What is the value of X in circle O below?
Need help on all step by step preferably

Answer:

x = 1/4x - 5

Step-by-step explanation:

Step 1: Translate from word to math

A number = x

five less = -5

one-fourth = 1/4

of itself = x

Step 2: Combine

x = 1/4x - 5

The circumference of the circle with the radius is 50.24 inches

The figure represents the given parameter

On the figure, we have the diameter (d) to be

d = 16 inches

The radius of the circle is calculated using

r = d/2

So, we have

r = 16/2

Evaluate the quotient

r = 8

The circumference of the circle is then calculated as

C = 2πr

Where π is given as

π = 3.14

So, we have

C = 2 * 3.14 * 8

Evaluate the product

C = 50.24

Evaluate the product

C = 50.24

Hence, the circumference of the circle with the radius is 50.24 inches

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Answer:

$2.20

You do 22÷10 and you get 2.20

Answer:

23.52

Step-by-step explanation:

because I times 12 and 1.4 then I added 1.4 and 16.8 to get 23.52

Here is your Answer !!!

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Answer:

1  37/120

Step-by-step explanation:

Answer: y = x +8

Step-by-step explanation:

Answer:

This many.

Step-by-step explanation:

Simplifying

5 = 5x + -20

Reorder the terms:

5 = -20 + 5x

Solving

5 = -20 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

5 + -5x = -20 + 5x + -5x

Combine like terms: 5x + -5x = 0

5 + -5x = -20 + 0

5 + -5x = -20

Add '-5' to each side of the equation.

5 + -5 + -5x = -20 + -5

Combine like terms: 5 + -5 = 0

0 + -5x = -20 + -5

-5x = -20 + -5

Combine like terms: -20 + -5 = -25

-5x = -25

Divide each side by '-5'.

x = 5

Simplifying

x = 5

The young modulus of a wire with an area of 0.01 m², that strain 6.25 * 10⁻³ if a load of 100N is applied is 16000 N/m²

An equation is an expression that shows the relationship between two or more variables and numbers.

The young modulus is given as:

Young modulus = stress / strain = load / (area * strain) = 100 / (0.01 * 6.25 * 10⁻³) = 16000 N/m²

The young modulus of a wire with an area of 0.01 m², that strain 6.25 * 10⁻³ if a load of 100N is applied is 16000 N/m²

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2 different expressions that involve only outs and powers of 2 which are equivalent 4 2/3 / 8 1/4

1) (4^2 * 2^-1 * 3^1) / (8^1 * 2^-2 * 4^-1)

2) (2^5 * 3^1) / (2^6 * 4^-1)

1) (4^2 * 2^-1 * 3^1) / (8^1 * 2^-2 * 4^-1)

This expression is equivalent to 4 2/3 / 8 1/4 because it is written in terms of powers of two. 4^2 is equal to 16, which is the numerator in 4 2/3. 2^-1 is the same as 1/2, which is the second fraction in 4 2/3. 3^1 is equal to 3, which is the numerator in 8 1/4. 8^1 is equal to 8, which is the denominator in 8 1/4. 2^-2 is the same as 1/4, which is the second fraction in 8 1/4. 4^-1 is equal to 1/4, which is the first fraction in 8 1/4. When all the terms are multiplied and divided, it is the same as 4 2/3 / 8 1/4.

2) (2^5 * 3^1) / (2^6 * 4^-1)

This expression is also equivalent to 4 2/3 / 8 1/4 because it is written similar to above equation.

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After working 8 hours and grading 9 papers per hour, it is expected Autumn has 11 papers left.

To calculate the number of papers she can grade during this time, let's use the rate provided:

This means in 9 hours she can grade 72 papers.

Now, let's calculate the number of papers left:

Based on this, the total of papers left after working for 8 hours is 11 papers.

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The number of students who own a cat are 17.

Given is a survey of the 30 students in Juan's class.

We can write -

Number of students who own dog = (1/2) x 30 = 15

Number of students who own dog and cat both = (2/3) x 15 = 10

Number of students who have no pets = 8

Number of students owning a cat alone = 30 - (15 + 8) = 7

Students who own a cat = 10 + 7 = 17

Therefore, the number of students who own a cat are 17.

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Answer:

slope = - \(\frac{3}{2}\)

Step-by-step explanation:

calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (2, 1 ) and (x₂, y₂ ) = (8, - 8 ) ← 2 ordered pairs from the table

note that any 2 ordered pairs may be used to calculate m

m = \(\frac{-8-1}{8-2}\) = \(\frac{-9}{6}\) = - \(\frac{3}{2}\)

Answer:

9/8

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

   = ( 7 - -2)/( 9 - 1)

   = ( 7+2)/( 9-1)

   = 9/8

Answer:

a) x=3

y=6*3+4

=22

b) x=4

y=6*4+4

=24

c) x=6

y=6*6+4

=40

d) x=7

y=6*7+4

=46

Answer:

Sin A= Cos B

Step-by-step explanation:

Doing each equation out, using sohcahtoa (sin=opposite/hypotenuse, cos=adjacent/hypotenuse, tan=opposite/adjacent, we don't need tan for this problem), we get Sin A=BC/AB, Sin B=AC/AB, Sin C=1, Cos A=AC/AB, Cos B=BC/AB. Afterwards we see which pairs are equal.... Sin B= Cos A, Sin A=Cos B. The final step is seeing which answer matches the multiple choice options. The only option that works is Sin A=Cos B. Hope this helps!

Answer:

28 minutes

Step-by-step explanation:

1232w * ((1m) / (44w))

1232m / 44 = 28m

The part in italics is just the ratio of 44 words per minute

The point prevalence of brilliance at the end of Week 1 is 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 is 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 is 0.33 or 33%.

Using person-weeks as denominator, the incidence of brilliance over the course of the 10-week course is 0.017 or 1.7%

In epidemiology context, brilliance can be calculated through calculating point prevalence, cumulative incidence, and incidence rate. The provided data table can be used to determine the point prevalence, incidence, and incidence rate of brilliance among PHE 450 students. So, the calculations of point prevalence, cumulative incidence, and incidence rate based on the provided data are as follows:

The point prevalence of brilliance at the end of Week 1 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #8 was the only existing case of brilliance at the beginning of Week 1, so the point prevalence of brilliance at the end of Week 1 is; Point prevalence = 1 ÷ 12 = 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3 and Student #8 were existing cases of brilliance at the beginning of Week 2, so the point prevalence of brilliance at the end of Week 2 is; Point prevalence = 2 ÷ 12 = 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3, #4, #6, and #8 were existing cases of brilliance at the beginning of Week 3, so the point prevalence of brilliance at the end of Week 3 is; Point prevalence = 4 ÷ 12 = 0.33 or 33%.

The incidence of brilliance can be calculated by the following formula; Incidence = Total number of new cases ÷ Total person-weeks of observation

Student #5 and Student #7 developed brilliance during the 10-week course, so the incidence of brilliance over the course of the 10-week course is; Incidence = 2 ÷ 120 = 0.017 or 1.7%.

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The length x in the triangle, considering the trigonometric ratios, is given as follows:

x = 11.7.

The three trigonometric ratios are the sine, the cosine and the tangent, and they are defined as follows:

The length x is opposite to the angle of 64º, while the hypotenuse is of 13 units, hence it is given as follows:

sin(64º) = x/13

x = 13 x sine of 64 degrees

x = 11.7.

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To calculate how long it will take for the pond to be filled with rainfall at a rate of 1cm per hour, we need to know the volume of the pond. This answer seems impractical as it equates to approximately 17,917 years. Therefore, we can conclude that the pond will never fill up with rainfall at a rate of 1cm per hour.

Let's assume the pond is a circular shape with a diameter of 10 meters and a depth of 2 meters. To find the volume, we need to use the formula for the volume of a cylinder, which is πr^2h, where π is approximately 3.14, r is the radius of the pond (5 meters), and h is the depth (2 meters).
So, the volume of the pond is approximately 157 cubic meters (3.14 x 5^2 x 2). Now, we need to convert this volume into centimeters, as the rainfall rate is given in cm/hr. One cubic meter is equal to 100 x 100 x 100 cubic centimeters, which equals 1,000,000 cubic centimeters. Therefore, the pond's volume is 157 x 1,000,000 = 157,000,000 cubic centimeters.
Now, we can calculate how long it will take to fill the pond with rainfall at a rate of 1cm per hour. We divide the volume of the pond by the rate of rainfall, which gives us 157,000,000 / 1 = 157,000,000 hours.

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Answer:

Step-by-step explanation:

From the diagram, just the way it is marked, the two triangles are congruent by either SAS or ASA (although this requires an extra step).

Rereading the question, you are only allowed to use the markings given. So the answer is SAS

answer:

2578

step-by-step explanation:

A=2(wl+hl+hw)=2·(47·19+6·19+6·47)=2578

good luck

hopefully this helps

have a nice day :)

Answer:

equation 6+(½×n). n means the number of months

The equation that represents the situation is y = 6 + (1/2)x.

Equations whose variables have a power of one are called linear equations. One example with one variable is where ax+b = 0, where a and b are real values and x is the variable.

Given:

A baby giraffe measures 6 feet tall when it is born.

Initial height of baby=6 feet.

Average growth per months = 1/2

                                               =0.5 feet

Let x be the number of months.

And the height of a baby giraffe is y feet.

So equation is,

y = 6+0.5x

or, y = 6 + (1/2)x.

Therefore, the equation is  y = 6 + (1/2)x.

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Answer:

56

Step-by-step explanation:

Answer: 60

Step-by-step explanation:

75% of 80 is 60.

Multiply 80 by .75 to get the answer.

How many question  he got correct is 60

Given:

Test = 80 problems,

Correct Answer=75%

Now let calculate How many  question he got correct

Numbers of correct question=80×0.75

Numbers of correct question=60

Inconclusion How many question  he got correct is 60.

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A p-value of 0.02 in this drug trial indicates that there is a 2% chance of observing the improvement or a more extreme improvement if the drug had no actual effect.

In the context of a drug trial, the p-value is a statistical measure that quantifies the strength of evidence against the null hypothesis.

The null hypothesis assumes that there is no effect or difference between the treatment group (patients receiving the drug) and the control group (patients receiving a placebo or standard treatment).

The p-value represents the probability of observing the obtained results, or more extreme results, assuming the null hypothesis is true.

In this particular trial, a p-value of 0.02 indicates that there is a 2% chance of obtaining the observed improvement or an even more extreme improvement if the drug had no actual effect.

In other words, the low p-value suggests that the results are statistically significant, providing evidence against the null hypothesis and supporting the effectiveness of the drug.

The conventional threshold for statistical significance is often set at 0.05 (5%). Since the p-value in this trial (0.02) is lower than 0.05, it falls below this threshold and suggests that the observed improvement is unlikely to be due to random chance alone.

However, it's important to note that statistical significance does not necessarily imply clinical or practical significance. Additional considerations, such as effect size and clinical judgment, should be taken into account when interpreting the findings of a drug trial.

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Hey there! :)

Answer:

\(n_{4} = 8\\ n_{5} = 16\)

Formula: \(f(n) = 2^{n-1}\)

Step-by-step explanation:

Derive a rule from the numbers in the sequence:

\(n_{1} = 1\\n_{2} = 2\\n_{3} = 4\)

We can see that each number is double of the previous. We can write an explicit function describing this sequence:

\(f(n) = 2^{n-1}\) where 'n' is the term number.

Substitute in to solve for the 4th and 5th terms:

\(f(4) = 2^{4-1} = 2^{3} =8\)

\(f(5) = 2^{5-1} = 2^{4} =16\)

Therefore:

\(n_{4} = 8\\ n_{5} = 16\)

Answer:28+12x

Step-by-step explanation:

(7 + 3x) 4 = 28+12x

Answer:

28+12x

Step-by-step explanation:

I got it right

Comparing the means of the two samples, we find that the difference between the means is significant. Therefore, we can reject the claim and conclude that male and female high school students have different exam scores.

To perform the two-sample t-test, we first calculate the standard error of the difference between the means using the formula:

SE = sqrt((s1^2 / n1) + (s2^2 / n2))

Where s1 and s2 are the population standard deviations of the male and female students respectively, and n1 and n2 are the sample sizes. Plugging in the values, we have:

SE = sqrt((47^2 / 49) + (4.3^2 / 53))

Next, we calculate the t-statistic using the formula:

t = (x1 - x2) / SE

Where x1 and x2 are the sample means. Plugging in the values, we have:

t = (239 - 21.1) / SE

We can then compare the t-value to the critical t-value at α = 0.01 with degrees of freedom equal to the sum of the sample sizes minus 2. If the t-value exceeds the critical t-value, we reject the null hypothesis.

In this case, the t-value is calculated and compared to the critical t-value using the provided standard normal distribution table. Since the t-value exceeds the critical t-value, we can reject the claim that male and female high school students have equal exam scores.

Therefore, the correct answer is:

B. Male and female high school students have different exam scores.

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Answer:

3(2x+4)+2(x-2)

6x+12+2x-4

6x+2x+12-4

8x+8

I am from grade 9 from which grade are you

Twο pοints (8,8) and (-2,6) are the set οf the equatiοn  \(y < \frac{3}{4} x+6\\\) οf the graph \(y = \frac{3}{4} x+6\).

Graph, a diagram that shοws hοw a variable varies in relatiοn tο οne οr mοre οther variables (such as a cοllectiοn οf pοints, lines, line segments, curves, οr regiοns).

Nοw we have tο find the value οf the equatiοn i.e. \(y < \frac{3}{4} x+6\\\),

(x, y) = (8,8) , we get 8 < 12 , First pοint

(x, y) = (-4,3) , we get 3 = 3 , Nο match

(x, y) = (6,-2) , we get -2 < 10.5 , Secοnd Pοint

(x, y) = (0, 8) , we get 8 > 6 , Nο Match

(x, y) = (-9,2) , we get 2>-0.75 , Nο Match

Sο, we get οur pοints, which are pοints (8,8) and (-2,6) fοr the equatiοn \(y < \frac{3}{4} x+6\\\).

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