What is the square root of 108what is the square root of 144

The commutative property of the addition is:

Where a and b are any numbers.

Therefore, in case of our problem

Then, the solution is

The solution is the first option

Answer: 314 mm

Step-by-step explanation:

Area of a circle is π*r^2

r is radius and π is 3.14

here the radius is 10

3.14 * 10^2 = 3.14 * 100 = 314

Answer:

honestly, i think it would be d

Step-by-step explanation:

i could be wrong, but i hope this helps :)

SOLUTION

The diagram below would be very helpful in answering the question

(a) to find f'(-2), we find the slope m of the line that I have made in red.

We use the points (-1, 0) and (-3, 1) we have

Hence the answer is

(c) We should determine x, where f'(x) = 0

Now f'(x) = 0 at a where we call the maximum point. That is the highest point of the graph curved as "n" From the figure above we can see that at this point, y is 3, also tracing down to the x-axis plane, can see that x = 3

Hence the answer is x = 3

Answer:

Step-by-step explanation:

B

Answer:

d 11x + 24

Step-by-step explanation:

Perimeter = 5x + 3 + 2x + 6 + 4x + 15

                 = (5x + 2x + 4x) + (3 + 6 + 15)

                 = 11x + 24

The reliability of the given system is 0.4033.

To calculate the reliability of a system, we need to multiply the reliability values of all the components in the system. In this case, we have a system composed of three components with the following reliability values:

Component 1: 0.90

Component 2: 0.90 0.90 0.85

Component 3: 0.85 0.85 0.92

To find the overall system reliability, we multiply these values together:

System reliability = Component 1 reliability x Component 2 reliability x Component 3 reliability

System reliability = 0.90 x (0.90 x 0.90 x 0.85) x (0.85 x 0.85 *x 0.92)

System reliability ≈ 0.90 x 0.6831 x 0.6528 ≈ 0.4033

Therefore, the reliability of the given system is 0.4033.

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Caitlyn used 4 43-cent stamps and 8 6-cent stamps

The given parameters are:

Amount paid = $2.20

Stamp used: 43-cent stamps and 6-cent stamps

Represent the amount of stamps in dollars

$0.43 and $0.06

Let the count of these stamps be x and y

So, we have:

0.43x + 0.06y = 2.20

Multiply through by 100

43x + 6y = 220

Let x = 4.

So, we have:

43* 4 + 6y = 220

This gives

6y = 48

Divide by 6

y = 8

Hence, Caitlyn used 4 43-cent stamps and 8 6-cent stamps

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Answer: i agree with the other guy ↑

Therefore, the number of ways a student can work 7 out of 10 questions on the exam is 120, which corresponds to option (D).

The number of ways a student can work 7 out of 10 questions on an exam can be calculated using the concept of combinations.

The formula for combinations is given by:

C(n, k) = n! / (k!(n - k)!)

Where n is the total number of items and k is the number of items chosen.

In this case, the student is choosing 7 questions out of a total of 10, so we have:

C(10, 7) = 10! / (7!(10 - 7)!) = 10! / (7!3!)

Simplifying:

10! = 10 * 9 * 8 * 7!

3! = 3 * 2 * 1

C(10, 7) = (10 * 9 * 8 * 7!) / (7! * 3 * 2 * 1)

The 7! terms cancel out:

C(10, 7) = (10 * 9 * 8) / (3 * 2 * 1)

C(10, 7) = 120

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The triangular prism has a surface area of 1340 square meters. The answer is 1340 m².

To calculate the surface area of a triangular prism, find the area of all its faces and add them together.

The triangular base has a base of 10 m and a height of 14 m, so its area is:

(1/2) × base × height = (1/2) × 10 m × 14 m = 70 m²

There are two identical triangular faces, so the total area of both is:

2 × 70 m² = 140 m²

The rectangular faces have dimensions of 10 m by 25 m and 14 m by 25 m, so their areas are:

10 m × 25 m = 250 m²

14 m × 25 m = 350 m²

Again, there are two rectangular faces, so the total area of both is:

2 × (250 m² + 350 m²) = 1200 m²

Finally, add the areas of all the faces:

140 m² + 1200 m² = 1340 m²

Therefore, the surface area of the triangular prism is 1340 square meters.

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~Stay Safe, I Guess ^-^

Step-by-step explanation:

tttttttttttttttttttttttttttt

we need to multiply this number by 100 to get the  as a percentage:

0.1806 * 100 = 18.06%

The probability of choosing a senior can be calculated using the formula:

P(senior) = (102/562) * 100

P(senior) = 18.06%

This means that there is an 18.06% chance of choosing a senior if a student is randomly selected from the school.

First, we need to calculate the total number of students in the school by adding together the number of students in each class:

Total = 165 + 145 + 114 + 102 = 562

Next, we need to calculate the probability of choosing a senior by taking the number of seniors enrolled in the school (102) and dividing it by the total number of students in the school (562).

102/562 = 0.1806

Finally, we need to multiply this number by 100 to get the probability as a percentage:

0.1806 * 100 = 18.06%

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Answer:

5x + 9y -4

Step-by-step explanation:

Answer:

1. ひよこ     は     ちいさい     。

2. おおかみ     は     どうくつ     に     すんでいます     。

3. せんせい     は     どうぶつたち     を     みます     。

(a) The mean of Z in case (a) is -60 and the variance is 400.

(b) The mean of Z in case (b) is 280 and the variance is 3600.

(c) The mean of Z in case (c) is 60 and the variance is 65.

(d) The mean of Z in case (d) is -20 and the variance is 65.

(e) The mean of Z in case (e) is 80 and the variance is 505.

To find the mean and variance of the random variable Z for each case, we can use the properties of means and variances.

(a) Z = 40 - 5X

Mean of Z:

E(Z) = E(40 - 5X) = 40 - 5E(X) = 40 - 5 * 20 = 40 - 100 = -60

Variance of Z:

Var(Z) = Var(40 - 5X) = Var(-5X) = (-5)² * Var(X) = 25 * Var(X) = 25 * (4)² = 25 * 16 = 400

Therefore, the mean of Z in case (a) is -60 and the variance is 400.

(b) Z = 15X - 20

Mean of Z:

E(Z) = E(15X - 20) = 15E(X) - 20 = 15 * 20 - 20 = 300 - 20 = 280

Variance of Z:

Var(Z) = Var(15X - 20) = Var(15X) = (15)² * Var(X) = 225 * Var(X) = 225 * (4)² = 225 * 16 = 3600

Therefore, the mean of Z in case (b) is 280 and the variance is 3600.

(c) Z = X + Y

Mean of Z:

E(Z) = E(X + Y) = E(X) + E(Y) = 20 + 40 = 60

Variance of Z:

Var(Z) = Var(X + Y) = Var(X) + Var(Y) = (4)² + (7)² = 16 + 49 = 65

Therefore, the mean of Z in case (c) is 60 and the variance is 65.

(d) Z = X - Y

Mean of Z:

E(Z) = E(X - Y) = E(X) - E(Y) = 20 - 40 = -20

Variance of Z:

Var(Z) = Var(X - Y) = Var(X) + Var(Y) = (4)² + (7)² = 16 + 49 = 65

Therefore, the mean of Z in case (d) is -20 and the variance is 65.

(e) Z = -2X + 3Y

Mean of Z:

E(Z) = E(-2X + 3Y) = -2E(X) + 3E(Y) = -2 * 20 + 3 * 40 = -40 + 120 = 80

Variance of Z:

Var(Z) = Var(-2X + 3Y) = (-2)² * Var(X) + (3)² * Var(Y) = 4 * 16 + 9 * 49 = 64 + 441 = 505

Therefore, the mean of Z in case (e) is 80 and the variance is 505.

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Answer:

Step-by-step explanation:

into decimal form:

\(2.4\)

\(240\%\)

Hint:

(a) The distance between the points (2, -4) and (6, 4) is 4√5.

To find the distance between the points (2, -4) and (6, 4), we can use the distance formula:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates:

Distance = √((6 - 2)^2 + (4 - (-4))^2)

        = √((4)^2 + (8)^2)

        = √(16 + 64)

        = √80

        = 4√5

Therefore, the distance between the points (2, -4) and (6, 4) is 4√5.

(b) The distance between the points (5, 4) and (-1, 14) is 2√34.

To find the distance between the points (5, 4) and (-1, 14), we use the distance formula:

Distance = √((x2 - x1)^2 + (y2 - y1)^2)

Plugging in the coordinates:

Distance = √((-1 - 5)^2 + (14 - 4)^2)

        = √((-6)^2 + (10)^2)

        = √(36 + 100)

        = √136

        = 2√34

Therefore, the distance between the points (5, 4) and (-1, 14) is 2√34.

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Answer:

Conservative. Replication produces one helix made entirely of old DNA and one helix made entirely of new DNA.

Semi-conservative. Replication produces two helices that contain one old and one new DNA strand.

Dispersive.

Step-by-step explanation:

Replication is the process by which a double-stranded DNA molecule is copied to produce two identical DNA molecules. DNA replication is one of the most basic processes that occurs within a cell.

Answer:

Note: A percentage is always a number over 100.      (34% = \(\frac{34}{100}\))

Cost of meal = 100%

Cost of tip = 34%

Total = 134%

134% = \(\frac{134}{100}\)

To find the total and the tip, you must multiply it by \(\frac{134}{100}\)

Answer:

Bill times the 0.34 percent equals the price of the tip. After you find what the tip is, you add the base price (the bill price) to the tip and you get the total number paid. However, another way you can solve (in one step) this is by adding 1.00 to the percent you are multiplying by which in this case we add 0.34 by 1.00 and this gives us 1.34. Suppose we set the bill to 4 dollars and use the normal way (2-step equation) by doing 3(0.34) which is 1.02 and 1.02 + 3 = 4.02 as our final answer / final bill. However, when we do our one-step equation, we can write this as 3x(1.34) and this is equal to 4.02.

1st Step

Bill(0.34) = tip

tip + bill = total

2nd Step (one-step equation)

Note: we are going to set the bill in this equation as $4

4(1.34) = total; Total = 4.02 ← We added 1.00 to the tip percentage in decimal form.

The required arc length of sector VW is 8\(\pi\).

Given that, in a circle U, radius  UV = 9 and  central angle of sector m∠VUW = 160°.

To find the arc length of sector VW, we can use the formula:

Arc length = (central angle / 360) x circumference of the circle.

First,  find the circumference of the circle by the  formula for the circumference of a circle is given by:

Circumference = 2 x \(\pi\) x radius.

Circumference = 2 x \(\pi\) x 9 = 18π.

Now, let's find the arc length of sector VW using the central angle of 160 degrees:

Arc length = (160/360) x 18π

Arc length = (4/9) * 18\(\pi\) = 8\(\pi\).

Therefore, the arc length of sector VW is 8\(\pi\).

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Answer:

\(f(x)=x^3+x^2-8x-8\)

Step-by-step explanation:

The answer to this question is less coping strategies.

What are coping strategies?

Coping strategies are ways through which an individual gains some control over their emotions

Yes research has proved that the   Younger adults use more coping strategies than Older adults because now a days so methods for coping strategies like Cigerrate, alcohol, drugs etc things are easily being available to them and they use that to overcome their emotions

where as older adults have already seen most of their life so they are less likely to use these things to overcome their emotions

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Polynomials are algebraic expressions consisting of terms that include real numbers, variables, and positive integer exponents. Each term in a polynomial has a variable raised to a non-negative integer power, and the coefficient of each term is a real number. Polynomials are classified by the degree of their highest power. If two or more terms in a polynomial have the same variable raised to the same power, they can be combined into a single term.

1. -x² + x - x² + 1

Combine like terms: -x² + x - x² + 1 = -2x² + x + 1

This polynomial has degree 2 because the highest power of the variable is 2.

2. x² + x + 2x³ - x

Rearrange terms: 2x³ + x² + x - x = 2x³ + x²

This polynomial has degree 3 because the highest power of the variable is 3.

3. 4x + x + x - 2

Combine like terms: 4x + x + x - 2 = 6x - 2

This polynomial has degree 1 because the highest power of the variable is 1.

4. 3x² + 4 - 3x² - 1

Combine like terms: 3x² - 3x² + 4 - 1 = 3

This polynomial has degree 0 because there is no variable term.

Therefore, the four given polynomials have degrees 2, 3, 1, and 0, respectively.

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The value of the sample statistic is used to estimate the value of the population parameter.

The sample statistic is the value that is calculated from the sample data, which is used to make inferences about the population parameter. Sample statistics are used to estimate population parameters. A sample statistic is an estimate of a population parameter that is obtained from a sample, whereas a population statistic is a value that is computed from a population.

Therefore, the correct answer is a. sample statistic.

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Answer:

The nearest tenths of 448,655.75, 4,478 and 27,591.769064 is 7

Solution. To graph f, we graph the equation y=f(x).

To this end, we use the techniques outlined in Section 1.2.1. Specifically, we check for intercepts, test for symmetry, and plot additional points as needed. To find the x -intercepts, we set y=0. Since y=f(x), this means f(x)=0.

\($$\begin{aligned}f(x) & =x^2-x-6 \\0 & =x^2-x-6 \\0 & =(x-3)(x+2) \quad \text { factor } \\x-3=0 & \text { or } x+2=0 \\x & =-2,3\end{aligned}$$\)

So we get (-2,0) and (3,0) as x-intercepts. To find the y-intercept, we set x=0. Using function notation, this is the same as finding f(0) and f(0)=0^2-0-6=-6. Thus the y-intercept is (0,-6). As far as symmetry is concerned, we can tell from the intercepts that the graph possesses none of the three symmetries discussed thus far. (You should verify this.) We can make a table analogous to the ones we made in Section 1.2.1, plot the points and connect the dots in a somewhat pleasing fashion to get the graph below on the right.

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The interquartile range of the number of jumps of the 10 students during the competition is 38.

The interquartile range is the difference between the third quartile and the first quartile. The interquartile range is used to determine the variation of a data set.

Th first step is to determine the median of the first half of the dataset. The median of the first half is the first quartile.

First half of the data set: 30, 36, 38, 45, 57

Median = first quartile =  38

The next step is to determine the median of the second half of the dataset. The median of the second half is the third quartile.

Second half of the data set: 60, 77, 86, 88, 88

Median : third quartile =  86

Interquartile range = third quartile - first quartile

86 - 38 = 48

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There are 64 ways to choose a single class representative.

To find the total number of ways to choose a single class representative, we add the number of students in each college: 18 students from the College of Liberal Arts and Social Sciences, 19 students from the College of Education, and 27 students from the College of Science and Health.

This gives us a total of 18 + 19 + 27 = 64 students. To choose a single class representative, we can choose any one of these 64 students, so there are 64 ways to choose a single class representative.

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The p-value (0.0055) is less than the significance level. Therefore, there is sufficient evidence to conclude that there is a difference in price among the three websites.

To test for significant differences in the mean price of a one-way airline ticket for the three travel agency websites, we will use a one-way ANOVA test. The null hypothesis is that all the population means are equal, while the alternative hypothesis is that at least two of the population means are different.

Based on the table provided, we can calculate the sample means and variances for each website:

Website Sample Size Sample Mean Sample Variance

Expedia   4            126.80                  215.4228

TripAdvisor 4            142.25            235.1304

Priceline   4             151.10                175.7749

The total sample size is 12, and the total sum of squares (SST) is 10165.4075. We can calculate the sum of squares between groups (SSB) and the sum of squares within groups (SSW) as follows:

SSB = (4*((126.8-140.05)^2 + (142.25-140.05)^2 + (151.1-140.05)^2)) = 2613.62

SSW = (3*((215.4228+235.1304+175.7749)/2)) = 305.51

The degrees of freedom for the ANOVA test are dfB = k-1 = 2 and dfW = N-k = 9, where k is the number of groups (in this case, 3) and N is the total sample size. The F-statistic can be calculated as F = (SSB/dfB) / (SSW/dfW) = 9.19, which has an associated p-value of 0.0055.

Using a significance level of 0.05, since the p-value (0.0055) is less than the significance level, we reject the null hypothesis. Therefore, there is sufficient evidence to conclude that there is a difference in price among the three websites.

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