Answer: a molecule
Explanation:
Which side of the water molecule is more negative
Due to the unequal distribution of electrons among the atoms and the asymmetrical shape of the molecule, a water molecule has two poles: a positive charge on the hydrogen pole (side) and a negative charge on the oxygen pole (side).
Which water end has a larger negative energy?Water is polar despite having a zero net charge due to the structure of its molecules. The molecule's hydrogen ends are positive, and its oxygen ends are negative. Water molecules are drawn to other polar molecules and to one another as a result.
Why is the negative side of a water molecule?The oxygen atom draws electrons in the covalent link between oxygen and hydrogen a little bit more strongly than the hydrogen atom.
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what are some difficulties in describing the motion of a pendulum using newton's laws instead of the principle of conservation of energy?multiple select question.the weight force varies in magnitudethe tension force varies in magnitudethe tension force varies in directionthe weight force varies in direction
The weight force acting on the pendulum varies in magnitude as it moves through its arc, as does the tension force of the string.
Describing the motion of a pendulum using Newton's laws can be challenging due to the following reasons:
1. The tension force varies in magnitude: As the pendulum swings, the tension force in the string changes depending on the angle of the swing, which affects the net force acting on the pendulum.
2. The tension force varies in direction: The direction of the tension force also changes as the pendulum swings back and forth. This changing direction makes it more difficult to apply Newton's laws directly to the problem.
3. The weight force varies in direction: While the weight force (gravity) remains constant in magnitude, its direction relative to the pendulum's motion changes throughout the swing. This change in direction adds complexity to the analysis of the pendulum's motion using Newton's laws.
By using the principle of conservation of energy, these challenges can be circumvented, as it allows for a more straightforward analysis of the pendulum's motion without needing to consider the varying forces acting on the system.
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A firefighter directs a stream of water from a fire hose at an angle of 40.0° above the horizontal. If the velocity of the stream is 39.0 m/s, what is
the furthest he can stand from the building and still hit it with water? t = Vy/g and x = Vx*2t
Firefighter can hit with water while standing at distance of 153 m from building.
What is a projectile motion?The projectile travels the path with a parabolic trajectory due to the effect of gravity. No horizontal forces so there is no horizontal acceleration.
The velocity of a projectile has horizontal component and the vertical component.
The vertical component of the velocity, \(\displaystyle V_y = Vsin\theta\)
The horizontal component of the velocity, \(\displaystyle V_x = Vcos\theta\)
Given the angle θ with the X- axis = 40°
The velocity of the stream V = 39 m/s
The Y component of the velocity, Vy = 39× sin 40°
Vy = 25.1 m/s
The X component of the velocity, Vx = 39× cos 40°
Vx = 29.88 m/s
The time , t = Vy/g = 25.2/9.8 = 2.56 sec
The distance from the building, \(x = V_x\times 2t\)
x = 29.88 ×2×2.56
x = 153 m
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ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements.
In working this problem, assume the value of "g" to be 9.8 m/s2 with two (2) significant digits unless otherwise stated.
A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine.
_____ W
500.
125
80.0
0.200
Answer:
The answer is 500
Explanation:
The carbon cycle describes the process in which carbon atoms continually travel from the atmosphere to the Earth and then back into the atmosphere. Examine the model. What are abiotic components of the carbon cycle? Choose ALL that apply
The carbon cycle involves both biotic (living) and abiotic (non-living) components.
What are the abiotic components of the carbon cycle?Abiotic components of the carbon cycle include:
Atmosphere: The atmosphere is a major abiotic component of the carbon cycle. Carbon dioxide (CO2) is a greenhouse gas that makes up a small percentage of Earth's atmosphere (currently around 0.04%). Carbon dioxide is released into the atmosphere through processes such as respiration, combustion of fossil fuels, and volcanic eruptions. It can also be absorbed from the atmosphere through processes such as photosynthesis and dissolution in bodies of water.
Oceans: The world's oceans are a significant abiotic component of the carbon cycle. They act as a sink for carbon dioxide, absorbing large amounts of it from the atmosphere. Carbon dioxide dissolves in seawater to form carbonic acid, which can then undergo various chemical reactions to form bicarbonate ions and carbonate ions. These dissolved forms of carbon can be transported and stored in the deep ocean for long periods of time, a process known as oceanic carbon sequestration.
Soil: Soil is another abiotic component of the carbon cycle. Dead plant material and other organic matter that accumulates in soil can undergo decomposition by microorganisms, releasing carbon dioxide back into the atmosphere through a process called soil respiration. Additionally, carbon can be stored in soil as organic carbon, which can remain in the soil for years to centuries depending on environmental conditions.
Geological formations: Carbon can also be stored in abiotic reservoirs such as geological formations, including fossil fuels such as coal, oil, and natural gas. These fossil fuels are formed from ancient organic matter that has been buried and preserved in the Earth's crust over millions of years. When these fossil fuels are burned for energy, carbon is released into the atmosphere as carbon dioxide, contributing to the increase in atmospheric carbon dioxide concentrations.
These abiotic components of the carbon cycle play a crucial role in regulating the balance of carbon between the atmosphere, oceans, soil, and geological formations, and are important in understanding the overall carbon cycle and its impact on the Earth's climate.
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how strong is the electric field between two parallel plates 5.8mm apart if the potential difference between them is 200V?
The electric field strength between the two parallel plates is approximately 34,483 V/m.
Given DataPotential difference (V) = 200VDistance between plates (d) = 5.8mm = 0.0058mThe expression for the computation of the electric field between two plates is given as
Electric field (E) = Potential difference (V) / Distance between plates (d)
Substituting our given values into the expression we have:
E = 200V / 0.0058m
E ≈ 34,483 V/m
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Which of the following is a chemical change?
A. Water vapor in the air turns to liquid water in the form of rain
B. The oxygen in the air forms ozone in presence of UV rays
C. Dust and soot particles being suspended in the air
D. Sulphur dioxide being released in the air
Answer:
B
Explanation:
Can someone cross all the bridges shown in the following map exactly once and return to the starting point? If yes, find one; otherwise, if no, explain why
The answer is no. People cannot cross ll the bridges shown in the following map exactly once and return to the starting point.
In order to determine whether someone can cross all the bridges shown in the map exactly once and return to the starting point, we need to use Euler's theorem.
Therefore, we need to calculate the degree of each vertex in the given map:
Each vertex has an odd degree, which implies that the given map does not have an Eulerian circuit and hence it is not possible to cross all the bridges exactly once and return to the starting point.
Therefore, the answer is no. People cannot cross ll the bridges shown in the following map exactly once and return to the starting point.
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An object is in simple harmonic motion. of the following quantities related to the object, which set of three can have maximum magnitudes at the same instant of time?.
The amplitude, restoring force and speed of an object undergoing simple harmonic motion may have maximum magnitudes at the same instant of time.
What is simple harmonic motion?Simple harmonic motion is a regular repeating motion. The acceleration of a simple harmonic motion is always directed towards the center of the motion.
There are three quantities related to the object that can have maximum values at the same time and these are;
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a photoelectric-effect experiment finds a stopping potential of 2.50 vv when light of 183 nmnm is used to illuminate the cathode.
The work function of the cathode material is approximately 4.97 x 10^-19 J.
Why the energy of the photons in the light must be greater than the work function of the material?The photoelectric effect refers to the phenomenon of electrons being emitted from a material when it is exposed to light. The energy of the photons in the light must be greater than the work function of the material for the electrons to be emitted.
In this experiment, the stopping potential of 2.50 V means that the kinetic energy of the emitted electrons has been completely stopped when they reach the anode. This stopping potential is related to the energy of the photons by the equation:
eV = h*f - Φ
where e is the electron charge, V is the stopping potential, h is Planck's constant, f is the frequency of the light, and Φ is the work function of the cathode material.
To find the frequency of the light, we can use the equation:
E = h*f
where E is the energy of a photon. The energy of a photon is related to its wavelength by the equation:
E = hc/λ
where c is the speed of light and λ is the wavelength of the light.
Substituting these equations, we get:
hf = hc/λ
f = c/λ
Substituting this expression for f into the first equation, we get:
eV = hc/λ - Φ
Solving for Φ, we get:
Φ = hc/λ - eV
Substituting the values given in the problem, we get:
Φ = (6.626 x 10^-34 J s) * (2.998 x 10^8 m/s) / (183 x 10^-9 m) - (1.602 x 10^-19 C) * (2.50 V)
Φ ≈ 4.97 x 10^-19 J
Therefore, the work function of the cathode material is approximately 4.97 x 10^-19 J.
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What voltage can be applied by a resistor
190 Ω and 100 A?
Answer:
V=IR
V=100×190
=19000 V
A small object of mass and charge -18.A NCs suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground. What are the magnitude and Grection of the electric hold? mageltude True direction Nood Relo?
The magnitude of the electric field is 18 N/C, and the true direction of the electric field is perpendicular to the ground.
In the given scenario, a small object with a mass and charge of -18.A NCs is suspended motionless above the ground when immersed in a uniform electric field perpendicular to the ground.
The electric field strength, or magnitude, is given as 18 N/C. The unit "N/C" represents newtons per coulomb, indicating the force experienced by each unit of charge in the electric field. Therefore, the magnitude of the electric field is 18 N/C.
The true direction of the electric field is perpendicular to the ground. Since the object is suspended motionless, it means the electric force acting on the object is balanced by another force (such as gravity or tension) in the opposite direction.
The fact that the object remains motionless indicates that the electric force and the opposing force are equal in magnitude and opposite in direction. Therefore, the electric field points in the true direction perpendicular to the ground.
In summary, the magnitude of the electric field is 18 N/C, and the true direction of the electric field is perpendicular to the ground.
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A 9.0x10^-2kg ice cube at 0.0 degrees Celsius is dropped into a styrofoam cup holding 0.35 kg of water at 13 degrees Celsius.
A. Find the final temperature of the system. Assume the cup and the surroundings can be ignored.
B. Find the amount of ice (if any) remaining.
C. Find the initial temperature of the water that would be enough to just barely melt all of the ice.
A. The final temperature of the system is 0°C.
B. The amount of ice (if any) remaining is 0.0331 g
C. The initial temperature of the water that would be enough to just barely melt all of the ice is 20.57 °C.
What is specific heat?The specific heat is the amount of heat required to change the temperature by 1°C. It is denoted by C.
Heat lost or gained is represented as
Q = m C ΔT
Given, Mass of ice, mice = 9x10⁻² kg, Mass of water, mw =0.35 kg, T = 13 °C
A. If ice is in excess, final water temperature will be 0°C.
B. Specific heat of water Cp = 1000 cal/kg°C
Latent heat of ice L = 80 kcal/kg
In that case, heat lost by water =Heat gain by ice
Q = mCp x dT = mL
0.35 x 1000 x 13 = m x 80 x 1000
m = 0.0569 kg of ice.
The gram of ice remaining = 0.09 - 0.0569
= 0.0331 gram of ice.
Thus, the amount of ice remaining is 0.0331 g
C. Heat required to melt 90 gram of ice, Q mL
Q = 90 x 80 = 7200 cal.
If the initial temperature of water needed = T,
mCp x dT = mL
350 x T = 7200
T = 20.57 °C
Thus, the initial temperature of the water that would be enough to just barely melt all of the ice is 20.57 °C.
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A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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URGENT LAB QUESTIONS
Graded Assignment
Lab Report: Creating and Interpreting Graphs
Answer each question, using complete sentences. When you have finished, submit this assignment to your teacher by the due date for full credit.
Total score: ____ of 25 points
(Score for Question 1: ___ of 6 points)
1. Which variable did you choose for the independent variable? Which variable did you choose for the dependent variable? Explain.
Answer:
(Score for Question 2: ___ of 12 points)
2. How did the masses affect the spring? Which mass stretched the spring the farthest? The least? Explain your answer using your data. Include your data sheet and the graph of your data in your answer.
Answer:
Type your answer here.
(Score for Question 3: ___ of 7 points)
3. Describe your graph, was it linear or nonlinear? What conclusions can you draw based on the shape of the graph?
Answer:
Type your answer here.
Answer:
give the main question as I can not see the information
compared to spiral galaxies, elliptical galaxies are:
flat disk like shape
________________
o0o0o0o0o0o0o0o0
This is because we see evidence of plate movement in the fact that as we look at rocks farther and farther from the ridge, the rocks--
A)Have higher iron content
B)Are made up of smaller particles
C)Become thicker and thicker
D)Are consistently older
Answer:c
Explanation:
Answer:
C
Explanation:
If the angle of reflection of a propagated ray is 35°. Calculate the a. Angle of incidence b. Angle of deviation c. Angle of glance
\( \LARGE{ \underline{ \blue{ \tt{Required \: answers}}}}\)
First of all,
Angle of incidence = Angle between normal and incident ray.Angle of reflection = Angle between normal and reflected rayGlance angle of incidence = Angle between incident ray and the surface.Glance angle of reflection = Angle between reflected ray and the surface.We have,
➝ Angle of reflection = 35°
(a) According to law of reflection,
Angle of incidence = Angle of reflection
➝ Angle of incidence = 35°
(b) By using formula,
Angle of Deviation = 180° - 2(Angle of incidence)
From (a),
➝ Angle of Deviation = 180° - 2(35°)
➝ Angle of Deviation = 180° - 70°
➝ Angle of Deviation = 110°
(c) We know,
Angle of Incidence + Glance angle of incidence = 90°
Angle of reflection + Glance angle of reflection = 90°
So,
As angle of incidence = angle of reflection
Then, Angle of glance is also equal.
➝ Angle of glance = 90° - 35° = 55°
━━━━━━━━━━━━━━━━━━━━
Consider a beaker with two holes X and Y near the base, such that hole X is ABOVE hole Y. The holes are closed with water-resistant tape and the beaker is filled with water.
Both the holes are then uncovered at the same time. If water from hole X comes out in a stream that touches the ground at a distance of 5 cm away from the beaker, how far from the beaker will the stream from hole Y touch the ground?
1. exactly 5 cm
2. less than 5 cm
3. more than 5 cm
4. (It will be more or less than 5 cm depending on the distance between the two holes.)
As the height of the hole increases, the velocity of the stream increases, results in a higher distance from the beaker. Therefore, the distance of the stream from the hole Y will be less than that from X thus, less than 5 cm is correct.
What is stream speed ?The speed of stream can be determined using the height and acceleration due to gravity g. We can use the equation for velocity using the parameters g and h.
v = √2gh
Therefore, as the height h increases, v increases.
Similarly the distance s = vt
therefore, the distance increases with v.
Here, the hole x is above the hole Y. Then the stream from X will have the greater speed and it covers greater distance (5 cm )from the beaker. Stream from Y slow compared to that in X hence covers a distance less than 5 cm. Hence, option 2 is correct.
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at what angular velocity is the centripetal acceleration 11.25 g if the rider is 16.5 m from the center of rotation? give your answer in rad/s.
Answer: The angular velocity at which the centripetal acceleration is 11.25 g, with a radius of 16.5 m, is approximately 2.59 rad/s.
Explanation:
Centripetal acceleration (ac) = angular velocity (ω)² × radius (r)
Here, the centripetal acceleration is given as 11.25 g, where g is the acceleration due to gravity (approximately 9.8 m/s²). The radius is given as 16.5 m.
First, we need to convert 11.25 g to meters per second squared (m/s²):
11.25 g = 11.25 × 9.8 m/s² ≈ 110.25 m/s²
Substituting the known values into the formula, we have:
110.25 m/s² = ω² × 16.5 m
To solve for the angular velocity (ω), we can rearrange the equation as follows:
ω² = 110.25 m/s² / 16.5 m
ω² ≈ 6.7 rad²/s²
Taking the square root of both sides, we find:
ω ≈ √6.7 rad/s =2.59 rad/sec
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PLEASE HELP! FOR BRAINLIEST!
Answer:
i read the whole thing the answer that matches the most is C
hope this helped :D
Explanation:
if a tennis ball of 50g mass is thrown at 20m/s velocity and it hits a wall and bounces back, what will be the change of momentum?
Answer:
Gold is a relatively dense metal because its atoms have more protons then atoms of many other metals
Explanation:
The andromeda galaxy, m31, is in many ways similar to our own galaxy but slightly larger. the linear diameter of the andromeda galaxy along its longest axis is 140,000 light-years, but from our perspective, the andromeda galaxy has a maximum angular diameter of 3.18°. how far away is the andromeda galaxy?
The Andromeda Galaxy distance is approximately 2.52 million light-years away from us.
The Andromeda Galaxy (M31) is indeed similar to our own Milky Way galaxy, but slightly larger with a linear diameter of 140,000 light-years along its longest axis. To determine its distance from us, we can use the angular diameter, which is 3.18°.
We can use the small-angle formula to find the distance. This formula relates the angular diameter (in radians), the actual diameter, and the distance between the observer and the object:
angular diameter (radians) ≈ actual diameter / distance
First, we need to convert the angular diameter from degrees to radians:
3.18° * (π radians / 180°) ≈ 0.0555 radians
Now, plug in the values into the small-angle formula:
0.0555 radians ≈ 140,000 light-years / distance
To solve for the distance, divide both sides of the equation by 0.0555 radians:
distance ≈ 140,000 light-years / 0.0555 radians
distance ≈ 2,522,522 light-years
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calculate the angular momentum of an ice skater spinning at 5.90 rev/s given his moment of inertia is 0.408 kg·m2.
The angular momentum of the ice skater can be calculated as L = (0.408 kg·m2) x (37.17 rad/s) = 15.16 kg·m2/s. The angular momentum of an ice skater spinning at 5.90 rev/s can be calculated using the formula L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity in radians per second.
In this case, the moment of inertia of the ice skater is given as 0.408 kg·m2 and the angular velocity is 5.90 rev/s or 37.17 rad/s (since one revolution is equivalent to 2π radians). Therefore, the angular momentum of the ice skater can be calculated as L = (0.408 kg·m2) x (37.17 rad/s) = 15.16 kg·m2/s.
This means that the ice skater has a significant amount of angular momentum due to the combination of his moment of inertia and angular velocity. This angular momentum must be conserved unless acted upon by external forces such as friction or collisions.
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A rider and his biycle weigh 100 ka If they sccelerate at a rate of 2 m/s2
(meters per second squared), how much force is generated?
1- 50 N
2- 200N
3- 0.5N
4- 300 N
What is the quality of the sound of an ambulance's siren when it moves toward a stationary hearer? What is the quality of the sound of an ambulance's siren when it moves away from a stationary hearer?
Answer:
A) As the ambulance's siren moves toward a stationary hearer, the quality of sound will have a higher pitch
B) As the ambulance's siren moves away from a stationary hearer, the quality of sound will have a lower pitch.
Explanation:
From Doppler effect, the closer the source of sound gets to the observer, the higher the frequency and in turn the higher the pitch.
Meanwhile, the farther a source goes from an observer, the lower the frequency of the sound and also the lower the pitch.
Thus, as the ambulance's siren moves toward a stationary hearer, the quality of sound will have a higher pitch.
As the ambulance's siren moves away from a stationary hearer, the quality of sound will have a lower pitch.
Answer:
a. The quality of the sound would have a high pitch and thus be loud.
b. The quality of the sound would have a low pitch and thus would have a lower volume than the sound from the source.
Explanation:
Using the formula for Doppler shift f' = (v ± v')f/(v ± v") where v = speed of sound in air, v'= speed of hearer = 0 m/s (since he is stationary), v" = speed of ambulance and f = frequency of sound from ambulance
So, f' = (v ± v')f/(v ± v")
f' = (v ± 0)f/(v ± v")
f' = vf/(v ± v")
a. What is the quality of the sound of an ambulance's siren when it moves toward a stationary hearer?
Since the source (ambulance) moves towards the detector, (hearer), we would get an upwards shift in frequency. (Since our denominator has to be a minimum, so we use the minus sign for v"). So, the quality of the sound would have a high pitch and thus be loud.
b. What is the quality of the sound of an ambulance's siren when it moves away from a stationary hearer?
Since the source (ambulance) moves away the detector, (hearer), we would get a downward shift in frequency. (Since our denominator has to be a maximum, so we use the plus sign for v"). So, the quality of the sound would have a low pitch and thus would have a lower volume than the sound from the source.
Martije has made a slight error in naming a compound monocarbon tetrabromide. What compound is she most likely naming, and what is its correct name? C1B4 (monocarbon tetrabromide) C1Br4 (monocarbon tetrabromide) CB4 (carbon tetrabromide) CBr4 (carbon tetrabromide)
Answer: \(CBr_4\) : carbon tetrabromide
Explanation:
\(CBr_4\) is a covalent compound because in this compound the sharing of electrons takes place between carbon and bromine. Both the elements are non-metals. Hence, it will form covalent bond.
The naming of covalent compound is given by:
1. The less electronegative element is written first.
2. The more electronegative element is written second. Then a suffix is added with it. The suffix added is '-ide'.
3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on.
Hence, the correct name for \(CBr_4\) is carbon tetrabromide.
Answer:
Carbon tetrabromide ~ CBr4
Chlorine monofluoride~ ClF
Explanation:
EDGU 2021
Which term best describes the form of beryllium shown
Answer:
✓ Ion
Explanation:
Which term BEST describes the form of beryllium shown? Protons=4 Neutrons=5 Electrons=2
✓ Ion
A hiker walks with an average speed of 2.6 M Square what distance in kilometers does the hiker travel in a time of 2.8 hours
Answer:
The answer is "26.208 km"
Explanation:
Given value:
\(\to S= 2.6 \ \frac{m}{s}\\\\\to t= 2.8 \ hours\)
Formula:
\(d= st\\\\d= 2.6 \times 2.8 \times \frac{60 \times 60}{1000}\\\\d= 26.208\ km\)
A 16.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.2-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.23 s. What is the average induced emf in the loop?
A 16.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.2-T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.23 s. The average induced emf in the loop is -0.1113 V.
Given:
Diameter of the loop of wire = 16.5 cm
Radius (r) of the loop = diameter/2 = 8.25 cm = 0.0825 m
Magnetic field (B) = 1.2 T
The time taken to rotate the loop = 0.23 s
We need to calculate the average induced emf in the loop.
The formula to calculate the average induced emf in the loop is given as,
e=ΔΦ/Δte=ΔB*A/Δt
Here, ΔΦ = change in magnetic flux
Δt = time taken to rotate the loop
A = area of the loop of wire
We can find the area of the loop as,
A = πr²A = 3.14 × (0.0825 m)²A = 0.0213 m²
Now, we need to find the change in magnetic flux (ΔΦ).
Initially, the loop is perpendicular to the magnetic field, so the magnetic flux is given by,
Φ = BAΦ = (1.2 T) × 0.0213 m²Φ = 0.0256 Wb
When the loop is rotated, the angle between the plane of the loop and the magnetic field changes from 90° to 0°.Hence, the change in magnetic flux is
,ΔΦ = BAcosθ
Here,θ = 90° - 0° = 90°
ΔΦ = BAcos90°
ΔΦ = 0 Wb
Substituting the values in the formula of emf,
e=ΔΦ/Δte
=ΔB*A/Δt
We get,e = (0 - 0.0256 Wb)/0.23 se = -0.1113 V
Thus, the average induced emf in the loop is -0.1113 V. The negative sign indicates that the emf induced in the loop is in the opposite direction to the change in magnetic flux.
To know more about induced emf refer to:
https://brainly.com/question/13744192
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