What magnification will be produced by a lens of power −4.10 D (such as might be used to correct myopia) if an object is held 22.5 cm away?

Answer:

the last time i had my tempature taken was at disney prings about a week ago -_- they used one of those gun things that dont touch u and the SHOVED me forward so i guess i was fine

Explanation:

Answer:

thermometer

Explanation:

If a planet has an orbital eccentricity equal to 0.70, then its orbit is

Eccentricity is a measure of how squashed an ellipse is compared to a perfect circle.

The value of eccentricity ranges from 0 to 1, where 0 represents a perfect circle and 1 represents a parabolic orbit (which is not a closed orbit).

An eccentricity of 0.70 indicates that the planet's orbit is significantly elongated and not close to a perfect circle.

Therefore, the correct answer is - A very elongated ellipse.

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a.

The difference in distance from point S and S' to point D is  seen to be as  1.25 mm.

b. the distance between the two sources is  12.8 mm.

Distance is described as a  a numerical or occasionally qualitative measurement of how far apart objects or points are.

We apply the formula of Δx = d sinθ

Δx=  difference in distance,

d=  distance between the two speakers = 4mm

θ =  angle between the line joining the two speakers and the line from the speakers to the point D, θ = tan^(-1)(1/3) = 18.43°

The distance between the two speakers is given as 4 mm.

Δx = d sinθ

Δx = 4 sin(18.43°)

Δx  = 1.25 mm

(b) we also use

λ = d sinθ

λ= wavelength of the sound waves = 4 mm

θ =  18.43°

d = λ/sinθ

d = (4 mm)/sin(18.43°)

= 12.8 mm

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The velocity of the ball is 100m/s

The first step is to write out the parameters;

The force used to kick the ball is 1000N

The mass of the ball is 0.8 kg

Time is 0.8 seconds

Therefore the velocity can be calculated as follows

F= Mv-mu/t

1000= 0.8(v) - 0.8(0)/0.8

1000= 0.8v- 0.8/0.8

Cross multiply both sides

1000(0.8) = 0.8v

800= 0.8v

divide both sides by the coefficient of v which is 8

800/0.8= 0.8v/0.8

v= 1000m/s

Hence the velocity is 1000m/s

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Saturation is defined as a solution containing 10 grams of KCl at 10 degrees Celsius.

When the temperature rises, solid solutes become more soluble in general. As a result, heating a KCl solution causes it to become unsaturated and begin dissolving more solute.

At 10 °C, KCl dissolves in an aqueous solution at a rate of 31,2 g per 100 g of water. The amount of a compound that may dissolve in a given amount of a solvent at a specific temperature is indicated by the solubility of the compound in the solvent.

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The syllogisms constructed from the given statements are valid, except for the one syllogism identified as invalid.

Categorical syllogisms are logical arguments that involve two premises and a conclusion, all of which are categorical statements. These statements are formed using categorical propositions that involve classes or categories of objects or concepts.

Let's examine the given statements and identify the valid and invalid syllogisms:

All mumbling is murmuring: This statement indicates that the class of mumbling is entirely contained within the class of murmuring. It can be represented as "All M is M."

All mumbling is nonsensical: This statement suggests that the class of mumbling is entirely nonsensical. It can be represented as "All M is N."

No murmuring is sensical: This statement implies that there is no overlap between the class of murmuring and the class of sensical. It can be represented as "No M is S."

Now, let's construct the syllogisms using these statements:Syllogism 1:

Premise 1: All M is Mumbling

Premise 2: All Mumbling is Nonsensical

Conclusion: Therefore, All M is Nonsensical

This syllogism is valid because it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.

Syllogism 2:

Premise 1: All Mumbling is Murmuring

Premise 2: No Murmuring is Sensical

Conclusion: Therefore, No M is Sensical

This syllogism is also valid as it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.

Syllogism 3:

Premise 1: All Mumbling is Nonsensical

Premise 2: No Murmuring is Sensical

Conclusion: Therefore, No Mumbling is Murmuring

This syllogism is valid as it follows the form of the categorical syllogism, where the conclusion is a valid inference based on the premises.

Invalid Syllogism:

Premise 1: All Mumbling is Murmuring

Premise 2: All Mumbling is Nonsensical

Conclusion: Therefore, All Murmuring is Nonsensical

This syllogism is invalid. It commits the fallacy of undistributed middle, where the middle term (Mumbling) is not properly distributed in either premise, leading to an invalid conclusion.

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The frictional force of an object is the product of the normal force and coefficient of kinetic friction. Here the frictional force acting on the object  is 16.4 N.

Frictional force is a kind of force acting on a body to resist it from motion. Thus, the direction of the force will be in negative with the magnitude. Frictional force is the product of coefficient of friction and the normal force.

The normal  force acting on the object of mass 4.2 Kg is N = mg

N = 4.2 Kg × 9.8 m/s² = 41.16 N

Frictional force = ц N

                         = 0.40 × 41.16 N

                         = 16.4 N.

Therefore, the frictional force acting between the surface of the object and the floor is 16.4 N

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Your question is incomplete. But your complete question probably was:

The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.40 the weight of the object is 4.2 kg. What is the frictional force of the object?

When a ray of light strikes a plane mirror, the angle of reflection is equal to the angle of incidence.

In this case, the ray of light makes an angle of 35 degrees with the plane mirror. Therefore, the angle of reflection will also be 35 degrees. To understand why this happens, we need to consider the properties of reflection. When light interacts with a smooth surface like a mirror, it follows the law of reflection.

According to this law, the incident ray, the reflected ray, and the normal (a line perpendicular to the mirror's surface) all lie in the same plane. The angle of incidence is the angle between the incident ray and the normal, measured on the side of the normal where the light is coming from. In this case, the angle of incidence is 35 degrees.

According to the law of reflection, the angle of reflection is the angle between the reflected ray and the normal, also measured on the side of the normal where the light is coming from. Since the incident and reflected rays are on opposite sides of the normal, the angle of reflection is also 35 degrees.

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Answer:

i) shadow

ii)size increases

iii)size decreases

iv)when an opaque object or material is placed in the path of rays of light.(opaque means not transpalent means not see through

v)--

A defining characteristic of a city is often referred to as a "landmark." A landmark is a distinctive feature or building that stands out and is used to identify or represent a location. Landmarks can be man-made, such as structures, monuments, or historical locations, or they can be natural, like mountains, rivers, or lakes.

Landmarks are significant tourist destinations for both locals and visitors because they frequently have historical, cultural, or architectural value. They can serve as a symbol of a city's identity, history, and personality and end up being recognised as the place's iconic symbols. Landmarks might be notable buildings, statues, cathedrals, museums, or bridges that have come to symbolise the city in which they are located.

Therefore, option (OB) "landmark" is the term used to describe a distinguishing feature in a city.

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Answer:

  c.  5.6 W

Explanation:

We can write the Kirchoff's voltage law (KVL) equations for the circuit using i1 for the clockwise current in the left loop, and i2 for the clockwise current in the right loop. Then the circuit equations are ...

  i1 (10 +10) -i2(10) = 12

  -i1(10) +i2(10 +15) = 8

Using Cramer's rule to find i2, we have ...

  i2 = (12(-10) -8(20))/((-10)(-10) -(25)(20)) = -280/-400 = 0.7

The power supplied by the Emf is ...

  (8 V)(0.7 A) = 5.6 W . . . . . matches choice C

Answer:

Solar energy is renewable.

Explanation:

If something is renewable, it is generated faster than it can be reasonably used or won't run out for longer than it would be used. Solar falls into the latter category. Using solar panels won't deplete the sun and the sun will likely be around for much longer than we will.

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

The answer is "wedge​"

Explanation:

A wedge is an item that tightens to a meager edge. Pushing the wedge one direction makes a force in a sideways direction. It is normally made of metal or wood and is used for parting, tightening, lifting, or fixing, as in making sure about a hammer head onto its handle.

The wedge was used in ancient occasions to part logs and shakes; an ax is also a wedge, similar to the teeth on a saw. As far as its mechanical capacity, the screw might be considered as a wedge folded over a cylinder.

Answer: The ball reaches a height of 68 feet after 1.7 seconds.

Explanation: To solve this problem, we can use the following formula:

h(t) = -16t^2 + vt + h

where h(t) is the height of the ball at time t, v is the initial velocity (in this case, 80 ft./sec.), and h is the initial height (in this case, 4 feet).

We want to find out when the height of the ball is 68 feet, so we can set h(t) = 68 and solve for t:

68 = -16t^2 + 80t + 4

Rearranging and simplifying:

16t^2 - 80t - 64 = 0

Dividing both sides by 16:

t^2 - 5t - 4 = 0

Factoring:

(t - 4)(t + 1) = 0

So t = 4 or t = -1. We can discard the negative value, since time cannot be negative. Therefore, the ball reaches a height of 68 feet after t = 4 seconds - the time at which it reaches maximum height.

However, we also know that the initial height of the ball is 4 feet, so we need to subtract this from the maximum height to get the actual height above the ground:

max height = h(4) = -16(4)^2 + 80(4) + 4 = 132 feet

So the ball first reaches a height of 68 feet on its way down, after reaching a maximum height of 132 feet. We can use the formula again to find when the ball reaches 68 feet on its way down:

68 = -16t^2 + 80t + 132

Rearranging and simplifying:

16t^2 - 80t + 64 = 0

Dividing both sides by 16:

t^2 - 5t + 4 = 0

Factoring:

(t - 1)(t - 4) = 0

So t = 1 or t = 4. We discard the value t = 4, since that is when the ball reaches maximum height. Therefore, the ball reaches a height of 68 feet again, on its way down, after t = 1 second.

Therefore, the ball reaches a height of 68 feet after 1.7 seconds (1 second on the way down + 0.7 seconds to reach maximum height on the way up).

Hope this helps, and have a great day!

Range and Maximum height are proportional to the square of the initial velocity.

In projectile motion, Range of the particle is the horizontal distance travelled by the projectile between launch and the landing points and is denoted as R,

R = u^2sin2θ/g

Here u is initial velocity.

Maximum height is the maximum height from the point of projection, a projectile can reach.

And at maximum height (h) attained, velocity of the object is zero (v=0)

we can use , v^2 - (u sinθ)^2= 2ah     (acceleration due to gravity is a= -g)

Or 0 -  (u sinθ)^2 = 2(-g)h

⇒ h = u^2 sin^2 θ / 2g

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1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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Answer:

solidification

Explanation:

a liquid becoming a solid, is called solidification. For any pure substance, the temperature at which melting occurs—known as the melting point—is a characteristic of that substance.

Answer:

a) v = 1.075*10^7 m/s

b) FB = 7.57*10^-12 N

c) r = 10.1 cm

Explanation:

(a) To find the speed of the alpha particle you use the following formula for the kinetic energy:

\(K=qV\)          (1)

q: charge of the particle = 2e = 2(1.6*10^-19 C) = 3.2*10^-19 C

V: potential difference = 1.2*10^6 V

You replace the values of the parameters in the equation (1):

\(K=(3.2*10^{-19}C)(1.2*10^6V)=3.84*10^{-13}J\)

The kinetic energy of the particle is also:

\(K=\frac{1}{2}mv^2\)       (2)

m: mass of the particle = 6.64*10^⁻27 kg

You solve the last equation for v:

\(v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.84*10^{-13}J)}{6.64*10^{-27}kg}}\\\\v=1.075*10^7\frac{m}{s}\)

the sped of the alpha particle is 1.075*10^6 m/s

b) The magnetic force on the particle is given by:

\(|F_B|=qvBsin(\theta)\)

B: magnitude of the magnetic field = 2.2 T

The direction of the motion of the particle is perpendicular to the direction of the magnetic field. Then sinθ = 1

\(|F_B|=(3.2*10^{-19}C)(1.075*10^6m/s)(2.2T)=7.57*10^{-12}N\)

the force exerted by the magnetic field on the particle is 7.57*10^-12 N

c) The particle describes a circumference with a radius given by:

\(r=\frac{mv}{qB}=\frac{(6.64*10^{-27}kg)(1.075*10^7m/s)}{(3.2*10^{-19}C)(2.2T)}\\\\r=0.101m=10.1cm\)

the radius of the trajectory of the electron is 10.1 cm

The speed, magnetic force and radius are respectively; 10.75 * 10⁶ m/s; 7.57 * 10⁻¹² N; 0.101 m

A) We know that the formula for kinetic energy can be expressed as;

K = qV

where;

q is charge of the particle = 2e = 2(1.6 × 10⁻¹⁹ C) = 3.2 × 10⁻¹⁹ C

V is potential difference = 1.2 × 10⁶ V

K = 3.2 × 10⁻¹⁹ *  1.2 × 10⁶

K = 3.84 × 10⁻¹³ J

Also, formula for kinetic energy is;

K = ¹/₂mv²

where v is speed

Thus;

v = √(2K/m)

v = √(2 * 3.84 × 10⁻¹³)/(6.64 * 10⁻²⁷)

v = 10.75 * 10⁶ m/s

B) The magnetic force is given by the formula;

F_b = qvB

F_b = (3.2 × 10⁻¹⁹ * 10.75 * 10⁶ * 2.2)

F_b = 7.57 * 10⁻¹² N

C) The formula to find the radius is;

r = mv/qB

r = (6.64 * 10⁻²⁷ * 10.75 * 10⁶)/(1.6 × 10⁻¹⁹ * 2.2)

r = 0.101 m

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In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To determine the maximum velocity at which you can make a turn without slipping in the rain at the intersection, we need to consider the changes in friction.

Let's assume the normal static friction and normal kinetic friction are represented by μs and μk, respectively.

In the case of rain, the static friction is halved, meaning the new static friction coefficient is 0.5μs, while the kinetic friction is reduced to one-third, resulting in a new kinetic friction coefficient of (1/3)μk.

To avoid slipping during the turn, we need to ensure that the centripetal force required for the turn is less than or equal to the maximum frictional force available.

The centripetal force is given by the equation mv²/r, where m is the mass, v is the velocity, and r is the radius of the turn.

The maximum frictional force in the rain can be calculated as (0.5μs)mg, where g is the acceleration due to gravity.

Thus, to avoid slipping, we set the centripetal force equal to the maximum frictional force:

mv²/r = (0.5μs)mg

Simplifying the equation, we find:

v = √(0.5μsgr)

By plugging in the values for μs, g, and the radius of the turn, we can calculate the maximum velocity.

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Answer You need to consider that the gravity on earth is 9.8 m/s/s. This means any object you let go on the earths surface will gain 9.8 m/s of speed every second. You need to apply a force on the object in the opposite direction to avoid this acceleration. If you are pushing something up at a constant speed, you are just resisting earths acceleration. The more massive and object is, the greater force is needed to accelerate it. The equation is Force = mass*acceleration. So for a 2kg object in a 9.8 m/s/s gravity you need 2kg*9.8m/s/s = 19.6 Newtons to counteract gravity. Work or energy = force * distance. So to push with 19.6 N over a distance of 2 meters = 19.6 N*2 m = 39.2 Joules of energy. There is an equation that puts together those two equations I just used and it is E = mgh

The amount of Energy to lift an object is (mass) * (acceleration due to gravity) * (height)

:Hence, the Work done to life the mass of 2 kg to a height of 10 m is 196 J. Hope it helps❤️❤️❤️

Explanation:

Answer:

1506.33J/Kgc

Explanation:

heat loss=heat gain

Qw=Qm

m1c1T1=m2c2T2

0.15×4200×(21-4)=0.09×c2×(100-21)

c2=1506.33J/Kgc

Answer:

sorry about this question

Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

Answer:

If he's 500 kg and 1 kg = 10 N then it would be 5,000 N

Explanation:

The surface area is unimportant and they'll use it to trick you.

The energy of the skater at each position is:

At position A, the skater is at the lowest point, so the PE is zero. The KE can be calculated using the formula KE = (1/2)mv², where m is the mass of the skater and v is the velocity:

KE = (1/2)(60 kg)(8 m/s)²

KE = 1920 J

Therefore, at position A, the skater has 1920 J of kinetic energy and 0 J of potential energy.

At position B, the skater has gained some height, so there is some potential energy. The KE can be calculated as before, and the PE can be calculated using the formula PE = mgh, where m is the mass of the skater, g is the acceleration due to gravity (9.81 m/s²), and h is the height:

KE = (1/2)(60 kg)(8 m/s)²

KE = 1920 J

PE = (60 kg)(9.81 m/s²)(3 m)

PE = 1764 J

Therefore, at position B, the skater has 1920 J of kinetic energy and 1764 J of potential energy.

At position C, the skater has reached the highest point, so the KE is zero. The PE can be calculated as before:

PE = (60 kg)(9.81 m/s²)(6 m)

PE = 3528 J

Therefore, at position C, the skater has 0 J of kinetic energy and 3528 J of potential energy.

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