What is the range(spread)in the student enrollment

Answer:

1.875

Step-by-step explanation:

the average rate of change of g(x) in the closed interval [ a, b ] is

\(\frac{g(b)-g(a)}{b-a}\)

here [a, b ] = [- 1, 3 ] , then

g(b) = g(3) = 2³ + 1 = 8 + 1 = 9

g(a) = g(- 1) = \(2^{-1}\) + 1 = \(\frac{1}{2}\) + 1 = 1.5

then

average rate of change = \(\frac{9-1.5}{3-(-1)}\) = \(\frac{7.5}{4}\) = 1.875

Answer:

is 3 units away from c

Step-by-step explanation:

Answer:

yes

Step-by-step explanation:

that's hard but you'll figure it out so don't worry

Answer:

See below.

Step-by-step explanation:

Alexi originally has $43 in his bank account and deposits $7 per week.

Week 1: $50

Week 2: $57

Week 3: $64

Week 4: $71

Week 5: $78

The pattern is that it increased $7 every week starting from $43.

A pattern rule would be: y = 7x + 43 where x represents the number of weeks.

On solving the provided question we can say that, the answer of the following number line will be  \(=|x-y| or |y-x|\)\(=|3-(-4)| or |-4-3|\)

A number line is a visual representation of real numbers in elementary mathematics. It is an image of a magnitude line. On the number line, each point represents a real number, and each real number is taken to represent a point. A number line in mathematics is a horizontal straight line with numbers uniformly spaced apart. A number line can show how all the numbers in a series are represented. Both endpoints of this line continue indefinitely.

On the number line, the two points are

\(x = -4\\ y=3\)

The distance is a quantity that is positive.

As a result, the distance between x and y may be expressed as:

\(=|x-y| or |y-x|\\ =|3-(-4)| or |-4-3|\\ =|3+4| or |-7|\\ =|7| or |-7|\)

The sentence will read:

\(=|x-y| or |y-x|\)

\(=|3-(-4)| or |-4-3|\)

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Answer:x 55x5x5x56x6x7x74 4,527,600

Answer:

that is so cool! Keep up the great work Josh

Step-by-step explanation:

The conditional proportions of people using their phones in the afternoon and the evening can be summarized as follows: A significant proportion of individuals use their phones both in the afternoon and evening, indicating a consistent pattern of phone usage throughout the day.

In the afternoon, many people rely on their phones for various purposes such as work, communication, entertainment, and staying connected to social media. With the advancements in technology and increased accessibility to smartphones, it has become common for individuals to utilize their phones during this time. Whether it's checking emails, browsing the internet, or engaging in social media activities, the afternoon serves as a convenient time for phone usage.

Moving on to the evening, phone usage remains prevalent as individuals unwind and engage in leisure activities. During this time, people often use their phones for entertainment purposes, such as streaming videos, playing games, or engaging in social interactions through messaging apps or social media platforms. The evening also offers a time for catching up on news, reading, or engaging in personal hobbies, which may involve the use of mobile devices.

Overall, the conditional proportions reveal that phone usage is not limited to a specific time of day but rather extends throughout the afternoon and evening. This emphasizes the significant role that smartphones play in our daily lives, providing us with a range of functionalities and opportunities for connectivity and entertainment.

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The probability is 1/10.

The equation x(x+5) = -n can be rewritten as x^2 + 5x + n = 0. To find the solutions of this equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a, where a = 1, b = 5, and c = n.

For there to be no real solutions, the discriminant (b^2 - 4ac) must be negative. The discriminant is 5^2 - 4(1)(n) = 25 - 4n. So for there to be no real solutions, 25 - 4n < 0, or n > 6.25.

Since the integer n is between 1 and 10 inclusive, the only value that would not have a real solution is n = 7. Therefore, the probability that for the randomly chosen n there exist no real solutions is 1/10.

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To find (f+g)(x), we first need to add the functions f(x) and g(x) together.
f(x) = 3x - 2
g(x) = x^2 + 5x

(f+g)(x) = f(x) + g(x)
= (3x - 2) + (x^2 + 5x)
= x^2 + 8x - 2
Therefore, the answer to (f+g)(x) is x^2 + 8x - 2. This function represents the sum of f(x) and g(x) evaluated at x.
I hope this helps!

To find (f+g)(x), you need to add the functions f(x) and g(x) together. Without knowing the specific functions, I cannot provide a complete solution. However, the general process is as follows:
1. Identify the functions f(x) and g(x).
2. Add the functions together: (f+g)(x) = f(x) + g(x).
3. Simplify the expression if possible.
If you can provide the specific functions f(x) and g(x), I'd be happy to help you further in finding (f+g)(x).

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Answer:

Sorry dude I don't know the answer.

The number of cruise passengers must there have been in 2017 is  26.7 million.

The term "percentage" comes from the Latin phrase "per centum," meaning "by the hundred." Percentages represent fractions with a denominator of 100. In other terms, it is the relationship between portion and whole in which the value of the whole is always assumed to be 100.

Now according to the question;

Let x represent the total number for cruise passengers during 2017.

In 2018, a 6.7% rise in x results in 28.5 million cruise passengers.

So, 106.7 % of x = 28.5

\(\begin{aligned}&\frac{106.7}{100} * x=28.5 \\&\frac{106.7 x}{100}=28.5\end{aligned}\)

Multiplying both sides by 100;

\(\begin{aligned}&\frac{106.7 x}{100} * 100=28.5 * 100 \\&106.7 x=2850\end{aligned}\)

Dividing both sides by 106.7;

\(\frac{106.7 x}{106.7}=\frac{2850}{106.7}\)

x = 26.7

Therefore, the number of cruise passengers in 2017 must have ranged from 26.7 million.

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Answer:

B

Step-by-step explanation:

12 multiplied by 5 is 60 and 10 multiplied by 6 is 60. which is the lowest that they both will meet

Answer:

24

Step-by-step explanation:

The Maclaurin series for f(x) converges absolutely for x within the interval (-2/3, 2/3).

To find the Maclaurin series for the function f(x) = (3cos(x))ln(1+x), we can use the standard formulas for the Maclaurin series expansion of elementary functions.

First, let's find the derivatives of f(x) up to the third order:

f(x) = (3cos(x))ln(1+x)

f'(x) = -3sin(x)ln(1+x) + (3cos(x))/(1+x)

f''(x) = -3cos(x)ln(1+x) - (6sin(x))/(1+x) + (3sin(x))/(1+x)² - (3cos(x))/(1+x)²

f'''(x) = 3sin(x)ln(1+x) - (9cos(x))/(1+x) + (18sin(x))/(1+x)² - (12sin(x))/(1+x)³ + (12cos(x))/(1+x)² - (3cos(x))/(1+x)³

Next, we evaluate these derivatives at x = 0 to find the coefficients of the Maclaurin series:

f(0) = (3cos(0))ln(1+0) = 0

f'(0) = -3sin(0)ln(1+0) + (3cos(0))/(1+0) = 3

f''(0) = -3cos(0)ln(1+0) - (6sin(0))/(1+0) + (3sin(0))/(1+0)² - (3cos(0))/(1+0)² = -3

f'''(0) = 3sin(0)ln(1+0) - (9cos(0))/(1+0) + (18sin(0))/(1+0)² - (12sin(0))/(1+0)³ + (12cos(0))/(1+0)² - (3cos(0))/(1+0)³ = -9

Now we can write the first three nonzero terms of the Maclaurin series:

f(x) = f(0) + f'(0)x + (f''(0)/2!)x² + (f'''(0)/3!)x³ + ...

f(x) = 0 + 3x - (3/2)x² - (9/6)x³ + ...

Simplifying, we have:

f(x) = 3x - (3/2)x² - (3/2)x³ + ...

To determine the values of x for which the series converges absolutely, we need to find the interval of convergence. In this case, we can use the ratio test:

Let aₙ be the nth term of the series.

|r| = lim(n->infinity) |a_(n+1)/aₙ|

= lim(n->infinity) |(3/2)(xⁿ+1)/(xⁿ)|

= lim(n->infinity) |(3/2)x|

For the series to converge absolutely, we need |r| < 1:

|(3/2)x| < 1

|x| < 2/3

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Answer:

2x + 5

Step-by-step explanation:

I am assuming you are talking about a linear function. If it is, then the equation would be:

2x + 5.

Hope this helps!

Answer:

\(y = 2x + 5\)

Step-by-step explanation:

For this example, I used the slope-intercept form, \(y = mx + b\), where m represents the slope and b represents the y-intercept.

In order to find the equation, we must find the slope and y-intercept.

The slope can be found with the formula:

\(m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\), where the x and y variables represent different x and y values from the given points.

Substituting in values from the points, we get:

\(m = \frac{-1 + 9}{-3 + 7}\\\\m = \frac{8}{4}\\\\m = 2\)

In order to find the y-intercept, we must substitute the slope back into the original equation:

\(y = 2x + b\)

After this, we must also substitute either of the two points. Both will give the correct answer, but (-3, -1) will be used for this example.

\(-1 = 2(-3) + b\\-1 = -6 + b\\5 = b\)

After this, all that must be done is to substitute the values for b and m back into the original equation.

\(y = 2x + 5\)

To check our work, we can substitute in either of the given points. For demonstration purposes, (-7, -9) will be used.

\((-9) = 2(-7) + 5\\-9 = -14 + 5\\-9 = -9\)

Answer:

-8

Step-by-step explanation:

Answer: -3,4

Step-by-step explanation:

The transformation can be defined as the introduction of a new set of mathematical coordinates. The rule that can describe the translation of the black triangle into the blue triangle is T<-3, -4>(x,y).

The transformation can be defined as the introduction of a new set of mathematical coordinates that are declared to be different functions of the original coordinates.

The translation can be found by observing any one coordinate of the image and the preimage.

Hence, The rule that can describe the translation of the black triangle into the blue triangle is T<-3, -4>(x,y).

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The ratio of John's money to Peter's money is 5/4. This means if John has a total amount of 5 then Peter will have a total of 4 as his amount.

Let's assume John has 'x' amount of  money, Peter has 'y' amount of money, The money John saved is 'p' and the money Peter saved is 'q'

So,

p = x - 80x/100                (equation 1)

q = y - 75y/100                (equation 2)

According to the given question, the amount John saved is equal to the amount Peter saved. Hence, we can equate equations 1 and 2.

p = q

x- 80x/100 = y - 75y/100

x - 0.8x = y - 0.75y

0.2x = 0.25y

x =  0.25y/0.2

x/y = 0.25/0.2

x/y = 25/20

x/y = 5/4

Hence, the ratio of John's money to Peter's money is 5/4.

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In LR2 (two-dimensional Euclidean space), a line passing through the origin is closed under vector addition, meaning that if you take any two vectors on that line, their sum will also lie on the same line.

However, a line not passing through the origin is not closed under vector addition.

To illustrate this, let's consider a line L in LR2 that does not pass through the origin. We can represent this line as a straight line segment starting from a point A and ending at a point B. The line segment AB represents the line L.

Now, consider two vectors represented by two line segments starting from the origin O and ending at points C and D, respectively. These vectors can be represented as OC and OD. Since the line L does not pass through the origin, OC and OD will not lie on line L.

If we try to add these two vectors, we construct the parallelogram OBCD, where BC represents the vector addition OC + OD. Since OC and OD do not lie on line L, their sum BC will also not lie on line L. This violates the closure property, where the sum of two vectors on a line should also be on the same line.

the geometric figure, in this case, would consist of a line L not passing through the origin, two vectors OC and OD not lying on line L, and the resulting vector BC (sum of OC and OD) not lying on line L. This figure demonstrates that a line in LR2 not passing through the origin is not closed under vector addition.

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Answer:

44

Step-by-step explanation:

5 1/2 = 11/2 = 44/8

Subtract 1/8 from 44/8 until you finish the number all.

Answer:

  c:  8,20,25

Step-by-step explanation:

You want to know which set of side lengths can form a triangle from the sets ...

A set of lengths can form a triangle if and only if the sum of the shorter two exceeds the longest.

In sets a, b, d, the sum of the shorter two is equal to the longest. These lengths will form a line segment, not a triangle.

A triangle can be formed by ...

  c: 8,20,25 . . . . . . 8+20=28 > 25

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The two-period moving average model and the two-period weighted moving average model are both common forecasting methods used to predict future demand. and we understand that the model with the lower MAD and MSE values will have the most accurate forecast.

To determine which model is better for this particular data set, we need to compare the accuracy of each model. To do this, we will calculate the Mean Absolute Deviation (MAD) and the Mean Squared Error (MSE) for each model.
For the two-period moving average model, we can calculate the forecast for period 7 by taking the average of p5 and 6:

Period 7 forecast = (Gallons in Period 5 + Gallons in Period 6)/2

For the two-period weighted moving average model, we can calculate the forecast for period 7 by using the weights of 0.6 and 0.4:

Period 7 forecast = (0.6 x Gallons in Period 5) + (0.4 x Gallons in Period 6)

We can then compare the accuracy of each model by calculating the MAD and MSE. To calculate MAD, we need to subtract the actual demand in each period from the forecasted demand and take the absolute value:

MAD = |Actual demand – Forecasted demand|

To calculate MSE, we need to square the differences between the actual demand and the forecasted demand:

MSE = (Actual demand – Forecasted demand)^2

After calculating the MAD and MSE for each model, we can compare the results to determine which model is better for this data set. The model with the lower MAD and MSE values will have the most accurate forecast.

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Answer:

0.7

Step-by-step explanation:

if we set the total race of win and lose is 1

then we use 1-0.3=0.7

Answer:0.1

Step-by-step explanation:

0.1

Answer:

Step-by-step explanation:

plane traveled 3200 km

aver. velocity = 222 m/s

find:

How long was the flight from Nevada to LA in seconds.

solution:

time = distance / velocity

       =   3200 km    x     1000 m    

               222 m/s            1 km

        =  14,414.41 seconds

Answer:

3b/2 + 3

Step-by-step explanation:

The formula to calculate perimeter of rectangle is 2l + 2w

The length is half the width so length is 1/2 (b/2 +1), which when simplified is b/4 + 1/2

Using the formula to calculate perimeter you can substitute and calculate

p= 2l + 2w

p= 2(b/4 + 1/2) + 2(b/2 + 1)

p= 2b/4 +2/2 + 2b/2 +2

p= 1/2b + 1 + b + 2

p= 3/2b + 3

Simplified it's 3b/2 +3