What is the solution to the equation
\( \sqrt{2x - 4} equals6\)
​

Answer: 99%

Step-by-step explanation:

Answer:

A and C

Step-by-step explanation:

Nadine and Trevor both conducted an experiment but Nadine conducted with four possible outcomes and Trevor doubled the trials, therefore, Trevor will have more experimental outcomes than Nadine because he doubled the trials. Moreover, Trevor's experimental probability is more likely closer to theoretical probability than Nadine's, therefore option 'A' and 'C' are correct.

Answer:  

Trevor has more experimental outcomes than Nadine.  

Trevor’s experimental probability is more likely closer to the theoretical probability than Nadine’s.

Step-by-step explanation:

Answer:

$2.10

Step-by-step explanation:

change the rate of sales tax to a decimal by dividing by 100, so 3%=.03

multiply the price by .03

Answer:

2.10

Step-by-step explanation:

You do 3% of 70 which equals 2.10

Answer: 8 times as long

Step-by-step explanation:

Answer:

I believe it is approx. 8 times longer.

Step-by-step explanation:

2^10 = 1024

2^7 = 128

1024 / 128 = 8

i hope this is right and helps :)

The equation of the known line is

y = 3/4x

The slope intercept equation of a line is expressed as

y = mx + c

where

m represents slope

c respresents y intercept

By comparing with the given equation, slope, m = 3/4

If two lines are parallel, it means thta they have the same slope. Therefore, the slope of the para;llel line is 3/4

Given that the line parallel to this line passes through (3, 3), we would determine the y intercept, c of this line by substituting x = 3, y = 3 and m = 3/4 into the slope intercept equation. it becomes

3 = 3 * 3/4 + c

3 = 9/4 + c

c = 3 - 9/4 = - 3/4

Therefore, the equation of the line is

y = 3x/4 - 3/4

The rate of change in the profit for the five months earned by the given small business is $2750.

The rate of change explains the relationship between two quantities.

Consider two quantities such profit and time in a small business.

Then, the rate of change in the profit is calculated by the ratio of change in the profit for the particular period to the time. I.e.,

rate of change in the profit = (change in the profit)/time

or

r = (p2 - p1)/(t2 - t1)

Where p1 is the profit gained at time t1 and p2 is the profit gained at time t2.

Given that, a small business earns a profit of $6500 in January (the first month of the year) and $17,500 in May (the fifth month of the year).

So, here p1 = $6500; p2 = $17,500; t1 = 1; and t2 = 5

Then, the rate of change in the profit for this period is

r = (17,500 - 6500)/(5 - 1)

 = 11000/4

 = 2750

Therefore, the rate of change in the profit for the five months is $2750.

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a) x + (1/4)t^4 + C = (1/3)t^3 + D, where C and D are integration constants.

b) arctan(x(1+t)) = t + C, where C is an integration constant.

To show that the given differential equations are separable, we rewrite them in the form N(y) dy/dx = -M(x). The general solutions are obtained by integrating both sides.

(a) For the equation x' = t^2 / (x(1+t^3)), we rearrange it as x(1+t^3) dx = t^2 dt. Separating variables, we get (1+t^3) dx/x = t^2 dt. Integrating both sides gives the general solution as ∫ (1+t^3) dx = ∫ t^2 dt. Evaluating the integrals, we have x + (1/4)t^4 + C = (1/3)t^3 + D, where C and D are integration constants.

(b) The equation x' = 1 + t + x^2 + tx^2 is rewritten as dx/(1 + x^2 + tx^2) = dt. We can separate variables by writing it as dx/(1 + x^2(1 + t)) = dt. Integrating both sides yields the general solution as arctan(x(1+t)) = t + C, where C is an integration constant.

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Answer:

to the power of 80 is 8.944 ÷5 is 1.788

Answer:

maximum- median

80-50=30

Answer:

452km

Step-by-step explanation:

The balance when the account went into overdraft was -48.61

An overdraft occurs when something is withdrawn in excess of what is in a current account. For financial systems, this can be funds in a bank account.

Let x be the balance when the account went into overdraft

To get back to a positive balance he deposited money at a steady rate of $31.97 per week.

Amount deposited per week = $31.97

Amount deposited 3 weeks = $95.91

Now amount in account after 3 weeks =x+95.91

We are given that After 3 weeks, he had $95.91 in the account.

So, x+95.91=47.3

x= 47.3-95.91

x= -48.61

Hence The balance when the account went into overdraft was -48.61

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The y-intercept of the given equation is (B) -2.

So, the y-intercept will be:

Plot the equation on the graph as follows:

Therefore, the y-intercept of the given equation is (B) -2.

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The critical value of F for a .05 significance level, with within-groups degrees of freedom of 15 and between-groups degrees of freedom of 5, is approximately 2.901.

To find the critical value of F, you need to consult an F-distribution table, which you can find in a statistics textbook or online. Using the table, locate the row corresponding to the between-groups degrees of freedom (5) and the column corresponding to the within-groups degrees of freedom (15). The intersection of this row and column will give you the critical value of F for a .05 significance level.

Remember that the critical value of F is used to determine whether there is a significant difference between group means in an analysis of variance (ANOVA) test. If your calculated F-value is greater than the critical value, you would reject the null hypothesis and conclude that there is a significant difference between the group means.

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Answer:

No it is not a solution

Step-by-step explanation:

Key skills needed - One variable equations

1) We look at the equation, y = 4x+ 1, and see the scholar's work.

2) The scholar did everything correctly, and at the end got 9 = 13.

3) This statement is FALSE, so it would be the 2nd option (No it is not a solution)

Hope this helps and have a nice day!! :D

Answer:

1.875kg

Step-by-step explanation:

48 - 1000g

90 - x

48x = 90000

x = 90000/48

  = 1875g = 1.875kg

Feel free to mark as brainliest :D

Answer:

Slope: −2-2

y-intercept: (0,4)

The scale Denise used is as follows:

3 centimetres: 2 metres

Denise measured a community college and made a scale drawing. In real life, at the college is 122 meters long. it is 183 centimetres long in the drawing.

The scale of Denise use can be calculated as follows:

Using the proportional relationship,

3 / x = 183 / 122

cross multiply

122(3) = 183x

366 = 183x

divide both sides by 183

x = 366 / 183

x  = 2 metres.

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Answer:

15.5kg  and   13.25kg

Step-by-step explanation:

8x+4y=177

3x+2y=73 (changes to -----> 6x+4y=146)

subtract

2x=31

x=15.5 (large)

plug back in

3(15.5)+2y=73

46.5+2y=73

26.5=2y

13.25=y

In a bigram model, the probability of a word is computed as the product of the probability of the previous word and the probability of the current word given the previous word. This is also known as a multinomial model.

A bigram model computes the probability of a pair of consecutive words in a document, represented as P(w2|w1), where w1 is the first word and (w1, w2) is the pair of consecutive words. This model is a multinomial model, which means the probability distribution is over multiple outcomes. Given a vocabulary size of V, the number of parameters in a bigram model would be V^2, as each word can be paired with any other word in the vocabulary.

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Answer:

17.2 feet

Step-by-step explanation:

The length of the ladder is 20.4 feet.

Heights and Distances is a study about the applications of Trigonometry. It has many real-life applications, such as measuring the object’s height, depth of the object, the distance between two celestial objects etc. The formulas and the ratios of trigonometry are helpful in the study of heights and distances.

Given that, the angle of elevation of the ladder is 73° when the bottom of the ladder is 15 feet from the side of the house.

Let the height of side of a house be x.

Now, tan73°=x/15

x/15=0.9192

x=0.9192×15

x=13.8 feet

Let the length of the ladder be y.

y²=15²+13.8²

y²=415.44

y=√415.44

y=20.4 feet

Therefore, the length of the ladder is 20.4 feet.

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The probability of selecting at least 2 corporations earned profits is 2/3.

A subfield of statistics known as probability studies random events and their likelihood of happening.

Using combination formula:

¹⁰C₂ =  \(\frac{10!}{(2! * (10-2)!)}\)  =  45

This tells us that there are 45 possible ways to select two corporations from the list of 10.

To determine the number of ways that two corporations that both earned profits can be selected,

⁶C₂ =  \(\frac{6!}{(2! * (6-2)!)}\)   = 15

So there are 15 ways to select two corporations that both earned profits.

Therefore, the probability of selecting two corporations that both earned profits is:

P(both earned profits) = 15/45 = 1/3

To find the probability of selecting one corporation that incurred a loss,

⁴C₁ × ⁶C₁ =  4 × 6 = 24

So there are 24 ways to select one corporation that incurred a loss and one corporation that earned a profit.

Therefore, the probability of selecting one corporation that incurred a loss is:

P(one incurred loss) = 24/45 = 8/15

If the IRS inspector selects 3 corporations from the list, we can use the complement rule to find the probability that at least 2 of them earned profits,

P(at least 2 earned profits) = 1 - P(none earned profits) - P(only 1 earned profit)

To find the probability that none of the three selected corporations earned profits,

⁴C₃ ÷ ¹⁰C₃ = 4/120 = 1/30

To find the probability that only one of the three selected corporations earned profits,

{ ⁶C₁ × ⁴C₂ } ÷ ¹⁰C₃   = 36/120 = 3/10

Therefore, the probability of selecting at least 2 corporations that earned profits is:

P(at least 2 earned profits) = 1 - 1/30 - 3/10 = 2/3

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There is one specific type of transformation that can cause a change in the period of a tangent or cotangent function, and that is a dilation.

A dilation is a transformation that stretches or compresses a function horizontally or vertically. When a tangent or cotangent function is dilated horizontally, the period of the function changes. The period of a tangent function is π, while the period of a cotangent function is also π.

If the function is dilated by a factor of k, then the new period will be π/k. This means that the function will oscillate faster if it is compressed horizontally (k > 1) and slower if it is stretched horizontally (k < 1). Therefore, it is important to consider the effects of dilations when analyzing the period of a tangent or cotangent function.

The type of transformation that could cause a change in the period of a tangent or cotangent function is called a "horizontal stretch" or "horizontal compression." These transformations affect the frequency of the function by scaling it horizontally, which in turn alters the period of the tangent or cotangent function.

In mathematical terms, the general form of a tangent function is y = A * tan(B(x - C)) + D, and for a cotangent function, it's y = A * cot(B(x - C)) + D. In these expressions, A represents the amplitude, B determines the horizontal stretch or compression, C is the phase shift, and D is the vertical shift.

The factor B directly affects the period of the function. For a tangent or cotangent function, the standard period is π. To find the new period after a horizontal transformation, you can use the formula: new period = (standard period) / |B|. Thus, by changing the value of B, the period of the tangent or cotangent function will be affected accordingly.

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The largest possible error in the area of the circle is of 44%.

The area of a circle of radius r is given by:

\(A = \pi r^2\)

With a diameter of 20 cm = radius of 10 cm, the area in cm² is given by:

\(A = \pi \times 10^2 = 100\pi\)

With the error, with a diameter of 20 x 1.2 = 24 cm = radius of 12 cm, the area in cm² is given by:

\(A = \pi \times 12^2 = 144\pi\)

The error is given by:

\(E = 144\pi - 100\pi = 44\pi\)

The percent error is the error divided by the initial amount, multiplied by 100%, hence:

\(P = \frac{44\pi}{100\pi} \times 100\% = 44\%\)

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Answer:

a) 15

b) 270

Step-by-step explanation:

a)

(√5)² = 5

(√3)² = 3

This is due to the square root and to the power of 2 cancelling each other out if that makes sense. It's the same with (√3)²

So all you're actually doing is 5 × 3 which is 15

b)

It's basically the same except (³√9)³ is cube(d) root and to the power of 3

(³√9)³ = 9

(√30)² = 30

So you do 9 × 30 = 270

:)

Answer:

incenter is angle bisectors

altitude orthocenter

centroid perpendicular bisector

circumcenter medians

Answer:

me me me omg

Step-by-step explanation:

The variance for the sample is not valid. The variance is -352.98 and the standard deviation is 18.77 for sample (b), while for sample (c), the variance is -10.263 and the standard deviation is 3.20.

To calculate the variance and standard deviation, we need to use the formulas involving the sum of squares (SS) and the sample size (n).

(a) We have: n = 11, Σx = 88, Σx² = 22

The variance (σ²) is calculated as:

σ² = (Σx² - (Σx)²/n) / (n - 1)

Substituting the values into the formula:

σ² = (22 - (88)²/11) / (11 - 1)

   = (22 - 7744/11) / 10

   = (-7700/11) / 10

   = -700/11

   = -63.636

Since variance cannot be negative, the variance for this sample is not valid.

The standard deviation (σ) is the square root of the variance:

σ = √(-700/11)

  = √(-63.636)

  = √(63.636)i

  = 7.982i

(b) We have: n = 42, Σx = 385, Σx² = 90

Using the same formulas:

σ² = (Σx² - (Σx)²/n) / (n - 1)

   = (90 - (385)²/42) / (42 - 1)

   = (90 - 14822/42) / 41

   = (-14552/42) / 41

   = -352.98

The variance is -352.98.

σ = √(-352.98)

  = √(352.98)i

  = 18.77i

(c) We have: n = 20, Σx = 15, Σx² = 14

Using the same formulas:

σ² = (Σx² - (Σx)²/n) / (n - 1)

   = (14 - (15)²/20) / (20 - 1)

   = (14 - 225/20) / 19

   = (-195/20) / 19

   = -10.263

The variance is -10.263.

σ = √(-10.263)

  = √(10.263)i

  = 3.20i

In summary:

(a) The variance is not valid as it is negative.

(b) The variance is -352.98 and the standard deviation is 18.77.

(c) The variance is -10.263 and the standard deviation is 3.20.

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For a normal distribution of property crime rates (per 100,000 residents) for the 50 states, percentage of the states had property crime rates between 3362 and 4055 is equals to the 44.1%.

In 2005, We have property crime rates for the 50 states and the District of Columbia. The rate is per 100,000 residents. Mean = 3477

Standard deviations = 747

Consider the distribution of property crime rates is normal distribution. We have to determine the percentage of the states had property crime rates between 3362 and 4055, P( 3362 < X < 4055).

Using the Z-Score formula for normal distribution, \(z = \frac{X- \mu}{\sigma} \)

where X --> observed value

mu --> mean

sigma --> standard deviations

For observed value, X = 3362

\(z = \frac{ 3362 - 3477}{747}\)

= −0.154

For observed value, X = 4055

\(z = \frac{ 4055 - 3477}{747}\)

= 0.774

Now, the required probability, P( 3362 < X < 4055) can be written as

\(= P( \frac{ 3362 - 3477}{747} < \frac{ X - \mu}{\sigma} <\frac{4055 - 3477}{747} )\)

= P( -0.15 < z <0.77 )

= P(z< 0.77) - P( z < - 0.15)

Using the normal distribution table,

= 0.441 - 0.881

= P( 3362 < X < 4055) = 0.441

Hence required percentage value is equals to 44.1%.

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acute angle and the answer looks like it would be 57.5 because acute is below 60 the other angles have a fractional portion on the angles corner so A

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a. The equator has the smallest circumference of all the circles of latitude or longitude.

The equator is an imaginary circle that is located at 0 degrees latitude and circles the Earth's surface at its widest point. Since the Earth is roughly spherical in shape, the equator represents the largest circle of latitude. However, it has the smallest circumference of all the circles of latitude or longitude because it is located at the widest point of the Earth, and its radius is equal to the Earth's radius.

In contrast, the circles of latitude and longitude located at higher latitudes have smaller radii and therefore larger circumferences than the equator. Similarly, circles of latitude and longitude located at lower latitudes have larger radii and smaller circumferences than the equator. Therefore, the equator has the smallest circumference of all the circles of latitude or longitude on the Earth's surface.

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