What is the resultant pressure if 3. 5 mol of


ideal gas at 273 K and 0. 96 atm in a closed


container of constant volume is heated to


619 K? Answer in units of atm

If we have a cup of ice cubes that weigh 80 grams and we place high heat under the cup, the ice will get converted into water . This stage is known as melting.

Melting is a phase change from solid to liquid under application of a certain temperature. Melting usually occurs when temperature is added to a body. It is a physical change of matter. The melting point is the temperature at which any substance melts i.e changes its state from solid to liquid.  The melting point of all pure samples of a compound is the same as it is an intensive property. The melting of a substance at its melting point is an isothermal process

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The mineral that is required to be added to the enrichment of bread is iron.

Bread enrichment is a common practice in the bakery industry, particularly for wheat-based bread. It is the procedure of adding nutrients to bread to compensate for the nutrients lost during milling and processing. This guarantees that the bread is nutritious and healthy.

Iron in bread enrichmentIron is required in the enrichment of bread. Iron is a nutrient that is required in small amounts. It is an essential mineral that is responsible for forming hemoglobin, a protein in the red blood cells that transports oxygen around the body.

Iron deficiency can lead to anemia and several other health problems. Since the majority of people do not receive sufficient iron from their diets, enrichment is a good method to guarantee that bread consumers get enough of it.

Thus, the correct answer is iron.

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The energy of a photon is given by the equation:



E = hc/λwhere h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.Substituting the given values, we get:E = (6.626 × 10^-34 J s)(2.998 × 10^8 m/s)/(587 × 10^-9 m)E = 3.38 × 10^-19 J per photonTo find the energy for 1 mole of photons, we need to multiply the energy per photon by Avogadro's number:E = (3.38 × 10^-19 J/photon) × (6.022 × 10^23 photons/mol)E = 2.04 × 10^5 J/molConverting to kilojoules:E = 2.04 × 10^5 J/mol / 1000 J/kJE = 204 kJ/molTherefore, the energy for 1 mole of photons with a wavelength of 587 nm is 204 kJ/mol.A laser is releasing photons with a 587 nm wavelength. What is the energy in kilojoules per mole for one of these photons?

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After 21.04 years, 50g of cobalt-60 remains.

Cobalt-60 is a radioactive isotope with a half-life of 5.27 years. This means that after 5.27 years, half of the initial amount of cobalt-60 will have decayed. After another 5.27 years, half of the remaining cobalt-60 will have decayed, and so on. Therefore, to find out how much cobalt-60 remains after 21.04 years, we need to calculate the number of half-lives that have elapsed.

21.04 years divided by the half-life of cobalt-60 (5.27 years) equals approximately 4. Therefore, after 21.04 years, 2^4, or 16 times less cobalt-60 remains. Starting with 100g, we can calculate that 100g divided by 16 equals 6.25g. Therefore, 50g of cobalt-60 remains after 21.04 years.

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Answer:

See explanation

Explanation:

For a chemical system in a state of dynamic equilibrium, the rate of forward reaction is equal to the rate of reverse reaction.

For this system under consideration;

I2(s)⇄I2(g)

When we heat the container, solid iodine is converted into purple coloured iodine vapour.

When equilibrium is achieved in the system, there will be no net change in the amount of solid iodine and iodine vapour present in the system since the rate of forward and reverse reactions are equal for a system in a state of equilibrium.

Answer:

Ride a bike or walk. If you are only going a short distance, consider riding a bike or walking instead of driving. ...

Take public transit. ...

Carpool. ...

Avoid idling. ...

Use alternative fuels.

The majority of the lead(II) iodide in the solution precipitates out as a yellow solid flag.

Define lead iodide?

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Answer:

The energy required to evaporate a cup of water (270 g) is approximately 2,215 joules. This is calculated by multiplying the mass of the water by the latent heat of vaporization (2.26 kJ/g) for water.

Explanation:

Answer:2.26 kj

Explanation:

(i) The air/fuel ratio by mass is approximately 0.0487 kg air / kg fuel.

(ii) The rate of heat loss from the combustion chamber is approximately 0.0349 kW.

To solve the given problem, we need to determine the air/fuel ratio by mass and the rate of heat loss from the combustion chamber. Let's calculate each of these values step by step:

(i) Air/Fuel Ratio by Mass:

To calculate the air/fuel ratio by mass, we need to determine the mass flow rates of air and fuel entering the combustion chamber.

Given:

Flow rate of fuel (benzene): 0.05 kg/min

To find the mass flow rate of air, we need to determine the stoichiometric ratio between air and fuel. The balanced equation for the combustion of benzene (C₆H₆) is:

C₆H₆ + (15/2)O₂ → 6CO₂ + 3H₂O

From the balanced equation, we can see that 1 mole of C₆H₆ reacts with (15/2) moles of O₂. Therefore, the stoichiometric ratio of air to fuel is:

(15/2) * (32 kg O₂ / 1 mole O₂) / (78 kg C₆H₆ / 1 mole C₆H₆) = 20.51 kg air / kg fuel

The air/fuel ratio by mass is the inverse of the stoichiometric ratio:

1 / (20.51 kg air / kg fuel) = 0.0487 kg fuel / kg air

Therefore, the air/fuel ratio by mass is approximately 0.0487 kg air / kg fuel.

(ii) Rate of Heat Loss from the Combustion Chamber:

To determine the rate of heat loss, we can use the energy balance equation for the combustion chamber. The energy balance equation is:

Q_in - Q_out - W_out = ΔE_system

where:

Q_in = Heat input from fuel combustion

Q_out = Heat loss from the combustion chamber

W_out = Work output from the combustion chamber

ΔE_system = Change in internal energy of the combustion chamber

In this case, the process is steady flow and constant pressure, so there is no work output (W_out). Additionally, we can assume that there is no change in internal energy (ΔE_system ≈ 0) since the temperature difference is relatively small.

Therefore, the energy balance equation simplifies to:

Q_in - Q_out = 0

This means that the heat input from fuel combustion is equal to the heat loss from the combustion chamber.

To calculate the rate of heat loss, we need to determine the heat input from fuel combustion. The heat of combustion for benzene (C₆H₆) is -3267 kJ/mol.

Given:

Flow rate of fuel (benzene): 0.05 kg/min

Heat of combustion of benzene: -3267 kJ/mol

First, we need to convert the flow rate of fuel to moles per minute. The molar mass of benzene (C₆H₆) is:

(6 * 12 kg/mol) + (6 * 1 kg/mol) = 78 kg/mol

The moles of benzene consumed per minute is:

(0.05 kg / min) / (78 kg/mol) = 0.000641 mol / min

The heat input from fuel combustion is:

Heat input = moles of fuel * heat of combustion

= 0.000641 mol / min * (-3267 kJ/mol)

= -2.095 kJ/min

Since the heat input and heat loss are equal (Q_in = Q_out), the rate of heat loss from the combustion chamber is 2.095 kJ/min (or 0.0349 kW).

Therefore, the rate of heat loss from the combustion chamber is approximately 0.0349 kW.

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Answer:

Yes

Beryllium is a chemical element with the symbol Be and atomic number 4. It is a steel-gray, strong, lightweight and brittle alkaline earth metal. ... Notable gemstones high in beryllium include beryl (aquamarine, emerald) and chrysoberyl.

Calcium is a mineral that is necessary for life. In addition to building bones and keeping them healthy, calcium enables our blood to clot, our muscles to contract, and our heart to beat. About 99% of the calcium in our bodies is in our bones and teeth.

Answer:

Sugar dissolves best in water

Carbon Dioxide dissolves best in water

(Not 100% sure on this one) Salt is the least soluble in water

I hope this helped :)

The pH of the solution after mixing is 3.17 in the given case.

To solve this problem, we first need to determine the number of moles of HCl and NaF that were mixed together. We can use the formula:

moles = concentration x volume

For HCl:

moles of HCl = 0.3 M x 0.125 L = 0.0375 moles HCl

For NaF:

moles of NaF = 0.15 M x 0.32 L = 0.048 moles NaF

Since NaF is a salt of a weak acid (HF) and a strong base (NaOH), it will undergo hydrolysis in water, which means that it will react with water to produce hydroxide ions (OH-) and the weak acid HF. The balanced equation for the hydrolysis of NaF is:

NaF + H2O → Na+ + OH- + HF

To determine the concentration of OH- produced by the hydrolysis of NaF, we need to use the Kb value of the HF:

\(Kb = [OH-][HF] / [NaF]\)

The Kb value for HF is 6.8 x 10^-4. At equilibrium, the concentration of HF produced by the hydrolysis of NaF will be equal to the concentration of NaF that is consumed, so we can substitute [HF] = 0.048 M into the equation:

\(6.8 x 10^-4 = [OH-][HF] / [NaF]\\6.8 x 10^-4 = [OH-] x 0.048 / 0.048\\[OH-] = 6.8 x 10^-4 M\)

Now we can use the fact that HCl is a strong acid to assume that all of the HCl will react with the OH- ions produced by the hydrolysis of NaF. This means that the concentration of H+ ions in the solution will be equal to the concentration of OH- ions produced by the hydrolysis of NaF:

\([H+] = [OH-] = 6.8 x 10^-4 M\)

To calculate the pH of the solution, we can use the formula:

\(pH = -log[H+]pH = -log(6.8 x 10^-4) = 3.17\)

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The joules required to boil 150. grams of water, given the heat of vaporization of water is 338,400 J.

To calculate the amount of energy required to boil 150 grams of water, we can use the following formula:

q = m × ΔHvap

First, we need to convert the heat of vaporization from kJ/mol to J/g:

40.67 kJ/mol = 40.67 × 10^3 J/mol

40.67 × 10^3 J/mol / 18.02 g/mol = 2256 J/g

So the heat of vaporization of water is 2256 J/g.

Now we can plug in the values:

q = 150 g × 2256 J/g

q = 338,400 Joules

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The Nernst equation, the modification that must be made to the free energy equation is that Gibbs free energy is expressed in terms of cell potential. Here's a step-by-step explanation:

1. Start with the Gibbs free energy equation:
ΔG = ΔG° + RT ln(Q)

2. Recognize the relationship between Gibbs free energy and cell potential:
ΔG = -nFE
ΔG° = -nFE°

3. Substitute the expressions for ΔG and ΔG° in terms of cell potential into the Gibbs free energy equation:
-nFE = -nFE° + RT ln(Q)

4. Rearrange the equation to isolate E (cell potential) on one side:
E = E° - (RT/nF) ln(Q)

This final equation is the Nernst equation, where E is the cell potential, E° is the standard cell potential, R is the gas constant, T is the temperature, n is the number of moles of electrons, F is the Faraday constant, and Q is the reaction quotient.

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By using acid-base extraction, you can effectively separate benzoic acid from potassium carbonate in a mixture. This method takes advantage of the difference in solubility and reactivity between the two substances.The method of separation

Here's a step-by-step explanation of how acid-base extraction can be used to separate benzoic acid and potassium carbonate:. First, dissolve the mixture in a suitable solvent, such as water. This will create a solution containing both benzoic acid and potassium carbonate.

Next, add an acid to the solution. Benzoic acid is a weak acid, so adding a stronger acid, such as hydrochloric acid (HCl), will cause the benzoic acid to react and form a soluble salt.The reaction between the acid and benzoic acid will result in the formation of a salt called benzoate, which is soluble in water.

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E(r) = 8π * [(-r^3/a_0^3 + 3r^2/a_0^2 - 6r/a_0 + 6) * exp(-r/a_0)] This is the expression for the expectation value of the radial distance of the electron in the 1s state of hydrogen.

To find the expectation value of the radial distance of the electron for the 1s state of hydrogen (H), we need to calculate the integral of the radial distance multiplied by the probability density function over all space.

In the case of the 1s state of hydrogen, the radial wavefunction is given by:

R(r) = (2/a_0^3/2) * exp(-r/a_0)

Where a_0 is the Bohr radius.

To calculate the expectation value, we need to integrate the radial distance r multiplied by the square of the radial wavefunction |R(r)|^2 over all space.

E(r) = ∫ (r * |R(r)|^2) * 4πr^2 dr

Since the 1s orbital is spherically symmetric, we integrate over all space from 0 to infinity.

To simplify the calculation, we can substitute u = r/a_0:

E(u) = ∫ (u * |R(u * a_0)|^2) * 4π(a_0^3) du

Now, substituting the radial wavefunction R(u * a_0):

E(u) = ∫ (u * (2/a_0^3/2) * exp(-u)) * 4π(a_0^3) du

Simplifying further:

E(u) = 8π ∫ u^3 * exp(-u) du

This integral can be solved using integration by parts. Let's denote I(n) as the integral of u^n * exp(-u) du. We can then express I(n) in terms of I(n-1):

I(n) = -u^n * exp(-u) + n * I(n-1)

Using this relation, we can calculate E(u):

E(u) = 8π * [ -u^3 * exp(-u) + 3 * (-u^2 * exp(-u) + 2 * (-u * exp(-u) + I(0)))]

Simplifying further:

E(u) = 8π * [-u^3 * exp(-u) + 3 * (-u^2 * exp(-u) + 2 * (-u * exp(-u) + exp(-u)))]

E(u) = 8π * [(-u^3 + 3u^2 - 6u + 6) * exp(-u)]

Finally, substituting u = r/a_0 back into the equation, we obtain the expectation value of the radial distance for the 1s state of hydrogen:

E(r) = 8π * [(-r^3/a_0^3 + 3r^2/a_0^2 - 6r/a_0 + 6) * exp(-r/a_0)]

This is the expression for the expectation value of the radial distance of the electron in the 1s state of hydrogen.

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Answer:

The awser is D.

The molar concentration of CO2 in a 4.26 L sample of acid rain is 0.0081 mol/L.Acid rain is caused by air pollution.

The molar concentration of carbon dioxide in a 4.26L sample of acid rain is calculated as follows:First, we will calculate the number of moles of carbon dioxide in the sample. The formula to calculate the number of moles is:Number of moles = mass of the substance/molar mass of the substanceThe molar mass of CO2 is 44.01 g/mol. 355 ppm means 355 parts per million, which is equivalent to 355 mg/L.To calculate the mass of carbon dioxide in 4.26 L of acid rain:Mass of CO2 = Volume × ConcentrationMass of CO2 = 4.26 L × 355 mg/L = 1510.3 mg = 1.51 gTherefore, the number of moles of CO2 in the sample is:Number of moles of CO2 = Mass of CO2/Molar mass of CO2 = 1.51 g/44.01 g/mol = 0.0344 molTo calculate the molar concentration of CO2:Molar concentration of CO2 = Number of moles of CO2/Volume of solution in litersMolar concentration of CO2 = 0.0344 mol/4.26 L = 0.0081 mol/L, When sulfur dioxide and nitrogen oxide pollutants combine with atmospheric moisture, they form acidic compounds that can travel long distances and fall as acid rain. Acid rain can damage forests, kill fish in streams, and corrode buildings and monuments, among other things.

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The ion with the smallest radius is b. Cl-.

To determine which of the following has the smallest radius, let's compare the elements and ions: a. P, b. Cl-, c. Al, d. S2-, and e. Ga.

1. Consider the periodic trends: atomic radius increases from top to bottom in a group and decreases from left to right across a period.

2. Compare the elements and ions:

  a. P and Al are in the same period, but Al is to the left, so it has a larger radius.

  b. Cl- has gained an electron, making it larger than neutral Cl, but it is still in the same period as P and Al.

  c. S2- has gained two electrons, making it significantly larger than neutral S.

  d. Ga is in the same group as Al but is lower in the group, so it has a larger radius.

3. Based on these comparisons, Cl- has the smallest radius among the given options.

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Answer:

Soap

Explanation:

Answer:

54.(4)° C (the 4 in the parentheses means the 4 goes forever), 327.594°K

Explanation:

When you convert 130°F to °C, you will get 54.(4)°C, and the 4 in the parentheses goes forever, and 130°F to °K is 327.594°K, hope it helps!

Answer:

bile salts emulsify fats and break them down into smaller particles which gives the enzyme lipase a greater surface area to act on during digestion of fats.

Explanation:

Answer:

100 g of water dissolves 204 g of sugar. Therefore, 25 g of water would dissolve 204×25÷100 =51g of sugar at 20°C.

Explanation:

Answer: 408g of sugar

Explanation: the amount of water increased by 2

so, multiply: 204 times 2= 408

Answer:

Because matter cannot be destroyed or created, It can change form through physical, chemical changes but the matter never gets destroyed or created.

Explanation: