What mass (in grams) of NH4Cl is needed to prepare 664 mL of 4.423 M NH CI solution?

With 25 grams of sodium chloride, 1.2 liters of a 0.35 M solution of sodium chloride may be created.

The quantity of solute dissolved in one liter of solution is known as molarity (M).

Molarity (M) is defined as the number of moles of a solute divided by the volume of the solution in litres.

M = n / v where

M stands for molarity, n for moles, and V for volume of solution.

NaCl's molar mass is 23 g/mol plus 35.5 g/mol.

= 58.5 g/mol

Now,

Given mass/molar mass equals the number of moles (n).

= 0.427

We must now determine the solution's volume.

M = 0.35 = 0.427 / v

V is 1.2 liters

Thus, 25 grams of sodium chloride might be used to create 1.2 liters of sodium chloride solution at 0.35M.

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Explanation:

A lot of the names you're just going to have to look up/know. CH4 is methane, which you would just have to know.

As for the molar mass, for each compound you have to add up the masses of each atom. Using CH4 as an example, you would have to add the mass of the carbon atom with the 4 hydrogen atoms. Using a periodic table you can see that the mass of carbon is about 12.0107 g and the mass of each hydrogen atom is about 1.008 g.

12.0107 + (4 x 1.008) = 16.0427 g

Just be careful with compounds such as Ca3(PO4)2, because there are 2 phosphorous atoms and 8 oxygen atoms.

For percent composition you have to find how much each element within the compound makes up the compound's mass. Since you will have already calculated the molar mass, you can add up the mass of a particular element within a compound and divide it by the compound's molar mass. Then multiply by 100 to get the percent.

For CH4,

Carbon:

(12.0107/16.0427) x 100 = 74.87 %

Hydrogen:

(4 x 1.008/16.0427) x 100 = 25.13 %

There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.

The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.

Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:

Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)

Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2

Moles of Al3+ = 0.84 mol Al3+

Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.

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Answer:

Mitochondria.

Explanation:

The organelles' activity which contributes most directly to muscle contraction in an earthworm is the mitochondria.

Answer:

The sun's position near earth

Explanation:

The following statement is true concerning the results of the Human Genome Project:

The Human Genome Project has raised many complicated ethical issues.

What is Human Genome?

The human genome refers to the complete set of genetic information (DNA) present in human cells. It includes both the protein-coding and non-coding regions of DNA. The human genome is made up of about 3 billion base pairs and is organized into 23 pairs of chromosomes. The study of the human genome is an important field of genetics and has many implications for understanding human biology, evolution, and disease.

The Human Genome Project was a scientific research project that aimed to identify and map all the genes in the human genome, which contains all the genetic information needed for human development and function. The project was completed in 2003 and provided a wealth of information about the structure and function of the human genome, including the location and sequence of all human genes.

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Answer:

hedges are used to be courteous in expressing (counterclaims)

Answer:

The molar mass of:

Helium = 4.00 g/mol

Potassium = 39.0983 g/mol

Manganese = 54.94 g/mol.

Boron = 10.81 g / mol

Explanation:

Helium = 4.00 g/mol

Potassium = 39.0983 g/mol

Manganese = 54.94 g/mol.

Boron = 10.81 g / mol

The sum of coefficients when the above-mentioned equation is balanced is 12.

A chemical equation is a symbolic representation of a chemical reaction where reactants are represented on the left, and products on the right.

A chemical equation is said to be balanced when the number of atoms of each element on both sides of the equation is the same.

According to this question, calcium hydroxide reacts with phosphoric acid as follows:

3Ca(OH)₂ + 2H₃PO4 → Ca₃(PO4)₂ + 6H₂O

The sum of the coefficients of the above balanced chemical equation is 3 + 2 + 1 + 6 = 12.

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Answer:

name four agricultural inputs are subsidized by the government

0.297 kJ of heat is needed to raise the temperature of 10g of aluminum from 22 degrees Celsius to 55 degrees Celsius.

The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.

It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.

It is given by the formula -

                                                  Q = mcΔT

where, Q = amount of heat

m = mass

c = specific heat

ΔT = Change in temperature

Given,

mass = 10g

c = 0.901J/g⁰C

Initial temperature (T₁) = 22⁰C

Final Temperature (T₂) = 55⁰C

Q = mcΔT

= 10 × 0.901 × (55 -22)

= 297.33 J = 0.297 kJ

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The correct answer is A. There are 6 carbon atoms, 12 hydrogen atoms, and 18 oxygen atoms on the reactant side, and 6 carbon atoms, 12 hydrogen atoms, and 18 oxygen atoms on the product side.

This is because of the law of conservation of matter, which states that matter cannot be created or destroyed by a chemical reaction. Therefore, the number of atoms of each element must remain the same on both sides of the reaction.

In this case, the number of carbon, hydrogen, and oxygen atoms must remain the same on both the reactant and product sides.

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Based on the information in the table above,  the best hypothesis regarding the properties of the compounds that can form from the given ions is option B. MgO forms the strongest ion-dipole interactions in aqueous solution.

Magnesium and oxygen have very different electronegativity properties. So instead of creating covalent bonds, they create ionic bonds.

Magnesium oxide is an ionic compound, meaning the elements are arranged in a lattice and are attracted to one another by extremely potent electrostatic interactions.

Since magnesium oxide is primarily ionic, there is a noticeable difference in the electronegativity of magnesium and oxygen. The interionic connections between Mg²⁺ and O²⁻ will be quite strong.

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For the absorbance of the solution in a 1.00 cm cell at 500 nm  is mathematically given as

A’ = 0.16138

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138

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Answer:

d = 1.8 g/mL

Explanation:

Given data:

Mass of bottle = 6.8 g

Volume of liquid = 23.1 mL

Mass of bottle + liquid = 48.8 g

Density of liquid = ?

Solution:

First of all we will calculate the mass of liquid.

Mass of liquid = combined mass - mass of bottle

Mass of liquid = 48.8 g - 6.8 g

Mass of liquid = 42 g

Density of liquid:

d = m/v

d = 42 g/ 23.1 mL

d = 1.8 g/mL

Answer:

Due to an electron-pair acceptor and donor.

Explanations:

Lewis acid can be defined as an electron-pair acceptor. An example is Hydrogen ion(H+). This is because it is a proton and it distributes positive charge which means that it accepts electrons(negative charge).

Lewis base can be defined as an electron-pair donor. This is because it donates electrons to be accepted by the proton. An example is ammonia(NH3).

Based on valence electron trends, the correct answer is C. Group 3A or 13.

Based on trends in valence electrons, the group of pairs with a group 5 non-metal, such as nitrogen (N), in a 1:1 ratio is Group 3A or 13. Group 5 non-metals have 5 valence electrons, and they tend to form compounds by either gaining 3 electrons to achieve a stable octet or by sharing 3 electrons in covalent bonds.

Group 1A or 1 elements, such as hydrogen (H) and lithium (Li), have only 1 valence electron. They would need to gain 4 additional electrons to achieve a stable octet, which is energetically unfavorable.

Group 2A or 2 elements, such as beryllium (Be) and magnesium (Mg), have 2 valence electrons. They would need to gain 3 additional electrons to achieve a stable octet, which is also energetically unfavorable.

Group 6A or 16 elements, such as oxygen (O) and sulfur (S), have 6 valence electrons. They would need to gain only 1 additional electron to achieve a stable octet, making them more likely to form a 2:1 ratio with a group 5 non-metal.

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The percent by mass of nitrogen in ammonia (NH3) is approximately 82.15%

Calculating the mass of nitrogen to the total mass of the compound and then expressing the result as a percentage will allow us to determine the percent by mass of nitrogen in NH3 (ammonia).

Ammonia's molecular structure, NH3, indicates that it is made up of one nitrogen atom (N) and three hydrogen atoms (H). We must take both the molar masses of nitrogen and ammonia into account when calculating the percent by mass of nitrogen.

Nitrogen's (N) molar mass is roughly 14.01 g/mol. The molar masses of nitrogen and hydrogen are added to determine the molar mass of ammonia (NH3). Since hydrogen's molar mass is around 1.01 g/mol, ammonia's molar mass is:

(3 mol H 1.01 g/mol) + (1 mol N 14.01 g/mol) = 17.03 g/mol = NH3.

Now, we can use the following formula to get the nitrogen content of ammonia in percent by mass:

(Mass of nitrogen / Mass of ammonia) / 100% is the percentage of nitrogen by mass.

Ammonia weighs 17.03 g/mol and contains 14.01 g/mol of nitrogen by mass. By entering these values, we obtain:

(14.01 g/mol / 17.03 g/mol) 100% 82.15 % of nitrogen by mass

Ammonia (NH3) has a nitrogen content that is roughly 82.15 percent by mass.

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Answer: one by one

Explanation:

Answer:

using Charles law

v1/t1= v2/ t2

Explanation:

875/t1=955/56+273

t1= 329* 875/955

t1= 302.82k

The initial temperature of the hot air balloon can be calculated from Charles's law. The initial temperature of the balloon was, 51.3 °C.

According Charles's law, at constant pressure, the temperature and volume of a gas is in direct proportionality. Thus volume increases with an increase in temperature. Therefore V/T = a constant.

Let V₁ and T₁ be the initial volume and initial temperature and V₂ and T₂ be the final volume and temperature respectively. Thus we can write the relation as:

V₁ /T₁  = V₂/T₂ .

Given that the initial and final volume are 875 L and 955 L respectively. The final temperature is 56 °C. Thus the initial temperature is calculated as :

T₁ = V₁T₂/V₂

   = (875 L × 56 °C )/955 L

   = 51.3 °C.

Hence, the initial temperature of the hot air balloon was 51.3 °C.

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The partial pressure of nitrogen on Venus is approximately 321.914 kPa.

To find the partial pressure of nitrogen on Venus, we need to calculate the partial pressure using the mole fraction of nitrogen and the total atmospheric pressure. First, we convert the total atmospheric pressure from psi to kilopascals (kPa) since the mole fraction is given in terms of kPa.

1 psi = 6.89476 kPa

Therefore, the total atmospheric pressure on Venus is:

1334 psi × 6.89476 kPa/psi = 9197.53 kPa

Next, we can calculate the partial pressure of nitrogen using the mole fraction. The mole fraction of nitrogen is given as 0.035, which means that nitrogen makes up 3.5% of the total moles of gas in the atmosphere.

The partial pressure of nitrogen is given by:

Partial pressure of nitrogen = Mole fraction of nitrogen × Total atmospheric pressure

Partial pressure of nitrogen = 0.035 × 9197.53 kPa

Partial pressure of nitrogen = 321.914 kPa

Therefore, the partial pressure of nitrogen on Venus is approximately 321.914 kPa.

It's important to note that the given atmospheric composition of Venus's atmosphere and the total atmospheric pressure are approximate values and can vary depending on specific conditions and measurements.

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Answer:

The energy stored in the spring when the bike goes over a bump is \(6.6\times 10^{-3}\) joules.

Explanation:

Let suppose that spring has a linear behavious, by means of Hooke's Law, definition of Work and Work-Energy Theorem we find that the potential energy stored in the spring (\(U_{g}\)), measured in joules, is defined by:

\(U_{e} = \frac{1}{2}\cdot k\cdot x^{2}\) (1)

Where:

\(k\) - Spring constant, measured in newtons per meter.

\(x\) - Deformation, measured in meters.

If we know that \(k = 33\,\frac{N}{m}\) and \(x = 0.02\,m\), the energy stored by the spring due to compression is:

\(U_{e} = \frac{1}{2}\cdot \left(33\,\frac{N}{m} \right) \cdot (0.02\,m)^{2}\)

\(U_{e} = 6.6\times 10^{-3}\,J\)

The energy stored in the spring when the bike goes over a bump is \(6.6\times 10^{-3}\) joules.

Answer:

1: Carboxyl group

2: Hydroxyl group

3: Hydroxyl group

4: Carboxyl group

Answer:

mass of sodium phosphate required = 25.37 g

Explanation:

Equations of reactions:

3CaCl₂ + 2Na₃PO₄ ---> Ca₃(PO₄)₂ + 6NaCl

3Mg(NO₃)₂ + 2Na₃PO₄ ---> Mg₃(PO₄)₂ + 6NaNO₃

Number of moles of the ions = molarity x volume

Ca²⁺ : 0.052 M x 1.6 L = 0.0832 moles

Mg²⁺ : 0.093 x 1.6 L = 0.1488 moles

From the equations of reaction, number of moles of sodium phosphate required to react with each ion is given as;

For calcium: 2/3 x 0.0832 = 0.0555 moles

For magnesium: 2/3 x 0.1488 = 0.0992 moles

Total number of moles of sodium phosphate required = 0.0555 + 0.0992 = 0.1547 moles

Mass of sodium phosphate = number of moles x molar mass

molar mass of sodium phosphate = 164 g/mol

Mass of sodium phosphate = 0.1547 moles x 164 g/mol = 25.37 g

Therefore, mass of sodium phosphate required = 25.37 g

Answer:

Kinetic Energy is the correct Answer.

Explanation:

At the highest point on the roller coaster (assuming it has no velocity), the object has a maximum quantity of gravitational potential energy. As the object begins moving down to the bottom, its gravitational potential energy begins to decrease and the Kinetic Energy starts to increase.

Answer:

D. double displacement reaction

Socraticorg

Explanation:

Silver hydroxide is almost an insoluble compound, its solubility product is 2*10^(-8). When it is in solution it dissolves like this way.

AgOH ----> Ag⁺ + OH⁻ Ksp = 2 * 10^(-8)

The expression for the solubilty product will be:

Ksp = [Ag+] * [OH-]

We are trying to dissolve the silver hydroxide in the silver nitrate solution. They have one ion in common, the silver cation (Ag+). Since the amount of silver hydroxide that can be dissolved is really small (because it is almost insoluble) we can consider that the concentration of the silver ion is governed by the concentration of the silver nitrate solution.

AgNO₃ ----> Ag+ + NO₃-

Since one molecule of silver nitrate has one nitrate ion we can say that the concentration of the silver ion will be the same as the concentration of the silver nitrate solution.

[AgNO₃] = [Ag+] = 0.270 M

Now that we know the concentration of the silver ion and the ksp, we can replace these values and find the concentration of the hydroxide ion.

Ksp = [Ag+] * [OH-]

[OH-] = Ksp/[Ag+]

[OH-] = 2 * 10^(-8)/(0.270 M)

[OH-] = 7.41 *10^(-8) M = [AgOH]

Answer: the maximum amount of silver hydroxide that will dissolve it 7.41*10^(-8) M

The strand 1 of hydrocarbons is used to produce plastic, hence option D is correct.

Raw resources like natural gas, oil, or plants that have been processed into ethane and propane are used to make plastics. The subsequent "cracking" procedure uses heat to transform ethane and propane into ethylene and propylene. To produce various polymers, these components are mixed.

Propylene is a substance found in large quantities in petroleum. In order to speed up chemical processes, refiners combine heated propylene with a catalyst to create plastic. Propylene molecules start to cluster together like beads on a thread as a result.

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Answer: (a) To calculate the activation energy (Ea) for a first-order reaction, we can use the Arrhenius equation:

k = Ae^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/mol K), T is the temperature in Kelvin, and e is the base of the natural logarithm.

We can rearrange the equation to solve for Ea:

Ea = -RT ln(k/A)

We'll use the rate constants at 25°C and 50°C:

k1 = 2.76 × 10-5 s-1 at 25°C

k2 = 6.65 × 10-4 s-1 at 50°C

T1 = 25 + 273.15 = 298.15 K

T2 = 50 + 273.15 = 323.15 K

Substituting these values into the equation for Ea:

Ea = -R * (T1) * ln(k1/A) = -R * (T2) * ln(k2/A)

Dividing both sides by -R:

T1 * ln(k1/A) = T2 * ln(k2/A)

Dividing both sides by T1 and T2:

ln(k1/A) / T1 = ln(k2/A) / T2

Taking the natural logarithm of both sides:

ln(k2/k1) = (T2/T1) * (ln(k1/A) / T1)

Substituting the values for k1, k2, T1, and T2:

ln(6.65 × 10-4 / 2.76 × 10-5) = (323.15 / 298.15) * ln(2.76 × 10-5 / A)

Solving for ln(k1/A):

ln(k1/A) = ln(6.65 × 10-4 / 2.76 × 10-5) / (323.15 / 298.15)

Using a logarithm calculator, we find that ln(k1/A) = 13.80.

Finally, substituting back into the equation for Ea:

Ea = -R * (T1) * ln(k1/A) = -R * 298.15 * 13.80 = 9,920 J/mol

So, the activation energy for this reaction is approximately 9.92 kJ/mol.

(b) To find the rate constant at 75°C, we can use the Arrhenius equation:

k = Ae^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy (9,920 J/mol), R is the gas constant (8.314 J/mol K), T is the temperature in Kelvin (75 + 273.15 = 348.15 K), and e is the base of the natural logarithm.

Substituting these values into the equation:

k = Ae^(-Ea/RT) = Ae^(-99

Answer:

12.937 mL

Explanation:

First, we have to start with the hendersson-hasselbach equation:

\(pH=pKa+\frac{A^-}{HA}\)(Equation 1)

So, from this equation, we already know the desired pH value 9.3. Therefore we have to calculate the pKa value, for this, we need to use the following equations:

\(pKb=-LogKb\) (equation 2) and \(14=pKa+pKb\) (equation 3) With this in mind we can do the calculations:

\(pKb=-Log(1.8x10^-^5)=4.74\)

\(pKa=14-4.74=9.26\)

Additionally, we have to know the buffer system reaction:

\(NH_4^+~<=>~NH_3~+~H^+\) (reaction 1)

With this in mind \(NH_4^-=HA\) and \(NH_3=A^-\). Now if we use the hendersson-hasselbach reaction we can find the ratio (\(\frac{A^-}{HA}\)) that we need for the desired pH value, so:

\(9.30=9.26+Log(\frac{A^}{HA})\)

\(\frac{A^-}{HA}=1.108\) (equation 4)

From the problem, we know that we already have a portion of \(NH_3=A^-\), 30 mL and 0.1 M. Also, the HCl that we are going to add will react with the NH3 (\(H^+=HCl\)), so:

\(H^+~+~NH_3=>~NH_4^+\) (reaction 2)

With this in mind, all the HA concentration will come from the addition of the HCl and this addition will consume some A-. Therefore, we have to know the moles of A- before the addition:

\(moles~of~A^-~=~0.03*0.1=0.003~mol~of~A-\)

So, we can write a new equation that calculates the concentration of \(A^-\) before the addition:

\(A^-=\frac{0.003-X}{0.03+Y}\) (equation 5)

In this case, "X" is the of A- (NH3) consumed in the reaction for the addition of HCl and Y is the volume of HCl (in litters). Additionally, we can write another equation for the concentration of HA after the addition of HCl:

\(HA=\frac{X}{Y+0.03}\) (equation 6)

Let's remember that we already have 0.03L (30mL) on the beaker, thats why we have to add "0.03" in the bottom. Now, we can include these last two equations on equation 4, so:

\(\frac{\frac{0.003-X}{0.03+Y}}{\frac{X}{Y+0.03}}=1.108\)(equation 7)

We have 2 unknows and 1 equation we need another equation to solve this. So, all X would be produced by the addition of HCl therefore "X" are the moles of HCl added and Y would be the volume of HCl, if we have a concentration of 0.11M for HCl we can use the molarity equation to relate "X" and "Y", so:

\(0.11M=\frac{X}{Y}\) (equation 8)

\(X=0.11*Y\) (equation 9)

Now, we can replace equation 9 in equation 7, so:

\(\frac{\frac{0.003-0.11*Y}{0.03+Y}}{\frac{0.11*Y}{Y+0.03}}=1.108\) (equation 10).

If we do some math we will obtain:

\(\frac{0.003-0.11*Y}{0.11*Y}=1.108\) (equation 11)

When we solve for "Y" we obtain a value of 0.012937 L or 12.937 mL.

I hope it helps!

Answer:

Number of moles = 0.057 × 10⁻⁷  mol

Explanation:

Given data:

Mass of SiO₂ = 3.4 × 10⁻⁷ g

Number of moles = ?

Solution:

Number of moles = mass/molar mass

Molar mass of SiO₂ = 60 g/mol

by putting values,

Number of moles =  3.4 × 10⁻⁷ g / 60 g/mol

Number of moles = 0.057 × 10⁻⁷  mol