What is:
2 + | -5 + 4 |

Answer:

I think it's 6 or 0.6

Answer:

is -15x+102 I belive. hope I helped!!! :D

Answer:

Group A has less variability in the data.

Step-by-step explanation:

Examining the data for both groups virtually as represented on the dot plot, we can easily tell that the data in group A are less spread compared to group B data.

Group A has a range value of 10 (14 - 4), while group B has a range value of 19 (26 - 7).

Therefore, "Group A has less variability in the data."

Answer:

+When the graph is below the x-axis, the barnacle is underwater.

+The graph dips below the x-axis three times between x = 0 and x = 20, so the barnacle goes underwater three times.

+Every time the barnacle goes underwater, the boat travels pi meters (one half the circumference of the wheel) before the barnacle comes back up, so the barnacle covers 3pi  meters underwater between x = 0 and x = 20

Step-by-step explanation:

To determine the number of times that the times the barnacle went beneath the water level, it can be illustrated when the graph is below the x-axis.

It should be noted that the graph dips below the x-axis three times between x = 0 and x = 20, therefore the barnacle goes underwater three times.

Also, every time the barnacle goes underwater, the boat travels pi meters before the barnacle comes back up.

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Answer:

12°

Step-by-step explanation:

it is a ratio let represent by x

6x+5x+4x=180

15x=180

x=12°

Exponential smoothing is a popular forecasting technique used to predict future trends in time-series data. It works by assigning weights to historical data points, with more recent data points receiving higher weights. The level of smoothing is controlled by a smoothing parameter called alpha, which ranges between 0 and 1. As alpha increases, the influence of older data points decreases, and the model becomes more reactive to recent changes in the data.

When alpha is high, the exponential smoothing model group of answer choices tends to produce sluggish forecasts. This is because the model gives more weight to recent data points, which can cause it to overreact to short-term fluctuations in the data. As a result, the model may miss important trends or patterns in the data that would have been captured by a more balanced weighting scheme.

On the other hand, when alpha is low, the model tends to be more stable and less reactive to short-term changes in the data. This can be useful for predicting long-term trends or for smoothing out noisy data sets.

In summary, the choice of alpha in an exponential smoothing model depends on the characteristics of the data and the goals of the forecast. A high alpha value may be appropriate for short-term forecasting or for data sets with high volatility, while a low alpha value may be more suitable for long-term forecasting or for data sets with low volatility.

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Answer:

i believe it is skewed. sorry if its wrong

Step-by-step explanation:

Based on the given diagram, we can estimate the area of the pond to be approximately 720 square feet, which is an option (B).In the given diagram, each unit on the coordinate plane represents 20 feet. The pond is represented by the shaded region in the diagram.

We can estimate the area of the pond by counting the number of squares inside the shaded region and then multiplying that number by the area of each square.

From the diagram, we can count 18 full squares and 4 half squares inside the shaded region. Each full square has an area of 20 x 20 = 400 square feet, and each half square has an area of 20 x 10 = 200 square feet. Therefore, the total area of the pond is approximately:

18 x 400 + 4 x 200 = 7200 + 800 = 8000 square feet

However, we need to keep in mind that this is only an estimate since we cannot determine the exact boundaries of the pond from the given diagram. Therefore, the best estimate of the area of the pond is 720 square feet, which is an option (B) in the given options.

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Answer:

Step-by-step explanation:

find the area of ​​the big rectangle and add the double area of ​​a triangle, they are the same so it is as if you have the area of ​​both

[(4+4+4)*5] + (4*3.5)=

8 * 5 + 14 =

40 + 14 =

51m²

The probability of the event {E} - "picking a 5 and then picking a number less than 7 is P{E} = 0.58.

Probability of an event indicates how likely that event is going to happen. It is in range between 0 and 1.

Given is that You pick a card at random. Without putting the first card back, you pick a second card at random.

We can write the probability of the event {E} - "picking a 5 and then picking a number less than 7" as -

P{E} = 1/4 + 1/3

P{E} = 0.25 + 0.33

P{E} = 0.58

Therefore, the probability of the event {E} - "picking a 5 and then picking a number less than 7 is P{E} = 0.58.

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1. When the population mean shifts to 7.8, the probability of detecting the change is approximately 0.0495 (or 4.95%).

2.  The probability of detecting the change is 0.0495 or 4.95%.

To solve this problem, we'll use the concept of control limits and the sampling distribution of the sample means.

When the population mean shifts to 7.8: First, let's calculate the standard deviation of the sampling distribution, also known as the standard error (SE). The formula for SE is given by SE = σ / sqrt(n), where σ is the standard deviation of the population (1.0 ounce) and n is the sample size (47).

SE = 1.0 / sqrt(47) ≈ 0.145

Next, we need to determine the z-score corresponding to the lower and upper tails of the sampling distribution that capture 5% each. Since the total probability in both tails is 10%, each tail will have a probability of 5%. We can find the z-scores using a standard normal distribution table or calculator.

The z-score corresponding to the lower tail of 5% is approximately -1.645.

The z-score corresponding to the upper tail of 5% is approximately 1.645.

Now, let's calculate the lower and upper control limits:

Lower Control Limit (LCL) = Population Mean - (z * SE)

Upper Control Limit (UCL) = Population Mean + (z * SE)

LCL = 7.8 - (-1.645 * 0.145) ≈ 8.026

UCL = 7.8 + (1.645 * 0.145) ≈ 9.574

To find the probability of detecting the change, we need to calculate the area under the sampling distribution curve that falls beyond the control limits. In this case, we're interested in the area above the upper control limit.

Since the distribution is assumed to be normal, we can use the standard normal distribution's cumulative distribution function (CDF) to calculate this probability.

Probability of detecting the change = 1 - CDF(z-score for UCL)

Using the z-score for the upper control limit (UCL), we can calculate the probability.

Probability of detecting the change ≈ 1 - CDF(1.645) ≈ 0.0495

Therefore, when the population mean shifts to 7.8, the probability of detecting the change is approximately 0.0495 (or 4.95%).

When the population mean shifts to 8.6: We'll follow the same steps as before.

SE = 1.0 / sqrt(47) ≈ 0.145

The z-score corresponding to the lower tail of 5% is still approximately -1.645.

The z-score corresponding to the upper tail of 5% is still approximately 1.645.

LCL = 8.6 - (-1.645 * 0.145) ≈ 8.926

UCL = 8.6 + (1.645 * 0.145) ≈ 10.274

Probability of detecting the change = 1 - CDF(z-score for UCL)

Probability of detecting the change ≈ 1 - CDF(1.645) ≈ 0.0495

Therefore, when the population mean shifts to 8.6, the probability of detecting the change is also approximately 0.0495 (or 4.95%).

In both cases, the probability of detecting the change is 0.0495 or 4.95%.

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Equations may be converted from Cartesian to polar coordinates because the two coordinate systems are equal.

Cartesian and polar coordinates are two different systems used to represent points in a two-dimensional space. In the Cartesian coordinate system, points are located using x and y coordinates, whereas in the polar coordinate system, points are located using a distance from the origin (r) and an angle (θ).

Although the two coordinate systems are different in their representation, they are mathematically equivalent. This means that any point in a Cartesian coordinate system can be uniquely represented in a polar coordinate system, and vice versa.

The conversion between Cartesian and polar coordinates involves applying certain formulas and trigonometric relationships to relate the coordinates in both systems.

By converting equations from Cartesian to polar coordinates, we can express mathematical relationships and functions in a different form that may be more suitable for certain applications. It allows us to explore and analyze mathematical concepts from a different perspective and can simplify calculations in some cases.

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Answer:

a=54 b=57 AB=246. This is the best answer ever!!!

Answer:The area A of a rectangle is represented by the formula A=lw where l is the length and w is the width. The length of the rectangle is 5.

Write an equation that makes it easy to find the width of the rectangle if we know the area and the length.

Step-by-step explanation:

Answer:

The number added to -2 that makes the answer -8 is -6.

Step-by-step explanation:

To solve this problem, we need to write an equation.

\(-2+x=-8\)

Now, we solve the equation.

\(-2+2+x=-8+2\)

Negative two plus two is 0, so that cancels out.  X is the only value left.  To find -8 plus 2, you would move two spaces (on a number line) to the right, towards the positive side.

\(x=-6\)

The mass of the pencil is approximately 5.49 ounces.

To find the mass of the pencil, we can integrate the density function over the length of the pencil.

The density function is given by rho(x) = 5/x oz/in.

We want to find the mass of the pencil, so we integrate the density function from x = 2 (the starting point of the pencil) to x = 6 (the endpoint of the pencil).

The integral is ∫[2, 6] (5/x) dx.

Evaluating the integral, we have:

∫[2, 6] (5/x) dx = 5 ln(x) ∣[2, 6] = 5 ln(6) - 5 ln(2) = 5 (ln(6) - ln(2)).

Using the property of logarithms, we can simplify this to:

5 ln(6/2) = 5 ln(3) ≈ 5 (1.098) ≈ 5.49 oz.

The mass of the pencil is approximately 5.49 ounces.

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3588.3 thats the answer

Answer:

x=-2

Step-by-step explanation:

-8-4=

-4

there the x value since there two x so u divide 2x=-4

×=-2

a. The number of students taking both math and science is 8.

b. The number of students taking English only is 10.

In order to find the solution, we can use a Venn diagram to represent the information given. Let's consider three overlapping circles representing math, science, and English.

From the given information:

8 students take both math and science (intersection of math and science).

5 students take science only (outside math but inside science).

12 students take English and math (intersection of English and math).

2 students take all three subjects (intersection of math, science, and English).

27 students take math (total in the math circle).

36 students take math or science (total in the combined math and science circles).

32 students take English or science (total in the combined English and science circles).

Using this information, we can solve for the missing values in the Venn diagram:

The number of students taking math only can be calculated as (total math - students in math and science - students in English and math + students in all three subjects) = 27 - 8 - 12 + 2 = 9.

The number of students taking English only can be calculated as (total in English and science circles - students in English and math + students in all three subjects) = 32 - 12 + 2 = 22.

Therefore, the solution is:

a. 8 students take both math and science.

b. 22 students take English only.

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Answer:

d

Step-by-step explanation:

The probability that the dart lands within the dartboard given the area of the dartboard and the square is 78.6%.

Probability is the odds that an event would happen. The odds the event occurs is 1 and the probability that the event does not occur is 0.

The probability that the dart lands within the dartboard = area of the dartboard / area of the square

25π / 100

(25 x 3.14) / 100 = 78.6%

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Answer:78.5 is the answer

Step-by-step explanation:

The probability that at least one of the four selected calculators is defective is approximately 0.7775, or 77.75%.

To find the probability that at least one of the selected calculators is defective, we can use the concept of complementary probability. We calculate the probability of none of the selected calculators being defective and subtract it from 1.

The total number of calculators in the group is 20 (defective) + 29 (no defects) = 49 calculators.

The probability of selecting a non-defective calculator in one draw is 29/49. Therefore, the probability of selecting four non-defective calculators in a row is (29/49)^4.

To find the probability of at least one defective calculator, we subtract the probability of none being defective from 1:

P(at least one defective) = 1 - P(none defective)

                       = 1 - (29/49)^4

Using this formula, we can calculate the probability.

P(at least one defective) ≈ 1 - (29/49)^4 ≈ 1 - 0.2225 ≈ 0.7775

Therefore, the probability that at least one of the four selected calculators is defective is approximately 0.7775, or 77.75%.

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Answer:

Answers below

Step-by-step explanation:

Radius = 3m

Diameter:

d = 2r

d = 2(3m)

d = 6m

Circumference:

c = 2πr

c = 2π(3m)

c = 6π m

c = 18.85 m

Area:

A = 2πr^2

A = 2π(3m)^2

A = 18π m^2

A = 56.55 m^2

Please mark brainliest if this helped

Please mark brainliest if this helped

The ratio of 17 out of 20, as a percent, would be: 85%.

To convert or represent a given ratio as a percent, follow the steps below:

1. Use the second number to divide the first number

2. To convert the ratio to percentage, multiply what you get in step 1 by 100.

3. Include the percent sign "%".

Thus, to convert or represent the ratio of 17 out of 20 as a percent, we have the following steps:

Step 1: 17/20 = 0.85

Step 2: 0.85 × 100 = 85

Step 3: 85%

Therefore, the ratio of 17 out of 20, as a percent, would be: 85%.

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Answer:

1/2

Step-by-step explanation:

The formula for slope is \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

9-6=3

8-2=6

3/6=1/2

Answer:

$200. had to edit, read the question wrong originally

=======================================================

Work Shown:

If you save 64%, then you still have to pay the remaining 100% - 64% = 36%

x = original price in dollars

sale price = 36% of x = 0.36*x = 72

0.36*x = 72

x = 72/0.36

x = 200

The original price is $200

discount = 64% of 200 = 0.64*200 = 128

You save $128

The amount you pay is 200-128 = 72 dollars, which matches with the given sale price.

Answer:

slope intercept form of a line is

y = mx+b

where m is the slope and b is the y intercept

y=2x-5

2 is the slope and -5 is the y-intercept

Step-by-step explanation:

Check the picture below.

1) The amplitude c+ is c+l

2) The expectation value is 0

3) The uncertainty ΔSX is √(3/7) c+.

Now, we know that any wave function can be written as a linear combination of two spin states (up and down), which can be written as:

Ψ = c+ |+> + c- |->

where c+ and c- are complex constants, and |+> and |-> are the two orthogonal spin states such that Sx|+> = +1/2|+> and Sx|-> = -1/2|->.

Hence, we can write the given wave function as:Ψ = c+|+> + i/√7|->

Now, we know that the given wave function has been defined in Sx basis, and not in the basis of |+> and |->.

Therefore, we need to write |+> and |-> in terms of |l> and |r> (where |l> and |r> are two orthogonal spin states such that Sy|l> = i/2|l> and Sy|r> = -i/2|r>).

Now, |+> can be written as:|+> = 1/√2(|l> + |r>)

Similarly, |-> can be written as:|-> = 1/√2(|l> - |r>)

Therefore, the given wave function can be written as:Ψ = (c+/√2)(|l> + |r>) + i/(√7√2)(|l> - |r>)

Therefore, we can write:c+|l> + i/(√7)|r> = (c+/√2)|+> + i/(√7√2)|->

Comparing the coefficients of |+> and |-> on both sides of the above equation, we get:

c+/√2 = c+l/√2 + i/(√7√2)

Therefore, c+ = c+l

The amplitude c+ is a real number and is equal to c+l

The expectation value of the operator Sx is given by: = <Ψ|Sx|Ψ>

Now, Sx|l> = 1/2|r> and Sx|r> = -1/2|l>

Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= -i/√7(c+l*) + i/√7(c+l)= 2i/√7 Im(c+)

As c+ is a real number, Im(c+) = 0

Therefore, = 0

The uncertainty ΔSX in the state |Ψ> is given by:

ΔSX = √( - 2)

where = <Ψ|Sx2|Ψ>and2 = (<Ψ|Sx|Ψ>)2

Now, Sx2|l> = 1/4|l> and Sx2|r> = 1/4|r>

Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= 1/4(c+l* + c+l) + 1/4(c+l + c+l*) + i/(2√7)(c+l* - c+l) - i/(2√7)(c+l - c+l*)= = 1/4(c+l + c+l*)

Now,2 = (2i/√7)2= 4/7ΔSX = √( - 2)= √(1/4(c+l + c+l*) - 4/7)= √(3/14(c+l + c+l*))= √(3/14 * 2c+)= √(3/7) c+

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