What is the volume occupied by 3.67 moles of h2 gas at stp? (hint: you do not need the molar mass to do this conversion because it is a gas) *

Answer:

588 mole

29.4

+29.4

5 8. 8g

The expression for α0, α1, and α2 implicated in the speciation of H2CO3 into HCO3- and CO32- are:

(2)These reactions can be defined using the acid dissociation constant (Ka) of H2CO3 as follows:

From these definitions, the acid dissociation constants for H2CO3's first (Ka1) and second (Ka2) dissociation reactions can be expressed as shown below:

An acid is a molecule or ion that can donate a proton, or, alternatively, can form a covalent bond with an electron pair. The first category of acids is the proton donor or Brønsted acid. In the special case of an aqueous solution, the proton donor forms the hydronium ion H₃O⁺ and is known as an Arrhenius acid. PH is the degree of acidity or alkalinity of a solution, expressing the negative logarithm of the concentration of H ions with a base number of 10. Neutral solutions have a PH of 7, acids less than 7, bases greater than 7. In waters that are not polluted, PH is controlled by CO2 ions, Carbonates and Bicarbonates.

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A) Because KOH is a strong base, it totally dissociates in water to create K+ and OH- ions. As a result, the concentration of OH- in solution equals the concentration of KOH. The solution's pOH can be computed as follows:

\(1.12 pOH = -log[OH-] = -log(7.6x10-2)\)

Because pH + pOH = 14, the solution's pH is:

pH = 14 - pOH = 14 - 1.12 = 12.88

B) Calcium hydroxide (\(Ca(OH)_{2}\)) is a strong base that totally dissociates in water to generate \(Ca_{2}\)+ and 2OH- ions. The OH- concentration in the diluted solution is calculated as follows:

\(Ca(OH)_{2}\) moles = concentration x volume = 1.10x\(10-^{2}\) x 14.0x\(10-^{3}\) = 1.54x\(10-^{4}\) mol

Because \(Ca(OH)_{2}\) dissociates into two moles of OH- for every mole of Ca(OH), the total number of moles of OH- in the solution is 2 x 1.54x\(10-^{4}\) = 3.08x\(10-^{4}\) mol.

After dilution, the total volume of the solution is 580.0 + 14.0 = 594.0 mL. As a result, the OH- concentration in the diluted solution is:

[OH-] = 3.08 x \(10-^{4}\) mol/0.594 L = 5.19 x \(10-^{4}\) M

C) To compute the concentration of hydroxide ions in the mixed solution, we must first know the moles of hydroxide ions present.

This is accomplished by calculating the moles of hydroxide ions contributed by each separate solution and then adding them all together.

In the case of :

OH- ion moles = concentration volume = 1.50\(10-^{2}\) mol/L 0.015 L = 2.25 \(10-^{4}\) mol

In the case of NaOH:

OH- ion moles = concentration volume = 7.6 \(10-^{3}\) mol/L 0.036 L = 2.736 \(10-^{4}\) mol

Total OH- ion moles = 2.25 \(10-^{4}\) mol + 2.736 \(10-^{4}\) mol = 4.986 \(10-^{4}\) mol

The concentration of hydroxide ions in the mixed solution can now be calculated:

15 mL + 36 mL = 51 mL = 0.051 L total volume of the combined solution

[OH-] = moles of OH- ions divided by total volume of mixed solution

(4.986 10-4 mol) / (0.051 L) = 9.77 10-3 M [OH-]

As a result, the hydroxide ion concentration in the mixed solution is

9.77 × 10-3 M.

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To determine the pressure of the ammonia gas at a new volume and temperature, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature is equal to the ratio of the final pressure, volume, and temperature.

Using the combined gas law equation: (P1 * V1) / T1 = (P2 * V2) / T2

Given:

P1 = 585 torr (initial pressure)

V1 = 20.0 ml (initial volume)

T1 = 20.0 °C + 273.15 = 293.15 K (initial temperature)

V2 = 50.0 ml (final volume)

T2 = 50.0 °C + 273.15 = 323.15 K (final temperature)

We need to solve for P2 (final pressure).

Rearranging the equation, we have:

P2 = (P1 * V1 * T2) / (V2 * T1)

Substituting the given values into the equation:

P2 = (585 torr * 20.0 ml * 323.15 K) / (50.0 ml * 293.15 K)

Calculating this expression gives us the final pressure (P2) of the ammonia gas at the new volume and temperature.

In summary, using the combined gas law equation, we can determine the pressure of the ammonia gas at a new volume and temperature. By substituting the given values into the equation and performing the calculation, we can find the final pressure of the gas.

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Answer:

2.coefficient how many molecules of Aluminum hydroxide there are

The solution with the lowest solubility of Zn(OH)2 is 1 M Zn(NO3)2 due to the presence of a high concentration of Zn2+ ions causing a common ion effect.

The solubility of Zn(OH)2 would be lowest in a solution with a high concentration of a common ion that can react with the Zn(OH)2 and shift the equilibrium towards the formation of the insoluble compound. Among the given options, the solution with the lowest solubility of Zn(OH)2 would be 1 M Zn(NO3)2.

When Zn(NO3)2 is dissolved in water, it dissociates to form Zn2+ and NO3- ions. The presence of a high concentration of Zn2+ ions in the solution creates a common ion effect, which reduces the solubility of Zn(OH)2. According to Le Chatelier's principle, the equilibrium is shifted in the direction that reduces the concentration of the common ion, in this case, Zn2+ ions. As a result, the solubility of Zn(OH)2 is decreased.

In contrast, solutions such as 1 M HCl, 1 M NaOH, pure water, and 1 M NH3 do not contain a high concentration of Zn2+ ions or any other common ions that can significantly affect the solubility of Zn(OH)2. Therefore, the solubility of Zn(OH)2 would be lowest in 1 M Zn(NO3)2 solution due to the common ion effect.

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Answer:

my sister said is in between b are a so that is what my sister thinks

The correct answer is option (b). The compound that will experience the strongest intermolecular forces is H2O.

It has hydrogen bonding, which is the strongest intermolecular force. The other compounds have weaker intermolecular forces, such as London dispersion forces and dipole-dipole interactions.

To determine which of the following compounds will experience the strongest intermolecular forces, we need to consider their molecular structures and types of forces involved. The compounds listed are:

1. HNNH (hydrazine)
2. H2O (water)
3. H2CCH2 (ethylene)
4. CaO (calcium oxide)
5. MgH2 (magnesium hydride)

Among these compounds, water (H2O) will experience the strongest intermolecular forces due to the presence of hydrogen bonding, which is a stronger type of force compared to the other forces present in the remaining compounds.

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The net cell reaction for the cobalt-silver voltaic cell is: Co(s) + 2Ag+ (aq) → Co2+ (aq) + 2Ag(s). This reaction involves the transfer of electrons from the cobalt electrode (anode) to the silver electrode (cathode), resulting in the oxidation of cobalt and reduction of silver.

The overall cell potential for this reaction is positive, indicating that it is a spontaneous reaction.

The net cell reaction for the cobalt-silver voltaic cell is as follows:

In a cobalt-silver voltaic cell, the half-reactions are:
1. Cobalt oxidation at the anode: Co(s) → Co^2+(aq) + 2e^-
2. Silver reduction at the cathode: Ag^+(aq) + e^- → Ag(s)

To find the net cell reaction, you will need to balance the electrons in both half-reactions:

1. Multiply the silver reduction half-reaction by 2 to balance the electrons:
2Ag^+(aq) + 2e^- → 2Ag(s)

2. Add the balanced half-reactions together:
Co(s) → Co^2+(aq) + 2e^- (anode reaction)
2Ag^+(aq) + 2e^- → 2Ag(s) (cathode reaction)
----------------------------
Net cell reaction: Co(s) + 2Ag^+(aq) → Co^2+(aq) + 2Ag(s)

So, the net cell reaction for the cobalt-silver voltaic cell is Co(s) + 2Ag^+(aq) → Co^2+(aq) + 2Ag(s).

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Silver is the best conductor of electricity. Its main disadvantage is that it tarnishes when exposed to air. the native mineral that is the best conductor of electricity.

The Latin argentum and Sanskrit argunas, both meaning "bright," are where the word "Ag" originates. Even in the Stone Age, silver was used. Silver use dates back at least 5000 years, according to archaeological findings. When aesthetics is crucial, it is utilised for silver dinnerware and jewellery. As the greatest known visible light reflector, silver is utilised to build mirrors, even though it tarnishes with time. Electrical connections, batteries, solder and brazing alloys, dental alloys, and other products also use it.

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The theoretical yield of a reaction is 5.00 moles of potassium permanganate . If the reaction actually produces 616.2 g KMnO₄ ,  the percent yield of the reaction is 78 %.

given that :

the theoretical yield of the reaction = 5 mol

mass of the potassium permanganate = 616.2 g

molar mass of the potassium permanganate = 158 g /mol

moles of the  KMnO₄ = mass / molar mass

                                   = 616.2 / 158

                                   = 3.9 moles

the percent yield = ( experimental yield / theoretical yield ) × 100 %

                              = ( 3.9 / 5 ) ×100 %

                              = 78 %

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To transform a secondary alkyl bromide into an alcohol, one has to use sodium borohydride in the presence of an alcoholic solvent.

An alkyl bromide is an organic molecule containing a bromine atom that is covalently bonded to an alkyl group. It can also be called a haloalkane. They have a general formula of CnH2n+1Br. The most common alkyl bromides are methyl, ethyl, propyl, isopropyl, butyl, sec-butyl, isobutyl, tert-butyl, and pentyl bromide. An alcohol is an organic compound containing one or more hydroxyl (-OH) functional groups that are bonded to a carbon atom. Alcohols with the general formula CnH2n+1OH are named systematically and are considered a homologous series. Methanol, ethanol, propanol, and butanol are some of the most common alcohols.Organolithium reagentOrganolithium compounds are organometallic compounds containing carbon-lithium bonds, and they are useful for a wide range of synthetic applications, including nucleophilic substitution, coupling reactions, and reductions. They are commonly used in organic chemistry for the synthesis of complex molecules. Alkyl and aryl lithium reagents are the most commonly used.What is an alkene?Alkenes are hydrocarbons that contain one or more carbon-carbon double bonds in their chemical structure. They have a general formula of CnH2n, which includes ethene (C2H4), propene (C3H6), and butene (C4H8), among others. They are important building blocks for the synthesis of many chemicals and polymers. The double bond between the carbon atoms is unsaturated and can participate in a variety of chemical reactions.

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Answer: Answer is in the Explanation.

Explanation: At noon the sun is directly above in the sky, the sun's rays are falling on the body making the shadow smaller. While in the evenings and mornings the sun is at a inclined position, so the sun's rays are falling at a inclined position making the body's shadow larger.  

I looked it up on the internet and reworded it as good as I could.

Answer: protons: 92

electrons: 92

1. neutrons: 234-92 = 142

2. Neutrons- 233-92 = 141

3. Neutrons 232-92= 140

Explanation:

Answer:

Salts that produce acidic solutions are acid salts. Neutral salts are those salts that are neither acidic nor basic. Zwitterions contain an anionic and a cationic centre in the same molecule, but are not considered to be salts. Examples of zwitterions include amino acids, many metabolites, peptides, and proteins.

Explanation:

Answer:

123.5 kPa

Explanation:

P2=P1T2/T1

You can check this by knowing that P and T at constant V have a proportional relationship. Hence, this is correct.

The heat energy needed to condense 22.25 grams of nitrogen gas at -195.8°C can be calculated as follows: 4390.125 Joules.

Latent heat is the energy released or absorbed by a material during a change of state (phase change) without causing any temperature change. When a gas changes to a liquid state, the process is called condensation. Thus, the given problem is related to the calculation of the heat needed to condense nitrogen gas at -195.8°C.According to the question, Amount of nitrogen gas = 22.25 grams Latent heat of vaporization of nitrogen = 199.0 J/g As we know that latent heat is the energy required for a substance to change its state without a change in temperature.

The energy required to condense 22.25 grams of nitrogen gas can be determined as follows: Heat energy = (Amount of nitrogen gas) × (Latent heat of vaporization of nitrogen)Heat energy = 22.25 g × 199.0 J/g Heat energy = 4390.125 Joules Thus, the heat energy needed to condense 22.25 grams of nitrogen gas at -195.8°C is 4390.125 Joules.

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Answer:

0.779

Explanation:

Determine the molecular weight of the hydrocarbon. We know that its vapor density is 29, which means that one mole of the hydrocarbon has a mass of 29 grams. Therefore, the molecular weight of the hydrocarbon is 29 g/mol.

Calculate the number of moles of the hydrocarbon. We can use the formula:

moles = mass / molecular weight

Substituting the values, we get:

moles = 29 g / 29 g/mol = 1 mol

Therefore, we have one mole of the hydrocarbon.

Write the balanced chemical equation for the combustion of the hydrocarbon in oxygen. The general equation is:

hydrocarbon + oxygen → carbon dioxide + water

For one mole of the hydrocarbon, we need one mole of oxygen to completely burn it. The balanced equation is:

CnHm + (n+m/4) O2 → n CO2 + m/2 H2O

Calculate the volume of carbon dioxide produced. We know that 1 mole of any gas at STP occupies 22.4 L. Therefore, one mole of carbon dioxide occupies 22.4 L. The volume of 448 ml of carbon dioxide at STP can be converted to liters:

448 ml = 0.448 L

The number of moles of carbon dioxide produced can be calculated using the ideal gas law:

PV = nRT

where P is the pressure (1 atm), V is the volume (0.448 L), n is the number of moles, R is the gas constant (0.0821 L atm/mol K), and T is the temperature (273 K). Substituting the values, we get:

n = PV/RT = (1 atm x 0.448 L) / (0.0821 L atm/mol K x 273 K) = 0.0177 mol

Therefore, 0.0177 moles of carbon dioxide are produced.

Calculate the mass of carbon dioxide produced. We can use the formula:

mass = moles x molecular weight

The molecular weight of carbon dioxide is 44 g/mol. Substituting the values, we get:

mass = 0.0177 mol x 44 g/mol = 0.779 g

Therefore, the mass of carbon dioxide produced is 0.779 grams.

Answer:

All of the above

Explanation:

I chose Option C because a living organism contains DNA and it can reproduce made of cells with membrane bound nucleus.

The bond that is most polar among the given options is C) H-F. The other options have relatively smaller electronegativity differences between the two atoms, resulting in weaker polar bonds.

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The hospital's experimentation with peroral endoscopic myotomy (POEM) filling is part of the tertiary care position.

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The molar mass of the unknown gas is 555.6 g/mol that can be calculated using Grahams' las of effusion.

The molar mass of gas 1= M1

The molar mass of gas 2= M2

As per Graham's law of effusion,

Rate1/Rate2= (M2/M1)1/2

Here, rate 1 is the rate of effusion of the first for the first gas and rate 2 is the rate of effusion for the second gas.

Substituting the given values,

Rate 1= 1.0 L/30 s

Rate 2= 1.0 L/125 s

Then,

[1/30]/[1/125]=(M2/32.0 g/mol)1/2

M2=555.6 g/mol

Therefore, the molar mass of the unknown gas is 555.6 g/mol.

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Answer:

[N2] = 0.3633M

[H2] = 1.090M

[NH3] = 0.2734M

Explanation:

Based on the reaction of the problem, Kc is defined as:

Kc = 0.159 = [NH3]² / [N2] [H2]³

Where [] are the equilibrium concentrations.

The initial concentrations of the reactants is:

N2 = 1.00mol / 2.00L = 0.500M

H2 = 3.00mol / 2.00L = 1.50M

When the equilibrium is reached, the concentrations are:

[N2] = 0.500M - X

[H2] = 1.50M - 3X

[NH3] = 2X

Where X is reaction quotient

Replacing in the Kc equation:

0.159 = [2X]² / [0.500 - X] [1.50 - 3X]³

0.159 = 4X² / 1.6875 - 13.5 X + 40.5 X² - 54 X³ + 27 X⁴

0.268313 - 2.1465 X + 6.4395 X² - 8.586 X³ + 4.293 X⁴ = 4X²

0.268313 - 2.1465 X + 2.4395 X² - 8.586 X³ + 4.293 X⁴ = 0

Solving for X:

X = 0.1367. Right solution.

X = 1.8286. False solution. Produce negative concentrations

Replacing:

[N2] = 0.500M - 0.1367M

[H2] = 1.50M - 3*0.1367M

[NH3] = 2*0.1367M

The equilibrium concentrations are:

The unknown product in the given chemical equation is potassium chloride (KCl).

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and potassium sulfite (\(K_2SO_3\)) is as follows,

\(\[2\text{HCl}(aq) + \text{K}_2\text{SO}_3(aq) \rightarrow \text{H}_2\text{O}(l) + 2\text{KCl}(aq)\]\)

In this reaction, hydrochloric acid (HCl) reacts with potassium sulfite             (\(K_2SO_3\)) to form water  and potassium chloride (KCl). The coefficient 2 in front of HCl indicates that two moles of hydrochloric acid react with one mole of potassium sulfite. The reaction can be understood as follows: the HCl donates a hydrogen ion (H+) to the sulfite ion , forming water and chloride ions (Cl-). At the same time, potassium ions (K+) from the \(K_2SO_3\) dissociate and combine with chloride ions to form potassium chloride (KCl). Overall, the reaction between HCl and \(K_2SO_3\) results in the formation of water and potassium chloride as the unknown product.

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1. The balanced equation for the reaction is:

Cu + I₂ -> CuI₂

2. The percentage yield of the reaction is 68%

1. The balanced equation for the reaction between copper and iodine to produce copper(II) iodide is:

Cu + I₂ -> CuI₂

2. How do I determine the percentage yield?

First, we shall obtain the theoretical yield. This can be obataned as follow:

Cu + I₂ -> CuI₂

From the balanced equation above,

253.8 g of I₂ reacted to produce 317.35 g of CuI₂

Therefore,

57.8 g of I₂ will react to produce = (57.8 × 317.35) / 253.8 = 72.3 g of CuI₂

Now, we shall determine the percentage yield of the reaction. Details below

Percentage yield = (Actual /Theoretical) × 100

Percentage yield of reaction = (49.2 / 72.3) × 100

Percentage yield of reaction = 68%

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