What kind of solid tends to have the lowest melting points?

Considering the ideal gas law, the volume of gas present in the sample is 7.15122 L.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar gas constant:

P×V = n×R×T

In this case, you know:

Replacing in the ideal gas law:

2.50 atm×V = 0.675 moles×0.082 (atmL)/(molK)× 323 K

Solving:

V= (0.675 moles×0.082 (atmL)/(molK)× 323 K)÷ 2.50 atm

V= 7.15122 L

Finally, the volume of gas is 7.15122 L.

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Answer:

C

Explanation:

Bacteria lacks a nucleus.

Answer:

The absolute zero temperature T = - 269.91° C

Explanation:

From the given information:

The plot of the volume of the experimental data against the celsius temperature can be expressed mathematically as:

V = mT + c

V = 0.0741 × T+c --- (1)

where;

m, which is the straight line of the slope = 0.0741

replacing the value of V to be = 20 L, T= 0.

Then:

20 = 0.0741 × 0 + c

20 = c

From equation (1), replacing the value of c with 20, we have:

V = 0.0741 × T+20

SO, to determine absolute zero temperature: we have the volume to be zero at absolute zero temperature, Thus:

0 = 0.0741 × T+20

0.0741 T + 20  = 0

0.0741 T = - 20

\(\mathbf{T = \dfrac{-20}{0.0741}}\)

T = - 269.91° C

Answer:

It's the A. 2-bromobutane

Explanation:

Have a good day

The name of the alkane molecule \(\rm CH_3CH_2CHBrCH_3\) is 2-bromobutane. The correct answer is option A.

An alkane is a type of hydrocarbon molecule that consists entirely of single-bonded carbon and hydrogen atoms. Alkanes are also known as saturated hydrocarbons.

Therefore, 2-bromobutane is the name of the alkane molecule \(\rm CH_3CH_2CHBrCH_3\). Option A is the correct answer.

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The average wavelength of the fluorine molecule will be 2.36 × 10⁻¹¹ metres.

Fluorine Molecule's Speed = 442.4 m/s

The Molar Mass of the F₂ = 38 g/mol

Now as we know that any molecule's

1 mole contain  = 6.022 × 10²³ Molecule

So, 1 Fluorine molecule mass =

Fluorine's Molar mass / Number of Fluorine molecule in 1 mole

So, 1 Fluorine molecule mass = 38 / ( 6.022 × 10²³ )

1 Fluorine molecule mass = 6.31 × 10⁻²³ g

1 Fluorine molecule mass = 6.31 × 10⁻²⁶  Kg

So molecule's momentum = Molecule's mass × Molecule's Velocity

So molecule's momentum = ( 6.31 × 10⁻²⁶ ) × 442.4

So molecule's momentum = 2.8 × 10⁻²³  Kg.m/s

Now wavelength of Fluorine molecule = λ = planks constant / momentum

wavelength of Fluorine molecule = λ = ( 6.626 × 10⁻³⁴ ) / ( 2.8 × 10⁻²³ )

wavelength of Fluorine molecule = λ = 2.36 × 10⁻¹¹ metre

So the wavelength of the diatomic fluorine molecule came out to be 2.36 × 10⁻¹¹ metres after applying all the concepts and formulas.

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Answer:

9.93712g

Explanation:

You have 10mL of water at 33 degrees, so you want to look at the density of water at 33 degrees. Then you multiply that density (.993712) by 10 and the mL cancel out and you are left with 9.93712g.

Hope this helps!

The number of molecules of a flask that contains 0.5 mol of liquid bromine is 3.01 × 10²³ molecules.

The number of molecules of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number as follows:

no of molecules = no of moles × 6.02 × 10²³

According to this question, a flask contains 0.500 moles of liquid bromine. The number of molecules can be calculated as follows:

no of molecules = 0.5 × 6.02 × 10²³

no of molecules = 3.01 × 10²³

Therefore, 3.01 × 10²³ molecules is the number of bromine molecules in 0.5 moles.

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The mass of hydrogen needed to produce 51.0 grams of ammonia is  ≈ 9.07 grams.

To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.

From the balanced chemical equation:

3 H₂(g) + N₂(g) → 2 NH₃(g)

We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).

First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.

Number of moles of NH₃ = Mass / Molar mass

                     = 51.0 g / 17.03 g/mol

                     ≈ 2.995 moles

Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.

Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃

           = (2.995 moles × 3) / 2

           ≈ 4.493 moles

Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).

Mass of H₂ = Moles × Molar mass

          = 4.493 moles × 2.02 g/mol

          ≈ 9.07 grams

Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.

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Answer:

Limewater is a solution of calcium hydroxide. If carbon dioxide is bubbled through limewater, the limewater turns milky or cloudy white.

Explanation:

yea

Answer:

Limewater or calcium hydroxide.

Explanation:

Limewater is a solution of calcium hydroxide. CO2 is bubbled through limewater, the solution turns cloudy.

Answer: 14.0

Explanation: 14.0 is a base. The more basic, the less hydrogen ion concentration.

Calcium (Ca) is in group 2 and period 4 on the periodic table be because Calcium has 2 valence electrons and 4 electron shell. Thus, calcium is a metal like all other group 2 element.

The correct answer to the question is Option C. Calcium, like all group 2 elements, is reactive and a solid at room temperature.

Calcium is a group 2 element majorly because it has 2 valence electrons. It is also in period 4 because it has 4 electron shells.

Being a group 2 element, calcium is a solid at room temperature and also reactive. All elements in the group 2 are metals.

There are other elements in period 4 which are not solid. For example krypton is an element in period 4 and it is a gas and not reactive.

From the above information, we can conclude that the correct answer to the question is:

Option C. Calcium, like all group 2 elements, is reactive and a solid at room temperature.

See attached image

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Answer: A volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

Explanation:

Given: \(V_{1}\) = ?,         \(M_{1}\) = 0.55 M

\(V_{2}\) = 100.0 mL,        \(M_{2}\) = 2.50 M

Formula used to calculate the volume of KBr is as follows.

\(M_{1}V_{1} = M_{2}V_{2}\)

Substitute the values into above formula as follows.

\(M_{1}V_{1} = M_{2}V_{2}\\0.55 M \times V_{1} = 2.50 M \times 100.0 mL\\V_{1} = 455 mL\)

Thus, we can conclude that a volume of 455 mL from 0.550 M KBr solution can be made from 100.0 mL of 2.50 M KBr.

Answer:

A. 455 mL

Explanation:

I took the Chemisty Exam

Answer:B electrons fill orbitals In order of their increasing energy from left to right

Explanation:

the equation is not present.

Answer: CH4

Explanation:

BRAINLESS PLEASE

Answer:

O₂

Explanation:

The example of the compound or the molecule that forms a non-polar bond is oxygen gas.

Oxygen gas has a formula of O₂

The products of the alpha decay of radium-226 and the beta decay of carbon-14 are radon-222 and nitrogen-14, respectively.

The alpha decay of radium-226 results in the emission of an alpha particle, which is a helium nucleus consisting of two protons and two neutrons.

Therefore, the product of the alpha decay of radium-226 is radon-222:

Ra-226 → Rn-222 + alpha particle

On the other hand, In the case of carbon-14, beta minus decay occurs, in which a neutron is converted into a proton, and an electron and an antineutrino are emitted.

So carbon-14 becomes nitrogen-14:

C-14 → N-14 + beta particle

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--The complete Question is, What is the product of the alpha decay of radium-226 and the beta decay of carbon-14?--

Answer:

5.185 gcm⁻³

Explanation:

The formula to find density is:

Density = \(\frac{mass}{volume}\)

Density = \(\frac{42}{8.1}\)

Density of magnetite sample = 5.185 gcm⁻³

Answer: 5.185

Explanation: the formula to find the density is

Density = mass/volume

Density = 42/8.1

Density of magnetite sample = 5.185 g/cm3

Answer:

search on YT Khan academy work done by gravity

Explanation:

you will get it for sure with best explanation

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The mass in grams of 8.94×10²² formula units of CuF₂ is 15.07 g

6.02×10²³ formula units = 1 mole of CuF₂

But

1 mole of CuF₂ = 101.5 g

Thus,

6.02×10²³ formula units = 101.5 g of CuF₂

6.02×10²³ formula units = 101.5 g of CuF₂

Therefore,

8.94×10²² formula units = (8.94×10²² × 101.5 ) / 6.02×10²³

8.94×10²² formula units = 15.07 g of CuF₂

Thus, 8.94×10²² formula units are present in 15.07 g of CuF₂

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Based on the data shown in the graph, the rate of reaction is directly proportional to the temperature of a reaction.

The speed at which a chemical reaction occurs is called the reaction rate or rate of reaction. The rate of a reaction is proportional to the increase in product concentration per unit time and the decrease in reactant concentration per unit time.

The rate of a reaction is affected by the following:

the temperature of the reaction - the rate of reaction is directly proportional to the temperature of a reaction. Hence, the rate of a reaction increases with an increase in temperature.

presence of a catalyst - the rate of a reaction increases with the addition of a catalyst. A catalyst speeds up the rate of a reaction.

the surface area of the reactants - the rate of a reaction increases with an increase in the surface area of the reactants,

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Answer:

At higher temperatures, chemical reactions occur more quickly.

Explanation:

edmentum

Answer: C

l

2

→

H

C

l

O

C

l

2

→

2

H

C

l

O

(Cl balance)

C

l

2

+

2

H

2

O

→

2

H

C

l

O

(O balance)

C

l

2

+

2

H

2

O

→

2

H

C

l

O

+

2

H

+

(H balance)

C

l

2

+

2

H

2

O

→

2

H

C

l

O

+

2

H

+

+

2

e

−

(Charge balance)

C

l

2

+

2

H

2

O

→

2

H

C

l

O

+

2

H

+

+

2

e

−

balanced half-reaction)

Explanation:

Complete of row:

A mole is a unit of account for chemistry. The unit of account is used to facilitate the calculation of an object.

One mole of any substance will have the same number of particles, which is equal to 6.02 × 10²³ particles." For example, 1 mole of air contains 6.02 × 10²³ molecules of H₂O. 1 mole of oxygen gas contains 6.02 × 10²³ molecules of O.

The mole scale is needed as an indication of the amount of substance or compound, mole is the gram of substance divided by the relative molecular mass (Mr). The formula for calculating the moles of a compound is n = gram/Mr, in this case, n is the moles of the substance and gr is the mass of the substance.

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Answer:

1 mole is equal to 1 moles C6H6, or 78.11184 grams.

Hopefully this helped!

-✩sandwichchan✩

Answer:

c. 2,2-dichloropentane.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to firstly draw the structure of the reactant, pent-1-yne:

\(CH\equiv C-CH_2-CH_2-CH_2\)

Now, we infer the halogen is added to the carbon atom with the most carbon atoms next to it, in this case, carbon #2, in order to write the following product:

\(CH\equiv C-CH_2-CH_2-CH_2+2HCl\rightarrow CH_3- CCl_2-CH_2-CH_2-CH_2\)

Whose name is 2,2-dichloropentane.

Regards!

The mean of the data set is approximately 4.0626, and the 90% confidence interval is [4.060925, 4.064275].

The sample mean (x) is calculated as follows:

x = (4.0620 + 4.0550 + 4.0650 + 4.0740 + 4.0550 + 4.0660) / 6

x ≈ 4.0626 (rounded to four decimal places)

The 90% confidence interval is calculated as follows;

Standard deviation (s):

(4.0620 - 4.0626)² = 0.00000036

(4.0550 - 4.0626)² = 0.00000576

(4.0650 - 4.0626)² = 0.00000006

(4.0740 - 4.0626)² = 0.00001328

(4.0550 - 4.0626)² = 0.00000576

(4.0660 - 4.0626)² = 0.00000012

average of the squared differences:

(0.00000036 + 0.00000576 + 0.00000006 + 0.00001328 + 0.00000576 + 0.00000012) / 6 ≈ 0.00000624

s = √(0.00000624)

s ≈ 0.002496

the standard error of the mean (SEM):

SEM = 0.002496 / √6

SEM ≈ 0.001018

For a 90% confidence interval, the z value is approximately 1.645.

ME = 1.645 * 0.001018 ≈ 0.001675

CI = x ± ME

CI = 4.0626 ± 0.001675

CI ≈ [4.060925, 4.064275]

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Answer: The concentration of solution made by the student is 1 M.

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.

The formula used to calculate molarity:

\(\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}\)       .....(1)

Given values:

Moles of solute = 0.5 moles

Volume of solution = 500 mL

Plugging values in equation 1:

\(\text{Molarity of solution}=\frac{0.5\times 1000}{500}\\\\\text{Molarity of solution}=1M\)

Hence, the concentration of solution made by the student is 1 M.

Answer:the Acasta gneisses

Explanation:

Approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

To determine the number of molecules of HCl required to form 34.52 g of MgCl₂, we need to use the molar mass and stoichiometry of the balanced equation:

Mg(OH)₂(s) + 2 HCl(aq) → 2 H₂O(l) + MgCl₂(aq)

The molar mass of MgCl₂ is 95.21 g/mol.

First, we need to calculate the number of moles of MgCl₂ formed:

Moles of MgCl₂ = mass of MgCl₂ / molar mass of MgCl₂

Moles of MgCl₂ = 34.52 g / 95.21 g/mol

Moles of MgCl₂ = 0.363 mol

According to the balanced equation, the stoichiometric ratio between HCl and MgCl₂ is 2:1. Therefore, the moles of HCl required can be calculated as follows:

Moles of HCl = 2 * Moles of MgCl₂

Moles of HCl = 2 * 0.363 mol

Moles of HCl = 0.726 mol

To calculate the number of molecules, we need to use Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules of HCl = Moles of HCl * Avogadro's number

Number of molecules of HCl = 0.726 mol * 6.022 x 10^23 molecules/mol

Number of molecules of HCl = 4.37 x 10^23 molecules

Therefore, approximately 4.37 x 10^23 molecules of HCl would be required to form 34.52 g of MgCl₂.

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The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

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