What is the slope of the line represented by the equation y= 4/5x-3

Minimum Increment operations to make Array unique

The UNIQUE function will return an array, which will spill if it's the final result of a formula. This means that Excel will dynamically create the appropriate sized array range when you press ENTER .

ArrayList is like an array behind the scenes as it’s backed by an array of type java.lang.Object in java.

Normally arrays are fixed in size which means the number of elements that can be added are fixed and cannot be increased once created. ArrayList can dynamically increase in size once the array that backs is full so, these way we won’t encounter runtime exceptions.

When we say list.get(0), it’s equivalent to array[0]. It can be said the ArrayList is a kind of more convenient way to use dynamic arrays.

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Answer: final answer is (x+1) (x+8)

We need two numbers that...

Add together to get 9

Multiply together to get 8

Try 1 and 8:

1+8 = 9

1*8 = 8

therefor the answer is  (x+1) (x+8)

Since the function, g(x), is obtained by vertically stretching f(x) = x2 + 1 by a scale factor of 3.The option that is the correct expression for g(x) is option C: g(x) = 3x² + 3

In the above case,  we shall multiply the base function by the scale factor when stretching a function vertically. As a result, we have g(x) = 3 f. (x). Don't forget to share 3 to each term in f. (x).

g(x) = 3(x² + 1)

=3x² + 3

As a result, the appropriate formulation for g(x) is 3x² + 3.

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See complete question below

The function, g(x), is obtained by vertically stretching f(x) = x2 + 1 by a scale factor of 3. Which of the following is the correct expression for g(x)?

 g(x) = 3x² + 1

g(x) = x² + 3

g(x) = 3x² + 3

g(x) = 3(x + 1)2

Answer:

answer is 75

Step-by-step explanation:

you need to add all of them then take away 12 then you get your answer.

Let be the subset of consisting of all vectors such that and determine if is a subspace of and check the correct answer(s) below. a. is a subpace because it has a zero element. Option (A)

Let \($S$\) be the subset of \($\mathbb{R}^3$\) consisting of all vectors such that \(x_1 + x_2 + x_3 = 0$.\) To determine if $S$ is a subspace of \($\mathbb{R}^3$\), we need to check the following three conditions:

\($S$\) contains the zero vector\(: $(0,0,0) \in S$ since $0+0+0=0$.\)

$S$ is closed under addition: if\($\mathbf{u}, \mathbf{v} \in S$,\)then \($(u_1+v_1)+(u_2+v_2)+(u_3+v_3) = (u_1+u_2+u_3) + (v_1+v_2+v_3) = 0+0 = 0$, so $\mathbf{u}+\mathbf{v} \in S$.\)

$S$ is closed under scalar multiplication: if\($\mathbf{u} \in S$ and $c$ is\) a scalar, then \(c\mathbf{u} = c(u_1,u_2,u_3) = (cu_1,cu_2,cu_3)$ and $(cu_1+cu_2+cu_3) = c(u_1+u_2+u_3) = c\cdot0 = 0$, so $c\mathbf{u} \in S$.\)

Since all three conditions are satisfied, we conclude that \($S$\) is a subspace of\($\mathbb{R}^3$.\)Therefore, the correct answer is (a) is a subspace because it has a zero element.

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The missing values of the given triangle DEF would be listed below as follows:

<D = 40°

<E = 90°

line EF = 50.6

To determine the missing part of the triangle, the Pythagorean formula should be used and it's giving below as follows:

C² = a²+b²

where;

c = 80

a = 62

b = EF = ?

That is;

80² = 62²+b²

b² = 80²-62²

= 6400-3844

= 2556

b = √2556

= 50.6

Since <E= 90°

<D = 180-90+50

= 180-140

= 40°

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By 2228 ways i can select the team to have more girls than boys

We have, total number of boys = 6, while the total number of girls = 8

Total size of team = 6

Condition given: In every case the total number of girls should be more than the total number of boys.

As for that we can choose the team like

(6G, 0B) + (5G, 1B) + (4G, 2B)

Making the combination as per above arrangements:

We will get it as:

=8C6*6C0+8C5*6C1+8C4*6C2

As we know,

The formula of combination is:

\($${ }_n C_r=\frac{n !}{r !(n-r) !}$$\)

\(${ }_n C_r=$\) number of combinations

n= total number of objects in the set

r= number of choosing objects from the set

So, applying the concept of combination in the above,

So, from above we can write it as:

8C6*6C0+8C5*6C1+8C4*6C2

=\([\frac{8!}{6! \times 2!}\times \frac{6!}{6!\times 0!}]+[\frac{8!}{5!\times 3!}\times \frac{6!}{5!\times 1}]+[\frac{8!}{4!\times 4!}\times \frac{6!}{2!\times 4!}]\\\\\)

\([\frac{8 \times7\times6! }{6!\times2} \times \frac{1}{1}]+[\frac{8\times7\times6\times5!}{5!} \times \frac{6\times5!}{5!}]+[\frac{8\times7\times6\times5\times4!}{4!\times24} \times \frac{6\times5\times4!}{4!\times2}]\)

[28*1]+[336*6]+[70*2]

=28+2016+140

=2228

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INFORMATION:

We have the next triangle

And we must select the answer that best describes XW segment

STEP BY STEP EXPLANATION:

We can see that XW segment divides the YZ side into two equal parts, which measure 15 units. And we can also see that the XW segment starts in one of the vertex of the triangles and goes to the opposite side.

Then, we can analyze the definition for the median of a triangle

Finally, if we compare, we can see that the definition of median describes the XW segment.

ANSWER:

B. Median.

Answer:

No it does not apply to this problem because the submarine starts at a depth of 100 feet below sea level.

The new diet was not effective, the researchers may need to continue searching for other solutions.

In the trial to determine whether a new diet reduces cholesterol, a group of twenty volunteers with high cholesterol were selected. The trial likely involved splitting the volunteers randomly into two groups - a treatment group and a control group.

The treatment group would be given the new diet to follow, while the control group would continue with their normal diet. The participants' cholesterol levels would be measured at the beginning of the trial, and then again at regular intervals throughout the trial to track any changes.

After the trial has ended, the researchers would analyze the results to see if there was a significant difference in cholesterol levels between the treatment and control groups. If the new diet was effective in reducing cholesterol, the researchers may recommend it as a potential treatment option for people with high cholesterol. However, if the new diet was not effective, the researchers may need to continue searching for other solutions.

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Answer:

85

Step-by-step explanation:

Angle Formed by Two Chords = 1/2 (sum of Intercepted Arcs)

< WSK = 1/2 ( 35+ 135)

           = 1/2 ( 170)

            =85

Answer:

a) 39 b) 17

Step-by-step explanation:

12x - 9

12(4) - 9

48 - 9

39

d/15 + 13

(60)/15 + 13

4 + 13

17

Answer:

A=39      B=17

Step-by-step explanation:

12 times 4= 48 then 48-9=39

a. N(0.52, 0.0275)

The probability is:

b. 0.1089
c. 0.8908

The sample proportion ˆp is defined as

ˆp=x/n, where x is the number of successes in the sample of size n.

The expected value of the sample proportion ˆp is E(ˆp) = p, and the variance is Var(ˆp) = p(1-p)/n.

In this case, p=0.52 and n=60

So, the distribution of the sample proportion is ˆp ~ N(0.52, 0.52(1-0.52)/60) = N(0.52, 0.0275).

Therefore, the distribution of ˆpp^ is N(0.52, 0.0275)

For the probability that the sample proportion is more than 0.55, we need to standardize the value of 0.55 using the mean and standard deviation from part (a).

z = (0.55 - 0.52)/√(0.0275)

z = 1.236

So, P(ˆp > 0.55) = P(z > 1.236) = 0.1089, using a standard normal distribution table.

Therefore, the probability that the sample proportion is more than 0.55 is 0.1089.

For the probability that the sample proportion is between 0.55 and 0.63, we need to standardize these values using the mean and standard deviation from part (a).

z₁ = (0.55 - 0.52)/√(0.0275) = 1.236

z₂ = (0.63 - 0.52)/√(0.0275) = 4.000

So, P(0.55 < ˆp < 0.63) = P(1.236 < z < 4.000)

= P(z < 4.000) - P(z < 1.236) = 0.9997 - 0.1089 = 0.8908. Therefore, the probability that the sample proportion is between 0.55 and 0.63 is 0.8908.

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Answer:

Chris = $25

Maria = $35

Justin = $75

Step-by-step explanation:

Chris's amount is x.

x + 3x + (x + 10) = 135

x = 25

Substitute 25 for x.

25 + 3(25) + (25 + 10) = 135

135 = 135

True

Answer:

Identify the terms and coefficients of each expression. 1. ... Frank buys p pounds of oranges for $2.29 per pound and the same number of pounds of apples for $1.69 per pound. ... .690 = total cost ... Write an expression to represent each situation. 9. Eliza earns $400 per week plus $15 for each new customer she signs up.

Step-by-step explanation:

A group of student organization who wants to study about voting preferences in its students during presidential election in 2012. So, they selected a sample of 120, is an example of stratified random sampling.

Stratified random sampling is a widely used statistical technique in which a population is divided into different subgroups, or strata, based on some shared characteristics. The purpose of stratification is to ensure that each stratum in the sample and to make inferences about specific population subgroups, that is they share (e.g., race, gender, educational attainment).

Therefore, the stratified random sample involves dividing the population into two or more strata (groups). These strata are expressed as H. A stratified random sampling because a random sample has been taken from each different strata (Freshmen through seniors).

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The correct value of \($t^*$\) to be used to create a 90% confidence interval for the true mean number of calls is 1.676

In this scenario, the director of a customer service center wants to estimate the mean number of customer calls the center handles each day. To create a 90% confidence interval for the true mean number of calls, the director needs to use a confidence interval formula that takes into account the sample size, sample mean, and the standard error of the mean.

The standard error of the mean, denoted as \($SE_{\bar{x}}$\), represents the standard deviation of the sampling distribution of the mean. It can be calculated using the formula:

\($SE_{\bar{x}} = \frac{s}{\sqrt{n}}$\)

where\($s$\) is the sample standard deviation and \($n$\) is the sample size.

The director can use the t-distribution to create the confidence interval, as the sample size is relatively small (less than 30). The formula for the 90% confidence interval is:

\($\bar{x} \pm t^* \frac{s}{\sqrt{n}}$\)

where\($\bar{x}$\) is the sample mean, \($s$\) is the sample standard deviation,\($n$\) is the sample size, and \($t^*$\) is the critical value from the t-distribution with (n-1) degrees of freedom and a 90% confidence level.

To determine the value of \($t^*$\), the director needs to consult a t-distribution table or use a statistical software. For a 90% confidence interval and 47 degrees of freedom (48 - 1), the value of \($t^*$\) is approximately 1.676.

Therefore, the correct value of \($t^*$\) to be used to create a 90% confidence interval for the true mean number of calls is 1.676. Using this value, the director can calculate the confidence interval by plugging in the sample mean, sample standard deviation, and sample size into the formula. This will give an estimate of the range of values where the true population mean lies with 90% confidence.

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Answer:

-1

Step-by-step explanation:

The Equivalent Units of Production for conversion costs is 16,750 units. The total material cost per unit is P0.94. The total manufacturing cost per unit is P2.59. The total cost for Started and Completed is P47,680. The total cost for Work in Process, Ending Inventory is P5,180.

21. The Equivalent Units of Production-Conversion Cost = 16,750 units.

22. The total material cost per unit = P0.94.

23. The total manufacturing cost per unit = P2.59.

24. The total cost for Started and Completed = P47,680.

25. The total cost for Work in Process, Ending Inventory = P5,180.

To calculate the required values, we'll use the FIFO method.

21. Equivalent Units of Production-Conversion Cost:

Equivalent Units of Production = Units completed + (Ending work in process inventory * Degree of completion)

Equivalent Units of Production = 17,500 + (2,000 * 3/4)

Equivalent Units of Production = 17,500 + 1,500

Equivalent Units of Production = 19,000 units

22. Total Material Cost per Unit:

Total Material Cost per Unit = Total material costs / Equivalent Units of Production

Total Material Cost per Unit = P16,500 / 17,500

Total Material Cost per Unit = P0.94

23. Total Manufacturing Cost per Unit:

Total Manufacturing Cost per Unit = (Total material costs + Conversion costs) / Equivalent Units of Production

Total Manufacturing Cost per Unit = (P16,500 + P23,945) / 17,500

Total Manufacturing Cost per Unit = P40,445 / 17,500

Total Manufacturing Cost per Unit = P2.59

24. Total Cost for Started and Completed:

Total Cost for Started and Completed = Units completed * Total Manufacturing Cost per Unit

Total Cost for Started and Completed = 17,500 * P2.59

Total Cost for Started and Completed = P45,325

25. Total Cost for Work in Process, Ending Inventory:

Total Cost for Work in Process, Ending Inventory = Ending work in process inventory * Total Manufacturing Cost per Unit

Total Cost for Work in Process, Ending Inventory = 2,000 * P2.59

Total Cost for Work in Process, Ending Inventory = P5,180

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The value of x+y in the equation \(2^{x}*3^{y}/2^{4}*3^{2} =6\)  using the law of indices is 8

An index, or power, is the small floating number that appears after a number or letter. Indices show how many times a number or letter has been multiplied by itself.

To determine the value of x+y in the equation below, we use the law of indices.

Equation:

We rearrange the equation,

Then we apply the law of indices

Comparing both sides of equation 1 below

Equating the base

And,

Therefore, x+y = 5+3 = 8

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Answer:

181 mi^2

Step-by-step explanation:

Dimensions of large rectangle, on the left, are 6 mi by 8 m; area is 48 m^2;

Dimensions of small rectangle, in the middle of the diagram, are 4 mi by 5 mi, or 20 mi^2; area is 20 mi^2.

Dimensions of circle:  r = 12 mi; area of quarter circle is (1/4)(3.14)(12 mi)^2, or 113 mi^2.

Total area is 113 mi^2 + 20 mi^2 + 48 mi^2, or 181 mi^2

Answer:

Step-by-step explanation:

So first off. lets take chunks of this shape. We have a 6x8 rectangle, a 4x5 rectangle, and a 1/4 circle with a radius of 12.

The area of a rectnagle is just length x width.

So lets plug in our values for our two ractnagles, and see what we get:

6*8

=

48

So our first rectangle has a area of 48

Next we have:

4*5

=

20

So our second rectangle has an area of 20.

Add these otgether you get 68.

Finally we have our 1/4 circle. To solve this, find the area of the full circle and divide by 4.

We already know the radius, which is 12, and the formula for area of a circle is:

a=πr^2

Plug in 12:

a=π12^2

=

a=π144

dividing by four for the 1/4circle:

a=π36

So this means your answer is either:

68 +36π

Or:

181.097(solving pi*36)

Either of these work, if the problem allows pi, then use the first one, If not, use the bottom one.

Hope this helps!

To find the intersection point between the curve y = tan(x) and the line y = 7x, we can use Newton's method. Newton's method is an iterative numerical method used to approximate the root of a function.

We need to find the x-value where the curves intersect, so we can set up the equation tan(x) - 7x = 0. We want to find a solution between x = 0 and some unknown value denoted as X.

Using Newton's method, we start with an initial guess x_0 for the solution and iterate using the formula:

x_(n+1) = x_n - f(x_n) / f'(x_n),

where f(x) = tan(x) - 7x and f'(x) is the derivative of f(x).

We continue this iteration until we reach a desired level of accuracy or convergence. The resulting value of x will be the approximate intersection point between the two curves.

Please note that without specific values or range for X or an initial guess x_0, it is not possible to provide a specific numerical answer. However, you can apply Newton's method using an initial guess and the given function to find the approximate intersection point.

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Answer:

D is not a function because it has 2 dots that makes a line (2 dots are lined up) and B is intersecting

Solution

1.

2.

3.

Answer: 4

Step-by-step explanation:

2+2=4

Answer:

2 + 2 = 4

Step-by-step explanation:

If u just started to learn how to sum, you can use sticks

II + II = IIII

(a) A bipartite graph G can be constructed where one set of vertices represents the elements of X and the other set represents the subsets of X. The problem of finding a transversal of X is equivalent to the problem of finding a matching in G.

(b) A transversal of X can be found by analyzing the constructed bipartite graph G and identifying a matching, or it can be shown that no transversal exists.

(a) To create a bipartite graph G, we consider one set of vertices to represent the elements of X (A, B, C, D, E, F, G), and another set of vertices to represent the subsets of X (A, B, C, D, E, F, G). Each vertex in the element set is connected to the vertices in the subset set if the element belongs to that subset. For example, vertex A is connected to vertices A, C, and D, as A is present in subsets A, C, and D.

(b) In order to find a transversal of X, we need to find a matching in the bipartite graph G. A matching in a bipartite graph is a set of edges where no two edges share a common vertex. By identifying such a matching in G, we can determine a transversal of X.

To find a matching, we can employ various algorithms like the Hopcroft-Karp algorithm or the Ford-Fulkerson algorithm. These algorithms will traverse the bipartite graph and identify a set of edges that form a matching.

If it is not possible to find a matching, it indicates that no transversal exists for X. This means that there is no subset in X that contains exactly one element from each of the other subsets. In such cases, we can conclude that X does not have a transversal.

In summary, by constructing a bipartite graph G and finding a matching in it, we can solve the problem of finding a transversal of X. If a matching exists, it represents a transversal, while the absence of a matching indicates the absence of a transversal.

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The series Σ √n / (n^(n+1)) and Σ (-1)^n / (n^2) both converge.

For the series Σ √n / (n^(n+1)), we will compare it with a known convergent series.

a) Consider the series Σ 1 / (n^(3/2)). Since n > 1, we can write √n > 1. Therefore, √n / (n^(n+1)) > 1 / (n^(n+1)).

b) Now, compare Σ √n / (n^(n+1)) with Σ 1 / (n^(n+1)) using the Comparison Test.

The series Σ 1 / (n^(n+1)) is a p-series with p = n+1 > 1. Thus, Σ 1 / (n^(n+1)) converges.

c) As Σ √n / (n^(n+1)) > Σ 1 / (n^(n+1)) and Σ 1 / (n^(n+1)) converges, can conclude that Σ √n / (n^(n+1)) also converges.

For the series Σ (-1)^n / (n^2), we will compare it with a known convergent series.

a) Consider the series Σ 1 / (n^2). As |(-1)^n / (n^2)| = 1 / (n^2), have |(-1)^n / (n^2)| ≤ 1 / (n^2).

b) Now, compare Σ (-1)^n / (n^2) with Σ 1 / (n^2) using the Comparison Test.

The series Σ 1 / (n^2) is a p-series with p = 2 > 1. Therefore, Σ 1 / (n^2) converges.

c) Since |(-1)^n / (n^2)| ≤ 1 / (n^2) and Σ 1 / (n^2) converges, we can conclude that Σ (-1)^n / (n^2) also converges.

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(a) The sample size is n = 38, which satisfies the restriction n ≥ 30. (b) μ = 1/0.05 = 20. (c)  σ = 1/0.05 = 20.

(a.) To apply the Central Limit Theorem (CLT) to the population represented by the given exponential distribution graph (X  E(0.05)), we need to consider the following restriction: n ≥ 30.

Since the CLT states that for any population distribution, as the sample size increases, the distribution of the sample means approaches a normal distribution, the requirement of n ≥ 30 ensures that the sample size is sufficiently large for the CLT to hold. This allows us to approximate the sampling distribution of the sample means to be approximately normal, regardless of the underlying population distribution.

In the given problem, the sample size is n = 38, which satisfies the restriction n ≥ 30. Therefore, we can apply the Central Limit Theorem to this population.

(b.) The population mean (μ) for the exponential distribution with decay parameter M = 0.05 can be calculated using the formula μ = 1/M. In this case, μ = 1/0.05 = 20.

(c.) The population standard deviation (σ) for an exponential distribution with decay parameter M can be calculated using the formula σ = 1/M. In this case, σ = 1/0.05 = 20.

Therefore, for the given sampling  exponential distribution with M = 0.05:

The population mean (μ) is 20.

The population standard deviation (σ) is 20.

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