What is the range of the given function? {(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)

We can see here that the total weight of candy in a 5/6 pound bag site is 377 grams.

Weight is a measure of the force exerted by gravity on an object. It is the measure of how heavy an object is. Weight is typically expressed in units such as pounds or kilograms. The weight of an object can vary depending on the gravitational force acting on it.

There are 16 ounces in a pound.

Thus, a 5/6 pound bag of candy weighs

5/6 × 16 = 13.3 ounces.

If you want to know the weight in grams, 13.3 ounces is equal to 377 grams.

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Answer: Should be 275%

Step-by-step explanation:

Answer:

x = 3/2 or x = -1

Step-by-step explanation:

2x² - x - 3 = 0

2*(-3) = -6

Factors of -6:

(-1, 6), (1, -6), (-2, 3), (2, -3)

We need to find a pair that adds up to the co-eff of x which is (-1)

Factors :(2,-3)

2 - 3 = -1

so, 2x² - x - 3 = 0 can be written as:

2x² + 2x - 3x - 3 = 0

⇒ 2x(x + 1) -3(x + 1) = 0

⇒ (2x - 3)(x + 1) = 0

⇒ 2x - 3 = 0 or

x + 1 = 0

⇒ 2x = 3 or x = -1

⇒ x = 3/2 or x = -1

Step-by-step explanation:

(x,y)-----(-20,-4)-----(-17,-5)

to go from -17 to -20 you subtract 3

to go from -20 to x you subtract 3 again to get -20-3=-23

to go from -5 to -4 you add 1

to go from -4 to y you add 1 again to get -4+1=-3

(-23,-3)  (the midpoint is equidistant from both endpoints)

Data

• distance: 37.5 meters

• speed: 3 meters/minute

• time: ? minutes

•

From definition:

speed = distance/time

Replacing with data, and solving for time:

3 = 37.5/time

time = 37.5/3

time = 12.5 minutes

Answer:

{ \(\frac{3}{5}\), 3 }

Step-by-step explanation:

Given

(3x - 9)(5x - 3) = 0

Equate each factor to zero and solve for x

3x - 9 = 0 ( add 9 to both sides )

3x = 9 ( divide both sides by 3 )

x = 3

and

5x - 3 = 0 ( add 3 to both sides )

5x = 3 ( divide both sides by 5 )

x = \(\frac{3}{5}\)

y = 3x/4

GIven: m = slope = 3/4

b = y-intercept = 0

We use the equation of line formula to get the equation

equation of line: y = mx + b

We insert the above into the formula:

y = 3/4 (x) + 0

y = 3x/4

Hence the equation of the line with the given slope,m and y-intercept (0,b) is y = 3x/4

Complete question is;

A researcher wished to compare the average amount of time spent in extracurricular activities by high school students in a suburban school district with that in a school district of a large city. The researcher obtained a simple random sample of 60 high school students in a large suburban school district and found the mean time spent in extracurricular activities per week to be six hours with a standard deviation of three hours. The researcher also obtained an independent simple random sample of 40 high school students in a large city school district and found the mean time spent in extracurricular activities per week to be four hours with a standard deviation of two hours. Let x¯1 and x¯2 represent the mean amount of time spent in extracurricular activities per week by the populations of all high school students in the suburban and city school districts, respectively. Assume two-sample t procedures are safe to use?

what is the 95% confidence interval a researcher wishes to compare the average amount of time spent in extracurricular?

Answer:

CI = (0.755, 3.245)

Step-by-step explanation:

For SRS of 60;

Mean: x1¯ = 6

Standard deviation: s1 = 3

For SRS of 40;

Mean: x2¯ = 4

Standard deviation; s2 = 2

Critical value for the confidence interval of 95% is: t = 1.96

Formula for the CI is;

CI = (x¯1 - x¯2) ± t√[(s1²/n1) + ((s2)²/n1)]

Plugging in the relevant values, we have:

CI = (6 - 4) ± 1.96√[(3²/60) + ((4)²/40)]

CI = 2 ± 1.96√[(3²/60) + ((4)²/40)]

CI = 2 ± 1.96√0.55

CI = 2 ± 1.245

CI = [(2 - 1.245), (2 + 1.245)]

CI = (0.755, 3.245)

Answer:

B) y - 2 = (-1/4)(x - 2)

Step-by-step explanation:

Start with the equation of the given line: y = 4x + 7.

Determine the slope of the given line, which is 4.

Since the perpendicular line has a negative reciprocal slope, the perpendicular line's slope is -1/4.

Use the point-slope form of a linear equation: y - y₁ = m(x - x₁), where (x₁, y₁) is the given point and m is the slope.

Substitute the values x₁ = 2 and y₁ = 2 into the point-slope equation: y - 2 = (-1/4)(x - 2).

Simplify by distributing -1/4 to (x - 2): y - 2 = (-1/4)x + 1/2.

Add 2 to both sides to isolate y: y = (-1/4)x + 1/2 + 2.

Simplify further: y = (-1/4)x + 5/2.

The equation in point-slope form for the line passing through (2, 2) and perpendicular to y = 4x + 7 is y - 2 = (-1/4)(x - 2), which matches option B.

Answer:

Earned Income because she is working full time, but also adds the extra 20$ for when she tutors in her free time

Step-by-step explanation:

Answer:

x = 16

Step-by-step explanation:

Opposite sides are equal in a parallelogram

AD = BC

5x - 12 = 3x + 20

5x - 3x = 20 + 12

2x = 32

x = 32/2

x = 16

Answer:

\(\begin{aligned}SA &= 7.125\pi \text{ in}^2\\& \approx 22.4 \text{ in}^2 \end{aligned}\)

Step-by-step explanation:

We can find the Surface Area of the can by adding the areas of each of its parts:

\(SA = 2( A_{\text{base}}) + A_\text{side}\)

First, we can calculate the area of the circular base:

\(A_{\text{circle}} = \pi r^2\)

\(A_{\text{base}} = \pi (0.75 \text{ in})^2\)

\(A_{\text{base}} = 0.5625\pi \text{ in}^2\)

Next, we can calculate the area of the rectangular side:

\(A_\text{rect} = l \cdot w\)

\(A_\text{side} = (4\text{ in}) \cdot C_\text{base}\)

Since the width of the side is the circumference of the base, we need to calculate that first.

\(C_\text{circle} = 2 \pi r\)

\(C_\text{base} = 2 \pi (0.75 \text{ in})\)

\(C_\text{base} = 1.5 \pi \text{ in}\)

Now, we can plug that back into the equation for the area of the side:

\(A_\text{side} = (4\text{ in}) (1.5\pi \text{ in})\)

\(A_\text{side} = 6\pi \text{ in}^2\)

Finally, we can solve for the surface area of the can by adding the area of each of its parts.

\(SA = 2( A_{\text{base}}) + A_\text{side}\)

\(SA = 2(0.5625\pi \text{ in}^2) + 6\pi \text{ in}^2\)

\(\boxed{SA = 7.125\pi \text{ in}^2}\)

\(\boxed{SA \approx 22.4 \text{ in}^2}\)

The range of the graph of the exponential function is (b) {y | y > 0}

From the question, we have the following parameters that can be used in our computation:

The graph of the exponential function

The rule of an exponential function is that

The domain is the set of all real numbers

This means that the input value can take all real values

However, the range is always greater than the constant term

From the graph, the constant term is 0

So, the range is y > 0

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The measurement of each of the squares will guarantee Mrs. O'Dell has 8 different squares and they are all the same size are 75 centimeters by 100 centimeters.

To begin, let's identify the best way to divide the total area. For this, there are 2 options:

Let's use the first pattern:

Based on this, the dimensions for each section should be 75 centimeters by 100 centimeters.

Note: This question is incomplete; here is the missing section:

Dimensions of the garden: 3 meters x 2 meters

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Answer:

10

Step-by-step explanation:

Answer:

10 apples

Step-by-step explanation:

20% of 50 = 10

10 apples

Answer:

A=60

Step-by-step explanation:

Complementary means it's 90 degrees

60 and 30 have a 30 degree difference.

The measure of angle a is 60°

What are Complementary Angles?

When the sum of two angles is equal to 90 degrees, they are called complementary angles. For example, 30 degrees and 60 degrees are complementary angles.

Given data ,

The two angles are a and b

a and b are complementary

So , a + b = 90°

The difference of angle a and b is 30°

The greater angle is a and smaller angle is b

So , a - b = 30°

Now , we have two equations

a + b = 90°

a - b = 30°

Adding both equations , we get

2a = 120°

Divide by 2 on both sides , we get

a = 60°

Hence , the measure of angle a is 60°

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Answer:

A) True

Hope this helps!

The 18th term of the sequence is -83, the correct option is C.

An arithmetic sequence is sequence of integers with its adjacent terms differing with one common difference.

If the initial term of a sequence is 'a' and the common difference is of 'd', then we have the arithmetic sequence as:

a, a + d, a +  2d, ... , a + (n-1)d, ...

Its nth term is

T_n = a + (n-1)d

(for all positive integer values of n)

And thus, the common difference is

T_{n+1} - T_n

for all positive integer values of n

Given:

The sequence=19,13,7,1...

n=18

D= 13-19

D= 6, a= 19

Now,

=a + (n+1)d

=19+(18-1)x-6

=-83

Therefore, the 18th term of the sequence will be -83

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Answer:

The Least Common Multiple is 3

Step-by-step explanation:

Maria's error was that she tried finding the largest multiple rather than the least.

Answer:

Step-by-step explanation:

Maria's error on this is the LCM is 30 not 60

the least is 30 not 60

Answer:

At least 39200 students.

Step-by-step explanation:

Given that there are 196 countries in the world, and each country would have at least 200 students in a university.

For each country to have at least 200 students in the university, then;

Number of students enrolled in the university = number of required students x number of countries

                                      = 200 x 196

                                      = 39200

At least, 39200 students must be enrolled in the university. Provided that the admission procedures are conditioned for the purpose.

Answer:

The expected loss for the car owner per year is $750.

Step-by-step explanation:

We are given that a car owner who has an 80% chance of no accidents in a year, a 20% chance of being in a single accident in a year, and no chance of being in more than one accident in a year.

Let X = Loss for the particular year for a car owner

Now as we know that the loss to the car owner may be of $0, $500, $5,000 or $15,000 because these amount he has to pay as a part of repair cost if his car met with an accident.

So, the probability distribution of X is given by;

           X (Amount of Loss)                               P(X)

                     $0                                                      0.80

                      $500                                            (0.20)(0.50) = 0.10

                      $5,000                                         (0.20)(0.40) = 0.08

                      $15,000                                        (0.20)(0.10) = 0.02

                       Total                                                         1                    

Here, the probability of (0.20)(0.50) means that for the loss of $500, first the car must have to met with an accident and then there is 50% chance that after the accident the car will need repairs costing $500.

Now, the expected loss for the car owner per year is  = \(\sum (X \times P(X))\)

   \(\sum (X \times P(X))\)  =  \((0 \times 0.80) + (500 \times 0.10)+(5,000 \times 0.08)+(15,000 \times 0.02)\)

                           =  50 + 400 + 300 = $750.

So, the expected loss for the car owner per year is $750.

The correct option is the third one, it can be written as the equation:

y = A*(1 - 0.073)ˣ

A general exponential decay can be written as:

y = A*(b)ˣ

Where A is the initial value, and b is the base.

It is an exponential decay only if 0 < b < 1.

From the given options, the one that can be modeled with an exponential decay is a car whose price depreciuates at a rate of 7.3% per year, because if the initial price of the car is A, we can write it as:

y = A*(1 - 0.073)ˣ

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The probability that a randomly chosen family has five children is 1/20.The probability that a randomly chosen child comes from a family with two children 1/3.

(a) To find the probability that a randomly chosen family has i children, we divide the number of families with is children by the total number of families in the community organization. Similarly, the probability that a randomly chosen family has three children is

5/20 = 1/4, the probability that a randomly chosen family has four children is

2/20 = 1/10, and the probability that a randomly chosen family has five children is 1/20.

(b) To find the probability that a randomly chosen child comes from a family having i children, we divide the number of children in families with i children by the total number of children in the community organization. The total number of children in the community organization is

4 + 16 + 15 + 8 + 5 = 48 children

Hence, the probability that a randomly chosen child comes from a family with one child is

4/48 = 1/12

The probability that a randomly chosen child comes from a family with two children is 16/48 = 1/3, and so on.

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Answer:

the inequaltiy is 16.5x\(\leq\)363

X \(\leq\)22

Step-by-step explanation:

Okay so we can’t go over 363 miles since thats the maximum amount of miles for a full tank

1 gallon can travel 16.5 miles

So we can make x stand for amount of gallons

16.5x\(\leq\)363

Now that makes sense becuase 16.5 miles for every gallon and we don’t know how much gallons since its not stated, now the amount can’t pass 363 but it could be equal so we make an less than or equal to sign

For X we solve it and get x\(\leq\)22.

So a full tank can have 22 or less gallons of gas.

The exact values for trigonometric functions are:

a) cos(A+B)=56/65

b) sin(A+B)=-33/65

c) sin(A-B)=-33/65

a) We have, cos A = -3/5 (using Pythagorean identity

and sin B = -5/13 (using Pythagorean identity  = 1).

Using the formula for cosine of sum of two angles, we have:

cos (A+B) = cos A cos B - sin A sin B

\(=(-3/5)(-12/13)-(4/5)(-5/13)\\\\=56/65\)

b) Using the same formula for sine of sum of two angles, we have:

sin (A+B) = sin A cos B + cos A sin B

\(=(-3/5)(-12/13)-(4/5)(-5/13)\\\\=-33/65\)

c) Using the formula for sine of difference of two angles, we have:

sin (A-B) = sin A cos B - cos A sin B

\(453=(4/5)(-12/13)+(-3/5)(-5/13)\\\\=-33/65\)

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Answer:

m > 82.28

Step-by-step explanation:

Price to Pay (P)

distance (m)

Company A

Pa = 0.80m

Company B

Pb = 65 + 0.01m

Company A charge more than B is written like this

0.8m > 65 + 0.01m

then we can solve this inequality

(0.8 - 0.01)m > 65

0.79m > 65

m > 65/0.79

m > 82.28 miles

so if Maya will go more than 82.28 miles, I suggest Company B is cheaper

Answer:

The depreciation tax shield for this project in year 4 is $178.24.

Explanation:

To calculate the depreciation tax shield for this project in year 4, we need to first determine the depreciation expense for year 4 using the MACRS three-year class life category and the double-declining balance (DDB) method.

From Table 12.8 on page 415 of the textbook, we can see that the depreciation rate for year 1 is 33.33%, for year 2 it is 44.45%, for year 3 it is 14.81%, and for year 4 it is 7.41%.

Using the DDB method, we can calculate the depreciation expense for each year as follows:

Year 1: Depreciation expense = $14,000 x 33.33% = $4,667

Year 2: Depreciation expense = ($14,000 - $4,667) x 44.45% = $3,554

Year 3: Depreciation expense = ($14,000 - $4,667 - $3,554) x 14.81% = $830

Year 4: Depreciation expense = ($14,000 - $4,667 - $3,554 - $830) x 7.41% = $557

The total depreciation expense over the four years is the sum of the individual year's depreciation expenses, which is:

$4,667 + $3,554 + $830 + $557 = $9,608

Now, we can calculate the depreciation tax shield in year 4. The depreciation tax shield is the amount of the depreciation expense that reduces the firm's taxable income, multiplied by the tax rate. In year 4, the depreciation tax shield is:

Depreciation tax shield = Depreciation expense in year 4 x Tax rate

Depreciation tax shield = $557 x 32% = $178.24

Therefore, the depreciation tax shield for this project in year 4 is $178.24.

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