the results of this experiment are only a measure of the heat produced by the fuels.

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Explanation:

To calculate the heat gained by nickel, we can use the formula:

q = m * c * ΔT

where q is the heat gained, m is the mass of the nickel, c is the specific heat of nickel, and ΔT is the change in temperature.

Given:

- Mass of nickel, m = 31.4 g

- Specific heat of nickel, c = 0.443 J/g · °C

- Change in temperature, ΔT = 64.2 °C - 27.2 °C = 37.0 °C

Substituting the values into the formula, we get:

q = (31.4 g) * (0.443 J/g · °C) * (37.0 °C)

Simplifying the calculation, we get:

q = 584 J

Therefore, the heat gained by nickel when 31.4 g of nickel is warmed from 27.2 °C to 64.2 °C is 584 J.

to prevent the glucose undergoing isomerization to an aldehyde, or fructose to alpha-hydroxy-ketone form. 

Answer:

acetaldehyde

When acetaldehyde is heated with Fehling's solution, a red precipitate is formed.

Explanation:

Evaporation followed by distillation is a physical process that  would allow you to isolate this salt after the acid-base titration occurs in solution.

Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste. Compounds  such as HCl, H₂SO₄ and HNO₃ are acids as they yield H+ ions on dissociation.

According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic  acids  depending on the number of protons which are liberated on dissociation.They are separated by distillation.

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Answer:

b

Explanation:

i know

The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.

First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:

C: 12.01 g/mol

H: 1.01 g/mol

Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol

Next, we calculate the moles of butane in the sample:

moles of butane = mass of butane sample / molar mass of butane

moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol

Now, we can calculate the heat released by the combustion of the butane sample using the equation:

q = C * ΔT

where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.

Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:

q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ

Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.

Energy of combustion for one mole of butane = q / moles of butane

Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol

Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.

In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.

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