What mass of the snack mix can you consume and still be within the fda limit?.

The specific heat capacity of the metal is 104.6 J/(g·°C), which is lower than the specific heat capacity of most metals, suggesting that the metal is likely a low heat capacity metal such as lead or tin.

The heat change of the metal can be calculated using the equation:
Q = mc∆T, where

Q = heat change,

m = mass of the water in grams

c = specific heat capacity of water in J/(g·°C)

ΔT = change in temperature of the water in °C

First, let's calculate the heat change of the water:

q_water = m_water × c_water × ΔT

where:

m_water = 250.0 g (mass of water)

c_water = 4.184 J/(g·°C) (specific heat capacity of water)

ΔT = 5.0 °C (change in temperature of water)

q_water = 250.0 g × 4.184 J/(g·°C) × 5.0 °C = 5230 J

This means that the water absorbed 5230 J of heat from the metal.

Since the calorimeter is insulated, the heat change of the metal is equal in magnitude but opposite in sign to the heat change of the water. Therefore, the heat change of the metal can be calculated as:

q_metal = -q_water = -5230 J

The negative sign indicates that the metal released 5230 J of heat to the water.

Now, we can use the mass of the metal to calculate its specific heat capacity, c_metal:

q_metal = m_metal × c_metal × ΔT

Solving for c_metal, we get:

c_metal = q_metal / (m_metal × ΔT)

Plugging in the values, we get:

c_metal = -5230 J / (10.0 g × -5.0 °C) = 104.6 J/(g·°C)

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Answer:

Q = 6.56 J

Explanation:

Given thatm

Mass of a sample of gold, m = 8.21 g

The temperature of the sample increase by 6.2°C.

We need to find heat added to the sample of gold. The heat required or added to raise the temperature is given by :

\(Q=mc\Delta T\)

c is the specific heat of gold, \(c=0.129\ J/g^{\circ} C\)

Putting all the values,

\(Q=8.21\times 0.129\times 6.2\\\\=6.56\ J\)

So, 6.56 J of heat is added to the sample of gold.

Collectively, electrons, muons, and neutrinos are called leptons.

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Toluene is a nonpolar molecule. Sucrose (table sugar) is a polar molecule with many hydroxyl groups. Isobutene is a nonpolar molecule .Ethylene glycol is a polar molecule.

Solubility is the ability of a substance to dissolve in a solvent to form a homogeneous mixture. It is an important property of substances, as it affects how they interact with each other in various chemical and biological processes. The solubility of a substance depends on the polarity of the molecule and the solvent in which it is being dissolved.

Water is a polar solvent, meaning it has a partial positive charge on one end and a partial negative charge on the other. Polar molecules, such as those with hydroxyl groups (-OH), tend to dissolve well in water because the partial charges on the solvent molecules can interact with the partial charges on the solute molecules, allowing them to dissolve. In contrast, nonpolar molecules, such as those with only carbon and hydrogen atoms, do not dissolve well in water, as the partial charges on the solvent molecules are not able to interact with the solute molecules.

Hexane, on the other hand, is a nonpolar solvent. It has no partial charges and does not interact with polar molecules. Nonpolar molecules, however, dissolve well in hexane because there is no charge separation in the solvent that can interfere with the interaction between the solute molecules.

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The color of the starch-iodine complex in Experiment 29: Rates of Chemical Reactions I is d. blue-black.

Experiment 29: Rates of Chemical Reactions I is one of the many experiments performed in a general chemistry laboratory that involves the determination of the rate of a chemical reaction experimentally. The experiment usually involves the reaction between sodium thiosulfate and hydrochloric acid that takes place in a beaker. This reaction causes the solution to become cloudy because of the formation of solid sulfur.

In this experiment, the reaction rate is measured using a stopwatch to time the duration of the reaction. The reaction rate is determined based on how long it takes for the solution to turn cloudy.The color of the starch-iodine complex in Experiment 29: Rates of Chemical Reactions I is blue-black.

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Using the change of base rule to find the logarithm to four decimal places. the correct answer is 11.4235.

To find the logarithm of 143.2 using the change of base rule, we can choose any base we prefer. Let's use base 10 and natural logarithm (base e) for this calculation.

First, we'll use the change of base formula, which states that log(base b) x = log(base c) x / log(base c) b. In this case, we'll calculate log(base 10) 143.2.

We'll use the natural logarithm (ln) as our intermediary step. The natural logarithm of 143.2 can be calculated as ln(143.2).

Using a calculator, we find that ln(143.2) is approximately 4.9628.

Next, we need to calculate log(base 10) e, which is the logarithm of e with base 10. Using a calculator, we find log(base 10) e is approximately 0.4343.

Finally, we apply the change of base formula:

log(base 10) 143.2 ≈ ln(143.2) / log(base 10) e
                ≈ 4.9628 / 0.4343
                ≈ 11.4235

Rounding to four decimal places, the logarithm of 143.2 using base 10 is approximately 11.4235.

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SN1 (Substitution Nucleophilic Unimolecular) and SN2 (Substitution Nucleophilic Bimolecular) are mechanisms that involve the substitution of a nucleophile for a leaving group. SN1 reactions proceed through a two-step process with a carbocation intermediate, while SN2 reactions occur in a single step with a concerted attack by the nucleophile.

E1 (Elimination Unimolecular) and E2 (Elimination Bimolecular) are mechanisms involving the removal of a leaving group and the formation of a double bond. E1 reactions proceed via a carbocation intermediate and involve the removal of a proton and a leaving group. E2 reactions occur in a single step with the simultaneous removal of a proton and a leaving group.

The dominance of a particular mechanism depends on factors such as the nature of the reactants, the leaving group, the nucleophile/base, the solvent, and the reaction conditions. Each mechanism has its own set of conditions under which it is more likely to occur.

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Answer:

The colder an object it, the slower the atoms are. This is the rule that affects how cold something can get. There is a limit of how cold something can get though. This is called absolute zero. And, actually, we've gotten very close to it. Scientists in Finland have cooled rhodium atoms to a 10th of a billionth of a degree above absolute zero.

False. Lipids are hydrophobic, which means they do not dissolve in water. This is because lipids are non-polar molecules and water is a polar solvent.

However, lipids can dissolve in other non-polar solvents such as oils and fats.
False. Lipids are actually hydrophobic, meaning they do not dissolve in water. Hydrophilic substances, on the other hand, do dissolve in water.

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Answer:

False

Explanation:

The outer core is a liquid and is made out of nickel and copper

Answer:

the answer is Energy will be exchanged, but matter will not be exchanged.

this because that in a closed system energy is able to be transfered but matter cant.

hope this helps

Answer:

b

Explanation:

none

Answer:

C9H13O3N

Explanation:

Take the atomic mass of C=12.0, H=1.0, O=16.0 and N=14.0.

We can draw a chart (please view this on desktop so to avoid spacing errors):

Let the mass of Epinephrine be 100g.

                             C                       H                          O                              N

mass(g) :              59                      7.15                    26.2                         7.65

no. of moles : 59/12 =4.9167     7.15/1 = 7.15     26.2/16=1.6375 7.65/14=0.5464

(n.o.m. = mass/molar mass)

Ratio:   4.9167/0.5464 =9    7.15/0.5464=13      1.6375= 3      0.5464/0.5464 =1

(divide the n.o.m. by the smallest n.o.m., which is 0.5464 in this case, take the whole numbers)

So, the empirical formula will be: C9H13O3N

But this is still not yet the molecular formula. We have to ensure the molar mass is 183g/mol. Multiply the empirical formula by n.

So, let the molecular formula of Epinephrine be (C9H13O3N)n.

12x9n + 1x13n + 16x3n + 14n = 183

108n + 13n + 48n + 14n = 183

183 n = 183.

n = 1

Hence, the molecular formula is C9H13O3N.

Answer:

Scientific Notation: 2.503 × 10⁶

Standard Form: 2,503,000

Hey there!

\(\mathsf{(3 \times 10^3) + (2.5 \times 10^6)}\)

\(\mathsf{= 3 \times 10^3 + 2.5 \times10^6}\)

\(\mathsf{10^3}\)

\(\mathsf{= 10 \times 10 \times 10}\)

\(\mathsf{= 100 \times 10}\)

\(\mathsf{\bf = 1,000}\)

\(\mathsf{10^6}\)

\(\mathsf{= 10 \times 10 \times 10 \times 10 \times 10 \times 10}\)

\(\mathsf{= 100 \times100 \times100}\)

\(\mathsf{= 10,000\times100}\)

\(\mathsf{= \bf 1,000,000}\)

\(\mathsf{= 3\times 1,000 + 2.5 \times 1,000,000}\)

\(\mathsf{3\times1,000}\)

\(\mathsf{\bf = 3,000}\)

\(\mathsf{2.5 \times 1,000,000}\)

\(\mathsf{\bf = 2,500,000}\)

\(\mathsf{3,000 + 2,500,000}\)

\(\mathsf{= \bf 2,503,000}\)

\(\boxed{\boxed{\large\textsf{Answer: } \mathsf{ \bf 2,503,000 \ or \ 2.503 \times 10^6}}}\huge\checkmark\)

\(\large\textsf{Good luck on your assignment and enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

Answer:

The independent variable effects the dependent variable.

Explanation:

The independent variable Is what you change whereas the dependent variable would change because of that.

for example, the indipendent variable could be how much you water a plant in ml each day, and the dependent variable would be how tall each plant grown]s with that water doseage per day.

Answer:

0.3651 moles

Explanation:

We know that the smaller mass of sugar c 12 aged 22011 is 342.3 grams per mole and the number of moles will be minus 125 grams, divided by molar mass 342.3 grams per mole, and this will be 0.3651 moles.

Based on the given information, the true statement about the time indicated by the blue arrow is: (c) The rate of the forward reaction (N₂O₄ formation) is equal to the rate of the reverse reaction (NO₂ formation).

The graph shows the relative amounts of NO₂ and N₂O₄ over time, and the point indicated by the blue arrow represents a state of equilibrium. In an equilibrium state, the forward and reverse reactions occur at equal rates.

The concentrations of NO₂ and N₂O₄ reach a constant value, indicating that the conversion of NO₂ to N₂O₄ and the conversion of N₂O₄ to NO₂ are occurring at the same rate.

Option a suggests that NO₂ molecules are no longer reacting, which is incorrect as the reaction is still ongoing at equilibrium. Option b suggests that the reactant has been completely used up, which is not the case in an equilibrium state. Option d refers to the activation energy, which is unrelated to the equilibrium state. Therefore, option c is the correct choice.

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Adding potassium chloride (KCl) to the external medium would likely cause the resting membrane potential of the neuron to change.

The resting membrane potential of a neuron is primarily determined by the concentration gradient of ions across the cell membrane and the selective permeability of the membrane to different ions. In a typical neuron, the resting membrane potential is largely influenced by the concentration gradient and permeability of potassium ions.

Adding potassium chloride (KCl) to the external medium increases the concentration of potassium ions in the extracellular environment. This change in potassium ion concentration can affect the resting membrane potential of the neuron.

If the external concentration of potassium ions increases significantly, the concentration gradient across the cell membrane may be altered. This can lead to a change in the membrane potential, potentially depolarizing or hyperpolarizing the neuron.

Additionally, the change in the external concentration of potassium ions can affect the permeability of the neuron's membrane to potassium ions. If the permeability to potassium ions changes, it can further impact the resting membrane potential.

In summary, adding potassium chloride to the external medium can alter the resting membrane potential of a neuron, depending on the concentration of potassium ions and the permeability of the neuron's membrane to potassium ions. The specific effect on the resting membrane potential would require more information about the concentration of KCl and the characteristics of the neuron.

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Answer:

Magnesium sulfide

Explanation:

Chemical formula- MgS

The compressibility of a gas is determined by the relationship between its volume and pressure measurements, with the compressibility factor providing a quantitative measure of this relationship and deviations from ideal gas behavior.

The compressibility of a gas is defined by the relationship between its volume and pressure measurements. Compressibility is a property that describes how easily a gas can be compressed or expanded under the influence of external pressure.

When a gas is subjected to an increase in pressure, its volume tends to decrease, indicating compressibility. On the other hand, when the pressure on a gas is reduced, its volume tends to increase, indicating expansibility. The compressibility factor (Z) is commonly used to quantify the compressibility of a gas.

Mathematically, compressibility is expressed by the equation:

Z = PV/RT,

where Z is the compressibility factor, P is the pressure, V is the volume, R is the ideal gas constant, and T is the absolute temperature.

The compressibility factor provides information about deviations from ideal gas behavior. For an ideal gas, Z equals 1 at all pressures and temperatures. However, real gases often deviate from ideal behavior due to intermolecular interactions and non-ideal conditions.

At low pressures and high temperatures, most gases behave close to ideal gas behavior and have a compressibility factor close to 1. However, at high pressures and/or low temperatures, gas molecules come closer together, and intermolecular interactions become significant, causing deviations from ideal behavior and resulting in a compressibility factor different from 1.

By studying the compressibility factor as a function of pressure and temperature, one can gain insights into the behavior of gases under various conditions, including phase transitions, critical points, and the presence of attractive or repulsive intermolecular forces.

In summary, the compressibility of a gas is determined by the relationship between its volume and pressure measurements, with the compressibility factor providing a quantitative measure of this relationship and deviations from ideal gas behavior.

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Answer:

Salt lowers the freezing point of water, which makes the melted snow on the road less likely to form ice.

Answer:

A

Explanation:

Edge.

Answer: 0.08 M

Explanation:

\(\text{molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}\\\\\text{molarity}=\frac{0.25}{3.00}\\\\\text{molarity}=\boxed{0.08 \text{ M}}\)

Answer:

A physical change is any change in matter that involves the substance going from one physical state to another. The reference to a physical state involves solids, liquids, and gases.

Explanation:

Total random kinetic energy of all the molecules in one mole of hydrogen at temperature of 300 K is 3741.3 J. Speed with which a mole of hydrogen have to move so that kinetic energy of the mass is equal to the total random kinetic energy of its molecules is 7482.6 m/s

According to kinetic theory, average kinetic energy of gas molecules depends on the absolute temperature. At given temperature, molecules of all the gases have same average kinetic energy".

Kinetic energy = 3/2 * R T

= 3/2 * 8.314 * 300

= 3741.3 J

KE = 1/2 * m v²

v² =  2 KE/m

= 2* 3741.3 /1

Speed =  7482.6 m/s

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1.189 x 10⁻¹² kg is lost when uranium-235 undergoes fission

The fission of uranium-235 releases 107 kJ/mol

We know that the formula for mass-energy equivalence is

                                              E=mc²

c = 3 x 10⁸ m/s

107000 J= m x  (3 x 10⁸ m/s)²

107000 = m x 9 x 10¹⁶

m = 1.189 x 10⁻¹² kg

In the fission of 1 mole of uranium,   1.189 x 10⁻¹² kg is lost in the reaction

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Answer:

edmentum sample answer

Explanation:

The percent by mass of  \(NaHCO_3\) in the original mixture is approximately 65.99%.

To find the percent by mass of \(NaHCO_3\) in the original mixture, we need to calculate the mass of  \(NaHCO_3\) in the sample and then determine the percentage.

1. Calculate the moles of \(CO_2\) produced:

First, we need to convert the mass of  \(CO_2\)  produced (0.561 g) to moles. We'll use the molar mass of  \(CO_2\)  to do this.

Molar mass of  \(CO_2\)  = 44.01 g/mol

moles of  \(CO_2\)  = mass of  \(CO_2\)  / molar mass of  \(CO_2\)

            = 0.561 g / 44.01 g/mol

            = 0.01274 mol (approximately)

2. Calculate the moles of  \(NaHCO_3\):

Since the balanced chemical equation for the reaction between  \(NaHCO_3\) and HA (assuming HA is an acid) is not provided, we can't directly determine the stoichiometry. However, we can use the information given to determine the moles of  \(NaHCO_3\) by assuming that all the  \(CO_2\)  produced comes from the  \(NaHCO_3\).

moles of  \(NaHCO_3\) = moles of  \(CO_2\)

               = 0.01274 mol (approximately)

3. Calculate the mass of  \(NaHCO_3\):

Now, we can calculate the mass of  \(NaHCO_3\) using its molar mass.

Molar mass of  \(NaHCO_3\) = 84.01 g/mol

mass of  \(NaHCO_3\) = moles of  \(NaHCO_3\) × molar mass of  \(NaHCO_3\)

              = 0.01274 mol × 84.01 g/mol

              = 1.067 g (approximately)

4. Calculate the percent by mass of  \(NaHCO_3\):

The percent by mass is calculated by dividing the mass of  \(NaHCO_3\) by the total mass of the mixture and multiplying by 100.

percent by mass of  \(NaHCO_3\) = (mass of  \(NaHCO_3\) / total mass of the mixture) × 100

                         = (1.067 g / 1.62 g) × 100

                         = 65.99% (approximately)

Therefore, the percent by mass of  \(NaHCO_3\) in the original mixture is approximately 65.99%.

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(a)When we use copper wire of gauge 24 AWG, the diameter of the wire is 0.0201 inches. The cross-sectional area of the wire can be calculated using the formula:

(b)The area of the diode can be determined using the formula:

(c)The cross-sectional area of the current path can be determined using the formula:

Cross sectional is a study to study the correlation between risk factors by approaching or collecting data at one time only. A cross-sectional descriptive survey can be used to assess how often, extensively, or otherwise, a variable occurs across a given demographic. The study was conducted using a cross-sectional study design. The reason for using a cross-sectional study design is because in this study design all variables are measured and observed at the same time (one point in time) so that it makes it easier for researchers to conduct research.

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For each combination, we can determine whether it can be a buffer or not: Weak acid and its conjugate base, Weak base and its conjugate acid can be buffer, Strong acid and strong base, Weak acid and strong base, Weak base and strong acid can not be a buffer.

Weak acid and its conjugate base: This combination can be a buffer, as it contains a weak acid and its corresponding conjugate base. When a strong acid is added to the solution, the conjugate base will react with the acid to form the weak acid, thus minimizing the change in pH.

Weak base and its conjugate acid: This combination can also be a buffer, as it contains a weak base and its corresponding conjugate acid. When a strong base is added to the solution, the conjugate acid will react with the base to form the weak base, minimizing the change in pH.

Strong acid and strong base: This combination cannot be a buffer, as it does not contain a weak acid or a weak base. When a strong acid or strong base is added to the solution, it will completely ionize and cause a large change in pH.

Weak acid and strong base: This combination cannot be a buffer, as the weak acid will be completely consumed by the strong base, resulting in the formation of the conjugate base and a large change in pH.

Weak base and strong acid: This combination also cannot be a buffer, as the weak base will be completely consumed by the strong acid, resulting in the formation of the conjugate acid and a large change in pH.

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The peptide bond between which two amino acid residues is cleaved by HIV protease will be "Phenylalanine Proline".

Whenever the carboxyl group with one molecule combines at all with  the amino group of the other molecule, a molecule of water is released, and a peptide bond is created among the two molecules (\(H_{2} O\))

The HIV protease breaks down large precursor proteins towards smaller ones. A new HIV virus is created when these smaller proteins interact with both the genetic material of HIV. HIV cannot replicate when protease is blocked by protease inhibitors (PIs).

HIV protease breaks down freshly created polyproteins specifically, Gag as well as Gag-Pol at nine cleavage sites to produce the mature protein components of such an HIV virion, the infectious version of the virus beyond the host cell. HIV virions do not spread disease in the absence of an efficient HIV protease.

Therefore, the peptide bond between which two amino acid residues is cleaved by HIV protease will be "Phenylalanine Proline".

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