what quantity of heat (in kj) will be released if 0.264 mol of nh₃ reacts according to the following chemical reaction? 4 nh₃ (g) o₂ (g) → 2 n₂h₄ (g

(b)

only CaCO3

Explanation:

Given:

Alkaline solution= 2 x 10^-4 M in CO32-Pool water was originally 4 x 10^-3 M in Mg2+, 6 x 10^-4 M in Ca2+ and 8 x 10^-7 M in Fe2+

Precipitate should be of:

MgCO3, CaCO3 and FeCO3

We know that:

Mg2+ + CO32- → MgCO3Ca2+ + CO32- → CaCO3Fe2+ + CO32- → FeCO3Thus, for MgCO3 to form, [CO32-] should be 4 x 10^-3 M which is not possible in the given question.

For CaCO3 to form,[CO32-] should be 6 x 10^-4 M which is possible.

So, precipitate should be only CaCO3.

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Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.

To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:

moles = concentration × volume

Given:

Concentration of AgNO3 solution = 0.500 M

Volume of AgNO3 solution = 150 mL

First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).

1 L = 1000 mL

Therefore, the volume of the AgNO3 solution in liters is:

150 mL × (1 L / 1000 mL) = 0.150 L

Now we can calculate the moles of AgNO3 using the formula:

moles = concentration × volume

moles = 0.500 M × 0.150 L

moles = 0.075 mol

So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.

Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).

From the balanced chemical equation:

2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)

We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.

Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:

moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol

To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:

Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol

mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4

mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g

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Ethyl acetate dissolves trans-1 2-dibenzoyl ethylene because of their similar polarities.

Ethyl acetate is a polar molecule with a dipole moment of 1.78 D (Debye), while trans-1 2-dibenzoyl ethylene is also polar with a dipole moment of 2.5 D (Debye). Polar molecules are attracted to other polar molecules through dipole-dipole interactions, which allows them to dissolve in each other. This is why ethyl acetate is able to dissolve trans-1 2-dibenzoyl ethylene.

In summary, the combination of ethyl acetate's polar and nonpolar characteristics allows it to dissolve a range of different compounds, including trans-1 2-dibenzoyl ethylene.

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Answer:

16 is the answer

Explanation:

0.5 x 32 = 16

Answer:

An exothermic releases the heat.

Answer:

to answer your question, an exothermic reaction releases energy.

Explanation:

An exothermic reaction is a chemical reaction that releases energy in the form of heat, light, or sound. It is a reaction that releases energy to the surroundings.:)

The placement of electrons in orbitals surrounding an atomic nucleus is known as electronic configuration

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Lysine can undergo decarboxylation to produce the end-product cadaverine.

Decarboxylation is a chemical reaction where a carboxyl group (-COOH) is removed from a molecule, resulting in the release of carbon dioxide (CO2). In the case of lysine, the decarboxylation reaction occurs at the carboxyl group (COOH) of the amino acid. The reaction can be catalyzed by enzymes known as decarboxylases. The chemical equation for the decarboxylation of lysine to cadaverine can be represented as follows:

H2N(CH2)4COOH (Lysine) → H2N(CH2)5NH2 (Cadaverine) + CO2

In this reaction, the carboxyl group (COOH) in lysine is removed, resulting in the formation of cadaverine, which has one less carbon atom and one less oxygen atom than lysine. It's important to note that decarboxylation reactions often require specific reaction conditions such as appropriate pH, temperature, and the presence of specific enzymes. Without these conditions, decarboxylation may not occur or proceed at a significant rate.

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387.27 K temperature will the reaction proceed 6.00 times faster than it did at 337 K.

k2 is 6 times k1 and hence k2/k1 = 6

we have ln(k2/k1) = Ea/R (1/T1- 1/T2)

ln(6) = 38670/8.314 x( 1/337 -1/T2)

0.00038522 = (1/337 -1/T2)

1/T2 = 0.0033525

T2 = 387.27 K

In chemistry and physics, activation electricity is the minimal amount of electricity that has to be supplied for compounds to result in a chemical reaction. The activation energy of a reaction is measured in joules per mole, kilojoules in keeping with mole, or kilocalories consistent with mole.

Activation strength is described as the minimum quantity of strength required via a reacting molecule to get transformed into a product. it may additionally be defined because the minimal amount of energy had to prompt or energize molecules or atoms in an effort to go through a chemical reaction or transformation. In transition-state theory, activation electricity is the distinction in electricity content material between atoms or molecules in an activated or transition-country configuration and the corresponding atoms and molecules in their initial configuration.

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Complete Question:

A certain reaction has an activation energy of 38.67 kJ/mol. At what Kelvin temperature will the reaction proceed 6.00 times faster than it did at 337 K?

Answer:

basalt

Explanation:

it’s rough on skin

The orbital diagram of the P^3- anion is shown in the orbital diagram attached.

An orbital diagram is a visual representation of where electrons are located within an atom or ion. A series of boxes or circles is used to symbolize an atomic orbital, which is the region of space around the nucleus where electrons are most likely to be found.

Each box or circle, which stands for an atomic orbital, has an image of an electron inside it, represented by an arrow.

Orbital diagrams can be used to visualize and understand the electronic structure of atoms and ions, as well as to predict their chemical and physical properties.

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Answer:

Argon has the chemical formula Ar. Argon has 18 protons and 22 neutrons in its nucleus giving it an Atomic Number of 18 and an atomic mass of 40. Argon is a Noble Gas. Argon is a gas at room temperature.

Explanation:

Answer:

Postulates of Dalton's Atomic Theory:

1) Atoms can neither be created nor destroyed.

2) During chemical reaction, atoms combine or separate or re-arrange. They combine in simple ratios.

3) All elements are composed of the indivisible particles called atoms.

4) Atoms of a particular element are identical. They have the same mass and volume.

Postulates of modern atomic theory:

1) All matter is composed of atoms.

2) Atoms consist of protons, electrons and neutrons.

3) Atoms of an element may differ in masses. (as in isotopes)

4) The ratio in which elements combine may not be simple.

Similarities:

1) All elements/matter are/is composed of atoms.

2) Atoms can neither be created nor destroyed.

3) During chemical reactions, atom combine or separate or rearrange.

Differences:

1) Dalton's theory said that atoms are indivisible particles but modern theory denies it and calls atom a divisible particle consisting of sub-atomic particles, protons, electrons and neutrons.

2) Dalton's theory said that atoms of the same element have same mass and volume but according to modern theory, it is said that atoms of the same element can differ in mass (as in isotopes).

3) Dalton said that atoms combine in simple ratio but modern theory denies it.

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Hope this helped!

The Hall coefficient (RH) in this case is approximately -3.01 * 10^-6 C^-1 cc (rounded to three significant figures in exponential notation).

The Hall coefficient (RH) is a parameter used to describe the behavior of charge carriers in a material when subjected to a magnetic field. It is given by the equation RH = 1/(e * p) where e is the elementary charge and p is the total charge carrier density. In this case, we are given the acceptor doping concentration (Na) and the donor doping concentration (Nd) in units of /cc.

To calculate the Hall coefficient, we need to determine the total charge carrier density (p). The total charge carrier density can be calculated as the difference between the acceptor doping concentration and the donor doping concentration: p = Na - Nd.

Given the acceptor doping concentration Na = 4.18 * 10^15/cc and the donor doping concentration Nd = 9.40 * 10^15/cc, we can substitute these values into the equation to find p:

p = Na - Nd
  = (4.18 * 10^15/cc) - (9.40 * 10^15/cc)
  = -5.22 * 10^15/cc

Now, we can substitute the value of p into the Hall coefficient equation:

RH = 1/(e * p)
    = 1/(1.60 * 10^-19 C * (-5.22 * 10^15/cc))
    = -3.01 * 10^-6 C^-1 cc

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The air pressure at the top of Mount Everest in atmospheres is equal to 0.2618 atm.

In Science, pressure can be defined as a measure of the force exerted per unit area of an object or physical body. This ultimately implies that, pressure is usually measured in Newton per meter square and calculated by using this formula:

P = F/A

Where:

Generally speaking, air pressure can be measured in other units such as the following:

In order to convert the value of pressure in millimeters of mercury (mm Hg) to atmosphere, we would divide by 760 as follows:

Air pressure = 199/760

Air pressure = 0.2618 atm.

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Answer: 0.261842

Explanation:

An ionic compound that uses neon is that neon does not easily form ionic compound because neon belongs to noble gases and they are extremely stable and their reactivity is practically nil.

Neon is belongs to group 18 which is noble gases. noble gases have 8 valence electron in the outer most shell and that follow the octet rule. noble gases are extremely stable in the periodic table. so, they are very less reactive or we can say that non reactive gases.

Thus, An ionic compound that uses neon is that neon does not easily form ionic compound because neon belongs to noble gases and they are extremely stable and their reactivity is practically nil.

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A chemistry student should way out 57.56 grams of pentane for the experiment he is willing to perform.

Given,

Density of pentane = 0.626 grams/ml

Volume of the pentane = 60 ml

The above data can be used to find the mass of the pentane by using the relation between density, mass and volume which is given as:

Density = mass of substance/ volume of substance

⇒ Mass of pentane = Density of pentane X Volume of pentane

Substituting the values we get,

Mass of pentane = 0.626g/ml X 60ml = 57.56 grams

Hence, to perform the experiment the chemistry student should weigh 57.56 grams of pentane.

The given question is incomplete and the complete question is given as,

A chemistry student needs 40.0 mL of pentane for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of pentane is 0.626 g cm^3. Calculate the mass of pentane the student should weigh out.

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371.2 g ,The maximum mass of a product that can be produced in a chemical process is known as the theoretical yield. The balanced chemical equation can be used to calculate it. the limiting reactant's mass and relative formula mass, and. the product's relative formula mass.

The quantity of moles of a product created in relation to the amount of reactant consumed during a chemical reaction is measured in chemistry as yield, also known as reaction yield.

The maximum mass of a product that can be produced in a chemical process is known as the theoretical yield. The balanced chemical equation can be used to calculate it. the limiting reactant's mass and relative formula mass, and. the product's relative formula mass.

The following formula represents the theoretical yield of our reaction: grams product = grams reactant x (1 mol reactant/molar mass of reactant) x (mole ratio product/reactant) x (molar mass of product/1 mol product). The molar mass of H2 gas is equal to 2 grams.

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The effect on the rate of reaction for this SN1 process when doubling the concentration of t-butyl bromide is an increase by a factor of 2, while quadrupling the concentration of methanol will have no impact on the rate.

In the solvolysis of t-butyl bromide in methanol, t-butyl methyl ether is produced through an SN1 reaction. When discussing the rate of an SN1 reaction, it's important to note that it is a two-step process involving the formation of a carbocation intermediate. The rate-determining step (RDS) is the first step, which involves the ionization of t-butyl bromide to form a carbocation and a bromide ion.

The rate of an SN1 reaction is directly proportional to the concentration of the substrate (t-butyl bromide) and independent of the concentration of the nucleophile (methanol). Thus, doubling the concentration of t-butyl bromide will double the rate of reaction, as it increases the availability of the substrate for ionization.

On the other hand, quadrupling the concentration of methanol will not affect the rate of the reaction, as it is not involved in the RDS. Methanol reacts with the carbocation in the second step, which is a fast step and does not determine the overall rate.

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The elements do all the “s” orbital span (go across) in each period is 2. Thus option a is correct.

Elements are defined as  a pure substance made up of only one sort of atom with the same number of protons in its nucleus.

It can also be defined as the a substance that can't be broken down into anything else.

Sublevels are defined as a quantum theory-defined energy level Sublevels are energies associated with electrons in chemistry.

There are mainly four sublevels

Thus, the elements do all the “s” orbital span (go across) in each period is 2. Thus option a is correct.

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To calculate the concentration of the iron sample by using a spectrophotometric method, it is necessary to dilute the sample. The volume to which the sample should be diluted is a crucial question in achieving the most accurate result.

The process involves diluting the sample, and the concentration must be calculated to determine the precise result of the dilution. This question can be answered by calculating the uncertainty and identifying the value of the uncertainty. The value with the lowest uncertainty will be the best value to choose. The volume with the lowest uncertainty will be the ideal volume to dilute the 5 ml aliquot of the iron sample to achieve a result with the minimum level of uncertainty.
To determine the optimal volume for dilution, the uncertainty should be calculated.
This can be done by using the equation for propagation of uncertainty, which states that the uncertainty of the result is equal to the square root of the sum of the squares of the uncertainties of the individual components. When calculating the uncertainty of the diluted sample, the uncertainty of the initial sample and the uncertainty of the diluent must be considered. The uncertainty of the initial sample can be calculated using the calibration curve. As the expected iron content is 40-60%, the concentration of the sample is expected to be 8-12 ppm. The uncertainty of the calibration curve is given by the standard deviation of the calibration standards.
The diluent has a negligible uncertainty. The uncertainty of the diluted sample will be lower if a larger volume is used for dilution because the relative contribution of the uncertainty of the initial sample will decrease. However, the uncertainty of the measurement will increase if the sample is diluted too much because the concentration of the analyte will be too low to be detected accurately. A 100 mL volume is a good choice because it balances the need for sufficient dilution to reduce the uncertainty of the initial sample with the need for sufficient concentration to allow for accurate detection of the analyte.

The volume of the sample that should be diluted is 5 ml. The minimum level of uncertainty is obtained at a dilution of 100 ml. When the volume of the diluent is greater than 100 ml, the uncertainty of the measurement increases, and when the volume of the diluent is less than 100 ml, the uncertainty of the measurement also increases. Thus, a 100 ml volume of diluent is the ideal volume to minimize the uncertainty in the analysis of iron.

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NaNO3 has a solubility of 80 grams per 100 grams of water at 10oC. (It seems to be somewhat less than 80 grams, but after rounded off, it's practically 80 grams.)

• Assume we just required 60 mL of NaNO3 solution at 10oC. Further Information: Because the solubility of solids rises with temperature, solutes whose curves go higher with increasing temperature are often solids.

Thus the solution in issue is saturated, or even somewhat supersaturated — but you're probably correct.

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The reaction of silver nitrate with copper is a substitution reaction. We have copper in its free state, Cu, and we have silver nitrate which has the formula AgNO3. The copper replaces the silver obtaining the following reaction:

The products obtained are copper nitrate and silver.

The word equation will be:

Answer:

Correct answer-C 5.3g

Explanation:

Molarity = no. of moles of solute/ volume of of solution in litre

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,so the mass of 0.03125 moles of AgNO3 = 0.03125×169.87= 5.3084g

The grams of AgNO₃ are needed to prepare 0.125 M solution in 250 mL of water is 5.3 grams.

Moles is a unit which is used to define any amount and it is calculated as:

n = W/M, where

W = required mass

M = molar mass

Given molarity of AgNO₃ = 0.125 M

Volume of water = 250mL = 0.25L

moles (n) from the molarity (M) will be calculated as:

n = M × V

n = (0.125)(0.25) = 0.0312 moles

Now we calculate the mass of AgNO₃ by using the above formula as:

W = (0.0312mol)(169.87g/mol)

W = 5.30 g

Hence option (c) is correct.

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Formation of precipitate/colored complex, gas evolution, pH change.Ions that do not participate in a reaction and remain unchanged are called spectator ions.

At the point when two arrangements are blended during subjective inorganic investigation, there are a few perceptions that can show the event of a response. One perception is the development of an encourage or a hued complex, which can be a sign of the development of another compound because of a substance response.

One more perception is the development of gas, which can happen because of the arrival of gas from a reactant, for example, the creation of carbon dioxide gas from the response of a corrosive with a carbonate or bicarbonate.

Furthermore, an adjustment of the pH of the arrangement can likewise show the event of a response, as acidic or fundamental arrangements can influence the dissolvability and reactivity of particles.

Onlooker particles are particles that don't partake in a compound response and stay unaltered all through the response. These particles can be available in an answer when a response, however they don't influence the result of the response or respond with different particles.

At the end of the day, observer particles are not engaged with the substance condition for the response and are thusly excluded while composing a net ionic condition.

An illustration of an onlooker particle is a metal cation in an answer of an ionic compound that stays unaltered when the compound responds with a corrosive, delivering an alternate ionic compound and water. The metal cation isn't engaged with the response and is viewed as an observer particle.

Onlooker particles are essential to consider in subjective inorganic examination since they can influence the dissolvability and reactivity of particles in an answer, however they don't add to the distinguishing proof of particles present in an example.

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Answer:

127,236 kj of heat

Explanation:

This is the final answer

By definition of noble gases, neon does not easily form an ionic bond because it belongs to the group of noble or inert gases, so its reactivity is practically nil.

Noble gases are not very reactive, that is, they practically do not form chemical compounds. This means that they do not react with other substances, nor do they even react between atoms of the same gas, as is the case with diatomic gases such as oxygen (O₂).

The chemical stability of the noble gases and therefore the absence of spontaneous evolution towards any other chemical form, implies that they are already in a state of maximum stability.

All chemical transformations involve valence electrons, they are involved in the process of covalent bond formation and the formation of ions. Therefore, the practically null reactivity of the noble gases is due to the fact that they have a complete valence shell, which gives them a low tendency to capture or release electrons.

Since the noble gases do not react with the other elements, they are also called inert gases.

Neon does not easily form an ionic bond because it belongs to the group of noble or inert gases, so its reactivity is practically nil.

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