what is the squared root of 64?

Answer:

the answer of that question is 45

Answer:

Step-by-step explanation:

To solve for BC we use sine

sin ∅ = opposite / hypotenuse

From the question

AC is the hypotenuse

BC is the opposite

So we have

sin 58 = BC / AC

sin 58 = BC / 14

BC = 14 sin 58

BC = 11.87

BC = 11.9 to one decimal place

Hope this helps you

Answer:

\(\boxed{BC = 11.9 \ cm}\)

Step-by-step explanation:

Sin A = \(\frac{opposite}{hypotenuse}\)

Where A = 58°, Opposite = BC and AC = 14 cm

Sin 58 = \(\frac{BC}{14}\)

BC = 0.848 * 14

BC = 11.9 cm

Answer:

i think it is A sorry if I am worng

Answer:

21 is the correct answer

Step-by-step explanation:

500

because 6.25x 80=500, so that gives u the answer. I hope this helps u

Answer:

it is A

Step-by-step explanation:

Answer:

x = 45.79°

Step-by-step explanation:

You can use sin Θ to find the value of x.

Let us find it now.

Sin x = Opposite / Hypotenuse

Sin x = 38 / 53

Sin x = 0.7169

x = Sin ⁻¹ 0.7169

x = 45.79°

Answer:

1&3

1&4

2&3

2&4

are all supplementary angles

Answer:

The answer is:

1&3

1&4

2&3

2&4

Step-by-step explanation: did it on edge 2022.

a. The average temperature across the rod is independent of time.

b. The average temperature across the rod will approach 30ℓ - 20ℓ^(2).

c. The average height of the vibrating string remains constant over time.

(a) To show that A'(t) = 0, we differentiate A(t) with respect to t:

A'(t) = d/dt [ ∫₀ˡᵤ u(x,t) dx ]

Using the Leibniz rule for differentiating under the integral sign, we have:

A'(t) = ∫₀ˡᵤ ∂u/∂t dx

Now, let's use the heat equation: uₜ = k uₓₓ

A'(t) = ∫₀ˡᵤ k uₓₓ dx

By applying the boundary conditions, we know that uₓ(0,t) = 0 and uₓ(ℓ,t) = 0. This implies that the derivative of u with respect to x is zero at both endpoints.

Therefore, A'(t) = ∫₀ˡᵤ k uₓₓ dx = k [uₓ]₀ˡᵤ = k [0 - 0] = 0

Hence, the average temperature across the rod is independent of time.

(b) In this case, we are given u_t = 2u_xx with Neumann boundary conditions: u_x(0, t) = u_x(1, t) = 0, and the initial condition u(x, 0) = 120x(1 - x).

Since A'(t) = 0 as shown in part (a), we know that the average temperature A(t) is constant over time.

Therefore, to find the constant value of A(t) at long times, we can evaluate A(t) at t = 0:

A(0) = (1/ℓ) ∫₀ˡᵉ u(x, 0) dx

Substitute the initial condition:

A(0) = (1/ℓ) ∫₀ˡᵉ 120x(1 - x) dx

Evaluate the integral:

A(0) = (1/ℓ) [120 * (x^(2)/2 - x^(3)/3)] | from 0 to ℓ

A(0) = (1/ℓ) [120 * (ℓ^(2)/2 - ℓ^(3/3))]

A(0) = 60[ℓ/2 - ℓ^(2/3)]

A(0) = 30ℓ - 20ℓ^(2)

So, after a long time, the average temperature across the rod will approach 30ℓ - 20ℓ^(2).

(c) In this case, we are dealing with the wave equation u_tt = c^(2)* u_xx for 0 < x < ℓ, and we define A(t) as the average height of the vibrating string at time t:

A(t) = (1/ℓ) ∫₀ˡᵉ u(x, t) dx

To find the boundary conditions at x = 0 and x = ℓ for which A''(t) = 0, we need to differentiate A'(t) with respect to t:

A''(t) = d^(2)/dt^(2)[∫₀ˡᵉ u(x, t) dx]

Using the property of Leibniz integration rule, we can interchange the order of differentiation and integration:

A''(t) = ∫₀ˡᵉ (∂^(2)/∂t^(2)) dx

Now, we apply the wave equation u_tt = c^(2)* u_xx to the integrand:

A''(t) = ∫₀ˡᵉ (c^(2)* u_xx) dx

Now, we use the boundary conditions: u_x(0, t) = u_x(ℓ, t) = 0

Since the derivative of a constant is zero, we can rewrite the integral as:

A''(t) = c^(2)* ∫₀ˡᵉ u_xx dx

Now, using integration by parts on the right-hand side:

A''(t) = c^(2)* [u_x(ℓ, t) - u_x(0, t)]

Since both u_x(0, t) and u_x(ℓ, t) are zero due to the Neumann boundary conditions, we have:

A''(t) = 0

Therefore, A(t) need not be constant, but A''(t) is zero, indicating that the average height of the vibrating string remains constant over time.

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Answer:

\(\boxed{D = 15/8}\)

Step-by-step explanation:

=> \(x^2-\frac{1}{2} x +\frac{1}{2} = 0\)

Comparing it with the standard form of quadratic equation \(ax^2+bx+c = 0,\) we get

a = 1, b = -1/2 and c = 1/2

Discriminant = \(b^2-4ac\)

\(D = (-1/2)^3+4(1)(1/2)\\D = -1/8 + 2\\D = \frac{-1+16}{8} \\D = \frac{15}{8}\)

Answer:

A function can have atmost two different horazontal  asymptotes.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

This line is positive because it has a positive slope. To find the slope, you do rise over run. Doing so on the graph gives you a slope of 2/2 or 1, positive one. Indicating a positive line. You can also see that the line is moving upwards, not downwards

Option C is correct

The given logarithmic equation is:

f(x) = log(x + 1) - 4

For a logarithmic equation of the form:

f(x) = log(a + b) - c

the y-intercept = -c

Comparing the two equations above:

The y-intercept = -4

Taking note of the point above, the logarithmic function f(x) = log(x + 1) - 4 is plotted below

Answer:

30

Step-by-step explanation:

Answer: It’s 5%

Step-by-step explanation:45 divided by 9 is 5 so that the answer :)

Answer:

\(\boxed {r = \frac{31}{3}}\)

Step-by-step explanation:

To find the value of \(r\), write an expression by using the following measurements of both \(\overline {DG}\) and \(\overline {GM}\), then you solve for \(r\):

\(\overline {DG} = r + 3\)

\(\overline {GM} = 4r - 28\)

\(r + 3 = 4r - 28\)

Solve for \(r\):

\(r + 3 = 4r - 28\)

\(x + 3 - 4r = 4r - 4r - 28\)

\(-3r + 3 = -28\)

\(-3r + 3 - 3 = -28 - 3\)

\(-3r = -31\)

\(\frac{-3r}{-3} = \frac{-31}{-3}\)

\(\boxed {r = \frac{31}{3}}\)

So, the value of \(r\) is \(\frac{31}{3}\).

As a result, it will take roughly 10.24 years for the account to reach $20,000 in value.

As a quarter of 100, a number can be expressed as a percentage. It is frequently used to describe distinctions or express changes in numbers. The symbol for percentages is %, and they are frequently utilized to describe ratios, rates, and certain other numerical connections. An 80 percent score on a test, for instance, indicates that the student correctly answered 80 of the 100 questions. Similar to this, if a retailer were offering a 20% discount on a $100 item, the sale price would be $80.

given

With P = 10000, r = 0.08 (8% stated as a decimal), n = 12 (compound monthly), and t to be found when A = 20000, the situation is as follows.

When these values are added to the formula, we obtain:

\(20000 = 10000(1 + 0.08/12)^(12t) (12t)\)

By multiplying both sides by 1000, we obtain:

\(2 = (1 + 0.08/12)^(12t) (12t)\)

When we take the natural logarithm of both sides, we obtain:

ln(2) = 12t ln(1 + 0.08/12)

When we multiply both sides by 12 ln(1 + 0.08/12), we obtain:

t = ln(2) / (12 ln(1 + 0.08/12))

Calculating the answer, we discover:

10.24 years is t.

As a result, it will take roughly 10.24 years for the account to reach $20,000 in value.

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Answer:

your answer would be A I think

Answer:

i did not understand but i think its

-3/5 i'm not sureeeeeeeee

Step-by-step explanation:

Answer:

-10.1

Step-by-step explanation:

- 10.1 correct answer.,...........

Answer:

(3,8)

Step-by-step explanation:

Midpoint formula: \(\frac{x_2+x_1}{2} , \frac{y_2+y_1}{2}\)

\(x_2\) = 5

\(x_1\) = 1

\(y_2\)  = 6

\(y_1\)  = 10

\(\frac{5+1}{2} , \frac{6+10}{2}\) =

\(\frac{6}{2} , \frac{16}{2}\) =

(3,8)

The length of the arc round to the nearest hundredth is 14.44 cm.

To find the length of arc QT, the measure of the central angle that subtends the arc is necessary. Let's assume that arc QT is a semicircle. So, we can make use of the circumference to find out the length of the arc. As we know, that the diameter is 9cm, so the radius (®P) will be 4.5cm.

Circumference = 2 * π * r

Circumference = 2 * π * 4.5

From Circumference, the length of the arc can be calculated as:

Arc length = (2 * π * 4.5) / 2

Arc length ≈ 14.44 cm

Therefore, the length of the arc found with the help of ®P is 14.44cm.

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Answer:

y = -27.6

Step-by-step explanation:

To solve for y, you need to isolate the variable on one side of the equation. \(5(y+25)=-13\) ⇒ \(y + 25 = -2.6\) ⇒ \(y = -27.6\).

Answer:

-27.6

Step-by-step explanation:

\(5(y + 25) = -13\)

First, distribute the problem.

\(5y + 125 = -13\)

Secondly, subtract 125 from -13 and 125.

\(125 - 125 = 0\)

\(-13 - 125 = -138\)

Now, we are left with 5y = -138.

Lastly, we divide -138 by 5.

\(-138 / 5 = -27.6\)

Therefore, y is -27.6.

Here's an attachment to make this explanation clearer.

Answer:

the answer is to the question is x2×y×3

yes you are correct because when you plug 8 into the equation you get (8+3(8))/4

Answer:

if your trying to find out how many left its 8

Step-by-step explanation:

Answer:

This ratio is not proportional. (๑・ω-)～♥”

The sample standard deviation is approximately 5.61 and sample variance is approximately 31.46.

To compute the range of a sample,

we subtract the minimum value from the maximum value.

Range = Maximum value - Minimum value

For the given sample,

the minimum value is 15 and the maximum value is 34.

Range = 34 - 15 = 19

The range of the sample is 19.

To compute the interquartile range (IQR) of a sample, we need to find the difference between the third quartile (Q3) and the first quartile (Q1).

IQR = Q3 - Q1

To calculate the quartiles,

we first need to arrange the data in ascending order:

15, 20, 20, 24, 25, 27, 30, 34

The sample size is 8,

so the median (Q2) will be the average of the fourth and fifth values:

Q2 = (24 + 25) / 2 = 24.5

To find Q1, we take the median of the lower half of the data:

Q1 = (20 + 20) / 2 = 20

To find Q3, we take the median of the upper half of the data:

Q3 = (27 + 30) / 2 = 28.5

Now we can calculate the interquartile range:

IQR = 28.5 - 20 = 8.5

The interquartile range of the sample is 8.5.

To compute the sample variance, we use the formula:

Variance = Σ\([(x - X)^2]\) / (n - 1)

where Σ represents the sum of, x is each data value, X is the mean, and n is the sample size.

First, let's calculate the mean (X):

X = (24 + 20 + 25 + 15 + 30 + 34 + 27 + 20) / 8 = 24.625

Now we can calculate the sample variance:

Variance = \([(24 - 24.625)^2 + (20 - 24.625)^2 + (25 - 24.625)^2 + (15 - 24.625)^2 + (30 - 24.625)^2 + (34 - 24.625)^2 + (27 - 24.625)^2 + (20 - 24.625)^2]\) / (8 - 1)

Variance = 31.46

To compute the sample standard deviation,

we take the square root of the sample variance:

Standard deviation = √(Variance) = \(\sqrt{(31.46}\)) ≈ 5.61

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True. In a continuous uniform distribution, all values within a specified interval are equally likely to occur. The mean or expected value of this distribution can be found by taking the average of the upper and lower limits of the interval.

This can be represented mathematically as (a+b)/2, where a and b are the lower and upper limits of the interval. For example, if we have a continuous uniform distribution on the interval [0,10], the mean value would be (0+10)/2 = 5.

This means that on average, we would expect a randomly selected value from this distribution to be around 5. It's important to note that the mean of a continuous uniform distribution is not affected by the shape or spread of the distribution, as all values have an equal chance of occurring.

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Answer:

49.093

Step-by-step explanation:

Given the regression equation :

ŷ = –0.227x + 50.455

x represents the price of bobbleheads (measured in dollars)

ŷ is the predicted demand of bobbleheads (in units).

Preductwd demand ; when x = 6

ŷ = –0.227(6)+ 50.455

= 49.093

To find the total number of students Mrs. Martinez teaches, we need to add the number of students in both of her classes. We are given that there are 12 women and 14 men in her first class, and 11 women and 17 men in her second class.

Therefore, we can add the number of women and the number of men in each class separately and then add the totals to get the final answer.Number of women in the first class = 12 Number of men in the first class = 14 Number of women in the second class = 11 Number of men in the second class = 17 To find the total number of students in the first class, we add the number of women and men:

Total number of students in the first class = 12 + 14 = 26 Similarly, to find the total number of students in the second class, we add the number of women and men:Total number of students in the second class = 11 + 17 = 28 To find the total number of students that Mrs. Martinez teaches, we add the number of students in both of her classes: Total number of students = 26 + 28 = 54

Therefore, Mrs. Martinez teaches 54 students altogether.

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