What is your power output while pushing a 10. 0-kg block of steel across a steel table at a steady speed of 2. 00 m/s for 3. 00 s? you push the block with a force of 60. 0 n.

Answers

Answer 1

the power output while pushing a 10.0-kg block of steel across a steel table at a steady speed of 2.00 m/s for 3.00 s with a force of 60.0 N is 120.0 W.

The power output while pushing a 10.0-kg block of steel across a steel table at a steady speed of 2.00 m/s for 3.00 s with a force of 60.0 N can be found using the formula:

P = W / t

where P is power, W is work done and t is time.

Here,

Work done (W) = force × distance moved in the direction of force= force × speed × time= 60.0 N × 2.00 m/s × 3.00 s= 360.0 J

Therefore, Power output = P = W / t= 360.0 J / 3.00 s= 120.0 W

Therefore,

the power output while pushing a 10.0-kg block of steel across a steel table at a steady speed of 2.00 m/s for 3.00 s with a force of 60.0 N is 120.0 W.

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Related Questions

(d) In this question you will be assessed on using good English, organising information clearly and using specialist terms where appropriate. The type of radiation emitted from a radioactive source can be identified by comparing the properties of the radiation to the properties of alpha, beta and gamma radiation. Describe the properties of alpha, beta and gamma radiation in terms of their: • penetration through materials • range in air • deflection in a magnetic field.

Answers

Answer:

Hey!

I did this question and have the answers/potential things you can write!

XD

Explanation:

Here!

structure

•alpha particle consists of a helium nucleus

•alpha particle consists of 2 protons and 2 neutrons

•a beta particle is an electron

•a beta particle comes from the nucleus  

penetration

•alpha particles are very poorly penetrating

•alpha particles can penetrate a few cm in air

•alpha particles are absorbed by skin

•alpha particles are absorbed by thin paper

•beta particles can penetrate several metres of air

•beta particles can pass through thin metal plate / foil

•beta particles can travel further than alpha particles in air

•beta particles can travel further than alpha particles in materials eg metals  

deflection

•alpha particles and beta particles are deflected in opposite directions in an electric field

•beta particles are deflected more than alpha particles

•alpha particles have a greater charge than beta particles but beta particles have much less mass or beta particles have a greater specific charge than alpha particles

Hope this helps!

Sorry if it's a bit too long!

an electron is accelerated from rest across the gap of a capacitor (two parallel plates charged -q and q respectively). a hole in the top plate allows the electron to emerge with a constant velocity of v

Answers

When an electron is accelerated from rest across the gap of a capacitor, it means that it moves from one plate to another. In this case, the two plates are charged with -q and q, respectively.

The electron emerges with a constant velocity of v through a hole in the top plate. The acceleration of the electron can be calculated using the equation: acceleration = change in velocity/time.

The electron is a subatomic particle (denoted by the symbol e or β−) whose electric charge is negative one elementary charge. Electrons belong to the first generation of the lepton particle family and are generally thought to be elementary particles because they have no known components or substructure.

However, without knowing the time it took for the electron to emerge, it is not possible to calculate the exact acceleration.

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What is the distance between two objects if one (a 185,000 kg object) experiences a gravitational force of 0.00200 N due to a 225,000 kg object

Answers

Using the gravitational force, the mass of item 1 and object 2, and the Newton's law of gravity calculator, one may calculate the distance between two objects.

How is gravitational distance determined?

g = GM/r2, where M is the Earth's mass, r is its radius (or the distance from the Earth's center to where you are standing), and G is the gravitational constant. The gravitational constant is G (without the subscripts), while the speed of light is c.

How is the gravitational force between two objects calculated?

By applying Newton's equation, we can accomplish this quite easily: forcegravity is defined as G M m2 separation. Suppose that you weigh 60 kilograms and your colleague weighs 70 kilograms. The center-to-centre distance, r, is 1 m, and the gravitational constant, G, is 6.67 10 -11 newtons square meter kilogram-2.

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orie wants to start her own business making custom furniture. She can purchase a factory that costs $400,000. Korie currently has $500,000 in the bank earning 3 percent interest per year. Refer to Scenario 13-1. Suppose Korie purchases the factory using $200,000 of her own money and $200,000 borrowed from a bank at an interest rate of 6 percent. What is Korie's annual opportunity cost of purchasing the factory

Answers

Korie's annual opportunity cost of purchasing the factory is $6,000.

To calculate Korie's annual opportunity cost of purchasing the factory, we need to consider the interest she could have earned on the $200,000 she used to purchase the factory. This interest is the opportunity cost.

Korie currently has $500,000 in the bank earning 3 percent interest per year. If she uses $200,000 of her own money to purchase the factory, she forfeits the opportunity to earn interest on that amount.

The annual opportunity cost can be calculated as:

Opportunity cost = Amount invested * Interest rate

Opportunity cost = $200,000 * 3% = $6,000

Therefore, Korie's annual opportunity cost of purchasing the factory is $6,000.

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Antonina throws a coin straight up from a height of 1.2m above the water surface in a fountain. The coin strikes the water 1.3s later. We want to know the vertical velocity of the coin at the moment it strikes the water. We can ignore air resistance.
Which kinematic formula would be most useful to solve for the target unknown?

Answers

Answer: v=1,56(m/s)

Explanation: Called: g(Gravity acceleration) =10\(m/s^{2} \\\)(or 9,8\(m/s^{2}\))

                                 h=1,2m  ;   t=1,3s

Because the coin fell freely, the velocity is calculated by the formula:

v=\(\sqrt{2gh}\)  (1)

besides, you have time to touch the bottom of the water is 1,3s:

t=\(\sqrt\frac{2g}{h} }\) (2)

(1) and (2) => v=1,56 (m/s)

As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.

Answers

As a freely falling object picks up downward speed, then the power supplied by gravitational force will increase.

We know that Power = work done /time

Power = W ×t and work = Force × displacement.

W= F(d) = F× speed/time (distance = speed /time)

So, if we increase the speed then work done will also increase, eventually it increases the power.

The longer an object is in free fall, the faster it falls toward the ground due to gravity. means it depend on the mass of object.

A falling object accelerates as it falls downward rapidly. The quantity of air resistance rises in proportion to the speed. The pull of gravity eventually is balanced by the force of air resistance as it grows. The item will cease accelerating since there is no net force at this point in time 0 newton.

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why doesn't the repulsive electric force of protons in the atomic nucleus cause the protons to fly apart?

Answers

The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons.

The repulsive electric force of protons in the atomic nucleus does not cause the protons to fly apart because of the strong nuclear force. The strong nuclear force is an attractive force between nucleons that overcomes the repulsion between protons due to the electromagnetic force. This force is responsible for holding the nucleus of an atom together.

We will explain the physics behind why the strong nuclear force overcomes the repulsive electric force. The protons in the nucleus are positively charged and would normally repel each other due to the electrostatic force. The reason why they do not is because they are held together by a stronger force, the strong nuclear force. This force acts between nucleons, which are particles found in the nucleus of an atom. The strong nuclear force is a short-range force that acts over distances of less than a femtometer. It is much stronger than the electrostatic force, which is why it is able to hold the nucleus together. The reason for this is that the strong nuclear force is mediated by particles called mesons, which are much heavier than electrons and photons. The strong force is able to overcome the repulsion between protons because it is much stronger than the electromagnetic force, which is what causes the repulsion in the first place.

The strong nuclear force overcomes the repulsive electric force of protons in the atomic nucleus because it is a much stronger force. It is able to act over very short distances and is mediated by particles that are much heavier than electrons and photons. This force is responsible for holding the nucleus of an atom together and is what allows for the existence of matter as we know it.

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A wave has a wavelength of 45 meters and a period of 9.0 seconds. What is the frequency of the wave?
405 Hz
5.0 Hz
5.0 m/s
0.11 Hz

Answers

Answer:405

Explanation:Multiply 45x9.0=405

Answer:

405 Hz

Explanation:

Give the person on top Brainly

A U-Shaped tube of constant cross-sectional area contains water of density 1000kg/m cubed. Bothe side of the tube are open to the atmosphere. The atmospheric pressure is 1. 00 x 10 to the power of 5. The left hand side is now connected to a gas supply using a length of rubber tubing. This causes the level of the water in the left hand side to drop by 0. 200m. Calculate the pressure of the gas supply. Give your answer to 3 significant figures

Answers

Answer:

If the water in the left side drops .2 m then the water on the right side rises by .2 m

The pressure on the gas is due to the height difference of the water on the two sides.

P = ρ g h

ρ g = 9.8 m/s^2 * 1000 kg / m^3 = 9800 N/m^3      weight density of water

P = 9800 N/m^3 * .4 m = 3920 N / m^2 = 3.92E3 N/m^2

Absolute pressure of gas = 3.92E3 / 1.01E5 = .0388 atmosphere

A solution which has a solid solute is saturated at 25°C. It is then heated to 35°C. There is no change in the appearance of the solution. What term would now be associated with this solution?

A.
unsaturated

B.
saturated

C.
oversaturated

D.
supersaturated






Answers

Answer:

C. oversaturated

Explanation:

Sana nakatulong

2A 5-kilogram rocket is projected upward from rest by an engine/applied force equivalent to 80-Newtons. After firing for 4-seconds the engine turns off. A. Draw and label all of the forces acting on the rocket at each of the intervals shown above. B. Determine the initial upward acceleration of the rocket during the first 4-seconds.

Answers

Answer:

(A). The force acting on the rocket is mg.

(B). The initial upward acceleration of the rocket is 6.2 m/s²

Explanation:

Given that,

Mass of rocket = 5 kg

Force = 80 N

Time = 4 sec

(A). We need to draw the figure

The force acting on the rocket at each of the intervals is shown in figure.

The force acting on the rocket is mg.

(B). We need to calculate the initial upward acceleration of the rocket

Using balance equation

\(ma=F-mg\)

\(a=\dfrac{F-mg}{m}\)

Put the value in the equation

\(a=\dfrac{80-5\times9.8}{5}\)

\(a=6.2\ m/s^2\)

Hence, (A). The force acting on the rocket is mg.

(B). The initial upward acceleration of the rocket is 6.2 m/s²

2A 5-kilogram rocket is projected upward from rest by an engine/applied force equivalent to 80-Newtons.

What information is given by the formula H2O2?

Answers

Answer:

it is hydrogen peroxide

what is the maximum wind velocity for a 30° crosswind if the maximum crosswind component for the airplane is 15 knots?

Answers

The maximum wind velocity for a 30° crosswind with a maximum crosswind component of 15 knots is 30 knots.

To determine the maximum wind velocity for a 30° crosswind when the maximum crosswind component for the airplane is 15 knots, follow these steps:

1. Identify the maximum crosswind component: 15 knots.
2. Determine the crosswind angle: 30°.
3. Use the formula: Wind velocity = Maximum crosswind component / sin(crosswind angle).

In this case:

Wind velocity = 15 knots / sin(30°)

The sine of 30° is 0.5, so:

Wind velocity = 15 knots / 0.5

Wind velocity = 30 knots

So, the maximum wind velocity for a 30° crosswind with a maximum crosswind component of 15 knots is 30 knots.

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what are effects of high gravity on blood pressure, blood circulatory system, size of lungs, bone fragility and density​

Answers

Answer:

Explanation:

On return to Earth, gravity once again “pulls” the blood and fluids into the abdomen and legs. The loss of blood volume, combined with atrophy of the heart and blood vessels that can occur in space, reduces the ability to regulate a drop in blood pressure that happens when we stand on Earth.

I will give Brainliest answer and 5 stars
Jay decides to walk home from school today. He lives 3 miles from school and can walk home in 45 minutes. At what rate is Jay traveling?
A. 1 mile/10 minutes
B. 1 mile/15 minutes
C. 1 mile/20 minutes
D. 1 mile/30 minutes

Answers

Answer:

James is traveling at 4 miles per hour.

Explanation:

3 miles per 45 minutes

x miles per 60 minutes(1 hour)

___________________

3*60=45*x

180=45x |:45

x=4

What would it take to get the stone slab to move? Propose an
idea and explain how it would work in the context of Newton's
laws.

Answers

In order to get a stone slab to move, one would have to apply force to it. This can be done in a number of ways, depending on the situation. Here are a few possible laws that could be proposed for moving a stone slab:1. Newton's first law of motion: This law states that an object at rest will stay at rest unless acted upon by an external force. Therefore, to move a stone slab, one would need to apply a force to it.

This could be done by pushing it, pulling it, or applying a force from a lever or other mechanical device. Newton's second law of motion: This law states that the force required to accelerate an object is directly proportional to its mass. Therefore, to move a stone slab, a greater force would be required if it is more massive. This could be accomplished by using more people to push or pull the slab, or by using a larger lever or other mechanical device.. Friction: Friction is the force that opposes motion between two surfaces that are in contact with each other. In order to move a stone slab, one would need to overcome the friction between it and the surface it is resting on. This could be accomplished by reducing the friction (for example, by using rollers or lubricant), or by applying a greater force to overcome the friction.Work: Work is defined as the product of force and distance. Therefore, in order to move a stone slab, one would need to apply a force over a certain distance.This could be accomplished by pushing or pulling the slab over a distance, or by using a lever or other mechanical device to apply force over a greater distance.These are just a few possible laws that could be proposed for moving a stone slab. Ultimately, the best approach will depend on the specific situation and the resources available.

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I need help with these questions

I need help with these questions

Answers

The velocity of the papaya is 20.98 m/s.

The gravitation potential energy of the spoon is 0.735 J.

The elastic potential energy of the spring is  0.0065 J.

What is the velocity of the papaya?

The velocity of the papaya is calculated by applying the formula for kinetic energy as shown below;

K.E = ¹/₂mv²

where;

m is the mass of the papayav is the velocity of the papaya

v² = 2K.E/m

v = √(2k.E/m)

v = √(2 x 110 / 0.5)

v = 20.98 m/s

The gravitation potential energy of the spoon is calculated by applying the formula for potential energy.

P.E = mgh

where;

m is mass of the spoonh is the height through which the spoon is liftedg is acceleration due to gravity

P.E = 0.05 x 9.8 x 1.5

P.E = 0.735 J

The elastic potential energy of the spring is calculated as follows;

U = ¹/₂kx²

where;

k is spring constantx is the extension of the spring

U = ¹/₂(5.2)(0.05²)

U = 0.0065 J

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The factors associated with the motion of an object are Force, Velocity, and
Acceleration. Out of these four factors which one remains constant for all bodies (large
or small) undergoing a free fall?

Answers

Answer:

there is one missing the height of where the object is dropped from. the height is what stays constant

A load cell is used to measure the weight of an object. The load cell is rated for 35kg. If the cell has an output range of 0-5V, what is theresolution?A. 0.250 kg/VB. 7.0 kg/VC. 31.25 kg/VD. 0.977 kg/V

Answers

B. 7.0 kg. resolution Is 35/5=7 kg/v, output voltage = 15.4/7 = 2.2 volts.

How is the capacity of a load cell determined?

The voltage input to the strain gauge and the ’s rated RO can be used to compute the output voltages from the load cell.The output voltage of a load cell with a 500 g (estimated capacity) load is VE * Rh = 2.0 V * 0.7 volt = 1.4 mV.

What is class 10's lowest count?

The smallest precise value inside the measured amount that may be recognized on the scale of the instrument is known as the least count.The instrument's precision is impacted by the least count.Range is essentially the difference between the highest and lowest values.

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WILL MARK THE HIGHEST

What elemental trend exists as we move down a column on the periodic table?

Answers

Answer:DOWN a Group: Atomic radius INCREASES as you go DOWN a Group because each successive Period (row) has an additional occupied energy level. If you visualize the not 100% accurate but still useful Bohr model of the atom, you can think of it this way: each time you drop down a row, you add a "ring." ACROSS a Period: Atomic radius DECREASES as you go ACROSS a Period because the net nuclear charge increases (Huh?). Remember, it's the protons (+) in the nucleus that pull on or attract the electrons in the orbitals. Across a Period you are adding more and more protons pulling on electrons occupying the same orbitals. The overall effect is more pulling power in the same basic space. This draws the electrons in closer, making the overall atomic radius smaller at the right side of a Period.

Ionization Energy:

DOWN a Group: Ionization energy DECREASES as you go DOWN a Group because the farther the valence electrons are from the nucleus (pulling power of the protons) the less energy it costs another atom to steal them. ACROSS a Period: Ionization energy INCREASES as you go ACROSS a Period because atoms are getting ever closer to that magic "octet" rule for stability via the Noble Gas configuration. In plain speak - your frequent buyer punch card gets one step closer to the freebie each time you move closer to the right of the Periodic Table so you guard those punches more carefully. The atomic radius is getting smaller, too, so those protons do a great job of holding on tighter.

Electron Affinity:

Electron affinity is a bit outside the scope of this class so I'm not going to get into it too deeply, other than to point out the general trend.

DOWN a Group: Electron Affinity DECREASES (a tiny bit) as you go DOWN a Group because elements become slightly less attractive toward electrons. Father from the pull of those protons, remember?  ACROSS a Period: Electron Affinity INCREASES as you go ACROSS a Period because generally speaking (and remember, exclude the Noble Gases here) elements toward the right of the Periodic Table give off a great deal of energy when they gaining electrons to become more stable.

Electronegativity:

DOWN a Group: Electronegativity DECREASES as you go DOWN a Group because the valence electrons are increasingly farther away from the attraction of the protons in the nucleus. Less pull, less "desire" to grab other electrons. ACROSS a Period: Electronegativity INCREASES as you go ACROSS a Period because the number of protons (+ charges) in the nucleus increases. More protons in the nucleus means electrons are more strongly attracted to the nucleus.

Chemical Reactivity:

METALS

DOWN a Group: In METALS reactivity INCREASES as you go DOWN a Group because the farther down a Group of metals you go, the easier it is for electrons to be given or taken away, resulting in higher reactivity. ACROSS a Period: In METALS reactivity DECREASES as you go ACROSS a Period because though they still want to give away valence electrons they have more of them to get rid of, which requires more energy. Not as easy to blow off a little steam!

I can't help it, I just love this video on reactivity (however embellished the reactions) down the Alkali Metals. Top Gear (BBC) fans will recognize Richard "Hamster" Hammond as the narrator here. Enjoy!

Explanation:

Match the volcano type with its correct plate tectonic setting Cinder Cone Composite (Stratovolcano) Shield Volcano Large Igneous Provinces (LIPS) Seafloor Volcanism Question 24 [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] [Choose ] Mostly Spreading Ridges, some Mantle Plumes Super mantle plumes Various tectonic settings Subduction Zones (Convergent Margins) Mostly Mantle Plumes, some Spreading Ridges Match the volcano type with its correct magma composition Cinder Cone Composite/Stratovolcano Shield Volcano Large Igneous Provinces (LIPs) Seafloor Volcanism [Choose ] [Choose ] Mafic Intermediate, varies from felsic to mafic Pillow Lava, Mafic [Choose ] [Choose ] [Choose ]

Answers

Match the volcano type with its correct

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Volcano types can be associated with specific plate tectonic settings and magma compositions. Let's match the volcano types with their correct plate tectonic settings and magma compositions:

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

Magma Composition: Mafic

Cinder cones are typically small, steep-sided volcanoes that form from the eruption of basaltic magma. They are commonly found in volcanic regions associated with spreading ridges, where tectonic plates are moving apart, or in areas influenced by mantle plumes, such as hotspot volcanism.

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

Magma Composition: Intermediate, varies from felsic to mafic

Composite or stratovolcanoes are characterized by their steep slopes and alternating layers of lava flows and pyroclastic materials. They are commonly found in subduction zones, where an oceanic plate is being subducted beneath  continental plate. The magma composition of these volcanoes varies, ranging from felsic (high silica content) to mafic (lower silica content).

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

Magma Composition: Mafic

Shield volcanoes are large, broad, and gently sloping volcanoes that form from the eruption of basaltic magma. They are often associated with mantle plumes, such as those found in hotspot regions, as well as in volcanic areas influenced by spreading ridges.

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Magma Composition: Mafic

Large Igneous Provinces (LIPs) are extensive regions of volcanic and intrusive rock formations that are associated with massive outpourings of mafic magma. They can occur in various tectonic settings, including continental rifts, hotspot regions, and flood basalt provinces.

5. Seafloor Volcanism, Pillow Lava:

Plate Tectonic Setting: Mostly Spreading Ridges

Magma Composition: Mafic

Seafloor volcanism is primarily associated with spreading ridges, where magma wells up and creates new oceanic crust. The lava erupted underwater cools rapidly, forming pillow-shaped structures known as pillow lavas. The magma composition is typically mafic, dominated by basaltic lavas.

These associations between volcano types, plate tectonic settings, and magma compositions provide insights into the geological processes and Earth's dynamics that shape the Earth's surface.

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pls help me fast and correct ​

pls help me fast and correct

Answers

Answer:

A

Explanation:

due to position at height is the answer

you are sliding a sofa across a horizontal floor to rearrange your living room. assume you are pushing with a horizontal force of 486.99 n, the sofa weighs 83.47 kg, and the coefficient of kinetic friction is 0.23 . calculate the magnitude of the acceleration of the sofa in units of m/s2, and round it to two decimal places.

Answers

To calculate the magnitude of the acceleration of the sofa in units of m/s2, we need to use Newton's Second Law of Motion, which states that the force acting on an object is equal to the mass of the object times its acceleration, F = ma.

We also need to account for the force of friction, which opposes the motion of the sofa and is equal to the coefficient of kinetic friction times the normal force, or Ff = μkFN.

Since the sofa is sliding across a horizontal floor, the normal force is equal to the weight of the sofa, or FN = mg. Therefore, the force of friction is Ff = μkmg.

Now we can plug in the given values and solve for the acceleration of the sofa:

F - Ff = ma

486.99 N - (0.23)(83.47 kg)(9.8 m/s2) = (83.47 kg)a

Solving for a, we get:

a = (486.99 N - (0.23)(83.47 kg)(9.8 m/s2))/(83.47 kg)

a = 3.82 m/s2

Rounding to two decimal places, the magnitude of the acceleration of the sofa is 3.82 m/s2.

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solid are _______, usually in a regular repeating pattern

Answers

Answer:

particles or arranged will be the answer depending on the previous line.

Answer:

Solids are crystalline , usually in a regular repeating pattern.

Having landed on a newly discovered planet,
an astronaut sets up a simple pendulum of
length 1.04 m and finds that it makes 475
complete oscillations in 1320 s. The amplitude of the oscillations is very small compared
to the pendulum’s length.
What is the gravitational acceleration on
the surface of this planet?
Answer in units of m/s^2.

Answers

Answer:

17.215 m/s^2

Explanation:

L = 0.825 m

It completes 397 oscillations in 546 s.

Time period is defined as the time taken to complete one oscillation.

So, Time period, T = 546 / 397 = 1.375 s

Let g be the gravitational acceleration at that planet.

Use the formula for the time period

g = 17.215 m/s^2

What is the weight of a person on the Moon who has a mass of 68.5 kg? (gMoon=1.6 N/kg)

Answers

Answer:

The weight of a person with a mass of 68.5 kg on the Moon is 109.6 N.

Explanation:

To find the weight of a person on the Moon, we need to use the formula:

Weight = Mass x Gravitational Force

On the Moon, the gravitational force is 1.6 N/kg. So, using that information:

Weight = 68.5 kg x 1.6 N/kg = 109.6 N

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if an object is in free fall it will experience air which generates a drag force

Answers

is this a trure/false? if it is then it is true

What type of gaussian surface is best to determine the electric field from a large (ignore edge effects) sheet of charge?A. A box either above or below the sheet. B. A box that straddles the sheet of charge C. A sphere either above or below the sheet. D. A sphere that straddles the sheet of charge E. A cylinder either above or below the sheet.

Answers

The easiest way to extract the electric field from a big sheet of charge is to use a cylindrical gaussian surface. The correct option is E.

The easiest way to extract the electric field from a big sheet of charge is to use a cylindrical Gaussian surface. Calculating the flux through the surface is simple since the cylinder-shaped surface encloses the sheet of charge and the electric field lines are parallel to the axis of the cylinder.

The symmetry of the cylindrical surface also makes it simple to calculate the electric field. If the cylindrical Gaussian surface is selected to be sufficiently big in comparison to the size of the sheet, the edge effects can be disregarded. Charges and their arrangements, such as in capacitors and battery cells, produce electric fields.

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A steel ball is released just below the surface of thick oil in a cylinder.
During the first few centimetres of travel, what is the acceleration of the ball?
A constant and equal to 10 m / s2
B constant but less than 10 m / s2
C decreasing
D increasing

Answers

Answer:

Increasing

Explanation:

I Hope it Helps

How do genetics connect to the human body?

Answers

They make a person up with specific eye color hair color skin color etc
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A cost that does not change with changes in volume of activity is called a _____ cost. multiple choice fixed variable mixed step-wise curvilinear give an order of magnitude estimate for the ratio of the electric force between two electrons 1 m apart If the given side lengths of a triangle are 16 and 10 which can NOT be the third side?A.21B.22C.25D.27 A company has an ROE of 12.63%. If the asset turnover ratio is 2.0 and the financial leverage ratio is 1.5, what is the return on sales Based upon research about marital relationships conducted by gottman, what feature of a relationship best predicts the demise of a relationship? by default, the fact table's primary key is always formed by combining the superkeys pointing to the dimension tables to which they are related. true or false? Find X : X/2 = 1X=1/2X=-2X=1X=2 Question: Which expression is undefined in the set of real numbers? A -4 B 0/-4 0-4 D - 4x0 Compare the masses of a one-liter sample of hydrogen and a one-liter sample of helium gas, each at 25C and 5.0 atm pressure.I will mark brainliest if right!!A) the helium gas has twice the mass of the hydrogen gasB) the helium gas has four times the mass of the hydrogen gasC) the hydrogen gas has twice the mass of the helium gasD) the hydrogen gas has four times the mass of the helium gasE) the mass of the hydrogen gas equals the mass of the helium gas Question is down below. No wrong ANSWER YOU WILL BE REPORTED TROLLS!! Point A is at (-6,8) and point M is at (0,0.5).Point M is the midpoint of point A and point B.What are the coordinates of point B? Please help! Dean's car can travel 21 miles on a gallon of gas. If his gas tank holds 15 gallons, how far can he travel on a full tank of gas? Explain how you got your answer. You are sitting in a bus in a depot, when suddenly you see in the window the bus next to yours start to move forward. List two scenarios that could be happening What was the first step when solving the equation below for x3x - 0.1 = 2.2A. subtract 0.1 from both sides of the equation.B.divide each side equation by 3.C.Add 0.1 to both sides of the equation.D.Add 2.2 to both sides of the equation. Elephant -Bird-fish-sheep-Book paper order from the biggest mass to the smaller In cumulene, what are the c-c-c and h-c-h bond angles, respectively? Read the excerpt from a text about online learning. "Virtual schools were growing quite quickly," said Christina Martin, a policy analyst at the Cascade Policy Institute, a free-market think tank based in Portland, Ore. . . . The big issue, she said, was fairness. Some students have access to virtual schools because they have a learning coach to stay home with them, while others dont. Also, Internet connections can be costly, and not every family has one. And families have to pay for their own printing. . . . "An adult must stay with a child during the day and make sure theyre doing their work. " This information would best support a claim about students need for personal coaches. Internet supervision. High-tech gadgets. Equal access to technology. kaye company acquired 100% of fiore company on january 1, 2021. kaye paid $1,000 excess consideration over book value, which is being amortized at $20 per year. there was no goodwill in the combination. fiore reported net income of $400 in 2021 and paid dividends of $100. assume the equity method is applied. how much equity income will kaye report on its internal accounting records as a result of fiore's operations? A2 kg object moves at a constant 5 m/s across a level surface. Determine its kinetic energy. 83736 with work ok