what social science principles can be applied to online video gaming?

Work = Exergy Decrease / Exergetic Efficiency

= 300 kJ/kg / 0.65

= 462.3 kJ/kg

Work is an activity that involves physical or mental effort and is often done in exchange for money or other rewards. It can be a job, a hobby or something that someone does out of passion or for personal fulfillment. Work can have many different forms, from the traditional 9-5 job to freelancing and other forms of self-employment. Work can also involve volunteering, caring for a family member or participating in an organized activity. Work can help people build skills, gain experience, and increase their confidence.

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Solution :

The correct size of the arc of a welding process depends upon the application and the electrode. As a rule, the arc length should not be more than a diameter of the core of the electrode.

As for the electrode of diameter size of 5/32" or 4 mm, the arc length should be more than its core diameter. Also for 5/32 " diameter electrode, the welding time for the one electrode must be one minute as well as the length of the weld be the same as the length of the electrode consumed.  

Answer: Technician B.

Explanation: Please vote brainliest.

Explanation:

I think both are correct.

Narrow seats have less area, therefore, given the same pressure the narrow seats will have greater force.

If the springs are of equal pressure, the larger valve must have narrower seats such that the seat AREA is the same between the two valves. If the area is the same and the pressure is the same, the force will be the same.

Answer:

The volume of water needed to be removed = 4301100 lbs/ [ 62.43 × 27] = 2551.66.

Explanation:

The first thing to do right now is to determine the weight of soil solids. This can be gotten below as:

The weight of soil solids = 1 × 118 × 27 = 3186 lbs.

Also, there is the need to determine the value of the water that we have and the one that is needed. This is calculated below as:

The weight of water needed = 3186 × 6% = 191.16 lbs.

The water available = 3186 × 7% = 223.02%.

The next thing to determine is the value for the total BCY of available of soil.

Thus, the total BCY of available of soil = [ 3186 + 223.02 ]/ 2800 × 135000 = 3409.02/ 2800 = 1.217551 BCY × 135000 = 164,363.46 BCY.

The last thing to do here is to determine the value for the weight and  volume of water to be removed.

The weight of water to be removed = [ 223.02 lbs -  191.16 lbs] × 135,000 = 4301100 lbs

The volume of water needed to be removed = 4301100 lbs/ [ 62.43 × 27] = 2551.66.

Answer:

the order higher is 3p79g5t88=yv5379

The given question is incomplete. The complete question is as follows.

Steam is contained in a closed rigid container with a volume of 1 m3. Initially, the pressure and temperature of the steam are 10 bar and 500°C, respectively. The temperature drops as a result of heat transfer to the surroundings. Determine

(a) the temperature at which condensation first occurs, in \(^{o}C\),

(b) the fraction of the total mass that has condensed when the pressure reaches 0.5 bar.

(c) What is the volume, in \(m^{3}\), occupied by saturated liquid at the final state?

Explanation:

Using the property tables

  \(T_{1} = 500^{o}C\),    \(P_{1}\) = 10 bar

  \(v_{1} = 0.354 m^{3}/kg\)

(a) During the process, specific volume remains constant.

  \(v_{g} = v_{1} = 0.354 m^{3}/kg\)

  T = \((150 - 160)^{o}C\)

Using inter-polation we get,

      T = \(154.71^{o}C\)

The temperature at which condensation first occurs is \(154.71^{o}C\).

(b) When the system will reach at state 3 according to the table at 0.5 bar then

  \(v_{f} = 1.030 \times 10^{-3} m^{3}/kg\)

  \(v_{g} = 3.24 m^{3} kg\)

Let us assume "x" be the gravity if stream

   \(v_{1} = v_{f} + x_{3}(v_{g} - v_{f})\)

   \(x_{3} = \frac{v_{1} - v_{f}}{v_{g} - v_{f}}\)

               = \(\frac{0.3540 - 0.00103}{3.240 - 0.00103}\)

               = 0.109

At state 3, the fraction of total mass condensed is as follows.

  \((1 - x_{5})\) = 1 -  0.109

                = 0.891

The fraction of the total mass that has condensed when the pressure reaches 0.5 bar is 0.891.

(c) Hence, total mass of the system is calculated as follows.

     m = \(\frac{v}{v_{1}}\)

         = \(\frac{1}{0.354}\)

         = 2.825 kg

Therefore, at final state the total volume occupied by saturated liquid is as follows.

     \(v_{ws} = m \times v_{f}\)

                 = \(2.825 \times 0.00103\)

                 = \(2.9 \times 10^{-3} m^{3}\)

The volume occupied by saturated liquid at the final state is \(2.9 \times 10^{-3} m^{3}\).

The heat transferred to and the work produced by the steam during this process  is 13781.618 kJ/kg

The Net Change in Enthalpy will be:

= m ( h2 - h1 ) = 11.216 ( 1755.405 - 566.78 ) = 13331.618 kJ/kg

Work Done (Area Under PV curve) = 1/2 x (P1 + P2) x ( V1 - V2)

= 1/2 x ( 75 + 225) x (5 - 2)

W = 450 KJ

From the First Law of Thermodynamics, Q = U + W

So, Heat Transfer = Change in Internal Energy + Work Done

= 13331.618 + 450

Q = 13781.618 kJ/kg

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The square feet of roof area that can be covered by one square of these shakes is 75%. The correct option D.

The condition of the atmosphere, including its temperature, pressure, wind, humidity, precipitation, and cloud cover, is referred to as the weather. It is distinct from climate, which is the average of all weather events for a certain location over a period of around 30 years.

Given Data,

Size of shakes = 24” x 3/8”

Weather exposure = 7 ½”

As explained above, 24” x 3/8” shakes with 7 ½” weather exposure has coverage of 75 square feet per square of shakes. 75 square feet

Therefore, the correct option D. 75%.

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The question is incomplete. Your most probably complete question is given below:

The shakes will be applied with an average spacing of '/>" between shakes, and the weather exposure will be 71/2". Look at the shake coverage table. According to the information in this table, approximately how many square feet of roof area can be covered by one square of these shakes?

Answer:

----------

Explanation:

Ancient machines have paved the way for improvement by being the foundation for change. these machines made it possible to find flaws so in the next generations, they could fix, develop, and produce better quality machines. eventually this process has reached the present time but after today, the process will continue to produce even better quality machines than the time before. I hope this helps!

Since tech A says that black exhaust indicates a very rich-running engine is false and since tech b says that white exhaust can indicate coolant in the exhaust, Tech B  is correct.

Black exhaust smoke is known to be one that can show up if the vehicle is said to be burning too much fuel.

Note that this situation could be as a result of  a clogged air filter, the malfunctioning of the fuel injection system, a blocked manifold, or other forms of issues.

Therefore, Since tech A says that black exhaust indicates a very rich-running engine is false and since tech b says that white exhaust can indicate coolant in the exhaust, Tech B  is correct.

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An articulated support is a type of beam support that restrains a beam from moving in all directions except one rotational direction. Determining the support reactions of a beam with an articulated support can be done using the following steps:

Step 1: Draw a free-body diagram of the beam that indicates the forces acting on the beam.Step 2: Write down the equilibrium equations that relate the forces and moments acting on the beam to the support reactions. For a beam with an articulated support, there will be two unknown support reactions: the vertical reaction and the rotational reaction.

Step 3: Solve the equilibrium equations for the unknown support reactions.Step 4: Check the solution by verifying that the forces and moments acting on the beam are in equilibrium. This can be done by substituting the values of the support reactions into the equilibrium equations and verifying that they are satisfied.

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A forecast is a prediction of what will occur in the future. This process can be uncertain due to the numerous variables and factors that can affect the outcome.

However, a strategic approach to forecasting can help support effective planning and decision-making. By analyzing trends and identifying potential risks and opportunities, a strategic forecast can provide valuable insights into the future, which can inform and guide strategic planning efforts. Therefore, all of the given answer choices are correct as a forecast group supports strategic planning and predicts what will occur in the future, despite the uncertain nature of the process.

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a. True. Because these activities require very little processing power. A basic processor such as an Intel Celeron or AMD Athlon will be more than sufficient for most web browsing and email-checking tasks.

A processor is a part of a computer that carries out operations and carries out instructions. It is in charge of carrying out the calculations and data manipulation necessary for a computer to work. It is the most crucial part of a computer system and is frequently referred to as the "brain" of the computer.

The processor contains an Arithmetic Logic Unit (ALU) which is responsible for carrying out arithmetic and logical operations. It also contains a Control Unit (CU) which is responsible for managing the flow of instructions and data to and from the various components of the computer.

The processor also contains a number of registers which are used to store intermediate results during calculations. The processor also contains several cache levels, which are used to store frequently accessed data and instructions in order to speed up the execution of programs.

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Design and simulation of a 14 kA impulse current generator can be done using the following steps:Step 1: Calculation of Parameters for Generator DesignThe parameters that need to be calculated for the generator design are:Inductance of the generator (L)Resistance of the generator (R)Capacitance of the generator (C)The inductance of the generator can be calculated as follows:L = Vt / i, where Vt is the voltage across the terminals of the generator, and i is the current flowing through it.

The resistance of the generator can be calculated using the following formula:R = Vt / iThe capacitance of the generator can be calculated using the formula:C = i * t / Vt, where t is the time for which the current flows.Step 2: Simulation of the Generator in SoftwareThe generator can be simulated using software like MATLAB, SIMULINK, or PSpice.

The simulation can be done by building a circuit that represents the generator, and then using the software to simulate the circuit. The simulation can be used to test the performance of the generator and to optimize the design.Step 3: Building and Testing the GeneratorOnce the design and simulation are complete, the generator can be built and tested. The generator should be tested to ensure that it meets the specifications and requirements. If any issues are found, the design can be modified and the generator can be retested. A detailed explanation of the generator design and simulation should be provided in the report.

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The Boolean expression is given as J'Q(t) + KQ'(t) = Q(t+1)

A sequential logic device called a J-K latch can hold one bit of data. The truth table for a J-K latch is as follows:

J, K, Q(t), and Q(t+1)

0 | 0 | 0 | 0

0 | 1 | 0 | 0

1 | 0 | 0 | 1

1 | 1 | 1 | 0

In this truth table, Q(t) represents the current state (output) at time t, whereas Q(t+1) represents the following state (output) at time t+1. J and K are the input signals.

A J-K latch's Boolean expression is given as;

J'Q(t) + KQ'(t) = Q(t+1)

The negative operation also known as the complement is indicated by the symbol "here."

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Answer:

3

Explanation:

it is compulsory to have a bachelor's degree

Answer:

\(250\ \text{lbm/min}\)

\(625\ \text{ft/min}\)

Explanation:

\(A_1\) = Area of section 1 = \(10\ \text{ft}^2\)

\(V_1\) = Velocity of water at section 1 = 100 ft/min

\(v_1\) = Specific volume at section 1 = \(4\ \text{ft}^3/\text{lbm}\)

\(\rho\) = Density of fluid = \(0.2\ \text{lb/ft}^3\)

\(A_2\) = Area of section 2 = \(2\ \text{ft}^2\)

Mass flow rate is given by

\(m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}\)

The mass flow rate through the pipe is \(250\ \text{lbm/min}\)

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

\(m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}\)

The speed at section 2 is \(625\ \text{ft/min}\).

(a) The mass flow rate will be "250 lbm/min".

(b) At section 2, the speed will be "625 ft/min".

According to the question,

Section 1 area, A₁ = 10 ft²

Section 2 area, A₂ = 2 ft²

Water's velocity, V₁ = 100 ft/min

Volume at section 1, v₁ = 4 ft³/lbm

(a) We know the formula,

Mass flow rate, m = ρA₁V₁

                              = \(\frac{A_1 V_1}{v_1}\)

By substituting the values,

                              = \(\frac{10\times 100}{4}\)

                              = \(\frac{1000}{4}\)

                              = 250 lbm/min

(2) The speed will be:

→ m = ρA₂V₂

or,

  V₂ = \(\frac{m}{\rho A_2}\)

By substituting the values,

       = \(\frac{250}{0.2\times 2}\)

       = \(\frac{200}{0.4}\)

       = 625 ft/min

Thus the responses above are correct.  

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Answer: the design stage uncertainty is ±5.6 rpm

Explanation:

Given that;

machine with an analog display dial graduated in 5 revolutions per minute (rpm) increments; Q = 5 rpm

now lets calculate zero order uncertainty in this machine

⇒ ± 1/2Q =  1/2(5) = ± 2.5 rpm

given that accuracy is 0.1% of reading

0.1% of 5000 rmp = 0.1/100 × 5000 = 5 rpm

now the design stage uncertainty at 5000 rpm will be;

⇒ √((5)² + (2.5)²)

= √(25 + 6.25)

= √ 31.25

= ±5.59 ≈ ±5.6 rpm

Therefore the design stage uncertainty is ±5.6 rpm

The common attribute within the HTML element that configures the number of choices the browser will display is the "size" attribute.

The "size" attribute is commonly used within HTML elements to specify the number of choices or options that should be displayed by the browser. It is typically used with the "select" element, which creates a drop-down list or selection menu.

By setting the "size" attribute to a specific value, you can control the number of visible options in the drop-down list. For example, if you set the "size" attribute to 5, the browser will display a drop-down list with five visible options. If there are more options that can fit within the specified size, the browser will provide a scrollbar to navigate through the remaining choices.

Here's an example of how the "size" attribute can be used within an HTML "select" element:

<select size="5">

 <option value="1">Choice 1</option>

 <option value="2">Choice 2</option>

 <option value="3">Choice 3</option>

 <option value="4">Choice 4</option>

 <option value="5">Choice 5</option>

 <option value="6">Choice 6</option>

 <option value="7">Choice 7</option>

 <!-- More options... -->

</select>

In this example, the "size" attribute is set to 5, so the browser will display a drop-down list with five visible choices. If there are more than five options, the user can scroll within the list to view and select additional choices.

To configure the number of choices the browser will display, you must set the desired value for the "size" attribute within the appropriate HTML element.

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there is no smoke its a electric train

Answer:

Tech A and Tech B are correct

Explanation:

Tech A is correct because radial ply tires have more flexible sidewalls than radial tires due to the fact that radial tires make use of two or more layers of casing piles and are thus not much flexible.

Also, tech B is correct because bias-ply tires typically have more durable construction than radial tires

The instantaneous magnitude of a sine wave after 212 degrees of rotation, given a peak value of 20 volts, is approximately -0.5299 volts.

A sine wave is a periodic function that oscillates between a maximum positive value and a maximum negative value. The peak value of the sine wave represents the maximum amplitude or magnitude of the wave. In this case, the peak value is given as 20 volts.

To find the instantaneous magnitude after 212 degrees of rotation, we need to convert the angle to radians since the sine function operates in radians. We can convert degrees to radians by multiplying the angle by π/180.

212 degrees * π/180 = 3.699 radians

The instantaneous magnitude of the sine wave can be determined by evaluating the sine function at the given angle. Using a scientific calculator or mathematical software, we find that sin(3.699) is approximately -0.5299.

Therefore, the answer is approximately -0.5299 volts (option a). It indicates that at 212 degrees of rotation, the sine wave has a negative instantaneous magnitude, and its value is 0.5299 volts below the zero reference line.

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Answer:

True

Explanation:

Bona Fide is a Latin term which means in good faith or without any intention to deceive. The business established on a bona fide basis means that there is an absence of fraud. The marketing agency has devoted its services to public relations, advertising and promoting the services of clients. There is no intention of fraud in the business.