What is the process called when the moon bagins to fade from full moon to new moon

Answers

Answer 1
Waining there’s not much to explain here it’s simple moon phases

Related Questions

Promiscuous enzymes metabolize many alcohols in the human liver The example molecule used in the Chemistry Tutorial (1-propanol) and its metabolite are not the only molecules that can be oxidized by ADH and ALDH, respectively. In fact, ADH and ALDH are promiscuous enzymes, meaning that they are not specific in catalyzing the oxidation of just one specific alcohol or aldehyde. On the other hand, ADH will not catalyze the oxidation of every alcohol either.
For example, ADH can oxidize all of the following compounds except tert-butanol
- Methanol
- Isopropanol
- Ethylene glycol
- Tert-butanol
What characteristic of the substrate must the active site of ADH recognize? a. a hydrogen atom located on a carbon next to a with an-OH group (vicinal position)
b. atom located on the same carbon as an-OH group (geminal position)
c. an internal - OH group (a secondary alcohol)
d. a terminal -OH group (a primary alcohol)

Answers

The characteristic of the substrate that the active site of ADH must recognize is option A: "hydrogen atom located on a carbon next to a with an-OH group (vicinal position)".

This is because ADH is an enzyme that catalyzes the oxidation of alcohols to aldehydes or ketones. In order for this reaction to occur, the substrate must have a hydrogen atom located on a carbon next to an -OH group. This allows the enzyme to recognize the substrate and catalyze the reaction.

Without this characteristic, the enzyme will not be able to recognize the substrate and the reaction will not occur.

ADH specifically recognizes and binds to this particular feature of the substrate through its active site, which has a complementary shape and chemical properties to the substrate. This binding allows the enzyme to position the substrate in a way that facilitates the transfer of a hydrogen ion and a pair of electrons to the coenzyme NAD+ to form NADH, while producing an aldehyde or ketone.

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The characteristic of the substrate that the active site of ADH must recognize is option A: "hydrogen atom located on a carbon next to a with an-OH group (vicinal position)".

This is because ADH is an enzyme that catalyzes the oxidation of alcohols to aldehydes or ketones. In order for this reaction to occur, the substrate must have a hydrogen atom located on a carbon next to an -OH group. This allows the enzyme to recognize the substrate and catalyze the reaction.

Without this characteristic, the enzyme will not be able to recognize the substrate and the reaction will not occur.

ADH specifically recognizes and binds to this particular feature of the substrate through its active site, which has a complementary shape and chemical properties to the substrate. This binding allows the enzyme to position the substrate in a way that facilitates the transfer of a hydrogen ion and a pair of electrons to the coenzyme NAD+ to form NADH, while producing an aldehyde or ketone.

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What led to the prohibition of alcohol?.

Answers

(- Temperance Movement

there was a combination of political and social factors that led to prohibition. one of the main political factors was the Temperance Movement.

The temperance movement was a social movement against the consumption of alcohol.








What is the percent weight of a solution containing 3.23 g NaCl in 77 g of the solution?

Answers

The percentage weight of a solution containing 3.23 g NaCl in 77 g of the solution is 4.02%.

Mass Percent Concentration (mass %) = mass of solute (g) ÷ mass of solution (g) × 100%

To find the mass percent concentration of NaCl in a solution, divide the mass of the solute (NaCl) by the mass of the solution and then multiply by 100 to get the percentage.

The mass of NaCl in the solution is given as 3.23 g, while the mass of the entire solution is 77 g.

Percent weight = mass of solute ÷ mass of solution × 100% = 3.23 g ÷ 77 g × 100% = 0.0402 × 100% = 4.02%

Therefore, the percentage weight of the solution is 4.02%.

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how many electrons can be assigned to orbitals designated by the quantum numbers n = 6, ℓ = 1?

Answers

The maximum number of electrons that can be assigned to orbitals designated by the quantum numbers n = 6, ℓ = 1 is six.

Quantum numbers n and ℓ

The quantum number n represents the principal energy level of an atom. The quantum number represents the sublevel or subshell of an atom.

For any given principal quantum number, n, there is a maximum of two electrons that can be assigned to any particular orbital of the same angular momentum quantum number, ℓ. In this case, n = 6, meaning that the orbital is part of the sixth energy level, and ℓ = 1, meaning that the orbital is a p-orbital and there is a maximum of six electrons that can be assigned in p-orbital:

↑↓     ↑↓   ↑↓

6px  6py  6pz

Therefore, the maximum number of electrons that can be assigned to this orbital is six.

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Upon the death or incapacitation of a president and the succession of the vice president, a new vice president is chosen by

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Upon the death or incapacitation of a president and the succession of the vice president, a new vice president is chosen by the process of nomination by the president and confirmation by both houses of the United States Congress.

According to the 25th Amendment to the United States Constitution, in the event of the death, resignation, or removal from office of the vice president, the president has the power to nominate a new vice president. The nomination must be confirmed by a majority vote in both the House of Representatives and the Senate.

This process ensures that there is a clear line of succession and continuity of leadership in the executive branch of the United States government. It provides a mechanism to fill the vacancy in the vice presidency to ensure that the executive branch remains functioning effectively. The nomination and confirmation process allows for the participation and decision-making of both the president and the legislative branch in selecting the new vice president.

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consider a double-slit experiment. match the equation with the appropriate type of interference.

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In a double-slit experiment, interference patterns are observed when light passes through two parallel slits. The interference pattern is created by the interaction of the waves, which causes a variation in the intensity of light. The equation used to describe the interference pattern is the double-slit interference equation, which is given by:

I = I₀cos²(πdsinθ/λ)

Here, I is the intensity of light at a particular point on the screen, I₀ is the maximum intensity, d is the distance between the slits, θ is the angle between the screen and the line connecting the slit and the point of interest, and λ is the wavelength of the light.

There are two types of interference observed in a double-slit experiment: constructive interference and destructive interference. Constructive interference occurs when the waves from the two slits are in phase and add up to produce a maximum intensity at a particular point on the screen. Destructive interference occurs when the waves from the two slits are out of phase and cancel out each other, producing a minimum intensity at a particular point on the screen.

The double-slit interference equation can be used to predict and explain the interference pattern observed in a double-slit experiment.

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a 10-ml sample of tartaric acid is titrated to a phenolphthalein endpoint with 20. ml of 1.0 m naoh. assuming tartaric acid is diprotic, what is the molarity of the acid?

Answers

The molarity of the tartaric acid is 1.0 M.

To find the molarity of the tartaric acid, we need to use the balanced chemical equation for the reaction:
H2Tartaric acid + 2NaOH → Na2Tartarate + 2H2O
From the equation, we can see that each mole of tartaric acid reacts with 2 moles of NaOH. Therefore, the number of moles of NaOH used in the titration can be calculated as:
n(NaOH) = M(NaOH) x V(NaOH) = 1.0 M x 20.0 mL = 0.020 mol
Since the reaction is diprotic, the number of moles of tartaric acid present in the 10 mL sample is equal to the number of moles of NaOH used divided by 2:
n(H2Tartaric acid) = 0.020 mol / 2 = 0.010 mol
Now, we can calculate the molarity of the tartaric acid as:
M(H2Tartaric acid) = n(H2Tartaric acid) / V(H2Tartaric acid) = 0.010 mol / 10 mL = 1.0 M
Therefore, the molarity of the tartaric acid is 1.0 M.

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Which is a way that paleontologists have contributed to humans' understanding of the history of life?
They found evidence that climate has not changed significantly.
They grouped organisms by the period in which they existed.
They discovered that the first humans lived with dinosaurs.
They learned that life has existed since Earth was created.​

Answers

Answer:b

Explanation:

Answer:

b

Explanation:

took test

If the following elements were involved in redox reactions, which noble-gas configuration would they most likely attain

Answers

The noble-gas configurations that the elements would most likely attain in redox reactions are as follows: Lithium (Li) would achieve a helium (He) configuration, Aluminum (Al) and Potassium (K) would attain neon (Ne), Oxygen (O) would attain Ne, Phosphorus (P) would attain argon (Ar), Selenium (Se) could attain either Ar or krypton (Kr), and Strontium (Sr) would attain Kr. These configurations are determined by the tendency of each element to gain or lose electrons in order to achieve a stable electron configuration similar to that of the noble gases.

In redox reactions, elements undergo changes in their electron configurations by either gaining or losing electrons. To determine the noble-gas configuration they would most likely attain, we need to consider their valence electrons and their tendency to gain or lose electrons.

1. Lithium (Li): Lithium has one valence electron and tends to lose it to achieve a stable electron configuration. Therefore, it would most likely attain a helium (He) configuration by losing its valence electron.

2. Aluminum (Al): Aluminum has three valence electrons and tends to lose them to achieve stability. Hence, it would also attain a noble-gas configuration of neon (Ne) by losing all three valence electrons.

3. Oxygen (O): Oxygen has six valence electrons and tends to gain two electrons to achieve stability. It would attain the noble-gas configuration of neon (Ne) by gaining two electrons.

4. Phosphorus (P): Phosphorus has five valence electrons and tends to gain three electrons. Therefore, it would attain the noble-gas configuration of argon (Ar) by gaining three electrons.

5. Potassium (K): Potassium has one valence electron and tends to lose it to achieve stability. Hence, it would attain a noble-gas configuration of argon (Ar) by losing its valence electron.

6. Selenium (Se): Selenium has six valence electrons and can either gain two electrons to achieve a noble-gas configuration of krypton (Kr) or lose six electrons to attain a noble-gas configuration of argon (Ar). Both options are possible depending on the specific reaction conditions.

7. Strontium (Sr): Strontium has two valence electrons and tends to lose them to achieve stability. Therefore, it would attain a noble-gas configuration of krypton (Kr) by losing both valence electrons.

In summary, the noble-gas configurations for the elements are as follows:

Li: He

Al: Ne

O: Ne

P: Ar

K: Ar

Se: Ar or Kr

Sr: Kr

Complete Question : If the following elements were involved in redox reactions, which noble-gas configuration would they most likely attain?

Appropriate elements to their respective bins. ( He OR Ne OR Ar OR Kr ); for { Li, Al, O, P, K, Se, Sr }

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please help me i need yall will mark brainliest and 30 points!

please help me i need yall will mark brainliest and 30 points!

Answers

Reaction

2Fe(OH)₃ + 3H₂SO₄⇒Fe₂(SO₄)₃ + 6H₂O

because the limiting reactant is Fe(OH)₃, then the moles of all compounds will be based on moles of Fe(OH)₃

mole H₂SO₄ = 3/2 x mole Fe(OH)₃ = 3/2 x 3 mole = 4.5 mole

remaining mole of H₂SO₄ (as an excess reactant) = 6.4 - 4.5 = 1.9 mole

At 2000 k the partial pressures of an equilibrium mixture of H2S, H2, and S are 0.0025, 0.041, and 0.035 atm, respectively. Calculate the value of the equilibrium constant Kp at 2000 K
H2 s(g) ⇌ H2(g)+ S(g)

Answers

At a temperature of 2000 K, the equilibrium constant Kp for the reaction H₂S(g) ⇌ H₂(g) + S(g) is approximately 1.47, based on the given partial pressures of the gases in the equilibrium mixture.

To calculate the value of the equilibrium constant Kp at 2000 K, we can use the given partial pressures of the gases in the equilibrium mixture.

The balanced equation for the equilibrium reaction is:

H₂S(g) ⇌ H₂(g) + S(g)

The expression for Kp is given by the partial pressures of the products raised to their stoichiometric coefficients divided by the partial pressure of the reactant raised to its stoichiometric coefficient.

Kp = (PH₂ * PS) / PH₂S

Where:

PH₂, PS, and PH₂S are the partial pressures of H₂, S, and H₂S, respectively.

Substituting the given values into the equation:

Kp = (0.041 * 0.035) / 0.0025

Calculating the expression:

Kp = 1.47

Therefore, the value of the equilibrium constant Kp at 2000 K is approximately 1.47.

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4. Juan tiene un cilindro de 40 libras herméticamente cerrado con gas propano y lo conecta mediante una válvula a otro cilindro de 100 libras completamente vacío. Si Juan abre la válvula del cilindro de 40 dejando pasar el gas al de 100. responda

¿Qué cantidad de gas propano le haría falta al cilindro de 100 y por qué?

Answers

Answer:

Ver explicacion

Explanation:

Cuando el cilindro de 40 libras está conectado al cilindro de 100 libras, generamos una presión que continúa hasta que los dos cilindros alcanzan la misma presión de gas en equilibrio. Recuerde que el cilindro de 100 libras estaba inicialmente vacío. Esto significa que su presión inicial es 0. El cilindro de 40 libras ya estaba lleno, por lo que dividimos esta cantidad en dos para tener en cuenta su distribución entre los dos cilindros.

Ahora tenemos 20 libras de gas propano presentes en cada cilindro. La implicación de esto es que, en el cilindro de 100 libras, necesitamos 80 libras adicionales para completar las 100 libras.

please answer these about Charles law

please answer these about Charles law
please answer these about Charles law

Answers

Answer:

1. V2.

2. 299K.

3. 451K

4. 0.25 x 451 = V2 x 299

Explanation:

1. The data obtained from the question include:

Initial volume (V1) = 0.25mL

Initial temperature (T1) = 26°C

Final temperature (T2) = 178°C

Final volume (V2) =.?

2. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K

3. Conversion from celsius to Kelvin temperature.

T(K) = T (°C) + 273

Final temperature (T2) = 178°C

Final temperature (T1) = 178°C + 273 = 451K

4. Initial volume (V1) = 0.25mL

Initial temperature (T1) = 299K

Final temperature (T2) = 451K

Final volume (V2) =.?

V1 x T2 = V2 x T1

0.25 x 451 = V2 x 299

Use the bond enthalpies to calculate the enthalpy change for this reaction. Is the reaction endothermic or exothermic?

Use the bond enthalpies to calculate the enthalpy change for this reaction. Is the reaction endothermic

Answers

Answer: that is the answer

Explanation:

Use the bond enthalpies to calculate the enthalpy change for this reaction. Is the reaction endothermic
Use the bond enthalpies to calculate the enthalpy change for this reaction. Is the reaction endothermic
Use the bond enthalpies to calculate the enthalpy change for this reaction. Is the reaction endothermic

Which substance in this redox reaction is the oxidizing agent
Cu+2AgNo3 = 2Ag + Cu(NO3)2
A. N
B. AgNO3
C. Cu
D. NO3-
E. Cu(NO3)2

Answers

B. AgNO₃ is the oxidizing agent

Further explanation

Oxidation is an increase/increase in oxidation number, while reduction is a decrease/decrease in oxidation number.

In the redox reaction, it is also known

Reducing agents are substances that experience oxidation

The oxidizer is a substance that is reduced

Reaction

Cu+2AgNO₃ ⇔ 2Ag + Cu(NO₃)₂

Oxidizing reaction :

Cu⇒Cu²⁺+2e⁻ (oxidation number from 0 to +2)

Reducing reaction

2Ag⁺+2e⁻⇒Ag (oxidation number from +1 to 0)

the oxidizing agent ⇒a substance that is reduced , so that is AgNO₃

Answer:

B. AgNO3

Explanation:

what is the molar mass of trans-9-(2-phenylethenyl)anthracene

Answers

Molar mass is the mass of one mole of a substance. Therefore, the molar mass of trans-9-(2-phenylmethyl)anthracene is 356.44 g/mol.

The substance in question is trans-9-(2-phenylethenyl)anthracene. This organic compound can be represented as C28H20. The molar mass of trans-9-(2-phenylethenyl)anthracene is therefore calculated as follows:Step 1Determine the molar mass of carbon (C) and hydrogen (H). The atomic mass of carbon is 12.01 g/mol, and the atomic mass of hydrogen is 1.008 g/mol. Step 2Calculate the total molar mass of carbon and hydrogen in the compound. Multiply the atomic mass of carbon by the number of carbon atoms in the compound (28), and multiply the atomic mass of hydrogen by the number of hydrogen atoms in the compound (20).Step 3Add the molar masses of carbon and hydrogen to get the total molar mass of the compound. 12.01 × 28 + 1.008 × 20 = 336.28 + 20.16 = 356.44 g/molTherefore, the molar mass of trans-9-(2-phenylethenyl)anthracene is 356.44 g/mol.

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The three nuclides, U-233, U-235, and U-238, are isotopes of uranium because they have the same number of protons per atom and A) the same number of neutrons per atom B) a different number of electrons per atom C) a different number of neutrons per atom D) the same number of electrons per atom

Answers

Answer:

The correct answer is - C) a different number of neutrons per atom.

Explanation:

Isotopes of an element are the same element and same atomic number but with different atomic mass and physical properties. The difference in their atomic mass occurs due to isotopes of an element have a different number of neutrons per atom.

The number of protons and the numbers of electrons are the same in the isotopes but only change occurs in the numbers of the neutrons. In isotopes of uranium U-233, U-235, and U-238 have the same number of protons but a different number of neutrons per atom.

The three nuclides U-233, U-235, and U-238 are isotopes because they have a different numbers of neutrons. Thus, option C is correct.

Isotopes of an element can be defined as the elements with the same atomic number but different mass numbers. The atomic number can be defined as the number of electrons of an atom.

The isotopes of Uranium thus have the same number of electrons. Thus option B is incorrect.

Statement D is correct but is not the characteristic property to differentiate an isotope. Thus, option D is incorrect.

The mass number can be defined as the sum of the number of protons and neutrons. The number of electrons and protons is equal in an atom.

Thus in an isotope, the number of protons will be the same per atom.

The number of neutrons in an atom has been different per atom. Thus, option A is incorrect. Option C is correct.

Thus the three nuclides U-233, U-235, and U-238 are isotopes because they have a different numbers of neutrons. Thus, option C is correct.

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Crubbers are flue gas desulfurization devices very expensive equipment to remove SO2 pollution control equipment that removes 90 percent SO2 or more from baseline levels all of the above only A and B are correct

Answers

A and B are correct. Crubbers are expensive flue gas desulfurization devices used to remove 90% or more of SO2 pollution from industrial emissions.

Crubbers are indeed flue gas desulfurization devices used as pollution control equipment to remove SO2 (sulfur dioxide) from industrial exhaust gases. They are designed to reduce SO2 emissions to levels that are 90 percent or more below baseline levels. The term "baseline levels" refers to the initial levels of SO2 emissions before the implementation of the flue gas desulfurization system.

Crubbers, or flue gas desulfurization systems, work by utilizing various chemical processes to react with and remove sulfur dioxide from the flue gas. This helps mitigate the harmful effects of SO2 emissions on the environment and human health. However, it's important to note that while rubbers are effective in reducing SO2 pollution, they can be expensive equipment to install and maintain due to their complex design and operation. Therefore, both options A and B, which state that clubbers are flue gas desulfurization devices and expensive equipment, are correct.

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1. The author says that bog bodies were discovered as long ago as the 1600s, but the only ones existing today are those found after the late 1800s. What hap- pened to the earlier bog bodies?​

Answers

Answer:

The earlier bog bodies that were discovered in the 1600s might have not been preserved properly due to a lack of knowledge on how to preserve them or a lack of awareness of their significance. It is also possible that they might have decayed and decomposed over time and not survived till the present day. However, the bog bodies found after the late 1800s were preserved and studied extensively due to the increasing awareness and understanding of their historical and archaeological significance.

Explanation:

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Of four atoms bellow,which two would be in the same group? Sorry that the quality is so bad :(

Of four atoms bellow,which two would be in the same group? Sorry that the quality is so bad :(

Answers

Numbers 1 and 4 because they have the same number of outer electrons.

first to answer correctly gets brainleist! (you dont needa hear that vid thingy tahts just for ppl who cant read or need orial commidations or wtv lol)

first to answer correctly gets brainleist! (you dont needa hear that vid thingy tahts just for ppl who

Answers

I think the answer is c

Answer:

The seasons are a result of the tilt of the earth

Is nh4oh a strong electrolyte

Answers

\(NH_4OH\) is a weak electrolyte. When dissolved in water, it partially dissociates into its ions, but only a small fraction of the solute exists in the ionic state.

Strong electrolytes are substances that dissolve in water to produce fully dissociated ions, which means that when a strong electrolyte dissolves in water, it produces a high number of ions, while weak electrolytes are substances that only partially dissociate in water, producing fewer ions.

This applies to \(NH_4OH\), which is a weak electrolyte because it only partially dissociates into its ions in water.  

\(NH_4OH\) partially dissociates in water because it is a weak base with a small acid dissociation constant. This results in the formation of both \(NH_4^+\) and OH- ions in solution, but not all \(NH_4OH\)  molecules dissociate completely.

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Green plants convert light energy from the sun into what during photosynthesis

Answers

Answer: It turns the energy from the sun into a food for the plant.

I hope this helps, and Stay Safe! :)

it tuns the light into food

the density of seawater is ____ fresh water?

Answers

Answer:

Since salt ions are heavier than water molecules, seawater is denser than freshwater. The density of seawater ranges from 1020 to 1030 kg/m 3 while the density of freshwater is about 1000 kg/m 3. Variations in salinity also cause the freezing point of seawater to be somewhat lower than that of freshwater.

Explanation:

HELP ME PLEASE!!! I NEED THIS OR I WILL FAIL!!!

HELP ME PLEASE!!! I NEED THIS OR I WILL FAIL!!!

Answers

Answer:

replacement

Explanation:

Because the No and The Ci switch but it might not be the answer but I know that they have to switch and replacement sounds like the best answer

Answer:

Oxidation

Explanation:

Hope this helps :)

Consider a 1.0 L solution which is 0.55 M NH4Cl and 0.2 M NH3 (Ka for NH4Cl = 5.6 x 10^-10). Complete the table by calculating the pH of the original solution. Then calculate the pH of the solutions after the indicated additions. Calculate all the pH values to two decimal places. Assume no volume change on addition.
pH
original solution =
0.10 mol of HCl added to the original solution =
0.20 mol of NaOH added to the original solution =

Answers

1. The pH value of a 1.0 L solution which is composed of 0.55 M NH₄Cl and 0.2 M NH₃ of the original solution is 8.83.

2. The pH value of 0.10 mol of HCl added to the original solution is 8.61.

3. The pH value of 0.20 mol of NaOH added to the original solution is 9.30.

1. To calculate the pH value of the original solution, we must find the pKa value of NH₄Cl:

pKa = - log Ka = - log (5.6 × 10⁻¹⁰) = 9.25

The concentration of [NH₃] and [NH₄⁺] are given as 0.2 M and 0.55 M respectively. Thus, pH can be calculated by substituting the given values in the above formula:

pH = pKa + log ([NH₃]/[NH₄⁺])

= 9.25 + log (0.2/0.55)

= 9.25 - 0.4202

= 8.83

Thus, the pH value of the original solution is 8.83.

2.. To calculate the pH value of the solution after the addition of 0.10 mol of HCl and 0.20 mol of NaOH to the original solution, we must find the new molar concentrations of NH₄⁺ and NH₃ ions:

a. Initial molar concentration of NH₄⁺ = 0.55 M

The number of moles of H⁺ ion produced by 0.10 mol of HCl = 0.10 mol

The number of moles of NH₄⁺ ion reacted with H+ ion = 0.10 mol

Final molar concentration of NH₄⁺ ion = 0.55 - 0.10 = 0.45 M

b. Initial molar concentration of NH₃ = 0.2 M

The number of moles of NH₃ reacted with H+ ion = 0.10 mol

Final molar concentration of NH₃ ion = 0.2 - 0.10 = 0.1 M

The Ka value of NH₄Cl remains the same in this case. Therefore, pH can be calculated by using the same formula used earlier:

pH = pKa + log ([NH₃]/[NH₄⁺])

= 9.25 + log (0.1/0.45)

= 9.25 - 0.6381

= 8.61

Thus, the pH value of the solution after the addition of 0.10 mol of HCl is 8.61.

3. To calculate the pH value after 0.20 mol of NaOH is added to the original solution, we must find the new molar concentrations of NH₄⁺ and NH₃ ions:

Initial molar concentration of NH₄⁺ = 0.55 MInitial molar concentration of NH₃ = 0.2 MThe number of moles of OH⁻ ion produced by 0.20 mol of NaOH = 0.20 molThe number of moles of NH₄⁺ ion reacted with OH- ion = 0.20 molThe final molar concentration of NH₄⁺ ion = 0.55 - 0.20 = 0.35 MThe final molar concentration of NH₃ ion = 0.2 + 0.20 = 0.4 M

The Ka value of NH₄Cl remains the same in this case. Therefore, pH can be calculated using the same formula:

pH = pKa + log ([NH₃]/[NH₄⁺])

= 9.25 + log (0.4/0.35)

= 9.25 + 0.055

= 9.30

Thus, the pH value of the solution after the addition of 0.20 mol of NaOH is 9.30.

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What eventually happens to a gas if its pressure is increased?​

Answers

Answer:

According to Boyle's law pressure of a particular amount of gas is inversely proportional to the volume of the gas.So, when we increase the pressure of the gas the volume of the gas decrease and the gas start to condense.Thus if the pressure of a gas increases it starts to condense.

Explanation:

Hope It Helps!!!!

Answer:

See belwo

Explanation:

First it becomes a compressed gas.... further pressure will cause it to condense into a liquid.

Need Help!!

Explain the relationship between volume and temperature (Charles’ Law)

Answers

Answer:

the volume of a give gas simple is directly propotional assolute temperature at constant pressure .the volume of a gavi. amount of gass is inversely propotional ot Its pressure when temperature is help constant

Information about how a chemical reacts under high pressure can be found in the ""reactivity"" section of a msds. True or false?.

Answers

Information about how a chemical reacts under high pressure can be found in the "reactivity" section of a MSDS: True.

What is MSDS?

MSDS is an abbreviation for Material Safety Data Sheet and it can be defined as a text-based document which is designed and developed to provide more information with respect to the chemical and physical properties of an equipment, chemical compound, or substance, based on the following:

ReactivityFlammabilityTemperatureRadioactivity

In this context, we can infer and logically deduce that it is true that the information about how a chemical react would under high pressure can be found in the "reactivity" section of a Material Safety Data Sheet (MSDS).

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please help i'll give brainliest!!!!!

A competitive go-cart driver is traveling 32 m/s. He sees a caution flag go up, so he slows at a rate of -1.5 m/s2 in 10.8 s. What is his final velocity?

Answers

Answer:

15.8 m/s

Explanation:

v= u+at

v= 32+(-1.5×10.8)

v=32-16.2

v=15.8m/s

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